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Arial;}{\f5 Times New Roman;}{\f6 Times New Roman;}{\f7 Times New
Roman;}{\f8 Times New Roman Bold;}{\f9 Times New Roman;}{\f1000000
Times New
Roman;}}{\colortbl;\red0\green0\blue0;\red0\green0\blue0;\red0\green0\blue0;\red0\green0\blue0;\red0\green0\blue0;\red0\green0\blue0;\red0\green0\blue0;\red0\green0\blue0;}\viewkind1\viewscale100\margl0\margr0\margt0\margb0\deftab80\dntblnsbdb\expshrtn\paperw11900\paperh16820\pard\sb0\sl-240{\bkmkstart
Pg1}{\bkmkend
Pg1}\par\pard\li2304\sb0\sl-276\slmult0\par\pard\li2304\sb0\sl-276\slmult0\par\pard\li2304\sb0\sl-276\slmult0\par\pard\li2304\sb0\sl-276\slmult0\par\pard\li2304\sb0\sl-276\slmult0\par\pard\li2304\sb225\sl-276\slmult0\fi0\tx4465
\up0 \expndtw-3\charscalex100 \ul0\nosupersub\cf1\f2\fs24 NAMA\tab
\up0 \expndtw-3\charscalex100 : EDYFAI VIRTUOSO
SIAHAAN\par\pard\li2304\sb242\sl-276\slmult0\fi0\tx4465 \up0
\expndtw-3\charscalex100 NIM\tab \up0 \expndtw-3\charscalex100 :
5133122007\par\pard\li2304\sb240\sl-276\slmult0\fi0\tx4465 \up0
\expndtw-3\charscalex100 PRODI\tab \up0 \expndtw-3\charscalex100 :
PEND.TEKNIK
OTOMOTIF\par\pard\li2304\sb242\sl-276\slmult0\fi0\tx4465 \up0
\expndtw-3\charscalex100 MATA KULIAH\tab \up0
\expndtw-3\charscalex100 :BAHAN BAKAR DAN
PELUMASAN\par\pard\li2304\sb240\sl-276\slmult0\fi0\tx4465 \up0
\expndtw-3\charscalex100 PERIHAL\tab \up0 \expndtw-3\charscalex100
: TUGAS 3\par\pard\ql \li2664\sb0\sl-400\slmult0
\par\pard\ql\li2664\ri1544\sb221\sl-400\slmult0\tx3024\tx3024\tx3024
\up0 \expndtw0\charscalex103 \ul0\nosupersub\cf2\f3\fs23
1.\ul0\nosupersub\cf3\f4\fs23 \ul0\nosupersub\cf2\f3\fs23 A sample
of pine bark has the following ultimate analysis on a dry basis,
\line\tab \up0 \expndtw-3\charscalex100 percent by mass: 5.6% H,
53.4% C, 0.1% S, 0.1% N, 37.9% O and 2.9% ash. \line \tab \up0
\expndtw-1\charscalex100 This bark will be used as a fuel by
burning it with 100% theoretical air in a \line \tab \up0
\expndtw-4\charscalex100 furnace. Determine the air-fuel ratio on a
mass basis. \par\pard\ql \li2664\sb102\sl-253\slmult0 \up0
\expndtw-3\charscalex100 \ul0\nosupersub\cf4\f5\fs22 Jawab :
\par\pard\li2786\sb0\sl-264\slmult0\par\pard\li2786\sb155\sl-264\slmult0\fi0\tx5389\tx6395\tx7254\tx8546\tx9693
\up0 \expndtw-2\charscalex100 \ul0\nosupersub\cf2\f3\fs23 zat\tab
