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7/18/2019 Bab 6-Ik Kimia-printable (1)
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Ikatan Kimia
• Konsep dalam Ikatan Kimia
• Simbol Lewis
•Ikatan ionik dan Struktur Lewis
•Ikatan kovalen dan struktur Lewis
•Jenis-jenis ikatan kovalen : tulen,
datif dan berkutub
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Konsep asas dalam ikatan kimia
Sebatianionikdankovalenadalahduasebatianyangumumdengansifatfizikyangberbezayangberasaskankepadapembentukanikatanmasing2.
Kata kunci
• Sebatian Ionikterbentukdaripadainteraksikuat(dayaelektrostatik)
antaraion-ion.Ion-ionwujudhasilpendermaandanpenerimaanelektron
atom-atom.Dayaelektrostatikantaraionyangwujudmenghasilkan
perbezaansifatfizikmisalnyatakatleburataukekonduksianelektrik.
• Sebatian kovalenmelibatkanperkongsianelektronantaraatom-atom.
Akibatperkongsianelektron,sifatfizikyangterhasilialahtakatlebur
yangrendahdankekonduksianelektrikyangrendah.
*Selainikionik&kovalen,terdapatbanyaklagidayayangmenghasilkan
ikatanantaraatom-atom.
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SIMBOL TITIK LEWIS
• Apabila suatu atom berinteraksi bagi membentuk ikatan kimia,hanya elektron valens sahaja yg berhubung.
• Ahli kimia menggunakan sistem titik untuk menunjukkan yang jumlah elektron bagi atom tidak berubah. 1 titik untuk 1elektron valens.
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Elektron Valens adalah elektron terluar (elektron di petala
terluar) suatu atom. Hanya e valens yg terlibat dalam
pembentukan ikatan.
1A 1Cth: 2.1
2A 2Cth: 2.8.23A 3Cth: 2.8.3
4A 4Cth: 2.4
5A 5Cth: 2.5
6A 6Cth: 2.8.6
7A 7Cth: 2.7
Kumpulan # e valensKonfigurasi e
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Contoh:
Tulis simbol Lewis bagi atom natrium dan ion natrium.
Jwpn: atom Na, Z = 11
konfigurasi e : 2.8.1
elektron valens : 1
atom natrium : Na •
ion natrium : [ Na ]+
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Contoh
Tulis simbol Lewis bagi atom oksigen dan ion oksida.
Jwpn : atom oksigen O, Z = 8
konfigurasi e : 2.6
elektron valens : 6
Atom oksigen :
ion oksida : [ ]2-
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Ik. Ionik
Suatu sebatian ionik terbentuk drpd gabungan ion positif dan negatif.Ion-ion dalam sebatian ionik dipegang oleh daya elektrostatik
Pembentukan kation
Atom logam, M menyingkir elektron bagi membentuk ion positif (kation)
M M+ + e
Pembentukan anion Atom bukan logam, X menerima e valens bagi membentuk ion negatif
(anion)
X + e X-
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Pembentukan sebatian ionik
Kation M+ dan anion X- bergabung dengan ikatan ionik bgmembentuk sebatian ionik .
M+ + X- MX
Ikatan kimia dalam MX adalah tarikan antara cas positif ion M
dengan cas negatif ion X. Sebatian MX secara elektriknyaneutral.
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Li + F Li+ F -
2.1 2.72 2.8
[He] [Ne]
Li Li+ + e-
e- + F F -
F -Li+ + Li+ F -
contoh Tbls antara litium dan florin bagi membentuk
litium florida.
( kation )
( Anion )
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2Ca( p) + O2(g ) 2CaO( p)
contoh kalsium terbakar dalam oksigen dan
membentuk kalsium oksida.
2.8.8.2 2.6 [Ar] [Ne]
Latihan
Gunakan simbol titik Lewis utk menunjukkan pembentukan :
(i) Magnesium nitrida, Mg3N2(ii) Aluminium oksida, Al2O3
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Ik kovalen ialah ik kimia di mana 2 atau lebih elektron
dikongsikan.
Mengapa atom-atom berkongsi elektron?
