Bình Phong Mã Hiện Đại

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Bình Phong Mã Hiện Đại

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ldr crdr trrrEuriNrr PHoNG vrA ta mOt ,nr r"*r, khai

cgc ndi tidng bflc nhdt trong cd Trr6ng.xd trr mri trrd trfn Thufn Ph6o drrqc

trinh biry mQt edeh di6u luyQn trong cdphd "Qudt Trung Bi" ctia Chu Tdn Trinhkhidn l;i thuydt cd trldng drrgc nflng l6nmQt brrdc dSng t<d tfri 70 nim sau thi VrlongT6i ViCt cho ra ddi quydn 'Mai Hoa Phd"d6 gAy chdn dQng trong ling cd. Tinh hoactia 'Mai hoa phd" chinh le thd trfn Binhphong Mi cria b6n di hfu ph6 thinh c6ngtrQn Ph6o ddu cria b6n di ti6n vir d5 chira mQt phrlong hr/dng hoin tdah mdi trongnghQ thuft cd trt'dng : phdng thri ehde,tdn c6ng m4nh. V6n cd trd n6n 6n hdahdn so vdi kidu choi ddi c6ng 6e liQt cfiaThuQn Ph6o. Dri e6ng thri song toin , tr{nBinh phong Mi v6n thd hi6n ddqc kiduchoi gay cdn, s6i ndi.

Tn/dc ti6n th6'binh phong li lo4i hinhti6u bidu cho phdng thir. Binh phong M5kh6ng nhrlng dfi srlc chdng l4i c6c trfnPh6o ddu mi cdn rlng ph6 hiQu qui vdibdt erl khai cgc niro ctia b6n di ti6n.

Ydu llnh d{c trdng ve cin bin nhdt eria

binh phong Me le : khi ch 2 M5 cr)ng l6nad tr6o vQ Tdt ddu thi s6 hinh thinh mQtbrtc binh phong, ph6t tridn c6n bing 6hai c6nh, thd tr{n s6 ddn ddn drlge dndinh vrlng chic. T4i sao vdy ?

Bdi vi Binh phong Mi c6 song M5 b6ov€ Tdt ddu, song Ph6o ri6ng biet b6o vQsong M5, song Xe ri6ng biQt lai b6o vQsong Ph6o. Cdn Si Tr/gng ri6ng biQt l6ntrung lQ li6n kdt, d6m b6o cho s{ dn dinhvrlng chdc ctia todn bO thd trfn. K6t hepvdi Binh phong Me (khi b6n ti6n di P2-5)thtrdng li l6n Tdt 3 hay l6n T6t 7,16n Tot3 thi thd trfn 6n hda, l6n Tdt 7 th_i th6'trfn kich li6t...

Trfn Binh phong M6 cdn drrgc c.5.c thdhQ sau nghiOn crlu vi bd sung, nAng caokh6ng ngrlng, khien eho trfn Binh phongMe ngiy th6m phong phri di6u luyQn,nhfing quydn s6ch Binh phong M5 chuyOnt6p de xudt hiQn, dio sdu th6m hing lo4tvdn dd lf thuydt vi ttrd trfn niy.

Quydn niNn PHoNG tuA ulEN Dd,r ramit ban dgc ldn niy nhim cung cdp chob4n dge nhrlng ly thuydt mdi vi cin binctia trfn binh phong M6. Dgc vi nim vfingnhrlng nguyGn tdc cfra n6, ch6c chdn trinhtIQ cria ngrrdi choi s6 dr/gc nAng cao.

cAcn Dec vA cnr cHEp vAN cd THEocAc xf Hr$u errY rjdc vrEr NAM

Bin cd T6ng dr{c vE nhu 0 hlnh bon. Clc cQt cla

Tr[ng du{c ddnh sdtil 9 tdi 1, cic cOt ben oen dfic

ddnh s61 dgn I (ngWc lai).

