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7/13/2019 Bo Co Th Nghim iu Khin Qu Trnh (3)
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BO CO TH NGHIMIU KHIN QU TRNH
Bi1:Xy dng hthng iu khin mt bnh mc
Bi 2: Xy dng hthng iu khin hai bnh mcthng nhau
Hv tn:ng V Trung
SHSV:20092850
Lp: K-TH 7K54
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SHSV ca em l 20092850 nn em chn stoptime l 2850
BI 1XY DNG HTHNG IU KHIN MT BNH MC
1: Xy dng m hnh cho i tng bnh mc
a.Xc nh tn hiu vo, tn hiu ra v nhiu ca hthng
-Tn hiu vo:mvan vo F1 F2-Tn hiu ra: cao mc cht lng h F1 h
-Nhiu : mvan ra F2
b.Xy dng m hnh ton hc i vi cc tham shnh thc.
Phng trnh cn bng khi lng:
A
=F1-F2
Bin i sang min Laplace:
A.s.h(s)=F1(s)-F2(s). Do t=0 th F2(s)0
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G(s)=
Van F1 ng mc dng:
Hm truyn hthng: G(s)=
c. Sdng Simulink xc nh tham sm hnh
Thay i cc thng strn Single-Tank theo shiu sinh vin v lp
-M phng trn Simulink
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p ng nhn c
-Khi h(t) c kch thch bng tn hiu step ta c thhm qu nh trn
-Ktip tuyn vi thhm qu h(t) ta xc nh c tham s;
T=3.5 v K=tan()=2.8
-Vy hm truyn ca hthng:
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G(s)
*Kim tra li kt qubng m hnh:
- Ta c thhm qu nh hnh sau:
Tthta thy p ng qu ph hp vi p ng m phng => btham sK=2.8,T=3.5 l ph hp
2: Cc sch lc iu chnh:
-Cc sch lc c thiu khin trong bi ton:
+iu khin phn hi
+iu khin tng
-Cc sch lc khng iu khin c:
+iu khin truyn thng
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+ iu khin la chn
+ iu khin phn vng
+ iu khin tl
*Gii thch:
-Sch lc c thiu khuyn c:
+ Sch lc phn hi vng n: c thdng c v khi o mc nc trongbnh sc so snh vi gi trt bk PID a ra quyt nh iu khuyn
+Sch lc iu khuyn tng: c thdng c v sch lc ny gm 2 vngn, vng 1: so snh gia gi trt v mc nc a ra quet nh iu
khuyn, vng 2: so snh gia lu lng ra, lu lng vo v tn hiu iukhuyn ca vng 1 a ra quyt nh dk
-Sch lc khng iu khuyn c
+ Sch lc truyn thng: khng dng c, v hthng van l hthng cqun tnh nn vi sch lc ny khi chng ta a ra quyt nh k th strmtmt thi gian hmi chp hnh v v khng c phn hi nn hskhng nnh
+ iu khin la chn, iu khin phn vng yu cu c t nht l 2 bin iukhin, m bnh mc chi c 1 bin iu khin, nn khng xc nh c tnhiu iu khin ln t => khng c p dng sch lc ny.
+ iu khin tlc p dng cho hthng : duy tr quan h gia 2 binnhm iu khin gin tip bin th3, m iu khin bnh mc ch c 1 biniu khin nn khng c p dng.
Bng tham stheo cng thc ZieglerNichols
Biu khin Kp Ti TdP 1/K = 0.36 0 0PI 0.9/K = 0.321 10T/3 = 11.67 0PID 1.2/K = 0.429 2T = 7 0.5T=1.75
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3:Lu P&ID ca sch lc truyn thng
*M phng trn Simulink
a : Vi biu khin P
Chn tham sKp = 0.357 ,Ti=0 , Td=0
Level
SP
OutValve
Single-
Tank
GUI
Tank GUIMax Level = 1000
In Valve
Out Valve
Level
In Flow
Out Flow
SINGLE-
TANK
Single-TankCourse = 54
Class = 7
Number = 50
Scope1
Scope
PID
PID Controller
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Kt qu: hin thtrn Scope
*Nhn xt: mc nc trong bnh tng lin tc cho ti khi trn bnh chng ththng khng n nh => khng th p dng sch lc ny.
