GII THIU BO V IN P V RLE IN P PH5354
Phn 11:
HNG DN VN HANH - TH NGHIM RLE QUA - KEM AP PH53, PH54I. GII THIU
CHUNG : Cht lng in nng cung cp c anh gia qua 2 chi tiu ma in ap n
inh la mt trong 2 chi tiu quan trong o. in ap cao qua hay thp qua u
anh hng ln n cht lng in nng, tui tho va kha nng lam vic cua thit bi
tiu thu in, anh hng n moi mt trong i sng kinh t, chinh tri, xa hi
va an ninh quc phong. Vi vy vic phat hin va ngn nga cac tinh trang
bt thng trong n inh in ap cn phai c t ra trong cac s bao v, iu
khin. Bao v in ap c chia thanh 02 loai : bao v qua in ap va bao v
kem in ap. 1. Chc nng bao v qua in ap : Phn t bao v loai nay lam
vic theo s tng cua cac thanh phn in ap. Khi in ap a vao phn t bao v
vt qua tri s t cua no, rle se tac ng khep cac tip im u ra a tin hiu
lam vic cua bao v qua in ap n cac c cu chp hanh hoc canh bao tin
hiu. 2. Chc nng bao v kem ap : Phn t bao v loai nay lam vic theo s
giam cua cac thanh phn in ap. Khi in ap a vao phn t bao v giam thp
vt qua tri s t cua no, rle se tac ng khep cac tip im u ra a tin hiu
lam vic cua bao v kem in ap n cac c cu chp hanh hoc canh bao tin
hiu. Tin hiu in ap a vao rle co th la mt trong hoc cac thanh phn th
t thun, th t nghich, th t khng. Tng ng vi cac tin hiu in ap cung
cp, ta se co cac loai rle bao v qua - kem ap th t thun, th t
nghich, va qua ap th t khng (cham t). II. NGUYN LY LAM VIC CUA CHC
NNG QUA - KEM AP : 1. Nguyn ly lam vic cua chc nng bao v qua ap :
Bao v qua ap co nhim vu bao v cac thit bi in khoi cac tinh trang
tng in ap khng cho phep. Qua ap co th xut hin do mt tinh trang vn
hanh khng chinh xac cua cac h thng kich thich, li h hong trong b iu
chinh in ap, s sa thai tai cua cac may phat in hay cac may phat bi
tach lia ra khoi h thng. Tin hiu in ap t mach nhi th cua may bin in
ap TU sau khi vao rle se c bin i thanh cac tin hiu phu hp va/hoc
loc nh cac b loc, a vao c cu so sanh. y se so sanh tin hiu nhn c vi
cac ngng t lam vic cua rle. Nu gia tri nay ln hn ngng t thi khi so
sanh se cho tin hiu u ra a n cac c cu tao thi gian tr cua bao v.
Sau khi thi gian tr kt thuc thi tin hiu u ra cua b phn tao thi gian
tr se tac ng n cac c cu trung gian (nu co) va c cu chp hanh. 2.
Nguyn ly lam vic cua chc nng bao v kem ap : Bao v kem ap co nhim vu
bao v cac thit bi in khoi cac tinh trang giam in ap khng cho phep,
ngn nga cac tinh trang vn hanh khng cho phep va co th gy mt n inh.
Kem ap co th xut hin do mt tinh trang s c trong h thng in, co th la
s c ngn mach hoc mt tinh trang mt i xng khac cua li.
Tin hiu in ap t mach nhi th cua may bin in ap TU sau khi vao rle
se c bin i thanh cac tin hiu phu hp va/hoc loc nh cac b loc, a vao
c cu so sanh. y se so sanh tin hiu nhn c vi cac ngng t lam vic cua
rle. Nu gia tri nay thp hn ngng t thi khi so sanh se cho tin hiu u
ra a n cac c cu tao thi gian tr cua bao v. Sau khi thi gian tr kt
thuc thi tin hiu u ra cua b phn tao thi gian tr se tac ng n cac c
cu trung gian (nu co) va c cu chp hanh. 3. Nguyn ly lam vic cua chc
nng bao v qua ap th t khng : Cung tng t nh chc nng bao v qua ap,
bao v qua ap th t khng phan ng vi cac tinh trang tng gia tri cua in
ap th t khng xut hin khi co cham t trong mang. in ap th t khng co
th nhn c theo mt trong 2 cach : - La tng cua 3 in ap pha 3U0 = (UA
+ UB + UC) hoc - La in ap nhn c t cun dy ni tam giac h cua TU. Khi
co cham t hoc s c trong mang, in ap th t khng xut hin va tng ln.