FF+
7e- 7e-
F F
8e- 8e-
F F
F F
Struktur Lewis F2
Psgn e sendiri
Ik. Kovalen tunggal
Ikatan kovalen
Psgn e sendiri
Psgn e sendiri Psgn esendiri
Ik. Kovalen tunggal
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8e-
H HO+ + OH H O HHor
2e- 2e-
Str Lewis air
Ik. berganda – 2 atom berkongsi 2 pasang e
Ik kov tunggal
O C O atau O C O
8e- 8e- 8e- Ik dubel
Ik ganda 3 – 2 atom berkongsi 3 pasang e
N N
8e- 8e-
N N
Ik tripel
atau
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1. Lukis str kerangka sebatian dengan atom jum
minimum (atau paling elektropositif) di tengah(atom pusat). Letak atom2 lain di keliling atompusat (atom hujung).
2. Hitung jum e valens. Tambah 1 pd setiap 1 casnegatif dan tolak 1 bagi setiap cas positif.
3. Lengkapkan oktet semua atom hujung terlebihdahulu, Oktet bg H ialah 2!
4. Jika struktur mengandungi lebihan e, bentukkanik dubel atau tripel dgn atom pusat sebgmnperlu.
Melukis str Lewis sebat kovalen
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Penulisan struktur Lewis bagi nitrogen triflorida (NF3).
Lgkh 1 – N kurang elektronegatif dari F, letak N di tengah
F N F
F
Lgkh 2 – Kira e valens bagi N - 5 (2s22p3) dan F - 7 (2s22p5)
5 + (3 × 7) = 26 e valens
Lgkh 3 – Lukis ik tunggal antara atom N dan F dan lengkapkan
oktet bagi atom N dan F.
Lgkh 4 - Semak, adakah e dalam struktur = bil e valens ?
3 ik. tunggal (3×2) + 10 e sendiri (10×2) = 26 e valens
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16
Write the Lewis structure of the carbonate ion (CO32-).
Step 1 – C is less electronegative than O, put C in center
O C O
O
Step 2 –
Count valence electrons C - 4 (2s2
2p2
) and O - 6 (2s2
2p4
)-2 charge – 2e-
4 + (3 x 6) + 2 = 24 valence electrons
Step 3 – Draw single bonds between C and O atoms and complete
octet on C and O atoms.Step 4 - Check, are # of e- in structure equal to number of valence e- ?
3 single bonds (3x2) + 10 lone pairs (10x2) = 26 valence electrons
Step 5 - Too many electrons, form double bond and re-check # of e-
2 single bonds (2x2) = 4
1 double bond = 4
8 lone pairs (8x2) = 16
Total = 24
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17
Struktur Lewis dan Cas Formal
1. Bagi molekul neutral, struktur Lewis dengan cas formal
sifar adalah yang terbaik/paling stabil berbanding struktur
dengan nilai cas formal.
2. Struktur Lewis dengan nilai cas formal yang besar
adalah kurang stabil berbanding struktur dengan nilai cas
yg kurang.
3. Jika terdapat lebih dari 1 struktur, yang lebih stabil ialah
agihan cas (-) yang diletakkan pada atom elektronegatif.
Struktur mana yang lebih mungkin untuk CH2O?
H C O H
-1 +1 HC O
H
0 0
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2 struktur kerangka bagi formaldehid (CH2O)
H C O HH
C OH
Cas formal suatu atom ialah perbezaan antara e valens bagi
atom asal dengan bil e yang ditetapkan dalam struktur Lewis.
Cas formal
satu atom dlm
struktur Lewis=
1
2
Jum e ikatan
( )
Jum e valens
dalam atom
bebas -Jum e bukan
ikatan -
Jum cas formal bagi semua atom dalam molekul atau ion =
cas bersih molekul / ion.
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H C O H
C – 4 e-
O – 6 e-
2H – 2×1 e-
12 e-
2 ik tunggal (2×2) = 4
1 ik dubel = 4
2 psg e sendiri (2×2) = 4
Total = 12
Cas formal C = 4 - 2 - ½ × 6 = -1
= 6 - 2 - ½ × 6 = +1
Cas formal
suatu atom
dalam struktur
Lewis
=1
2
Jum e ikatan
( )
Jum e valens
dalam atom
bebas -Jum e bukan
ikatan -
-1 +1
Cas formal O
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2 0
C – 4 e-
O – 6 e-
2H – 2x1 e-
12 e-
2 single bonds (2x2) = 4
1 double bond = 4
2 lone pairs (2x2) = 4
Total = 12
HC O
H
formal charge
on C= 4 - 0 - ½ x 8 = 0
formal charge
on O= 6 - 4 - ½ x 4 = 0
formal charge
on an atom in
a Lewis
structure
=1
2
total number
of bonding
electrons
( )
total number
of valence
electrons in
the free atom
-total number
of nonbonding
electrons
-
0 0
9.7
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Struktur resonans ialah satu atau lebih struktur yang boleh
mewakili dengan tepat sesuatu struktur Lewis molekul.