b : Sdng biu khin PI
Chn cc tham s: KP = 0.321 , Ti = 11.67 , Td=0
Kt qu: thmc nc ca biu khin PI hin thtrn Scope
0 500 1000 1500 2000 2500 30000
100
200
300
400
500
600
700
800
900
1000 2
1
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*Nhn xt: Mc nc trong bnh vn khng bm xung quanh gi trsetpoint .Biu khin PI cng khng sdng c trong sch lc ny.
c : Sdng biu khin PIDChn cc tham s: KP = 1.7 , Ti = 0.43, Td=6.8
Kt qu: thmc nc ca biu khin PID
0 500 1000 1500 2000 2500 30000
100
200
300
400
500
600
700
800
900
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*Nhn xt: mc nc trong bnh tng qu mc gi trt ri li gim v
mc khng do mvan =>> dng bphng php iu khin ny hthngkhng n nh
4 :Sch lc phn hi vng n
*Lu P&ID sch lc phn hi vng n:
0 500 1000 1500 2000 2500 30000
100
200
300
400
500
600
700
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*M phng bng Simulink
a , Biu khin tlP cho sch lc phn hi vng n
Chn tham sKp = 0.357 ,Ti=0 , Td=0
thp ng thu c:
Scope
Level
SP
OutValve
Single-
Tank
GUI
Tank GUI
Max Level = 1000
In Valve
Out Valve
Level
In Flow
Out Flow
SINGLE-
TANK
Single-Tank
Course = 54
Class = 7
Number = 50
Scope1
Scope
PID
PID Controller
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Scope1
0 500 1000 1500 2000 2500 30000
100
200
300
400
500
600
700
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Tthta thy :
Mc nc trong bnh tng n vtr setpoint ri dng li v lun gin nh ti gi tr
.b , Biu khin PI cho sch lc phn hi vng n
Chn cc tham s: KP = 0.321 , Ti = 11.67 , Td=0
Kt qu:thmc nc trong bnh
0 500 1000 1500 2000 2500 30000
0.5
1
1.5
2
2.5
3x 10
4
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Scope 1:
0 500 1000 1500 2000 2500 30000
100
200
300
400
500
600
700
800
900
1000
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*Nhn xt: mc nc trong bnh ban u c dao ng quanh gi trt SP,sau bin dao ng gim dn, v dng hn ti gi trt
Mc nc km n nh hn so vI bP do khu tch phn Ic , Biu khin PID cho sch lc phn hi vng n
Chn cc tham s: KP = 0.429 , Ti = 7, Td=1.75
Kt qu: thmc nc trong bnh
0 500 1000 1500 2000 2500 30000
0.5
1
1.5
2
2.5
3x 10
4
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Scope:
Scope1:
0 500 1000 1500 2000 2500 30000
100
200
300
400
500
600
700
800
900
1000
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=>>Nhn xt:Biu khin PID c thi gian qu v qu iu chnh ln hn sovi biu khin PI v biu khin P.Nn bPID km n nh hn bPI v km nnh hn so vi bP
=>>Nhn xt chung: iu khuyn bnh mc thc cht c khu tch phn nn khichn biu khuyn ta chcn chon bP l , nu dng bPI hoc PID do cthnh phn tch phn nn dgy ra hin tng bo ha tch phn.
*, Hin tng bo ha tch phn l hin tng u ra ca biu chnh vn tiptc tng qu mc giI hn khi sai lch iu khuyn trv0.
