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8/7/2019 Bai Tap Chuong+4 5 hvnh
1/22
BI TP CHNG 4-5
8/7/2019 Bai Tap Chuong+4 5 hvnh
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Bai 8
YdYdMPCCC .75,0145. !!355!! II
550!!GG
YYtTT .2,010. !!
298!! XEEX
YYIM .4,0. !!
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a, Vit hm s tng cu, mc sn lng cn bng?Biu din trn th?
Hm tng cu:
? AYMPMMPCtMPCICAD .).1(. !
? AYAD .4,075,0.2,0110.75,02985503551450
!
625,16750 ! Y
Trng thi cn bng ca nn kinh t: AD0 = Y
AD0 = 1340,5 + 0,2.Y
YY ! .2,05,1340
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b, Xu hng nhp khu cn bin gim cn 0,25, sn
lng cn bng, cn cn ngn sch, cn cnthng mi thay i ntn?
Hm tng cu mi:
? AYMPMMPCtTMPCXEGICAD .).1(.11
!
308,20621! Y
Trng thi cn bng mi ca nn kinh t: AD1 = Y
AD1 = 1340,5 + 0,35.Y
1340,5 + 0,35.Y = Y
S thay i sn lng: Y = 2062,308 1675,625 = 386,683
? AYAD .25,075,0.2,0110.75,02985503551451
!
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AD
0
450
Y2062,3
E1
E01340,5
AD0 = 1340,5 + 0,2.Y
1675,6
AD1 = 1340,5 + 0,35.Y
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Cn cn ngn sch ban u: B0 = T0 G0
S thay i cn cn ngn sch: B = B1 B0
= - 87,538 (- 204,875) = 117,336
Cn cn ngn sch BT thm ht 117,336
B0 = 10 + 0,2. 1675,625 550 = - 204,875
Cn cn ngn sch
Cn cn ngn sch sau khi c s thay i: B1 = T1 G1
B1 = 10 + 0,2. 2062,308 550 = - 127,538
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Cn cn thng mi ban u: NX0 = EX0 IM0
S thay i cn cn thng mi: NX = NX1 NX0 =
Cn cn thng mi bt thm ht:
NX0 = 298 0,4. 1675,625 =
Cn cn thng mi
Cn cn thng mi sau khi c s thay i: NX1 = EX1 IM1
NX1 = 298 - 0,25. 2062,308 =
8/7/2019 Bai Tap Chuong+4 5 hvnh
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0
450
2262,3
E1
E01340,5
1685
AD1 = 1340,5 + 0,35.Y
c, Nu Y* = 1685, MPM thay i tc ng ntn n
nn kinh t? a Y = Y*,C
P cn a ra chnhsch ng ph ntn?
AD
0Y
AD2
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Bai 9
YdYdMPCCC .8,055. !!115!! II
260!!GG
YYtTT .25,0. !!
125!! XEEXYYMPMIM .2,0. !!
8/7/2019 Bai Tap Chuong+4 5 hvnh
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a, Vit hm s tit kim, hm tng cu. Biu dintrn th?
Hm tng cu:
? AYMPMMPCtMPCICAD .).1(. ! ? AYAD .2,08,0.25,01125260115550 !
9250 ! YTrng thi cn bng ca nn kinh t: AD0 = Y
AD0 = 555 + 0,4.Y
Hm tiu dng: )( TYMPCCC ! YC 6,055!
Hm tit kim: )( TYMPSCS ! YS 15,055!
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450
925
E0
555
366,67
AD0 = 555 + 0,4.Y
AD
Y
C = 55 + 0,6.Y
55
- 55
S = - 55 + 0,15.Y
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AD
0
450
555
AD0 = 555 + 0,4.Y
925
E0
Y
b, Khi sn lng thc t l 1000, nn kinh t d
cung hay cu? Mt lng l bao nhiu? a snlng v mc 1000, CP cn thc hin CSTK ntn?
1000
955
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Bai 11
C = 297 + 0,7 Yd
EX = 240 I = 100 8,4 i MPM = 0,4 T = 0,2 Y + 10 G = 350 MD = 0,2 Y 8 i MS = 200 P =2
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a, Xy dng ng IS
, LM. Xc nh li sut v snlng cn bng. Minh ha trn th
Y
nd
MPMMPCt
nd
TMPCICiIS .
)1(1._)(
0
!
)..(1
_)(0
P
MSYk
hiLM !
(IS0): Y = 1166,7 10 i
(LM0): Y = 500 + 40 i
im cn bng E0 (i0, Y0)
!
!
Yi
Yi
025,05,12
1,067,116
!
!
33,1033
33,13
0
0
Y
i
(IS0): i = 116,67 0,1 Y
(LM0): i = 12,5 + 0,025Y
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b, NHTWmua 5 t ng tri phiu trn OMO, s = 0,2;
rb = 0,1, rex= 0. Quyt nh ny nh hng ntn nnn kinh t?
!
!
exbrrs
smm
1
!
!
Yi
Yi
025,075,13
1,067,116
ng LM dch phi n LM1
(LM1): Y = 550 + 40 i
im cn bng mi E1 (i1, Y1)
!
!
33,1043
33,12
1
1
Y
i
MBmmMS (!( .
)..(1
_)( 11
P
MSYk
hiM !
MS = 4 . 5 = 20 t
MS1 = MS0 + MS =
(LM1): i = 13,75 + 0,025Y
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LM1
E112,33
1043,33
i
Y0
LM0
IS0
1033,33
13,33
E0
Y = 10 t
i = - 1 %
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Bai 13
C = 150 + 0,7 Yd
EX = 290 I = 80 12 i MPM = 0,14 T = 0,2 Y + 20 G = 150 MD = 0,2 Y 10 i MS = 200 P = 1
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a, Vit phng trnh ng IS
, LM.T
nh li sut vsn lng cn bng, biu din trn th
(IS0): Y = 1131,034 20,69 i
(LM0): Y = 1000 + 50 i
im cn bng E0 (i0, Y0)
!
!
683,1092
854,1
0
0
Y
i
ng IS: tha mn iu kin cn bng th trng hng ha
AD= Y
ng LM: tha mn iu kin cn bng th trng tin t
MD= MS/P
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i
Y0
LM0IS0
1092,68
E01,854
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b, Nu chnh ph tng chi tiu thm 60 th snlng cn bng v li sut thay i ntn?
ng IS dch phi n IS1
(IS1): Y = 1234,48 20,69 i
im cn bng mi E1 (i1, Y1)
!
!
854,1165
317,3
1
1
Y
i
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i
Y0
LM0IS0
E0
IS1
E1
Y =
i =
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b, VicCP tng chi tiu gy tc ng g? Nu ko c tc ng
ny mc sn lng cao nht c th t c l bao nhiu? t c mc sn lng cao nht trn CP cn lm g?
Thoi lui u t
Quy m ca thoi lui u t
Y2 - Y1 =
Chnh ph c th a nnkinh t v im cn bngmi E2 bng CSTT m rng
i
Y0
LM0IS0
1092
1,854
E0
IS1
E1
3,317
1165
E2
Ymax = 1196
1196
LM1
MS = 20,69
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