O O O+ -
OOO+-
O C O
O
- -O C O
O
-
-
OCO
O
-
-
Apakah struktur resonans bagi ion
karbonat (CO32-)?
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H F FH
Ik kovalen berkutub adalah ik kovalen denganketumpatan elektron yang tidak sekata antara 2 atom.
Kaw kaya
elektron
Kaw kurang
elektron e- riche- poor
d+ d-
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Ke-elektronegatifan ialah kebolehan suatu atom untuk menarik
elektron kepadanya dalam suatu ikatan kimia.
Afiniti Elektron – boleh diukur, Cl tertinggi
Ke-Elektronegatifan - relatif , F tertinggi
X (g) + e- X-(g)
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25
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26
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kovalen
kongsi e-
Kovalen berkutubpartial transfer of e-
Ionik
pemindahan e-
Perbezaan keelektronegatifan meningkat
Klasifikasi ikatan yang bergantung kpd perbezaan keelektronegatifan
perbezaan Jenis ikatan
0 kovalen 2 Ionik
0 < dan <2 Kovalen berkutub
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28
Kelaskan yang berikut sebagai ionik, kov berkutub,atau kovalen: ik dlm CsCl; dalam H2S danthe NN bond in H2NNH2.
Cs – 0.7 Cl – 3.0 3.0 – 0.7 = 2.3 Ionik
H – 2.1 S – 2.5 2.5 – 2.1 = 0.4 Kovalen berkutub
N – 3.0 N – 3.0 3.0 – 3.0 = 0 Kovalen
f C
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29
Bond
Type
Bond
Length
(pm)
C-C 154
C C 133
C C 120
C-N 143
C
N 138C N 116
Lengths of Covalent Bonds
Bond Lengths
Triple bond < Double Bond < Single Bond 9.4
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3 0
DativeCovalentBondorCoordinateCovalentBond
Covalentbondformsbetweentwoatomsthatdonateanelectroneach.
However,itispossibleforbothelectronstocomefromthesame
atom.Thisisknownasadativecovalentbond oracoordinate
covalentbond.
Theatomthatdonatetheelectronsisknownasthedonor andit
musthaveatleastonelonepairofelectrons.
Theotheratomthatsharestheelectronsisknownastheacceptor
anditmusthaveanincompleteoctet .
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31
Example1
Example2
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3 2
Exceptions to the Octet Rule
The Incomplete Octet
H HBeBe – 2e-
2H – 2x1e-
4e-
BeH2
BF3
B – 3e-
3F – 3x7e- 24e-
F B F
F
3 single bonds (3x2) = 6
9 lone pairs (9x2) = 18Total = 24
9.9
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3 3
Exceptions to the Octet Rule
Odd-Electron Molecules
N – 5e- O – 6e-
11e-
NO N O
The Expanded Octet (central atom with principal quantum number n > 2)
SF6 S – 6e-
6F – 42e-
48e- S
F
F
F
F
F
F
6 single bonds (6x2) = 12
18 lone pairs (18x2) = 36
Total = 48
9.9
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3 4
Hydrogen Bonding
A hydrogen atom in a polar bond (e.g. H-F, H-O or H-N) canexperience an attractive force with a neighboring electronegativemolecule or ion which has an unshared pair of electrons (usually anF, O or N atom on another molecule)
Hydrogen bonds are considered to be dipole-dipole type interactions
A bond between hydrogen and an electronegative atom such as F, Oor N is quite polar:
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35
• The hydrogen atom has no inner core of electrons, so the side of theatom facing away from the bond represents a virtually naked nucleus
• This positive charge is attracted to the negative charge of anelectronegative atom in a nearby molecule
• Because the hydrogen atom in a polar bond is electron-deficient onone side (i.e. the side opposite from the covalent polar bond) this sideof the hydrogen atom can get quite close to a neighboringelectronegative atom (with a partial negative charge) and interactstrongly with it (remember, the closer it can get, the stronger the
electrostatic attraction)
Hydrogen bonds vary from about 4 kJ/mol to 25 kJ/mol sothey are still weaker than typical covalent bonds.