Khi gia tri vao rle vt qua gia tri t trc, rle se khep tip im cua no
a tin hiu n cac trung gian hoc c cu chp hanh. II. S U NI CUA RLE PH
53, PH 54: ~TU
2AC/DC PH53/PH54
5 1
7 3
8 S u ni rle bao v in ap PH53/ PH54
III. NGUYN LY LAM VIC CUA RLE PH53, PH54 : 1.- Nguyn ly lam vic
cua rle PH53 : Rle PH53 la loai rle in c thc hin chc nng bao v qua
in ap. Nguyn ly lam vic cua rle nay co th m ta nh sau : Tin hiu in
ap t mach nhi th cua may bin in ap sau khi vao rle se c nn thanh
tin hiu mt chiu. Khi in ap vao rle u ln, lc in t do no sinh ra thng
c lc can cua mmen xon cua lo xo lam dich chuyn c cu a tip im ng
khep vao tip im tinh cua rle a tin hiu n tac ng cac c cu chp hanh.
2.- Nguyn ly lam vic cua rle PH54 : Rle PH54 la loai rle in c thc
hin chc nng bao v kem in ap. Nguyn ly lam vic cua rle nay co th c m
ta nh sau :
Binh thng in ap a vao rle u ln va lc in t ma no sinh ra u ln
thng c lc can cua lo xo lam tip im ng ri khoi tip im tinh cua no.
Khi in ap a vao rle giam xung di gia tri t cua no thi luc nay mmen
quay do lc in t sinh ra khng u thng c mmen can cua lo xo lam rle tr
v vi tri ban u di tac ng cua sc cng lo xo. IV. U NI MACH IN AP VA
CHINH INH TRI S T : Mach in ap u vao cua rle co th c ni qua 1 hoc 2
in tr. Khi in ap u vao c ni qua 1 in tr, in ap tac ng cua rle se
bng vi cac gia tri t trn thang t cua rle. Khi in ap u vao c ni qua
2 in tr, in ap tac ng se tng gp 2 ln so vi cac gia tri t trn thang
t. Nh vy t mach u ni cua mach in ap co th t cac tri s t cho s lam
vic cua rle thc hin chc nng bao v. Khi mach in ap vao rle c ni qua
2 in tr thi tri s t trn thang se bng 1/2 tri s t mong mun, con khi
mach in ap ni qua 1 in tr thi tri s t trn thang t cua rle se bng
ung gia tri t mong mun. chinh inh tri s t cho bao v, gat cn gat trn
thang t n gia tri mong mun vi chu y n s ni cua mach in ap vao rle.
V. TH NGHIM RLE BAO V IN AP PH53, PH54 : 1.- Cac chun bi ban u : +
Mt hp b phat in ap n 200V, + Mt ng h van nng o in ap, o kim tra tip
im, + Cac dy ni thi nghim, + Ngun thi nghim. 2.- Th nghim rle bao v
qua in ap PH53 : Thc hin theo cac bc th nghim sau y : + Kim tra c
khi cua rle : - S dich chuyn cua phn ng phai d dang quanh truc cua
no ma khng co ma sat ln, - Khe h doc truc cua phn ng nm trong gii
han 0,2 0,3mm, - Khe h gia gia cua phn ng va cac cc mach dn t khi
phn ng a bi hut phai u nhau va bng 0,55mm, - Khe h gia tip im tinh
va tip im ng trang thai m vao khoang 2,5mm, - Goc quay cua phn ng
va ca cach b tri cac tip im tinh i vi phn ng phai loai tr c kha nng
cham cu vao mt u cua tip im tinh khi quay phn ng lam ong cac tip
im, - Phn ng mang cu tip im ng tip xuc vi tip im tinh vi tri cach
mep ngoai khng xa va trt doc theo ng trung binh, - nen cua tip im
thng m khi phn ng bi hut phai bng vi nen tip im thng ong khi nha
phn ng (khoang 0,3mm), - Khi dich chuyn cn gat tri s t trn thang t
cua rle, cac vong cua lo xo xon c khng c cham nhau bt ky vi tri nao
cua thang o. + Kim tra tri s tac ng cua rle : - Cung cp mt in ap xp
xi vi gia tri in ap t trn thang rle.
Kim tra rle khng tac ng, phn ng khng dich chuyn. Tng dn gia tri
in ap cung cp cho rle cho n khi rle tac ng, phn ng dich chuyn lam
tip im ng khep vao tip im tinh cua no. Ghi lai gia tri tac ng nay.
