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Prof. Cícero José – Anhanguera Uniban 2012
1
CAPÍTULO I – Matemática Básica
Expressões Numéricas 1) Calcule o valor das expressões abaixo: a) 20 – [(8 – 3) + 4] – 1 b) 123 – [90 – (38 + 50) – 1]
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c) 10 + [–8 – (–1 + 2)] d) –3 – [8 + (–6 – 3) + 1]
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e) 8 – (4 + 5) – [3 – (6 – 11)] f) –(–2) – [9 + (7 – 3 – 6) – 8]
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g) 1 + [–7 – (–2 + 6) + (–2)] – (–6 + 4) h) 6 – {4 + [–7 – (–3 – 9 + 10)]}
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Prof. Cícero José – Anhanguera Uniban 2012
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i) –3 – [(–1 + 6) + 4 – (–1 – 2) – 1] j) 2 – (–2) – {–6 – [–3 + (–3 + 5)]} – 8
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2) Calcule o valor das expressões abaixo: a) 21 – 15 : 5 – 12 + 3 + 1 b) (21 – 15) : (15 – 12 + 3) + 1
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c) 31 – 40 : 2 d) –10 – 20 : 4
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e) 30 : (–6) + (–18) : 3 f) 7 : (–7) + 2(–6) + 11
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3) Escreva a expressão numérica que representa cada situação abaixo: a) Um milionário, antes de morrer, deixou escrito no testamento: “Dos três milhões que tenho no
banco, deixo 1 milhão e 800 mil para instituições de caridade e o restante para ser repartido igualmente
entre meus três filhos”. Quanto recebeu cada filho?
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Prof. Cícero José – Anhanguera Uniban 2012
3
b) João tem 26 tickets refeição e André tem o triplo. Quantos tickets refeição têm os dois juntos?
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c) Dois operários, Paulo e Pedro, cobram juntos, R$ 385,00 por um trabalho a ser realizado em 5
dias. Paulo ganha R$ 32,00 por dia de trabalho. Quanto ganhou Pedro pelo trabalho?
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d) Gaspar comprou uma bicicleta pagando um total de R$ 960,00, sendo R$ 336,00 de entrada e o
restante em 8 prestações mensais iguais. Qual o valor de cada prestação?
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e) Em cada mão humana há 27 ossos e em cada pé, 26. Quantos ossos há, ao todo, nas mãos e nos
pés humanos?
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f) José mandou fazer, de alumínio, as janelas de sua casa. Deu uma entrada de R$ 250, 00 quando
fez a encomenda e o restante vai pagar em quatro parcelas iguais de R$ 140,00 cada uma. Qual a
quantia que José vai gastar para fazer as janelas?
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g) O preço de uma corrida de táxi é formado de duas partes: uma fixa, chamada “bandeirada”, e uma
variável, de acordo com o número de quilômetros percorridos. Em uma cidade, a “bandeirada” é de
R$ 4,00 e o preço por quilômetro percorrido é de R$ 2,00. Quanto pagará uma pessoa que percorrer, de
táxi, 12 quilômetros?
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h) Regina comprou roupas, gastando um total de R$ 814,00. Deu R$ 94,00 de entrada e o restante da
dívida vai pagar em 5 prestações mensais iguais. Qual é o valor de cada prestação?
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Prof. Cícero José – Anhanguera Uniban 2012
4
CAPÍTULO II – Cálculo Algébrico
Parte I – Monômios 4) Determine as seguintes somas algébricas: a) –5a + 3a b) xy + xy
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c) –ac – 5ac d) 10am – 13am
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e) –3a2 + 4a2 f) –xy2 + 7xy2
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g) 2bc – 15
bc h) 2 21 2x x
2 5−
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i) 3
mn 2mn4
− j) 3x – 10x + 11x
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k) –2y2 + 3y2 – 5y2 l) 6ab – 11ab + 6ab
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Prof. Cícero José – Anhanguera Uniban 2012
5
m) 5a2m – 12a2m + 7a2m n) –xy + 3xy + 4xy – 2xy
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o) –10n3 + 8 n3 – 7n3 + 12n3 p) –5am + 8am – 3am + am – 6am
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q) a4 + 4 42 3a a
3 2− r)
1 4 1bc bc bc
2 5 10− −
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____________________________________ ____________________________________ 5) Reduzindo os termos semelhantes, simplifique as expressões algébricas: a) 2y3 – 7y + y3 + 5y – y b) 5a – 10ab + 4b – 4a + 8ab
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c) 6x2 – 8x + 3x2 – 5 + 10x + 4 d) mn + 3m – 5n + 4mn – m + 6n – 2mn
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e) 2a2 – 5ab + 7b2 + 4ab – a2 + 2b2 f) x + y – 2 + 3x + 5 – 2y – x + 1 – y
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Prof. Cícero José – Anhanguera Uniban 2012
6
g) 1 2
a + b + a 2b2 3
− h) 2 21 1 1x + x + x + 3x x
2 4 8−
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6) Sabemos que um triângulo é equilátero quando todos os seus lados têm a mesma medida. Se você
representar a medida do lado do triângulo pela letra x, como poderá representar, de forma simbólica, o
perímetro desse triângulo?
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7) Escreva a expressão algébrica que representa cada situação abaixo: a) a soma do quadrado do número x com o quíntuplo do número y.
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b) a soma dos quadrados dos números x e y.
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c) o quadrado da soma dos números x e y.
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d) o produto da soma de a e b pela diferença desses dois números.
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e) o perímetro do retângulo de base a e altura h.
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f) a soma dos cubos dos números a e b.
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Prof. Cícero José – Anhanguera Uniban 2012
7
g) o cubo da soma dos números a e b.
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h) a diferença entre os quadrados dos números x e y.