\up0 \expndtw-2\charscalex100 S\tab \up0 \expndtw-2\charscalex100
H\ul0\nosupersub\cf5\f6\fs18 2\tab \up0 \expndtw-2\charscalex100
\ul0\nosupersub\cf2\f3\fs23 C\tab \up0 \expndtw-2\charscalex100
O\ul0\nosupersub\cf5\f6\fs18 2\tab \up0 \expndtw-2\charscalex100
\ul0\nosupersub\cf2\f3\fs23 N\ul0\nosupersub\cf5\f6\fs18
2\par\pard\li2786\sb212\sl-264\slmult0\fi0\tx5389\tx6395\tx7254\tx8546\tx9693
\up0 \expndtw-2\charscalex100 \ul0\nosupersub\cf2\f3\fs23 c/M =\tab
\up0 \expndtw-2\charscalex100 0.1/32\tab \up0
\expndtw-2\charscalex100 5.6/2\tab \up0 \expndtw-2\charscalex100
53.4/12\tab \up0 \expndtw-2\charscalex100 37.9/32\tab \up0
\expndtw-2\charscalex100
0.1/28\par\pard\li2786\sb215\sl-264\slmult0\fi0\tx5389\tx6395\tx7254\tx8546\tx9693
\up0 \expndtw-2\charscalex100 kmol / 100 kg coal\tab \up0
\expndtw-2\charscalex100 0.003\tab \up0 \expndtw-2\charscalex100
2.80\tab \up0 \expndtw-2\charscalex100 4.45\tab \up0
\expndtw-2\charscalex100 1.184\tab \up0 \expndtw-2\charscalex100
0.004\par\pard\li2786\sb213\sl-264\slmult0\fi0\tx5425\tx6351 \up0
\expndtw-2\charscalex100 Produk\tab \up0 \expndtw-2\charscalex100
SO\ul0\nosupersub\cf5\f6\fs18 2\tab \up0 \expndtw-2\charscalex100
\ul0\nosupersub\cf2\f3\fs23 H\ul0\nosupersub\cf5\f6\fs18
2\ul0\nosupersub\cf2\f3\fs23 O\ul0\nosupersub\cf5\f6\fs18
\ul0\nosupersub\cf2\f3\fs23 CO\ul0\nosupersub\cf5\f6\fs18
2\par\pard\li2786\sb214\sl-264\slmult0\fi0\tx5389\tx6395\tx7254\tx8546\tx9693
\up0 \expndtw-2\charscalex100 \ul0\nosupersub\cf2\f3\fs23 Oksigen
yang dibutuhkan\tab \up0 \expndtw-2\charscalex100 0.003\tab \up0
\expndtw-2\charscalex100 1.40\tab \up0 \expndtw-2\charscalex100
4.45\tab \up0 \expndtw-2\charscalex100 --\tab \up0
\expndtw-2\charscalex100 --\par\pard\ql
\li3024\sb210\sl-264\slmult0 \up0 \expndtw-3\charscalex100
Pembakaran membutuhkan : \par\pard\qj
\li3790\ri4491\sb55\sl-460\slmult0\fi12 \up0
\expndtw-3\charscalex100 0.003 + 1.40 + 4.45 = 5.853 kmol
O\ul0\nosupersub\cf5\f6\fs18 2 \line \up0 \expndtw-3\charscalex100
\ul0\nosupersub\cf2\f3\fs23 Yang ada dikulit 1.184 kmol
O\ul0\nosupersub\cf5\f6\fs18 2 \par\pard\ql
\li3024\sb191\sl-253\slmult0 \up0 \expndtw-4\charscalex100
\ul0\nosupersub\cf2\f3\fs23 Sehingga yang bersih dari udara adalah
4.669 kmol O\ul0\nosupersub\cf5\f6\fs18 2
\ul0\nosupersub\cf4\f5\fs22 ,karena mol O\ul0\sub\cf6\f7\fs21 2
\par\pard\ql \li3024\ri1879\sb43\sl-380\slmult0\tx3745 \up0