Ki hltu vi cdch ghl nUdc di :

Ddu chdm 1.1 la ti6n

Ddu gqch (-) li di ngang (binh)

Ddu gqch ch6o (/) ldr lii (thoai)

M6i nudc diduqc ghitheo thr/ tr/ :

- S6 thf tu nudc di

- T6n qudn cd- Vi trivi srJ dich chuy6n quAn cd

VidU : Ntldc ddu,Tring di Phrio 2binh 5 (vAo Phrlo ddu), b6n Den

Ua e ffn 7 thlghi :

1.P2-5 M8.7 (xem hlnh)

Nr/dc thf hai :

2.P811 97.1

Tr{ns drra ph6o 0 c6r e ri,i r u,roc }ill(ddm 1 0 vd phia mlnh), Den dua

Tdt cQt 7 l6n m6t budc (ddm 1 6 vd

phiad6iphudng) e 8 7 6 5 4 3 2

Truong hgp 2 Phrio(M6, Xe) Ben Trangnim tr6n mgt drJdng thi ghi Pt ld

Phdo trudc, Ps lA Ph6o sau.

N6u c6 e Tdt nlm tr6n cl)ng mot c6t thlk! hieu Bt (Binh tn]dc), Bg (Binhgi0a), Bs (Binh sau)

Ki hi€u cdc qu6n cd :

TU6ng - T9

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birn ddu p15 = Ma l6n c6t gira (M6 dQi)b6n ti6n = b6n di trudcb6n h?u = ben di sauBinh phong M6 = hai M6 c0a mQt b6n ctng l6n lQ 3 vd lQ 7c{c = thd cd, the trindo6i = ddidi = ddy, phia sauddn dd Y15 = Md ra bi6nd0 ha = vuqt s6nghoinh Xa = di Xe ngang (l6n Xe 1 nr.Idc dd sau d6 di ngang)6flu = phiihodn khai Xa = ra Xe chdmkhi Ma, khi Xa = b6 M6, b6 Xeky hi Xa = Xe l6n dudng s6ng b6n ddi phrldng (X2.5)khai Xa = m6 dudng cho Xekhdi Ma = di nudc ddu bing MiliQt Ph6o = nghich Phdo = hai b6n vdo Ph6o ngUQc hudng nhaul0 = cQt (hay dudng dgc tr6n bdn cd)lddng chidu = TLrdng cung lOc bi 2 quAn chieulddng ddu xi = rin haiddu (len cA T6t 3 va Tdt 7)Mi ngoq tao = Ma nim ngoiri nhim vdo cung ddi phudngngO lgc Ph5o = Phdo vdo c6t 5 vd c6t 6phAn cung Ma = Phao tdi g6c cung Tudng rdi l6n MaphiTUqng = di nudc ddu bing TrlqngphAn ti€n = gidnh thd ch0 d0ng tU tay ddi phudngphd = b6, hy sinhquAi gi6c M6 = M6 nim d g6c cung Tuldng , Mi qu!'qu6 hir Xa = Xe l6n qud dudng s6ng b6n d6i phrldng (X2.6)qud cung = di qua cung Tgdng vd nim d g6c cungquy bdi Phio = nit Phiio v6 sau, tai thdnh hinh mai rta.Si gi6c = 99n9 51= g6c phia tr6n c0a cung TudngSITTJQng toin = con d0 2 SIvd 2 Tuqngsiit chi6u = don bit Tudngsong = nhi = lddng = hai (2)tr{c Xa = di Xe dgc (ra Xe mQt nudc dd sau do di Xe dqc)trung - gi0a (Trung PhAo, Trung binh = Phdo ddu, Tdt dau)

t

tA = trAitu6n hd Xa = Xe l6n drJdng s6ng b6n minh (X2.4)tidn tam Binh = ti6n T6t 6 c6t 3thuQn Ph6o = 2 b6n vdo Ph6o cing hudngTi6n nh6n chi l0 =nudc ddu ti6n l6n Tdt cQt 3 hay Tdt cQt 7tam t0 quy bi6n = 3 quAn Xe, Ph6o , Md c0ng ddn vd mQt b6n

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