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i) a terça parte do quadrado do número x.
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j) a diferença entre o número x e 5.
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8) Com vistas à reforma agrária, uma fazenda foi desapropriada pelo Governo Federal e dividida em
100 lotes, todos de forma quadrada e de mesma área, para distribuição entre os “sem-terra”. Determine
a expressão algébrica que expressa a área A do terreno em função da medida x do lado de cada lote.
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9) Duas lojas vendem o mesmo artigo pelo mesmo preço x para pagamento à vista. Para compra a
prazo, esse artigo tem preços diferentes:
Loja 1: entrada de 40% do preço x mais três prestações iguais de y reais.
Loja 2: entrada de 30% do preço x mais duas prestações iguais de y reais. Nessas condições, escreva o polinômio que expressa:
a) O preço do artigo comprado a prazo na loja 1.
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b) O preço do artigo comprado a prazo na loja 2.
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c) A diferença entre o preço na loja 1 e o preço na loja 2.
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10) Pedro é estagiário em uma empresa. Ele recebe R$ 5,87 a hora. No mês de agosto ele trabalhou 157
horas. Determine a expressão numérica que representa seu salário.
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Prof. Cícero José – Anhanguera Uniban 2012
8
11) Calcule o valor numérico das expressões abaixo:
a) 2a + 3b, para a = –2 e b = –3 b) x2 + 2x, para x = –5
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c) x + yx y−
, para x = 4 e y = –2 d) x y
+ 3 4
, para x = 9 e y = –8
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e) (x – y)2, para x = 9 e y = –3 f) (x + y)2, para x = 5 e y = –9
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12) Elimine os parênteses, os colchetes e as chaves e reduza os termos semelhantes. a) x – (–2y + 3x) + (5x – 4y)
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b) a2 – (–2a + 5) + a – (–3a2 + 4a – 1)
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Prof. Cícero José – Anhanguera Uniban 2012
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c) 10x3 – (x2 + 3x – 1) + (x3 – 3x2 + 2) – (4x – 3)
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d) 2a + [–5b + 2c – (a + 2b – c)] – (4b – 2c)
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e) x2 – [2xy + x2 – (y2 + 3xy) + 2y2] – xy
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f) ab – {–bc – [ac + (ab – ac – bc) + bc]}
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Prof. Cícero José – Anhanguera Uniban 2012
10
g) (a – x) + [(2a – x) – 7] – (a – 2x – 6)
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h) 2a + [(a – b) + (c – d)] + (b – c)
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i) 5x – {[3x – (7 – 5y)] + [x – (9 – 6y)] – (2x + y)}
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j) {(3x – y) – [(x – y) – (3x – 5y)]} – (2x – 4y)
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Prof. Cícero José – Anhanguera Uniban 2012
11
13) Determine os seguintes produtos: a) (–3y) � (+9y) b) (–2xy) � (–5x)
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c) (6b) � (4c) d) (x2y3) � (–xy2)
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e) (10xy3) � (x3) f) (4m2nx) � (–3mx2)
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g) 41 3x y xy
2 5� � � �−� � � �� � � �
� h) ( )25p q 2pq
8� �− −� �� �
�
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i) (–5x2) � (2x) � (–x3) j) (ax) � (–6a2) � (3x)
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k) (–2a) � (–5b) � (–6ab3) l) (–mx2) � (xy2) � (mxy2)
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m) 2 21 1xy x y
2 3� � � �� � � �� � � �
� � (–6xy) n) 22 1hx h
3 5� � � �− −� � � �� � � �
� � (–hxy)
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Prof. Cícero José – Anhanguera Uniban 2012
12
o) (–kx2) � (–2kx) � (–5x) � (3) p) 1 1
3 anp 2 bnx3 4
� � � �−� � � �� � � �
�
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14) Determine os seguintes quocientes: a) (–24y5) : (–6y2) b) (5x3) : (x) c) (–18a2) : (6a2)
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d) (–2x2) : (–2x) e) (6a4) : (–6a4) f) (10xy) : (5x)
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g) (a4b2c) : (–abc) h) (–4m2n2) : (–mn2) i) (–a4b2) : (2a3b)
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j) 5 41 1x : x
3 5� � � �� � � �� � � �
k) 32 4mn : mn
3 3� � � �−� � � �� � � �
l) ( )1ab : 2b
4� �− −� �� �
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Prof. Cícero José – Anhanguera Uniban 2012
13
m) (2a3b5c2) : 1
abc3
� �−� �� �
n) (a4b4c) : (a3b2)
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15) Determine as seguintes potências: a) (–4x3y)2 b) (–mx2)3 c) (2ac3)5 d) (–3b2c)4
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e) (–h2m)6 f)
341
y2
� �−� �� �
g) 2
2mn
5� �−� �� �
h) (x2y5)5
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i) (–2a3)10 j) (–4a3c)0 k) 6
31a
2� �−� �� �
l) (–0,5x4y7)2
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Prof. Cícero José – Anhanguera Uniban 2012
14
Parte II – Polinômios
Polinômios 16) Dados A = 2m2 + 5m + 3, B = 4m2 – 2m + 1 e C = –3m2 – m + 3, determine: a) A – B
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b) B – A
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c) A – C
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d) B – C
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e) C – A
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Prof. Cícero José – Anhanguera Uniban 2012
15
f) C – B
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17) Calcule:
a) 1 1 3
y c c a2 2 4
� � � �− − −� � � �� � � �
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b) 4 2 4 23 1x x + x x +
5 2� � � �− − −� � � �� � � �
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c) 3 31 15m m + + m 7m
4 2� � � �− −� � � �� � � �
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Prof. Cícero José – Anhanguera Uniban 2012
16
d) 2 21 1 3x 2x + 1 + x +
2 2 2� � � �−� � � �� � � �
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18) O número de cada retângulo é obtido adicionando os números dos dois retângulos situados abaixo.
