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MATHEMATICS 1º ESO PROGRAMA DE ENSEÑANZA BILINGÜE I.E.S. ANDRÉS DE VANDELVIRA MANUEL VALERO LÓPEZ (MATEMÁTICAS) ANTONIO MARTÍNEZ RESTA (INGLÉS)

Book 1 ESO Geometric

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Page 1: Book 1 ESO Geometric

MATHEMATICS

1º ESO

PROGRAMA DE ENSEÑANZA BILINGÜE

I.E.S. ANDRÉS DE VANDELVIRA

MANUEL VALERO LÓPEZ (MATEMÁTICAS)

ANTONIO MARTÍNEZ RESTA (INGLÉS)

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Diseño de portada de Patricia Jiménez Fiérrez

1º ESO B curso 2008-2009

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INDEX

Unit 1 Numbers Numbers 1-1 More about reading numbers 1-2 Exercises I 1-3 Decimals 1-4 Fractions and percentages 1-5 Roman numerals 1-5 Decimal notation and place value. Exercises 1-6 Rounding numbers 1-7 Exercises II 1-8 Calculations 1-11 Exercises III 1-12 Exercises IV 1-13 Solutions 1-15

Unit 2 Powers Powers. How to name powers 2-1 Exercises 2-2 Operations with powers. Exercises 2-6 Square roots 2-8 Solutions 2-10

Unit 3 Multiples and factors Multiples 3-1 Factors 3-2 Prime Numbers 3-3 Tests of divisibility 3-5 Common Multiples 3-6 Lowest common multiple 3-7 Common Factors 3-9 Highest Common Factor 3-10 Exercises 3-11 Solutions 3-15 Unit 4 Fractions Fractions 4-1 Reading fractions 4-1 Equivalent fractions 4-2 Comparing and ordering fractions 4-5 Adding and subtracting fractions 4-5 Improper fractions. Mixed numbers 4-8 Multiplying fractions 4-9

Multiplying a fraction by a whole number. Calculating a fraction of a quantity

4-10

Dividing fractions 4-12 Exercises 4-13 Solutions 4-15

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Unit 5 Decimal numbers Decimal numbers 5-1 How to read decimal numbers 5-1 Adding and subtracting decimal 5-2 Multiplying decimal numbers 5-3 Dividing whole numbers, with decimals 5-3 Dividing decimals by decimals 5-4 Rounding Decimal Numbers 5-5 Writing a fraction as a decimal 5-6 Repeating decimals 5-7 Exercises 5-8 Solutions 5-11

Unit 6 Integers The negative numbers 6-1 The Number Line. Exercises 6-1 Absolute Value 6-3 Adding Integers 6-3 Subtracting Integers. Exercises 6-5 Multiplying Integers 6-9 Dividing Integers 6-12 Order of operations. Exercises 6-14 Solutions 6-19

Unit 7 Measurements Measurement 7-1 Metric Prefix Table 7-2 Length 7-2 Capacity 7-6 Weight 7-7 Area 7-9 Volume 7-10 Imperial Units of Length, Capacity and Mass 7-12 Temperature 7-20 Solutions 7-22

Unit 8 Ratio and percentages Ratio 8-1 Comparing Ratios 8-1 Direct Proportionality 8-3 Inverse Proportionality 8-6 Ratios with more than two parts 8-7 Percentages 8-8 Calculations with percentages 8-10 Exercises, extra exercises 8-14 Solutions 8-21

Unit 9 Algebra and equations

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Variables 9-1 Expressions 9-1 Monomials 9-2 Operations of monomials 9-3 Manipulating algebraic expressions 9-5 Equations 9-8 Solving an equation 9-8 Exercises 9-11 Solutions 9-16

Unit 10 Geometry, angles Basic terms 10-1 Angles 10-2 Type of angles 10-5 Related angles 10-6 Angles between intersecting lines 10-7 Operations with angles 10-10 Angles in the polygons 10-13 Angles in a circle 10-14 Symmetric shapes 10-15 Solutions 10-17

Unit 11 Polygons and 3-D Shapes Triangles 11-1 Equality of triangles 11-3 Points and lines associated with a triangle 11-3 The Pythagorean Theorem 11-6 Quadrilaterals 11-8 Regular polygons 11-12 Circle and circumference 11-14 Polyhedrons 11-16 Solids of revolution 11-19 Solutions 11-21

Unit 12 Areas Area 12-1 Quadrilaterals 12-1 Area of a triangle 12-2 Area of a rhombus 12-5 Area of a trapezium 12-5 Measures in regular polygons and circles 12-8 Solutions 12-12

Unit 13 Graphs Previous ideas 13-1 Graphs. Exercises 13-1 Graph of a function 13-6 Handling with data. Exercises 13-11 Solutions 13-20

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1 Numbers

1 Numbers

The cardinal numbers (one, two, three, etc.) are adjectives referring to quantity, and the ordinal numbers (first, second, third, etc.) refer to distribution.

Number Cardinal Ordinal

1 one first (1st)

2 two second (2nd)

3 three third (3rd)

4 four fourth (4th)

5 five fifth

6 six sixth

7 seven seventh

8 eight eighth

9 nine ninth

10 ten tenth

11 eleven eleventh

12 twelve twelfth

13 thirteen thirteenth

14 fourteen fourteenth

15 fifteen fifteenth

16 sixteen sixteenth

17 seventeen seventeenth

18 eighteen eighteenth

19 nineteen nineteenth

20 twenty twentieth

21 twenty-one twenty-first

22 twenty-two twenty-second

23 twenty-three twenty-third

24 twenty-four twenty-fourth

25 twenty-five twenty-fifth

26 twenty-six twenty-sixth

27 twenty-seven twenty-seventh

28 twenty-eight twenty-eighth

29 twenty-nine twenty-ninth

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30 thirty thirtieth

40 forty fortieth

50 fifty fiftieth

60 sixty sixtieth

70 seventy seventieth

80 eighty eightieth

90 ninety ninetieth

100 one hundred hundredth

1,000 one thousand thousandth

100,000 one hundred thousand

hundred thousandth

1,000,000 one million millionth

Beyond a million, the names of the numbers differ depending where you live. The places are grouped by thousands in America and France, by the millions in Great Britain, Germany and Spain.

Name American-French English-German-Spanish

million 1,000,000 1,000,000

billion 1,000,000,000 (a thousand millions)

1,000,000,000,000 (a million millions)

trillion 1 with 12 zeros 1 with 18 zeros

quadrillion

1 with 15 zeros 1 with 24 zeros

2 More about reading numbers

AND is used before the last two figures (tens and units) of a number.

325: three hundred and twenty-five 4,002: four thousand and two

A and ONE

The words hundred, thousand and million can be used in the singular with “a” or “one”, but not alone. “A” is more common in an informal style; “one” is used when we are speaking more precisely.

I want to live for a hundred years The journey took exactly one hundred years I have a thousand euros

“A” is also common in an informal style with measurement-words A kilo of oranges costs a euro Mix one litre of milk with one kilo of flour…

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“A” is only used with hundred, thousand, etc at the beginning of a number 146 a hundred and forty-six 3,146 three thousand, one hundred and forty-six

We can say “a thousand” for the round number 1,000, and we can say “a thousand” before “and”, but we say “one thousand” before a number of hundreds.

1,000 a thousand 1,031 a thousand and thirty-one 1,100 one thousand, one hundred 1,498 one thousand, four hundred and ninety-eight

Compare also: A metre but one metre seventy (centimetres) A euro but one euro twenty (cents)

Exercises I 1. Write in words the following numbers: 37 →_______________________ 27 →_______________________

28 →_______________________ 84 →_______________________ 62 →_______________________ 13 →_______________________ 15 →_______________________ 158 →_______________________ 38 →_______________________ 346 →_______________________ 89 →_______________________ 461 →_______________________ 35 →_______________________ 703 →_______________________

73 →_______________________ 102 →_______________________ 426 →_______________________ 1,870 →_______________________ 363 →_______________________ 1,015 →_______________________ 510 →_______________________ 1,013 →_______________________ 769 →_______________________ 6,840 →_______________________ 468 →_______________________ 8,900 →_______________________ 686 →_______________________ 6,205 →_______________________ 490 →_______________________ 9,866 →_______________________ 671 →_______________________ 7,002 →_______________________

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804 →_______________________ 5,676 →_______________________ 3,750 →_______________________ 77→_______________________

3 [ 0 ] nought, zero, o, nil, love

The figure 0 is normally called nought in UK and zero in USA

- When numbers are said figure by figure, 0 is often called like the letter O Examples: My telephone number is nine six seven double two o four six o (967 220460) My telephone number is nine six seven double two o treble/triple six (967

220666)

- In measurements (for instance, of temperature), 0 is called zero Water freezes at zero degrees Celsius

- Zero scores in team-games are usually called nil in UK and zero in USA.

- In tennis, table-tennis and similar games the word love is used (this is derived from the French l’oeuf, meaning the egg, presumably because zero can be egg-shaped)

Examples: Albacete three Real Madrid nil (nothing) Nadal is winning forty-love

2. Write in words and read the following telephone numbers:

967252438

678345600

961000768

918622355

0034678223355

0034963997644

4 Decimals

Decimal fractions are said with each figure separate. We use a full stop (called “point”), not a comma, before the fraction. Each place value has a value that is one tenth the value to the immediate left of it.

0.75 (nought) point seventy-five or seventy-five hundredths

3.375 three point three seven five

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5 Fractions and percentages

Simple fractions are expressed by using “ordinal numbers” (third, fourth, fifth...) with some exceptions:

1/2 One half / a half 1/3 One third / a third 2/3 Two thirds 3/4 Three quarters 5/8 Five eighths 4/33 Four over thirty-three

Percentages:

We don’t use the article in front of the numeral 10% of the people Ten per cent of the people

6 Roman numerals Examples:

- There is no zero in the Roman numeral system.

- The numbers are built starting from the largest number on the left, and adding smaller numbers to the right. All the numerals are then added together.

- The exception is the subtracted numerals, if a numeral is before a larger numeral; you subtract the first numeral from the second. That is, IX is 10 - 1= 9.

- This only works for one small numeral before one larger numeral - for example, IIX is not 8; it is not a recognized roman numeral.

- There is no place value in this system - the number III is 3, not 111.

I=1 (I with a bar is not used)

V=5 _ V=5,000

X=10 _ X=10,000

L=50 _ L=50,000

C=100 _ C = 100 000

D=500 _ D=500,000

M=1,000 _ M=1,000,000

1 = I

2 = II

3 = III

4 = IV

5 = V

6 = VI

7 = VII

8 = VIII

9 = IX

10 = X

11 = XI

12 = XII

13 = XIII

14 = XIV

15 = XV

16 = XVI

17 = XVII

18 = XVIII

19 = XIX

20 = XX

21 = XXI

25 = XXV

30 = XXX

40 = XL

49 = XLIX

50 = L

51 = LI

60 = LX

70 = LXX

80 = LXXX

90 = XC

99 = XCIX

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7 Decimal notation and place value

Every digit represents a different value depending on its position. For example in 54 the digit 5 represents fifty units, in 5329 the digit 5 represents five thousand units. 3. Write in words the following numbers as in the examples: BILLION HUNDRED

MILLION TEN MILLION

MILLION HUNDRED THOUSAND

TEN THOUSAND

THOUSAND HUNDRED TEN UNIT

8 3 4 1 6 7 2 9 3 4 5 8 3 4 0 0

- “Eight billion three hundred forty one million six hundred seventy two thousand

nine hundred and thirty four”. - “Five hundred eighty three thousand four hundred”.

2,538 90,304 762 8,300,690,285 593 1,237,569 3,442,567,321 76,421 90,304 762 8,321,678 250,005

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4. Read the following numbers: 120,000.321 453,897 700,560 5,542,678,987 34,765 94,540 345,971 82,754 763,123 1,867,349 500,340 4,580,200,170 5. Read the following numbers:

8,300,345 3,000,000,000 678,987,112 30,000,000,000

678,234,900

Use this table only if you need it.

BILLION HUNDRED

MILLION TEN MILLION

MILLION HUNDRED THOUSAND

TEN THOUSAND

THOUSAND HUNDRED TEN UNIT

8 Rounding numbers When we use big numbers it is sometimes useful to approximate them to the nearest whole number Examples: 1. Round 3533 to the nearest ten

3533 is closer to 3530 than 3540 so 3533 rounded to the nearest ten is 3530

2. Round 1564 to the nearest hundred

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1564 is closer to 1600 than 1500 so 1564 rounded to the nearest hundred is 1600 The rule is: 1. Look at the digit which is one place on the right to the required approximation. 2. If the digit is less than 5, cut the number (change the digits on the right to

zeros) as in the example 1.

3. If the digit is 5 or more than 5, add one unit to the digit of the rounding position and change the others to zeros like in the example 2.

Exercises II

1 Use the information of the table below to round the population to the nearest

a) Ten b) Hundred c) Ten thousand

Round the land areas to the nearest

a) Hundred b) Thousand

2 Round the following numbers to the nearest indicated in the table

Numbers Ten Hundred Thousand

6,172

18,776

5,217

City/Land Population a) b) c) Area (km2)

a) b)

Oxford 151,573 2605

Worcester 93,353 1,741

Edinburgh 451,710 263

Hereford 50,468 2,180

Glasgow 611,440 175

Bristol 410,950 2,187

London 7,355,420 1,577

York 193,268 272

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126,250

5,208

37,509

8,399

7,257

129,790

999

3 Write the answer in the following cases:

a) What is the volume of liquid in the graduated cylinder to the nearest 10 ml?

b) How long is the rope to the nearest cm?

c) What is the weight of the bananas rounded to the nearest 100g and to the nearest kg?

d) If the capacity of this stadium is 75,638 people, round it appropriately to the nearest.

Ten

Hundred

Thousand

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Rounding helps us to estimate the answers to calculations

4 For each question

a) Estimate the answer by rounding each number appropriately.

b) Find the exact answer.

c) Check that both answers are similar.

4.1 Anne bought a house for 76,595€ in 2001 and in 2007 sold it for 92,428€.

Which was the profit?

a)

b)

c)

4.2 In a shoe shop 3,670 boxes of shoes have to be

organized. There are three employees at the shop. How

many boxes does each employee have to organize?

a)

b)

c)

4.3 Constance bought some furniture. She bought an

armchair for € 499, a bed for 298€, a table for 189€ and four

chairs at 97€ each. If she had a discount of 48€, how much

did she have to pay?

a)

b)

c)

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4.4 The “Instituto Andrés de Vandelvira” has 1,048 students, who have been

distributed in 30 groups. How many students are there in each group?

a)

b)

c)

4.5 The number of votes for each party in an election was: Party A 20,446, party

B 10,866, party C 7,994 and others 5,743.

How many people voted?

What was the difference between the highest and the lowest numbers of

votes?

a)

b)

c)

9 Calculations

What’s …? ¿cuánto es..? / ¿cuántos son..? It’s ... es… /son…

Addition PLUS

In small additions we say and for + and is/are for = 2+6=8 two and six are eight What’s eight and six? It’s eight

In larger additions (and in more formal style) we use plus for +, and equals or is for =

720 + 145= 865 Seven hundred plus two hundred equals / is nine

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Subtraction MINUS

With small numbers, people say 7 - 4 = 3 four from seven leaves/is three or seven take away four

leaves/is three

In a more formal style, or with larger numbers, we use minus and equals 510 - 302 = 208 Five hundred and ten minus three hundred and two

equals /is two hundred and eight

Multiplication TIMES MULTIPLIED BY

In small calculations we say 3 x 4 = 12 three fours are twelve 6 x 7 = 42 six sevens are forty-two

In larger calculations we can say 17 x 381 = 6,477 17 times 381 is/makes 6,477, or in a more formal style 17

multiplied by 381 equals 6,477

Division DIVIDED BY

270:3 = 90 Two hundred and seventy divided by three equals ninety But in smaller calculations (8:2 = 4) we can say two into eight goes four (times)

Exercises III

1 Write the missing words. Write the answers in words

Twelve minus seven equals ____________

Six times five equals ____________

Eighty minus seventeen is _______________

Forty four minus nine plus twenty three equals_________________

Three times fifteen divided by five equals______________________

2 Write the missing numbers and write the answers in words as in the example

3 +14 = 17 three plus fourteen equals seventeen

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1. 6x ___ = 42

2. 18 ___ = 11

3. 6: ____ + 7 = 10

4. 12x3 - ____ = 25

5. (5x___ +5) : 8 = 5

3 Write the missing operation symbols. Then write the answers in words

1. 6 __ 7__ 2 = 40

2. 8 __ 2 __ 5 =2

3. 28 __ 9 __ 1 = 18

4. 9 __ 3 __ 5 = 8

5. 49 __ 7 __ 3 = 10

6. 6 __ 4 __ 2 __ 8 = 0

Exercises IV

1 A shop is open daily except on Sundays. The profit after a year was 96300€.

a) Calculate the average (mean) per working day. (Total profit divided by the number of days)

b) Tony has worked in the shop every day for a year earning 294€ per week. How much has he earned in a year? How much per day? 2 A car travels 17 km per litre of petrol. How many litres are needed to travel 560 km? If the capacity of the tank is 42 litres how far can the car travel on a full tank? 3 Find three consecutive numbers whose product is 4080. 4 Calculate:

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a) ( )5348 +÷ b) ( ) 1445 ×+ c) ( ) 53040 ÷+ d) ( ) 32127 ÷+ e) ( ) 113322 ÷+ f) ( ) 32040 ⋅÷ 5 Calculate: a) 5263 +⋅+ b) ( ) 2534 −⋅+ c) 42:615 ×− d) ( )13:1615 +− e) 10263 +×+ f) ( ) ( )13271858 +⋅− g) ( ) ( )36:832 −− h) ( ) 36:832 −− i) 31667 ×+ 6 Insert brackets to make the following calculations correct a) 37845 =+ x b) 72845 =+ x c) 113156 =÷+ d) 73:156 =+ e) 547345 =++ x f) 3752316 =++ x g) 28724/24 =⋅+ h) 83475:240 =−+ x 7 Abel buys 35 litres of petrol at 0.98€ per litre. a) Estimate how much that costs by rounding appropriately. b) Find the exact answer. c) Check that both answers are similar.

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Solutions

Exercises I 1. 37 →thirty seven; 27 → twenty-seven; 28 → twenty-eight; 84 → eighty four 62 → sixty two; 13 → thirteen; 15 → fifteen; 158 → one hundred and fifty eight 38 → thirty eight; 346 →three hundred and forty six; 89 →eighty nine; 461 →four hundred and sixty one; 35 → thirty five; 703 →seven hundred and three; 73 → seventy three; 102 → one hundred and two; 426 → four hundred and twenty six 1,870 → one thousand, eight hundred and seventy; 363 → three hundred and sixty three; 1,015 → one thousand and fifteen; 510 →five hundred and ten; 1,013 → one thousand and thirteen; 769 →seven hundred and sixty nine; 6,840 →six thousand, eight hundred and forty; 468 → four hundred and sixty eight; 8,900 → eight thousand nine hundred; 686 → six hundred and eighty six; 6,205 → six thousand, two hundred and five; 490 → four hundred and ninety; 9,866 → nine thousand, eight hundred and sixty six; 671 → six hundred and seventy one; 7,002 → seven thousand and two; 804 → eight hundred and four; 5,676 → five thousand, six hundred and seventy six 3,750 → three thousand, seven hundred and fifty; 77→ seventy seven 2. 967252438 Nine six seven, two five two, four three eight

678345600 Six seven eight, three four five, six double oh

961000768 Nine six one, triple oh, seven six eight

918622355 Nine one eight, six double two, three double five

0034678223355 Double oh three four six, seven eight double two double three, double five

0034963997644 Double oh three four nine, six three double nine, seven six double four

3. 2,538: two thousand, five hundred and thirty eight; 90,304: ninety thousand, three hundred and four; 762: seven hundred and sixty two; 8,300,690,285: Eight billion, three hundred million, six hundred ninety thousand, two hundred and eighty five; 593: five hundred and ninety three; 1,237,569: One million, two hundred [and] thirty seven thousand, five hundred and sixty nine; 3,442,567,321: three billion, four hundred [and] forty two million, five hundred [and] sixty seven thousand, three hundred and twenty one; 76,421: seventy six thousand, four hundred and twenty one; 90,304: ninety thousand, three hundred and four; 762: seven hundred and sixty two; 8,321,678: eight million, three hundred [and] twenty one thousand, six hundred and seventy eight; 250,005: two hundred [and] fifty thousand and five

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Exercises II 1

Population Area (km2)

a) b) c) a) b)

151,570 151,600 152,000 2600 3000

93,350 93,400 93, 000 1,700 2, 000

451,710 451,700 452, 000 200 0

50,470 50,500 50, 000 2,100 2, 000

611,440 611,400 611, 000 100 0

410,950 411,000 411, 000 2,100 2, 000

7,355,420 7,355,400 7,355, 000 1,500 2, 000

193,270 193,300 193, 000 200 0

2

Numbers Ten Hundred Thousand

6,172 6,170 6,200 6,000

18,776 18,780 18,800 19,000

5,217 5,220 5,200 5,000

126,250 126,250 126,300 126,000

5,208 5,210 5,200 5,000

37,509 37,510 37,500 38,000

8,399 8,400 8,400 8,000

7,257 7,260 7,300 7,000

129,790 129,790 129,800 130,000

999 1000 1000 1000

3 a) 40; b) 12 cm; c) 300, 0; d) 75,640, 75,600, 76,000. 4 4.1 a) 92,400€ - 77,000€ = 15,400€; b) 92,428€ - 76,595€ = 15,833

c) The difference is of 433€ (not too much for a house)

4.2 a) 3,600 : 3 = 1200; b) 3,670 : 3 ≈ 1223; c) They are very similar

4.3 a) 500 + 300 + 200 + 400 – 50 = 1350€, b) 499 + 298 + 189 + 4·97 – 48 = 1326€

c) There is not a big difference.

4.4 a) 1,050 : 30 = 35 students, b) 1,048 : 30 = 34.93 = 35 students

4.5 Number of people that voted a) 20,000 + 11000 + 8000 + 6000 = 45000

b) 20,446 + 10,866 + 7,994 + 5,743 = 45 049 c) They are very similar

Difference between the highest and the lowest numbers of votes

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a) 20,500 – 5,700 = 14,200, b) 20,446 – 5,743 = 14,703, c) In this case there is a

significant difference

Exercises III 1 Five, thirty, sixty three, fifty four, nine 2

1. 6x 7 = 42 six times seven is forty two

2. 18 –7 = 11 eighteen minus seven equals eleven

3. 6: 2 – 7 = 10 six divided by two plus seven equals ten

4. 12x3 – 11 = 25 twelve times three minus eleven is twenty five

5. (5x7 +5) : 8 = 5 five times seven plus five, all divided by eight is five

3 1. 6 x 7– 2 = 40 six times seven minus two is forty 2. (8 + 2) : 5 =2 eight plus two, all divided by five is two 3. 28 – 9 – 1 = 18 twenty eight minus nine minus one is eighteen 4. 9 + 3 – 5 = 8 nine plus three minus five equals eight 5. 49 : 7 + 3 = 10 forty nine divided by seven plus three is ten 6. 6 + 4 – 2 – 8 = 0 six plus four minus two minus eight is zero

Exercises IV

1 a) 370.38€ (260 working days); b) He has earned 15288€ in a year and 42€ per day 2 33l of petrol; 714km 3 15, 16 and 17 4 a) 6; b) 126; c) 14; d) 16; e) 5; f) 6. 5 a) 20; b) 33; c) 3; d) 11; e) 25; f) 1600; g) 8; h) 1; i) 115 6 a) 378x45 =+ ; b) ( ) 728x45 =+ ; c) 113156 =÷+ ; d) ( ) 73:156 =+

e) ( ) 547x345 =++ ; f) ( ) 3752x316 =++ ; g) ( ) 28724/24 =⋅+ ;

h) ( ) 83x475:240 =−+

7 a) 35€ (at 1€ per litre); b) 34.30€; c) The difference is 30 cents

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2 Powers

1 Power It is a number obtained by multiplying a number by itself a certain number of times

For example 34 = 3x3x3x3 = 81

How to name powers.

56 Is read as

- Six to the fifth power - Six to the power of five - Six powered to five.

The most common is six to the power of five

6 is the base 5 is the index or exponent

Especial cases: Squares and cubes (powers of two and three) 32 is read as: - Three to the second power - Three squared - Three to the power of two. - Three to the square power The most common is

35 Is read as: - Five cubed - Five to the third power

- Five to the power of three.