- Giam dn in ap cho n khi phn ng tr v lai vi tri ban u cua no. Ghi
tri s in ap thi im phn ng lam dich tip im ng ra khoi tip im tinh. -
Kim tra h s tr v (Ktv = in ap tr v/ in ap tac ng) at khoang 0,85
0,87. - H thng ng cua rle phai lam vic chc chn, khng dng lai vi tri
trung gian khi rle tac ng va tr v. Cac tip im phai lam vic chc chn,
n inh, khng bi rung. - Trng hp rle co tri s tac ng ln hn so vi tri
s t thi cn a vit chn traii vao gn phn ng hoc un cong cac tip im
thng ong va tng xon cua lo xo. Cac thao tac hiu chinh nay se tin
hanh theo hng ngc lai nu tri s tac ng cua rle nho hn so vi tri s t.
- H s tr v cua rle c hiu chinh bng cach iu chinh vi tri cua phn ng
nh vit phai va bng cach un cong cac tip im thng m. - Tham chiu thm
tai liu rle anh gia cht lng va kha nng lam vic n inh cua no. 3.- Th
nghim rle bao v kem in ap PH54 : Thc hin theo cac bc th nghim sau y
: + Kim tra c khi cua rle : - S dich chuyn cua phn ng phai d dang
quanh truc cua no ma khng co ma sat ln, - Khe h doc truc cua phn ng
nm trong gii han 0,2 0,3mm, - Khe h gia gia cua phn ng va cac cc
mach dn t khi phn ng a bi hut phai u nhau va bng 0,55mm, - Khe h
gia tip im tinh va tip im ng trang thai m vao khoang 2,5mm, - Goc
quay cua phn ng va ca cach b tri cac tip im tinh i vi phn ng phai
loai tr c kha nng cham cu vao mt u cua tip im tinh khi quay phn ng
lam ong cac tip im, - Phn ng mang cu tip im ng tip xuc vi tip im
tinh vi tri cach mep ngoai khng xa va trt doc theo ng trung binh, -
nen cua tip im thng m khi phn ng bi hut phai bng vi nen tip im thng
ong khi nha phn ng (khoang 0,3mm), - Khi dich chuyn cn gat tri s t
trn thang t cua rle, cac vong cua lo xo xon c khng c cham nhau bt
ky vi tri nao cua thang o. + Kim tra tri s tac ng cua rle : - Cung
cp mt in ap bng inh mc vao rle. - Kim tra phn ng cua rle ang khep
vao ma trai cua tip im tinh. Giam dn gia tri in ap cung cp cho rle
cho n khi rle tac ng, phn ng dich chuyn lam tip im ng tr v khep vao
tip im tinh bn phai cua no. Ghi lai gia tri tac ng nay.
-
Tng tr lai in ap cung cp cho n khi phn ng ri khoi tip im tinh v
bn phai cua no. Ghi tri s in ap thi im phn ng lam dich tip im ng ra
khoi tip im tinh. - Kim tra h s tr v (Ktv = in ap tr v/ in ap tac
ng) at khoang 1,15 1,25. - Cach hiu chinh cac sai khac gia tri s
tac ng va tri s t thc hin tng t nh i vi trng hp rle bao v qua in ap
PH53. Tham chiu cac thng s ky thut cua rle kt lun cht lng va kha
nng lam vic n inh cua rle. VI. TIU CHUN ANH GIA : Mt s cac yu cu i
vi rle v mt c khi nh nu trong phn th nghim cung la cac tiu chun anh
gia rle, ngoai ra rle con phai at c cac tiu chi sau : + Sai lch tri
s in ap tac ng so vi tri s t ghi trn thang khng vt qua 8% khi nhit
mi trng xung quanh la 200C, + Cng sut tiu thu cua rle vao khoang
1VA in ap t nho nht va khng qua 5VA in ap inh mc, + H s tr v cua
rle khng nho hn 0,8 i vi rle bao v qua ap PH53 va khng ln hn 1,25 i
vi rle bao v kem ap PH54, + Thi gian tac ng cua ban thn rle khng
qua 0,1 s khi in ap tac ng bng 1,2 ln gia tri t i vi rle PH53 va