Escreva uma expressão simplificada no retângulo colorido superior.
a) b) c)
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19) Calcule os seguintes produtos: a) 5x � (ax2 + bx + c)
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b) –3xy2 � (5x + 6y – 7xy)
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3 x 2x
3 + x
–2x –7 –x
–7 – x
x 3x
1 + x
212
Prof. Cícero José – Anhanguera Uniban 2012
17
c) mn � (m2 – mn + n2)
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d) (3a – 4b + 5c) � 2x
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e) (–a + 3b – 5c) � (–7ax)
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f) (3x2 – 2x + 1) � 2x
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g) 3x2
� (8x2 + 6x + 5)
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20) Dados os polinômios A = x – 5, B = x2 – 7x + 12 e C = x2 – 6, determine: a) A � B b) A � C
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Prof. Cícero José – Anhanguera Uniban 2012
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c) B � C d) (A + B) � C
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e) (C – A) � B f) (A + B – C) � B
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21) (Saresp-SP) Qual expressão algébrica representa a área da figura? _________________________________________________________________________________ _________________________________________________________________________________ _________________________________________________________________________________ _________________________________________________________________________________ _________________________________________________________________________________ _________________________________________________________________________________ _________________________________________________________________________________ _________________________________________________________________________________ _________________________________________________________________________________ _________________________________________________________________________________
a
a a
a
a2
a2
b
Prof. Cícero José – Anhanguera Uniban 2012
19
22) Calcule os quocientes: a) (12x2 + 9x) : 3x b) (–6x2 + 4x) : 2x
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c) (x4 + 5x3 + x2 – 4x) : x d) (–8a4 + 6a3 – 10a) : (–2a)
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e) (–10m4 + 35m3 – 15m2) : (–5m) f) (40x2 – 20x – 3ax) : (–10x)
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23) Efetue as divisões de polinômios: a) (x2 + 9x + 14) : (x + 7) b) (6x2 – 13x + 8) : (3x – 2)
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Prof. Cícero José – Anhanguera Uniban 2012
20
c) (12x2 – 11x – 15) : (4x + 3) d) (2x3 – 5x2 + 6x – 4) : (x – 1)
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e) (–15x3 + 29x2 – 33x + 28) : (3x – 4) f) (x3 – 6x2 – x + 30) : (x2 – x – 6)
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g) (2x4 + 3x3 – x2 + 7x – 3) : (2x2 – x + 3) h) (–8x4 – 8x3 + 6x2 – 16x + 8) : (4x3 + 6x2 + 8)
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Prof. Cícero José – Anhanguera Uniban 2012
21
i) (3x3 – 30x + 2) : (x2 – 3x + 1) j) (x4 + x2 – 3x + 1) : (x2 – x – 1)
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k) (8x4 – 6x2 + 3x – 2) : (2x2 – 3x + 2) l) (x3 – 64) : (x – 4)
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24) Escreva o polinômio que permite calcular a área da parte colorida da figura. _________________________________________________________________________________
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3x 5 x x 4
2x
Prof. Cícero José – Anhanguera Uniban 2012
22
25) (Saresp-SP) Numa padaria há um cartaz afixado em que constam os seguintes itens:
LEITE R$ 0,70 PÃO R$ 0,12
Joana comprou uma quantidade x de litros de leite e uma quantidade y de pães. Determine a expressão
algébrica que representa essa compra.
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26) O tangran é um jogo chinês de formas, uma espécie de
quebracabeças, que consta de sete peças com as quais se podem compor
numerosas figuras. Na foto, as sete peças formam um quadrado.
Determina a área de cada peça, sabendo-se que a soma de todas as áreas
corresponde a 4x2.
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Brincando... com a álgebra 27) Pense em um número inteiro de 20 a 29. Some os algarismos do número. Agora, subtraia essa
soma do número pensado.
a) Qual vai ser o resultado?
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b) Imaginando que o número pensado seja 20 + x, efetue os cálculos algébricos para mostrar que o
resultado é sempre o mesmo.
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1 2 3
4 5
6
7
x
x
2x
Prof. Cícero José – Anhanguera Uniban 2012
23
28) No exercício anterior, se o número pensado for um número inteiro de 30 a 39, qual será o resultado
final?
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29) Se você escrever um número natural, de 40 a 49, multiplicá-lo por 10 e subtrair 396, você obterá o
mesmo número, mas com a ordem dos algarismos invertida.
a) Faça esse truque com o número 46. Qual será o resultado?
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b) Utilizando a álgebra, explique por que esse truque sempre dá certo.
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30) Com três números naturais consecutivos acontece uma pequena surpresa. Multiplicando o menor
pelo maior e depois somando 1, obtém-se o número do meio, elevado ao quadrado.
a) Mostre que isso acontece com os números 6, 7 e 8.
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b) Mostre que isso acontece sempre, utilizando os números x – 1, x e x + 1.
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Prof. Cícero José – Anhanguera Uniban 2012
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31) Veja o desafio da professora:
• Pense em número natural. Some 3. Multiplique o resultado pelo número pensado.
• Agora, some 2. Divida o resultado pelo sucessor do número pensado.
• No final, deu o número pensado, mais 2, não é? Mostre que isso sempre acontece, usando
álgebra.
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32) Efetue a seguinte sequência de cálculos: Pense em um número real x, não-nulo. Some 7.
Multiplique o resultado por 5. Subtraia 35. Divida o resultado pelo número pensado. Qual é o resultado
final?
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33) Pense em um número natural qualquer. Some 5. Multiplique por 3. Subtraia 12. Divida por 3. O
resultado é o sucessor do número que você pensou. Usando álgebra, explique por que isso sempre
acontece.