The most common is

Three squared

Five cubed

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Exercises

1. Calculate mentally and write in words the following powers: a) =

34 b) =

45 c) =

211 d) =

52 e) =

35 f) =

2100 g) =

310 2. Match the following numbers to their squares. 169 196 25 81 400 10000

220 213 29 25 2100 214 3. Describe the pattern formed by the last digit of any square number.

- Are there any numbers that do not appear as the last digits?

- Could 413 be a square number? 4. Match the following numbers to their cubes. 125 8000 1 64 1000 27

320 34 310 33 35 31

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5. Find and read the whole expression: a) =

33 b) =36 c) =

2600 d) =72 e) =

31000 6. Fill in the missing numbers.

a) [ ]555555 =xxxxx b) [ ]88888 =xxx c) [ ]1010000000 =

d) [ ]481= e) [ ]216 = f) [ ]216 = 7. Write a list with the squares of all the whole numbers from 1 to 12 8. Write a list with the cubes of all the whole numbers from 1 to 10 9. You can build up a pattern using square tiles.

Shape 1 Shape 2 Shape 3

a) Draw the next two shapes in the pattern.

b) Count the numbers of tiles in each shape and put your results in a table

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Shape number 1 2 3 4 5

Tiles

c) How many tiles would be in: 1. Shape 6 2. Shape 9 3. Shape 15 d) Without drawing it, explain how to know the number of tiles when you

know the number of the shape. 10. This pattern is built up using square tiles.

1 3 + 5 7+9+11 Shape 1 Shape 2 Shape 3

e) Draw the next two shapes in the pattern.

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f) Count the numbers of tiles in each shape and put your results in a table

Shape number 1 2 3 4 5

Tiles

g) How many tiles would be in: 1. Shape 5 2. Shape 7 3. Shape 10 h) Without drawing it, explain how to know the number of tiles when you

know the number of the shape. 11. Some numbers are equal to the sum of two squares, for example

3453 22=+ .

Which numbers smaller than 100 are equal to the sum of two squares? How many of them are equal to the sum of two squares in more than one

way?

Big numbers can be written using powers of 10, for example 410770000 x= , 81023.1123000000 x= this form of writing numbers is called standard form.

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12. Express in standard form the following numbers:

a) 4,000,000,000 b) A billion

c) 321,650,000 (round to the million)

d) The length of the earth meridian in metres.

e) The number of seconds in a year (round appropriately) 13. Write as ordinary numbers a) 5104.3 x b) 21005.0 x c) 810473.2 x d) 21026.7 x e) 710006.7 x f) 12109x 2 Operations with powers To manipulate expressions with powers we use some rules that are called laws of powers or laws of indices. 2.1 Multiplication: When powers with the same base are multiplied, the base remains unchanged and the exponents are added Example:

( ) ( ) 835 77777777777 == xxxxxxxx

So 835 777 =x Exercise 14. Fill in the missing numbers.

a) ( ) ( ) [ ]33333333333333333 43=⋅⋅⋅⋅⋅⋅=⋅⋅⋅⋅⋅⋅=⋅

b) [ ]777 85=⋅ c) [ ]666 72

=⋅ d) [ ] 95 666 =⋅

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e) [ ] [ ] 7432=⋅ f) [ ] 65 222 =⋅ g) [ ][ ] 97 22 =⋅

2.2 Division: When powers with the same base are divided, the base remains unchanged and the exponents are subtracted. Example:

So 347 66:6 = Exercise 15. Fill in the missing numbers.

a) [ ]77:7 25= b) [ ]1212:12 713

= c) [ ] 538 3:3 =

d) [ ] [ ] 725:5 = e) [ ] 538 3:3 = f) [ ] [ ] [ ]9:

912=

2.3 Power of a power: The exponents or indices must be multiplied Example:

( ) ( ) ( ) ( ) ( ) ( ) 1553333333333353 222222222 ====++++ xxxxx

So ( ) 1553 22 =

Exercise 16. Fill in the missing numbers.

a) ( ) [ ]4452

= b) ( )[ ] 82 33 = c) [ ]( ) 8233 =

d) [ ]( ) 632

5= e) ( )[ ][ ]822 =

2.4 Powers with different base but the same exponent Multiplication: When powers with the same exponent are multiplied, multiply the bases and keep the same exponent.

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Example:

( ) 5555 147272 == xx Division: When powers with the same exponent are divided, bases are divided and the exponent remains unchanged. Example:

( ) 3333 42:82:8 == , we can also use fractions notation 3

3

3

3

42

8

2

8=

=

Exercise 17. Fill in the missing numbers.

a) [ ]777 83 =⋅ b) [ ] [ ] 2226=⋅ c) [ ] 222 155 =⋅

d) [ ] [ ]14222

=⋅ e) [ ]555 4:8 = f) [ ]55

5

5

15=

g) [ ]77

7

8

16= h) [ ][ ]

=12

12

3

6

Exercise 18. Operate. a) [ ]777 53

=⋅ b) =⋅⋅⋅ 4444 632 c) =⋅⋅272 999

d) =37 5:5 e) ( ) =⋅

362 2:22 f) ( ) =4214

g) ( ) =⋅327 33:3 h) ( ) [ ]222 32 =⋅ i) ( ) =⋅

432 1212

j) ( ) [ ]222 3:6 = k) ( )[ ] [ ]333:32328

=⋅ l) =⋅4

37

5

55

3 Square roots. The inverse operation of power is root.

The inverse of a square is a square root, that is: If we say that 39 = , that

means that 932=

19. Calculate the following square roots: a) =81 b) =121 c) =100 d) =10000 e) =900 f) =1600 g) =250000

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There are numbers that are not squares of any other number, for example between 9 and 16 (squares of 3 and 4); there is not any whole square number.

The square root of all numbers between 9 and 16 are between 3 and 4, for example

4133 << , this is an estimation of the 13 value.

Exercise 20. Estimate the value of the following square roots: a) << 57 b) << 250 c) << 700 d) << 1500 e) << 30 f) << 2057

When we estimate a square root as 4133 << we can also say that 13 is 3

and the difference of 13 and 9 (square of 3), which is 4, is called the remainder.

So we say that the square root of 13 is 9 and the remainder is 4.

That means 4313 2+=

Exercise 21. Calculate the square roots and the remainders for the numbers of the previous exercise; write the meanings as in the example.

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Solutions

1. a) 6443= four cubed is sixty four; b) 62554

= five to the power of four equals six

hundred and twenty five; c) 121112= eleven squared is one hundred and twenty

one; d) 3225= five to the power of five is/are thirty two; e) 12553

= five cubed is

one hundred and twenty five; f) 100001002= one hundred squared is ten thousand;

g) 1000103= ten cubed is one thousand

2. (169, 213 ); (196, 214 ); (25, 25 ); (81, 29 ); (400, 220 ); (10000, 2100 ) 3. The last digit of any square number can be 0, 1,4, 5, 6 or 9; 413 can not be a square number 4. (125, 35 ); (8000, 320 ); (1, 31 ); (64, 34 );(1000, 310 ); (27, 33 )

5. a) 2733= ; b) 21663

= ; c) 3600006002= ; d) 12827

= ; e) 100000000010003=

6. a) [ ]555xx5x5x5x5 = ; b) [ ]488x8x8x8 = ; c) [ ]71010000000 = ; d) [ ]4

381=

e) [ ]2416 = ; f) [ ]4216 =

7. 112

= ; 422= ; 932

= ; 1642= ; 2552

= ; 3662= ; 4972

= ; 6482= ; 8192

= ;

100102= ; 121112

= ; 144122= .

8. 113

= ; 823= ; 2733

= ; 6443= ; 12553

= ; 21663= ; 34373

= ; 51283= ;

72993 = ; 1000103= .

9. a) Shape 4 Shape 5 b)

1. Shape 6 = 36; 2. Shape 9 = 81; 3. Shape 15 = 225 c) The number of tiles is the square of the number of the shape

Shape number 1 2 3 4 5

Tiles 1 4 9 16 25

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10. a)

b) c) 1. Shape 5 = 125; 2. Shape 7 = 343; 3. Shape 10 = 1000

d) The number of tiles is the cube of the number of the shape

11. 1, 5, 8, 10, 13, 17, 18, 20, 25, 26, 29, 32, 34, 37, 40, 41, 45, 50, 52, 53, 58, 61,

65, 67, 72, 73, 74, 80, 82, 85, 89, 90, 92, 97, 100. 505571 2222=+=+ ;

658174 2222=+=+ ; 859276 2222

=+=+

12. a) 9104 ⋅ ; b) 12101⋅ ; c) 81022.3 ⋅ ; d) 7104 ⋅ e) 71015.3 ⋅

13. a) 000,34010x4.3 5= ; b) 510x05.0 2

= ; c) 000,300,24710x473.2 8=

d) 72610x26.7 2= ; e) 000,060,7010x006.7 7

= ; f) 000,000,000,000,910x9 12=

14. a) [ ]73 ; b) [ ]137 ; c) [ ]96 ; d) 46 ; e) [ ] [ ]4322 ⋅ ; f) [ ]12 ; g) [ ][ ]2

2

15. a) [ ]37 ; b) [ ]612 ; c) [ ]33 ; d) [ ] [ ]29 5:5 ; e) [ ]33 ; f) [ ] [ ] [ ]391299:9 =

16. a) [ ]104 ; b) ( )[ ]423 ; c) [ ]( )243 ; d) [ ]( )325 ; e) ( )[ ]

[ ]842 22 = 17. a) [ ]7

24 ; b) [ ] [ ]2223 ⋅ ; c) [ ]22 35 ⋅ ; d) [ ] [ ]222 1472 =⋅ ; e) [ ]5

32 ; f) [ ]53 ;

g) [ ]72 ; h) [ ][ ]12

2

18. a) [ ]87 ; b) 124 ; c) 119 ; d) 45 ; e) 52 ; f) 814 ; g) 23 ; h) [ ]2

6 ; i) 2012 ;

j) [ ]22 ; k) [ ]63 ; l) 65 .

19. a) 9 ; b) 11; c) 10 ; d) 100 ; e) 30 ; f) 40 ; g) 500 20. a) 8577 << ; b) 1625015 << ; c) 2770026 << ; d) 39150038 << ; e)

6305 << ; f) 46205745 << .

21. a) 8757 2

+= ; b) 2515250 2+= ; c) 2426700 2

+= ; d) 56381500 2+= ;

e) 5530 2+= ; f) 32452057 2

+= .

Shape number 1 2 3 4 5

Tiles 1 8 27 64 125

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3 Multiples and factors

1 Multiples

The products of a number with the natural numbers 1, 2, 3, 4, 5, ... are called the multiples of the number.

For example:

284x7

213x7

142x7

71x7

=

=

=

=

So, the multiples of 7 are: 7, 14, 21, 28, and so on. Note: The multiples of a number are obtained by multiplying the number by each of the natural numbers. For example:

• multiples of 2 are 2, 4, 6, 8, … • multiples of 3 are 3, 6, 9, 12, … • multiples of 4 are 4, 8, 12, 16, …

Example 1

Write down the first ten multiples of 5. Solution: The first ten multiples of 5 are 5, 10 15, 20, 25, 30, 35, 40, 45, 50.

Exercise 1 a) Write down all the multiples of 6 between 20 and 70 b) Write down all the multiples of 7 between 30 and 80 c) Write the three smallest multiples of 8 which are over 50 d) Write the smallest multiple of 37 which is over 500

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2 Factors

A whole number that divides exactly into another whole number is called a factor of that number.

For example 54:20 = So, 4 is a factor of 20 as it divides exactly into 20. We could also consider than 20:5 = 4 So, 5 is a factor of 20 as it divides exactly into 20. Note: If a number can be expressed as a product of two whole numbers, then the whole numbers are called factors of that number. For example 5x410x220x120 ===

So, the factors of 20 are 1, 2, 4, 5, 10 and 20. Example 2

List all the factors of 42. Solution: 7x614x321x242x142 ====

So, the factors of 42 are 1, 2, 3, 6, 7, 14, 21 and 42.

Example 3

Is 7 a factor of 15? Solution:

=÷1remainder

2quotient715 .

Clearly 7 does not divide exactly into 15, so 7 is not a factor of 15

Exercise 2 Write down all the factors of

a) 60 b) 20

c) 100

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3 Prime Numbers

If a number has only two different factors, 1 and itself, then the number is said to be a prime number.

For example, 7 = 1x7 7 is a prime number since it has only two different factors. 2 = 1x2, 3 = 1x3, 5 = 1x5,… 2,3,5,…. Are prime numbers Exercise 3 The Sieve of Eratosthenes A Greek mathematician, Eratosthenes (276-195 BC), discovered the Sieve which is known as the Sieve of Eratosthenes, it is a method to get prime numbers. 3.1 We start with a table of whole numbers e.g. from 1 to 200 and cross out the number 1, as it has been done below.

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3.2. Circle the number 2 and then cross out all the multiples of 2, as shown below.

3.3. The next number that is not crossed out is 3. Circle it and then cross out all the multiples of 3: 3, 6, 9, 12.... 3.4. The next number that is not crossed out is 5. Circle it and then cross out all the multiples of 5: 5, 10, 15, 20…. 3.5. The next number that is not crossed out is 7. Circle it and then cross out all the multiples of 7. 3.6. Continue this process until there is no number to be crossed. 3.7. Make a list of all the circled numbers. 3.8. Write the factors of each of the circled numbers. 3.9. Make a list of the first twenty crossed out numbers and write the factors of these numbers.

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3.10 What do you observe about the number of factors of the circled numbers and the crossed out numbers? Write a brief sentence in your own words. 3.11. What name is given to the circled numbers? 3.12. What name is given to the crossed out numbers? 3.13. How many prime numbers are less than 100?

4 Tests of divisibility

One number is divisible by:

2 If the last digit is 0 or is divisible by 2, (0, 2, 4, 8).

3 If the sum of the digits is divisible by 3.

4 If the last two digits are divisible by 4.

5 If the last digit is 0 or is divisible by 5, (0,5).

9 If the sum of the digits is divisible by 9.

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8 If the half of it is divisible by 4.

6 If it is divisible by 2 and 3.

11 If the sum of the digits in the even position minus the sum of the digits in the

uneven position is 0 or divisible by 11.

Exercise 4 Find which of the numbers: 239 300 675 570 800 495 888 6402 2088 are multiples of:

a) 3 → b) 2 → c) 5 → d) 4 → e) 11 → f) 9 →

Exercise 5 Find the factor decomposition of the following numbers:

24 123 420 4752

24 = 123 = 420 = 4752 =

5 Common Multiples

Multiples that are common to two or more numbers are said to be common multiples.

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E.g. Multiples of 2 are 2, 4, 6, 8, 10, 12, 14, 16, 18, … Multiples of 3 are 3, 6, 9, 12, 15, 18, … So, common multiples of 2 and 3 are 6, 12, 18, … Example 4

Find the common multiples of 4 and 6. Solution: Multiples of 4 are 4, 8, 12, 16, 20, 24, 28, 32, 36, … Multiples of 6 are 6, 12, 18, 24, 30, 36, … So, the common multiples of 4 and 6 are 12, 24, 36, …

Exercise 6 a) Find the sequence of the common multiples of 3 and 5. b) Find the sequence of the common multiples of 12 and 9.

Lowest common multiple

The smallest common multiple of two or more numbers is called the lowest common multiple (LCM).

E.g. Multiples of 8 are 8, 16, 24, 32, … Multiples of 3 are 3, 6, 9, 12, 15, 18, 21, 24, … LCM of 3 and 8 is 24

Method I (for small numbers) To find the lowest common multiple (LCM) of two or more numbers, list the multiples of the largest number and stop when you find a multiple of the other number. This is the LCM. Example 5

Find the lowest common multiple of 6 and 9. Solution: List the multiples of 9 and stop when you find a multiple of 6.

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Multiples of 9 are 9, 18, … Multiples of 6 are 6, 12, 18, … LCM of 6 and 9 is 18

Example 6

Find the lowest common multiple of 5, 6 and 8. Solution: List the multiples of 8 and stop when you find a multiple of both 5 and 6. Multiples of 8 are 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96, 104, 112, 120, … Stop at 120 as it is a multiple of both 5 and 6. So, the LCM of 5, 6 and 8 is 120.

Exercise 7 Find the LCM of

a) 6 and 8 b) 10 and 20 c) 8 and 12

Method II (General)

To find the lowest common multiple (LCM) of higher numbers: - Find the prime factor decomposition. - Choose the non common factors and the common factors with the highest exponents.

Example 7

Find the lowest common multiple of 18 and 24. Solution:

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3224

32183

2

⋅=

⋅= So, the LCM of 18 and 24 is 7232LCM 23

=⋅= .

Exercise 8 Find the LCM of

a) 150 and 350 b) 100 and 120

c) 120, 480 and 180

6 Common Factors

Factors that are common to two or more numbers are said to be common factors.

For example 32616

22414

xx

xx

==

==

- Factors of 4 are 1,2 and 4 - Factors of 6 are 1, 2, 3 and 6

So, the common factors of 4 and 6 are 1 and 2 Example 8

Find the common factors of 10 and 30. Solution:

1036515230130

5210110

xxxx

xx

====

==

So, the common factors of 10 and 30 are 1, 2, 5 and 10.

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Example 9

Find the common factors of 26 and 39. Solution:

13339139

13226126

xx

xx

==

==

So, the common factors of 26 and 39 are 1 and 13.

7 Highest Common Factor

The largest common factor of two or more numbers is called the highest common factor (HCF).

For example 436212112

42818

xxx

xx

===

==

- Factors of 8 are 1,2, 4 and 8 - Factors of 12 are 1, 2, 3, 4, 6 and 12

So, the common factors of 8 and 12 are 1, 2 and 4 HCF is 4 Example 10

Find the highest common factor of 14 and 28. Solution:

7414228128

7214114

xxx

xx

===

== HCF = 14

To find the Highest Common Factor of higher numbers: - Find the prime factor decomposition. - Choose only the common factors with the lowest exponents.

Exercise 9 Find the HCF and the LCM of:

a) 18 and 24 b) 180 and 40

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c) 60, 320 and 140

EXTRA EXERCISES

1. Which numbers between 37 and 74 have a factor of 3?

2. Which of these is a multiple of 6?

122, 28, 30, 402, 634, 348, 10,500

3. List all the prime numbers between 20 and 50.

4. List all the factors of:

a) 12 b) 30 c) 66 d) 200

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5. In a bus station there is a bus leaving for London every 45 minutes and

one leaving for Brighton every 60 minutes. If a bus to London and a bus to

Brighton leave at the same time, how many minutes will it be before two

buses leave again at the same time?.

6. Find the prime factorization of both 156 and 250. What is the HCF of

these numbers? What is the LCM?

7. List all the common factors of 30 and 75. What is the HCF of 30 and 75?

What is the LCM of 30 and 75?

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8. Find the HCF and the LCM of 36 and 90.

9. Lara has a day off every six days and Dave has a day off every eight

days, if they both have a day off on the first of November, which day will

they have the same day off again?

10. What numbers that are less than 100 are multiples of 3 and 5?

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11. How many different rectangles with an area of 36 cm2 using only whole

numbers (centimetres), can be made?

12. Three traffic lights are placed along the same avenue at three different

crosses. The first one changes every 20 seconds, the second, every 30

seconds and the third every 28 seconds. They have changed to green

simultaneously. How long does it take until they change again at the same

time? Explain your answer.

13. Marta has 12 red, 30 green and 42 yellow marbles and she wants to

put them in boxes, as many as possible, all the boxes with the same

amount of each colour and with no marbles remaining. How many boxes

will she have? How many marbles of each colour are there in each box?

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Solutions Exercise 1 a) 24, 30, 36, 42, 48, 54, 60 and 66; b) 35, 42, 49, 56, 63, 70 and 77 c) 56, 64 and 72; d) 518 Exercise 2 a) 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30 and 60; b) 1, 2, 4, 5, 10 and 20; c) 1, 2, 4, 5, 10, 20, 25, 50 and 100 Exercise 3: 3.1 to 3.7

3.8. Only the number multiplied by 1 3.9. 1=1, 4=2x2, 6=3x2, 8=2x2x2, 9=3x3, 10=2x5, 12=2x2x3, 14=2x7, 15=3x5, 16=2x2x2x2, 18=3x3x2, 20=2x2x5, 21=3x7, 22=2x11, 24=2x2x2x3, 25=5x5, 26=2x13, 27=3x3x3, 28=2x2x7, 30=2x3x5 3.11. Prime numbers 3.12. Composite numbers 3.13. 25 numbers Exercise 4 Multiples of: a) 3 → 300, 675, 570, 495, 888, 6402, 2088 b) 2 → 300, 570, 800, 888, 6402, 2088; c) 5 → 300, 675, 570, 800, 495 d) 4 → 300, 800, 888, 2088; e) 11 → 495, 6402; f) 9 → 675, 495, 2088 Exercise 5 3224 3

⋅= ; 413123 ⋅= ; 7532420 2⋅⋅⋅= ; 11324752 34

⋅⋅= Exercise 6 a) 15, 30, 45, …; b) 36, 72, 108, … Exercise 7 a) 24; b) 20; c) 24. Exercise 8 a) 1050; b) 600; c) 1440

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Exercise 9 a) 6 and 72; b) 20 and 360; c) 20 and 6720.

EXTRA EXERCISES

1. 39, 42, 45, 48, 51, 54, 57, 60, 63, 66 and 69

2. 30, 402, 348 and 10,500

3. 23, 29, 31, 37, 41, 43 and 47.

4. a) 1, 2, 3, 4, 6 and 12. b) 1, 2, 3, 5, 6, 10, 15 and 30. c) 1, 2, 3, 6, 11, 22, 33

and 66. d) 1, 2, 4, 5, 8, 10, 20, 25, 40, 50, 100 and 200.

5. LCM(45,60) = 180 min.

6. 1332156 2⋅⋅= , 352250 ⋅= , 2)250,156(HCF = , 19500)250,156(LCM =

7. 1, 3, 5 and 15, 15)75,30(HCF = , 150)75,30(LCM = .

8. 18)90,36(HCF = , 180)90,36(LCM = .

9. 24)8,6(LCM = , they both will have a day off again on the 25th of november.

10. 15, 30, 45, 60, 75 and 90.

11. 1x36, 2x18, 3x12, 4x9 and 6x6 cm.

12. LCM(20,30,28) = 420 secons or 7 minutes.

13. 6)42,30,12(HCF = , so 6 boxes, each one containing 2 red, 5 green and 7

yellow marbles.

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4-1

4 Fractions

1 Fractions A fraction is a number that expresses part of a unit or a part of a quantity.

Fractions are written in the form b

a where a and b are whole numbers, and

the number b is not 0. They can be written also in the form a/b

The number a is called the numerator, and the number b is called the denominator. The numerator tells us how many equal parts we have. The denominator tells us how many equal parts are available.

The fraction 6

4 represents the shaded

portion of the circle on the right. There are 6 pieces in the group, and 4 of them are shaded.

2 Reading fractions

We use the cardinals to name the numerator and the ordinals for the denominator with two exceptions when the denominators are 2 and 4, for denominator larger than 10 we say “over” and do not use ordinal, so we read:

2

1 one half

2

3 three halves

3

2 two thirds

4

1 a quarter or a fourth

15

12 twelve over fifteen

4

3 three quarters or three fourths

10

6 six tenths

32

17 seventeen over thirty-two

5

7 seven fifths…...

Exercise 1 Write in words the following fractions

4

11 ⇒

8

3 ⇒

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4-2

6

9 ⇒

2

17 ⇒

9

4 ⇒

62

19 ⇒

12

1 ⇒

93

14 ⇒

903

17 ⇒

Exercise 2 Write and read the fractions that represent the shaded portions.

3 Equivalent fractions

Equivalent fractions are different fractions that name the same amount. Examples: - 1/2 is equivalent to 2/4, because we have multiplied both the numerator and the denominator by 2 and the total amount does not change. - 12/20 is equivalent to 3/5, because we have divided both the numerator and the denominator by 4. - The fractions 1/2, 2/4, 3/6, 100/200, and 521/1042 are all equivalent fractions. - The fractions 3/5, 6/10, 12/20 and 24/40 are all equivalent fractions.

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4-3

Exercise 3 Write a sequence of equivalent fractions as in the example:

Starting fraction Equivalent fractions

3

1

6

2

9

3

12

4

15

5

18

6

21

7

5

2

16

8

32

16

3

7

27

18

We can test if two fractions are equivalent by cross-multiplying their numerators and denominators. This is also called taking the cross-product.

a c b d

So if we want to test if 20

12and

40

24are equivalent fractions

The first cross-product is the product of the first numerator and the second denominator: 12 × 40 = 480.

