Can Bang Dinh Luong Cua Nha May Sx Xi Mang Diendandaihoc.vn 04530817112011

8/2/2019 Can Bang Dinh Luong Cua Nha May Sx Xi Mang Diendandaihoc.vn 04530817112011

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GII THIU VBIU KHIN PLC

1

Vi ti Nghin cu h thng cn bngnh lng

trong nh my sn xut xi mng l ng.

Chng 1TNG QUAN V CNG TY XI MNG TIN SN H TY

1.1.Gii thiu slc v cng ty:

Cng ty xi mng Tin Sn tin thn l nh my vi , nm 1995 c s quan

tm cho ca ng v Nh nc, nh my u t xy xng mt dy chuyn sn

xut xi mng c cng 25Tn/h v a vo hot ng t nm 1996,thit b v dy chuyn

cng ngh ban u c nhp khu hon ton ca Trung Quc,vi tng gi tru t

ban u l 39 tng.Sau gn 10 nm hot ng sn xut cho ti nay nh my c

nhiu thay i sa cha nng cp thit b cng nh dy chuyn cng ngh,nhm nng

cao hiu qu kinh t trong qu trnh sn xut, c bit l kt hp cng vi trng i

Hc Cng Nghip Thi Nguyn thit k ci tin v thay th mt s thit b ca dy

chuyn cn bng nh lng.

Vi i ng CBCNV giu kinh nghim a nh my hot ng ngy cng pht trin

i ln,c hiu qu kinh t cao lun t danh hiu l n vi u cho ngnh xi mng

trong khu vc.vi ccu sp xp t chc cn b hp l khng nhng a nh my

hot ng c hiu qu kinh t cao m cn xng danh l n v vng mnh trong cng

tc t chc cng on v on TN ca khu vc.Vi a hnh nh my c xy dng

trn vng t ca x Hng Quang - huyn ng Ho tnh H Ty,khu sn xut t st vi


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2

ni thun tin cho vic khai thc nguyn liu, vn phng lm vic ca cng ty c

xy dng cch nh my sn xut khong 500m,thun tin cho vic qun l v theo di

x l kp thi nhng vng mc trong qu trnh sn xut, tin cho vic giao dch v

tiu th sn phm cng ty xy dng tt c 3 vn phng i din trn a bn cc

huyn v tnh ln cn trong khu vc.Vi phng chm phn u sn xut v tiu th

150.000 tn xi mng trn nm, trong nhiu nm nh my phi hot ng lin tc ht

cng sut hon thnh mi ch tiu ra, trong thi gian gn y sn phm xi mng

ca nh my sn xut ra khng cung cp cho th trng trong tnh v trong nc,

hng ti cng ty mun u t nng cng sut sn xut ca nh my ln nhm m bo

sn lng cung cp cho th trng tiu th trong nc c bit l th trng trong

tnh H Ty v mt s tnh ln cn.1.2 Tm hiu v t chc hot ng ca cng ty :

c bit cng ty hot ng sn xut c hiu qu, sn phm sn xut ra c

ngi tiu dng a chung l nhc b my lnh o tt, kt hp vi vic b tr sp

xp cng vic hp l cho tng CBCNV . Qua tm hiu c bit s t chc ca cng

ty nh sau : (Hnh 1.1)


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3

Hnh 1.1 S tchc cng ty xi mng Tin Sn

1.3.Quy trnh cng ngh sn xut xi mng - Nh my xi mng Tin Sn:

Vi thit k quy trnh cng ngh gm hai dy chuyn hot ng song song vi

nhau nh my sn xut rt c hiu qu, trnh c vic lng ph thi gian v nguyn

vt liu trong qu trnh sn xut, kt hp vi vic ci to thay th mt s thit b trong

dy chuyn, nn hin nay nh my thuc din mt trong nhng nh my sn xut xi

mng hin i ca nc ta. c bit l h thng cn bng nh lng, cng ty kt hp

vi trng i hc cng nghip - Thi Nguyn ci to v thay th h thng cn bng

nh lng, trc y s dng theo nguyn l cp liu rung, thay vo nay c lp

Gim cPh trach chung

P.Gim cVTVT(QMR)

P.Gim cPh trach SX

PHNGKTCN

BANISO

PHNGVTVT

PHNGTCHC

PHNGVTTK

PHNGKH

PHNGT.PHM

PXCiin

PXLiu

PXL

PXK.thc

PXT.phm


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4

t h thng cn cp liu tng iu khin bng bin tn, thit b hin i c m

phng trn my tnh. Di y l s khi dy chuyn sn xut xi mng ca nh my

xi mng Tin SnH Ty (Hnh 1.2):


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5

H20

L nung s 1+2

Kim tra

H20

Nghin liu s 1 + 2My ht bi

Phn ly s 1 + 2

Ht th

Kim tra

Si l 6,7,8My ht bi

ng nht B

Trn m 1+2

V vin 1+2

Kim tra

My ht bi

Kim tra Kim tra

Thch cao Ph gia

A

p,np


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6

Nhp kho

B

Si l 9,10,11 Si l 12,13My ht bi

Nghin xi s 3+4My ht bi

H thng cn bng nh lng s 3+4

Phn ly s 3+4

Ht th

Si l 14,15,16 My ht bing nht

ng bao

Kim tra D

Kim tra

Kim tra

Kim traKim tra


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Hnh 1.2 S khi dy chuyn cng ngh sn xut xi mng Cty xi mng Tin Sn

1.4. Thuyt minh s cng ngh:

1.4.1 Cngon chun bnguyn liu.

Nguyn liu sn xut xi mng ch yu l vi, ngoi ra cn c cc loi ph

gia khc nh than, t, qung st, thch cao. Vi iu kin thun li l nguyn liu

gn st nh my, sau khi c khai thc c h thng cc bng ti cao su vn

chuyn v ni tp kt v c phn loi ( vi en, vi xanh), kim tra cht lng.

t cht lng c kch thc gii hn l 350 mm.

t cht lng c a xung cc mng , t cc mng ny, c cc

bng ti xch tm a n cc my kp hm thc hin cng on p ln th

nht. Sau khi qua cc my kp hm ny th kch thc t kch thc gii hn l 80

mm. Sau khi qua cng on p ln 1, c h thng bng ti cao su a vo

my p ba thc hin cng on p ln 2. Qua khi cng on ny, nguyn

liu t kch thc 25 mm v c h thng gu ti xc ln vo cc xilo 1 v 2.

Cc loi ph gia khc th c a t cc ni v v tp kt kho cha ph gia.

qua cng on p nh, sy, sng phn loi c c kch cquy nh to iu kin

cho my nghin t nng sut sau c vo cc xilo 3v 4.

Ring ph gia thch cao th cng nh nguyn liu ( vi) c my kp

hm p nh ri c gu ti xc ln cha trong xilo 5.1.4.2 Cngon phi v nghin nguyn liu.

y l cng on quan trng, quyt nh cht lng sn phm ca cng ngh sn

xut xi mng l ng. m nhn cng on quan trng ny chnh l h thng cn bng

nh lng iu khin bng my vi tnh. H thng gm 06 b cn bng c t di

y cc xilo theo th t t cui bng ti chnh n ming my nghin l : 1, 2,

than, qung st, thch cao. Nhim v chnh ca cc cn bng p ng sn nh v lu

lng v iu khin lng nguyn liu cp ny sao cho ph hp vi yu cu cng ngh

t ra.Nguyn liu ty cc xilo c trt ln mt cc bng ti cn bng qua h thng

c p liu. Mi cn bng trong h thng nhn 1 nhim v khc nhau (vn chuyn cc

nguyn liu khc nhau vi 1 lu lng khc nhau) nhm mc ch khng ch v iu

chnh (tc bng) sao cho lu lng liu nhn c ng vi gi trt trc theo yu

cu cng ngh sn xut vi sai s b hn hoc bng gi tr cho php.


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H thng 06 cn bng nh lng ny nguyn liu ln 1 bng ti cao su v

bng ti ny c nhim v vn chuyn nguyn liu ( c phi) vo my ngin bi

thc hin nghin thnh bt liu. Cc ht bt liu t tiu chun (v kch thc) sc

h thng gu ti xc ln vo c xilo cha, cc ht cha t (c mn > 10% trn

sng 4900 l/cm2 ) sc my phn ly a trli vo u my nghin nghin li.

T l phi liu theo nh mc sau:

1: t (29 37%)

2 : t (32 40%)

Qung st : 6%

Than : 16%

t st : 4%

Thch cao : 5%

1.4.3 Cngon nung luyn clinke.

y cng l 1 trong nhng cng on quyt nh cht lng ca sn phm. Bt

liu c ly ra v c ng nht bng h thng rt liu,sau qua h thng my trn

m t m 60% ri a vo my v vin kiu sng quay. Nhng vin liu c kch c

6 8 mm sc xung 1 bng ti cao su ri a vo h thng cp liu cho l

nung, cc vin liu c cp vo l bng cch ri u tng lp mt v c nung

nhit 1500

o

c sau c rt ra bng h thng my ghi x. Lc ny cc vin liu trthnh clinke v dnh vo nhau thnh tng tng c kch thc khong 80 100 mm.

H thng ghi x s x clinke nng ln bng ti xch tm t ngay di y l v cc tng

clinke c a vo my kp hm clinke p nh. Tu theo cht lng clinke tt hay

xu m c a vo cha trong cc xilo ring ( sau ny rt ra v phi vi cc lng

ph gia khc nhau.

1.4.4 Cngon nghin clinke thnh ximng thnh phm v ng bao xi mng.

Clinke sau khi c cc b phn chc nng kim tra cht lng, clinke c h

thng cn bng nh lng phi cng vi cc thnh phn m, thch cao, t php c,x bng theo mt t l nht nh, sau c h thng bng ti cao su a vo my

nghin bi. Sn phm sau my nghin chnh l xi mng thnh phm. Cc ht xi mng

cha t (c mn > 10% trn sng 4900 l/cm2 ) sc my phn ly a trli vo

u my nghin nghin li. Sn phm xi mng t cht lng c vo cc xilo

14, 15, 16. Sau khi ngui th c a vo my ng bao, thnh phm c ng

kho kt thc quy trnh sn xut.


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Chng 2M T H THNG IU KHIN CN BNG PHI LIU

2.1. Khi nim:

Cn bng nh lng l bao gm cc thit b ghp ni vi nhau m thnh, cn

bng nh lng ca nh my sn xut xi mng l cn nh lng bng ti, c dng

cho h thng cn lin tc (lin tc theo ch di hn lp li). Thc hin vic phi liu

mt cch lin tc theo t l yu cu cng nght ra.

Trong cc nh my sn xut cng nghip, cc dy chuyn sn xut xi mng, h

thng cn bng nh lng cn p ng sn nh v lu lng liu v iu khin

lng liu cho ph hp vi yu cu, chnh v n ng mt vai tr rt quan trng trong

vic iu phi v hoch nh sn xut, do n quyt nh vo cht lng sn phm,

gp phn vo s thnh cng ca cng ty.

Cn bng nh lng trong nh my sn xut xi mng l cn bng ti, n l thit b

cung cp kiu trng lng vt liu c chuyn trtrn bng ti m tc ca n ciu chnh nhn c lu lng vt liu ng vi gi tr do ngi vn hnh t trc.

2.2. Cu to ca cn bng nh lng :

1

3 6 7 8 94

10 2

5

Hnh 2.1: S cu to cn bngnh lng.


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Cu to ca cn bng nh lng gm cc phn sau:

1: Phu cp liu

2: Cm bin trng lng (Load Cell).3: Bng truyn.

4: Tang bng.

5: Bulng ckh.

6: Tang chng.

7: Hp s.

8: SenSoro tc .

9: ng ckhng ng b (c ni vi bin tn)

10: Cm bin v tr2.3. T bo cn o trng lng:

L thit bo trng lng trong h thng cn nh lng bao gm 2 loi t bo l

loi SFT (Smat Foree Tran Sduer) v t bo cn Tenzomet.

2.3.1. Nguyn l tbo cn sSFT:

Ti trng cn o

Ngng hnch

Dy rung

Giao thc truyn tin ni tip

Hnh 2.1: S tbo cn sSFT

B chuyn i

Cm binnhi t

B vi x lN

SS

N


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u o trng lng l ni t ti cn o, n truyn lc tc ng trc tip ca ti ln

mt y dn t trong t trng khng i. N lm thay i sc cng ca dy dn nn

dy dn b dao ng (b rung). S dao ng ca dy dn trong t trng sinh ra sc in

ng cm ng. Sc in ng ny c tc ng cht ch ln ti trng t trn u o.

u cm bin nhit xc nh nhit ca mi trng thc hin vic chnh nh

v cc phn t SFT ph thuc vo rt nhiu vng nhit .

B chuyn i : Chuyn i cc tn hiu o lng tu o thnh dng tn hiu s.

B x l : X l tt c cc tn hiu thu c v cc tn hiu ra bn ngoi theo phng

thc truyn tin ni tip.