0,8 ln gia tri t i vi rle PH54. Bang di y cho cac thng s ky thut
cua rle loai PH50 : in ap inh mc Loai va cua dai t (V) nhan hiu Th
rle Th hai nht in ap ln nht PH 53/60 30 60 PH 53/200 100 200 PH
53/400 200 400 PH 53/60 100 200 in ap nho nht PH 54/48 30 60 PH
54/160 100 200 PH 54/320 200 400 Gia tri t tng ng dai t th (V) Gii
han Dai t th nht Dai t th hai tri s t Ucp dai Ucp dai (V) Ut Ut han
han 15 60 50 200 100 400 15 60 12 48 40 160 80 320 15 30 50 100 100
200 15 30 12 24 40 80 80 160 33 110 220 110 33 110 220 30 60 100
200 200 400 30 60 66 220 440 220
-
24 48 66 80 160 220 160 320 440
Phn 12: RLE BO V QU - KM P SPAU 330CI./ : GII THIU CHUNG
- Rle bo v qu - km p SPAU 330C gm 03 khi thc hin cc chc nng clp
+ Khi SPCU 1C6 : khi bo v in p th t khng; + Khi SPCU 3C14 : khi bo
v qu, km in p dy; + Khi SPCR 8C27 : khi ghi nhiu v cc tnh trng s c
- Rle bo v qu - km p SPAU 330C c s dng gim st v bo v nhm loi tr cc
tnh trng nhiu lon in p cng nh cc tnh trng h hng trn thanh ci ca trm
bin p. - u vo Rle : + 03 u vo xoay chiu nhn cc in p dy t cc my bin
in p l U12, U23, U31 + 01 u vo xoay chiu dnh cho bo v in p th t
khng Uo - Cc u vo ny c th c chn nh mc 100V hay 110V nh s la chn cc
terminal ca u vo mt sau ca rle; + 01 u vo iu khin c th c s dng thc
hin cc chc nng iu khin bn ngoi hay kha mt s chc nng bo v ca rle . -
u ra + 05 rle u ra thc hin cc chc nng cnh bo hay tc ng p ng theo s
iu khin ca rle do ngi s dng lp trnh v 01 rle u ra cnh bo cc h hng
bn trong rle. u ra cnh bo ny l u ra mc nh khng th ci t c.
- Ngun nui rle + 01 u vo cp ngun nui mt chiu cho s lm vic ca
rle. in p nh mc cho s lm vic ca rle c th l ngun 110/ 220VDC (VAC)
ng vi dy in p lm vic 80...265 Vdc/Vac hoc 24/ 48/60VDC ng vi dy in
p lm vic 18...80 Vdc v c ghi ch trn mt trc ca rle. y l thng s phi
la chn khi t hng * Mt trc ca rle - Mt trc ca rle c 03 khi mun ring
bit thc hin 03 chc nng nu trn v 01 khi chung RS 613. - Hai khi o
lng v gim st in p SPCU 1C6 v SPCU 3C14 c cc n ch th cho cc thng s t
trn rle v cc nm iu chnh thng s tng ng, 01 nhm cng tc lp trnh la chn
cc chc nng lm vic ca rle SG1 v n ch th tng ng ca n, 02 n ch th cc s
lm vic ca bo v , 01 n gim st s lm vic lin tc ca rle (IRF), 01 nt
nhn STEP dng cho vic truy cp vo cc trnh n ca h thng trnh n ca rle v
01nt n RESET dnh cho ci t v gii tr. - Khi SPCR 8C27 c cung cp 02 nt
n STEP v RESET dng cho vic truy cp trnh n v c cc thng s o lng cng
nh s c; 01 n ch th s lm vic ca b ghi s kin. Khi khi ny ang ghi nhn
thng tin n ny s sng xanh, v khi qu trnh ghi kt thc, d liu c lu
trong b nh th n s chuyn sang sng . Khi ny cng c 01 n IRF gim st lin
tc s lm vic ca rle. - Khi chung RS 613 cung cp mt s cc thng s k
thut ca rle nh : tn s, in p nh mc, ngun nui rle; cc nh ngha thanh
ghi ca 03 khi mun tng ng v nhm cng tc lp trnh SGR dng cho vic cu
hnh cc u ra ca rle - Mn hnh c hin th 4 ch s : 03 ch s pha phi ca mn
hnh ch th cc gi tr chnh nh, o lng, ghi s c hay gi tr ca cc thanh
ghi v 01 ch s pha tri ca mn hnh ch th loi s c hay m s ca thanh ghi.