The second cross-product is the product of the second numerator and the first denominator: 24 × 20 = 480. Since the cross-products are the same, the fractions are equivalent.

Exercise 4

a) Test if 3/7 and 18/42 are equivalent fractions.

b) Test if 2/4 and 13/20 are equivalent fractions.

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Simplest form

We know that 4/12 = 2/6 = 1/3 4 and 12 have a common factor (4), so 4/12 can be written as 1/3 (Divide the top and the bottom by 4.) 2 and 6 have a common factor (2), so 2/6 can be written as 1/3 (Divide the top and the bottom by 2.) However, 1 and 3 have no common factors, so 1/3 is the simplest form of these fractions. There are two methods of reducing a fraction to the lowest terms. Method 1: Divide the numerator and denominator by their HCF. 12/30 = (12 : 6)/(30 : 6) = 2/5 Method 2: Divide the numerator and denominator by any common factor. Keep dividing until there are no more common factors.

12/30 = (12 : 2)/(30 : 2) = 6/15 = (6 : 3)/(15 : 3) = 2/5

Exercise 5 Express these fractions in the simplest form.

a) 10

5 b)

9

3 c)

21

7 d)

51

9

e) 84

48 f)

51

17 g)

72

9 h)

88

64

i) 125

25 j)

100

30 k)

49

21 l)

90

52

Exercise 6 Express, in the simplest form, which fraction corresponds to these situations:

a) In a bag of 90 pens, 15 are blue b) The number of girls and boys in our class

c) There are 90 pupils of the 270 who come by bus to the school.

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4 Comparing and ordering fractions

1. To compare fractions with the same denominator, look at their numerators. The largest fraction is the one with the largest numerator. 2. To compare fractions with different denominators, take the cross product. Compare the cross products.

a. If the cross-products are equal, the fractions are equivalent. b. If the first cross product is larger, the first fraction is larger.

c. If the second cross product is larger, the second fraction is larger.

Examples: Compare the fractions 3/7 and 1/2. The first cross-product is: 3 × 2 = 6. The second cross-product is: 7 × 1 = 7. Since the second cross-product is larger, the second fraction is larger. Compare the fractions 13/20 and 3/5. The first cross-product is: 5 × 13 = 65. The second cross-product is: 20 × 3 = 60. Since the first cross-product is larger, the first fraction is larger. Exercise 7 Order the following fractions:

a) 5

2,

7

3 b)

5

3,

13

8

c) 19

22,

11

8,

4

3 d)

17

9,

7

18,

12

7

5 Adding and subtracting fractions

1. If the fractions have the same denominator:

The numerator of the sum is found by simply adding the numerators over the denominator. Their difference is the difference of the numerators over the denominator.

We do not add or subtract the denominators!

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Reduce if necessary. Examples: 3/8 + 2/8 = 5/8 9/2 - 5/2 = 4/2 = 2 2. If the fractions have different denominators

For example 8

7

5

3+

1) First, find the lowest common denominator. For this problem complete the following steps:

a) We find the LCM of the denominators as it is the smallest number into which both denominators will divide. For 5 and 8, it is easy to see that 40 is the LCM. We look for equivalents fractions with 40 as common

denominator. [ ]405

3= and

[ ]408

7=

b) We divide every new denominator by the previous one and we multiply the result by the numerator.

[ ]405

3= We divide the new denominator 40 by the previous one 5 what gives

us 8, we must multiply 3 by 8, so 40

24

5

3= .

With the same process:

[ ]40

35

408

7== We have multiplied top and bottom by 5

2) Add the numerators and do not change the denominator.

40

59

40

3524

40

35

40

24

8

7

5

3=

+=+=+

3) Reduce if necessary. Exercise 8 Find and reduce:

a) 4

5

4

3+ b)

13

5

13

3+

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4-7

c) 4

3

4

1+ d)

5

3

5

7−

e) 7

2

7

3

7

6+− f)

2

3

2

1−

g) 10

3

5

4+ h)

16

3

8

3+

i) 15

2

6

1+ j)

16

3

12

5−

k) 4

3

3

4+ l)

6

7

4

3

2

1++

m) 8

3

2

1

4

3+− n)

2

3

7

1

14

11+−

o) 5

8

16

13

12

7+−

Exercise 9 Laura bought a 1/2 kg bag of sweets. She ate 1/3 kg herself and gave the rest to Robert. How much did she give to Robert?

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6 Improper fractions Mixed numbers Improper fractions have numerators that are larger than or equal to their

denominators.

For example 7

15,

7

7, and

3

18 are improper fractions.

Mixed numbers have a whole number part and a fraction part.

For example 5

32 ,

3

15 are mixed numbers, meaning

5

32

5

32 += and

3

15

3

15 += .

Converting improper fractions to mixed numbers

To change an improper fraction into a mixed number, divide the numerator by the denominator. The quotient is the whole part and the remainder is the numerator of the fractional part. For example

4

15,

⇒3remainder

3quotient4:15 so

4

33

4

15=

3

17,

⇒2remainder

5quotient3:17 so

3

25

3

17=

Converting mixed numbers to improper fractions

To change a mixed number into an improper fraction, multiply the whole number by the denominator and add it to the numerator of the fractional part.

For example

5

13

5

352

5

32

5

32 =

+⋅=+=

3

23

3

237

3

27 =

+⋅=

Note that converting mixed numbers to improper fractions is the same as

adding whole numbers and fractions

Exercise 10 Operate converting first to improper fractions and express the result as a mixed number.

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a) 8

73

4

1

2

31 ++

b) 3

14

2

13 +

c) 5

21

4

12 −

d) 3

11

4

12

6

13 −+

7 Multiplying fractions

When two fractions are multiplied, the result is a fraction with a numerator that is the product of the fractions' numerators and a denominator that is the product of the fractions' denominators. Reduce when possible.

Examples:

40

9

58

33

5

3

8

3=

⋅=⋅ i)

15

7

53

7

56

27

5

2

6

7=

⋅=

⋅=⋅ We cancel the common factor

of 2 in the top and bottom of the product. Remember that like factors in the numerator and denominator cancel out.

Exercise 11 Multiply giving your answers in the simplest form

a) =⋅11

7

5

4 b) =⋅

19

15

15

14

c) =⋅7

2

4

5 d) =⋅

19

2

6

5

e) =⋅⋅2

17

7

5

3

1 f) =⋅⋅

7

3

5

2

9

5

g) =⋅⋅23

7

21

26

13

12 h) =⋅⋅

9

14

40

3

7

120

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8 Multiplying a fraction by a whole number Calculating a fraction of a quantity

To multiply a fraction by a whole number, choose one of the two methods:

1. Write the whole number as an improper fraction with a denominator of 1, and then multiply as fractions.

2. Multiply the whole number by the numerator and do not change the

denominator. Examples:

a) 7

12

7

2

1

6

7

26 =⋅=⋅ b)

19

15

19

35

19

35 =

⋅=⋅

To calculate a fraction of a quantity which is multiple of the denominator it is more convenient to divide it by the denominator and then multiply by the numerator. Example:

8

5 of 192 kg.

328:192 = , and 1605x32 = . So the 8

5 of 192 kg are 160 kg

Exercise 12 Operate giving your answers in the simplest form

a) =⋅6

542 b) =⋅

9

4198

c) =⋅374

5 d) =⋅18

8

5

e) =⋅⋅5

17

9

32 f) =⋅⋅

7

33

8

2

g) =⋅⋅13

17

21

667 h) =⋅

4

315

Exercise 13 Calculate:

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a) 6

5 of 2 days (in hours) b)

5

3 of a litre (in ml)

c) 7

3 of 1470 g d)

3

1 of 30 pupils

e) 9

7 of 270 ml f)

21

2 of 9 weeks (in days)

g) 8

3 of 3000 € h)

4

3 of 7 tonnes (in kg)

Exercises 14 14.1 There are 720 pupils in a school, find the number of pupils in each group if:

a) 3

2 enjoy mathematics

b) 6

5 enjoy sports

c) 8

3 do not do their homework

d) 20

9 expect to go to university

14.2 There are 360º in one complete revolution. Calculate the degrees of the following angles:

a) 5

3 of a revolution

b) 12

7 of a revolution

c) 6

5 of a revolution

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d) 9

5 of a revolution

e) 4

3 of a revolution

9 Dividing fractions

To divide fractions, multiply the first one by the reciprocal of the second fraction. The reciprocal of a fraction is obtained by switching its numerator and denominator. We can also take the cross product. To divide a number by a fraction, multiply the number by the reciprocal of the fraction.

Example:

35

44

7

11

5

4

11

7:

5

4=⋅= or simply taking the cross product

35

44

7x5

11x4

11

7:

5

4==

Exercise 15 Operate:

a) =9

4:

2

3

b) =19

5:

5

1

c) =7

4:

14

3

d) =6

5:

3

15

e) =

4

7:

8

5:

3

5

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4-13

f) =

3

13:

7

9:2

g) =

3

13:

7

9:2

h) =⋅

9

14

40

3:5:

55

20

Exercises 16

16.1. In a factory a metal rod 49 metre long is divided into 5

7 metre

pieces. How many pieces can be made from each rod?

16.2. A math’s teacher spends 5

4 of his working time in school teaching

his classes. If 9

2 of this teaching time is spent with his first year

classes. What fraction of his working time does he spend teaching the first year?

16.3 A six tonne load of soil container is divided in 140

3 tonne bags.

How many bags can be filled?

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4-14

16.4. How many pieces would there be if 10

34 metres of ribbon were

divided into tenths of a metre?

16.5 Last night John spent 4

3 of an hour on English homework and

6

1

on his maths. If he started his homework at 20 o’clock, did he finish it in time to watch The Simpsons, which started at 21 o’clock? Explain your answer.

16.6 Dolly opened a 4

3 litre bottle of coke, James drank

3

1 litre and

Carole 5

1 litre. How much coke was left for Dolly?

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4-15

Solutions

Exercise 1 4

11 ⇒ Eleven quarters or eleven over four or eleven fourths,

8

3 ⇒ three over eight or three eighths,

6

9 ⇒ nine over six or nine sixths,

2

17 ⇒ seventeen halves or seventeen over two,

9

4 ⇒ four over nine or four

ninths, 62

19 ⇒ nineteen over sixty two,

12

1 ⇒ one over twelve or one twelfth,

93

14 ⇒ fourteen over ninety three,

903

17 ⇒ seventeen over nine hundred and

three. Exercise 2 Three over eight or three eighths, two over three or two thirds. Exercise 3

Starting fraction Equivalent fractions

3

1

6

2

9

3

12

4

15

5

18

6

21

7

5

2

10

4

15

6

20

8

25

10

30

12

35

14

16

8

32

16

48

24

64

32

80

40

96

48

112

56

32

16

48

24

64

32

80

40

96

48

112

56

128

64

3

7

6

14

9

21

12

28

15

35

18

42

21

49

27

18

54

36

81

54

108

72

135

90

162

108

189

126

Exercise 4 a) Yes, b) No.

Exercise 5 a) 2

1

10

5= , b)

3

1

9

3= , c)

3

1

21

7= , d)

17

3

51

9= , e)

7

4

84

48= ,

f) 3

1

51

17= , g)

8

1

72

9= , h)

11

8

88

64= , i)

5

1

125

25= , j)

10

3

100

30= , k)

7

3

49

21= ,

l) 45

26

90

52= .

Exercise 6 6

1, c)

3

1.

Page 65: Book 1 ESO Geometric

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4-16

Exercise 7 a) 5

2

7

3> , b)

5

3

13

8> , c)

19

22

4

3

11

8<< , d)

7

18

12

7

17

9<<

Exercise 8 a) 2 , b) 13

8, c) 1, d)

5

4, e)

7

5, f) 1− , g)

10

11, h)

16

9, i)

10

3, j)

48

11,

k) 12

25, l)

12

29, m)

8

5, n)

28

115, o)

240

329.

Exercise 9 6

1 Kg .

Exercise 10 a) 8

56 , b)

6

57 , c)

20

17, d)

12

14 .

Exercise 11 a) 55

28, b)

19

14, c)

14

5, d)

57

5, e)

42

85, f)

21

2, g)

23

8, h) 2

Exercise 12 a) 35 , b) 44 , c) 4

185, d)

4

45, e)

15

34, f)

28

9, g)

13

374, h)

4

45

Exercise 13 a) 40 hours, b) 600 ml, c) 630 g, d) 10 pupils, e) 210 ml, f) 6 days, g) 1125 €, h) 5250 kg Exercises 14 14.1 a) 480, b) 600, c) 270, d) 324; 14.2 a) 216º, b) 210º, c) 300º, d) 200º, e) 270º.

Exercise 15 a) 8

27, b)

25

19, c)

8

3, d) 6 , e)

21

32, f)

27

182, g)

39

14, h)

297

448

Exercises 16

16.1. 35 pieces of rod, 16.2. he spends teaching the first year 45

8 of his

working time, 16.3 280 bags, 16.4. 43 pieces, 16.5. yes, John spends on his

homework 55 minutes. 16.6 60

13of a litre.

Page 66: Book 1 ESO Geometric

5-1

5 Decimal numbers

1 Decimal numbers Decimal numbers such as 3.762 are used in situations in which we look for

more precision than whole numbers provide.

As with whole numbers, a digit in a decimal number has a value which

depends on the place of the digit. The places to the left of the decimal point

are ones, tens, hundreds, and so on, just as with whole numbers. This table

shows the decimal place value for various positions:

Note that adding extra zeros to the right of the last decimal digit does not

change the value of the decimal number.

Place (underlined) Name of Position

1.234567 Ones (units) position

1.234567 Tenths

1.234567 Hundredths

1.234567 Thousandths

1.234567 Ten thousandths

1.234567 Hundred Thousandths

1.234567 Millionths

Example:

In the number 3.762, the 3 is in the units place, the 7 is in the tenths place,

the 6 is in the hundredths place, and the 2 is in the thousandths place.

- 3 is called the whole number portion

- 762 is the decimal portion

2 How to read decimal numbers. We have to read the whole number, then the word “point” and the decimal

numbers one by one.

Example:

In the number 2.34 we say two point three four

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5-2

We read the number 0.057 as nought point zero five seven.

Exercise 1

Write in words the following:

21.456

0.77

0.0089

5.7254

3 Adding and subtracting decimals To add or subtract decimals, line up the decimal points and then follow the

rules for adding or subtracting whole numbers, placing the decimal point in

the same column as above.

When one number has more decimal places than another, use 0's to give

them the same number of decimal places.

Example:

Add 43.67 + 2.3

1) Line up the decimal points and adds a 0 on the right of the second:

2) Then add.

43.67

2.30

45.97

Example:

Subtract. 57.8 – 8.06

1) Line up the decimal points.

2) Add extra 0's

3) Subtract.

57.80

8.06

49.74

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4 Multiplying decimal numbers Multiplying decimals is just like multiplying whole numbers. The only extra

step is to decide how many digits to leave to the right of the decimal point. To

do that, add the numbers of digits to the right of the decimal point in both

factors.

Example:

Multiply 23.56 x 34.1

23.56

34.1

2356

9424

7068

803.396

Exercise 2 Calculate

a) 5.6 x 6.9 b) 12.37 x 76.78

c) –4.66 x 4.7 d) 0.345 (32.4 – 4.67)

5 Dividing whole numbers, with decimals Continue the whole division adding zeros to the right of the number being

divided until you get the amount of decimal digits required.

Example:

Divide 235:6 until the hundredth

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5-4

235 6

55 39.16

10

40

4

Exercise 3 Calculate with two decimal digits

a) 56 : 7 b) 7634 : 34

c) – 679 : 32 d) 9783 : 127

6 Dividing decimals by decimals To divide by a decimal, multiply that decimal by a power of 10 great enough

to obtain a whole number. Multiply the dividend by that same power of 10.

Then the problem becomes one involving division by a whole number instead

of division by a decimal.

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Exercise 4 Calculate with three decimal digits

a) 56.7 : 2.34 b) 1432.3 : 0.42

c) – 12.34 : 3.5 d) 1 : 1.2

7 Rounding Decimal Numbers To round a number to any decimal place value, we want to find the number

with zeros in all of the lower places that is closest in value to the original

number. As with whole numbers, we look at the digit to the right of the place

we wish to round to.

Note: When the digit 5, 6, 7, 8, or 9 appears in the ones place, round up;

when the digit 0, 1, 2, 3, or 4 appears in the ones place, round down.

Exercise 5 Round:

1.17 to the nearest tenth

2.375 to the nearest hundredth

0.7084 to the nearest thousandth

12.87 to the nearest unit

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151.504 to the nearest hundred

7478 to the nearest thousand

8 Writing a fraction as a decimal

Method 1 - Convert to an equivalent fraction whose denominator is a power of 10, such as 10, 100, 1000, 10000, and so on, then write in decimal form.

Examples:

1/4 = (1 × 25)/(4 × 25) = 25/100 = 0.25

3/20 = (3 × 5)/(20 × 5) = 15/100 = 0.15

Method 2 - Divide the numerator by the denominator. Round to the decimal place asked for, if necessary.

Examples:

13/4 = 13 ÷ 4 = 3.25

Convert 3/7 to a decimal number. Round it to the nearest thousandth.

We divide one decimal place past the place we need to round to, then round the result.

3/7 = 3 ÷ 7 = 0.4285…

That equals 0.429 when rounded to the nearest thousandth.

Exercise 6 Convert to a decimal. Round it to the nearest hundredth.

a) 3

4 b)

6

13

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5-7

c) 7

11 d)

4

7

9 Repeating decimals

Every fraction can be written as a decimal.

For example, 1/3 is 1 divided by 3.

If you use a calculator to find 1 ÷ 3, the calculator returns 0.333333... This is

called a repeating decimal. To represent the idea that the 3's repeat forever, one uses an arc

== 3.0....33333.03

1

In Britain they use a horizontal bar 3.0....33333.03

1==

0 is the whole number portion

3333… is the decimal portion

3 is called the period or the recurring number, there is a period of one digit

Another example

== 18.1....181818.111

13 or 18.1....181818.1

11

13==

1 is the whole number portion

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5-8

1818… is the portion

18 is the period, this period has two digits

If there is no mark over the number it means that it has been an exact

division. These numbers are called regular numbers.

Example 2/5 = 0.4 is a regular number

There can be decimals numbers without repeating decimals

Examples: 1.01001000100001……

........14159.3=π

These are called irrational numbers and can not be written as fractions.

Exercise 7 Write as a decimal:

a) 6

17 b)

7

13

c) 11

131 d)

9

71

Exercises

1 Ellen earns ₤137.40 per week and after 4 weeks she gets an extra

payment of ₤24.75, she spends ₤354.60 in this period. How much has

she saved?

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5-9

2 A student has been studying a total time of 4 h 35 min and during this

time has been writing for 100 min. How long, in hours has he been

studying without writing?

3 Susan cooked a cake and used 1.35kg of flour, 0.37kg of sugar, 3

eggs that weigh 80g each and 240g of milk. Which is the weight of the

mixture?

4 I buy 7 mugs and pay 53.55 €. How much does each mug cost?

5 Henry had 83.40 €. He bought four tickets for the cinema at 6.50 each

and 2 bags of pop corn at 2.25 each. How much money has he got left?

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6 A breeder gives to each pig 0.65 kg of food for every 4 kg of body

weight. There are 4 pigs of 75.8 kg, 56.4 kg, 75.4 kg and 89.3 kg. How

much food must be prepared in total?

7 In a restaurant 7 friends are having a meal, the bill is £173.6 and each

person contributes £25.50. What tip does the waiter receive?

8 A company produces items that are sold for £13.63 each, the daily

production is 1275 items and the cost of production is £11,324.50. What

is the daily income for the company?

9 Three partners share a benefit of £18538, the first one receives a third

minus £173, the second one £5938.55. How much does the last one

receive?

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5-11

Solutions

Exercise 1 21.456 twenty one point four, five, six; 0.77 nought/zero point seven, seven; 0.0089 nought/zero point zero, zero, eight, nine; 5.7254 five point seven, two, five, four. Exercise 2 a) 38.64 , b) 949.7686, c) –21.902, d) 9.56685 Exercise 3 a) 8, b) 224.53, c) – 21.22, d) 77.03 Exercise 4 a) 24.231, b) 3410.238, c) – 3.526, d) 0.833 Exercise 5 1.2; 2.38; 0.708; 13; 200; 7000. Exercise 6 a) 1.33, b) 2.17, c) 1.57, d) 1.75.

Exercise 7 a) 38.2)

, b) 857142.1 , c) ∩

90.11 , d) 8.7)

Exercises 1 Ellen saves ₤219.75.

2 He has been studying without writing 6913.2)

h.

3 The weight of the mixture is 2.2 kg.

4 Each mug costs 7.65 €.

5 Henry has 52.90 € left.

6 He have to prepare 48.25 Kg of food.

7 The waiter receives a tip of £4.90.

8 The daily income for the company is £6053.75.

9 He receives 6593.12 £.

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6 Integers

1 The negative numbers.

There are many situations in which you need to use numbers below zero, one

of these is temperature, others are money that you can deposit (positive) or

withdraw (negative) in a bank, steps that you can take forwards (positive) or

backwards (negative).

Positive integers are all the whole numbers greater than zero: 1, 2, 3, 4,

5, ... . Negative integers are all the opposites of these whole numbers: -1, -2, -3,

-4, -5, ….

The Number Line The number line is a line labelled with the integers in increasing order from left to right, that extends in both directions:

For any two different places on the number line, the integer on the right is greater than the integer on the left.

Examples:

9 > 4 Is read: nine is ‘greater than’ four -7 < 9 Is read: minus seven is ‘less than’ nine.

Exercise 1

a) Read: 6 > -9 -2 > -8 0 > -5

b) Write down the temperatures shown on these thermometers. Find their

position in a number line.

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Exercise 2 What is the temperature which is:

a) 7 degrees lower than 5º C

b) 6 degrees lower than 4º C

c) 16 degrees higher than - 4º C

d) 9 degrees lower than - 6º C

Exercise 3 What is the difference in temperature between each pair of

thermometers?

Exercise 4 Write using integers.

a) Four degrees above zero b) A withdrawal of 20.000 €

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c) 250 meters below sea level d) Three degrees below zero e) A deposit of $200.00 f) An elevation of 8848 meters above sea level g) A gain of 19kg Exercise 5 Write the opposite of each integer given above.

2 Absolute Value of an Integer

The absolute value of any number is the distance between that number and zero on the number line.

.

If the number is positive, the absolute value is the same number. If the number is negative, the absolute value is the opposite.

The absolute value of a number is always a positive number (or zero). We specify the absolute value of a number n by writing n in between two vertical bars: |n|.

Examples: |6| = 6 |-10| = 10 |0| = 0 |123| = 123 |-3404| = 3404

3 Adding Integers There is a way to understand how to add integers. In order to add positive and negative integers, we will imagine that we are moving along a number line. If we want to add -1 and 5, we start by finding the number -1 on the number line, exactly one unit to the left of zero. Then we would move five units to the right. Since we landed four units to the right of zero, the answer must be 4.

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If asked to add 3 and -5, we can start by finding the number three on the number line (to the right of zero).

Then we move five units left from there because negative numbers make us move to the left side of the number line.

Since our last position is two units to the left of zero, the answer is -2.

Addition rules

When adding integers with the same sign

We add their absolute values, and give the result the same sign.

Examples: 2 + 5 = 7 (-7) + (-2) = -(7 + 2) = -9 (-80) + (-34) = -(80 + 34) = -114

With the opposite signs

We take their absolute values, subtract the smallest from the largest, and give the result the sign of the integer with the larger absolute value.

Example: 8 + (-3) = ? The absolute values of 8 and -3 are 8 and 3.

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Subtracting the smaller from the larger gives 8 - 3 = 5, and since the larger absolute value was 8, we give the result the same sign as 8, so 8 + (-3) = 5. Example: 8 + (-17) = ? The absolute values of 8 and -17 are 8 and 17. Subtracting the smaller from the larger gives 17 - 8 = 9, and since the larger absolute value was 17, we give the result the same sign as –17

So 8 + (-17) = -9.

Example: -22 + 11 = ? 1111

2222

=

=−

Subtracting the smaller from the larger gives 22 - 11 = 11, and since the larger absolute value was 22, we give the result the same sign as -22

So -22 + 11 = -11.

Example: 32 + (-32) = ?

=

=−

3232

3232

Subtracting the smaller from the larger, it gives 32 - 32 =0. The sign in this case does not matter, since 0 and -0 are the same. Note that 32 and -32 are opposite integers.

