Acero AISI 1045 Sut=570MPa(82kpsi) Sy=310MPa(45kpsi) Se’=0,5Sut Se’=0,5(570*10^6) Se’285*10^6Pa Se=kakbkckdkekf 1 Kf Se ' Se=0,3(285*10^6) Se=85,5*10^6 a= ( 0,87 x 570 x 10 6 ) 2 85,5 x 10 6 = 2876,22x10^6 b= −1 3 log [ 0,87( 570 x 10 6 ) 85,5 x 10 6 ] =−0,2544 σ = 32 M 2 πd 2 = 32 ( 47260) 2 π ( 0,03 ) 2 = 267,437x10^6N n= σ Se = 267,437 x 10 6 85,5 x 10 6