*,Bin php khc phc:
- Sdng khu b thnh phn tch phn- Ct bthnh phn tch phn khi gi trc iu khin t ti gi trt
D:Sdng khu chng bo ha tch phn:+ PI-RW: S :Khu PI ni tip vi khu chng bo ha tch phn
0 500 1000 1500 2000 2500 30000
0.5
1
1.5
2
2.5
3x 10
4
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Trong :Thng sca khu PI-RW c xc nh theo Zinger Nicol1 nh sau:Gain:K=Kc=0.321Gain1:K=1/Ti=0.0857Gain2:K=1/Tt=4/Ti=0.343
S simulink:
p ng thu c l:
Scope
Level
SP
OutValve
Single-
Tank
GUI
Tank GUIMax Level = 1000
In1 Out1
Subsystem
In Valve
Out Valve
Level
In Flow
Out Flow
SINGLE-
TANK
Single-TankCourse = 54
Class = 7
Number = 50
Scope1
Scope
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Scope1:
0 500 1000 1500 2000 2500 30000
100
200
300
400
500
600
700
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+ PID-RW:
S :Khu PID ni tip vi khu chng bo ha tch phn:
Trong :Thngsca khu PID-RW c xc nh theo Zinger Nicol1 nh sau:Gain:K=Kc=0.429Gain1:K=1/Ti=0.143.Gain2:K=1/Tt=4/Ti=0.512Gain3:K=1.75
0 500 1000 1500 2000 2500 30000
5000
10000
15000
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p ng thu c
Scope:
Scope1:
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*Nhn xt: mc nc trong bnh tng (gim) ti gi trt v ng nguyn tivtr , khc dao ng do thnh phn tch phn gy ra.
*Cn phi o lu lng ra v:
Khi olu lng ra, p ng ca hthng n nh ko phthuc vo sthayi ca lu lng ra, ta gim c snh hng ca tn hiu nhiu
6. Sch lc iu khin tng
* Gii thch ti sao cn sdng iu khin tng:
- Vng iu khin n cha p ng c yu cu cht lng- Ta c thdng o c v iu khin c bin qu trnh th2 c lin
quan ti bin thnht- c tnh ng hc ca bin th2 nhanh hn bin thnht
*Xc nh cc vng iu khin , nhim vv c im tng vng
- Vng iu khin:
+Vng 1(vng ngoi): o mc ca bnh ri phn hili so snh vi SP1
+ Vng 2(vng trong):o hiu lu lng Out Flow & In Flow,phn hi
li so snh vi gi tr u ra ca vng 1(l gi trSet Poit cho vng 2)
- Nhim vv c im ca tng vng:+ Vng 1: so snh gi tr SP1 vI mc ca bnh cha cho ta lu
lng vo mong mun (gi tr SP2 cho vng 2) .+ Vng 2 : so snh SP2 vI hi u lu lng Out Flow & In Flow cho ta
tn hiu iu khin ( mvan ph hp)+ Vng 2 c c tnh ng hc bin I nhanh hn c tnh ng hcca vng 1
* M phng Simulink
- Trng hp khng o lu lng ra:
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a , biu khin P-P
Hsvng ngoi K=1000. Vng trong K=1000.Ta c thsau:
Scope
Level
SP
OutValve
Single-
Tank
GUI
Tank GUIMax Level = 1000
In1 Out1
Subsystem1
In Valve
Out Valve
Level
In Flow
Out Flow
SINGLE-TANK
Single-Tank1Course = 54
Class = 7
Number = 50
Scope1
Scope
PID
PID Controll er
0 500 1000 1500 2000 2500 30000
100
200
300
400
500
600
700
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Scope1:
-Trng hp c o lu lng ra
* M phng trn Simulink
0 500 1000 1500 2000 2500 30000
5000
10000
15000
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Kt qu:ta c thsau:
b. Biu khin P/PI -RW
Level
SP
OutValve
Single-
Tank
GUI
Tank GUI
Max Level = 1000
0:11
0:4
In1 Out1
Subsystem1
In Valve
Out Valve
Level
In Flow
Out Flow
SINGLE-TANK
0:0
Single-Tank1
Course = 54
Class = 7
Number = 50
0:3
Scope1
0:2
Scope
PID
PID Controller
0 500 1000 1500 2000 2500 30000
100
200
300
400
500
600
700
