Clase 3

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Clase 3

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7/21/2019 Clase 3

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lımx → a

f (x ) lımx → a

g(x )

lımx → a

(f (x ) + g(x )) = lımx → a

f (x ) + lımx → a

g(x )

lımx → a

(f (x ) − g(x )) = lımx → a

f (x ) − lımx → a

g(x )

lımx → a

αf (x ) = α lımx → a

f (x ) ∀α ∈ R

lımx → a

(f (x )g(x )) = lımx → a

f (x ) lımx → a

g(x )

lımx → a

f (x )g(x )

=lım

x → af (x )

lımx → a

g(x ) lım

x → ag(x ) = 0

lımx → a

(f (x )) n = lımx → a

f (x )n

∀n ∈ Z +

lımx → a

n f (x ) = n lımx → af (x ) lım

x → af (x ) ≥ 0 n

f (x ) lımx → a

f (x ) = f (a )

lımx →− 1

x 3 + x − 1 = ( − 1)3 + ( − 1) − 1 = − 1 − 1 − 1 = − 3

lımx → 1

x 2 + 2 xx + 1

=(1) 2 + 2(1)

1 + 1=

32

lımx → 3

f (x ) − 1x − 2

= 1 lımx → 3

f (x )

lımx → 3

f (x ) − 1x − 2

=lım x → 3 f (x ) − 1

lım x → 3 x − 2 = lım

x → 3[f (x ) − 1] = lım

x → 3f (x ) −

lımx → 3

1

= lım x → 3 [f (x ) − 1

x − 2] = [lım x → 3 f (x )] − 1 = 1

lim x → 3 f (x ) = 2