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Prof. Cícero José – Anhanguera Uniban 2012
25
34) Adivinhando data de aniversário: – Multiplique o número do mês por 5 e adicione 7.
– Multiplique por 4 e adicione 13.
– Multiplique por 5.
– Adicione o dia do mês correspondente ao seu aniversário.
– Agora subtraia 205 da resposta. Os dois primeiros números representam o mês do seu aniversário e dois últimos representam o dia do
seu nascimento. Usando álgebra, explique por que isso sempre acontece.
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35) – Pense em um número inteiro de 10 a 19, mas não me diga qual é. Some os dois algarismos.
– Agora, subtraia essa soma do número que você pensou.
– Agora, eu vou adivinhar o resultado que você encontrou. O resultado é nove! Certo?
Usando álgebra, explique por que isso sempre acontece.
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Prof. Cícero José – Anhanguera Uniban 2012
26
CAPÍTULO III – Produtos Notáveis
36) Desenvolva os seguintes produtos notáveis: a) (x2 + y3)2 b) (5ax2 + 6a3)2
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c) (4a3x + 2by)2 d) (a2 + 5am)2
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e) (x6 + 3x2)2 f)
25x 2y
+ 3 3
� �� �� �
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____________________________________ ___________________________________
g) 2
4 13x +
3� �� �� �
h) 223a
+ a4
� �� �� �
____________________________________ ___________________________________ ___________________________________ ___________________________________ ____________________________________ ___________________________________
____________________________________ ___________________________________
____________________________________ ___________________________________ ____________________________________ ___________________________________
i) 23 4x x
+ 3 4
� �� �� �
j) 22 2ab a b
+ 3 3
� �� �� �
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Prof. Cícero José – Anhanguera Uniban 2012
27
k) (a3 – 4a)2 l) (3x2 – 5xy)2
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m) (5a2 – 4b2)2 n) (x3 – y3)2
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o) (2ax2 – 4a2x2) p)
23 4
x3
� �−� �� �
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____________________________________ ___________________________________
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q) 2
2 32 1a b a x
3 2� �−� �� �
r) 22 2m x 3y
4 5� �
−� �� �
____________________________________ ___________________________________ ___________________________________ ___________________________________ ____________________________________ ___________________________________
____________________________________ ___________________________________
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s) 232a x 5by
3 2� �
−� �� �
t) 26x 5
+ 2 4
� �� �� �
____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________
Prof. Cícero José – Anhanguera Uniban 2012
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37) Desenvolva os seguintes produtos notáveis: a) (a2 – 1) (a2 + 1) b) (a3b2 + c) (a3b2 – c)
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c) (x3 + y3) (x3 – y3) d) (5a3b + 2xy2) ((5a3b – 2xy2)
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e) (x2y4 – 5x) (x2y4 + 5x) f)
2 2x 3 x 3 +
5 4 5 4� �� �
−� �� �� �� �
____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________
g) 2 23m 1 3m 1
+ 2 3 2 3
� �� �−� �� �
� �� � h) 3 3b b
a + a5 5
� �� �−� �� �� �� �
____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________
i) 2 25x 5x
+ 6 63 3
� �� �−� �� �
� �� � j)
4 4x x + 6 6 +
3 3� �� �
−� �� �� �� �
____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________
Prof. Cícero José – Anhanguera Uniban 2012
29
38) Desenvolva os seguintes produtos notáveis: a) (a2 + b2)3 b) (2ax + 3a2)3
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c) (x3 + x)3
d) 3
3x 1 +
2 3� �� �� �
____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________
e) 32a b
+ 4 3
� �� �� �
f) 32ax bx
+ 2 3
� �� �� �
____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________ g) (x2 – y3)3 h) (3a2 – b3x)3
___________________________________
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i) (m2 – 3xy2)3
j) 22x 3
3 4� �
−� �� �
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Prof. Cícero José – Anhanguera Uniban 2012
30
k) 331 a
2 4� �
−� �� �
l) 32x y
2 3� �
−� �� �
____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________ 39) Desenvolva os seguintes produtos notáveis: a) (x + y + 3)2 b) (x2 + y + 1)2
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c) (2x – y – 1)2 d) (x – 4y + 3)2
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e) (m5 – 1)2 f)
21
8xy4
� �−� �� �
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g) (x + 5)3 h) (x – c)3
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31
i) (5x5 + 2x)2 j) 2 21 1
5m + 5m2 2
� �� �−� �� �� �� �
____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________ k) (5m3x – 7n3z2)(5m3x + 7n3z2) l) (3a + 2y)2
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m) 2
2 33m 5n
2� �−� �� �
n) 2 24 2 4 2a b a b +
5 9 5 9� �� �−� �� �� �� �
____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________
o) 3
1xy 3x
3� �−� �� �
p) 2
2 12x + y
2� �� �� �
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___________________________________
____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________ 40) Calcule os seguintes produtos, utilizando o produto de Stevin: a) (x + 6)(x + 4) b) (a – 3)(a – 5) c) (y – 7)(y + 3)
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d) (m – 12)(m + 8) e) (x – 9)(x + 5) f) (x + 15)(x + 3)
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g) (b – 4)(b + 20) h) (k – 8)(k – 13) i) (x + 11)(x – 6)
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j) (u – 4)(u + 15)
k) 1 3
x + x + 2 4
� �� �� �� �� �� �
____________________________________ ___________________________________ ___________________________________ ___________________________________ ____________________________________ ___________________________________ ___________________________________ ___________________________________ ____________________________________ ___________________________________
l) 3 5
x x + 5 3
� �� �−� �� �� �� �
m) ( )2x + x 9
3� � −� �� �
____________________________________ ___________________________________ ___________________________________ ___________________________________ ____________________________________ ___________________________________ ___________________________________ ___________________________________ ____________________________________ ___________________________________
n) 2 3
x x5 2
� �� �− −� �� �� �� �
o) ( )7x + x 2
3� � −� �� �
p) 3 7
x + x4 4
� �� �−� �� �� �� �
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Prof. Cícero José – Anhanguera Uniban 2012
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41) Qual é o valor de x2 + y2, sabendo que x + y = 7 e xy = 10?