ng thi tng ng vi ch th trn mn hnh, rle c cc n mu vng ch th cc gi tr
o lng hay gi tr s c tng ng. - trng thi vn hnh bnh thng ch c n ch th
ngun Uaux l bc sng , tt c cc n khc v mn hnh trng thi ti. II./ S U
NI V THNG S K THUT
Trong : * Khi in p u vo xoay chiu: - Terminal 13-14: u vo in p
dy U12 ( 100V) - Terminal 13-15: u vo in p dy U12 ( 110V) -
Terminal 16-17: u vo in p dy U23 ( 100V) - Terminal 16-18: u vo in
p dy U23 ( 110V) - Terminal 19-20: u vo in p dy U31 ( 100V) -
Terminal 19-21: u vo in p dy U31 ( 110V) - Terminal 28-29: u vo in
p Uo ( 100V) - Terminal 28-30: u vo in p Uo ( 110V) - Kh nng chu in
p lin tc : 2xUn - Cng xut in p Un : v Uo>>. Khi ny s o lng
thnh phn in p th t khng xut hin khi c chm t v so snh vi cc ngng t
trn rle. Khi in p o lng c vt qu cc ngng t, cp bo v tng ng s khi to
v cho tn hiu khi to n cc u ra SS1 hoc SS2 tng ng, n ch th s lm vic
ca bo v s sng vng. Nu tnh trng ny ko di n ht thi gian t trc ca cp
bo v tng ng th tn hiu lm vic s c gi n cc u ra TS1 v TS2 tng ng, lc
ny n ch th s lm vic ca bo v s sng v trn mn hnh s xut hin m ca thanh
ghi s c. Vic gii tr cc tn hiu cnh bo ny c th c thc hin nh cc nt n
mt trc ca rle hoc nh lnh V101, V102 thng qua phn mm giao din. S lm
vic ca cc cp bo v c th c kho nh cc tn hiu kho BTS1, BTS2 v cc cng
tc lp trnh tng ng SGB. 2.- Khi SPCU 3C14 : c s dng bo v chng cc tnh
trng qu, km in p 3 pha hoc 1 pha xut hin trong mng. Khi gm 01 cp bo
v qu p U> v 01 cp bo v km p U c th c chn lm vic vi c tnh thi
gian c lp hoc c tnh thi gian nghch, trong khi cp bo v U< ch lm
vic vi c tnh thi gian xc lp. Khi mt trong cc in p o lng c vt qu cc
ngng t, cp bo v tng ng s khi to v cho tn hiu khi to n cc u ra SS1
hoc SS2 tng ng, n ch th s lm vic ca bo v s sng vng. Nu tnh trng ny
ko di n ht thi gian t trc ca cp bo v tng ng th tn hiu lm vic s c gi
n cc u ra TS1 v TS2 tng ng, lc ny n ch th s lm vic ca bo v s sng v
trn mn hnh s xut hin m ca thanh ghi s c. Vic gii tr cc tn hiu cnh
bo ny c th c thc hin nh cc nt n mt trc ca rle hoc nh lnh V101, V102
thng qua phn mm giao din.
S lm vic ca cc cp bo v c th c kho nh cc tn hiu kho BTS1, BTS2 v
cc cng tc lp trnh tng ng SGB. III./ PHNG PHP CHNH NH, CI T V CC
THNG S K THUT 1./ Truy cp h thng trnh n - S dng nt Step di chuyn
trong h thng trnh n ca cc khi, nu mun di chuyn theo hng thun th n
gi nt trong 1 giy, di chuyn theo hng nghch th n nt 0,5 giy. bit v
tr hin ang truy cp phi cn c vo v tr n vng ang bt sng v con s tn cng
bn tri ca mn hnh. ngha ca tng v tr c xc nh da vo h thng trnh n cho
sn i vi tng khi rle. 2./ Ci t thng s - Mun ci t thng s no th phi th
phi truy cp vo ng v tr ca thng s . Lc ny ba con s bn phi mn hnh l
gi tr t hin hnh ca thng s . Mun thay i gi tr ta phi iu chnh nm xoay
. Ci t rle u ra - Cc rle u ra c ch to tha hnh cho mt s chc nng c th
l c nh v mt s chc nng phi ci t. Vic ci t c thc hin bi nhm cng tt
SGR nm trn khi RS 613. Cng tt no c t 1 (ON) th chc nng tng ng ca
cng tt c cu hnh n u ra, ngc li cng tt no c t 0 (OFF) th chc nng tng