Bng thng k mt s loi t bo

Ti nh mc 20kg 30kg 100kg 120kg 200kg 300kg

Ti cc i 30kg 45kg 150kg 180kg 300kg 450kg

Phm vi nhit cho php

-10 60oc -1060oc -1040oc -1060oc -1040oc -1060oc

Giao thc truyntin ni tip vibn ngoi

RS 422RS 485

RS 422RS 485

RS 422RS 485

RS 422RS 485

RS 422RS 485

RS 422RS485

Nng lng tiuth 1w 1w 1w 1w 1w 1w

Khong ghp ni 500m 500m 500m 500m 500m 500m

phn gii 3,4g 5g 0,0001% 0,0001% 0,0001% 0,0001%


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2.3.2. Nguyn l tbo cn Tenzomet:

R-R R +R

UN

R+R R-R

Ur

Hnh 2.2: S cu tbo cn Tezomet.

Nguyn l t bo cn Tenzomet da theo nguyn l cu in tr, trong gi trin

trca cc nhnh cu thay i bi ngoi lc tc ng ln cu. Do nu c mt ngun

cung cp khng i (UN=const) th hai ng cho kia ca cu ta thu c tn hiu thay

i theo ti trng t ln cu. Khi cu cn bng th in p ra Ur=0. Khi cu in tr

thay i vi gi trR th in p ra s thay i, lc ny in p ra c tnh theo cng

thc.

R( 2.1) Ur=UN *

RTrong : UN - in p ngun cp cho u o

Ur - in p ra ca u o

R - lng in trthay i bi lc ko trn u o

R - gi trin trban u ca mi nhnh cu.

vi R t l vi khi lng vt liu trn bng cn th thy tn hiu Ura l khuych i nn

sau gi tn hiu ny qua bin i A/D vo biu khin x l.


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Gi s cp cho u vo cu cn mt in p l UN=10v th c 100kg vt liu trn bng

LoadCell s chuyn thnh 2mv/v tng ng. Lc ny, in p ra ca cu cn s l

Ura=20mv

Bng thng k mt s t bo cn Tenzomet

Ti nh mc 20 30 50 70 100 150 250 300

Ti cc i 150% ti nh mc

Sai s < 0.015%

Phm vi iu chnh -10 40

Ngun cung c p -10 15

2.3.3. Chun b:

Sau khi chnh nh cm bin trng lng th tin hnh chun b cho cn bng cchthc hin chc nng (chun b tng ). Xc nh s trt ca bng trong lc tr b

bng ti rng, biu khin ghi vo b nhs phn on thc ca bng ti gia 2 ln

quay li ca thit bnh v (Belt in dex) v so snh vi phn on ghi trong b nh.

Nu c s sai khc tc l c s trt ca bng trn puly truyn ng v biu khin

s bo ng.

2.4. Nguyn l tnh lu lng ca cn bng nh lng:

2.4.1. Nguyn l tnh lu lng:Cn bng nh lng (cn bng ti) l thit b cung cp liu kiu trng lng.Vt

liu c chuyn trtrn bng ti, m tc ca bng ti c iu chnh nhn c

lu lng t trc khi c nhiu tc ng lin h(liu khng xung u).

Cu cn v cbn bao gm : Mt cm bin trng lng (LoadCell) gn trn gi

mang nhiu con ln. Trng lng ca vt liu trn bng c bn cm bin trng lng

(LoadCell) chuyn i thnh tn hiu in a v b x l tnh ton lu lng.

xc nh lu lng vt liu chuyn ti ni liu th phi xc nh ng thi

vn tc ca bng ti v trng lng ca vt liu trn 1 n v chiu di. Trong tc

ca bng ti c o bng cm bin tc c lin hng hc vi ng c.

Tc bng ti V (m/s) l tc ca vt liu c truyn ti. Ti ca bng truyn

l trng lng vt liu c truyn ti trn mt n v chiu di

(kg/m).


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Cn bng ti c b phn o trng lng o v biu khin iu chnh tc

bng ti sao cho im liu, lu lng dng chy liu bng gi trt do ngi vn

hnh t trc.

Biu khin o ti trng trn bng truyn v iu chnh tc bng m bo lu

lng khng i im liu.

(2.2) Q = * V

Trng lng tng trn bng l lc Fc(N) c o bi h thng cn trng lng v ,

c tnh theo biu thc:

(2.3) g

L

FC

2

=

trong : L - chiu di ca cu cng - gia tc trng trng (g=9,8 m/s2)

Lc hiu dng Fm(N) do trng lng ca vt liu trn bng ti gy nn:

(2.4) Fm =Fc F0

Trong : F0 l lc o trng lng ca bng ti c con ln v gi cu cn.

Ti trng trn bng truyn c th tnh l:

(2.5) = S * Trong : - khi lng ring ca vt liu (kg/m3)

S - tit din ct ngang ca vt liu trn bng (m2)

Do lu lng c th tnh l:

(2.6) Q =gL

VFc

gL

VFc

*

*2

2

*=

2.4.2.o trng lng liu trn bng ti:

Trng lng o nhtn hiu ca LoadCell bao gm trng lng ca bng ti v trng

lng vt liu trn bng. V vy o c trng lng ca liu th ta phi tin hnh tr

b (tc l tri trng lng ca bng ti ).

Biu khin xc nh trng lng ca liu nh tr b tng cc phn on bng

ti.


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* Nguyn l ca qu trnh tr b nh sau :

Bng ti phi c chia thnh cc phn on xc nh. Trong lc tr b bng ti rng

(khng c liu trn bng) trng lng ca mi on bng c ghi vo b nh. Khi vn

hnh bnh thng cn bng ti trng lng ca mi vt liu trn mi phn on c

xc nh bng cch ly trng lng o c trn on tri trng lng bng ti

tng ng ghi trong b nh. iu ny m bo cn chnh xc trng lng liu ngay

c khi dng bng ti c dy khng u trn chiu di ca n. Vic iu chnh trng

lng cn phi thc hin ng b vi v tr ca bng (belt index c gn trn bng)

mi bt u thc hin tr b. Khi ngng cn v tr ca bng ti c gi li trong b nh

do ln khi ng tip theo vic tr b c thc hin ngay.

2.5. Khi qut viu chnh cp liu cho cn bng:Vic iu chnh cp liu cho bng cn nh lng chnh l iu chnh lu lng liu

cp cho bng cn.

*Thc hin bng 3 phng php:

-Phng php 1: iu chnh cp liu kiu tri

Phng php ny iu chnh cp liu bng tn hiu ca sensr cp liu kiu tri iu

khin 5 thit b cp liu.

V tr ca sensr cp liu theo kiu tri c t pha cui ca ng liu.

- Phng php 2: iu chnh cp liu lin tc.

Phng php ny iu chnh cp liu lin tc cho bng cn nh lng s dng b

iu chnh PID iu chnh cp liu (c th l van cp liu hoc van quay) m bo

cho lng ti trn mt n v chiu di bng ti l khng i. B PID c tc dng iu

chnh nu lu lng th tch ca liu trn bng thay i theo phm vi 15% v b PID

ch hot ng sau khi bng hot ng.

* Nhn xt 2 phng php trn:

Hai phng php trn iu chnh cp liu khc hn nhau v bn cht. Xt v

chnh xc iu chnh th phng php 2 hn hn phng php 1, thi gian iu chnh

nh, thit b cp liu lm vic n nh khng b ngt qung, nhng phm vi iu chnh

khng rng. Phng php 1 n gin hn, phm vi iu khin rng hn v c th dc


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t bi ngi s dng, nhng trong phm vi iu chnh thit b phi lm vic gin on

th nh hng khng tt n tui th ca thit b.

- Phng php 3: iu chnh mc vt liu trong ngn xp:

Phng php iu chnh mc liu trong ngn x p c th coi l s kt hp ca 2

phng php trn : phng php iu chnh gin on v iu chnh lin tc. Phng

php ny tn dng nhng u im v khc phc nhng nhc im ca 2 phng php

trn v c thit kc bit cho cc bng cn nh lng.

2.6 Cu trc ca mt h cn:

2.6.1 Cu to chung ca h cn:

Hnh 2.3. S cu trc ca mt h thng

Cu to ca h thng bao gm:

1- Gm 06 h cn liu t 1 cho ti Thch cao .Cc cn ny c kch

thc: chiu di l 3910mm, rng 1250mm, cao 1150mm, chiu rng mt bng 650mm,

tc ca bng 0.51m/s, s cu to nhhnh 1.1, h truyn ng s

dng hai loi ng c l 1.5kw v 0.75kw, tc ca ng c truyn ng u l

: nd : 970 v/p

Hiu sut hp s : 2 : 0,8

T s truyn gia bng rng 1 v 2:

H cn2

H cn1

H cnthan

H cnqung

H cnt

H cnthch cao

Bng ti chnh


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i = 5,126

40=

2- Bng ti chnh.C thng s k thut nh sau:

- Chiu di tng th ca bng ti:

- Chiu rng :

- Chiu cao :

- Chiu rng mt bng :

- Cng sut ng ctruyn ng:

- Tc ng ctruyn ng :

- T s truyn ca hp s :

- Vn tc ca bng ti :

Cu trc ca mt h cn trn dy chuyn bao gm 06 h thng cn bng v mt bng ti

chnh, trong qu trnh lm vic 06 cn bng trn sng thi liu xung bng ti

chnh, ton b phi liu c bng ti chnh vn chuyn vo Sil trn a vo my

nghin.

Chng 3TNH TON LA CHN H THNG T CHO CN CP THAN

3.1. Hot ng ca cn bng:


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LoadCell Hp gim tc My pht tc cKB

AC

P

VHnh 3.1: S cu trc h thng cn bngnh lng.

Trong :ng cs dng l ng ckhng ng b ba pha r to lng sc, tc ca ng

co c nhsensro tc (my ft xung).

S xung pht ra t my pht xung t l vi tc ng cv c a v biu

khin.

Biu khin (dng vi x l) iu chnh tc ca bng ti v lu lng liu

im liu sao cho tng ng vi gi trt.

B cm bin trng lng (LoadCell) bin i trng lng nhn c trn bng

thnh tn hiu in a v b khuych i.

iu chnh tc ca ng cbng cch iu chnh tn s cp ngun cho ng c.

3.2. Hiu chnh tc ng ckhng ng b dng bin tn:

3.2.1. Khi qut vng ckhngng b:

MYFT

XUNG

BKHUYCHI

BIUKHIN

Nt FT M

BINTN


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ng ckhng ng b (KB) c kt cu n gin, d ch to vn hnh n gin an

ton, s dng trc tip t li in xoay chiu 3 pha nn ng cKB c s dng

rng ri trong cng nghip, t cng sut nhn cng sut trung bnh n chim t l ln

so vi ng c khc. Trc y do cc h thng truyn ng ng cKB c iu

chnh tc li chim t l nh do vic iu chnh tc ng cKB kh khn hn

nhiu so vi ng c1 chiu. Ngy nay do vic pht trin ca cng ngh ch to bn

dn cng sut v k thut tin hc. Nn ng cKB pht trin v dn c xu hng

thay thng c1 chiu trong cc h truyn ng.

Khc vi ng c1 chiu, ng cKB c cu to bi phn cm v phn ng

khng tch bit. T thng ng c cng nh mmen ng c sinh ra ph thuc vo

nhiu tham s. Do vy hiu chnh tng truyn ng in ng cKB l hiuchnh nhiu tham s c tnh phi tuyn mnh.

Phng trnh c tmh:

(3.1) M =**

*3 21s

RU

Trong :1- l tc gc ca t trng quay

(3.2) 1 =p

fn 1*2

vi f1 - l tn sin p ca Statorp - l si cc

U1- tr s hiu dng in p pha ca stator

R1- in trcun dy ca stator

R2- in trrotor quy i v stator

Xnm - in khng ngn mch

S - h s trt ca ng c

(3.3) S =1

1

vi - h s gc ca ng c

phng trnh trn cho ta thy M = f(s) ph thuc vo cc i lng U1,1,R2. Tng ng

vi cc i lng ta c 4 phng php iu chnh in p nh sau:

- Phng php iu chnh mch rotor.


20/107


20

- iu chnh in p Stator cp cho ng c.

- iu chnh cng sut trt

- iu chnh cng sut ngun cp cho ng c.

Phng php iu chnh in p stator v iu chnh Rotor p dng ch yu cho vic

iu khin ng cKB 3 pha rotor lng sc trc y rt kh thc hin. Ngy nay do

s pht trin mnh m ca in t cng sut v k thut vi s l mra c hiu qu

phng php iu khin ng cKB lng sc bng iu khin bin tn, phng php

ny cho php iu chnh tc ng ctrong phm vi rng vi chnh xc cao.

Tc ng cc tnh theo cng thc:

(3.4) n1=p

f1*60

T cng thc trn cho ta thy vic iu chnh ng cKB ph thuc vo s bin i

tn s li in. khi iu chnh tn s th tc ng ccng thay i theo.