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42) Qual é o valor de 22
1x +
x, sabendo que
1x
x− = 9.
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43) Qual é o valor de x2 + y2, sabendo que x – y = 15 e xy = 100?
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44) Usando produto notável, calcule: a) 51 � 49 b) 202 � 198 c) 77 � 63 d) 21 � 19
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45) Qual é o valor de 22
14x +
x, sabendo que
12x
x− = 20?
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Prof. Cícero José – Anhanguera Uniban 2012
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46) Qual é o valor de x – y, sabendo que x2 – y2 = 800 e x + y = 100?
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47) Sendo A = (x + 2)2, B = (x + 3)(x – 3) e C = (x – 1)2, determine o valor de A + B – C.
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48) Sabendo que 1
aa
− = 3, calcule o valor de 22
1a +
a.
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49) Mostre que a diferença entre os quadrados da soma e da diferença de dois números inteiros não
nulos é sempre divisível por cada um deles e pelo número quatro.
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Prof. Cícero José – Anhanguera Uniban 2012
35
50) Sendo A = 2
1x +
x� �� �� �
e B = 2
1x
x� �−� �� �
, determine o valores de (A – B)2 e (A + B)2.
_________________________________________________________________________________ _________________________________________________________________________________ _________________________________________________________________________________ _________________________________________________________________________________ _________________________________________________________________________________ _________________________________________________________________________________ _________________________________________________________________________________ _________________________________________________________________________________ 51) Sendo S = ( )( )x + 7 x 7− , P = (x – 3)2 – 12 e Q = (x + 5)(x – 2)(x – 1), determine Q – (S + P).
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52) Sendo 1
a + a
= 35
, determine o valor de 33
1a +
a.
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53) (Olimpíada Bras. de Matemática) Se x + y = 8 e xy = 15, qual é o valor de x2 + 6xy + y2?
a) 109 b) 120 c) 124 d) 154 _________________________________________________________________________________
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Prof. Cícero José – Anhanguera Uniban 2012
36
CAPÍTULO IV – Fatoração
54) Fatore os seguintes polinômios. a) a3 – ax b) 5ax – 5a3x2 c) 7p2 + p
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d) 15a2 – 225a4 e) 15 + 25x2 f) 6x3 + 2x4 + 4x5
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g) 2x2y3 – 6x2y2 + 2xy3 h) 3a4 – 3a3b + 6a2b2 i) 5x5 – 10a2x3 – 15a3x3
_______________________ _______________________ _______________________
_______________________ _______________________ _______________________
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_______________________ _______________________ _______________________
j) 6x3 – 9x2y + 12xy2
k) 5 2 4 2 21 1 1a b c + a b + a b
12 6 2−
____________________________________ ___________________________________ ___________________________________ ___________________________________ ____________________________________ ___________________________________ ___________________________________ ___________________________________ ____________________________________ ___________________________________
l) 5 4 5 4 6 3 71 1 1a m n m n + m n
20 20 8− m) 2 3 2 3 2 56 9 9
h k x h k y + h k15 20 10
−
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Prof. Cícero José – Anhanguera Uniban 2012
37
n) 7 4 3 7 5 92 1 2a b a b + a b
15 12 3− o) 2 10 6 9 2 46 12 18
y z + y z y z35 45 25
−
____________________________________ ___________________________________ ___________________________________ ___________________________________ ____________________________________ ___________________________________ ___________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________ ____________________________________ ___________________________________ 55) Fatore os seguintes polinômios. a) a2 + ab + ac + bc b) 2x + cx + 2c + c2
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c) 5a + ab + 5b + b2 d) mx – my – nx + ny
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e) a2 – ac + ax – cx f) 3ax – bx – 3ay + by
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g) 6x2 + 3xy – 2ax – ay h) ax2 – 3bxy – axy + 3by2
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Prof. Cícero José – Anhanguera Uniban 2012
38
i) x2 – 3x – xy + 3y j) x4 + x3 + 2x + 2
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k) 3 21 1 1 1a + a + a +
3 5 3 5 l) 2 21 1
x + mxy xy my4 4
− −
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m) 3
2m m 2 2m +
2 6 3 9− −
n) 6am + 4m + 15an + 10n
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o) a5 – a2b + a3 – b p) 36am + 45an + 4m + 5n
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56) Fatore os seguintes polinômios. a) r2 – x2 b) a2 – 4 c) m2 – 9 d) b2 – 16
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39
e) 25 – y2 f) 16 – x4 g) a4 – 100 h) n2p2 – 1
________________ ________________ ________________ _______________
________________ ________________ ________________ _______________
________________ ________________ ________________ _______________
________________ ________________ ________________ _______________
i) x4 – y4 j) 16x2 – 25y2 k) x6 – 144a4 l) x4 – a2b2
________________ ________________ ________________ _______________
________________ ________________ ________________ _______________
________________ ________________ ________________ _______________
________________ ________________ ________________ _______________
m) 9a4 – 16n2 n) 21
y4
− o) 2 2a b
9 16− p)
2 2
2 2
x ya b
−
________________ ________________ ________________ _______________ ________________ ________________ ________________ _______________ ________________ ________________ ________________ _______________ ________________ ________________ ________________ _______________
q) 2 2 2 2m r x p
16 25−
r) (a – b)2 – (a + b)2
___________________________________ ___________________________________ ___________________________________ ___________________________________
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s) (1 + a)2 – (1 – a)2 t) (a – 2)2 – (a + 3)2
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57) Fatore os seguintes polinômios, quando possível. a) 4x2 + 4x + 1 b) x2 + 10x + 25 c) 4x4 + 4x2y3 + y6 _______________________ _______________________ _______________________
_______________________ _______________________ _______________________
_______________________ _______________________ _______________________
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40
d) 16 – 8x + x2 e) 36m2n4 – 24mn2x3 + 4x6 f) 25x4y2 – 20x2yp3 + 4p6 _______________________ _______________________ _______________________
_______________________ _______________________ _______________________
_______________________ _______________________ _______________________
g) 4x10 + 12x5y2m + 9y4m2 h) 4x2 + 1 – 4x i) x2 + a2 – 2ax _______________________ _______________________ _______________________