4 Subtracting Integers

To understand how to subtract integers, we will imagine that we are moving along a number line.

If we have to subtract 6 and 4, we start by finding the number six on the number line (6 units to the right of zero). Then we move four units to the left. Since we land two units to the right of zero, the answer is 2.

If we have to subtract 3 and 5, first find the number three on the number line, then move five units further left. Since we land two units left of zero, the answer is -2.

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If we have to subtract -4 and -6, we start at -4, four units to the left of zero, and

then we move six units to the right (because we subtract a negative

number!). Since we land two units to the right of zero, the answer is 2.

So, to add and subtract positives or negatives numbers using the number line,

you must move as is indicated below.

Subtraction rules

Subtracting an integer is the same as adding the opposite.

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We convert the subtracted integer to its opposite, and add the two integers. Examples: 7 - 4 = 7 + (-4) = 3 12 - (-5) = 12 + (5) = 17 -8 - 7 = -8 + (-7) = -15 -22 - (-40) = -22 + (40) = 18 The result of subtracting two integers could be positive or negative.

Exercises Exercise 6 Write and solve an addition for each of the following sentences.

a) The temperature rises 6 degrees, and then falls 3 degrees.

b) You deposit $50.5 into the bank and then withdraw $38.25

c) The temperature falls 10 degrees, and then falls 4 degrees.

d) You fall 45.3 metres down a mountain, and then climb up 23.5 metres,

but you fall again 15 metres.

Exercise 7 Add the following. a) 5+(-3)=

b) (-12)+(-8)= c) (-6)+12=

d) 15+(-19)=

e) (-5)+(-6)=

f) 22+(-43)=

g) (-5)+9=

h) 3+5=

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i) (-4)+(0)= Exercise 8 8.1 Add the following. a) 18+(-20)+6= b) (-13)+(-9)+(+5)= c) (-7)+(-5)+(-4)= d) (-17)+8+(-4)= e) (8)+(-30)+22= f) (-6)+5+(-6)= g) (-9)+7+(-4)+6= h) 7+(-13)+(-4)+(-5)=

8.2. Remove brackets that are not needed, rewrite the subtraction sentence and solve. a) (+6)-(+8) = b) (-4)-(-3) = c) (+6)-(+9) = d) (+3)-(-2) = e) (+4)+(-3)+(-6)-(+7)+(+6) = f) (-8)-(+5)+(+7)+(-8 ) = 8.3.Subtract. a) 6-8 = e) -3-6 = b) -7-3 = f) -12-8 = c) 4-(-3)= g) -7-(-9)= d) 8-(-8)= h) -6 - 4 =

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8.4. Subtract. a) 5-(-3)= e) -9-(-5)= b) 5-4= f) 9-(-4)= c) -8-4= g) -5-3= d) -3-6= h) -2-(-4)= 8.5. Subtract. a) –3 + (-4) –2 = b) – 6 - (-8) – 9 = c) –12 - (-4) + (-3) = d) –7 + (-3) + (-2) =

5 Multiplying Integers To multiply a pair of integers:

If both numbers have the same sign (positive or negative)

Their product is the product of their absolute values (their product is positive)

These examples help us to understand why a positive number is always the result of multiplying two numbers of the same sign.

Negative times negative: Make a pattern. Look at these sequences and complete them :

Example 1

-2 x 3 = -6

-2 x 2 = -4

-2 x 1 = -2

-2 x 0 = 0

-2 x -1 = 2

-2 x (-2) =

-2x(-3) =

-2x(-4) =

Example 2

-3 x 3 = -9

-3 x 2 = -6

-3 x 1 = -3

-3 x 0 = 0

-3 x (-1) =

-3 x (-2) =

-3 x(-3) =

-3 x(-4) =

Example 3

(-4) x 3 =

(-4) x 2 =

(-4) x 1 =

(-4) x 0 =

(-4) x (-1) =

(-4) x (-2) =

(-4) x (-3) =

(-4) x (-4) =

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If the numbers have opposite signs

their product is the opposite of the product of their absolute values (their product is negative). If one or both of the integers is 0, the product is 0.

Look at the following chart below.

PRODUCT + -

+ POSITIVE NEGATIVE

- NEGATIVE POSITIVE

Note: Multiplying integers of the same sign will give a positive number. Multiplying integers with opposite sign will give a negative number.

Examples: 4× 3 = 12 Both numbers are positive, so we just take their product. (-4) × (-5) = |-4| × |-5| = 4 × 5 = 20 Both numbers are negative, so we take the product of their absolute values. In the product of (-7) × 6, the first number is negative and the second is positive, so we take the product of their absolute values, which is |-7| × |6| = 7 × 6 = 42, and give this result a negative sign: -42 So (-7) × 6 = -42 In the product of 12 × (-2), the first number is positive and the second is negative, so we take the product of their absolute values, which is |12| × |-2| = 12 × 2 = 24, and give this result a negative sign: -24

So 12 × (-2) = -24.

To multiply any number of integers:

1. Count the number of negative numbers in the product. 2. Take the product of their absolute values. If the number of negative integers counted in step 1 is even, the product

is just the product from step 2 (positive).

If the number of negative integers is odd, the product is the opposite of the product in step 2 (give the product in step 2 a negative sign).

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If any of the integers in the product is 0, the product is 0.

Example: 4 × (-2) × 3 × (-11) × (-5) = ? Counting the number of negative integers in the product, we see that there are 3 negative integers: -2, -11, and -5. Next, we take the product of the absolute values of each number: 4 × |-2| × 3 × |-11| × |-5| = 1320. Since there were an odd number of integers, the product is the opposite of 1320, which is –1320

So 4 × (-2) × 3 × (-11) × (-5) = -1320. Example: -5 × (-2) × (-3) × (-1) × (4) = ? Counting the number of negative integers in the product, we see that there are 4 negative integers

Next, we take the product of the absolute values of each number: 5 × 2 × 3 × 1 × 4 = 120. Since there is an even number of integers, the product is 120. Exercise 9 Multiply the following. a) 5x(-13) = b) (-12)x(-8) = c) (-16)x12 = d) 15x(-19) =

e) (-5)x(-6) = f) 12x(-3) =

g) (-15)x6 = h) 3x35 =

i) (-4)x(0)= k) -3x(-5) = Exercise 10 10.1 Multiply . a) 7x(-12)x6= b) (-13)x(-9)x(+5)= c) (-3)x(-7)x(-14)= d) (-6)x8x(-4)= e) (9)x(-30)x2=

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f) (-13)x5x(-6)= g) (-9)x17x(-4)x26= h) 4x(-81)x(-4)x(-2)=

10.2. Multiply a) (+6) ⋅ (+18) =

b) (-12) ⋅ (-3) =

c) (+6) ⋅ (+7) =

d) (+7) ⋅ (-6) =

e) (+3) ⋅ (-3) ⋅(-2) ⋅ (+6) ⋅ (+3) =

f) (-6) ⋅ (+9) ⋅ (+3) ⋅ (-1 ) =

10.3. Operate a) –3 ⋅[ (-4) –2 ] =

b) – 6 ⋅ [- (-8) – 9] =_

c) [–12 - (-4)] ⋅(-3) =

d) (–7 + (-3)) ⋅(-2) =

6 Dividing Integers To divide a pair of integers the rules are the same as the rules for the product:

If both numbers have the same sign (positive or negative)

Divide the absolute values of the first integer by the absolute value of the second integer (the result is positive)

If the numbers have opposite signs

Divide the absolute value of the first integer by the absolute value of the second integer, and give this result a negative sign.

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The chart is.

DIVISION + -

+ POSITIVE NEGATIVE

- NEGATIVE POSITIVE

Note: Dividing integers of the same sign will give a positive number. Dividing integers with opposite sign will give a negative number.

Examples: 14 ÷ 2 = 7 Both numbers are positive, so we just divide as usual. (-24) ÷ (-3) = |-24| ÷ |-3| = 24 ÷ 3 = 8. Both numbers are negative, so we divide the absolute value of the first by the absolute value of the second. (-100) ÷ 25 The numbers have different signs, so we divide the absolute value of the first number by the absolute value of the second. |-100| ÷ |25| = 100 ÷ 25 = 4, and give this result a negative sign: -4

So (-100) ÷ 25 = -4 98 ÷ (-7) Both numbers have different signs, so we divide the absolute value of the first number by the absolute value of the second. |98| ÷ |-7| = 98 ÷ 7 = 14, and give this result a negative sign: -14.

So 98 ÷ (-7) = -14. Exercise 11 Divide the following. a) 15:(-3)=

b) (-12):(-4)= c) (-16):2=

d) 150:(-6)=

e) (-225):(-15)=

f) 12:(-3)=

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g) (-156):6=

h) 35:(-35)=

i) (-4):(0)= Exercise 12 12.1 Divide . a) 12:(6:(-2))= b) (-30):[(-15):(+5)]= c) (-8):[(-14):(-7)]= d) [(-6)x8]:(-4)= e) [(9)x(-30)]:2= 12.2. Divide a) (+76):(+18) = b) (-12):(-3) = c) (+42):(+7) = d) (+72):(-6) = 12.3. Operate a) –30: [ (-4) –2 ] = b) – 34 :[ (-8) – 9] = c) [–12 - (-3)]:(-3) = d) (–7 + (-3)):(-2) =

Order of operations

• Do of all the operations in brackets first.

• Then do multiplication and division in the order they appear, then do addition and subtraction in the order they occur Easy way to remember them

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• Brackets

• Exponents

• Division

• Multiplication

• Addition

• Subtraction

• This gives you BEDMAS. Do one operation at a time. Example [10+(-16)+(-24)]/3 = [-6+(-24)]/3 = -30/3= -10

13. Operate a) (+3):(-3)+(-12):(+6)+ (+3) = b) 62/[-10+(-4)-4] = c) =−+−−−⋅− )3(:156:)24()4()3(

d) =+−⋅−−− 4)3()7()2(:10

e) ( ) ( )( )[ ] =−−+−−+ )7/(3525/31

f) [ ] =−−+−⋅−+− )9(:)72()2()3(74

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EXTRA EXERCISES 1 Mount Everest is 29,028 feet above sea level. The Dead Sea is 1,312 feet below sea level. What is the difference of altitude between these two points? 2 The temperature in Chicago was 4º C at two in the afternoon. If the temperature dropped 12º C at midnight, what is the temperature now? 3 A submarine was situated 2100 feet below sea level. If it ascends 1230 feet, what is its new position? 4 Aristotle was born in 384 B.C. and died in 322 BC. How old was he when he died? 5 A submarine was situated 1230 feet below sea level. If it descends 125 feet, what is its new position? 6 This is the three-day forecast for Yellowknife (Canada) from the 24th of November 2008

Today Nov 24

Tue Nov 25

Wed Nov 26

Snow

Cloudy

Snow

-6° -7°

-6°

-13° -8° -14°

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What is the difference between the maximum and the minimum temperatures each day?

What are the maximum and the minimum temperatures during these three days? 7 This is the three-day forecast for Birmingham, UK from the 24th of November 2008

Today Nov 24

Tue Nov 25

Wed Nov 26

Rain

Sunny

Partly Cloudy

13° 14° 14° 2° -2° 1°

What is the difference between the maximum and the minimum temperatures each day? 8 The Punic Wars began in 264 B.C. and ended in 146 B.C. How long did the Punic Wars last? 9 This is a table with the melting points of some metals Metal

Melting point º C

Boiling point º C

Aluminium

660.32

2519

Iron

1538

2861

Gold

1064.18

2856

Mercury

-38.83

656.73

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a) Calculate the difference between the melting and the boiling point

of each metal

b) How much warmer is the melting point of mercury than the melting point of iron?

10 On the 2nd of January, the temperature dropped from 3ºC at two o’clock in the afternoon to -11ºC at 8 a. m. the next day. How many degrees did the temperature fall? 11 A Greek treasure was buried in the year 164 BC and found in 1843 AD. How long was the treasure hidden? 12 On the 1st of December, the level of the water in a reservoir was 130 cm above its average level. On the 1st of July it was 110 cm below its average level. How many cm did the water level drop in this time?

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Solutions Exercise 1

a) Six is greater than minus nine, minus two is greater than minus eight, zero is

greater than minus five.

b) a) 13º C, b) 24º C, c) 21º C, d) -11º C, e) -13 º C, f) -10º C, g) 45º C, h) 1º C.

Exercise 2 a) -2ºC; b) -2ºC; c) 14º C; d) - 15º C

Exercise 3 (Right thermometer temperature minus left thermometer

temperature) a) 22º; b) -28º; c) 6º; d) -58º.

Exercise 4 a) 4; b) -20.000; c) -250; d) -3; e) 200; f) 8848; g) 19.

Exercise 5 a) -4; b) 20.000; c) 250; d) 3; e) -200; f) -8848; g) -19.

Exercises Exercise 6 a) 336 =−+ , b) 25.1225.385.50 =− , c) 14410 −=−− , d)

8.36155.233.45 −=−+− . Exercise 7 a) 2, b) -20, c) +6, d) -4, e) -11, f) -21, g) 4, h) 8, i) -4. Exercise 8 8.1 a) 4, b) -17, c) -16, d) -13, e) 0, f) -7, g) 0, h) -15, 8.2. a) 286 −=−+ , b) 134 −=+− , c) 396 −=− , d) 523 =+ , e) 667634 −=+−−− , f) 148758 −=−+−− 8.3. a) -2, b) -10, c) 7, d) 16, e) -9, f) -20, g) 2, h) -10. 8.4. a) 8, b) 1, c) -12, d) -9, e) -4, f) 13, g) -8, h) 2. 8.5. a) – 9, b) – 7, c) –11, d) – 12. Exercise 9 a) -65, b) 96, c) -192, d) -285, e) 30, f) -36, g) -90, h) 105, i) 0, k) 15. Exercise 10 10.1 a) – 504, b) 585, c) – 294, d) 192, e) – 540, f) 390, g) 15912, h) – 2592, 10.2. a) 108, b) 36, c) 42, d) – 42, e) 324, f) 162. 10.3. a) 18, b) 6, c) 24, d) 20. Exercise 11 a) – 5, b) 3, c) – 8, d) – 25, e) 15, f) – 4, g) – 26, h) – 1, i) It is a forbidden calculation. Exercise 12 12.1 a) – 4, b) 10, c) – 4, d) 12, e) – 135, 12.2. a) 4.2, It is not a integer, b) 4, c) 6, d) – 12. 12.3. a) 5, b) 2, c) 3, d) 5. 13. a) 0, b) – 3.4, It is not a integer, c) 11, d) – 22, e) 7, f) – 1.

EXTRA EXERCISES 1 30340; 2 – 8 ºC; 3 870 feet below sea level; 4 62 years old; 5 1355 feet below sea level; 6 Nov 24: 7º, nov 25: 1º, nov 26: 8º ; maximum -6º, minimum -14º 7 Nov 24: 11º, nov 25: 16º, nov 26: 13º; 8 118 years; 9 a) Boiling point minus melting point: Aluminium 1858.68º, iron 1323º, gold 1791.82º mercury 695.56; b) – 1576.83 ( It is negative because the melting point of mercury is cooler than the melting point of iron); 10 14 ºC; 11 2007 years; 12 240 cm.

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7 Measurements

1 Measurement

Different units of measurement have been used in the past, some of them are

still in use in UK and USA, but in most places is used the Metric System of

Measurements.

The metric units are:

Length metre (In U.S.A. “meter”) Area square metre Volume cubic metre Capacity litre Mass or weight gram

It is very useful to be able to estimate lengths, masses, etc. because it may

not always be easy to measure them. Some useful hints for estimating are

listed below:

The height of a standard door is about 2 m.

The length of an adult pace is about 1 m.

The length of a size 8 (41 in Spain) shoe is about 30 cm.

Most adults are between 1.5 m and 1.8 m in height.

It takes about 15 minutes to walk one kilometre.

The mass of a standard bag of sugar is 1 kg.

The mass of a family car is about 1 tonne.

2 hectares = 20 000 m2 (about 3 football pitches).

A teaspoon holds about 5 ml of liquid.

The volume of a normal can of drink is about 330 cm3.

In England some imperial units are in common use today. People may for

example give their height in feet and inches; give a distance in miles, their

weight in stones or a capacity in gallons. We will see the relationships

between the units of the Imperial and the Metric systems of measurement.

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2 Metric Prefix Table The metric (decimal) system uses a number of standard prefixes for units of

length, mass, etc.

To change any of the other units of measurement into their equivalent

values in the main unit we have to use the conversion factor given by the

value of the prefix.

Remember:

Number Prefix Symbol

10 deca da

100 hecto h

1000 kilo k

1,000,000 mega M

10 9 giga G

10 12

tera T

Number Prefix Symbol

0.1 deci d

0.01 centi c

0.001 mili m

0.000001 micro

0.000000001 nano n

0.000000000001 pico p

3. Length The main unit of length is the metre; it is very useful to be able to convert

between different units. This is the conversion table:

Kilometre Hectometre Decametre Metre Decimetre Centimetre Millimetre

Kilometre km 1 10 100 1000 10000 100000 1000000

Hectometre hm 0.1 1 10 100 1000 10000 100000

Decametre dam 0.01 0.1 1 10 100 1000 10000

Metre m 0.001 0.01 0.1 1 10 100 1000

Decimetre dm 0.0001 0.001 0.01 0.1 1 10 100

Centimetre cm 0.00001 0.0001 0.001 0.01 0.1 1 10

Millimetre mm 0.000001 0.00001 0.0001 0.001 0.01 0.1 1

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Exercise 1 Measure the width of this page and write it in the seven

different units of the table.

Exercise 2 Write all the following in centimetres.

a) 4 cm 2 mm

b) 18 cm 9 mm

c) 75 mm

d) 4 dm 3 cm 45 mm

e) 7.8 m 43 dm

f) 55.3 m

g) 0.3 dam 5 cm 64 mm

h) 0.05 hm 5 m 36 cm

i) 4.6 km 0.3 dam 0.5 m 78 mm

Exercise 3 Write all the following in millimetres.

a) 0.4 cm 12 mm

b) 1.78 cm 15 mm

c) 17.5 m

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d) 35 dm 13 cm 67 mm

e) 17.4 m 45 dm

f) 75.8 m

g) 0.7 dam 5 m 64 mm

h) 1.05 hm 15 m 36 cm

i) 0.06 km 0.3 dam 1.6 m 38 dm

Exercise 4 Write all the following in metres.

a) 10.4 cm 140 mm

b) 198 cm 150 mm

c) 17.5 km

d) 37 hm 13 m 1067 mm

e) 32.6 dam 470 dm

f) 1275.8 mm

g) 0.29 dam 5 m 765 mm

h) 1.32 hm 150 m 3600 cm

i) 0.005 km 0.12 dam 1.6 m 38 cm

Exercise 5 Write all the following in kilometres.

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a) 10700 cm 140000 mm

b) 158 m 120000 mm

c) 17.5 hm

d) 346 hm 14m 10400 mm

e) 320.9 dam 47000 dm

f) 1275.8 dam

g) 8.78 dam 500 m 775000 mm

h) 43.32 hm 150000 m

i) 0.005 km 14 dam 160 m 38000 cm

Exercise 6 Round each of the following measurements to the nearest

centimetre.

a) 3.84 cm

b) 158 m 1.2 mm

c) 415.5 mm

d) 134 m 19 mm

e) 342 dam 0.47 dm

f) 1273.8 mm

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Exercise 7 Round each of the following measurements to the nearest

metre.

a) 13.84 dm

b) 333 m 12 dm

c) 2473.5 mm

d) 543 m 900 mm

e) 78.9 dam 47.47 dm

f) 7654.8 mm

4. Capacity The main unit of capacity is the litre; this is the conversion table:

Kilolitre Hectolitre Decalitre Litre Decilitre Centilitre Millilitre

Kilolitre kl 1 10 100 1000 10000 100000 1000000

Hectolitre hl 0.1 1 10 100 1000 10000 100000

Decalitre dal 0.01 0.1 1 10 100 1000 10000

Litre l 0.001 0.01 0.1 1 10 100 1000

Decilitre dl 0.0001 0.001 0.01 0.1 1 10 100

Centilitre cl 0.00001 0.0001 0.001 0.01 0.1 1 10

Millilitre ml 0.000001 0.00001 0.0001 0.001 0.01 0.1 1

Exercise 8 Write all the following in centilitres.

a) 14 cl 32 ml

b) 4 dl 3 cl 45 ml

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c) 0.38 dal 5 cl 68 ml

Write all the following in litres.

a) 90.5 hl 5 l 36 cl

b) 15.6 kl 0.03 dal 3.6 l 668 ml

c) 4.2 kl 0.53 dal 0.5 l 780 ml

Write all the following in kilolitres.

a) 43107cl 670140000 ml

b) 73.39 hl 17000 l

Exercise 9 Round each of the following measurements to the nearest

litre.

a) 16.84 dl

b) 543 l 640 ml

c) 127 l 98 dl

d) 2283.5 ml

5. Weight

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The unit of weight is the gram, this is the conversion table:

Kilogram Hectogram Decagram Gram Decigram Centigram Milligram

Kilogram kg 1 10 100 1000 10000 100000 1000000

Hectogram hg 0.1 1 10 100 1000 10000 100000

Decagram dag 0.01 0.1 1 10 100 1000 10000

Gram g 0.001 0.01 0.1 1 10 100 1000

Decigram dg 0.0001 0.001 0.01 0.1 1 10 100

Centigram cg 0.00001 0.0001 0.001 0.01 0.1 1 10

Milligram mg 0.000001 0.00001 0.0001 0.001 0.01 0.1 1

1 tonne = 1000 kg

Exercise 10 Find your own weight in all the units.

Exercise 11 (You must be groups of four). Calculate the average weight

of the group.

Round the result to the nearest

a) kg

b) hg

c) dag

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Exercise 12 The average weight of a group of ten boys is 72 kilograms

890 grams. When one boy leaves the group the average of the nine

becomes 72.5 kg.

Find the weight of the boy who left the group.

Exercise 13 A bridge has been designed to support 550 tonnes. If the

average weight of a vehicle is 1 tonne 850 kg, is it safe to have 300

vehicles on the bridge at one time?

6. Area The S I unit of area is the square metre. To change any of these other units of area into their equivalent values in square metres use the operation given.

square Kilometre Hectometre Decametre Metre Decimetre Centimetre Millimetre

Kilometre km2 X 1 X 10

2 X 10

4 X 10

6 X 10

8 X 10

10 X 10

12

Hectometre hm2 : 10

2 1 X 10

2 X 10

4 X 10

6 X 10

8 X 10

10

Decametre dam2 : 10

4

: 102

1 X 102 X 10

4 X 10

6 X 10

8

Metre m2 : 10

6 : 10

4 : 10

2 1 X 10

2 X 10

4 X 10

6

Decimetre dm2 : 10

8 : 10

6 : 10

4 : 10

2 1 X 10

2 X 10

4

Centimetre cm2 : 10

10 : 10

8 : 10

6 : 10

4 : 10

2 1 X 10

2

Millimetre mm2 : 10

12 : 10

10 : 10

8 : 10

6 : 10

4

: 102

1

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Land measurements units: Are = dam2, Hectare = hm2

Exercise 14 Write all the following in m2.

a) 3 km2 5 hm2 54 dm2

b) 7,890 ha 23 a

c) 30,000 dm2

Write all the following in ares and in hectares.

d) 90.5 km2 5 hm2 36 dam2

e) 1.6 dam2 0.03 km2 34500 dm2

f) 5,000,000 cm2

7. Volume

The distinction between 'Volume' and 'Capacity' is artificial and kept here only

for historic reasons. A cubic metre is 1000 litres, a cubic decimetre is a

litre, and a cubic centimetre is a millilitre. This is the conversion table:

cubic Kilometre Hectometre Decametre Metre Decimetre Centimetre Millimetre

Kilometre km3 X 1 X 10

3 X 10

6 X 10

9 X 10

12 X 10

15 X 10

18

Hectometre hm3 : 10

3 1 X 10

3 X 10

6 X 10

9 X 10

12 X 10

15

Decametre dam3 : 10

6 : 10

3 1 X 10

3 X 10

6 X 10

9 X 10

12

Metre m3 : 10

9 : 10

6 : 10

3 1 X 10

3 X 10

6 X 10

9

Decimetre dm3 : 10

12 : 10

9 : 10

6 : 10

3 1 X 10

3 X 10

6

Centimetre cm3 : 10

15 : 10

12 : 10

9 : 10

6 : 10

3 1 X 10

3

Millimetre mm3 : 10

18 : 10

15 : 10

12 : 10

9 : 10

6 : 10

3 1

Exercise 15 Write all the following in m3.