Khi thay i tn s li in cng vi vic b qua in trdy qun stator, tc l coi

R1=0 th mmen ti hn t cc i :

(3.5)n

n

thX

U

Xn

UM

*2

3

*55.9

23

1

21

1

21

==

Trong :

(3.6) Xn = 1* Ln

(3.7) n

thLf

PUM

**)2(2

*32

12

221

=

t ==nL

Pa

*)2(2

32

2

const

(3.8) 2

1

213

f

UaMth =

Biu thc trn cho thy khi tng tn s ngun (f1> f1dm) m gi nguyn U1 th

momen ti hn cc i2

1

1~

fMth s gim rt nhiu. Do , khi thay i tn s f1 th nn

thay i ng thi cin p U1 theo mt quy lut nht nh m bo s lm vic

tng ng gia momen ng cv momen ph ti (hay trnh tnh trng ng cb qu


21/107


21

dng). Tc l t s gia momen cc i ca ng cv momen ph ti tnh i vi cc

c tnh cl hng s:

(3.9)M

Mth= =const

Trng hp tn s gim (f1< f1dm) nu gi nguyn in p U1 th momen v dng

in ng cs tng rt ln. Nn khi gim tn s th phi gim in p theo mt quy

lut nht nh sao cho ng c sinh ra c momen nh trong chnh mc.

c tnh ckhi f1< f1dm vi iu kin t thng = const (hoc gn ng gia1

1

f

U

= const th Mthc gi khng i vng f1< f1d

Hnh 3.2.c tnh ckhi thay i tn sng ckhngng b

3.2.2. M tng ckhngng b di dng cc i lng vect:

Khi iu chnh tn sKB, thng ko theo iu chnh cin p, dng in hoc

t thng mch stato, do tnh cht phc tp ca qu trnh in t trong KB, nn cc

phng trnh , biu thc phn tch khng s dng trc tip c cho trng hp iu

chnh tn s. thun tin cho vic kho st h thng iu chnh tn s, di y nu raphng php nh gi qu trnh in t di dg vect.

Trong ng cKB, t nht c 06 cun dy trn mach t, phng trnh cn bng

in p ca mi cun nh sau:

(3.10) uk= Rkik+dt

kd

0

14

13

1

12

11

f11

f12

f1 > f1m

f1m

F13

F14

f1 < f1m

M


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22

trong ch s k l tn ca dy qun.

Nu coi mch t l tuyn tnh v b qua tn hao st th mmen in t ca ng c

l:

(3.11) M = ik dtk

n gin trong khi vit, coi ng cc hai cc (p = 1) Xem hnh 3.1, trong

cc ch s bng ch thng a,b,c Ch cc dy qun pha stato, cc ch s bng ch in hoa

A,B,C Ch cc pha rto, gc lch gia dy qun rto v dy qun stato l v th tc s

l o hm ca gc ny.

(3.12) =dt

dT thng mc vng ca cc dy qun

(3.13) k= Lkjij,

trong j cng l ch s ca cc pha dy qun,

Khi j = k c t thng t cm,

j k c t thng h cm,

iu chnh tc ng cKB rto lng sc c nhiu phng php nh :

- iu chnh tc bng biu pha in p- iu chnh tc bng b bin tn ngun dng- iu chnh tc bng b bin tn ngun pDo c im ca cn bng ny l s dng ng c truyn ng c cng sut nh

di vi kw nn b bin i c dng y l bin tn tranzito,ngun p bin iu b

rng xung.

3.2.3.iu chnh tn sng cbng bin tn:Mun iu chnh tc ng cKB bng cch thay i tn s ta phi c mt b

ngun xoay chiu c thiu chnh tn sin p mt cch ng thi thng qua mt

bin tn.

to ra cc b bin tn c U v f thay i c ngi ta thit k ra nhiu loi

bin tn nhng trong n ny ta ch xt n b bin tn ngun p lm vic theo


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23

nguyn l iu bin rng xung (PWM - Pulse Width Modulation). B bin tn ny

p ng c yu cu iu chnh, ng thi n cn to ra c in p v dng in

gn ging hnh sin.

Hnh 3.3. S mch lc b bin tn ngun p dng Tranzitor

Dng phng php PWM ta c gin in th v in p pha A nh sau:

0 /2

3/2 2

0


24/107


24

Hnh 3.4 Phng php PWM

- S bin tn ba pha dng Tranzitor gm:

B nghch lu bin i in p mt chiu t ngun cp thnh in p xoay chiu

c tn s bin i c. in p xoay chiu qua b lc v a vo s cu Tranzitor.

S bin tn Tranzitor ba pha dng 6 Tranzitor cng sut T1T6 v 6 it T7

T12u song song ngc vi cc Tranzitor tng ng.Tn hiu iu khin Vbc a vo bazca Tranzitor c dng ch nht, chu k

l 2, rng l /2.

Khi Vb = 0 --> Tranzitor b kha

Vb = 1 --> Tranzitor mbo ha

Cc Tranzitorc iu khin theo trnh t 1,2,3,4,5,6,1...

Cc tn hiu iu khin lch nhau mt khong bng /3.

3.2.4. Lutiu chnh tn s- in p theo kh nng qu ti:

Khi iu chnh tn s th tr khng, t thng, dng in v.v ca ng cu

thay i, m bo mt s ch tiu iu chnh m khng lm ng cb qu nng th


25/107


25

cn phi iu chnh cin p . i vi h thng bin tn ngun p thng c yu cu

gi cho kh nng qu ti v mmen l khng i trong sut di iu chnh tc .

Mmen cc i m ng csinh ra c chnh l mmen ti hn Mth, kh nng qu ti

v mmen c quy nh bng h s qu ti mmen M.

(3.14) M =M

Mth

Hnh 3.5 Xcnh kh nng qu ti vmmen

Nu b qua in trca dy qun stato Rs = 0 th t biu thc mmen in t ca

ng c:

(3.15) M = M.Mth

C th tnh c mmen ti hn nh sau:

(3.16) Mth =LroLs

Lm

22

2

2

2

o

Us

= 2

o

UsK

iu kin gi h s qu ti khng i l:

(3.17) M =M

Mth=

Mdm

Mthdm

Thay th (3.16) vo (3.17) v rt gn ta c:

(3.3.18)

Us=

dm

Usdm

Mthdm

M

c tnh cgn ng ca cc my sn xut (ph ti) c th vit nh sau:

m

0m

0U,f

Mc() Mth Mth M


26/107


26

(3.19) Mc = Mm (dm

)x

32.5. B khuych i tn hiu:

B khuych i s khuych i cc tn hiu nhn c t t bo cn v a v b

iu khin. Tn hiu thu c l ti trng tc thi m t bo cn o c kt hp vi tn

hiu nhn c t my pht xung xc nh khong thi gian (khong thi gian tr)

m on bng i t t bo cn n im x.

Sau khong thi gian tr lu lng ti im x ca cn nh lng l kt qu ca tch

s gia lng ti trn mt n v chiu di ca bng (o c lc i qua t bo cn) vi

tc hin thi ca on bng .

Vic tnh ton v iu chnh sai lch gia lu lng t v lu lng thc do b

iu chnh P trong biu khin thc hin, b ny s khuych i v trit tiu sai lch

ch tnh. Tn hiu u ra ca b t l P c a n iu khin bin tn ng c

lm cho tc ca ng ctruyn ng bng ti thay i sao cho lu lng ti im x

liu tng ng vi lu lng t.

3.2.6. Thng skthut ca cn:

Di 3910mm

Rng 1250mm

Mt bng: 650mm

Cao 1150mm

Lu lng 40-60T/h

Tc ca bng: 0,5-1ms

3.2.7. Cu trc h thng cung cp in cho h cn:


27/107


27

Tng lc ca h cn c ly ngun t t phn phi T 1, trong tc b tr

gm 06 atmat 02 pha u vo n 06 bin tn iu khin tc ng c, u ra ca 06

bin tn c ni qua 06 atmat 03 pha n cc ng c.s nh(hnh 3.6).

3.3. Tnh chn cng sut ng ccho bng cn:


28/107


28

3.3.1. S cu trc h truyn ng:

Bnh rng 2Hp gim tc ng c

Bnh rng 1

Hnh 3.7: S cu trc h truyn ng

Cho bit cc thng s:

Tc ng c : nd : 970 v/p

Hiu sut hp s : 2 : 0,8

T s truyn gia bng rng 1 v 2

i = 5,126

40=

Tc ca bng truyn :V=1m/s

Tm tc gc ca ng c:

(3.20) d = 260

dn = =14,3*260

970 102,5 Rad/s

Tc ca bnh rng 2(tc ca puly chng) 2

(3.21) 2 =D

V

*= =

32,0*14,3

1 0,99Rad/s

Trong D l ng knh bnh rng 2 : D=0,32m

Tc ca bnh rng 1 : 1(3.22) 1 = i*2 = 1,5*0,99 =1,49 Rad/s

T s truyn ca hp s: i1

(3.23) i1 = 8,6849,1

5,102

1

==

d

T s truyn gia puly v ng c:

i1 n2 n


29/107


29

(3.24) i2 = 5,10399,0

5,102

2

==

d

2.3.2. Tnh chn cng sutng c:

(3.25) P1 = 211

*

*

VF

Trong 1 l hiu sut bng ti 1=0,8

F1 l lc ca trng lng tng trn bng

(3.26) F1= L*g*

L chiu di ca bng L=2,8m

(3.27) = mkgV

Q/6,16

1*3600

60==

g- gia tc trng trng g=9,8m/S

(3.28) F1= 2,8*9,8*16,6=455,6 N

(3.29) P1 = 8,7118,0*8,0

1*6,455= w

Vy ta chn cng sut cho ng cl 0,75k w

3.4. Tnh chn LoadCell:

Khi c ti chy trn bng th m men lc ca ti trng s c cn bng vi

mmen lc ca i trng v LoadCell.

F0 F2


30/107


30

l2

F1

L0 l1 LoadCell

Hnh 3.8: cu trc cu cn bng m men lc

Da vo cng thc tnh tng hp momen lc:

(3.30) F0L0 = F1L1 + F2L2

Trong : F0 l lc ca ti trng tc ng ln cu cn

F1 l lc ca LoadCell

F2 l lc ca i trng

L0 l khong cch (cnh tay n ) t ti n puly L0 =0,16m

l1 l khong cch (cnh tay n) t puly n LoadfCell l1=0,12m

l2 l khong cch (cnh tay n ) ti trng n puly, l2=0,20m

Suy ra ta c :(3.31) F0 =

0

222111

0

2211 ....

L

lamlam

L

LFLF +=

+

y LoadCell v trng c ni cng vi nhau nn coi a1=a2=1

(3.32) F0 =1

22001

0

2211 ....

l

lmLFm

L

lmlm =

+(*)

Trong : m1: L khi lng ca LoadCell

m2: L khi lng ca i trng chn loi 8kg

Nng sut ca bng l: 60T/h

tc truyn l: V=1m/p

khi vt liu c truyn ti trn 1 n v chiu di l

(3.33) = mkgV

Q/7,16

1*3600

60000==


31/107


31

Trng lng tng trn bng l lc F0(N) c o bi h thng cn trng lng v

c tnh theo biu thc:

(3.34) g

L

F

*

2

1

0=

trong L1 -chiu di ca cn

g - l gia tc trng trng

suy ra :

(3.35) F0= * gL

*2

1 thay vo phng trnh (* )

(3.36) M1= kgl

lmLogL

7412,0

20,0*816,0*8,9*2

8.07,16***

2*

1

221

=

=

3.5. Tnh chn bin tn:

T cng sut ng cta c c cng sut bin tn nh sau:

theo cng thc:

(3.37) Pbt = 1,5* Pdc = 1.5*0,75 = 1,12kw

Do c tnh ng cc cng sut nh,ti nh nn ta chn bin tn VF - S9 c cng

sut P = 0.75kW.Do hng Toshiba (Nht bn)sn xut.

Vi cc thng s sau:

+ in p : 400v

+ Tn s : 50 Hz

+ Dng in : 2,4A

3.6. Bin tn cng nghip TOSHIBA


32/107


32

3.6.1 S mch lc bin tn VF - S9. 0.75 kW

3.6.2. Chc nng cc cc ca mch iu khin

K u Chc nng Cc c Mch bn trong ca bin

Hnh 3.9 Mn hnh hin th vcc phm chc nng

MON

ENT

RUN

STOP

G S/TL1 S/TL2 S/TL3

VF - S9- -

U/T1 U/T2 U/T3

TOSHIBA

MCCBS/L1

T/L3

Blc Mch chnh U/T1

V/T2

ng cP0PA PB

Mch iukhinVF -S9

B phnkt ni

FMV Ngun

FMC

Rlepht

RC

RY

Tn hiu chobit tc thp

FL

FL

FL

R

TnP2

O

Tn hiu dng-

F

R

RST

S1

S2

S3

CC

CC

My +Tn hiu in p 0Nm phn th ngoi cc VIA v IIkhng c s dng ng thi cng

mt lc

PPVIACC VIBFM

PC

Bngiukhin

Hnh 3.10 Mch lc ca bin tn VF - S9


33/107


33

hiucc

vo/ra im vin

tn

F u vo Ngn mch qua F-CC lnguyn nhn quay, mhp gim tc v dng.