_______________________ _______________________ _______________________
_______________________ _______________________ _______________________
j) 6 3 29 12x + x y + 4y
25 5 k) 8 41 9
m m + 9 4
−
___________________________________ ___________________________________ ___________________________________ ___________________________________
___________________________________ ___________________________________ ___________________________________ ___________________________________
l) 6 3 4 2 8 41 1 1a + a b c + b c
16 4 4 m) 6 3 24 1
4x + x y + y3 9
___________________________________ ___________________________________ ___________________________________ ___________________________________
___________________________________ ___________________________________ ___________________________________ ___________________________________
n) 36m4y6 + 6m2y5x + 2 41x y
4
o) x2 + y8 – 2y4x
___________________________________ ___________________________________ ___________________________________ ___________________________________
___________________________________ ___________________________________ ___________________________________ ___________________________________
p) a2 + 4ab + 9b2 q) 4x2 – 4x + 1 r) a2 – ab + b2
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_______________________ _______________________ _______________________
_______________________ _______________________ _______________________
s) 16x2 – 20xy + 9y2 t) a2 + b + 14
u) 21 2x + x + 1
9 3
_______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________
Prof. Cícero José – Anhanguera Uniban 2012
41
58) Fatore os seguintes trinômios. a) x2 + 7x + 12 b) x2 + 7x + 10 c) x2 – 7x + 6 d) x2 – 6x + 8
________________ ________________ ________________ _______________
________________ ________________ ________________ _______________
________________ ________________ ________________ _______________
e) x2 – 9x + 14 f) x2 + x – 12 g) x2 – 9x + 18 h) x2 – 9x + 8
________________ ________________ ________________ _______________
________________ ________________ ________________ _______________
________________ ________________ ________________ _______________
i) x2 – x – 12 j) x2 + 4x – 12 k) x2 + 7x – 8 l) x2 – 2x – 15
________________ ________________ ________________ _______________
________________ ________________ ________________ _______________
________________ ________________ ________________ _______________
m) x2 + x – 6 n) x2 – 5x + 4 o) y2 – 11y – 12 p) m2 – 13m + 12
________________ ________________ ________________ _______________
________________ ________________ ________________ _______________
________________ ________________ ________________ _______________
q) t2 + 8t + 12 r) a2 – 2a – 8 s) k2 + 13k + 40 t) z2 – 7z – 8
________________ ________________ ________________ _______________
________________ ________________ ________________ _______________
________________ ________________ ________________ _______________
59) Aplicando os casos de fatoração estudados, fatore os polinômios. a) x2 + 5x b) 4x2 – 12x + 9 c) x3 – 2x2 + 4x – 8
_______________________ _______________________ _______________________
_______________________ _______________________ _______________________
_______________________ _______________________ _______________________
d) 4x2 – 9 e) a6 – 5a5 + 6a3 f) ax – a + bx – b
_______________________ _______________________ _______________________
_______________________ _______________________ _______________________
_______________________ _______________________ _______________________
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g) 64y2 + 80y + 25 h) a3b2 + a2b3 i) m6 – 1
_______________________ _______________________ _______________________
_______________________ _______________________ _______________________
_______________________ _______________________ _______________________
j) 4a2x2 – 4abx + b2 k) 12a2b + 18a l) x3 – x2y + xy – y2
_______________________ _______________________ _______________________
_______________________ _______________________ _______________________
_______________________ _______________________ _______________________
m) (x + 1)2 – 9 n) a2bc + ab2c + abc2 o) 25x2 + 70x + 49
_______________________ _______________________ _______________________
_______________________ _______________________ _______________________
_______________________ _______________________ _______________________
p) 1 – (a + b)2 q) x6 + x4 + x2 + 1 r) 15a3m – 20a2m
_______________________ _______________________ _______________________
_______________________ _______________________ _______________________
_______________________ _______________________ _______________________
s) 21m
4– 25n2
t) 81y2 + 18y + 1
___________________________________ ___________________________________ ___________________________________ ___________________________________
___________________________________ ___________________________________ ___________________________________ ___________________________________
u) x2 + 3x + 2 v) m2 + 3m – 4
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___________________________________
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w) m2 – 2m – 3 x) x2 + 3x – 10 y) m2 – m – 2 z) x2 – 13x + 36
________________ ________________ ________________ _______________
________________ ________________ ________________ _______________
________________ ________________ ________________ _______________
Prof. Cícero José – Anhanguera Uniban 2012
43
60) Fatore os seguintes polinômios, usando sucessivamente os casos de fatoração. a) 10a2 – 10 b) x3 – 10x2 + 25x c) 2m2 – 8
_______________________ _______________________ _______________________
_______________________ _______________________ _______________________
_______________________ _______________________ _______________________
d) ay2 + 4ay + 4a e) h4 – m4 f) x2y – 36y
_______________________ _______________________ _______________________
_______________________ _______________________ _______________________
_______________________ _______________________ _______________________
g) ab2 – a + b2c – c h) x4 + 2x3 + x2 i) 81 – k4
_______________________ _______________________ _______________________
_______________________ _______________________ _______________________
_______________________ _______________________ _______________________
j) x3y – 8x2y2 + 16xy3 k) x2y – 8xy + 16y l) 4z2 – 120z + 900
_______________________ _______________________ _______________________
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m) 5x2 – 20 n) 4x2z – 25z o) 12ax4 – 24a2x2 + 12a3
_______________________ _______________________ _______________________
_______________________ _______________________ _______________________
_______________________ _______________________ _______________________
p) 4x3 – 8x2 + 4x q) a3 + a2 – 4a – 4 r) x6 – y6
_______________________ _______________________ _______________________
_______________________
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s) 3(a + b – c)2 – 3(a – b + c)2 t) x3 – 6x2 + 9x – x5
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61) (Furb–SC) Um professor de Matemática tem 4 filhos. Em uma de suas aulas, ele propôs aos alunos
que descobrissem o valor da expressao ac + ad + bc + bd, sendo que a, b, c e d são as idades de seus
filhos na ordem crescente. O professor disse, também, que a soma das idades dos dois mais velhos é 59
anos e a soma das idades dos dois mais novos é 34 anos. Qual o valor numérico da expressão proposta
pelo professor?