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a) 0.0003 km3 0.05 hm3 5400 dm3

b) 7,320 dm3 5000 cm3

c) 210,000 dm3

Write all the following in cm3 and dm3

d) 0.0123 m3 40 dm3 45800 mm3

e) 0.0000045 dam3 0.323 m3 0.234 dm3

f) 5,000,000 mm3

Exercise 16 Write all the following in litres and in centilitres.

a) 0.0000125 hm3 5.4 dm3

b) 0.000043 hm3 50000 cm3

c) 210,000 millilitres

Write all the following in cm3 and dm3

d) 10.7 kl 40 hl 44,300 l

e) 6.7 kl 234 cl

f) 5,000,000 ml

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8. Imperial Units of Length, Capacity and Mass The imperial system was used, until very recently, for all weights and measures throughout the UK. There are many aspects of everyday life where the system is still in common usage. Miles instead of kilometres are used. The units of length are:

The relationships are:

from \ to miles yards feet inches

mile 1 1760 5280 63360

yard (1/1760) 1 3 36

foot (1/5280) (1/3) 1 12

inch (1/63360) (1/36) (1/12) 1

The following list gives some help to you.

- The height of a tall adult is about 6 feet. - The width of an adult thumb is about 1 inch. - The length of a size 41, 8 in England, shoe is about 1 foot. - An adult pace is about 1 yard.

You will find the following abbreviations used for imperial units:

1 yard = 1 yd 6 feet = 6ft = 6' 9 inches = 9 in = 9 " 8 ounces = 8 oz 7 pounds = 7 lb

Do not to use m as an abbreviation for miles because m is a standard abbreviation for metres.

For areas, apart from the correspondent to the length units, it is also used the acre.

1 mile = 1609.344 metres 1 yard = 0.9144 metres 1 foot = 0.3048 metres 1 inch = 0.0254 metres

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1 acre 43560 feet2 6272640 inches2

4046.8… meters2 (1/640) miles2

4840 yards2

In U.S.A. the conversion table (not all exact) for units of volume and capacity are:

from \ to feet3 gallons inches3 litres pints quarts yards3

foot3 7.48 1728 28.3 59.8 29.9 (1/27)

gallon 0.13 231 3.78 8 4 0.0049

inch3 (1/1728) (1/231) 0.016 (1/29) (1/57.75) (1/47)

pint 0.0167 (1/8) 28.87 0.47 (1/2) 0.0006

quart 0.033 (1/4) 57.75 1.057 2 0.00123

yard3 27 0.0049 46656 764 1615.79 807.896

Remember that all these relationships are not exact. But a gallon in U.K. are 4.546 litres, so for units of volume and capacity we have:

Common for U.S.A. and U.K.

1 gallon = 4 quarts = 8 pints

Only for USA

1 gallon = 3.78 litres 1 pint = 0.47 litres

Only for UK

1 gallon = 4.546 litres 1 pint = 0.57 litres

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Some of the units of mass are:

(Be careful 1 tonne is 1000 kg) The following list gives some help to you.

- The mass of a bag of sugar is just over 2 pounds. - The weight of an adult is between 10 and 16 stones - Chocolate is sold in Spain in pounds and ounces. The conversion table (not all exact) for units of weight is:

from \ to stone pound ounce kg

stone 1 14 224 6.35

pound 1/14 1 16 0.45

Ounce 1/224 1/14 1 0.028

Kg 0.16 2.2 35.3 1

Exercise 17 a) Estimate the length of the following line, in inches: b) The picture shows a man standing with a gate in it: Estimate the height in feet of both the gate and the wall.

1 ton (UK) = 1016 kg

1 ton (USA) = 907 kg

1 stone = 6.35 kg

1 pound = 0.453 kg

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c) Estimate the size of the top of your desk, in inches. d) Estimate the heights of 4 of your friends, in feet and inches. e) Estimate the length and width of your classroom, in feet. f) Estimate the total mass of 3 text books, in pounds. g) Estimate the mass of an apple, in ounces. (Remember that there are 16 ounces in 1 lb.) h) Estimate the capacity of a mug, in pints. i) Estimate your own weight in stones and pounds.

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Exercise 18 While on holiday in France, a family sees the following road-sign:

PARIS 342 km

How many miles is the family from Paris? Exercise 19 While on holiday in England you see the following road-sign:

How many km/h is the speed limit? Exercise 20 A bottle contains 2.5 litres of milk. How many pints of milk does the bottle contain?

Exercise 21 Vera buys 27 litres of petrol for her car. How many gallons of petrol does she buy? if she buys 4 gallons of petrol. How many litres does she buy?

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Exercise 22 Change the following lengths into appropriate units of the

metric system ( cm, m or km).

4 feet 8 feet 7 inches 5 yards 2 feet 7 feet 5.5 feet 1 mile 4 feet 2 inches 2 yards 17 inches 95 inches Change the following lengths into metres: 60 inches 29 inches 48 inches 240 inches Exercise 23 Change the following masses into kg:

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a) 7 pounds b) 11 pounds c) 36 pounds d) 904 pounds e) 2 stones f) 9 stones 12 pounds g) 5.5 pounds Change the following masses into pounds or pounds and ounces: a) 3.5kg b) 500 g c) 720 ounces d) 750 g e) 40 ounces f) 125 g Exercise 24 Change the following volumes into litres: a) 5 gallons b) 11 gallons c) 63 gallons

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d) 412 gallons Exercise 25 Change the following volumes into gallons and litres: a) 56 pints b) 528 pints c) 2 pints d) 160 pints e) 12 pints Into gallons f) 25 l g) 120 l h) 5.5 l Exercise 26 A recipe requires 2 lb of flour. Give the equivalent amount of flour in: a) Grams b) Kilograms c) Ounces Exercise 27 The capacity of a fuel tank is 30 gallons. What is the capacity of the tank in: a) Litres b) Pints Exercise 28 A cow produces an average of 18 pints of milk each time she is milked. Convert this to litres, giving your answer to 1 decimal place.

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9. Temperature

There are two main temperature scales, each one being named after the person who invented it. G D FAHRENHEIT (1686-1736) a German physicist, in about 1714 proposed the first practical scale. He called the freezing-point of water 32 degrees (so as to avoid negative temperatures) and the boiling-point 212 degrees. Anders CELSIUS (1701-1744) a Swedish astronomer, proposed the 100-degree scale (from 0 to 100) in 1742. This was widely adopted as the centigrade scale. But since grades and centigrade were also measures of angle, in 1947 it officially became the Celsius scale. Nowadays, the CELSIUS scale is the preferred scale in our everyday lives. However, the Fahrenheit scale is still widely used in U.S.A. and there frequently is a need to be able to change from one to the other.

To change temperature given in Fahrenheit (F) to Celsius (C)

1. Start with (F) 2. Subtract 32 3. Multiply by 5 and divide by 9 4. The answer is (C)

To change temperature given in Celsius (C) to Fahrenheit (F)

1. Start with (C) 2. Multiply by 9 and divide by 5 3. Add on 32 4. The answer is (F)

Example 1: To convert 45º F to ºC

1. 45ºF 2. 45 – 32 = 13 3. (13x5)/9 = 7.2 4. 7.2º C

Example 2: To convert 25º C to ºF 1. 25º C 2. 25x9:5=45

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3. 45+32 =77 4. 77º F

Exercise 29 Change the following temperatures into º C scale:

a) 72º F b) 100º F c) 93º F d) 5º F

e) – 52º F

f) Write the temperature of the human body in ºF

g) Write a list of 6 temperatures in ºC and ºF including the ones that

you consider more interesting.

Exercise 30 Change the following temperatures into º F scale:

a) 37º C

b) 100º C

c) 18º C

d) – 5º C

e) – 22º C

Compare your answers in this scale that is only an approximation.

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Solutions

Exercise 1 21 cm, 210 mm, 2.1 dm, 0.21 m, 0.021 dam, 0.0021 hm,

0.00021km.

Exercise 2 a) 4.2 cm, b) 18.9 cm, c) 7.5 cm, d) 47.5 cm e) 1210 cm, f) 5530

cm, g) 311.4 cm, h) 1036 cm, i) 460357.8 cm.

Exercise 3 a) 16 mm, b) 32.8 mm, c) 17,500 mm, d) 3697 mm, e) 21,900

mm, f) 75,800 mm, g) 12,064 mm, h) 120,360 mm, i) 64,980 mm.

Exercise 4 a) 0.244 m, b) 2.13 m, c) 17,500 m, d) 3714.067 m, e) 373 m, f)

1.2758 m, g) 8.665 m, h) 318 m, i) 8.18 m.

Exercise 5 a) 0.247 km, b) 0.278 km, c) 1.75 km, d) 34.6244 km, e) 7.909

km, f) 12.758 km, g) 1.3628 km, h) 154.332 km, i) 0.685 km.

Exercise 6 a) 4 cm, b) 15800 cm, c) 42 cm, d) 13402 cm, e) 342005 cm, f)

127 cm.

Exercise 7 a) 1 m, b) 334 m, c) 2 m, d) 544 m, e) 794 m, f) 8 m.

Exercise 8 a) 17.2 cl, b) 47.5 cl, c) 386.8 cl. a) 9055.36 l, b) 15604.568 l, c)

426.58 l. a) 670.57107 kl, b) 24.339 kl.

Exercise 9 a) 2 l, b) 544 l, c) 137 l, d) 2 l.

Exercise 10 Different for each case.

Exercise 11 Different for each case.

Exercise 12 76.4 kg.

Exercise 13 No, the total weight is 555 tonnes.

Exercise 14 a) 3,055,400 m2, b) 78,902,300 m2, c) 300 m2, d) 905,536 a,

9055.36 ha; e) 305.05 a, 3.0505 ha; f) 5 a, 0.05 ha.

Exercise 15 a) 30505.4 m3 , b) 7.325 m3 , c) 210 m3 . d) 52.3458 dm3 ,

52345.8 cm3 , e) 327.734 dm3 , 327734 cm3 , f) 5 dm3 5000 cm3.

Exercise 16 a) 12,505.4 l, 1,250,540 cl, b) 43,050 l, 4,305,000 cl, c) 210 l,

21,000 cl, d) 59,000,000 cm3, 59,000 dm3, e) 6,702,340 cm3, 6,702.34 dm3, f)

5,000,000 cm3, 5,000 dm3.

Exercise 17 a) 4 inches, b), c), d), e) and f) differents solutions, g) 8 ounces,

h) half a pint, i) differents solutions.

Exercise 18 201.3 miles.

Exercise 19 64.4 km/h.

Exercise 20 4.39 pints.

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Exercise 21 5.94 galons, 18.18 litres. Exercise 22 4 feet = 1.22 m, 8 feet 7 inches = 2.62 m, 5 yards 2 feet = 5.49 m, 7 feet = 2.13 m, 5.5 feet = 1.68 m, 1 mile = 1.609 km, 4 feet 2 inches = 15.24 m, 2 yards = 1.83 m, 17 inches = 43.2 cm, 95 inches = 2.41 m, 60“ = 1.524 m, 29“ = 0.737 m, 48“ = 1.219 m, 240“ = 6.1 m. Exercise 23 a) 3.15 kg, b) 4.95 kg, c) 16.2 kg, d) 406.8 kg, e) 12.7 kg, f) 62.55 kg, g) 2.475 kg. a) 7 lb 3.5 ounces, b) 1lb 1.6 ounces, c) 45 lb, d) 1 lb 10.4 ounces, e) 2 lb 8 ounces, f) 4.4 ounces. Exercise 24 a) 22.73 l, b) 50 l, c) 286.4 l, d) 1872.95 l. Exercise 25 a) 7 gallons, 31.8 l, b) 66 gallons, 300 l, c) .25 gallons, 1.14 l, d) 20 gallons, 90.92 l, e) 1.5 gallons, 6.8 l, Into gallons, f) 5.5 gallons, g) 26.4 gallons, h) 1.21 gallons. Exercise 26 a) 900 grams, b) 0.9 kilograms, c) 32 ounces. Exercise 27 a) 136.38 l, b) 240 pints. Exercise 28 10.3 l Exercise 29 a) 22.2º C, b) 37.8º C, c) 33.9º C, d) – 15º C, e) – 46.7º C, f) 97.7º F. Exercise 30 a) 98.6º F, b) 212º F, c) 64.4º F, d) 23º F, e) -7.6º F.

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8 Ratio and percentages

1 Ratio

A ratio is a comparison of two numbers. We generally separate the two numbers in the ratio with a colon (:) or as a fraction.

Suppose we want to write the ratio of 8 and 12. We can write this as 8:12 or as 8/12, and we say the ratio is eight to twelve. Examples: Janet has a bag with 4 pens, 3 sweets, 7 books, and 2 sandwiches. 1. What is the ratio of books to pens? Expressed as a fraction, the answer would be 7/4. Two other ways of writing the ratio are 7 to 4, and 7:4. 2. What is the ratio of sweets to the total number of items in the bag? There are 3 candies, and 4 + 3 + 7 + 2 = 16 items total. The answer can be expressed as 3/16, 3 to 16, or 3:16.

2 Comparing Ratios

To compare ratios, write them as fractions. The ratios are equal if they are equal when written as fractions.

We can find ratios equivalent to other ratios by multiplying/ dividing both sides by the same number. Example: Are the ratios 2 to 7 and 4:14 equal? The ratios are equal because 2/7 = 4/14. The process of finding the simplest form of a ratio is the same as the process of finding the simplest form of a fraction. 1 : 3.5 or 2 : 7 could be given as more simple forms of the ratio 4 : 14.

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Exercise 1 Simplify the following ratios: 3:6 25:50 40:100 9:21 11:121

For some purposes the best is to reduce the numbers to the form 1 : n or n : 1 by dividing both numbers by either the left hand side or the right-hand side number. It is useful to be able to find both forms, as any of them can be used as the unit in a problem.

Examples:

Which will be the divisor if we are to reach the form 1 : n for the ratio 4 : 5 ? The divisor will be 4 and the ratio will be 1 : 1.25

And if we are to reach the form n : 1 for the same ratio? The divisor will be 5, and the ratio will be 0.8 : 1 Exercise 2 Reduce to the form 1:n and n:1 10 shovels of cement, 25 shovels of sand Exercise 3 Reduce to the form 1:n the following: 4:9 7:5 30:100 5:12 Exercise 4 Reduce to the form n:1 the following: 14:9 15:5

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40:100 75:12

3. Direct Proportionality

We say that there is a direct proportionality between two magnitudes if when we double one magnitude, the other also doubles, when we half the first, the second also halves.

Examples: If a can of cola costs 40p, the cost of: 2 cans is 80p 5 cans is £2.00 We can see that, for example, if we double the number of cans, we double the price. We say that the total cost of the cans increases proportionally with their number. A proportion is one equality with a ratio on each side. It is a statement that two ratios are equal. 3/4 = 6/8 is an example of a proportion. Note that proportions, ratios and equalities with fractions are different forms of expressing the same idea. When one of the four numbers in a proportion is unknown, cross products may be used to find the unknown number. This is called solving the proportion. Letters are frequently used in place of the unknown number. Example: Solve for n: 1/2 = n/4. Using cross products we see that 2 × n = 1 × 4 =4, so 2 × n = 4. Dividing both sides by 2, n = 4 ÷ 2 so n = 2. Exercise 5 Find the unknown side in each ratio or proportion:

1:7 = 5:x

1/9 = 5/x

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1:5 = 3:x

2/7 = x/21

3:4 = 7:x

5/8 = 8/x

1/4=3/x

2 : 3 = 5 : x 12 : 21 = 16 : x

Exercise 6 Think of examples of proportionality in real life

Exercise 7 7.1 If 3 litres of petrol cost 3.45 €. How much will cost

a) 5 litres b) 23.5 litres

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7.2 If we travel 136 km in 1.5 hours driving at a constant speed.

a) How many km will we travel in 7.4 h? b) How many hours do we need to travel 200 km?

7.3 Adrian finds that in each delivery of 500 bricks there are 20 broken bricks. How many bricks are broken in a delivery of 7500?

7.4 In a drink 53 ml of fruit juice are mixed with 250 ml of water. How many litres of water there are in 30l of that drink?

7.5 A car uses 25 litres of petrol to travel 176 miles. How far will the car travel using 44 litres of petrol?

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4. Inverse Proportionality

Look at the relationship that exists between the number of the members of a family and the days that one box of apples lasts them (suppose that all the people eat the same amount of apples at the same rate). Observe that the more people there are in the family the less time the box of fruit lasts, and the less people there are, the longer it lasts. We will say that this relationship is of inverse proportionality

We say that there is an inverse proportionality between two magnitudes if when increasing one magnitude, (double, triple…) the other decreases (half, third…), when decreasing one (half, third…), the other increases (double, triple…).

Exercises 8 8.1 A truck that carries 3 tons need 15 trips to carry a certain amount of sand. How many trips are needed to carry the same amount of sand with another truck that carries 5 tons? 8.2 An automobile factory produces 8100 vehicles in 60 days. With the production rhythm unchanged. How many units will be made in one year?

8.3 A driver takes 2

13 hours to drive 329 km. How long will it take

another trip in similar conditions as the previous one, but travelling 282 km instead?

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8.4 Two hydraulic shovels make the trench for a telephone cable in ten days. How long will it take to make the trench with 5 shovels?

5. Ratios with more than two parts

There are ratios with 3 or more parts. Example: Tim, Tom and Tam are brothers. Tim has £10, Tom has £20 and Tam has £30. The money they have as a ratio is 10 : 20 : 30

We can simplify to 1 : 2 : 3

Exercise 9 Three angles are a = 60°, b = 80°, c = 80°. Write them as a ratio, and then simplify the ratio.

Can these be the angles of a triangle? If the answer is no, calculate the angles of a triangle with this ratio.

Exercise 10 The lengths of the sides of a quadrilateral are 4 cm, 4 cm, 6 cm and 6 cm. Find their ratio and simplify it.

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T: What type of quadrilateral can it be if the sides are listed in order? Exercise 11 Red blue and yellow paint are mixed in the ratio 3:2:7 to produce 6 litres of another colour. How much of each colour paint is used?

6. Percentages

A percent is a ratio of a number to 100. A percent is expressed using the symbol %. A percent is also equivalent to a fraction with denominator 100.

Examples: a) 5% of something = 5/100 of that thing. b) 52% = 52/100 = 13/25 (nearly equals 1/2) c) 8/200 is what %? Method 1: 8/200 = (4 × 2)/(100 × 2), so 8/200 = 4/100 = 4%. Method 2: Let 8/200 be n%. n = (8x100):200 = 4, so n% = 4%. 6.1 Percent as a decimal Percent and hundredths are basically equivalent. This makes conversion between percent and decimals very easy. To convert from a decimal to a percent, just move the decimal 2 places to the right. Examples: 0.15 = 15 hundredths = 15%.

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0.0006 = 0.06% Converting from percent to decimal form is similar, only you move the decimal point 2 places to the left. Examples: Express 3% in decimal form. Moving the decimal 2 to the left (and adding in 0's to the left of the 3 as place holders,) we get 0.03. Express 97’5% in decimal form. We move the decimal 2 places to the left to get 0.975.

Exercise 12 Convert the following percentages to decimals.

a) 75% b) 1.74% c) 3.7% d) 80% e) 15% f) 0.6% g) 9% h) 0.07%

Exercise 13 Convert the following decimals to percentages. a) 0.5 b) 0.74 c) 0.35 d) 0.08 e) 0.1 f) 0.52 g) 0.8 h) 0.07

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i) 0.04 j) 0.18 k) 0.4 l) 0.3

6.2 Common percentages

Some percentages are very common and it is useful to know them as fractions or decimals. Some very simple percents are: 100% = 1 50% = 1/2 = 0.5 25% = 1/4 = 0.25 10% = 1/10 = 0.1 1% = 1/100 = 0.01

7 Calculations with percentages

7.1 Percentage of a quantity To calculate the percentage of a quantity we must multiply it by the percent

and divide by 100.

Example:

Calculate the 5% of 72

5% of 72 is 6.3100

572=

Exercise 14 Calculate:

a) 15% of 540 b) 3% of 320

c) 5.3% of 7 d) 6% of 5430

7.2 Calculate the number when we know the Percentage

We must multiply the percentage by 100 and divide by the percent.

Example:

The 22% of a number is 66, which is the number?

The quantity is 30022

10066=

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Exercise 15 Calculate the number if:

a) 95% of the number is 1020

b) 5% of the number is 7

c) 15.3% of the number is 500

d) 83% of the number is 1086

7.3 Express a ratio or a fraction as a percent

To write as a percent a ratio or a fraction , we may convert them into a number dividing and then multiply by 100 Example:

Calculate 27 out of 32 as a . We do %3.8410032

27=⋅

Exercise 16 Express each of the following as percentages.

a) 8 out of 50

b) 3 out of 25

c) 8 out of 20

d) 3 out of 10

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e) 6 out of 50

f) 6 out of 40

g) 12 out of 80 h) 84 out of 200

i) 75

23

j) 5

3

k) 37

102

7.4 Estimating percentages Estimating a percent is as easy as estimating a fraction as a decimal, and converting to a percent by multiplying by 100. To estimate the percent of a number, we may convert the percent to a fraction, if useful, to estimate the percent. Example: Estimate 19 as a percent of 80. As a fraction, 19/80 20/80 = 1/4 =0.25 = 25%. The exact percent is in fact 23.75%, so the estimate of 25% is only 1.25% off. (About 1 part out of 100.)

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Exercise 17 Estimate, and later calculate the exact answer: 7 as a percent of 960. 12% of 72. 9.6% of 51.

7.6 Calculate a number increased with a percentage

We add to the number the percentage.

Example: Calculate the value of 320 increased by a 5%

1. The increase is 5% of 320 is 16100

5320=

2. The final value is 320 + 16 = 336

7.7 Calculate a number decreased with a percentage

We subtract to the number the percentage.

Example: Calculate the value of 320 decreased by a 12%

1. The decrease is 12% of 320 is 4.38100

12320=

2. The final value is 320 – 38.4 = 281.6

7.7 Percentage increase decrease

Percent increase and decrease of a value measure how that value changes, as a percentage of its original value.

Percentage increases and decreases are calculated using:

100xvalue initial

increase increase Percentage =

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100xvalue initial

decreasedecrease Percentage =

Examples: 1. A collectors' comic book is worth 120 € in 2004, and in 2005 its value is 132 €. The increase in price is 12€; 12 is 10% of 120, so we say its value increased by 10%. 2. Amy is training for the 1500 meter run. When she started training she could run 1500 meters in 5 minutes and 50 seconds. After a year of practice her time decreased by 8%. How fast can she run the race now? Her old time was 5 × 60 + 50 = 350 seconds, and 8% of 350 are 28, so she can run the race in 350 - 28 = 322 seconds (5 minutes and 22 seconds). 3. A compact disc that sells for $12 is on sale at a 20% discount. How much does the disc cost on sale? The amount of the discount is 20% of $12, which is $2.40, so the sale price is $12.00 - $2.40 = $9.60. Exercises 18 18.1 A magazine for teenagers sells 110000 copies each month. The company's president wants to increase the sales by 6%. How many extra magazines would they have to sell to reach this goal?

18.2 Chocolate bars normally cost 80 cents each, but are on sale for 40 cents each. What percent discount is this? 18.3 Movie tickets sell for $8.00 each, but if you buy 4 or more you get $1.00 off each ticket. What percent discount is this?

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18.4 A firm decides to give 20% extra free in their packets of soap powder. How much extra soap powder would be given away free with packets which normally contain

(a) 2 kg of powder

(b) 1.2 kg of powder?

18.5 A house costs £30,000. A buyer is given a 10% discount. How much money does the buyer save?

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18.6 Karen bought an antique vase for £120. Two years later its value increases by 25%. What is the new value of the vase?

18.7 When Wendy walks to school she covers a distance of 1800 m. One day she discovers a shortcut, which reduces this distance by 20%. How much shorter is the new route?

18.8 Kim's mother decides to increase her pocket money by 40%. How much extra does Kim receive each week if previously she was given £2.00 per week?

18.9 Express '30 out of 40' and '40 out of 50' as percentages. Which is the best score?

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EXTRA EXERCISES

1. The price of a bar of chocolate is 35 c and includes 7 c profit. Express the profit as a percentage of the price.

2. In the crowd at a football match there were 35000 Manchester United supporters and 25000 Manchester City supporters. What percentage of the crowd supported each team?

3. A school won a prize of £1800. The Headmaster spent £750 on a new computer and the rest on software. What percentage of the money was spent on software?

4. James needs another 40 football stickers to complete his collection. There are a total of 500 stickers in the collection. What percentage of the collection does he have?