Khng c

in ptip imu vo24Vdc

5mAhoc nh

hn

+24v+5v

JB301

4.7K 10KF

15K

S3 0.1

3.9K

R u vo Ngn mch qua R-CC lnguyn nhn ng cquay theo chiu thun. Khimch h, ng c chmdn v dng hn.

RST u vo Ngn mch qua RST_CC.L nguyn nhn nh hngn vic iu chnh khichc nng bo v bin tn

ang hot ng. Ch rngkhi bin tn ang hot ng bnh thng th n khnghot ng u n nu cngn mch qua RST.

S1 u vo Ngn mch qua S1_CC lnguyn nhn tc ttrc hot ng

S2 u vo Ngn mch qua S2_CC l

nguyn nhn tc ttrc hot ng

S3 u vo Ngn mch qua S3_CC lnguyn nhn tc ttrc hot ng

CC imtrungtnh

Cc ng th ca mchiu khin.

PP u ra u vo tng t thit lp

u ra ngun.

10 Vdc

I u vo Nhiu chc nng chngtrnh c u vo l tn hiutng t. Tiu chun xclp mc nh u vo4~20mAdc v 0~50Hzhoc 0-60Hz

4~20mA(trkhngtrong:400)

VIA u vo Nhiu chc nng chng 10Vdc

Ngunbin tn

0.47 0.1

P

+24v

1K

0.115K150 250II

VIA 15K

+5v


34/107


34

trnh c u vo l tn hiutng t. Tiu chun xclp mc nh, u vo0~10vdc v 0-80Hz

(trkhngtrong:30)

VIB u vo Nhiu chc nng chngtrnh c u vo l tn hiutng t. Tiu chun xclp mc nh, u vo0~10vdc v 0-50Hz (60Hz)

10Vdc(trkhngtrong:30)

FM u ra Nhiu chc nng chngtrnh c tn hiu tng t.Tiu chun xc lp mcnh: u ra c mt dngc ni vi mt ampemet

c t l 1mA hoc volmeto in p 1 chiu 7.5Vdc(10Vdc) c th thay i t0~20mA bng cch nhychuyn mch JP302

CC imtrungtnh tiu vov u

ra

Cc ng th ca mchiu khin.

P24 u ra u ra ca dng 24Vdc

OUT u ra Nhiu chc nng m ccgp u ra. Nhng thitlp mc nh v cc thngs tiu chun pht hin vcho tc u ra t c

tn s ra ca tn hiu.

RCRY

u ra Rle a chc nng cl p trnh ngt in ura. Cng sut ngt: 250V-2A (cos=1), 30V-1A,250V-1A (cos=0.4).Nhng thit lp mc nh

VIB 15K+5v

15K0.1

FMC

JP302FMV

FM

P24 +24VPTC

OUT

P24

RY


35/107


35

v thng s tiu chun spht hin ra tn hiu v tns ra c tc thp.

FLAFLBFLC

u ra Rle a chc nng cl p trnh ngt in u

ra. Cng sut ngt: 250V-2A (cos=1), 30V-1A,250V-1A (cos=0.4). Cccc ny bo cho bit chcnng bo v ca bin tnang hot ng. Khi chcnng bo v ang hotng, hai tip im FLA-FLC ng, cn hai tipim FLB-FLC m.

3.6.3. Bn phm v mn hnh hin th

* Loi bin tn sdng

Kiu Hnh dng

Bng mch tuchn, m kthut c bit

V F S 9 - 2 0 0 7 P L - W N A 2 2

* Tn v chc nng

Tn modelVF_S9

S phangun:3 pha

in thuvo: 400V

Dung lngng ctng

ng

007: 0.75KW

Bng hotng

P: iukin

Chc nng ph:L: nhm A gnlin my lc.M: tiu chun.

Gn lin my lc

Giao din s hc

AN: cc mWN: cc mWP: cc dng

Bng mch tu chn,m k thut c bit.A00: m k thut t

bit(00: l s )

FLA

FLB

FLC

RY+24V


36/107


36

n VEC : n sng khi vectcm bin c lnh chy

n RUN :Sng khi bin tn ang hot ng, nhp nhy khi chy tng giatc/gim tc hot ng

n MON : Sng khi cch bin tn kim tra

n PRG : Sng khi cch bin tn t thng s

n ECN : Sng khi cch tit kim nng lng hot ng

n phmln/xung :

n phm ln hoc xung khi n sng cho php vic t tn s hotng .

n phmRUN : n bo RUN cho php chy

Phm RUN : Khi n bo cho php chy sng th n nt ny bt u hotng

PhmSTOP : Nhn nt ny khi n bo RUN sng s dng my mt cch t t

ENTER : Phm Enter

: Phm ln

: Phm xung

n gn lin vinm phn th

Gn lin vi nm phn th.Khi n gn lin vi nm

phn th sng th c ththay i tn s hot ng


37/107


37

MON :Phm gim st hin th tn s hot ng, thng sv nguyn nhn li

Chargelamp :

n bo ang c in, cho bin hin ti trong bintn ang c mt in th cao, khng c mnp

bng cha u cc khi n ang sng.

Terminalboad cover :

Bng lp cha u cc, lun lun phi ng chtnp ny trc khi my hot ng trnh tnh trngngu nhin chm vo cc u cc.

Conector forcommon

serial option:

Np bng cha mi ni la chn theo th timchung, ko np ny sang bn phi chn mi ni.

Terminalboad coverlock screws

: Dng c vt kha cht np bng.

3.6.4. Tiu chun kt ni

Ngun cung cp nng lng v kt ni vi ng c

Hinh 3.11 S kt ni dy

Ch : Kiu 3 pha 200 0.2; 0.4; 0.75Kw khng c cc ni t c ni t v

ca bin tn

S kt ni cc thit b ngoi vi

VF-S9

Dy ngunc ni viR.,S.,T.

ng ccni vi U,V,W.

R/L1 S/L2 T/L3 U/T1 V/T2 W/T3

E

Ngun cungcp nngl n

ng c

Dy dn

IM

Bin tnR/l1

S/L2

T/L3

U/T1

V/T2

W/T3


38/107


38

Hinh 3.12 S kt ni cc thit b ngoi vi

Mch chnh

K hiu cc Chc nng ca cc cc

Cc ni t c ni vi v hp ca bin tn

R/L1, S/L2,T/L3

Loi 200v: 1 pha 200 ~240v, 50/60 Hz3 pha 200 ~230v, 50/60 Hz

Loi 400v: 3 pha 380 ~500v, 50/60 HzLoi 1 pha khng c cc T/L3

U/T1, V/T2,W/T3

Ni vi ng c(phn cng 3 pha)

PA, PB c ni vi cc in trhm, cc thng s c th thay inu cn F304, F305, F308

PC y l cc (-) trong mch chnh ca dng mt chiu. imtrung tnh ca dng 1 chiu c th ni qua cc PA (in p (+))

PO, PA Hai cc ny c ni vi l phn ng mt chiu (thit b lachn bn ngoi)

3.6.5. Phn mm thuyt minh

3.6.5.1. La chn phng thc iu khin

a. t tn shotng gn lin vi nm phn thv chy, dng trn bng hot

ng:

- Cc thng s ci mc nh.

Cu

chTipxcin

uvo

Blc


39/107


39

Tiu Chc nng Gi tr lp trnh

CNOd Tnh la chn lnh 1

FNOd Cch la chn tn st

- Hot ng

+ Chy / dng: n phm RUN v STOP trn bng

+ Tn st: iu chnh v tr ca ci o in th

b.t tn shotng v khi ng, dng dng bng hotng

- Cc thng s ci t

Tiu Chc nng Gi tr lp trnh

CNOd Cch la chn lnh 1

FNOd Cch la chn tn st 1

- Hot ng :

+ Chy / dng: n phm RUN v STOP trn bng

+ Tn st: t vi cc phm , trn bng hot ng

+ lu gi tn st vo b nh, n phm ENT

FC v tn st s chp v ln lt tt.

c.t tn shotng dng nm phn thv chy/dng cc tn hiu bn ngoi.

- Trnh t trong vic t tn s

Phm hotng

Mnhin th

Cch hot ng

0.0 Hin th hot ng ca tn s (hot ng ngng). Khitiu chun monitor chn F701 th t tn s hotng l 0

MON AUI Nhn phm MON cho hin th thng s cbn utin AUI (t gia tc/gim tc)

CNOd n 1 trong 2 phm, ti chn CNOd

1 n phm ENTER cho hin th thng st (t mc


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nh : 1)

0 Thay i thng s v 0 bng phm

0CNOd

n phm ENTER ghi li thng s thay i. CNOd vgi tr b thng s lun phin c hin th.

FNOd n 1 trong 2 phm, cho la chn FNOd2 n phm ENTER cho hin th thng st (t mc

nh : 2)

1 Thay i thng s ln 1 bng phm

0FNOd n phm ENTER ghi li thng s va thay i.FNOd v gi tr b thng s lun phin c hinth.

n phm MON 2 ln quay li hin th cch iu chnh tiu chun.

- Cch khi ng v dng my

1. Khi ng v dng s dng cc phm trn bng hot ng (CNOd:1)

Dng phm RUN v STOP trn bng hot ng v dng ng c.

2. Khi ng v dng ng cbng cch dng cc tn hiu bn ngoi trn bng cc.

Short F v C: Tip tc chy

Open: F v C: chy chm dn v dng

Ci t thng s mc nh tiu chun mc ch l dng ng cmt cch t

t. dng c mt cch t t th phi n nh cc chc nng ca cc ST vi mt cc

b khng. Sau chn tn hiu F103: ST, khi dng ng ctrng thi nhc m t

hnh trn phi ST-CC hmch th mi dng. Lc ny trn mn hnh ca bin tn s

hin th tn hiu OFF.

ONOFF

Tns

Dng t t

F-CC F-CC

ST-CC

Tc ng

c

ONOFF

ONOFF


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+ Ci t tn s

Thit lp tn s bng cch dng nm phn th trn bng mch chnh ca bin tn

(FNOd: 20

t tn s bng cc mc vch trn nm phn th.

3. Chc nng cc cc u vo s

F110: Chn chc nng u vo st thng s

Lnh Chc nng Dy iu chnh Xc lp mc nh

F 110 Hot ng 0..51 (bng 1.1) 0

Thay i chc nng u vo:

F 111 : Chn chc nng u vo 1 (F)

F 112 : Chn chc nng u vo 2 (R)

F 113 : Chn chc nng u vo 3 (RST)

F 114 : Chn chc nng u vo 4 (S1)



S dng cc tham s trn gi tn hiu t biu chnh chng trnh ngoi ti

cc cc iu khin input khc nhau hot ng hoc ci t bin tn. Yu cu tip xc

ca chc nng cc cc u vo c thc la chn t 51 loi. Tnh linh ng c

thit kt gi vo h thng.S ci t cc tip im u vo

Biutng

ccTn Chc nng

Dy iuchnh

La chn mcnh

- F 110 Chn chc nng u vo s Bng 0 (khng ch nh

Tn s tng ccmc vch cao hn

theo chiu kimng ht tn s bng

cc mc vch trnnm phn th


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(11) chc nng)

F F 111 Chn chc nng u vo 1(F) 2 (chy thun)

R F 112 Chn chc nng u vo 2(R) 3 (chy ngc)

RST F 113 Chn chc nng u vo 3(RST) 10 (reset)

S1 F 114 Chn chc nng u vo 4(S1) 6 (t tc 1)



* Phng php ni

+ A tip xc u vo

+ Phng php vi transisto output

Giao din gia chng trnh iu khin v bin tn:

- Khi s hot ng c iu khin bng chng trnh iu khin mcc gpu ra. Nu chng trnh iu khin tt m bin tn li m. S khc nhau trong ngun

iu khin phn th s l nguyn nhn cc tn hiu sai c gi ti bin tn nh trong s

di. Thc cht ngi ta chun b mt kha lin ng cho b iu khin

chng trnh khng th tt khi bin tn m.

* Thay i chc nng cc cc u ra.

Bin tn Cng tc

S ni

* y l chc nng lm khicc input v cc ngn mch, s

dng chc nng ny ch r F/Rchy hoc t tc hot ng

input

Bin tn PLC

S ni

S hot ng c thc iu khin bngvic kt ni gia u vov CC (im trung tnh)ti u ra (khng ccng tc tip xc) cachng trnh. Chc nngny c dng nhr s hot ng: chythun, chy ngc hoct tc hot ng.

Tranzitor dng loi24Vdc/5mA

input

cc


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43

F130 : Chn cc u ra 1 (RY-RC)

F131 : Chn cc u ra 2 (OUT)

F132 : Chn cc u ra 3 (FLA/B/C)

Dng cc thng s trn gi cc tn hiu khc nhau t bin tn n cc thit bbn ngoi. Di 30 chc nng c thc dng ci t cc thng sc bit nh:

RY-RC, OUT, FL (FLA, FLB, FLC) trn bng cc iu khin.