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Vng ngoi l biu khin P vi K=1000, vng trong l biu khin PI-RW
Trong :Thng sca khu PI-RW c xc nh theo Zinger Nicol1 nh sau:Gain:K=Kc=0.357Gain1:K=1/Ti=0.0857Gain2:K=1/Tt=4/Ti=0.343
S simulink:
Kt qum phng
Level
SP
OutValve
Single-
Tank
GUI
Tank GUIMax Level = 1000
In1 Out1
Subsystem
In Valve
Out Valve
Level
In Flow
Out Flow
SINGLE-
TANK
Single-TankCourse = 54
Class = 7
Number = 50
Scope1
Scope
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Scope:
Scope1:
0 500 1000 1500 2000 2500 30000
100
200
300
400
500
600
700
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c. Biu khin P/PID-RW
Vng ngoi l biu khin P vi K=1000, vng trong l biu khin PI-RW
Trong :Thng sca khu PID-RW c xc nh theo Zinger Nicol1 nh sau:Gain:K=Kc=0.429Gain1:K=1/Ti=0.143.Gain2:K=1/Tt=4/Ti=0.512Gain3:K=1.75
Kt qum phng
Scope: Scope1
0 500 1000 1500 2000 2500 30000
5000
10000
15000
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Nhn xt:M phng vi cc biu khin khc nhau, ta u thu c kt qugnging nhau.
Vy :Khi o lu lng ra, p ng ca hthng n nh ko phthuc vo sthayi ca lu lng ra, ta gim c snh hng ca tn hiu nhiu
- Overshoot nh- Sai lch gia INFLOW & OUTFLOW nh
So snh hai trng hp:
- Trng hp o lu lng ra khi hthng n nh , thay i lu lng ra thhthng vn n nh
- Trng hp khng o lu lng ra khi hthng n nh , thay i lu lngra th hthng mt n nh
- Trng hp o lu lng ra cho ta cht lng tt hn so vi khng o lulng ra
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BI 2
XY DNG HTHNG IU KHIN HAI BNH MC
THNG NHAU
1: Xy dng m hnh i tng:
-Xc nh tn hiu vo ra v nhiu : F3
+Tn hiu vo:F1,F2 F1 h1
+Tn hiu ra:h1,h2
+Nhiu:F3 F2 h2
Hthng hai binh mc
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2:Xy dng m hnh ton hc i vi cc tham shnh thc
A1
F1-F2
A2
=F2-F3
*Chuyn sang min Laplace:
=>> A1.s.H1(s)=F1(s)-F2(s)
A2.s.H2(s)=F2(s)-F3(s)
G1(s)=
G1(s)=
.G1(s)=
G2(s)=
G2(s)=
G2(s)=
3: M phng trn Simulink:
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Valve 1
Valve 2
Valve 3
Level 1
Level 2
Flow 1
Flow 2
Flow 3
TWO-
TANK
Two-TankCourse = 54
Class = 7
Number = 50
Step
Scope1
Scope
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-Tng tkt qubi 1:Ta ktip tuyn v xc nh hsT1,K1 cho khi Scope
Ta c T1=3.4 v K1=3.2
thhm qu h1(t) khi scope(trn) v h2(t) khi scope1 (di)
Ktip tuyn vi thh(t) ta xc nh c :
- K2= tan=0.5
- Thi gian tr:=2.0
- T2=2.7
* Kim chng m hnh
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thkim chng m hnh :
Scope
Scope1
Valve 1
Valve 2
Valve 3
Level 1
Level 2
Flow 1
Flow 2
Flow 3
TWO-
TANK
Two-TankCourse = 54
Class = 7
Number = 50
3.2
3.4s+1
Transfer Fcn1
0.5
2.7s+1
Transfer Fcn
Step
Scope1
Scope
1
s
Integrator1
1
s
Integrator
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Nhn xt :Bqua sai sthhm qu gn ging vi tnh ton => c thchn cc btham schn trn
Bng tham stheo cng thc ZieglerNicholsBnh 1
Biu khin Kp Ti Td
P 1/K1 = 0.313 0 0PI 0.9/K1 = 0.282 10T1/3 = 11.33 0PID 1.2/K1 = 0.375 2T1 = 6.8 0.5T1=1.7Bnh 2
Biu khin Kp Ti TdP 1/K2 = 2 0 0PI 0.9/K2 = 1.8 10T2/3 = 9 0PID 1.2/K2 = 2.4 2T2 = 5.4 0.5T2=1.35
4 :Cc sch lc iu khin
1. iu khin vng phn hi n.2. iu khin tng.