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5. A 750 ml bottle of shampoo contains 200 ml of free shampoo. What percentage is free?

6. Adrian finds that in a delivery of 1500 bricks there are 50 broken. What is the percentage of broken bricks?

7. A glass of drink contains 50 ml of fruit juice and 200 ml of lemonade. What percentage of the drink is fruit juice?

8. Find each of the following, giving your answers to the nearest penny. a) 30% of £150 b) 12% of £903 c) 12.6% of £140 d) 4.5% of £320 e) 5.9% of £50 f) 8.2% of £18.

9. A MP4 player has a normal price of £150.

a) In a sale its normal price is reduced by 12%. Find the sale price. b) After the sale, normal prices are increased by 12%. Find the new

price of the MP4 player.

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10. Peter earns £9000 per year. He does not pay taxes on the first £3500 he earns and pays 25% taxes on the rest. How much tax does he pay?

11. A new gas supplier offers a 25% discount on the normal price and a further 5% discount if customers pay on line. For one client the gas bill is £130. Find out how much they have to pay after both discounts.

Remember

100xvalue initial

increase increase Percentage =

100xvalue initial

decrease decrease Percentage =

12. A baby weighed 5.6 kg and six weeks later her weight increases to 6.8kg. Find the percentage increase.

13. A factory produces blank DVDs at a cost of 88p and sells them for £1.10. Find the percentage profit.

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14. A new car cost £11500 and one year later it is sold for £9995. Find the percentage reduction in the value of the car.

15. An investor bought some shares at a price of £14.88 each. The price of the shares drops to £11.45. Find the percentage loss.

16. A supermarket offers a £8 discount to all customers spending more than £40. Karen spends £42.63 and John spends £78.82. Find the percentage saving for each one.

17. In a year, the value of a house increases from £146 000 to £148 000. Find the percentage increase in the value of the house.

18. A battery powers an iPod for 12 hours. An improved version of the battery powers the iPod for an extra 30 minutes. Find the percentage increase in the life of the batteries.

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Solutions Exercise 1 1:2, 1:2, 2:5, 3:7, 1:11. Exercise 2 1:2.5 and 0.4:1

Exercise 3 1:2.25, 1:0.71, 3.3:1)

, 1:2.4.

Exercise 4 1:5.1)

, 3:1, 0.4:1, 6.25:1

Exercise 5 35x = , 45x = , 15x = , 6x = , 3.9x)

= , 8.12x = , 12x = , 5.7x = , 28x = .

Exercise 6 Exercise 7 7.1 a) 5.75 €, b) 27.03 €. 7.2 a) 670.93 km, b) 2.2h or 2h 12 minutes. 7.3 300 bricks. 7.4 24.75 l 7.5 309.76 miles. Exercises 8 8.1 25 trips. 8.2 49275 vehicles. 8.3 3 h. 8.4 25 days. Exercise 9 60:80:80; 3:4:4 or 0.75:1:1;no, they can not be the angles of a

triangle; º09.49 , º45.65∩

and º45.65∩

Exercise 10 4:4:6:6, 1:1:1.5:1.5 T: It is a trapezoid (kite). Exercise 11 1.5 of red, 1 l of blue and 3.5 l of yellow paint. Exercise 12 a) 0.75, b) 0.0174, c) 0.037, d) 0.8, e) 0.15, f) 0.006, g) 0.09, h) 0.0007. Exercise 13 a) 50%, b) 74%, c) 35%, d) 8%, e) 10%, f) 52%, g) 80%, h) 7%, i) 4%, j) 18%, k) 40%, l) 30%. Exercise 14 a) 81, b) 9.6, c) 0.371, d) 325.8. Exercise 15 a) 1073.68, b) 140, c) 3267.97, d) 1308.43. Exercise 16 a) 16%, b)12%, c) 40%, d) 30%, e) 12%, f) 15%, g) 15%, h) 42%, i) 30.66%, j) 60%, k) 275.68%. Exercise 17 7% and 0.729%, 8% and 8.64%, 5% and 4.896% Exercises 18 18.1 6600 magazines. 18.2 50%. 18.3 12% discount in each extra ticket. 18.4 (a) 0.4kg, (b) 0.24 kg. 18.5 £3000. 18.6 £150. 18.7 360m. 18.8 80 p. 18.9 75% and 80%, '40 out of 50' is the best score.

EXTRA EXERCISES

1. 20%. 2. 58.3% Manchester United supporters and 41.7% Manchester City supporters. 3. 58.3%. 4. 92%. 5. 26.6%. 6. 3.3%. 7. 20%. 8. a) £45, b) £108.30, c) £17.64, d) £14.40, e) £2.95, f) £1.48. 9. a) £132, b) £168. 10. 1375£. 11. 92.63£. 12. 21.4%. 13. 25%. 14. 13%. 15. 23%. 16. Karen 18.77% and John 10%. 17. 1.4%. 18. 4.2%

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9 Algebra and equations

1 Variables

A variable is a symbol that represents a number. We usually use letters such as x, n, p, t for variables.

Letters are useful if we want to operate with an unknown number instead with a particular one. Let us look at some examples: We say that s represents the side of a square, then s represents a number and:

s4 Is the perimeter of the square

ss ⋅ Is the area of the square When letters express numbers they have the same operating properties. The part of mathematics that deals with the study of the expressions with letters and numbers is called algebra.

2 Expressions

An expression is a mathematical statement with numbers and variables.

Examples:

3 x x+3 ( )5x2 −⋅ x3x 2−

If Mark weights 80 kg and he gains n kg, the new weight is 80 + n Exercise 1 Calling ‘a’ the age of a person write an expression for: 1.1 The age he/she will be in 2012. 1.2 The age he/she was 7 years ago 1.3 The age he/she will be after living the same time again. Exercise 2 Calling x a number, express in algebra:

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2.1 The sum of the number and 10 2.2 The difference between 123 and the number 2.3 The double of the number 2.4 The triple of the number plus three units 2.5 The half of the number minus seven 2.6 The three quarters of the number plus forty-six

3 Monomials

The simplest algebraic expressions formed by products of numbers and letters are called monomial.

A monomial consists of the product of a known number (coefficient) by one or several letters with exponents that must be constant and positive whole numbers (literal part). Generally in the monomials the product signs are not included, so we find a

number followed by one or more letters, we understand that they are

multiplied.

Examples: a) 2x is a monomial. 2 is the coefficient, x is literal part.

b) 2x3− is a monomial, -3 is the coefficient, x2 is the literal part, x is the variable and the degree is 2

Coefficien

Literal part

Degree

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c) 7t5

3 is a monomial,

5

3 is the coefficient, 7t is the literal part, t is the

variable and the degree is 7

d) 2xy5 is a monomial, 5 is the coefficient, 2xy is the literal part, x and y are

the variables and the degree is 3 e) 7x2 + is an algebraic expression but it is not a monomial.

f) x

3 is an algebraic expression but it is not a monomial.

Exercise 3 Find which of the following expressions are monomials and determine, if they are so, their coefficient, literal part and variables:

a) 7x5

1−

b) 2t2 c) a + b

d) 9a

e) 4n2

f) n3

g) 2abc7

4 Operations of monomials

4.1 Addition or subtraction of two monomials.

We add or subtract the coefficients and we leave the literal part unchanged.

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Two monomials can only be simplified when both have the same literal part,

that is, when they are “like monomials”. When the literal part is different,

the addition is left indicated.

Examples:

x12x7x5 =+

x2

5x2

2

1x2x

2

1=

+=+

ab9ab2ab7 =+

Exercise 4 Operate

a) =− x7x2 b) =+ x2x15 c) =− xx8

d) =+ x2x2

15 e) =+−

22 x23x2 f) =+ 2x15

g) =− a7a3 h) x3x 2+ i) =+ x

3

2x

4.2 Product of two monomials.

We multiply the coefficients and also the literal part (remember how we

multiply powers with the same base).

Examples:

2x35x7x5 =⋅

32 xx2x2

1=⋅

523 a14a2a7 =⋅

Exercise 5 Operate

a) =⋅ x7x2 b) =⋅ x2x15 c) =⋅ xx8

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d) =⋅3x2x

2

15 e) =⋅−

22 x23x2 f) =⋅ 2x15

5 Manipulating algebraic expressions

5.1 Evaluate an expression.

To evaluate an expression at some number means we replace a variable in

the expression with the number and then, if necessary, we calculate the

value.

Example:

Evaluate 3x5 + when 2x = , 3x5 + becomes 13325 =+⋅

Remember the rules: parenthesis, exponents, multiplications and

divisions and, the last, additions and subtractions.

Exercise 6 Evaluate the expressions:

a) 2x5

1− when 3x =

b) 2t2 when 2t =

c) a+b when 7ba ==

d) 9a when 1a −=

e) n3n4+ when 3n =

f) 3n

2n3

+ when 5n =

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g) 2cba7 −+ when 4c,2b,3a =−==

5.2 Expansion of brackets.

Multiplying a number by an addition is equal to multiplying by each adding

number and then to adding the partial products.

Examples:

( ) 12x26x2 +=+

3(2x-7) = 6x-21

3x(3x+2) = 9x2+6x

Exercise 7 Fill in the missing terms:

a) 5(3x-4)= - 20 b) x(x-2)= -2x

c) a(4-a)= - a2 d) 7x(3x-y)= - 7xy

Exercise 8 Expand:

a) =− )4x(2 b) =− )x2(6

c) =− )1x2(x6 d) =+ )8t2(t2

e) =− )y3x2(x5 f) =− )1x(x

g) =+ )x77(2 h) =− )ax3(x2

Exercise 9 Write down expressions for the area of these rectangles and

then expand the brackets as in the example.

a) 3x+1

3 3x9)1x3(3A +=+=

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b) 2x-1

7 =A

c) 3x

x-2 =A

d) x-7

4 =A

5.3 Common factors

It is important to know how to write expressions including brackets when it is

possible; this is called factorization or factoring

Examples:

)1x2(616x266x12 +=⋅+⋅=+

)1x2(6 +=

)2x3(727x3714x21 −=⋅−⋅=−

)2x3(7 −=

)8x5(xx8x5 2−=− We can check our answer by expanding the expression.

Exercise 10 Factorise:

a) =+ 15x10 b) =− 12x4 c) =− 9x9

d) =− x2x3 2 e) =+ x3x9 2 f) =− 3x3

g) =− x3x33 2 h) =−2x3x5 g) =− 2x13 2

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6 Equations

An equation is a statement in which two expressions are equal.

- The letter in an equation is called the unknown. (Sometimes it is called the variable). Examples of equations: x = 2 3 = x 2x = 4 5x+1 = 3 x2 = 4 In an equation we consider two members: First member is the left member Second member is the right member. Each monomial is called a term. Monomials with the same literal part are called “like terms” Example: In the equation 72t3 −=− we say: - The first member is 2t3 − - The second member is 7−

- There are three terms 3t, -2 and –7 - The unknown is t.

In the equation 2x56x3 2+=− :

- The first member is 6x3 2−

- The second member is 2x5 +

- There are four terms 2x3 , -6, 5x and 2 - The unknown is x.

7 Solving equations

Solving an equation is to find out a solution. A solution to an equation is the number that makes the equality true when we replace the unknown or variable with that number.

Examples:

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2 is a solution to the equation 2x = 4 because if we replace x by 2 that gives

us 422 =⋅ , which is true.

3 is a solution to the equation 5x + 8 = 16, if we replace x by 3, we have

16835 =+⋅ , which is true.

4 is not a solution to 41x3 =− because 4143 =−⋅ is not true.

7.1 Rules of simplifying and solving equations

These are the basic rules for simplifying equations:

These rules must be followed, usually in this order, to solve linear equations.

Rule 1 If there are brackets we must remove them (expand the expression)

as in the usual operations with numbers.

Rule 2 We can add or subtract any number to or from both members of the

equation so any x-term or number that is adding (positive sign) moves to

the other side subtracting (negative sign) and vice versa.

Rule 3 Move x-terms to one side and numbers to the other.

Rule 4 Combine like terms

Rule 5 Any number that is multiplying, the whole expression, on one side

moves to the other side dividing, and a number that is dividing, the whole

expression, on one side moves to the other multiplying.

Examples:

1. Solve 2412x5 −=−+

We add the two numbers in the first member, we get

28x5 −=+

We may subtract 8 from each member and make the addition of the integers

numbers that appear

8288x5 −−=−+ ,

8205 −−=+x , 825 −−=x

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More easily , 8 that is positive moves to the right member as 8−

10x5 −=

We divide each member by 5 or we can say that 5 which is multiplying moves

to the second member dividing 5

10x

−=

2x −= we can check the solution (always in the original equation)

241225 −=−+⋅

241210 −=−+

22 −=− So our solution is correct.

2. Solve x25x7 =+

We may subtract 5 from each member and make the addition of the integers

numbers that appear

5x255x7 −=−+

5x2x7 −=

We may subtract 2x from each member

5x2x2x2x7 −−=−

We can add like terms

We divide each member by 5

5x5 −=

We divide each member by 5 and we get

1x −= We check the solution

( )125)1(7 −=+−⋅

257 −=+−

22 −=− So our solution is correct.

3. Solve ( ) 1715x2 =++

We can expand

17110x2 =++

1711x2 =+

We may subtract 11 from each member

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11171111x2 −=−+ or simply 11 moves to the right member as 11−

and then 11172 −=x

6x2 =

We divide each member by 2 or 2 which is multiplying moves to the right

member dividing 3x =

We check the solution

( ) 171532 =++

17182 =+⋅

1717 = So our solution is correct.

Exercise 11 Solve:

1. 107x =+

2. 213x =−

3. 76t =−

4. 41322x −=−

5. 54y4 =+

6. z312 +=

7. 1724m =−

8. 892p1 −=+

9. 237xx −=+

10. 3y2y23 =++

11. 129x4 −=

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12. 20x16100 +=

13. 203x5 =+

14. 213x10 −=

15. 67x2 =+

16. 3x72 −=

17. 137x12 =−

18. 23x5x3 =−

19. 123x7x5 −=+

20. x312x44 −=+

Exercise 12 Solve:

1. ( ) 72x3 =−

2. ( ) 23x2 =+

3. ( ) 25x6 −=−

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4. ( ) 20x21x7 =+−

5. ( ) 03x22x3 =+−

6. ( ) 100x5x34 =−−

7. ( ) x131x3621 −−=−

8. ( ) 1x22x219 =+−

9. ( ) x31x5x32 −=+−

10. ( ) ( ) 1x2x3132x152x3 −+−=+−⋅−

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Exercise 13 Express each problem as an equation and solve them

1. The sum of my age and 7 is 42. Find my age.

2. The difference of a number and 23 is 124. Find the number.

3. The quotient of 35 and a number is 7. Find the number.

4. If someone gives me 24€ I will have 34.23 € Find the money I have.

5. The double of my age minus 7 years is the age of my elder brother

who is 19 years old.

6. The area of a square is 144 square metres. Find its length.

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7. A teacher gives x coloured pencils each one of 8 girls except to one

of them who only receives 4 pencils. The teacher gives 53 pencils in

total. How many pencils did each girl receive?

8. Donald thinks of a number, multiplies it by 3 and subtracts 7. His

answer is the double of the number plus 5 units. Which is the number?

9. In a triangle, the smallest angle is 20º less than the middle angle and

the largest angle is twice the middle one. Find all the angles.

10. If we shorten 2 cm each of the two opposite sides of a square, we

get a rectangle with an area which has 28 cm2 less than the area of the

square. Find out the perimeter of the rectangle.

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Solutions Exercise 1 1.1 12a + , 1.2 7a − , 1.3 a2 . Exercise 2 2.1 10x + , 2.2 x123 − ,

2.3 x2 , 2.4 3x3 + , 2.5 72

x− , 2.6 46x

4

3+ . Exercise 3 a) 7x

5

1− is a

monomial, 5

1− is the coefficient, 7x is literal part, x is the variable; b) 2t2 is a

monomial, 2 is the coefficient, 2t is literal part, t is the variable; c) a + b is an

algebraic expression but it is not a monomial; d) 9a is a monomial, 1 is the

coefficient, 9a is literal part, a is the variable; e) 4n2 is a monomial, 2 is

the coefficient, 4n is literal part, n is the variable; f) n3 is an algebraic

expression but it is not a monomial; g) 2abc7 is a monomial, 7 is the

coefficient, 2abc is literal part, a, b and c are the variables. Exercise 4 a)

x5− , b) x17 , c) x7 , d) x2

19, e) 2x21 , f) 2x15 + , g) a4− , h) x3x 2

+ , i)

x3

5. Exercise 5 a) 2x14 , b) 2x30 , c) 2x8 , d) 4x15 , e) 4x46− , f) x30 .

Exercise 6 a) 5

9− , b) 8, c) 14, d) 1− , e) 90, f)

2

17, g) 3. Exercise 7 a) x15 ,

b) 2x , c) 4ª, d) 2x21 . Exercise 8 a) 8x2 − , b) x612 − , c) x6x12 2− , d)

t16t4 2+ , e) xy15x10 2

− , f) xx2− , g) x1414 + , h) ax2x6 2

− . Exercise 9

b) 7x14A −= , c) x6x3A 2−= , d) 28x4A −= . Exercise 10 a) ( )3x25 + , b)

( )3x4 − , c) ( )1x9 − , d) ( )2x3x − , e) ( )1x3x3 + , f) ( )1x3 − , g) ( )1x11x3 − , h)

( )x35x − , g) It can not be factorized. Exercise 11 1. 3x = , 2. 5x = , 3.

13t = , 4. 31x = , 5. 50y = , 6. 9z = , 7. 41m = , 8. 88p −= , 9. 2

35x = ,

10. 3

20y −= , 11. 4x = , 12. 5x = , 13.

5

17x = , 14.

10

11x = , 15.

2

1x −= ,

16. 7

5x = , 17.

3

5x = , 18.

2

23x −= , 19.

6

11x = , 20. 8x −= .

Exercise 12 1. 3

13x = , 2. 2x −= , 3.

3

14x = , 4. 3x = , 5. 6x −= , 6.

11

120x = ,

7. 3x −= , 8. 2x −= , 9. 6

5x −= , 10.

5

3x = .

Exercise 13 1. 35x427x =→=+ ; 2. 147x12423x =→=− ;

3. 5x7x

35=→= ; 4. 23.10x23.3424x =→=+ ; 5. 12x177x2 =→=− ;

6. 12x144x2=→= ; 7. 7x534x7 =→=+ ; 8. 12x5x27x3 =→+=− ;

9. 50x180x220xx =→=+−+ , the angles are 30º, 50º and 100º;

10. ( ) 7x4xx28x2=→−=− , the perimeter is 20 cm.

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10 Geometry, angles

1 Basic terms

Points

A point is one of the basic terms in geometry. We say that a point is a "dot" on a piece of paper. We identify this point with a number or letter. A point has no length or width.

Lines

A line is a "straight" line that we draw with a ruler on a piece of paper; a line extends forever in both directions.

Rays A ray is a "straight" line that begins at a certain point and extends forever in one direction. The point where the ray begins is known as its endpoint.

Line Segments A line segment is a portion of a "straight" line. A line segment does not extend forever, but has two distinct endpoints. We write the name of a line

segment with endpoints A and B as AB .

Intersection The term intersect is used when lines, ray lines or segments share a common point. The point they share is called the point of intersection. Example: In the diagram below, line AB and line GH intersect at point D; line 2 intersects the circle at point P:

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Parallel Lines Two lines in the same plane which never intersect are called parallel lines. We say that two line segments are parallel if the lines that they lie on are parallel. Examples: Lines 1 and 2 below are parallel.

The opposite sides AB, DC or AD, BC of the rectangle below are parallel.

2 Angles Two rays with the same endpoint form an angle. The point where the rays intersect is called the vertex of the angle. The two rays are called the sides of the angle. Some examples of angles are:

2.1 How to name the angles.

We can name the angle below as B∠ or even b, but it is better to name it as

ABC or as CBA. Note how the vertex point is always given in the middle.

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2.2 Angle Bisector An angle bisector is a ray that divides an angle into two equal angles. Example

The ray AD on the right is the angle bisector of the angle BAC on the left

because BAC = 2· BAD = 2· DAC.

A

B

CA

B

C

D

2.3 Bisecting line of a segment Two lines that meet at a right angle are perpendicular. The perpendicular line that divides a segment into two equal parts is the bisecting line of the segment 2.4 Measuring angles. Degrees We measure the size of an angle using degrees. There are 360º in a full turn. Here are some examples of angles and their approximate degree measurements.

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45º 90º 120º For drawing and measuring angles we use a protractor.

Note that usually there are two scales in the protractors, use the correct one. Exercise 1 1.1 Draw in your notebook the following angles: a) ∠ ABC = 23º b) ∠ CDE = 56º c) ∠ PQR = 88º d) ∠ RST = 68º e) ∠ KRT = 144º f) ∠ MVL = 180º 1.2 Measure the size of the following angles: a) b) c) d) e)

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Approximations

• 1° is approximately the width of a pinky finger nail at arm's length • 10° is approximately the width of a closed fist at arm's length.

3 Type of angles

Acute angles: An acute angle is an angle measuring between 0 and 90 degrees.

Obtuse angles: An obtuse angle is an angle measuring between 90 and 180 degrees.

Right angles: A right angle is an angle measuring 90 degrees. Two lines or line segments that meet at a right angle are perpendicular.

Straight angles: A straight angle is an angle measuring 180º

Complete turn: One complete turn is 360º Exercise 2

a) Make a list of objects in the classroom or in your house which contain:

A right angle

A straight angle

An acute angle

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b) Name all the obtuse, acute and right angles in the diagrams.

A A B

B C C D

D F

E F H

E G

Exercise 3 How many degrees will the minute hand of a clock move in

a) 15 minutes b) 30 minutes

c) 5 minutes d) 20 minutes

e) 1 minute f) 46 minutes

4 Related angles Complementary Angles

Two angles are called complementary angles if the sum of their degree measurements equals 90 degrees. One of the complementary angles is the complement of the other. The two angles º60DCB =∠ and º30ACB =∠ are complementary. A B 30º 60º D C

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Supplementary Angles Two angles are called supplementary angles if the sum of their degree measurements equals 180 degrees. One of the supplementary angles is the supplement of the other. The two angles º50DAB =∠ and º130CAB =∠ are supplementary. B

130º 50º C A D Exercise 4 Calculate the complement and draw them on your notebook : a) 17º b) 42º c) 7º d) 90º Exercise 5 Calculate the supplement of: a) 37º b) 52º c) 123º d) 7º e) 90º

5 Angles between intersecting lines

Vertical Angles For any two lines that meet, such as in the diagram below, angle ∠ BEC and angle ∠ AED are called vertical angles or vertical opposite angles. Vertical angles have the same degree measurement. Angle ∠ AEB and angle ∠ DEC are also vertical angles.

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When a line crosses two parallel lines like in the diagram below

dcba ===

And

hgfe ===

c and b are called Alternate Interior Angles g and f are also Alternate Interior Angles e and h are called Alternate Exterior Angles a and d are also Alternate Exterior Angles e and f are called Corresponding Angles a and b are also Corresponding Angles Remember that f and h or b and d, for example, are Vertical Angles Exercise 6 a) Find the unknown angles and say all the correspondences you can see:

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a = b = c = d = e = f =

g = h = i = j = k = l =

m = n =

b) Find the unknown angles:

1. a = b = c = 2. a = b = c = 3. a = b = c = d =

4. a = b = c = d = e = f =

5. a = b = c = d = 6. a = b = c = d =

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6 Operations with angles The subunits of the degree are the minute of arc and the second of arc.

One minute 60

11 =′ of a degree, that is 06º1 ′=

One second 60

11 =′′ of a minute, that is 061 ′′=′

These are the sexagesimal units, so an angle “a” can be expressed for example 0432º25a ′′′= and we need to operate angles expressed in this

form.

6.1 Addition. We need to add separately degrees minutes and seconds and then convert the seconds into minutes and the minutes into degrees if we get more than 60 subunits. Example Add 5333º120435º45 ′′′+′′′

Adding separately we get 5768º575333º120435º45 ′′′=′′′+′′′ but

51157 ′′′=′′ so we add 1′ and get 72º178 ′=′ we add º1 and finally the

solution is 5172º585768º57 ′′′=′′′

6.2 Subtraction We need to subtract separately degrees minutes and seconds, if we do not have enough seconds or minutes we convert one degree into minutes or a minute into seconds. Example Subtract 5334º12and1231º57 ′′′′′′ We write 1237º56as1231º57 ′′′′′′ and

then:

- 5334º12

1827º56

′′′

′′′

6492º44 ′′′ Is the answer

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6.3 Multiplication by a whole number We multiply separately degrees minutes and seconds and then convert the seconds into minutes and the minutes into degrees when we get more than 60 subunits. Example

Multiply ( ) 65231º22 ⋅′′′

6.4 Division by a whole number

We divide the degrees, and the remainder is converted into minutes that must be added to the previous, divide the minutes and we repeat the same that we have done before. The remainder is in seconds.