+ Ci t chc nng cc cc u ra

K hiucc

Tn Struynt thng

tin

Chc nng Diiu

chnh

M Cng dng

RY-RC F130 0130 Pht hin tnhiu tc thp

4 LOW ON: Tn s ura bng hoc caohn gi tr tF100

OUT F131 0131 a ra cctn hiu vtn s (honthnh giatc/gimtc)

6 RCH ON: Tn s ura trong gii hn(tn su vo +tn st F102)OFF: Tn sura vt gii hn(tn su vo +tn st F102

FL F132 0132 Mt in FL(ngt u ra)

10 FL ON: Khi bin tnngtOFF: khi bintn khng ngt.

3. Thit lp thi gian tng tc / gim tc

AU1: Tng tng tc / gim tc

ACC: Thi gian tng tc 1

DEC: Thi gian gim tc 1

* Chc nng:

1. Thi gian tng tc ACC cho php tn s ra ca bin tn c th tng t0Hz ti tn s cc i FH sau mt khong thi gian.


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2. Thi gian gim tc dEC cho php tn s ra ca bin tn c th gim ttn s cc i FH xung 0Hz sau mt khong thi gian.

a. Tng tng tc, gim tc

Tng iu chnh thi gian tng tc v gim tc vi mc ti:AU 1 = 1 Tng iu chnh thi gian tng tc, gim tc vi dng bin tn

nm trong khong t 1/8 n khong ci t ACC v dEC. N t gi tr ti u c tnh

n khong cho php.

AU 1 = 2 T ng iu chnh ti khong thi gian ngn nht trong khong

120% ca dng bin tn. N l gi tr quan trng t c i vi thi gian tng, gim.

Khi tng ci t iu chnh thi gian lun lun i thi gian tng gim do

n ph hp vi ti.

i vi phn o cn thi gian tng gim cnh. S dng ch tng gim

bng tay (ACC, dEC)

Ci t thi gian tng gim (ACC.dEC) ph hp vi ti trung bnh cho php ci

t tt nht, ph hp vi s thay i ti.

S dng s hiu ny sau khi kt ni vi ng c.

Tn sRa Hz

Khi ti nh

0

Thi gian

gia tc

Thi gian

gim tc

Tns

Khi ti ln

0

Thi giangia tc

Thi giangim tc

Thi gian gia tc/gim tc gim

Thi gian gia tc/gim tc gim


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Tng thi gian c th khng hon thnh c nu phn o hot ng trong vng

mch iu chnh. Nu tng thi gian c hon thnh th iu chnh thi gian tng gim

bng tay (AU =1).

Nu gi tr ci t ln hn thi gian gim tc xc nh bng iu kin ti. Chc

nng qu ti dng hoc cng c th lm thi gian tng gim di hn thi gian ci

t. Nu thi gian ci t ln hn c th c mt di dng hoc mt di cng qu ti

i vi phn bo vo ngc.

b. Mmen khi ng

AU2: B tng mmen

* Chc nng:

Tng thc hin chuyn mch ng thi gia chiu khin u ra ca bin

tn v ch chy ca ng c b m men ca ng c. Thng s ny b sung cho

vic ci t chiu khin V/F c bit, v d nh chiu khin vector.

Ch : Bng biu th bn ti lun trv gi tr 0 sau khi iu chnh. Nhng gi tr

cc biu thbng bn tri.

1. Khi s dng chiu khin vector s b c mmen khi ng v tng

chnh xc khi hot ng.Ci t ch tng kim sot AU2 l 1 (chiu khin vector khng c

sensor).

Vic t chiu khin tng AU2 1 s cho mmen khi ng cao, iu

ny gip cho ng cc tht c tc ti a t vng tc thp. Nhng thay i

kh nhiu ca tc ng cgy ra do dao ng ti cho my hot ng vi

chnh xc cao. y l c trng quan trng i vi cc loi my nng v cc loi my

vn chuyn khc.

Phng php iu chnh

Cc nt n Bng hin th Hot ng

0:0 Hin th tn s hot ng (khi dng hot ng,khi m hin th trn chun F7 10 c t 0


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MON AU 1 Nhn MON hin th thng s c bn utin AU 1 (tng tng / gim tc )

AU 2 Nhn thay i thng s sang AU2 9tng b mmen)

ENT 0 0 Bm ENTER hin th ci t thng s 0 1 Bm i thng s sang 1 (iu khin

vector khng c sensor + tng iu chnh)

ENT 1AU2 Bm ENTER lu thng s thay i AU2v cc thng sc hin th thay.

Lu 1: iu khin V/F chn Pht trin 3 cho cng kt qu F400 (tng iu

chnh) c t 2.

Lu 2: t AU2 1 v tt chng trnh Pht trin 3

Nu iu khin vector khng t c. Xem hng dn viu khin vector mc

5, 12, 6.

AU2 (ch b mmen tng) v pht trin (ch chn m iu khin).

Ch tng mmen tng l thng st ch chn m iu khin v ch

tiu chnh (F400). l nguyn nhn lm cho tt c nhng thng s c lin quan

n AU2 tng thay i khi ch AU2 b thay i.

Cc thng s chng trnh tng

AU2 Pt F400

0 Hin th 0 sau khi ci t -Kim tra gi tr ca Phttrin (nu AU2 khng i,

n s v 0 (V/F l hng s)

-

1Chiu khin vectorkhng c sensor + tng iu chnh

3iu khin vector khngc sensor

Hon thnhch tiu chnh

* B mmen bng tay (iu khin V/F khng i)

Nh thit k ci t mc nh chiu khin ny cho bin tn VF-S9.


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47

t mmen khng i ph hp vi bng ti. N cng c p dng b mmen

khi ng bng tay.

Nu chiu khin V/F khng i c ci t sau khi AU2 thay i th chn

m iu khin V/F 0

Ch :

1.Nu mun tng mmen hn na phi nng ch ci gi tr bng tay.2. Chn chiu khin V/F 1 (mmen bin thin) l cch ci t hiu qu

nht i vi ti cc thit b nh qut v bm.

c. Ci t thng s bng phng php hot ng

AU4: Thit lp chc nng tng

Chc nng: Tng iu khin cc thng s (cc thng sc m tdi) c lin

quan n cc chc nng bng cch chn phng php vn hnh ca bin tn.

Tn Chc nng Di iu chnhCi t mc

nh

AU4 Ci t tng 0: khng cho php1: Dng t t2: Vn hnh 3 dy

3: Ci UP/DOWN cho u vo4: Hot ng vi u vo cdng 4- 20mA

0

Cc chc nng v gi tr ca thng sc iu khin tng

Ci tmc nh

1: Dng tt2: Vnhnh 3

dy

CiUP/DOWN

cho u vo

Hot ngvi u voc dng 4-

20mA

FNOd 2: Nmphn th

2: Nm phn th 2: nmphn th

1: Bng hotng

0: Bng cc

CNOd 1: Bnghot ng

0: Bng cc 0: Bngcc

0: Bng cc 0: Bng cc

F111(F) 2:F 2:F 2:F 2:F 2:F


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48

F112(R) 3:R 3:R 3:R 3:R 3:R

F113(RST)

10:RST 10:RST 10:RST 10:RST 10:RST

F114(S1) 6:SS1 6:SS1 6:SS1 41:UP 6:SS1

F115(S2) 7:SS2 7:SS2 7:SS2 42:DOWN 38:FCHGF116(S3) 8:SS3 1:ST 49:HD 43:CLR 1:ST

F103(ST) 1: lun hotng

0: kch hot bngcch chuyn ch ST sang ch hot ng

1: lunhot ng

1: lun hotng

0: kch hotbng cchchuyn ch ST sangch hotng

F200 0:VIA/II 0:VIA/II 0:VIA/II 3:UP/DOWN 0:VIA/IIF201 - - - - 20%

F202 - - - - -

F203 - - - - -

F204 - - - - -

F210 - - - 1 -

F211 - - - 0.1Hz -

F212 - - - 1 -

F213 - - - 0.1Hz -

Khng thay i (AU4 : 0 ): Cc cc v thng s vo c t theo tiu chunni sn xut.

Ch dng t t (AU4 : 1): Vic t ch dng t t ST (tn hiu ch) c

chnh cho cc S3 v qu trnh vn hnh c iu khin bi nt ON v OFF ca cc

S3.

Ch vn hnh 3 dy ( AU4 : 2): c vn hnh bng mt nt n nhanh HD(ch gi hot ng) c chnh cho cc S3. Ch t gi hot ng c xc lp

trong bin tn bng cch ni cng tc dng vi cc S3 v ni cng tc chy vi cc F

hoc cc R.

Ch ci UP/DOWN cho u vo (AU4:3): cho php t tn su vo t mt

im tip xc bn ngoi. C th p dng thay i tn snhiu v tr khc nhau. UP


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49

(tn hiu tng tn s u vo t tip im bn ngoi) c ch nh cho cc S1 v

DOWN (tn hiu gim tn su vo t tip im bn ngoi) c chnh cho cc S2,

CLR (tn hiu xa ch UP/DOWN tn su vo t mt tip im bn ngoi) c

chnh cho S3.

Ch vn hnh dng dng in vo 4-20mA (AU4:4): c s dng t tn

s vo bng dng 4-20mA, ngi ta hay dng lnh vo FCHG (chuyn i theo lnh tn

s) v ST (cc ch) tng ng vi cc cc S2 v S3. iu khin t xa bng tay (bng cc

lnh tn s khc nhau) c thc chuyn i sang cc S2. Cc S3 c thc dng

dng my t t.

d. Chn ch vn hnh

CNOd : Chn m lnh

FNOd : Chn m t tn s

Chc nng:

Cc thng s ny thng c s dng ch vn hnh v cht tn s

t lnh cho bin tn (t bng hot ng hoc cc)

* Chn m lnh:

- Gi trt:

+ Ch vn hnh t bng cc chn m 0: k hiu ON OFF cho bit ch

chy v dng ca my.

+ Ch vn hnh t bng hot ng chn m 1

+ Nhn nt RUN STOP trn bng hot ng chy v dng chng trnh

+ Thc hin ch chy v dng chng trnh khi s dng bng ph (mrng)

C hai loi chc nng: Chc nng tng thch vi lnh LNOd v chc nng chtng ng vi lnh t bng cc (xem bng 11 chn cc cc chc nng).

* Chn m t tn s:

- Gi trt:


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+ Ch vn hnh t bng cc chn m 0: Cc lnh t tn sc a vo

bng cc tn hiu ngoi. (cc VIA/VIB: 0-10Vdc hoc cc II: 4-20mAdc).

+ Ch vn hnh t bng hot ng chn m 1: nhn phm hoc phm

trn bng hot ng hoc trn bng pht tn s.

+ Dng nm phn th chn chn m 2: nm phn th trong bin tn c s dng

t tn s. Quay vch theo chiu kim ng h tng tn s.

* Cho d ch chn m lnh CNOd v ch chn m t tn s FNOd c

t cho u vo bt k gi tr no th chc nng ca cc cc c a ra di vn

lun trng thi hot ng.

- Cc t li tn s (ci t mc nh: RST, ch ph hp trong trng hp ang

vn hnh).

- Cc ch(iu khin chc nng cc u vo chng trnh)

- Cc dng hot ng ca u vo (iu khin chc nng cc u vo chng

trnh).

* thay i ch chn m lnh CNOd v ch chn m t tn s FNOd,

trc tin phi dng my tm thi (c th thay i trong khi my ang hot ng nu

F600 c t 2e. La chn chiu chy thun v ngc

Fr chn chiu chy thun v ngc

Chc nng:

t chiu quay trong qu trnh chy v dng s dng phm RUN v STOP trn

bng hot ng. Ch c gi tr khi CNOd (m lnh) c t 1

Thng s ci t

Tn Chc nng Di iu chnh Ci t mc nh

FrChn chy thun /ngc

0: Chy thun1: Chy ngc

0

* Kim tra chiu quay trn mn hnh


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Fr-F : Chy thun

Fr-r : Chy ngc

Khi u cui F v rc s dng chuyn mch gia chy thun / ngc t

bng cc, chn Fr chy thun / ngcf. Tn s cc i (FH)

Chc nng:

1. t chng trnh cho khong tn su ra bi bin tn (cc gi tru ra cc

i)

2. Tn s ny c dng lm tham chiu cho thi gian tng / gim tc.

Chc nng ny quyt nh gi tr cc i lin quan ti mc ng cv ti

Tn s cc i khng thc iu chnh khi ang hot ng. iu chnh

trc ht phi dng bin tn.

Nu FH tng, chnh gii hn trn ca tn s UL nu cn:

* Ci t thng s:

Tn Chc nng Mc iu chnh Ci t mc nhFH Tn s cc i 30 400Hz 80.0

g. Gii hn tn s cao tn s thp

UL : Tn s gii hn cao

LL : Tn s gii hn thp

100% Tn hiu t

tn s (%)

Hz80Hz

60Hz

0

FH=80Hz

FH=60Hz


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* Chc nng: t tn s gii hn thp quyt dnh gii hn thp ca tn su ra

v tn s gii hn cao quyt nh gii hn cao ca tn s cao.