ng ca cng tt khng c cu hnh n u ra. C th: Chc nng c th c cu hnh cho
cc rle u ra Rle A gm: Tn hiu Trip ca chc nng U> nu SGR/1 =1 Tn
hiu Trip ca chc nng U< nu SGR/2 =1 Tn hiu Trip ca chc nng Uo>
nu SGR/3 =1 Tn hiu Trip ca chc nng Uo>> nu SGR/4 =1 Rle B gm:
Tn hiu Trip ca chc nng U> nu SGR/5 =1 Tn hiu Trip ca chc nng
U< nu SGR/6 =1 Tn hiu Trip ca chc nng Uo>> ( C nh) Rle C
gm: Tn hiu Star ca chc nng U> nu SGR/7 =1 Tn hiu Trip ca chc nng
U> ( C nh) Rle D gm: Tn hiu Star ca chc nng U< nu SGR/8 =1 Tn
hiu Trip ca chc nng U< ( C nh) Rle E gm: Tn hiu Trip ca chc nng
Uo> ( C nh)
3./ Khi qu p th t khng SPCU 1C6
3.1.- H thng trnh n :
3.2 S khi:
3.3 Cc thng s o lng v thng s chnh nh: - Uo : Gi tr o lng ca in p
Uo, tnh theo phn trm ca in p nh mc. - Uo>/Un : Gi tr in p khi ng
ca chc nng Uo>, tnh bng phn trm ca in p nhn mc. Dy lm vic ph
thuc vo trng thi ca cng tt SG1/5 - t>[s] : Thi gian lm vic ca
chc nng Uo>, tnh bng giy. Dy lm vic ph thuc vo trng thi ca cng
tt SG1/1 v SG1/2 - Uo>>/Un : Gi tr in p khi ng ca chc nng
Uo>>, tnh bng phn trm ca in p nhn mc. Dy lm vic ph thuc vo
trng thi ca cng tt SG1/6 - t>>[s] : Thi gian lm vic ca chc
nng Uo>>, tnh bng giy. Dy lm vic ph thuc vo trng thi ca cng
tt SG1/7 v SG1/8 Nhm cng tt SG1 - Nhm cng tt SG1 l nhm cng tt c kh,
tr s tng kim tra ca nhm s c hin th trn mn hnh khi n vng ch th ca
nhm bt sng. ngha ca nhm cbg tt ny nh sau: SG1/1 v SG1/2: La chn dy
thi gian lm vic t> ca chc nng Uo> SG1/1 SG1/2 Dy thi gian lm
vic ca chc nng Uo> ( t>) 0 0 0,05.... 1,00 s 1 0 0,5 ....10,0
s 0 1 0,5 .... 10,0 s 1 1 5,0 .... 100,0 s
SG1/3: Khng s dng SG1/4: La chn ch t gi hoc khng t gi ca tn hiu
Trip ca chc nng Uo> (TS1) v chc nng Uo>> (TS2). SG1/4=0:
Tn hiu Trip TS1, TS2 khng t gi. SG1/4=1: Tn hiu Trip TS1, TS2 c t
gi. Reset phi nhn ng thi 2 nt n STEP v RESET SG1/5: La chn dy in p
khi ng ca chc nng Uo> SG1/5=0, dy t l 2 .... 20%Un SG1/5=1, dy t
l 10 .... 100%Un SG1/6: La chn dy in p khi ng ca chc nng Uo>>
SG1/6=0, dy t l 10 .... 80%Un SG1/6=1, dy t l 2 .... 16%Un SG1/7 v
SG1/8: La chn dy thi gian lm vic t>> ca chc nng Uo>>
SG1/7 0 1 0 1 SG1/8 0 0 1 1 Dy thi gian lm vic ca chc nng
Uo>> ( t>>) 0,05.... 1,00 s 0,5 ....10,0 s 0,5 ....
10,0 s 5,0 .... 100,0 s
* Nhm cng tt SG2 - Nhm cng tt SG2 l nhm cng tt phn mm, n nm
trong thc n ph th 3 ca thc n SG1. Nhm cng tt SG2 iu khin ch t gi
hoc khng t gi ca cc n Led. Nu cng tt no t bng 0 th Led tng ng vi
cng tt s t ng Reset, ngc li nu t bng 1 phi Reset bng tay Tn hiu Ch
th khi ng Uo> Ch th lm vic Uo> Trng s 1 2 V d c th Ci S kinm
tra ngha t 0 0x1=0 Ch th vng ca Led Uo> t ng tr v 1 1x2=2 Ch th
ca Led Uo> khng t ng tr v 0 0x4=0 Ch th vng ca Led Uo>> t
ng tr v 1 1x8=8 Ch th ca Led Uo>> khng t ng tr v 10
Ch th khi ng 4 Uo>> Ch th lm vic Uo>> 8 Tng kim
tra
* Nhm cng tt SGB - Nhm cng tt SGB nm bn trong Card ca khi:
+ SGB/1: Tn hiu khi ng t chc nng Uo> gi n u vo ST2 ca khi ghi
s c SPCR 8C27 + SGB/2: Tn hiu khi ng t chc nng Uo>> gi n u vo
ST2 ca khi ghi s c SPCR 8C27 + SGB/3: Tn hiu khi ng t chc nng