\expndtw-4\charscalex100 \ul0\nosupersub\cf4\f5\fs22 seluruhnya
dikurangkan mol d kulit yaitu : O\ul0\sub\cf6\f7\fs21
2\ul0\nosupersub\cf4\f5\fs22 bersih = 5,853 - 1,184 = 4,669
\line\tab \up0 \expndtw-5\charscalex100 \ul0\nosupersub\cf2\f3\fs23
AF = (4.669 + 4.669 3.76) 28,97/100 = \ul0\nosupersub\cf7\f8\fs23
6.44 kg airkg bark {\shp
{\*\shpinst\shpleft7724\shptop11995\shpright9537\shpbottom12016\shpfhdr0\shpbxpage\shpbypage\shpwr3\shpwrk0\shpfblwtxt1\shpz1233\shplid0{\sp{\sn
shapeType}{\sv 0}}{\sp{\sn fFlipH}{\sv 0}}{\sp{\sn fFlipV}{\sv
0}}{\sp{\sn geoRight}{\sv 1813}}{\sp{\sn geoBottom}{\sv
21}}{\sp{\sn pVerticies}{\sv
8;4;(0,21);(1813,21);(1813,0);(0,0)}}{\sp{\sn pSegmentInfo}{\sv
2;10;16384;45824;1;45824;1;45824;1;45824;24577;32768}}{\sp{\sn
fFillOK}{\sv 1}}{\sp{\sn fFilled}{\sv 1}}{\sp{\sn fillColor}{\sv
0}}{\sp{\sn fLine}{\sv 0}}{\sp{\sn lineType}{\sv 0}}{\sp{\sn
fArrowheadsOK}{\sv 1}}{\sp{\sn fBehindDocument}{\sv 1}}{\sp{\sn
lineColor}{\sv
0}}}}\par\pard\sect\sectd\fs24\paperw11900\paperh16820\pard\sb0\sl-240{\bkmkstart
Pg2}{\bkmkend Pg2}\par\pard\ql \li2664\sb0\sl-400\slmult0
\par\pard\ql\li2664\sb0\sl-400\slmult0
\par\pard\ql\li2664\sb0\sl-400\slmult0
\par\pard\ql\li2664\sb0\sl-400\slmult0
\par\pard\ql\li2664\sb0\sl-400\slmult0
\par\pard\ql\li2664\ri1532\sb370\sl-400\slmult0\tx3024\tx3024 \up0
\expndtw0\charscalex102 \ul0\nosupersub\cf2\f3\fs23
2.\ul0\nosupersub\cf3\f4\fs23 \ul0\nosupersub\cf2\f3\fs23 Many
coals from the western United States have a high moisture content.
\line\tab \up0 \expndtw0\charscalex102 Consider the following
sample of Wyoming coal, for which the ultimate \line \tab \up0
\expndtw-3\charscalex100 analysis on an as-received basis is, by
mass:
\par\pard\li2863\sb114\sl-264\slmult0\fi641\tx5905\tx6682\tx7402\tx8123
\up0 \expndtw-2\charscalex100 Component Moisture\tab \up0
\expndtw-2\charscalex100 H\tab \up0 \expndtw-2\charscalex100 C\tab
\up0 \expndtw-2\charscalex100 S\tab \up0 \expndtw-2\charscalex100 N
O
Ash\par\pard\li2863\sb133\sl-264\slmult0\fi641\tx5905\tx6682\tx7402\tx8123\tx8786\tx9563
\up0 \expndtw-2\charscalex100 % mass 28.9\tab \up0
\expndtw-2\charscalex100 3.5\tab \up0 \expndtw-2\charscalex100
48.6\tab \up0 \expndtw-2\charscalex100 0.5\tab \up0
\expndtw-2\charscalex100 0.7\tab \up0 \expndtw-2\charscalex100
12.0\tab \up0 \expndtw-2\charscalex100
5.8\par\pard\li2863\sb256\sl-264\slmult0\fi160 \up0