Ci t thng s:Tn Chc nng Di iu chnh iu chnh sau

ci t

VLLL

Gi tr tn s caoGi tr tn s thp

0.5F-H (Hz)0.0 UL (Hz)

50 or 600,0

Gi tr ci t ph thuc vo phn di ca cc dng AN, WN: 60Hz, WP:50Hzh. Tn s cbn

* Chc nng:

t tn s cbn ph hp vi trng lng hoc tn s ca ng c

Lu : y l thng s quan trng quyt nh vng kim sot mmen u

Gi tr ci t ph thuc vo phn ui ca dng AN, WN: 60Hz, WP:50Hz

i. iu khin bng tay

100%0

FH

UL

100%0

FH

LL

Tn s ra Hz

Tn sinp cbn

F 306

0


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Ub tng lc

Chc nng: Nu mmen khng chy my tc thp, phi tng mmen

bng cch tng t l quay ca mmen bng thng s ny

Tn Chc nng Khong iu chnh Ci t

Ub Tng mmen 1 0 30% Theo loi

C hiu lc vi cc ci t mc nh tiu chun

Pht trin = 0 (V/F u) v 1 (lc xon a dng)

Lu 1: Gi tr ti u c t cho dung lng mi bin tn. Khng c tng t

l momen quay ln qu cao, v nh vy s gy ra s tng t ngt v dng in im

khi ng. Nu mun thay i cc gi tr ci t, phi gi cc gi tr trong phm

vi +2% ca cc gi tr mc nh tiu chun.

k. t mc nhit ca in

- Chc nng: Chn c tnh ngn nhit in ph hp vi cc gi tr ca ng c.

y l cc thng s nh cc thng s m rng F600. Cc gi trc ci t sc

gi nguyn d cc thng s khc thay i.Ci t thng s:

Tn Chc nng Khong iu chnhCimcnh

Gi trci

Ngnqu ti

Ngn ngtt ngt

Tn s ra Hz

Tn sinp cbn

F 306

0


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OLN

Chn c tnh

ngn nhit in

0ng c

tiu chun

0 x

0

1 0 0

2 x x

3 x 0

4ng c

VF

0 x

5 0 0

6 x x

7 x 0

F600Ngn nhit inng cmc 1

10 ~100% 100

Ch bo v bng nhit in tc s dng cho php hoc khng cho phpng cchy qu ti v dng qu ti. Khi thng bo qu ti, bin tn ang hot ng

khng i th c th dng thng s OLN thng bo qu ti.

Gii thch thut ng:

- Dng qu ti: Khi bin tn pht hin c hin tng qu ti, chc nng ny t

ng gim tn s ra trc khi thng bo qu ti ca ng cOL2 c kch hot. Chc

nng gim t t cho php ng cchy tn s dng ti cn bng m khng hin ln

thng bo. y l chc nng quan trng cho cc thit b nh qut, bm v thit b thi

gi c tc momen thay i, dng ti gim khi tc vn hnh gim.

+ Ch : Khng c s dng ch gim ti vi nhng ti c tc momen

khng i (nh bng truyn c dng ti cnh, khng thay i tc ).

S dng cc ng ctiu chun (thay v cc ng cc s dng vi bin tn)

Khi mt ng cc s dng vng tn s thp hn vi tn s ci, iu s

lm gim hiu qa lm mt cho ng c. Khi ng ctiu chun c s dng ngnhin tng qu nhit, n s lm tng tc ban u ca qu trnh pht hin qu ti.

Ci t chng nhit ng cin t cp 1

Nu cng sut ca ng cnh hn cng sut bo ngc hoc dng chun ca

ng cnh hn dng chun ca bo ngc, iu chnh ci t chng nhit ng c

in t cp 1 ph hp dng chun.

[%]/[A]


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Phm hotng

Mn LED Hot ng

0.0 Hin th tn s hot ng (trong khi dng) (Khimn tiu chun hin th la chn F710 c ci

t 0 (tn s hot ng)MON AUI Nhn phm MON hin th tham s cbn u

tin AUI (tng tng gim)

100 Nhn phm hoc chuyn i thng s

ENT 417 Nhn phm ENTER hin th ci t thng s(ci t chun 100%)

417 Nhn phm iu chnh thng s 417 (bngdng chun ng c/ hiu sut dng o x 100 =

1.0/4.8 x 100 (khi PWM tn sc ci 12kHz)ENT Nhn phm ENTER thay i thng s v gi

tr ci t thng sc hin th lin tc.

S dng mt ng cVF (ng c s dng vi bo)Ci t la chn tnh nng bo v nhit in t

Gi tr ci t Bo v qu ti Mt qu ti

4 0 x

5 0 06 x x

7 x 0

0: C gi tr

x: Khng c gi tr


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Mt ng cVF c thc s dng trong di tn thp hn ng ca nng,

nhng nu tn s cc thp, nh hng ca vic lm mt s gim dn.

Ci t bo v nhit ng cin cp 1

Nu cng sut ca ng cang s dng nh hn cng sut bo ngc hocdng chun ca ng cnh hn dng chun ca bo ngc iu chnh bo v nhit

ph hp vi dng chun ca ng c.

Nu ch s trong khong (%) n 100% tng ng cng sut dng chun.

Tnh nng qu ti bin tn

Ci t bo v b phn bin tn, khng th thay i hoc iu chnh bng

thng s ci t.

Nu chc nng qu ti bin tn c kch hot lin tc n c thc nng ln

bng cch iu chnh cp hot ng F601 tng hoc gim thi gian gia tc ACC hoc

thi gian gim tc dEC

%/A

Hz

s

%

60

0110 150


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4. Kiu chy nhp

F 260 : Tn s chy nhp

F 261 : Chy nhp dng

Chc nng: Dng cc thng s chy nhp ng chot ng theo cch nhp.

ng vo ca tn hiu chy nhp pht ra cng mt lc u ra mt tn s chy nhp.

Khng k thi gian gia tc chnh.

ng c c th hot ng kiu nh p trong khi vic ci t cc cc chy nhp

c kt ni (RST ON), (t F113 ln 4)

Thng s ci t

Tn Chc nng Dy iu chnh t mcnh

F301

La chnlnh tng chyli

0: Khng s dng1: Tng chy li sau dng tm thi2: Khi i chiu ST_CC on hoc off3: Tng chy li hoc i chiu ST_CCon hoc off4: Chuyn ng hm mt chiu khi ng(tng chy li sau dng tm thi).5: Chuyn ng hm mt chiu khng khing (khi i chiu ST_CC on hoc off)6: Chuyn ng hm mt chiu khi ng( t ng chy li hoc khi i chiuST_CC on hoc off).

0

Nu motor chy li trong phng thc chy li mt ln, th chc nng s hotng. Bt chp st ca tham s.

a. Tng chy li sau khi ngun khng hot ng tm thi (chc nng tngchy li)

Tc

motor

in p uvo V


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58

Hinh 3.13 S chc nng tng chy li

t F30 1 to 1, (3) chc nng ny hot ng sau khi ngun c du hiu khi

phc sp pht hin ra s di in p bi mng li mch v iu chnh ngun.

b. Khi ng li Motor (chc nng tm tc motor)

t F30 1 to 2, (3) : y l chc nng hot ng sau khi ST_CC chuyn tip c

du hiu mtrc tip v khi thng trli

(1). DC braking trong thi gian chy liNu tham s l tp hp la chn 4, 5 hoc 6. DC braking l thuyt bi

tham s F 251, hoc F 252 s l hng dn trong thi gian chy li ca Motor.

Chc nng ny l c hiu qa khi motor di tm thi ngun khng c hoc tnh

trng i xung v o chiu v mt s l do bn ngoi.

c. Hm mt chiu trong thi gian khi ng li

Nu thng s l mt trong nhng b 4, 5 hoc 6, DC hm l thuyt bng

thng s F 251 hoc F 252 s dn trong thi gian khi ng li ca ng c.

Chc nng ny c hiu lc khi ng cb di tm thi in p li hoc tnh

trng xung thp v so chiu bi mt s l do bn ngoi.

5. iu bin tn s mang (PWM)

F 300 : PWM tn s mang

ONOFF

F_CC

Tc ng

c

ONOFF

ST_C


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F 312 : kiu ngu nhin

Chc nng:

+ F 300 thng s cho php lm gim t tnh lm n n ng csau ny thay i

bng PWM tn s mang, thng s ny ngoi ra cn c hiu lc ngn cn ng cn scng hng vi trng ti my hoc gi .

+ Trong php cng, thng s F 300 gim bt in t lm n pht ra do bin tn.

Gim bt tn s mang t vic gim bt in t lm n.

+ Tu chn cch gim bt in t lm n ng c bng s thay i mu mc

gim bt tn s mang.

Tham st

Tn Chc nng Dy hot ng t mc nh

F 300 PWM tn s vtmang

2.0 ~ 16.5 (kHz) 2.0

Gim bt ti s gim bt PWM tn s mangT l quy nh s gim bt ti

< Nhm 200V >VFS9 VFS9S Tn s

4kHz hockm hn

12kHz 15kHz 16.5kHz

2002PL/M 1.5 A 1.5 A 1.5 A 1.5 A

2004PL/M 3.3 A 3.3 A 3.1 A 3.0 A

2007PL/M 4.8 A 4.8 A 4.2 A 3.9 A

2015PL/M 7.8 A 7.8 A 7.2 A 7.1 A

2022PL/M 11.0 A 11.0 A 9.1 A 8.7 A

2037PL/M 17.5 A 17.5 A 15.0 A 14.3 A

2055PL/M 27.5 A 27.5 A 25.0 A 25.0 A

2075PL/M 33.0 A 33.0 A 29.8 A 28.2 A

2110PL/M 54.0 A 54.0 A 49.0 A 49.0 A

2150PL/M 66.0 A 66.0 A 54.0 A 51.0 A


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< Nhm 400V >

VFS9

480 hoc nh hn 480 hoc ln hn

Tn s Tn s

4kHzhoc T

3.8.2. Xc nh thng sbiu chnh

Ta c s h thng nh hnh sau:

Ta coi: K = K1 * K2

p dng tiu chun modul ti u cho biu chnh P ta c:

TKKR *2

=

Hm truyn ca h thng:

PTP

KFdt

)1( +=

)1(1

+TP

K

P

K

2 U- U1

)1(21

+TPP

KK

U1

RQ+

-

Qd

)1(21

+TPPKK

Q

RQ+

-

Qd


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75/107


75

AU2

0001 T ng tngmmen

- - 0: khng x1: vector iukhin + t ngiu chnh

0

AU3 0002 Tng t theomi trng - - 0: khng x1: t tng 0

AU4

0040 Chng trnh ttng

- - 0: khng x1: dng2: 3 vng iukhin3: t gi truvo ln xung4: 4-20mA dng

iu khin uvo

0

Chng 4GII THIU V BIU KHIN PLC

4.1 KHI QUT V PLCPLC (vit tt t ting Anh ca t: Programmable Logic Controller) c gi l Biu khin

logic kh trnh. S pht trin ca k thut iu khin tng hin i v cng nghiu khinlogic kh trnh da trn cspht trin ca tin hc, c th l s pht trin ca k thut mytnh.

Thit biu khin logic kh trnh PLC hin nay c ng dng rt rng ri. Thit biu khinlogic kh trnh PLC c th thay thc c mt mng rle, hn th na PLC ging nh mtmy tnh nn c th l p trnh c. Chng trnh ca PLC c th thay i rt d dng, ccchng trnh con cng c th sa i nhanh chng.

Thit biu khin logic kh trnh PLC p ng c hu ht cc yu cu v nh l yu tchnh trong vic nng cao hn na hiu qu sn xut trong cng nghip. Trc y th vic tng ho chc p dng trong sn xut hng lot nng sut cao. Hin nay cn thit phi t

ng ho c trong sn xut nhiu loi khc nhau, nng cao nng sut v cht lng.

4.2. CC THNH PHN CA MT B PLC.

Mt b PLC thng thng c nhng Modul phn cng nh sau:

Modul ngun.

Modul n v x l trung tm CPU.

Modul b nhchng trnh.

Modul u vo.


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Modul u ra.

Modul phi ghp.

Modul chc nng ph.

Modul ngun nhn t ngun in li cng nghip to ra ngun in mt chiu cung cpcho hot ng ca ton b PLC.

Modul n v x l trung tm CPU: trong mi thit b PLC Modul n v x l trung tmgm nhiu h thng vi x l bn trong, c hai loi n v x l trung tm l: n v x lmt bt v n v x l bng t ng.

Modul b nhchng trnh: Chng trnh iu khin hin hnh c gi li trong b nhchng trnh bng cc b phn lu giin t nh RAM, PROM hoc EPROM. Chng trnhc to ra vi s trgip ca mt n v lp trnh chuyn dng, ri c chuyn vo b nhchng trnh. Mt ngun in d phng cn thit cho RAM duy tr chng trnh ngay ctrong trng hp mt ngun in chnh.

