2. Chun dd baz yu a. dd baz yu n chc

BOH + HCl BCl + H2O* CV = 0 => F = 0 (cha chun )

Dd ( BOH) =>pHo=14- (pKb lgCo)* 0 < CV < CoVo => 0 < F < 1BOH + HCl BCl + H2O

Dd BOH:

BCl:Dd n baz yu

)1lg(14)lg(14 001 FF

CVCVVCpH ==

VVCVVCCb +

=

0

00

VVCVCm

+=

0

* CV = CoVo => F = 1

BOH + HCl BCl + H2ODd (BCl)

* CV > CoVo => F > 1 BOH + HCl BCl + H2O

Dd HCl: BCl

)lg(0

0021

VVVCpKpKpH bnt +=

VVVCCVpH

+

=

0

002 lg

VVCVVCCm +

=

=

0

00

VVVCCVCa +

=

0

00

ng cong chun :Td: Chun 10ml dd NH4OH 0,1 M (pKb= 4,8) bng dd HCl 0,1 M NH4OH + HCl NH4Cl + H2O CoVo CVF Cng thc tnh pH pH Ghi ch0,0 pHo= 14- (4,8-lg0,1) 11,1 Cha c.

0,5 pH0,5=14-(pKb-lgCa/Cm) 9,2

1,0 pHt = [14-4,8-lg(0,1)/2] 5,25 t

1,5 pH2= -lg[(15.0,1-10.0,1)/(10+15)] 1,6

Nhn xt

im tng ng ti min axit Cht ch th thch hp nht cho php chun ny l metyl da cam, metyl