\expndtw-1\charscalex100 This coal is burned in the steam generator
of a large power plant with
150%\par\pard\li2863\sb133\sl-264\slmult0\fi160 \up0
\expndtw-2\charscalex100 theoretical air. Determine the air-fuel
ratio on a mass basis.\par\pard\li2863\sb253\sl-264\slmult0\fi160
\up0 \expndtw-2\charscalex100 Jawab
:\par\pard\li2863\sb215\sl-264\slmult0\fi0\tx5675\tx6567\tx7784\tx8939\tx10092
\up0 \expndtw-2\charscalex100 zat\tab \up0 \expndtw-2\charscalex100
S\tab \up0 \expndtw-2\charscalex100 H\ul0\nosupersub\cf5\f6\fs18
2\tab \up0 \expndtw-2\charscalex100 \ul0\nosupersub\cf2\f3\fs23
C\tab \up0 \expndtw-2\charscalex100 O\ul0\nosupersub\cf5\f6\fs18
2\tab \up0 \expndtw-2\charscalex100 \ul0\nosupersub\cf2\f3\fs23
N\ul0\nosupersub\cf5\f6\fs18
2\par\pard\li2863\sb212\sl-264\slmult0\fi0\tx5675\tx6567\tx7784\tx8939\tx10092
\up0 \expndtw-2\charscalex100 \ul0\nosupersub\cf2\f3\fs23 c/M =\tab
\up0 \expndtw-2\charscalex100 0.5/32\tab \up0
\expndtw-2\charscalex100 3.5/2\tab \up0 \expndtw-2\charscalex100
4.86/12\tab \up0 \expndtw-2\charscalex100 12/32\tab \up0
\expndtw-2\charscalex100
0.7/28\par\pard\li2863\sb215\sl-264\slmult0\fi0\tx5675\tx6567\tx7784\tx8939\tx10092
\up0 \expndtw-2\charscalex100 kmol / 100 kg coal\tab \up0
\expndtw-2\charscalex100 0.0156\tab \up0 \expndtw-2\charscalex100
1.75\tab \up0 \expndtw-2\charscalex100 4.05\tab \up0
\expndtw-2\charscalex100 0.375\tab \up0 \expndtw-2\charscalex100
0.025\par\pard\li2863\sb212\sl-264\slmult0\fi0\tx5840\tx7784 \up0
\expndtw-2\charscalex100 produk\tab \up0 \expndtw-2\charscalex100
SO\ul0\nosupersub\cf5\f6\fs18 2 \ul0\nosupersub\cf2\f3\fs23
H\ul0\nosupersub\cf5\f6\fs18 2\ul0\nosupersub\cf2\f3\fs23 O\tab
\up0 \expndtw-2\charscalex100 CO\ul0\nosupersub\cf5\f6\fs18
2\par\pard\li2863\sb215\sl-264\slmult0\fi0\tx5675\tx6567\tx7784\tx8939\tx10092
\up0 \expndtw-2\charscalex100 \ul0\nosupersub\cf2\f3\fs23 Oksigen
yang dibutuhkan\tab \up0 \expndtw-2\charscalex100 0.0156\tab \up0
\expndtw-2\charscalex100 0.875\tab \up0 \expndtw-2\charscalex100
4.05\tab \up0 \expndtw-2\charscalex100 --\tab \up0
\expndtw-2\charscalex100 --\par\pard\ql \li3385\sb0\sl-264\slmult0
\par\pard\ql\li3385\sb0\sl-264\slmult0
\par\pard\ql\li3385\sb177\sl-264\slmult0 \up0
\expndtw-3\charscalex100 Pembakaran membutuhkan : \par\pard\ql
\li3442\sb217\sl-264\slmult0 \up0 \expndtw-3\charscalex100 0.0156 +