But they are stronger than dipole-dipole and or dispersion
forces. They are very important in the organization of biological
molecules, especially in influencing the structure ofproteins
W t i l i it bilit t f t i h d b di
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3 6
Water is unusual in its ability to form an extensive hydrogen bondingnetwork
• As a liquid the kinetic energy of the molecules preventsan extensive ordered network of hydrogen bonds
• When cooled to a solid the water molecules organizeinto an arrangement which maximizes the attractiveinteractions of the hydrogen bonds
• This arrangement of molecules has greater volume(is less dense) than liquid water, thus water expandswhen frozen• The arrangement has a hexagonal geometry
(involving six molecules in a ring structure) which isthe structural basis of the six-sidedness seen in snowflakes
• Each water molecule can participate in fourhydrogen bonds
- One with each non-bonding pair of electrons- One with each H atom
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3 7
Metallic Bond
Assume that a metallic lattice is composed of closely packed positiveions surrounded by an electron cloud. This happen when metal atoms
lose their valence electrons, forming metal cations, and the valenceelectrons then make up the electron cloud. The attractive force betweenthe electron cloud and the positive ions called the metallic bond.
The strength of the metallic bond is inversely proportional to the size
of the ion and directly proportional to the number of valenceelectrons on the metal atom. The smaller the size of the cation and/orthe more electrons supplied by the atoms to electron cloud, thestronger is the attractive force between the positively charged ionand the electron cloud. Hence, the stronger is the metallic bond
formed.
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3 8
Intermolecular Forces
Intermolecularforcesaregenerallymuch weakerthancovalent
bonds.Only16kJ/molofenergyisrequiredtoovercomethe
intermolecularattractionbetweenHClmoleculesintheliquidstate
(i.e.theenergyrequiredtovaporizethesample)
However,431kJ/molofenergyisrequiredtobreakthecovalent
bondbetweentheHandClatomsintheHClmolecule
Thus, when a molecular substance changes states the atoms within
the molecule are unchanged
Thetemperatureatwhichaliquidboilsreflectsthekineticenergy
neededtoovercometheattractiveintermolecularforces(likewise,
thetemperatureatwhichasolidmelts).
Thus, the strength of the intermolecular forces determines the
physical properties of the substance
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3 9
Attractiveforcesbetweenneutral molecules
Attractiveforcesbetweenneutralandcharged ionic) molecules
ion - dipoleforces
Note that all of these forces will be electrostatic in nature
Typically,dipole-dipoleanddispersionforcesaregrouped
togetherandtermedvan der W aals forces (sometimesthe
hydrogenbondingforcesarealsoincludedwiththisgroup)
Dipole - dipoleforces
London dispersionforces
Hydrogen bondingforces
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4 0
Ion-dipole
Involvesaninteractionbetweenacharged ionandapolar
molecule (i.e.amoleculewithadipole)•Cations areattractedtothenegativeendofadipole
• Anions areattractedtothepositiveendofadipole
Ion-dipoleforcesareimportantinsolutionsofionicsubstances
inpolarsolvents(e.g.asaltinaqueoussolvent)
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4 1
Dipole-Dipole Forces
Adipole-dipoleforceexistsbetweenneutralpolarmolecules
Polarmoleculesattractoneanotherwhenthepartialpositive charge ononemoleculeisnearthepartialnegativecharge onthe
othermolecule.
Thepolarmoleculesmustbeincloseproximityforthedipole-dipole
forcestobesignificant.
Dipole-dipole forcesarecharacteristicallyweakerthanion-dipoleforces.
Dipole-dipoleforcesincreasewithanincreaseinthepolarityofthe
molecule.
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4 2
Nonpolar moleculeswouldnotseemtohaveanybasisforattractive
interactions.However,gasesofnonpolarmolecules canbeliquefiedindicatingthatifthekineticenergyisreduced,sometypeofattractive
forcecanpredominate.
FritzLondon(1930)suggestedthatthemotionofelectronswithinan
atomornon-polarmoleculecanresultinatransientdipolemoment.