Modul u vo: Modul u vo c chc nng chun b cc tn hiu bn ngoi chuyn vo

trong PLC c cha cc b lc v b thch ng mc nng lng. Mt mch phi ghp c lachn c dng ngn cch in gii mch trong ra khi mch ngoi. Cc Modul u voc thit k c th nhn nhiu u vo v c th cm thm cc Modul u vo mrng.Vic chn on cc sai xt h hng sc thc hin rt d dng vi mi u vo c trang

b mt it pht sng (led) b ch th nh sng bo hiu cho s c mt ca in th u vo.

Modul u ra: Modul u ra c cu to tng t nh Modul u vo. N gi thng cc thngtin u ra n cc phn t kch hot (cho dn ng) ca my lm vic. V vy m nhiu Modulu ra thch hp vi hng lot mch phi ghp khc nhau c cung cp. it pht sng(led) cng c th gip quan st in thu ra.

Modul phi ghp: Modul phi ghp dng ni biu khin kh trnh PLC vi cc thit bbn ngoi nh mn hnh, thit b lp trnh hoc cc Panen mrng. Thm vo , nhiu chcnng ph cng cn thit hot ng song song vi nhng chc nng thun tu logic ca mt bPLC cbn. Cng c th ghp thm nhng thin t phc bit to ra cc chc nng

ph. Trong nhng trng hp ny u phi dng n mch phi ghp.

Modul chc nng ph: Nhng chc nng phin hnh nht ca PLC l b nhduy tr ccng chc nng nh Rle duy tr ngha l bo tn tn hiu trong qu trnh mt in. Khi ngunin tr li th b chuyn i ca b nhnm t th nh trc lc mt in. B thi gianca PLC c chc nng tng t nh cc rle thi gian, vic t thi gian c lp trnh hociu chnh t bn ngoi. Bm c lp trnh bng cc lnh logic cbn hoc thng qua cc

thin t ph. B ghi tng ng vi ccu nt bm- bc. Bc tip theo c th ra bib pht thi gian hoc bng xung ca mch chuyn i. Chc nng s hc c thit kthc hin bn chc nng s hc cbn: cng, tr, nhn. chia v cc chc nng so snh: lnhn, nh hn, bng v khng bng. Chc nng iu khin s ca PLC iu khin cc qutrnh cng ngh trn cc my cng c hoc trn cc tay my, ngi my cng nghip.

4.3. CHC NNG CA PLC.Chc nng ca biu khin logic kh trnh cng ging nh cc biu khin khc thit ktrn cscc rle hoc cc thnh phn in t:


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Thu nhn cc tn hiu u vo v phn hi (t cc cm bin).

Lin kt, ghp ni li v ng mmch ph hp vi chng trnh.

Tnh ton v son tho cc lnh iu khin trn csso snh cc thng tin thu c.

Phn pht cc lnh iu khin n cc a ch thch hp.

4.4. U IM CA VIC NG DNG PLC.Vic ng dng cc b PLC vo cc h thng gp rt nhiu thun li nh

Thi gian lp t ngn.

tin cy cao v ngy cng tng.

D dng thay i phn mm nhthit k.

C th tnh ton c chnh xc gi thnh.

X l t liu tng.

Tit kim khng gian.

Chun ho c phn cng iu khin.

Kh nng ti to.

Thch ng trong mi trng khc nghit: nhit , m, in p giao ng, ting n.

Ghp ni my tnh.

Ghp ni my in.

4.5. THIT BIU KHIN LOGIC KH TRNH SIMANTIC S7- 200Simatic S7 - 200 l thit biu khin logic kh trnh ca hng Siemen (Cng ho Lin Bangc) . Th h Simatic S7 - 200 rt linh hot v hiu qu s dng cao do nhng c tnh sau:

C nhiu loi CPU khc nhau trong h S7-200 nhm p ng yu cu khc nhau ca

tng ng dng.C nhiu Modul m rng khc nhau nh cc Modul ng vo/ ra tng t, Modul ng

vo/ ra s.

Modul truyn thng kt ni PLC trong h S7-200 vo mng Profibus- DP nh l mtSlave.

Modul truyn thng kt ni PLC trong h S7 - 200 vo mng AS- I nh l mtMASTER.

Phn mm STEP 7- Micro/ Win softwarl.

Trong phm vi n ny, em xin c gii thiu v CPU 215 ca hng SIEMENS . CPU 215

nh hnh sau:

4.5.1. Cc c tnh kthut ca CPU 215 v Modull 315

c tnh k thut CPU 215

Kch thc vt l 246 x 80 x 62 mm

Trng lng 0,5 kg

Cng sut tiu th 8w


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78

Dung lng b nhchng trnh 4 K Word

Dung lng b nhd liu 2,5 K Word

S lng u vo tng t 16

S lng u ra tng t 10

S lng u vo s 64

S lng u ra s 64

C th ghp ni mrng cc Modul 2

S lng b to thi gian tr 256

S lng bm 256

S lng bt nhc bit 368

u vo

Kiu u vo Kiu khe cm

Di tn hiu vo T 15 30 V in p mt chiu , 4mA

Thi gian phn ng li:

I0.0 ti I1.5

I0.6 ti I1.5

T 0,2 ms n 8,7 ms

mc nh 0,2ms

6 s bt v 30 s tt

C cch ly quang 500 V AC ,1 pht

u ra

Di in p T 24,4 n 28,8 V mt chiu

Dng ti ti a

Q0.0 ti Q0.7

Q1.0 ti Q1.1

nhit t 00n 550 C

0,5 A/ im

10 A/ im

Dng in d

Q0.0 ti Q0.7Q1.0 ti Q1.1

200 A400 A

Thi gian chuyn mch

Q0.0 ti Q0.7

Cc u ra khc

100 s, ON/OF

150 s ON, 400 s OF


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79

in trtrong ln nht 400 m

Bo v dng ngn mch

Q0.0 ti Q0.7

Q1.0 ti Q1.1

0,7 n 1,5 A/ Knh

1,5 n 3 A/ Knh

C cch ly quang 500 VAC , 1pht

Ngun cp

in p T 20,4 n 28,8 VDC

Dng vo 120 mA

Cch kt ni cc cng dnh cho CPU 215 c biu din nh hnh sau:Modull mrng EM235

c tnh k thut CPU 215

Kch thc vt l 90 x 80 x 62 mm

Trng lng 0,2 kg

Cng sut tiu th 2w

S lng u vo tng t 3

S lng u ra tng t 1

u vo

Kiu u vo Diferential

Di tn hiu vo cc i 30 V in p mt chiu , 32mA

phn gii chuyn i t Analog sangDigital

12 bit hoc 1 trong 4096

Thi gian chuyn i t Analog sangtng t

25 s

u ra

in p ra 10 V

Dng ti ti a T 0 n 20 mA


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80

4.5.2. Cng truyn thng.

S7-200 s dng cng truyn thng ni tip RS 485 vi phch ni 9 chn phc v cho vicghp ni vi thit b lp trnh hoc vi cc trm PLC khc. Tc truyn cho my lp trnhkiu PPI l 9600 baud.

Chn Gii thch1 t

2 24 VDC

3 Truyn v nhn d liu

4 Khng s dng

5 t

6 5VDC

7 24 VDC

8 Truyn v nhn d liu

9 Khng s dng

Ghp ni S 7- 200 vi my lp trnh PG 702 hoc vi cc loi my lp trnh thuc h PG7 XXc th s dng mt cp ni thng qua MPI.

Ghp ni S7- 200 vi my tnh qua cng RS 232 cn c cp ni PC/ PPI vi b chuyn iRS 232/ RS 485.

4.5.3. Cu chc chng trnh ca S 7 - 200

C th lp trnh cho PLC S7-200 bng cch s dng mt trong nhng phn mm:STEP - MICRO/ DOS.

STEP - MICRO/WIN.

Phn mm ny c th ci t c trn cc my lp trnh hoc PG 7xx v cc my tnh cnhn (PC). Chng trnh c th vit bng cc ngn ng sau

Lu hiu khin (Control system flow chart)

Gin thang (Ladder Diagram).

Danh sch lnh (Statment List).

Cc lnh kiu khi v cc lnh bc cao.

Trong bn n ny em gii thiu v ngn ng lp trnh gin thang bng my tnh c nhn.

Cc chng trnh cho S7-200 c cu trc bao gm chng trnh chnh v cc chng trnh conv cc chng trnh x l ngt.

Chng trnh chnh c kt thc bng lnh kt thc chng trnh (MEND).

Chng trnh con l mt b phn ca chng trnh. Cc chngtrnh con c vit sau lnhkt thc chng trnh, l lnh MEND). Cc chng trnh con c nhm li thnh mt

5 4 3 2 1

9 8 7 6


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81

nhm ngay sau chng trnh chnh. Sau n cc chng trnh x l ngt th cu trc chngtrnh c r rng v thun tin hn trong vic c chng trnh.

Main program

MEND

Thc hin trong mt vngqut

SBR0 chng trnh con th nht

RET

Thc hin khi cchng trnh tnh gi

SBRn chng trnh con th n+1

RET

INT O chng trnh x l ngt

th nht

RETI

Thc hin khi c tnhiu

bo ngt

INTn chng trnh x l ngt th n+1

RETI

4.6. NGN NGLP TRNH CA S7 - 200.

4.6.1. Phng php lp trnh.

S7-200 biu din mt mch logic cng bng mt dy cc lnh lp trnh. Chng trnh l mtdy cc lnh S7 - 200. Thc hin chng trnh bt u t lnh lp trnh u tin v kt thc lnh lp trnh cui trong mt vng c gi l vng qut (scan).

Mt vng qut (scan cycle) c bt u bng vic c trng thi ca u vo, v sau thchin chng trnh. Mt vng qut kt thc bng vic thay i trng thi u ra. Trc khi btu mt vng qut tip theo S7-200 thc thi cc nhim v bn trong v nhim v truyn thng.Chu trnh thc hin chng trnh l chu trnh lp c th hin hnh 3.3.

Cch l p trnh cho S7 -200 ni ring v cho cc PLC ca Siemen ni chung da trn haiphng php cbn:

Phng php hnh thang (Ladder logic vit tt thnh LAD).

Phng php lit k lnh (Stamennt List vit tt thnh STL).

Giai on nhp dliu t ngoi vi

Giai on chuynd liu ra ngoi vi

Giai on thchin chng trnh

Giai on truyn

thng ni b v tkim tra li

Hnh 4.3. Chng trnh theo vng qut trong S7-200 thc hin


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Phng php hnh thang LAD l mt ngn ng lp trnh bng ho. Nhng thnh phn cbn dng trong lad tng ng vi cc thnh phn ca Bng iu khin bng r le. Trongchng trnh LAD cc phn t cbn dng biu din lnh logic.

Cc tip im thng mc m t

Cc tip im thng kn c m t

Cun dy c m t

Hp l biu tng m t cc hm khc nhau n lm vic khi c dng in chy nhp. Nhng dng hm thng c biu din bng hp l cc b thi gian (TIM ER) bm(COUNTER)v cc hm ton hc

Mng LAD l ng ni cc phn t thnh mt mch hon thin i tng ngun bn trisang ng ngun bn phi, ng ngun bn tri l dy nng, ng ngun bn phi l dytrung ho hay l ng trv ngun cung cp

Phng php lit k lnh STL l phng php th hin chng trnh di dng tp hp cc culnh. Mi cu lnh trong trng trnh k c nhng lnh hnh thc biu din mt chc nng ca

PLC.H lnh ca S7- 200 c chia lm ba nhm v xp xp theo th t Alphaber

Cc lnh m khi thc hin th lm vic c lp khng ph thuc vo gi tr Logic cangn xp.

Cc lnh ch thc hin c khi bit u tin ca ngn xp c gi tr logic bng 1.

Cc nhn lnh nh dn v tr trong tp lnh.

Chng trnh c vit theo kiu LAD, thit b lp trnh s t to ra mt chng trnhtheo kiu STL tng ng. Ngc li khng phi mi chng trnh c vit theokiu STL cng c th chuyn sang c LAD.