Uo>> gi n u vo ST3 ca khi ghi s c SPCR 8C27 + SGB/4:
Uo>-Tripping s b kho bi u vo BS1 + SGB/5: Uo>>-Tripping s
b kho bi u vo BS1 + SGB/6: khng s dng + SGB/7: khng s dng + SGB/8:
khng s dng 3.4./ Cc thng s k thut: * Chc nng Uo> + in p khi ng
2....20%Un hoc 10....100%Un + Thi gian khi ng in hnh 70ms + Thi
gian tc ng0,05....1,0s, 0,5....10,0s, 5....100s +Thi gian Reset
> + in p khi ng 10...80%Un v hoc 2...16%Un v + Thi gian khi ng
in hnh 70ms + Thi gian tc ng0,05....1,0s, 0,5....10,0s, 5....100s
+Thi gian Reset , n(Uo>)= 0...255 - Thng s 3: S ln khi ng ca chc
nng Uo>>, n(Uo>>)= 0...255
- Thng s 4 Thi gian khi ng ca chc nng Uo>, tnh bng phn trm so
vi thi gian tc ng. Mi mt ln khi ng b tnh s Reset v tnh t Zero. Khi
chc nng tc ng th gi tr thng s ny l 100 - Thng s 5 Thi gian khi ng
ca chc nng Uo>>, tnh bng phn trm so vi thi gian tc ng. Mi mt
ln khi ng b tnh s Reset v tnh t Zero. Khi chc nng tc ng th gi tr
thng s ny l 100 4./ Khi qu, km in p dy SPCU 3C14
4.1.- H thng trnh n :
4.2 S khi:
4.3 Cc thng s o lng : - U12 : Gi tr o lng ca in p dy U12, tnh
theo t l vi in p nh mc. - U23 : Gi tr o lng ca in p dy U23, tnh
theo t l vi in p nh mc. - U31 : Gi tr o lng ca in p dy U31, tnh
theo t l vi in p nh mc. * Cc thng s chnh nh - U>/Un : Gi tr in p
khi ng ca chc nng U>, tnh bng t l vi in p nh mc. Dy lm vic
0,8....1,6xUn - t>[s] k>: Thi gian tc ng ca chc nng U>,
tnh bng giy. Dy lm vic ca t tnh thi gian c lp hoc la chn loi ng t
tnh ph thuc vo trng thi ca cng tt SG1/3, SG1/4 v SG1/5. Dy lm vic
ca h s k= 0,05....1,0 - U Ch th lm vic U> Ch th khi ng U< Ch
th lm vic U< Tng kim tra
1 2 4 8
0 1 0 1
0x1=0 1x2=2 0x4=0 1x8=8 10
Ch th vng ca Led U> t ng tr v Ch th ca Led U> khng t ng tr
v Ch th vng ca Led U< t ng tr v Ch th ca Led U< khng t ng tr
v
* Nhm cng tt SGB - Nhm cng tt SGB nm bn trong Card ca khi: +
SGB/1: Tn hiu khi ng t chc nng U> gi n u vo ST1 ca khi ghi s c
SPCR 8C27 + SGB/2: Tn hiu khi ng t chc nng U< gi n u vo ST1 ca
khi ghi s c SPCR 8C27 + SGB/3: Tn hiu khi ng t chc nng U< gi n u
vo ST3 ca khi ghi s c SPCR 8C27 + SGB/4: khng s dng + SGB/5: U + in
p khi ng 0,8....1,6%Un + Thi gian khi ng 0,1 s hoc 30 s + Thi gian
tc ng0,05....1,0s, 0,5....10,0s, 5....100s + H s k> ca t tnh thi
gian nghch: 0,05 ...1,0 +Thi gian Reset in hnh 60ms + H s tr v in
hnh 0,97 + Sai s thi gian tc ng cho php ca t tnh thi gian c lp hoc
sai s thi gian khi ng 2% ca gi tr t hoc 25ms + Sai s thi gian tc ng
ca t tnh thi gian nghch: 25ms hoc l bng sai s xut hin khi in p thay
i 3% + Sai s in p tc ng cho php: 3% ca gi tr t Chc nng U< + in p
khi ng 0,4.... 1,2xUn + Thi gian khi ng 0,1 s hoc 30 s + Thi gian
tc ng1 ...12s hoc 10 ...120s +Thi gian Reset in hnh 60 ms + H s tr
v in hnh 1,03
+ Sai s thi gian tc ng v thi gian khi ng cho php: 2% ca gi tr t
hoc 25ms + Sai s in p tc ng cho php: 3% ca gi tr t 4.5./ Ghi s c:
Mi khi khi chc nng hot ng th b ghi s c s c kch hot thc hin vic ghi
s c. B ghi s c gm 8 thng s c a ch t 1 n 8 trong h thng thc n chnh.