Sch lc truyn thng khng dng c, v hthng van l hthng cqun tnh nn vi sch lc ny khi chng ta a ra quyt nh k th str
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mt mt thi gian hmi chp hnh v v khng c phn hi nn hskhng n nh.
5 : iu khin phn hi vng n kt hp b nhiu
a.Biu khin P-P
M phng trn Simulink :
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Kt quthu c:Scope: Scope1
Level1
Level2
Valve
SP1
SP2
Valve1
Valve2
Valve3
Two-Tank
GUI
Two-Tan k GUI
Max Height 1 = 1000
Max Height 2 = 1000
Valve 1
Valve 2
Valve 3
Level 1
Level 2
Flow 1
Flow 2
Flow 3
TWO-
TANK
Two-Tank
Course = 54
Class = 7
Number = 50
In1 Out1
Subsystem1
In1 Out1
Subsystem
Scope3
Scope2
Scope1
Scope
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b. Biu khin PI -RWS: Khu PI ni tip vi khu chng bo ha tch phn:
S simulink:
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Trong :- Biu khin PI-RW 1 c cc thng sxc nh theo ziegler Nichol 1 l:
Gain: K=Kc=0.282Gain1:K=1/Ti=0.083Gain2:K=1/Tt=4/Ti=0.353
- Biu khin PI-RW 2 c cc thng sxc nh theo ziegler Nichol 1 l:Gain: K=Kc=1.8Gain1:K=1/Ti=0.11Gain2:K=1/Tt=4/Ti=0.444
Kt quthu c:
Scope: Scope1
Level1
Level2
Valve
SP1
SP2
Valve1
Valve2
Valve3
Two-Tank
GUI
Two-Tan k GUI
Max Height 1 = 1000
Max Height 2 = 1000
Valve 1
Valve 2
Valve 3
Level 1
Level 2
Flow 1
Flow 2
Flow 3
TWO-
TANK
Two-Tank
Course = 54
Class = 7
Number = 50
In1 Out1
Subsystem1
In1 Out1
Subsystem
Scope3
Scope2
Scope1
Scope
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So snh Set Point vi Level
Mc nc trong bnh dao ng quanh SP1 ri sau n nh ti SP1Mc nc trong bnh dao ng quanh SP2 sau n nh ti gi trnh(ln) hn SP2 c sai lch phthuc vo mvan
c. Biu khin PID-RW:S : Khu PID ni tip vi khu chng bo ha tch phn
Trong :- Biu khin PID-RW 1 c cc thng sxc nh theo ziegler Nichol 1 l:
Gain: K=Kc=0.375Gain1:K=1/Ti=0.147
Gain2:K=1/Tt=4/Ti=0.588
Gain3:K=Td=1.7- Biu khin PID-RW 2 c cc thng sxc nh theo ziegler Nichol 1 l:
Gain: K=Kc=2.4Gain1:K=1/Ti=0.1853
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Gain2:K=1/Tt=4/Ti=0.74
Gain3:K=Td=1.35
Kt qum phng:Scope: Scope1
Nhn xt :
Mc nc trong bnh tng nhanh ti gi trt ca bnh 1
Mc nc trong bnh t ti gi trt v n nh ti mc .