Example

Divide ( ) 4:5231º22 ′′′

Exercise 7 7.1 Add:

a) 28º 35’ 43” + 157º 54’ 21” b) 49º 55’ 17” + 11º 5’ 47”

22º 13’ 25” 6 6 6 132 78 150

80’ 2’ 30”

133º 1º 20’ Solution 133º 20’ 30”

22º 13’ 25” 4 2º x 60 = 120 5º 33’ 21” quotient

133’ 1’ x 60 = 60” 85” 1” remainder

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c) 233º 5’ 59” + 79º 48’ 40” 7.2 a) Subtract 34º 32’ 12” – 11º 30’ 22”

b) Calculate the complement of 13º 45’ 12” c) Calculate the supplement of 93º 30’

7.3 Given A = 22º 32’ 41” Calculate:

a) 2·A b) 3·A

c) 5

A

d) 5

A·2

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7 Angles in the polygons

7.1 Triangle A triangle is a three-sided polygon.

The sum of the angles of a triangle is 180 degrees.

7.2 Quadrilateral A quadrilateral is a four-sided polygon The sum of the angles of any quadrilateral is 360º

a

b cd

ef

a + b + c = 180º d + e + f = 180º

a + b + c + d + f = 360º

7.3 Polygon of n sides The sum of the angles of a polygon with n sides, where n is 3 or more, is

( ) º1802n ⋅− .

7.4 Regular Polygon

A regular polygon is a polygon whose sides are all the same length, and whose angles are all the same.

As the sum of the angles of a polygon with n sides is ( ) º1802n ⋅− , each

angle in a regular polygon is ( )

n

º1802n −.

a

a b

b

c

a + b + c = 180º

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Exercise 8 Complete the following table

Name

Number of sides

Sum of the interior angles

Name of the regular polygon

Interior angle

Triangle

3 180º Equilateral triangle

Quadrilateral

4 360 Square

Pentagon

Regular pentagon

Hexagon

Heptagon

Regular heptagon

8

Nonagon

Decagon

Undecagon

Dodecagon

8 Angles in a circle

8.1 Central angle A central angle is an angle whose vertex is the center of a circle and whose sides pass through a pair of points on the circle. There is an arc of the circumference associated to the angle and it is, by definition equal to the central angle itself. ∠ MON is a central angle of 60º

8.2 Inscribed angle It is formed when two lines intersect a circle and its vertex is on the circumference. The measure of the intercepted arc in an inscribed angle is exactly the half of the central angle. ∠ MPN is an inscribed angle with the same arc, so it is a 30º angle.

60º

30º

M

N

O

P

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Exercise 10 Calculate the angles in each figure and explain your answer:

57º

a

b

c

d 120º

h

e

fg

12º

130ºi

25º

a = b =

c = d =

e = f =

g = h =

i =

9 Symmetric shapes

A figure that can be folded flat along a line so that the two halves match perfectly is a symmetric figure; such a line is called a line of symmetry. Examples:

The triangle, the square and the rectangle below are symmetric figures. The dotted lines are the lines of symmetry.

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The regular pentagon below is a symmetric figure. It has five different lines of symmetry shown below. The circle below is a symmetric figure. Any line that passes through its centre is a line of symmetry! The figures shown below are not symmetric.

Exercise 11 Draw in all the lines of symmetry in the following regular polygons and use your answers to complete the table:

Polygon Hexagon Octagon Nonagon Decagon

Nº symmetry lines

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Solutions

Exercise 1 1.1 1.2 a) 45º, b) 104º, c) 22º, d) 113º, e) 71º. Exercise 2 a) b)

Left: obtuse BAC∠ , BDC∠ , EDF∠ , ACF∠ , ABE∠ ; right: EBC∠ , BEF∠ ,

BCF∠ , CFE∠ ; all the rest are acute angles. Right: acute: FEG∠ ; obtuse:

DFE∠ ; all the rest are right angles. Exercise 3 a) 90º, b) 180º, c) 30º, d)

120º, e) 6º, f) 276º. Exercise 4 a) 73º, b) 48º, c) 83º, d) 0º. Exercise 5 a)

143º, b) 128º , c) 57º, d) 173º, e) 90º. Exercise 6 a) a = 60º, b = 120º, c =

60º, d = 60º, e= 120º, f = 64º, g = 116º, h = 64º, i = 116º, j = 146º, k = 146º, l

= 34º, m = 146º, n = 34º. b) 1. a = 148º, b = 148º, c = 32º, 2. a = 154º, b =

26º, c = 154º, 3. a = 80º, b = 60º, c = 80º, d = 120º, 4. a = 108º, b = 72º, c =

72º, d = 72º, e = 72º, f = 108º, 5. a = 80º, b = 60º, c = 40º, d = 40º, 6. a =

130º, b = 140º, c = 140º, d = 130º. Exercise 7 7.1 a) 186º 30’ 4’’, b) 61º 1’

4’’, c)312º 54’ 39’’. 7.2 a) 23º 1’ 50’’, b) 76º 14’ 48’’, c) 86º 30’. 7.3 a) 45º 5’

22’’, b) 67º 38’ 3’’, c) 4º 30’ 32’’, d) 9º 1’ 4’’. Exercise 8

Name Number of

sides

Sum of the interior

angles

Name of the regular

polygon

Interior

angle

Triangle 3 180º Equilateral triangle 60º

Quadrilateral 4 360º Square 90º

Pentagon 5 540º Regular pentagon 108º

Hexagon 6 720º Regular hexagon 120º

Heptagon 7 900º Regular heptagon 128º 36’

Octagon 8 1080º Regular octagon 135º

Nonagon 9 1260º Regular nonagon 140º

Decagon 10 1440º Regular decagon 144º

Undecagon 11 1620º Regular undecagon 147º 18’

Dodecagon 12 1800º Regular dodecagon 150º

Exercise 10 a = 57º, b = 28º 30’, c = 90º, d = 60º, e = 12º, f = 50º, g = 72º, h

= 108º, i = 155º. Exercise 11

Polygon Hexagon Octagon Nonagon Decagon

Nº symmetry lines 6 8 9 10

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11 Polygons and 3-D shapes

1 Triangles A triangle is a three-sided polygon. Sides of a polygon are also called edges. Triangles can be classified either by sides or by angles. By sides:

Equilateral Triangle It is a triangle that has: Three equal sides Three equal angles of 60 degrees. Isosceles Triangle It is a triangle that has: Two sides of equal length. Two equal angles Scalene Triangle It is a triangle that has: Three sides of different lengths. Three different angles

By angles:

Acute Triangle It is a triangle that has three acute angles. Obtuse Triangle It is a triangle that has an obtuse angle, (measures more than 90º).

Right Triangle It is a triangle that has a right angle. The side opposite the right angle is called the hypotenuse. The two sides that form the right angle are called the legs.

l

l

h

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Exercise 1 Classify the following triangles by their sides and by their angles. Find the asked angles of the triangles.

Triangle By the sides By the angles Calculate ABC

DEF

HGI

=

H

JKL

MNO

=

N

YAZ

=

Y =∧

Z

BCD

=

C =∧

D

QPR

=

P

SUT

XVW

=

X

MKL

=

L

NPO

=

O

GEF

=

F

QSR

=

R

UTV

∧∧∧

=== VTU

HIJ

=

I

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2 Equality of triangles Two triangles are equal if the angles and the sides of one of them are equal to the corresponding angles and sides of the other But we can assure that two triangles are equal if:

I. The lengths of their corresponding sides are equal II. Two corresponding sides of two triangles and their included angles

are equal. III. One side and the angles at any side are equal.

3 Points and lines associated with a triangle

3.1 Perpendicular bisectors, circumcentre

A perpendicular bisector of a triangle

is a straight line passing through the

midpoint of a side and perpendicular to

it.

The three perpendicular bisectors

meet in a single point, it is called the

triangle's circumcentre; this point is the

centre of the circumcircle, the circle

passing through the three vertices.

3.2 Altitudes, orthocentre An altitude of a triangle is a straight line through a vertex and perpendicular to the opposite side. This opposite side is called the base of the altitude, and the point where the altitude intersects the base (or its extension) is called the foot of the altitude. The length of the altitude is the distance between the base and the vertex. The three altitudes intersect in a single point, called the orthocentre of the triangle.

O

A

BC

A

BC

ha

bc

hh

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3.3 Angle bisectors, incentre An angle bisector of a triangle is a straight line through a vertex, which cuts the corresponding angle in half. The three angle bisectors intersect in a single point called the incentre, which is the centre of the triangle's incircle. The incircle is the circle, which lies inside the triangle and is tangent to the three sides.

3.4 Medians, barycentre A median of a triangle is a straight line through a vertex and the midpoint of the opposite side. The three medians intersect in a single point, the triangle's barycentre. This is also the triangle's centre of gravity. Exercise 2

a) Construct a triangle with a base of 6 cm and angles of 60º and 45º.

b) Draw the three perpendicular bisectors and check that the three of them have a common point. Which is its name?

c) Use a compass to draw the circumcircle.

A

B

C

O

m

m m

A

B

C

G

a

b c

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Exercise 3 a) Construct a triangle with a base of 5 cm, one side 7 cm and the

angle between these sides of 50º. b) Draw the three altitudes and check that the three of them have a

common point. Which is its name?

Exercise 4 a) Construct a triangle with sides of 9.5 cm, 7.2 cm and 6 cm. b) Draw the three angle bisectors and check that the three of them

have a common point. Which is its name? c) Draw the incircle of the triangle

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Exercise 5 a) Construct a triangle with sides of 6.4 cm, 7.8 cm and the angle

between these sides of 37º. b) Draw the three medians and check that the three of them have a

common point. Which is its name? c) Check that the barycentre in every median is at a distance of the

vertex double than the one it has to the midpoint of the side.

Exercise 6 Draw in your notebook each of these triangles and find the

asked point.

Triangle DATA (lengths in cm) POINT

ABC a = 5 cm, b = 3 cm, c = 6 cm Orthocentre

DEF d = 6 cm, º33E =

, º52F =∧

Barycentre

GHI h = 7 cm º53H =

º67I =∧

Incentre

JKL k = 4 cm, j = 6 cm º42L =

Circumcentre

MNO m = 8 cm n = 6.6 cm º62M =

Circumcentre

PQR p = 6 cm, q = 8 cm, r = 10 cm Orthocentre and circumcentre

4 The Pythagorean Theorem

In a right triangle one of the angles of the triangle measures 90 degrees. The

side opposite the right angle is called the hypotenuse. The two sides that

form the right angle are called the legs.

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In a right triangle the sum of the squares of the lengths of the legs equals the

square of the length of the hypotenuse. This is known as the Pythagorean

Theorem.

For the right triangle in the figure, the lengths of the legs are a and b, and the hypotenuse has length c. Using the Pythagorean Theorem, we can write that a2 + b2 = c2.

The acute angles of a right triangle are complementary.

Exercise 7 Find the value of the third side of the following right

triangles ABC in which º90A =∧

. Round the calculations to the nearest hundredth:

a) b = 7 cm, a = 9 cm.

b) b = 3 cm , c = 4 cm

c) a = 12.5 cm, c = 8.6 cm

d) a = 0.34 cm, c = 0. 27 cm

A

BC

a

b c

2

2

2

a

b

c

Pythagorean theorem

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5 Quadrilaterals A quadrilateral is a polygon with four sides. The four angles of any quadrilateral add up to 360º.

These are the special quadrilaterals

- Rectangle

All the angles are right angles. Opposite sides are equal. Diagonals have the same length and bisect each other.

- Square All the angles are of 90º All the sides are equal in length Diagonals have the same length and bisect each other at right angles.

- Rhombus

All the sides have the same length. Opposite sides are parallel. Opposite angles are equal. Diagonals bisect each other at right angles.

- Parallelogram or rhomboid

Opposite sides are parallel and have the same length. Opposite angles are equal. Diagonals have the same length and bisect each other.

- Trapezium (U.K.) or

Trapezoid (U.S.A.)

One pair of sides is parallel. The two sides that are parallel are called the bases of the trapezium.

In an isosceles trapezium the base angles are equal, and so is the pair of non-parallel sides.

Trapezium (U.K.)

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- Trapezoid (U.K.) or Trapezium (U.S.A.) Quadrilateral that has no parallel sides

- Kite It is a special type of trapezoid in which: The adjacent sides are equal. Diagonals intersect each other at right angles Exercise 8 One of the sides of a rectangle measures 4 cm and the diagonal 6 cm

a) Construct the rectangle. b) Calculate the other side and the perimeter.

Exercise 9 In a rectangle the length of its sides are 8.3 cm and 5.4 cm. Calculate the length of its diagonal.

Trapezoid (U.K.)

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Exercise 10 Construct a rhombus with diagonals 4 cm and 7 cm. Calculate the perimeter. Exercise 11 Construct a square with a diagonal of 7.5 cm. Calculate the perimeter. Exercise 12 Say how many axes of symmetry there are in:

a) A square

b) A rectangle

c) A rhombus

d) A trapezium

e) A pentagon

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f) An hexagon Exercise 13 Find all the missing sides and angles in the polygons below.

4 cm27 °

2 cm d = 5cm

l = 3 cm

61 °

AA

B

B

C

C

DD

h

A B

CD

124 °

6 cm

4 cm

2 cm

6 cm4 cm

67 °

128 °

A

B

C

D

51 °

116 °

2 cm1 cm

5 cm

3 cm

A

B

C

D

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6 Regular polygons

6.1 Definition and names

A regular polygon is a polygon in which all angles are equal and all sides have the same length.

Others polygons are called irregular polygons

Irregular hexagonRegular Hexagon

A five-sided polygon is a Pentagon A six-sided polygon is a Hexagon A seven-sided polygon is a Heptagon An eight-sided polygon is an Octagon A nine-sided polygon is a Nonagon A ten-sided polygon is a decagon With more than ten sides it is better to call them a polygon of “n“ sides.

6.2 Proprieties of the regular polygons

All the regular polygons can be circumscribed by a circle, this is called the circumcircle, and it is a circle which contains all the vertices of the polygon. The centre of this circle is called the circumcenter and it is the centre of the regular polygon. The radius of this circle is also the radius of the polygon.

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Apothem is the line drawn from the centre of the polygon perpendicular to a side. Example: In this hexagon O is the centre OP is the apothem OQ is the radius

Central angle is the angle formed with

two radiuses drawn in two consecutive

vertices, it is equal to 360º divided by

the number of sides

Exercise 14 Calculate the apothem of

this pentagon

O

P

Q

72 °

4 cm3 cm

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Exercise 15 Construct a regular hexagon with a radius of 3 cm.

Calculate the apothem and the central angle

7 Circle and circumference

7.1 Definitions - A circumference is the collection of points in a plane that are all at the same distance from a fixed point. The fixed point is called the centre. - A circle is the shape inside the circumference. - Circle is commonly used meaning circumference

7.2 Lines in a circle 1. Radius is the distance from the centre to the edge. (Segment OP) 2. Diameter is the segment between two points of the circle that passes through the centre. (Segment QR) 3. Chord is a straight line between two points of the circumference. (Segment CD) 4. Arc is a part of the circumference of a circle. (Curve CD) 5. Sector is the shape made by two radiuses (radii) of the circle. (OAB) 6. Segment is a shape made by a chord and an arc. (Curve CD and segment CD) 7. Tangent is a straight line that touches the circle at only one point. (TU)

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A tangent of a circle is always perpendicular to a correspondent radius 8. Secant is a line that intersects two points of a circle. (SU)

7.3 Positions of circles

- Concentric circles are circles, which have the same centre

- Eccentric circles have different centres.

- Interior circles are circles, one inside the other. They can be concentric or

eccentric circles.

- Exterior circles have their centres at a distance greater or equal to the

sum of their radiuses.

-Tangent circles have a common point. They can be interior or exterior

circles.

- Secant circles have two common points.

Exercise 16 Draw circles in your notebook in all the different positions

that you can see in 7.3

Exercise 17

a) Construct a circumference with a radius of 5 cm and a chord of

7cm.

b) b) Calculate the distance from the centre to the chord.

c) Draw two secants and one tangent to the circle.

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3-D shapes.

8 Polyhedrons

Polyhedrons are geometric solids whose faces are formed by polygons

Components:

- Faces are the polygons that bound the polyhedron

- Edges are the lines where two faces join.

- Vertices are the points where three or more edges meet

- Diagonal is a segment that joins two non-consecutive vertices

- Dihedron angle is the angle between two faces

8.1 Regular polyhedrons.

The regular polyhedrons have all their faces formed by identical regular

polygons. They are:

Tetrahedron: Four equal faces, each of them is a equilateral triangle

Cube: Six squares

Octahedron: Eight equilateral triangles

Dodecahedron: twelve regular pentagons

Icosahedron: Twenty equilateral triangles

8.2 Cuboids

A cuboid is a geometric objet with faces that are rectangles (in some cases

squares). The special case in which all the faces are squares is the cube.

Tetrahedron Cube Octahedron Dodecahedron Icosahedron

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They have 6 faces, 12 edges and 8 vertices

8.3 Prisms A prism is a polyhedron with two equal and parallel faces that are polygons (bases) and the other faces are parallelograms. The distance between the two bases is the height of the prism. Prisms can be right prisms when the parallelogram faces are perpendicular to the bases, otherwise they are oblique prisms. Depending on the polygons of the bases they can be: Triangular prism, with triangular bases Square prism, with square bases (these are also called cuboids or parallelepipeds), Pentagonal prism, when the bases are pentagons. Hexagonal prism, etc.

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Hexagonal prism 8.4 Pyramids A pyramid is a polyhedron in which one of its faces is any polygon called the base and the other faces are triangles that join in a point that is the apex. The height of a pyramid (h) is the distance from the base to the apex. Like the prisms, pyramids can also be right or oblique and depending on the polygons of the base they can be: triangular, square, pentagonal, hexagonal, etc.

Square pyramid

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8.5 Euler formula

The Euler formula relates the number of vertices V, edges E, and faces F of any polyhedron:

F + V = E + 2

Exercise18. Complete this table and check in each case that the Euler formula comes true.

NAME OF THE SOLID Number of faces Number of vertices Number of edges Cuboid Tetrahedron Cube Octahedron

Dodecahedron Triangular prism Pentagonal prism Hexagonal pyramid Octagonal pyramid

9 Solids of revolution

9.1 Cylinders

A cylinder is a curvilinear geometric solid formed by a curved surface with all the points at a fixed distance from a straight line that is the axis of the cylinder and by two circles perpendicular to the axis that are the bases.

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The height of a cylinder (h) is the distance from the base to the top. The pattern of the curved surface when it is unrolled is a rectangle The two bases are circles; the radius of the cylinder is the radii of the bases.

9.2 Cones

A cone is a solid bounded by a curved surface that has a common point (vertex), with a line that is the axis of the cone and a circle perpendicular to the axis that is called the base of the cone.

Vertex or apex is the top of the cone (V).

Generatrix of the cone is the straight line that joins the vertex with the circle of the base (g).

9.3 Sphere

A sphere is the solid bounded by a surface in which all points are at the same distance r from a fixed point that is the centre of the sphere C.

The distance from the centre to the surface of the sphere is called the radius of the sphere r

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Solutions

Exercise 1 Triangle By the sides By the angles Calculate ABC Scalene Acute triangle DEF Isosceles Acute triangle

HGI Equilateral Acute triangle º60H =∧

JKL Scalene Right triangle

MNO

Scalene Obtuse triangle º32N =∧

YAZ

Isosceles Right triangle º45Y =∧

º45Z =∧

BCD

Isosceles Acute triangle º50C =∧

º50D =∧

QPR Isosceles Obtuse triangle º120P =∧

SUT Isosceles Acute triangle

XVW Scalene Acute triangle º75X =∧

MKL Isosceles Obtuse triangle º100L =∧

NPO

Isosceles Acute triangle º75O =∧

GEF

Scalene Right triangle º90F =∧

QSR Equilateral Acute triangle º60R =∧

UTV Equilateral Acute triangle º60VTU∧∧∧

===

HIJ Scalene Right triangle º70I =∧

All exercises from 2 to 6 have to be drawn in class. Exercise 7 a) c = 5.66 cm, b) a = 5 cm, c) b = 9.07 cm, d) b = 0.21 cm. Exercise 8 side 4.47 cm, perimeter 16.9 cm. Exercise 9 diagonal 9.9 cm. Exercise 10 perimeter 16.12 cm. Exercise 11 perimeter 21.2 cm Exercise 12 a) 4, b) 2, c) 2, d)1 (if It is isosceles), e) 5 (regular pentagon)f) 6 (regular hexagon). Exercise 13 polygon 1. º27ADC =∠ ; polygon 2. º29DAC =∠ cm31.3D = ;

polygon 3. º56BCDBAD =∠=∠ , cm46.3h = , cm8DC = ; polygon 4.

º128A =∧

, º37B =∧

; polygon 5. cm6.3AB = , cm16.3CD = , º129ABC =∠ ,

º64D =∧

. Exercise 14 2.24 cm. Exercise 15 apothem 2.6 cm, central angle 60º.

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Exercise 16 It should be drawn during class. Exercise 17 b) cm57.3d = .

Exercise18. NAME faces vertices edges Cuboid 6 8 12 Tetrahedron 4 4 6 Cube 6 8 12 Octahedron 8 6 12 Dodecahedron 12 20 30

Triangular prism 5 6 9 Pentagonal prism 7 10 15 Hexagonal pyramid 8 12 18 Octagonal pyramid 9 9 16

In All solids faces + vertices = edges + 2 comes to be true.

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12 Areas

1 Area The area of a figure measures the size of the region enclosed by the figure.

This is expressed in one of the square units, square meters, square

centimetres, square inches, and so on.

2 Quadrilaterals

2.1 Area of a square

If ‘a’ is the length of the side of a square, the area is aa × or 2a .

Example:

What is the area of a square if the side-length is 7cm?

The area is 7x7 =49 cm2

2.2 Area of a rectangle

The area of a rectangle is the product of its width and length.

Example:

What is the area of a rectangle having a length of 12 m and a width of 3.2 m?

The area is the product of these two side-lengths, which is 12 × 3.2 = 38.4 m2

2.3 Area of a parallelogram

The area of a parallelogram is hb × , where b is the length of the base of the

parallelogram, and h is the perpendicular height. To picture this, consider the

parallelogram below:

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We can cut a triangle from one side and paste it to the other side to form a

rectangle with side-lengths b and h. the area of this rectangle is b × h.

Example:

What is the area of a parallelogram with a base of 82 mm and a

perpendicular height of 73 mm?

The area 2mm59867382A =×=

3 Area of a triangle Consider a triangle with base length b and height h.

The area of the triangle is hb2

1× .

b

h

b

h

b

h

The perpendicular height can be inside the triangle, one of its sides or

outside of the triangle as can be seen in the picture.

To demonstrate this formula, we could take a second triangle identical to the

first, then rotate it and "paste" it to the first triangle as pictured below:

b

h

b

h

The figure formed is a parallelogram with base length b and height h, and has

area hb × .

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This area is twice that the area of the triangle, so the area of the triangle is

hb2

Example:

What is the area of the triangle of the

picture on the right?

The area of a triangle is half the

product of its base and height, which

is 2cm24032152

1A =×=

Exercise 1 Calculate the area of these shapes

b = 32 cm

h = 15 cm

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4 Area of a rhombus The area of a rhombus can be calculated as the

area of a parallelogram as we have seen in point

2.3, but it can also be calculated if we know the

length of the diagonals.

The area of the rectangle is dD× , there are four

equal triangles inside and outside the rhombus, so

the area of the rhombus is 2

dDA

×= .

The perimeter of a rhombus is l4 if l is the length of each side.

Exercise 2 Calculate the area and the perimeter of a rhombus, whose

diagonals are of 6cm and 8 cm.

5 Area of a trapezium If a and b are the lengths of the two parallel bases of a trapezium, and h is its

height, the area is h2

baA ⋅

+= .

To demonstrate this, consider two identical trapezoids, and "turn" one around

and "paste" it to the other along one side as it is drawn below:

a

ab

b

h

h

a + b

b + a

d

D

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The figure formed is a parallelogram having an area of ( ) hbaA ⋅+= , which is

twice the area of one trapezium.