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62) Efetue: a) 502 – 492 b) 20002 – 19992 c) 502 – 482
_______________________ _______________________ _______________________
_______________________
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d) 20012 – 20002 e)
2 2123 456 123 455123 456 + 123 455
−.
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63) Multiplique um número natural pelo sucessor de seu sucessor. (Por exemplo, 3 . 5 ou 9 . 11). Some
1 ao resultado. Aí, extraia a raiz quadrada. Surpresa! Essa raiz quadrada é sempre um número inteiro.
Usando álgebra, explique por que isso acontece.
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__________________________________________________________________________________
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64) A diferença dos quadrados de dois inteiros consecutivos pode ser um número par?
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65) Determine o valor de 2
2 2
1 000252 248−
.
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66) x e y são as medidas dos lados de um retângulo de área 20 e perímetro 18. Qual é o valor numérico
da expressão 3x2y + 3xy2?
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67) Fatore as seguintes expressões: a) x9 + y6 b) m6 + 8n12 c) y12 – 27
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_______________________
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_______________________
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_______________________
x
y
Prof. Cícero José – Anhanguera Uniban 2012
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d) 8a3 – 27b3 e) 64 + a6 f) 125x6 – 1
_______________________ _______________________ _______________________
_______________________ _______________________ _______________________
g) x6y3 – a9b12
h) 9x 64
+ 8 27
i) 3 15a m
1125
−
_______________________ _______________________ _______________________ _______________________ _______________________
_______________________ _______________________
_______________________ _______________________
_______________________ _______________________ _______________________ _______________________ _______________________
_______________________ _______________________
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j) 12 98x 216a
+ 27 125
k) 27a6 – 31b
8 =
___________________________________ ___________________________________ ___________________________________ ___________________________________
___________________________________ ___________________________________ ___________________________________ ___________________________________
___________________________________ ___________________________________ 68) (SEE-RJ) O resultado de uma expressão é a2 – b2.
• Sílvio encontrou como resposta (a – b)2;
• Cláudio, (a + b)(a – b);
• Célia, (a + b)2 – 2b2 Como o professor aceita o desenvolvimento incompleto da resposta, podemos afirmar que:
a) apenas Sílvio acertou.
b) apenas Cláudio acertou.
c) apenas Célia acertou.
d) apenas os rapazes acertaram.
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69) Calcule: a) 31 � 29 b) 21 � 19 c) 22 � 18 d) 91 � 89
________________ ________________ ________________ _______________
________________ ________________ ________________ _______________
________________ ________________ ________________ _______________
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e) 102 � 98 f) 103 � 97 g) 108 � 92 h) 42 � 38
________________ ________________ ________________ _______________
________________ ________________ ________________ _______________
________________ ________________ ________________ _______________
i) 28 � 32 j) 55 � 45 k) 51 � 49
_______________________ _______________________ _______________________
_______________________ _______________________ _______________________
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70) Simplifique a expressão: E = ( )426 24− � ( )4
26 + 24 .
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________________________________________________________________________________
71) O valor da expressão 2 24a 4b
3(a + b)(a b)−
−para a = 3,7 e b = 2,9 é:
a) 43
b) 43
− c) 209
d) 209
−
________________________________________________________________________________ ________________________________________________________________________________ ________________________________________________________________________________ ________________________________________________________________________________ ________________________________________________________________________________ ________________________________________________________________________________
72) Se x = 3 + 1, calcule x2 – 2x + 1.
