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feat. Oliver, Evan, Michelle, and John
Material property ρ Describes the microscopic structure of a
conductor▪ The stuff that an electron has to move through
Total resistance depends on resistance What makes it harder for an electron to move?
▪ Longer wire▪ Less cross-sectional area
R=ρL/A
Deals with potential difference, resistance, and current Current (speed which charges can move)
is directly related to how much they want to move (voltage) and inversely related to how much stuff is in their way (resistance)
I=V/RV=IR
Kirchhoff’s Voltage Law (KVL) (Loops) Around a closed loop, the sum of all
voltage changes must equal zeroKirchhoff’s Current Rule (KCL)
(Nodes) The sum of currents flowing into a node
equals the currents flowing out of a node
In series, current through each resistor is equal (no node splits), but voltage is split up, so…
ΔVTOT= ΔV1+ ΔV2
IRTOT=IR1+IR2
RTOT=R1+R2
In parallel, voltage drop is the same (closed loops all over), but current is split up, so…
ITOT=I1+I2
V/RT=V/R1+V/R2
1/RT=1/R1+1/R2
P=ΔW/Δt ΔW=(Δq)V I=Δq/tP=IV
Using V=IR, we can substitute to get: P=IV=(V/R)(V)=V2/R P=IV=(I)(IR)=I2R
Math is on the handout.
Remember C=Q/VCapacitors in Parallel follow KVL
CT=C1+C2
Capacitors in Series follow KCL 1/CT=1/C1+1/C2
Remember I=dQ/dt; C=Q/ΔV Apply KVL:
Over time, the amount of current in the circuit decreases
C
Q
dt
dQRV
C
QiRV
VVV
battery
battery
capcacitorresistorbattery
τ=RC Time constant for charging depends on resistance
in the circuit and how much the capacitor can hold At 3τ, the device is 95% charged
▪ Steady state conditions Meanwhile while charging…
I asymptotically approaches 0 as I = Qstored asymptotically increases to CVbattery
Vcap approaches Vbattery
t
eR
VtI s
)(
t
eR
Vs
Rearranging
gives you Constants depend on charge in circuit at t=0 and
t=infinity
But what really matters:
At first, there is no charge in a capacitor. Over a long period of time, the charge equals the product of capacitance and battery voltage
C
Q
dt
dQRVbattery
BAeQ pt
)1( /tbattery eVCQ
From previous capacitor info U=1/2(QV)=1/2(CV2)=1/2(Q2/C)
Current in the circuit is defined as:
V here is the V of the cap, not necessarily the V of supply
Charge in the Capacitor is defined as:
Q0 is the charge on the capacitor when the switch is flipped
t
eR
VtI o
)(
teQtQ o
)(
A capacitor of capacitance C is discharging through a resistor of resistance R. Leave answers in terms of τ. When will the charge on the capacitor be half of its
initial value? When will the energy stored in the capacitor be
half of its initial value?
Half charge? Using discharging formula Adjust for half Take natural log Rearrange for t
teQtQ o
)(t
QeQ
5.0
69.0t)ln()5.0ln(
te
Half energy? Using energy formula Adjust for discharging Adjust for half Take logs Rearrange for t
U= 1/2(Q2/C)
teQtQ o
)(t
eCQU o
2
)/)(2/1( 2
t
UeU2
5.0
)ln()5.0ln(
2 te
35.0t
So in case you haven’t been paying attention, what is an RL circuit?: As the name would imply it is a circuit
with a resistor and inductor.▪ What is a resistor?: It resists things. In the case
of circuits it is resisting the flow of electrons.▪ What is an inductor?: A circuit component that
initially tries to oppose changes in the current running through it. After a while it stops fighting the change and begins acting like a wire.
So in an RL circuit that you just turn on the current in the resistor does not rise quickly to a value of ε/R, but it doesn’t. Why?▪ The inductor in the circuit creates a self induced
emf to oppose the rise of the current, which in turn means that the emf of the inductor is opposite in polarity to that of the battery.
▪ As long as the inductor is opposing the emf of the battery the resistor will have a value smaller than ε/R. As time goes on the discrepancy between what the current at the resistor should be and what it actually is will get smaller.
But Evan, what kind of formulas could we use in solving RL circuits? Well, I’m glad you asked:
Loop rule for RL circuits.
But what if I want more forumals?:
A circuit consisting solely of an inductor and a capacitor
In the circuit, stored energy oscillates at a specific resonant frequency
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