0.875 + 4.05 = 4.9406 \par\pard\ql \li3385\sb217\sl-264\slmult0
\up0 \expndtw-5\charscalex100 Batu bara tidak termasuk 0.375
O\ul0\nosupersub\cf5\f6\fs18 2 \par\pard\ql
\li3024\ri1619\sb92\sl-390\slmult0\fi360\tx3385 \up0
\expndtw-2\charscalex100 \ul0\nosupersub\cf2\f3\fs23 Sehingga hanya
4.5656 O\ul0\nosupersub\cf5\f6\fs18 2 \ul0\nosupersub\cf2\f3\fs23
dari air/100 kg coal,\ul0\nosupersub\cf4\f5\fs22 karena mol
O\ul0\sub\cf6\f7\fs21 2\ul0\nosupersub\cf4\f5\fs22 seluruhnya
\line\tab \up0 \expndtw-4\charscalex100 dikurangkan mol d kulit
yaitu : O\ul0\sub\cf6\f7\fs21 2\ul0\nosupersub\cf4\f5\fs22 bersih =
4,9406 - 0,375 = 4,5656 \line \up0 \expndtw-4\charscalex100
\ul0\nosupersub\cf2\f3\fs23 AF = 1.5 (4.5656 + 4.5656 3.76)
28,97/100 = \ul0\nosupersub\cf7\f8\fs23 9.444 kg air/kg coal {\shp
{\*\shpinst\shpleft7821\shptop11539\shpright9738\shpbottom11560\shpfhdr0\shpbxpage\shpbypage\shpwr3\shpwrk0\shpfblwtxt1\shpz1266\shplid0{\sp{\sn
shapeType}{\sv 0}}{\sp{\sn fFlipH}{\sv 0}}{\sp{\sn fFlipV}{\sv
0}}{\sp{\sn geoRight}{\sv 1917}}{\sp{\sn geoBottom}{\sv
21}}{\sp{\sn pVerticies}{\sv
8;4;(0,21);(1917,21);(1917,0);(0,0)}}{\sp{\sn pSegmentInfo}{\sv
2;10;16384;45824;1;45824;1;45824;1;45824;24577;32768}}{\sp{\sn
fFillOK}{\sv 1}}{\sp{\sn fFilled}{\sv 1}}{\sp{\sn fillColor}{\sv
0}}{\sp{\sn fLine}{\sv 0}}{\sp{\sn lineType}{\sv 0}}{\sp{\sn
fArrowheadsOK}{\sv 1}}{\sp{\sn fBehindDocument}{\sv 1}}{\sp{\sn
lineColor}{\sv
0}}}}\par\pard\sect\sectd\fs24\paperw11900\paperh16820\pard\sb0\sl-240{\bkmkstart
Pg3}{\bkmkend Pg3}\par\pard\ql \li2664\sb0\sl-393\slmult0
\par\pard\ql\li2664\sb0\sl-393\slmult0
\par\pard\ql\li2664\sb0\sl-393\slmult0
\par\pard\ql\li2664\ri1533\sb197\sl-393\slmult0\tx3024\tx3024\tx3024
\up0 \expndtw-1\charscalex100 \ul0\nosupersub\cf2\f3\fs23
3.\ul0\nosupersub\cf3\f4\fs23 \ul0\nosupersub\cf2\f3\fs23 Repeat
Problem 14.26 for a certain Utah coal that contains, according to
the \line\tab \up0 \expndtw0\charscalex103 coal analysis, 68.2% C,
4.8% H, 15.7% O on a mass basis. The exiting \line \tab \up0
\expndtw-4\charscalex100 product gas contains 30.9% CO, 26.7%
H\ul0\nosupersub\cf8\f9\fs20 2\ul0\nosupersub\cf2\f3\fs23 , 15.9%
CO\ul0\nosupersub\cf8\f9\fs20 2 \ul0\nosupersub\cf2\f3\fs23 and
25.7% H\ul0\nosupersub\cf8\f9\fs20 2\ul0\nosupersub\cf2\f3\fs23 O
on a \line \tab \up0 \expndtw-4\charscalex100 mole basis.