Example:

What is the area of a trapezium having bases 13 and 9 and a height of 6?

Using the formula for the area of a trapezoid, we see that the area is

6662

913=×

+ units of area

Exercise 3 Calculate the area of these shapes

2,9 cm

5,9 cm

2,5 cm

4,7 cm

3 cm

a) b)

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3,9 cm3,3 cm

2,5 cm

3,1 cm 4 cm

7 cm

2 cm

c) d)

4 cm

8.4 cm

3 cm

6 cm

6,0 cm

4 cm

e) f)

3 cm

5 cm

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6 Measures in regular polygons and circles

6.1 Area and perimeter of regular polygons All the regular polygons can be divided into n equal isosceles triangles and in any of these triangles the base is the side of the polygon (like QP) and the height is the apothem OR, the area of each triangle is

2

apothemesidepoligonA

×= so the area

of a regular polygon with n sides of length l and apothem a is.

2

apn

2

alA

×=

×= Where p is the

perimeter

Exercise 4 Calculate the apothem of

this pentagon and the its area

Measures in a circle

6.2 Area of a circle

4 cm3 cm

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The area of a circle is 2r×π , where r is the length of its radius. π is a number

that is approximately 3.14159.

Example:

What is the area of a circle having a radius

of 53 cm, to the nearest tenth of a square

cm? Using an approximation of 3.1415927

for π , and the fact that the area of a circle

is 2r×π , the area of this circle is

73.8824531415927.3 2=× square cm,

which is 8824.7 cm2 rounded to the nearest

tenth.

6.3 Length of a circumference

The length of a circle’s circumference is r2l ⋅= π

Example:

The length of the circumference of the previous circle using for π 3.14 is

cm4.1665314.3l =×=

6.4 Length of an arc of the circumference

The length of an arc of the circumference of n degrees is nr

l360

2π= because

there is a direct proportionality between the length of the arc and the

corresponding angle.

6.5 Area of a sector

There is also a direct proportionality between the area of a sector and the

corresponding angle, so n360

rA

2⋅

.

Exercise 5 Calculate the length or the arcs and the area of the shaded

part in the pictures.

r

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Exercise 6 Calculate the area of the shaded part in this logo.

Exercise 7 Calculate the area of the shaded part in these pictures.

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Solutions

Exercise 1 a) 2cm19.9 , b) 2cm59.9 , c) 2cm13.4 , d) 2cm43.12 ,

e) 2cm11.11 , f) 2cm48.10 .

Exercise 2 2cm24

Exercise 3 a) 2cm11 , b) 2cm05.7 , c) 2cm16.20 , d) 2cm21 , e) 2cm16 , f) 2cm6.45 .

Exercise 4 Apothem cm24.2 , area 2cm36.22

Exercise 5 Left picture: Arc L = 11.73 cm, Area = 70.37 cm2. Right picture

Arcs L = 15.71 cm, l= 11.52 cm, Area 2cm45.5436.638.117A =−= .

Exercise 6 2cm24.19A =

Exercise 7 Picture 1: 2

circles cm34.35A = , shaded area 2cm16.47A = .

Picture 2: Square area 2sq cm169A = , circle area 2

c cm73.132A = , shaded

area 2cm13.18A =

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12 Areas

1 Area The area of a figure measures the size of the region enclosed by the figure.

This is expressed in one of the square units, square meters, square

centimetres, square inches, and so on.

2 Quadrilaterals

2.1 Area of a square

If ‘a’ is the length of the side of a square, the area is aa × or 2a .

Example:

What is the area of a square if the side-length is 7cm?

The area is 7x7 =49 cm2

2.2 Area of a rectangle

The area of a rectangle is the product of its width and length.

Example:

What is the area of a rectangle having a length of 12 m and a width of 3.2 m?

The area is the product of these two side-lengths, which is 12 × 3.2 = 38.4 m2

2.3 Area of a parallelogram

The area of a parallelogram is hb × , where b is the length of the base of the

parallelogram, and h is the perpendicular height. To picture this, consider the

parallelogram below:

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We can cut a triangle from one side and paste it to the other side to form a

rectangle with side-lengths b and h. the area of this rectangle is b × h.

Example:

What is the area of a parallelogram with a base of 82 mm and a

perpendicular height of 73 mm?

The area 2mm59867382A =×=

3 Area of a triangle Consider a triangle with base length b and height h.

The area of the triangle is hb2

1× .

b

h

b

h

b

h

The perpendicular height can be inside the triangle, one of its sides or

outside of the triangle as can be seen in the picture.

To demonstrate this formula, we could take a second triangle identical to the

first, then rotate it and "paste" it to the first triangle as pictured below:

b

h

b

h

The figure formed is a parallelogram with base length b and height h, and has

area hb × .

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This area is twice that the area of the triangle, so the area of the triangle is

hb2

Example:

What is the area of the triangle of the

picture on the right?

The area of a triangle is half the

product of its base and height, which

is 2cm24032152

1A =×=

Exercise 1 Calculate the area of these shapes

b = 32 cm

h = 15 cm

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4 Area of a rhombus The area of a rhombus can be calculated as the

area of a parallelogram as we have seen in point

2.3, but it can also be calculated if we know the

length of the diagonals.

The area of the rectangle is dD× , there are four

equal triangles inside and outside the rhombus, so

the area of the rhombus is 2

dDA

×= .

The perimeter of a rhombus is l4 if l is the length of each side.

Exercise 2 Calculate the area and the perimeter of a rhombus, whose

diagonals are of 6cm and 8 cm.

5 Area of a trapezium If a and b are the lengths of the two parallel bases of a trapezium, and h is its

height, the area is h2

baA ⋅

+= .

To demonstrate this, consider two identical trapezoids, and "turn" one around

and "paste" it to the other along one side as it is drawn below:

a

ab

b

h

h

a + b

b + a

d

D

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The figure formed is a parallelogram having an area of ( ) hbaA ⋅+= , which is

twice the area of one trapezium.

Example:

What is the area of a trapezium having bases 13 and 9 and a height of 6?

Using the formula for the area of a trapezoid, we see that the area is

6662

913=×

+ units of area

Exercise 3 Calculate the area of these shapes

2,9 cm

5,9 cm

2,5 cm

4,7 cm

3 cm

a) b)

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3,9 cm3,3 cm

2,5 cm

3,1 cm 4 cm

7 cm

2 cm

c) d)

4 cm

8.4 cm

3 cm

6 cm

6,0 cm

4 cm

e) f)

3 cm

5 cm

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6 Measures in regular polygons and circles

6.1 Area and perimeter of regular polygons All the regular polygons can be divided into n equal isosceles triangles and in any of these triangles the base is the side of the polygon (like QP) and the height is the apothem OR, the area of each triangle is

2

apothemesidepoligonA

×= so the area

of a regular polygon with n sides of length l and apothem a is.

2

apn

2

alA

×=

×= Where p is the

perimeter

Exercise 4 Calculate the apothem of

this pentagon and the its area

Measures in a circle

6.2 Area of a circle

4 cm3 cm

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The area of a circle is 2r×π , where r is the length of its radius. π is a number

that is approximately 3.14159.

Example:

What is the area of a circle having a radius

of 53 cm, to the nearest tenth of a square

cm? Using an approximation of 3.1415927

for π , and the fact that the area of a circle

is 2r×π , the area of this circle is

73.8824531415927.3 2=× square cm,

which is 8824.7 cm2 rounded to the nearest

tenth.

6.3 Length of a circumference

The length of a circle’s circumference is r2l ⋅= π

Example:

The length of the circumference of the previous circle using for π 3.14 is

cm4.1665314.3l =×=

6.4 Length of an arc of the circumference

The length of an arc of the circumference of n degrees is nr

l360

2π= because

there is a direct proportionality between the length of the arc and the

corresponding angle.

6.5 Area of a sector

There is also a direct proportionality between the area of a sector and the

corresponding angle, so n360

rA

2⋅

.

Exercise 5 Calculate the length or the arcs and the area of the shaded

part in the pictures.

r

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Exercise 6 Calculate the area of the shaded part in this logo.

Exercise 7 Calculate the area of the shaded part in these pictures.

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Solutions

Exercise 1 a) 2cm19.9 , b) 2cm59.9 , c) 2cm13.4 , d) 2cm43.12 ,

e) 2cm11.11 , f) 2cm48.10 .

Exercise 2 2cm24

Exercise 3 a) 2cm11 , b) 2cm05.7 , c) 2cm16.20 , d) 2cm21 , e) 2cm16 , f) 2cm6.45 .

Exercise 4 Apothem cm24.2 , area 2cm36.22

Exercise 5 Left picture: Arc L = 11.73 cm, Area = 70.37 cm2. Right picture

Arcs L = 15.71 cm, l= 11.52 cm, Area 2cm45.5436.638.117A =−= .

Exercise 6 2cm24.19A =

Exercise 7 Picture 1: 2

circles cm34.35A = , shaded area 2cm16.47A = .

Picture 2: Square area 2sq cm169A = , circle area 2

c cm73.132A = , shaded

area 2cm13.18A =

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13 Graphs Previous ideas

The number line

Numbers can be represented on a line in this way 1. Draw a line. 2. Choose a point for zero. 3. Positive numbers are drawn to the right, negatives to the left.

Decimal numbers can also be placed on the line

Example 1 Place approximately on the number line the following numbers a) 1.5 b) 2.8 c) - 5.3 d) - 3.7

1 Graphs How to plot points on a plane To represent points in a plane we use two perpendicular number lines.

The horizontal line is called the x-axis (positives numbers to the right and

negatives to the left).

The vertical line is called the y-axis (positive numbers up and negatives down).

The common point of the two lines is called the origin O

For plotting a point we need an ordered pair of numbers, be careful! The order

in which the couple is written is important.

The firs number of the pair is the x-coordinate (abscissa).

The second one is the y-coordinate (ordinate).

Example 2 Plot the numbers A(2,5) B(5,3) and C(1,3.5)

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Example 3 Plot the numbers A(-2,-3) B(5,-7) and C(-4,4) and D(5,-3.5)

1

1

O

A(-2,-3)

B(5,-7)

C(-4,4)

D(5,-3.5)

Exercises

Exercise 1 In the graph data is plotted about the height and weight of a group of students, where x is the height in cm and y is the weight in kg of each one. Answer these questions.

a) Who is the tallest and how tall is she/he.

b) Who is the heaviest and what is his/her weight.

c) How much heavier is Antonio than Alex?

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d) Who are taller than Vanessa and who are shorter?

e) In this case, is it true that the taller people are generally heavier?

This is a scatter graph

Exercise 2

a) Write the coordinates of A, B, C, D, E, F, and G

b) Which two points have the same x-coordinate?

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13-4

c) Which two points have the same y-coordinate? d) Which points have the same x and y coordinates? e) Plot a point P which has the same x coordinate as C and the same y

coordinate as A.

f) Plot a point, which has the same coordinates as B but in the opposite order.

Exercise 3

a) Plot the points A(-2,-2); B(0,0); C(4,4) and D(5.5,5.5). b) Draw the line that joins all of them.

c) Plot P(5,7) and P’(7,5). What can you see?

d) Plot Q(-2,4) and Q’(4,-2). What can you see?

The points P’ and Q’ are the images of the points P and Q under reflection of the symmetric line drawn in b).

e) Plot the points R(-4,-1) and the symmetric R’ f) Plot the points S(5,2) and the symmetric S’

Exercise 4 Draw a grid. Join these points in the order they appear.

1. (2,2); (2,10); (9,10); (9,2); (2,2) 2. (3,7); (3,8); (4,8); (4,7); (3,7) 3. (7,7); (7,8); (8,8); ((8,7); (7,7) 4. (5,5); (5,7); (6,7); (6,5); (5,5) 5. (4,3); (4,4); (7,4); (7,3); (4,3)

Exercise 5 Write a set of instructions to a friend to see if she/he can write the school initials displayed on the grid.

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Exercise 6 Write the coordinates of the points that are plotted on the Cartesian diagram.

Exercise 7 For each plotting draw a new coordinate diagram 7.1 Plot the points, join them in order and name the shapes

a) (2,2); (2,5); (6,5); (6,2); (2,2) b) (2,6); (4,4); (7,7); (2,6)

7.2 Write down the coordinates of the missing point and name the shape. (1,2); (2,5); (5,4); ( , ) 7.3 Write down the coordinates of the missing points the shape is ABCDEFGH its opposite angles are the same, but the sides are not all of the same length. A(0,0); B(-2,2); C(-2,4); D(0,6); E(3,6)... Exercise 8 Look at the map of this small island and:

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a) Write the coordinates of every important place in the island. b) Can Peter walk in a straight line from coordinates (-7,-4) to the shop?

c) Tom is on Sun beach, he travels 3.5 km north and 2 km east. Where is

he now?

2 Graph of a function 2.1 Definitions. Graphs describe relationships between two different quantities; from this relationship we can build up a set of pairs and draw a graph. Example 4 Tomatoes are sold at €1.5 per kg, we can plot a graph showing the cost depending on the number of kg bought like this:

You can see that all the points are on a line These magnitudes are directly proportional, when one doubles the second will be doubled also. In general graphs describe the relationship between two variables x and y x is the independent variable (in the example kg of tomatoes). y is the dependent variable (in the example price of the purchase). We see that y depends on x Notice that for each x-value, there is one and only one possible y-value. This is important! Sometimes it is easy to describe the relationship by a formula in the example the formula is y = 1.5·x

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2.1 Conversion graphs. They are used to convert between different units of a magnitude. Example 5 converting miles into km and vice versa. We know that 1 mile is approximately 1.609 km and they are directly proportional. We can draw a graph and use it to convert between these units. It is useful using a drawing triangle.

From the graph you can see that 2.5 miles is about 4 km, 3.6 km are about 2.2 miles or 3 km are approximately 1.9 miles. Can you convert three different lengths in km into miles and three more from miles into km? Exercises Exercise 9 If in U.K. is the same as km/h in Europe

a) Draw a line graph for the conversion between mph and km/h b) Use the graph to complete the tables:

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Exercise 10 Draw a graph to convert € into $ and vice versa. (Use the conversion rate of €10 = 14 $). Use the graph to convert approximately to the other unit of money: a) $12 b) €12 c) $20 d) €7 e) $16

Speed limit mph In U.K.

Speed limit in km/h In Europe

Speed limit in km/h In Europe

Speed limit mph In U.K.

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Exercise 11 There are two main temperature scales, Fahrenheit which is very common in U.S. and Celsius. These are the data related to the freezing and boiling temperatures of the water.

Freezing point Boiling point Celsius 0ºC 100ºC Fahrenheit 32ºF 212ºF

a) Draw a graph line through the two points given. b) Use it to convert these temperatures into the other scale. 150ºF 70ºF 90ºF 100ºF 40ºF 15ºC 25ºC 37ºC 40ºC 60C Exercise 12 The graph below describes the time required to defrost a piece of meat in a microwave oven depending of the weight. How long is needed to defrost pieces of meat of: a) 200g b) 600g c) 0.5 kg d) 300 g e) 1kg and 200g What mass of meat can be defrosted in: a) 8min b) 15min c) 1/2h

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How much longer it takes to defrost 300g than 350g of meat? Exercise 13 This is the height of Wendy recorded every year since she was 4

a) How tall was Wendy at 7?

b) How old was she when she reached 132 cm?

c) Between which years she grow faster?

Exercise 14 In this graph we plot the distance travelled by Jane on her way to the school. Describe the journey.

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Exercise 15 The distance from Paul’s house to the school is on the graph. Describe his way to school.

3. Handling with data. When we need to analyse data they must be collected and organized in a table. Data can be categorical or numerical.

Examples of categorical data are: colour, kind of music, foods, our favourite subject… Numerical data can be discrete or continuous. Examples of numerical discrete data are: size of shoes, number of brothers and sisters… Examples of numerical continuous data are: height, measures of length, … Exercise 16 Classify as categorical, numerical discrete or numerical continuous the following.

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Weight, length of words, favourite sport, number of leaves of a plant, a house number, time practising a sport, favourite TV program, calories of different foods, mark in the last test of maths. Think of some other types of data on your own and classify them.

3.1 Organising data. Frequency tables It is advisable to follow these steps.

1. Collect data. 2. Organise data and display them in a frequency table.

3. Draw a graph.

Example 6 30 students have been asked about the number of brothers and sisters they are in their families. These are the answers: 1. Collect data: 1, 2, 1, 3, 6, 3, 2, 1, 1, 1, 2, 2, 3, 2, 3, 2, 2, 4, 2, 3, 3, 2, 2, 3, 4, 2, 2, 3, 1, and 2. 2. Organise data into a frequency table:

Number of B/S Tally Frequency 1 IIIII I 6 2 IIIII IIIII III 13

3 IIIII III 8 4 II 2 5 0 6 I 1

Then a bar chart can be drawn with this information.

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Brothers and sisters

0

2

4

6

8

10

12

14

1 2 3 4 5 6

number

freq

uen

cy

frequency

There are other types of graphs for example a pie chart; in this we draw sectors that represent the proportion in each category. Example 7 Using the same data from the previous example we can organize them in this way:

Type of family Frequency One child 6 Two children 13 Large family 11

If 30 people is 360º, that is the full circle 6 people would be x and:

º7230

3606x =

⋅= , and repeating for the rest of data we get:

Type of family Frequency Degrees One child 6 72º Two children 13 156º Large family 11 132º

Total 30 360º

A formula can be used: dataTotal

360frequencyAngle

⋅=

Sectors might be labelled.

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Brothers and sisters

6

13

11One child

Two children

Large family

Another type of graph is the pictogram. Example 8 Using the same data from the example 6 we would have:

Number of brothers and sisters Frequency 1 6 2 13

3 8 4 2 5 0 6 1

And a pictogram:

1

2

3

4

5

6

Frequency

Bro

the

rs a

nd s

iste

rs

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Exercises Exercise 17 Copy and organize in a frequency table the number of vowels in these texts.

- “Pure mathematics is in its way, the poetry of logical ideas”. (Einstein).

- “The laws of Nature are but the mathematical thoughts of God”. (Euclid’s).

Draw a frequency chart and a pie chart with the data. Translate the two sentences into Spanish and do the same as above.

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Exercise 18 Roll a dice 30 times and record the scores Organize the data in a table Draw a bar chart Which is the most frequent score? Is that what you expected? How could you improve the reliability of the experiment? Exercise 19 The results for the best British band survey in a high school are represented in this pictogram

Coldplay

Muse

Kaiser Chiefs

Arctic Monkeys

Radiohead

Where represents 100 votes

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Organize the data in a table Draw a pie chart Exercise 20 The marks in a test of mathematics have been: 2 3 8 7 7 3 9 5 5 4 1 6 5 7 6 6 5 8 7 3 4 5 6 5 4 6 7 7 9 8 Organize the data in a frequency table Draw a bar chart

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Draw a pie chart organizing the data as IN, SF, B, NT, SB

Exercise 21 In a survey, a group of 80 people were asked which kind of films they liked the most. The answers are represented in this pie chart.

film preferences

51%

20%

29%

Adventures

Romantic

Horror

How many people like each kind of film? Organize the data into a frequency table Draw a bar chart

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Which of the two graphs is the best for describing the data?

Exercise 22 This is the 24-hr average temperature of 118 months between 1981 and 1990 recorded in the Weather station ALBACETE/LOS LLANOS

Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec Year

°C 5.1 6.5 9.5 11.4 15.3 20.9 24.5 23.9 20.8 14.8 9.8 6.3 14.2

°F 41.2 43.7 49.1 52.5 59.5 69.6 76.1 75.0 69.4 58.6 49.6 43.3 57.6

Draw a bar chart with the temperatures in ºC Draw a line graph with the temperatures in ºF What can be seen in both graphs?

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Solutions Exercise 1 a) Juan and Carmen, both are 155 cm, b) Juan weights 60 kg, c) Both have the same weight, d) Juan and Carmen are taller than Vanessa, Stella, Alex and Antonio are all shorter, e) No. Exercise 2 a) A(2,2); B(2,7); C(-4,4); D(-2,-2); E(7,-3); F(10,0), and G(0,10) b) A and B, c) D and E, d) A and D e) f)

Exercise 3 Exercise 4

Exercise 5 a. (2,2); (2,7); (6,7); (6,2); (5,2); (5,4); (4,4); (4,2); (2,2). b. (3,5); (3,6); (5,6); (5,5); (3,5). c. (8,7); (9,7); (10.5,3); (12,7); (13,7); (11,2); (10,2); (8,7). Exercise 6 A(1.5,2); B(2.5,0.75); C(0,1.75); D(-2,-0.5); E(-0.75,3) Exercise 7.1 7.2 7.3

Exercise 8 a) Cape Storm (13,8) , Hotel (2,4), Post Office (7,4), Tennis court (-4,2), Café (4,0), Sun beach (-2,-3), Shop (2,-6); b) No; c) In the hotel. Exercise 9 a)

b) 30 mph = 48 km/h, 40 mph = 64 km/h, 70 mph = 112 km/h, 40 km/h = 25 mph, 90 km/h = 56.5 mph, 120 km/h = 75 mph

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Exercise 10

b) $12 = €8.5 b) €12 = 16.9$ c) $20 = €14 d) €7 = $10 e) $16 = €11.5

Exercise 11 b) 150ºF= 66ºC, 70ºF = 22ºC, 90º F = 32ºC, 100º F = 37ºC, 40º F = 5ºC 15ºC = 58º F, 25ºC = 73º F, 37ºC = 98º F, 40ºC = 104º F, 60ºC = 140ºF

Exercise 12 a) 200 g = 4 min, b) 600 g = 12 min, c) 0.5 kg = 10 min, d) 300 g = 6 min e) 1 kg and 200 g = 23.5 min a) 8 min = 40 g, b) 15 min = 750 g, c) 1/2 h = 1.5 kg 1 min more. Exercise 13 a) 120 cm, b) She was10 years old, c) Between 7 and 8 Exercise 14 O-A She travelled at a constant speed for 12 min and covered 400 m. A-B She stopped for 8 min. B-C She ran faster and travelled 500 m in 8 min. C-D She travelled slowly and got over 300m in 12 min. D-E She travelled even more slowly and covered the last 200 m in 20 min In total she travelled 1400 m in 1 hour Exercise 15 1. He walked for 8 min and got over 500 m 2. He stopped for 6 min or walked in a circle in which the house was the centre. 3. He went back home for 8 min and got 200 m closer to his house. 4. He walked at a constant speed for 10 min and arrived at the school that is 1400 m from his house and lasted 30 min in total. Exercise 16 Categorical Numerical discrete Numerical continuous favourite sport length of words Weight

Favourite TV program house’s number number of leaves of a plant

mark in the last test of maths time practising a sport

calories of different foods Exercise 17

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- “Pure mathematics is in its way, the poetry of logical ideas”. (Einstein). - “The laws of Nature are but the mathematical thoughts of God”. (Euclides).

Translation: - Las matemáticas puras son a su manera la poesía de las ideas lógicas. - Las leyes de la Naturaleza no son sino los pensamientos matemáticoss de

Dios. Exercise 18 (It depends on the occurrence) Exercise 19

English

Letter Frequency

a 11

e 10

i 7

o 7

u 4

Spanish

Letter Frequency

a 21

e 13

i 8

o 10

u 3

Band Frequency

Coldplay 400

Muse 250

Kaiser Chiefs 200

Arctic Monkeys 150

Radiohead 100

Vowels in English

0

2

4

6

8

10

12

a e i o u

f requency

Vowels in English

28%

26%18%

18%

10%

a

e

i

o

u

Vow els in Spanish

0

5

10

15

20

25

a e i o u

f requency

Vowels in Spanish

38%

24%

15%

18%

5%

a

e

i

o

u

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Exercise 20

Mathematics

0

1

2

3

4

5

6

7

1 2 3 4 5 6 7 8 9

Number of pupils

M athemat ics

IN

27%

SF

20%B

17%

NT

29%

SB

7%IN

SF

B

NT

SB

Exercise 21 Adventures 23 Romantic 41 Horror 16

Film preferences

23

41

16

0

10

20

30

40

50

Adventures Romantic Horror

Film preferences

Pie chart is better to compare with the total

Exercise 22

Both graphs are similar because they show exactly the same phenomena.

Marks Frequency

1 1

2 1

3 3

4 3

5 6

6 5

7 6

8 3

9 2

Film Frequency

Adventures 23

Romantic 41

Horror 16

A lbacet e

0

5

10

15

20

25

30

Temperat ue ºC

Albacete

0

10

20

30

40

50

60

70

80

Jan

Feb Mar

AprM

ayJu

nJu

lAug Sep O

ctNov

Dec

Year

Temperature ºF

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