M t vic thc hin lnh a gi tr logic ca tip im IO.O vo trong ngn sp x p theocch biu din LAD v STL nh sau:

LAD STl

LD IO.O

= Q1.0

4.6.2. C php h lnh ca S7- 200.

SIMATIC S7- 200 c mt khi lng lnh tng i ln th hin cc thut ton ca i sBoolean, song ch c mt vi cc kiu lnh khc nhau. Tng lnh ca S7- 200 c m t chi

tit v cch s dng, chc nngv tc ng ca chng vo ni dung ngn xp.Gii hn tonhng ca CPU 215 c trnh by nh sau:

Phng php truy cp Gii hn cho php ton hng CPU 215

I O.O Q 1.O


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Truy cp bit

(a ch byte, ch s bit)

V

I

Q

M

SM

T

C

S

(0.0 n 5119.7)

(0.0 n 7.7)

(0.0 n 7.7)

(0.0 n 31.7)

(0.0 n 194.7)

(0 n 255)

(0 n 255)

(0 n 31.7)

Truy cp byte

VB

IB

MB

SMB

AC

SB

Hng s

(0 n 5119)

(0 n 7)

(0 n 7)

(0 n 31)

(0 n 194)

(0 n 15)

Truy cp tn

(a ch byte cao)

VW

T

C

IW

QW

(0 n 5118)

(0 n 255)

(0 n 255)

(0 n 6)

(0 n 6)

Truy cp tn

(a ch byte cao)

MW

SMW

AC

AIW

AQW

SW

Hng s

(0 n 30)

(0 n 193)

(0 n 3)

(0 n 30)

(0 n 30)

(0 n 30)


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Lnh LDN np gi tr logic, nghch o ca mt tip im vo trong bit u tin ca ngn xp,cc gi tr c cn li trong ngn xp by li xung mt bt.

M t lnh bng LAD:

LAD M t Ton hng

Tip im thng mscng nu n= 1

n: I, Q, M, SM, T,C, V (bit)

Tip im thng ng s mkhi n= 1

Tip im thng m sngthc thi khi n= 1

n: I

Tip im thng ng s mthc thi khi n= 1

M t lnh bng STL:

Lnh M t Ton hng

LD n Lnh np ga tr logic ca im n u tintrong ngn xp

n: I,Q,M,SM,T(bit) C,V

LDN n Lnh np nghch o ca im n vo bit utin trong ngn xp

LDI n Lnh np tc thi gi tr logic ca im nvo bt u tin trong ngn xp.

n: I

LDNI n Lnh np tc thi gi tr logic nghch o caim n vo bt u tin trong ngn xp

3. Lnh ra.

OUT PUT (=): Lnh sao chp ni dung ca bit u tin trong ngn xp vo bit c chnhtrong lnh. Ni dung ca ngn xp khng b thay i.

M t lnh bng LAD:

LAD M t Ton hng

Cun dy u ra trng thi kch thchkhi c dng iu khin i qua

n: I,Q,M,SM,T,C,V

(bit)

Cun dy u ra c kch thch tcthi khi c dng iu khin i qua

n: Q

M t lnh bng STL nh sau:

STL M t Ton hng

n

n

n

n

n

n


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86

= n Lnh = sao chp gi tr ca nh ngnxp ti tip im n c ch dn tronglnh.

n: I,Q,M,SM,T,C,V

(bit)

= 1 n Lnh = 1 sao chp tc thi gi tr canh stack ti tip im n c ch dntrong lnh

n: Q

(bit)

4. Cc lnh ghi / xo gi trcho tip im.

SET (S)

RESET (R)

Lnh dng ng v ngt cc im gin on c thit k. Trong LAD, logic iu khindng in ng hoc ngt cc cun dy u ra. Khi dng iu khin n cc cun dy th cccun dy ng hoc mcc tip im (hoc mt dy cc tip im).

Trong STL, lnh truyn trng thi bit u ca ngn xp n cc im thit k. Nu bit ny c

gi tr bng 1, cc lnh S v R sng ngt tip im hoc mt dy cc tip im (gii hn t 1n 255) Ni dung ca ngn xp khng b thay i bi cc lnh ny.

M t lnh S v R bng LAD:

LAD M t Ton hng

ng mt mng gm n tip im

k t S_ BIT

S_ BIT: I, Q, M, SM, TC,V(bit)

n: IB,QB, MB, SMB,VB (byte) AC, hng s,*VD,

* AC

Ngt mt mng gm n tip imk t S_BIT. Nu S_BIT li ch

vo Timer hoc Counter th lnhs xo bt u ra ca Timer/Counter.

ng tc thi mt mng gm n cctip im k t S_BIT

S_BIT: Q

(bit)

n: IB,QB,MB,SMB,VB(byte) AC, hng s,

*VD, *AC

Ngt tc thi mt mng gm n cctip im k ta ch S_BIT

M t lnh S (set) v R (Reset) bng STL nh sau:

Lnh M t Ton hng

S S_BITn

Ghi gi tr logic, vo mt mng gm nbit k ta ch S_BIT

S_BIT : I, Q, M,SM, T C,V(bit)

S' Bit RI n

S' Bit S n

S' Bit R n

S' Bit SI n


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R S_BITn

xo mt mng gm n bit k t a chS_BIT. Nu S_BIT li ch vo Timerhoc Counter th lnh s xo bit u raca Timer/ Couter.

SI S_BITn

Ghi tc thi gi tr logic 1 vo mt mnggm n bt k ta ch S_BIT

S_BIT: Q

n:IB,QB,MBSMB,VB(byte) AC, hng s,

*VD, * ACRI S_BIT n Xo tc thi mt mng gm n bt k t

a ch S_BIT

5. Cc lnh logic i sboolean

Cc lnh tip im i s Boolean cho php to lp c cc mch logic (khng c nh).Trong LAD cc lnh ny c biu din thng qua cu trc mch, mc ni tip hay song songcc tip im thng ng v cc tip im thng m. STL c th s dng cc lnh A (And)v O (Or) cho cc hm hhoc cc lnh AN (And Not), ON (Or Not) cho cc hm kn. Gi tr

ca ngn xp thay i ph thuc vo tng lnh.

Lnh M t Ton hng

O n

A n

Lnh thc hin ton t (A) v (O) gia gi trlogic ca tip im n v gi tr bit u tintrong ngn xp. Kt quc ghi li vo bit uca ngn xp

n:I,Q,M,SM,

(bit) T,C,V

AN n

ON n

Lnh thc hin ton t (A) v (O) gia gi trlogic nghch o ca tip im n v gi tr bit

u tin trong ngn xp. Kt quc ghi li vobit u ca ngn xp

AI n

OI n

Lnh thc hin ton t (A) v (O) gia gi trlogic ca tip im n v gi tr bit u tin trongngn x p. Kt quc ghi li vo bit u cangn xp

n: I

(bit)

ANI n

ONI n

Lnh thc hin ton t (A) v (O) gia gi trlogic nghch o ca tip im n v gi tr bitu tin trong ngn xp. Kt quc ghi li vo

bit u ca ngn xp

6. Cc lnh can thip vo thi gian vng qut.

Trong LAD v STL chng trnh chnh phi kt thc bng lnh kt thc khng iu kinMEND. C th s dng lnh kt thc c iu kin END trc lnh kt thc khng iu kin.

Lnh STOP kt thc chng trnh, n chuyn iu kin chng trnh n ch STOP. Nunh gp lnh STOP trong chng trnh chnh hoc trong chng trnh con th chng trnhang c thc hin sc kt thc ngay lp tc.


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Nu nh gp lnh STOP trong chng trnh x l ngt th chng trnh x l ngt s kt thcngay lp tc v tt c cc tn hiu ngt ang chx l, sau u b b qua v khng cthc hin.

Lnh WOR s khi ng li ng h quan st v chng trnh tip tc c thc hin trongvng qut ch quan st.

S dng lnh MEND, STOP v WDR trong LAD nh sau:

LAD M t Ton hng

Lnh kt thc chng trnh chnh hin hnhc iu kin.

khng c

Lnh kt thc khng iu kin dng ktthc mt chng trnh hin hnh.

Lnh STOP kt thc chng trnh hin hnh

v chuyn sang ch STOP.

Lnh WRD khi to li ng h quan st.

Lnh NOP khng c hiu lc trong chngtrnh hin hnh. Ton hng n l mt s nmtrong khong 0255

n: 0 255

S dng lnh END, STOP v WDR trong STR trong STL nh sau:

STL M t Ton hng

ENDLnh kt thc chng trnh chnh hin hnh nu

bit u ngn xp c gi tr logic 1.

khng cMEND

Lnh kt thc khng iu kin dng kt thcmt chng trnh hin hnh.

STOPLnh STOP kt thc chng trnh hin hnh vchuyn sang ch STOP.

WDR Lnh WRD khi to li ng h quan st.

NOP nLnh NOP khng c hiu lc trong chng trnhhin hnh. Ton hng n l mt s nm trongkhong 0 255

n: 0 255

7. Cc lnh shc :

Cc lnh s hc dng thc hin cc php tnh s hc trong chng trnh .Cc php tnh vis thc hoc vi s thc du phy ng v php bin i gia s thc v s nnguyn kiu tkp ch thc hin c CPU214.Ngoi bn php ton cbn (cng, tr, nhn, chia) .S7-200

STOP

WRD

NOP

END

END


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cn cung cp cc lnh thc hin php bin i s thc (4byte)cn c s nguyn kiu t kp vly du cn.

Lnh ADD _I (LAD)

+I (STL)

Lnh thc hin php cng cc s nguyn 16 bit IN1v IN2 .Trong LAD kt qu l mt snguyn 16 bit c ghi vo out tc l :

IN1+ IN2 = OUT

Trong STL kt qu cng l mt gi tr 16 bit nhng c ghi vo IN2 tc l :

IN1 + IN2 = IN2

Lnh SUB_I(LAD)

-I (STL)

Lnh thc hin php tr cc s nguyn 16 bit IN1v IN2. Trong LAD kt qu l mt s nguyn16 bit c ghi vo out tc l :

IN1- IN2 = OUTTrong STL kt qu cng l mt gi tr 16 bit nhng c ghi vo IN2 tc l :

IN1- IN2 = IN2

C php dng lnh cng tr hai s nguyn 16 bit trong LAD v STL nh sau :

LAD STL Ton hng

+ IN1 IN2 IN1,IN2 : VW, T, C,QM, MW, SMW, AC,AIW

OUT : VW , T, C, QM,MW, SMW, AC, AIW

- IN1 IN2

Lnh ADD-DI (LAD)

+D (STL)

Lnh thc hin php cng cc s nguyn 32 bit IN1v IN2. Trong LAD kt qu l mt snguyn 32 bit c ghi vo OUT tc l :

IN1 + IN2 = OUT

Trong STL kt qu cng l mt gi tr 32 bit nhng c ghi vo IN2 tc l :

IN1 + IN2 = IN2

Lnh SUB_DI (LAD)

-D (STL)

SUB-IEN

IN1 OUT

IN2

ADD-IEN

IN1 OUT

IN2


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Lnh thc hin php tr cc s nguyn 32 bit IN1v IN2. Trong LAD kt qu l mt s nguyn32 bit c ghi vo OUT tc l :

IN1- IN2 = OUT

Trong STL kt qu cng l mt gi tr nguyn 32 bit nhng c ghi vo IN2 tc l :

IN1- IN2 = IN2

C php dng lnh cng tr hai s nguyn 32 bit trong LAD v STL nh sau :

LAD STL Ton hng

+ IN1 IN2

IN1,IN2 : VD, ID, QD,MD, SMD, AC,

OUT : VD, ID, QD,MD, SMD, AC,

- IN1 IN2

Lnh ADD _R (LAD)

+R (STL)

Lnh thc hin php cng cc s thc 32bit IN1v IN2 .Trong LAD kt qu l mt s thc 32

bit c ghi vo OUT tc l :IN1+IN2=OUT

Trong STL kt qu cng l mt gi tr thc 32 bit nhng c ghi vo IN2 tc l

IN1+IN2=IN2

Lnh SUB-R (LAD)

-R (STL)

Lnh thc hin php tr cc s thc 32bit IN1v IN2 .Trong LAD kt qu l mt s thc 32bit c ghi vo OUT tc l :

IN1-IN2=OUTTrong STL kt qu cng l mt gi tr thc 32 bit nhng c ghi vo IN2 tc l

IN1-IN2=IN2

C php dng lnh cng tr hai s thc 32 bit trong LAD v STL nh sau:

LAD STL Ton hng

SUB-DI

EN

IN1 OUT

IN2

ADD -DIEN

IN1 OUT

IN2


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+ IN1 IN2

IN1,IN2 : VD, ID, QD,MD, SMD, AC,

OUT : VD, ID, QD, MD,SMD, AC,

- IN1 IN2

Lnh MUL:*R (STL)

Trong LAD: Lnh thc hin php nhn hai s thc 32-bit IN1v IN2 v cho ra kt qu 32 bitcha trong t kp OUT (4byte).

Trong STL: Lnh thc hin php nhn hai s thc 32-bit IN1 v s nguyn cha trong t thp(t 0-bit 15)ca ton hng 32bit IN2.Kt qu 32 bit c ghi trong IN2.

C php dng lnh nhn hai s thc trong LAD v STL:

Lnh DIV:

Trong LAD: lnh thc hin php chia hai s nguyn 16-bit IN1v IN2 v cho ra kt qu 32bit cha trong t kp OUT (4byte) gm thng s ghi trong mng 16 bit t 0-15 (t thp) vphn d cng 16 bit ghi trong mng t bit 16 n 31(t cao)

Trong STL: Lnh thc hin php chia hai s nguyn 16-bit IN1 cho s nguyn 16 bit chatrong t thp (t 0-bit 15) ca ton hng 32bit IN2.Kt qu 32bit

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