\par\pard\ql \li2664\sb123\sl-253\slmult0 \up0
\expndtw-3\charscalex100 \ul0\nosupersub\cf4\f5\fs22 Jawab :
\par\pard\li3385\sb0\sl-264\slmult0\par\pard\li3385\sb64\sl-264\slmult0\fi0\tx9603
\up0 \expndtw0\charscalex100 \ul0\nosupersub\cf2\f3\fs23
Mengkonversi konsentrasi massa untuk sejumlah kmol per\tab \up0
\expndtw0\charscalex100
100kg\par\pard\li3385\sb133\sl-264\slmult0\fi0 \up0
\expndtw0\charscalex100 batubara
:\par\pard\li3385\sb212\sl-264\slmult0\fi0\tx6625 \up0
\expndtw0\charscalex100 C : 68.2/12.01 = 5.679\tab \up0
\expndtw0\charscalex100 H\ul0\nosupersub\cf5\f6\fs18
2\ul0\nosupersub\cf2\f3\fs23 : 4.8/2.016 = 2.381\par\pard\ql
\li3385\sb216\sl-264\slmult0 \up0 \expndtw-3\charscalex100
O\ul0\nosupersub\cf5\f6\fs18 2\ul0\nosupersub\cf2\f3\fs23 :
15.7/32.00 = 0.491 \par\pard\ql \li3385\sb197\sl-264\slmult0 \up0
\expndtw-3\charscalex100 Sekarang persamaan pembakaran menjadi :
\par\pard\ql \li3745\sb217\sl-264\slmult0 \up0
\expndtw-3\charscalex100 x(5.679 C + 2.381
H\ul0\nosupersub\cf5\f6\fs18 2 \ul0\nosupersub\cf2\f3\fs23 + 0.491
O\ul0\nosupersub\cf5\f6\fs18 2\ul0\nosupersub\cf2\f3\fs23 ) + y
H\ul0\nosupersub\cf5\f6\fs18 2\ul0\nosupersub\cf2\f3\fs23 O + z
O\ul0\nosupersub\cf5\f6\fs18 2 di\ul0\nosupersub\cf2\f3\fs23 dalam
\par\pard\qj \li3385\ri1534\sb104\sl-400\slmult0\fi360 \up0
\expndtw-4\charscalex100 30.9 CO + 26.7
H\ul0\nosupersub\cf5\f6\fs18 2 \ul0\nosupersub\cf2\f3\fs23 + 15.9
CO\ul0\nosupersub\cf5\f6\fs18 2 \ul0\nosupersub\cf2\f3\fs23 + 25.7
H\ul0\nosupersub\cf5\f6\fs18 2\ul0\nosupersub\cf2\f3\fs23 O diluar
100kmol campuran \up0 \expndtw-4\charscalex100 keluar \par\pard\qj
\li3385\ri1535\sb81\sl-400\slmult0 \up0 \expndtw0\charscalex101
Sekarang kita bisa melakukan keseimbangan atom untuk menemukan \up0
\expndtw-3\charscalex100 (x, y, z)
\par\pard\li3747\sb190\sl-264\slmult0\fi0\tx7345 \up0
\expndtw-3\charscalex100 C : 5.679x = 30.9 + 15.9\tab \up0
\expndtw-3\charscalex100 \u8594? x = 8.241\par\pard\ql
\li3745\sb200\sl-264\slmult0 \up0 \expndtw-3\charscalex100
H\ul0\nosupersub\cf5\f6\fs18 2\ul0\nosupersub\cf2\f3\fs23 : 2.381
8.241 + y = 26.7 + 25.7 \u8594? y = 32.778 \par\pard\qj
\li3385\ri1534\sb104\sl-400\slmult0\fi360 \up0
\expndtw0\charscalex102 O\ul0\nosupersub\cf5\f6\fs18
2\ul0\nosupersub\cf2\f3\fs23 : 0.491 8.241 +32,778/2 + z = 30,92/2+
15.9 + 25,7/2 \u8594? z = \up0 \expndtw-3\charscalex100 23,765
\par\pard\ql \li3620\sb0\sl-264\slmult0
\par\pard\ql\li3620\sb0\sl-264\slmult0
\par\pard\ql\li3620\sb125\sl-264\slmult0 \up0
\expndtw-3\charscalex100 Oleh karena itu,untuk 100kmol campuran
keluar \par\pard\ql \li5206\sb217\sl-264\slmult0 \up0
\expndtw-3\charscalex100 Memerlukan : \par\pard\ql
\li4791\sb217\sl-264\slmult0 \up0 \expndtw-3\charscalex100
\ul0\nosupersub\cf7\f8\fs23 824.1\ul0\nosupersub\cf2\f3\fs23 kg
dari batu bara \par\pard\ql \li4870\sb217\sl-264\slmult0 \up0
\expndtw-3\charscalex100 \ul0\nosupersub\cf7\f8\fs23
32.778\ul0\nosupersub\cf2\f3\fs23 kmol dari uap \par\pard\ql
\li4678\sb217\sl-264\slmult0 \up0 \expndtw-3\charscalex100
\ul0\nosupersub\cf7\f8\fs23 23.765\ul0\nosupersub\cf2\f3\fs23 kmol
dari oksigen \par\pard\sect\sectd\fs24}