Mun c phi dng nt Step di chuyn n cc a ch t 1 n 8 nh ni trn. Con s
bn tri ch a ch, 3 con s bn phi ch gi tr. - Thng s 1: Ghi gi tr in p
dy ln nht, tnh theo t l in p nh mc. Khi chc nng qu p khi ng th gi
tr ca ln hot ng c s b xo gi tr in p mi s c ghi lin tc. Vic ghi s
dng li khi chc nng qu p tc ng v gi tr in p ln nht trong sut qu trnh
khi ng s c lu li trong b ghi. - Thng s 2: Ghi gi tr in p ln nht tng
xy ra, tnh theo t l in p nh mc. B ghi s c cp nht ngay khi c mt gi
tr in p mi ln hn gi tr c trong b ghi. - Thng s 3: Ghi gi tr in p dy
nh nht, tnh theo t l in p nh mc. Khi chc nng km p khi ng th gi tr
ca ln hot ng c s b xo gi tr in p mi s c ghi lin tc. Vic ghi s dng
li khi chc nng km p tc ng v gi tr in p nh nht trong sut qu trnh khi
ng s c lu li trong b ghi. - Thng s 4: Ghi gi tr in p nh nht tng xy
ra, tnh theo t l in p nh mc. B ghi s c cp nht ngay khi c mt gi tr
in p mi h thp hn gi tr c trong b ghi. - Thng s 5: S ln khi ng ca
chc nng U>, n(Uo>>)= 0...255 - Thng s 6: S ln khi ng ca
chc nng U>)= 0...255 - Thng s 7 Thi gian khi ng ca chc nng
U>, tnh bng phn trm so vi thi gian tc ng. Mi mt ln khi ng b tnh
s Reset v tnh t Zero. Khi chc nng tc ng th gi tr thng s ny l 100 -
Thng s 8 Thi gian khi ng ca chc nng U a +c U U > 0 ,5 p b
U>
t: Thi gian hot ng ( s ) k>: H s thi gian U: Gi tr in p u vo
( V ) U>: Gi tr t ( V ) a: Hng s 480 b: Hng s 32 c: Hng s 0,035
p: Hng s ph thuc vo h t tnh
H t tnh A: p=2 H t tnh B: p=3 - B thi gian Trip ca chc nng qu p
ch khi ng khi in p u vo vt qu 106% gi tr in p t. - Sai s thi gian
tc ng ca chc nng qu p cho trong thng s k thut ch c p dng khi gi tr
in p u vo ln hn 110% gi tr in p t. H t tnh A
H t tnh B
IV./ HNG DN TH NGHIM RLE SPAU330 1./ Cng vic chun b trc khi th
nghim:
- Kim tra ngun nui : Ngun nui phi c tr s nm trong dy in p cho
php ca rle, v c ni n rle ng Terminal, ng cc tnh. - Kim tra tnh trng
bn ngoi ca rle: Rle phi cn nguyn vn , khng c vt nt, cc hng dn ch th
in trn thn rle phi r rng. - Kim tra rle c u t tt. 2./ Th nghim rle:
- ng nui nui rle, theo di cc ch th trn mn hnh rle, v n bo ngun nui
phi bt sng. - Kim tra v ci t cu hnh u vo , u ra, ch th Led, cc thng
s t. Vic ci t u vo u ra c th c thay i cho ph hp v thun li trong tng
bc th nghim cc chc nng nhng phi xc nh c u vo u ra no lin quan n chc
nng ang chun b th t c th kim tra c trng thi ca chng trong qu trnh
th Kim tra tr s o lng - Kim tra tr s o lng: Ni ngun p ca hp b th
nghim n cc u vo in p xoay chiu Uo, U12, U23, U31. Thc hin bm in p
vo ln lt cc u vo. ng vi mi u vo phi thc hin bm nhiu tr s in p khc
nhau, v mi ln bm phi truy cp vo trnh n c tr s trn mn hnh, i chiu s
ng nht gia u vo ang bm vi hin th. Kim tra sai s ca hin th phi nm
trong phm vi cho php ca thng s k thut. Kim tra ngng khi ng - Kim
tra ngng khi ng: Vic kim tra ngng khi ng phi c th nghim cho tng u
vo v tng chc nng ring bit. Ch khi th khi SPCU 1C6 th ngng khi ng
ang th phi nh nht trnh tc ng nhm. C th nh sau * Kim tra ngng khi ng
ca khi SPCU 1C6 - Th nghim chc nng Uo>,( Uo>>) :Thc hin bm
t t in p cho n khi rle khi ng, sau gim t t cho n khi rle tr v. Kim
tra u ra, led, bng ghi s c, so snh gi tr khi ng, h s tr v vi tiu
chun cho php. Th nghim tng t cho chc nng Uo>> * Kim tra ngng
khi ng ca khi SPCU 3C14 - Ngng khi ng ca chc nng U>: + Th nghim
chc nng U>: Phi a thi gian khi ng v gi tr nh nht. + Thc hin bm t
t in p vo u vo U12 cho n khi rle khi ng, sau gim t t cho n khi rle
tr v. Kim tra u ra, led, bng ghi s c, so snh gi tr khi ng, h s tr v
vi tiu chun cho php, tip tc th nghim i vi U23, U31 - Ngng khi ng ca
chc nng U