London Dispersion Forces
A Model To Explain London Dispersion Forces: Helium atoms 2e)
Considertheparticlenatureofelectrons.
Theaveragedistributionofelectronsaroundeachnucleusis
sphericallysymmetrical.
Theatomsarenon-polarandpossesnodipolemoment.Thedistributionofelectronsaroundanindividualatom, at a given
instant in time,maynotbeperfectlysymmetrical.
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43
•Bothelectronsmaybeononesideofthenucleus
•Theatomwouldhaveanapparentdipolemomentatthatinstantin
time(i.e.atransientdipole)
•Acloseneighboringatomwouldbeinfluencedbythisapparent
dipole-theelectronsoftheneighboringatomwouldmoveawayfromthenegativeregionofthedipole
Due to electron repulsion, a temporary dipole on one atom can
induce a similar dipole on a neighboring atom
•Thiswillcausetheneighboringatomstobeattracted to one another•ThisiscalledtheLondondispersionforce(orjustdispersionforce)
•Itissignificantonlywhentheatomsareclose together
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4 4
Theeasewithwhichanexternalelectricfieldcaninduceadipole
(altertheelectrondistribution)withamoleculeisreferredtoasthe
"polarizability"ofthatmolecule.
Thegreaterthepolarizabilityofamoleculetheeasieritistoinducea
momentarydipoleandthestrongerthedispersionforces
Largermoleculestendtohavegreaterpolarizability
Theirelectronsarefurtherawayfromthenucleus(any
asymmetricdistributionproducesalargerdipoleduetolarger
chargeseparation)
Thenumberofelectronsisgreater(higherprobabilityof
asymmetricdistribution)
thus, dispersion forces tend to increase w ith increasing molecular mass
Dispersionforcesarealsopresentbetweenpolar/non-polarand
polar/polarmolecules(i.e.betweenallmolecules)
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Exercise
2. Use the octet rule and draw the Lewis structure of each ofthe following substances or ions, keeping in mind that oneH atom in a compound cannot be bonded to another H
atom.
(a) OH
-
(b) H3O+
(c) NH4
+
(d) NH2
- (e) SH - (f) H3S+
4 5
1. Write Lewis symbols for the following:
(a) P (b) Te (c) Br (d) B
(e) Mn2+ (f) Mn3+ (g) Pb2+ (h) Pb4+
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4 6
4. Determine the formal charges for the following
compounds, considering all possible Lewis structuresif there are more than one.
(a) SO2 (b) NH3 (c) H2SO4
3.WriteLewisstructuresforthefollowingcovalent
molecules:
(a)HNNN(hydrazoicacid)
(b)H2NCN(cyanamide)
(c)CH3NH2(methylamine)
5. Draw the possible structures of HNO2 and use formalcharge to pick the most likely. The order of atoms is
HONO.
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7. What happens to the valence shells of Rb and Cl whenthese elements react to form an ionic compound. What
is the formula of this compound?.
6. Write the Lewis structure for acetate ion ( CH3COO- ),
including resonance structures if appropriate.
8. Give the empirical formulas and names of thecompounds formed from the following pairs of ions:
(a) Rb+ and I- (b) Cs+ and SO42-
(c) Sr 2+ and N3- (d) Al3+ and S2-
9. Write the Lewis dot symbols of the reactants andproducts in the following reactions. ( First balance the
equations.)
(a) Sr + Se SrSe (b) Li + N2 Li3N
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10. The atom of element A has a nuclear charge of +11.
Atom B requires two electrons to achieve an octet
( A and B are not the actual symbols of the elements).
(a) By using Lewis structures, show the formation of the
compound formed when element A combine
with element B.
(b) Can the solid compound formed conduct electricity?.
Explain briefly.
11. Phosphonium ion, PH4+ is formed when phosphene,
PH3 combine with H+ ion via a type of bond. By using
the Lewis structure show the formation of the PH4+ ion
and label this new bond.
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12. Using Lewis structures, show the formation of a dative
covalent bond between
(i) NH3 molecule and H+ ion
(ii) phosphorus chloride, PCl3 and oxygen, O.
13. With the aid of a suitable diagram, describe a metallic
bond according to the electron cloud model.
14. Arrange the following substances, NaF, HF, F2 and
CF4 in order of increasing boiling points. Explain briefly
your answer.