5 5.1 5.2 5.3 5.4 5.5 5.6

5.1.1 5.1.2 5.1

5.1.1 1 160.50 1015.43

HoHa16, Excel,15.43

215.43160.570.57160.50,0.575 .XLS

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N1 ,O116L1L2ABS=ABS(K2-$O$1)K2O1 10

16Excel1000 11000K2L2K3:L1001KL16

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1000160.57160.51010000.570.571616

15.89160.1110000.110.400.11

5.1.2

1 HoHa2zt t

3a/2

4 z tPztPPa Ho

5

5.2

5.2.1 5.2.2 P 5.2.3

5.2.1

150.15014.9820.05

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1.961.96P

5 .xlsz

B415B50.1E414.982E650B6=B3/SQRT(E3)0.014142B90.05E10z=(E2-B2)/B4-1.27279 zPz

5.2.2 P Pzz

ExcelNORMSDIST1.2729, NORMSDIST1.27279NORMSDIST1-1.27279

E9=2*NORMSDIST(-ABS(E10))0.203092 PP0.2030920.05B13

IFIF

logical-testE9B9 Value-if-trueValue-if-falseB13(15),(P)14.982:

15E414.95z()3.53553,P0.000407P

5.2.3

z NORMSINV

10 NORMSINV

NORMSINVProbabilityzzzProbabilityB9/2B10z-1.95996

B10=NORMSINV(B9/2)ABS=ABS(NORMSINV(B9/2))1.95996 Excel

B14ExcelIFIFLogical_testE10B10FALSEE101.27279,1.959961Value_if_true

Value_if_falseB13B14E414.98214.95-3.53553B13B14B4B5B9E4E5Excel

1200.01530120.010.01?

Ho=120, Ha120z3.651484P0.000261z2.575835

5.3 241.55024.490.01

Ho24 Ha24z24 a=0.01

2.33,2.0537Pa

5 .xlsz

B4B5E4E5B9241.524.9500.01E9=(NORMSDIST(-ABS(E10)))0.00000105025B10=ABS(NORMSINV(B9))2.33B13B1424245024

5.4 St $9350$935012$9323$800.05$9350

Ho=9350 Ha9350t9350a =0.05

11t2.201t2.201P,0.025

(1) 7 .xlst

B49350B580E49323E512B90.05B6E10t(2)tPtExcel

tTINVtTINVB10 TINVTINV

TINVtExcelt

ProbabilityB90.05Deg_freedomE5-111t2.20986273B10 PE9 TDISTTDIST

XE101.169 Deg_freedomE5-1 11Tails2 2 P0.267061E9

(3)B13=IF(E9B10,"","")B14

5.5

0.653152140.1

HO=0.65 Ha0.65z a=0.1

1.65,1.65P0.05

(1)7.xls

0.65Pi=214/315=0.6794PB40.65

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=SQRT((B4*(1-B4))/E5)B50.026874

E10

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(3)PE9=2*(NORMSDIST(-ABS(E10)))0.274531 (4)B13=IF(E9B10,"","")B14

5.6.1 5.6.2 5.6.3 ()5.6

5.6.1

11- a a

P

2 (1)HoHa

(2) ~ (n-1) Ho n-1

(3)(4) Ha(5)

5.6.2

641.6501.90.051.6

Ho1.6Ha>1.6 S1.91.6

(1) 7 .xls

B4()1.6B51.9B650B90.05 (2) P E9=(B5^2*(B6-1))/B4^2 E9 69.09766

E10CHIDISTCHIDIST

XE9Deg_freedomB6-1P0.030749

B10CHIINVCHIINV

ProbabilityB90.05Deg_freedomB6-1 66.33865B10(3)IFB16

IFIF

Logical_testE10

66.33865 69.0976666.33865 1.60

5.6.3 () 0.05 1.60?

Ho=1.6 Ha1.6.

5 .xlsE11=2*E10E10B18IF(E110.05

0.05cL2 cR2 0.05CHINV (cR2)0.025 cL21 (1-0.025=0.975)

B12=CHIINV(B9/2,B6-1)cR2 70.22236B13=CHIINV(1-B9/2,B6-1) cL2 31.5549369.0976