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SOAL NME 5.22) Diket : h = 7 m A = 23 km 2 ρ= 1000 kg/m 3 L = 21 km t = 370 min Dit : Ep rata-rata? Jawab : ρ = m V ρ = m A.h m = ρ.A.h = (1000 kg/m 3 ) (23 km 2 ) (7 m) (10 3 m/km) 2 = 1,61 x 10 11 kg Ep = m.g.h = (1,61 x 10 11 kg) (9,8 m/s 2 ) (7 m) = 1,10 x 10 13 J Ep rata-rata = (1,10 x 10 13 J) (2) (0,85) ( 1 370 min ) ( 1 min 60 s ) = 5,06 x 10 8 J/s = 5,06 x 10 8 W

5.22 & 5.23

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5.22 & 5.235.22 & 5.235.22 & 5.235.22 & 5.235.22 & 5.23

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SOAL NME

5.22)Diket : h = 7 mA = 23 km2 = 1000 kg/m3L = 21 kmt = 370 minDit : Ep rata-rata?Jawab : = = m = .A.h = (1000 kg/m3) (23 km2) (7 m) (103 m/km)2 = 1,61 x 1011 kgEp = m.g.h = (1,61 x 1011 kg) (9,8 m/s2) (7 m) = 1,10 x 1013 JEp rata-rata = (1,10 x 1013 J) (2) (0,85) () () = 5,06 x 108 J/s = 5,06 x 108 W

5.23)Diket : Dilihat menggunakan steam tablesKeadaan pertama : T = 250,5oCP = 4000 kPaH = 2801 kJ/kgV = 0,05 m3/kgKeadaan kedua : T = 650oCP = 10.000 kPaH = 3748,3 kJ/kgV = 0,0410 m3/kgDit : U ?Jwb : U = H - pV = (3748,3 2801) [ (10.000 x 0,041) (4000 x 0,05)] = 737,3 kJ/kg