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Números de oxidacion
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DANIEL CANTOS SORIA 4160
DADO LOS SIGUIENTES ELEMENTOS CALCULE SU NUMERO DE OXIDACION
Na2SO3 → Na2+2 S+4 O3
-6 → Na= +1 S= +4O= -2
KMnO4 → K+1Mn+7O4-8 → K= +1 Mn= +7
O= -2
(Cr2O7)-2 → (Cr2+12O7
-14)-2 → Cr= +6 O= -2
Mn2O3 → Mn2+6O3
-6 → Mn= +3 O= -2
Cl2O7 → Cl2+10O7-10 → Cl= +5 O= -2
Al2O3 → Al2+6O3-6 → Al= +3 O= -2
H3PO4 → H3+3P+5O4
-8 → H= +1 P= +5O= -2
H2SO4 → H2+2S+6O4
-8 → H= +1 S= +6O= -2
H2CO3 → H2+2C+4O3
-6 → H= +1 C= +4O= -2
HCl → H+1Cl-1 → H= +1 Cl= -1
CuSO4 → Cu+2S+6O4-8 → Cu= +2 S= +6
O= -2
(ClO)-1 → (Cl+1O-2)-1 → Cl= +1 O= -2
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