6/Sch lc iu khin tng
a. Lu P&ID.
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b.M phng vi cc biu khin:+) Vng ngoi l biu khin P (ly Kp = 1000) , vng trong l biukhin P (Kp = 10000)
S :
Scope: Scope1
Level1
Level2
Valve
SP1
SP2
Valve1
Valve2
Valve3
Two-Tank
GUI
Two-Tank GUIMax Height 1 = 1000
Max Height 2 = 1000
Valve 1
Valve 2
Valve 3
Level 1
Level 2
Flow 1
Flow 2
Flow 3
TWO-
TANK
Two-Tank
Course = 54Class = 7
Number = 50
In1 Out1
Subsystem2
In1 Out1
Subsystem1
Scope3
Scope2
Scope1
Scope
PID
PID Controller3
PID
PID Controller2
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Nhn xt
- So snh gia Level1 v SP1
Mc nc trong bnh 1 tin nhanh ti SP1 v n nh ti im ny
- So snh gia Level2 v SP2
Mc nc tng nhanh v n nh kh st SP2
+)Biu khin P/PI-RW
Vng ngoi l biu khin P (Kp =1000), vng trong l biu khinPI-RWTrong :- Biu khin PI-RW 1 c cc thng sxc nh theo ziegler Nichol 1 l:
Gain: K=Kc=0.282Gain1:K=1/Ti=0.083Gain2:K=1/Tt=4/Ti=0.353
- Biu khin PI-RW 2 c cc thng sxc nh theo ziegler Nichol 1 l:Gain: K=Kc=1.8Gain1:K=1/Ti=0.11
Gain2:K=1/Tt=4/Ti=0.444S :
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Kt qum phng
Scope: Scope1
Level1
Level2
Valve
SP1
SP2
Valve1
Valve2
Valve3
Two-Tank
GUI
Two-Tank GUIMax Height 1 = 1000
Max Height 2 = 1000
Valve 1
Valve 2
Valve 3
Level 1
Level 2
Flow 1
Flow 2
Flow 3
TWO-
TANK
Two-TankCourse = 54
Class = 7
Number = 50
In1 Out1
Subsystem2
In1 Out1
Subsystem1
Scope3
Scope2
Scope1
Scope
PID
PID Controller3
PID
PID Controller2
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+)Biu khin P/PID-RD
- Vng ngoi l biu khin P (Kp =1000), vng trong l biu khin
PID-RWTrong :- Biu khin PID-RW 1 c cc thng sxc nh theo ziegler Nichol 1 l:
Gain: K=Kc=0.375
Gain1:K=1/Ti=0.147Gain2:K=1/Tt=4/Ti=0.588
Gain3:K=Td=1.7- Biu khin PID-RW 2 c cc thng sxc nh theo ziegler Nichol 1 l:
Gain: K=Kc=2.4Gain1:K=1/Ti=0.1853
Gain2:K=1/Tt=4/Ti=0.74Gain3:K=Td=1.35
M hnh
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Kt qum phng:
Scope: Scope1
Nhn xt: mc nc lc u cha n nh ti Set Point do mvan ra ca
bnh 2 nhng sau mc nc c n nh=>> Nhn xt chung : hthng vi sch lc k tng c cht lng tt nht so vicc sch lng cn li, sai lch nhhn, t phthuc vo lu lng ra ca bnh 2nht
Level1
Level2
Valve
SP1
SP2
Valve1
Valve2
Valve3
Two-Tank
GUI
Two-Tank GUIMax Height 1 = 1000
Max Height 2 = 1000
Valve 1
Valve 2
Valve 3
Level 1
Level 2
Flow 1
Flow 2
Flow 3
TWO-
TANK
Two-TankCourse = 54
Class = 7
Number = 50
In1 Out1
Subsystem2
In1 Out1
Subsystem1
Scope3
Scope2
Scope1
Scope
PID
PID Controller3
PID
PID Controller2
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