a) 3 b) 3 c) 4 + 4 3 d) 4
________________________________________________________________________________
________________________________________________________________________________
________________________________________________________________________________
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CAPÍTULO V – Frações Algébricas
73) Determine o mdc e o mmc dos monômios: a) 12x2, 9x3 b) 8m2n, 20mn3
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c) 16x2, 20x, 10x3 d) 3x, 6x2y, 9y3
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e) 12a2x, 16ax3, 20a2x2 f) 6a3b, 9ab2c, 15a2b4c2
___________________________________
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g) 2x5, 5x3, 4x4 h) 60ay2, 24a3y, 12a2y4
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74) Determine o mdc e o mmc das seguintes expressões algébricas: a) 4x, 2x – 2 b) ab, ab + bc
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c) 3xy, 5x2 + 5xy d) 2ax, a2 – a, ax – a
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e) x + 1, x2 – 1 f) ax + bx, a2 + 2ab + b2
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g) x2 + xy, xy + y2, x2 – y2 h) 5x + 10, 2x + 4, 3x + 6
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i) x2 – 25, x2 – 10x + 25, 5x – 25 j) 5x, x2 – 2x, x2 + 2x
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___________________________________ ___________________________________
k) x2 – a2, 2x + 2a, x2 + ax l) x + 3, x2 – 9, 2x + 6
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m) 4 – 4a + a2, 4 – a2, 2a2 – a3 n) 2x2 – 2, 2x2 – 4x + 2
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o) a2 – 1, 2a + 2, a + 1 p) 2x, x2 + x, x2 – x, x2 – 1
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75) Simplifique as seguintes frações algébricas:
a) 2a
ab b)
6x12y
c) 2 2
abcb c
d) 2
2
5x y10xy
________________ ________________ ________________ _______________ ________________ ________________ ________________ _______________ ________________ ________________ ________________ _______________ ________________ ________________ ________________ _______________ ________________ ________________ ________________ _______________
e) 3 2
2 2
4a m12a m
f) 3 2
2
6a c9a bc
g) 2
mm + m
h) 2
ac + bcc
________________ ________________ ________________ _______________ ________________ ________________ ________________ _______________ ________________ ________________ ________________ _______________ ________________ ________________ ________________ _______________ ________________ ________________ ________________ _______________
i) 2
2ab2a + 2a
j) 2x + 2yax + ay
k) 2 2
a xa x
−−
l) 2x + x
xy + y
________________ ________________ ________________ _______________ ________________ ________________ ________________ _______________ ________________ ________________ ________________ _______________ ________________ ________________ ________________ _______________ ________________ ________________ ________________ _______________
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m) 2
1 + 2a4a 1−
n) 2c + 3c
2c + 6 o)
2
2 2
h + bha b−
p) 2
2
x + 6x + 9x 9−
________________ ________________ ________________ _______________ ________________ ________________ ________________ _______________ ________________ ________________ ________________ _______________ ________________ ________________ ________________ _______________ ________________ ________________ ________________ _______________
q) 2
4
2x + 2x 1−
r) 3
6
x 1x 1
−−
s) bx + cx + by + cy
ax + ay
_______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________
t) 2
2 2
x xyx 2xy + y
−−
u) 2x 16
5x + 20−
v) 3 2
2
x + x + x + 1x 1−
_______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________
w) 24x + 8ax
2x + 4a x)
2 2
3 3
x + xy + yx y−
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76) Determine as seguintes somas algébricas:
a) x 3x
+ 5a 10a
b) 3x 5x x
+ 4y 6y 3y
− c) 2
1 2 + + 1
x x
_______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________
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d) 3a 2b
+ b a
e) 2
2 5 1 +
a a 2− f)
1 1 1 + +
x y xy
_______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________
g) a 1 a + 1
+ a 2−
h) x + a a x
x a−− i)
x + y x y +
2x 2y−
_______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________
j) 2
1 x +
x + 2 x 4− k)
1x + 1
x 1−
−
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___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________
l) a b 2a
+ a + b a b
−−
m) 2
2
x 5y 5y +
x + y xy + y−
___________________________________ ___________________________________ ___________________________________ ___________________________________
___________________________________ ___________________________________ ___________________________________ ___________________________________
___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________
Prof. Cícero José – Anhanguera Uniban 2012
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n) 2
2
1 + a 4a 1 a +
1 a 1 a 1 + a−−
− − o)
2
2 2
a aa b a b
−− −
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___________________________________ ___________________________________ ___________________________________ ___________________________________
___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________
77) Determine os seguintes produtos:
a) 2a 2
3x y� b) 2
x y
2a a� c) 2
am xy
x a�
_______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________
d) 3
2
3a x
x 6a� e)
3 2 2
3 2
a b 2x y
10xy a c� f)
2 2x y ab 2
a x by� �
_______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________
g) x + 2 x 1
x 2x
−� h)
x y
x y x + y−� i)
2 2a a b
a b ab−
−�
_______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________
Prof. Cícero José – Anhanguera Uniban 2012
54
j) 2
9x a + 2
a 4 3x−� k) 2 2
ax + x 3x 3y
x y a + 1−
−� l)
3
4 2
5a + 5 x
x + x a + 1�
_______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________
m) 2 2
2 2
a + 2ax + x m n
m n a + x−
−� n)
2
4
x + 1 ab + a 4x + 4
4 x 1 a−� �
___________________________________ ___________________________________ ___________________________________ ___________________________________
___________________________________ ___________________________________ ___________________________________ ___________________________________
___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________
78) Determine os seguintes quocientes:
a) 3x b
: a x
b) 5a 10
: bc c
c) 2
3a a :
4b b
_______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________
d) 6a 2
: 5bc abc
e) 3
1 2x :
xy y f)
3 2
2 2
8m 4mb :
3ax 3x
_______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________
Prof. Cícero José – Anhanguera Uniban 2012
55
g) 2
2
a a :
x + 1 x 1− h)
x + y 2x + 2y :
x y 2− i) 2 2
am m :
a m a + m−
_______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________
j) 2x 25 2x + 10
: xy x−
k) 23a 3a
: c + 1 2c + 2
l) 2
2
x 2x + 1 x 1 :
x + 2x x− −
_______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________
m) 2 2
2
4 + 4a + a a 4 :
1 b b + 1−
− n)
2 3 2
2
a + a + 1 a + a + a :
a + 1 a 1−
___________________________________ ___________________________________ ___________________________________ ___________________________________
___________________________________ ___________________________________ ___________________________________ ___________________________________
___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________
o)
2
1a1a
p) 2
2
xyaxa
___________________________________ ___________________________________ ___________________________________ ___________________________________
___________________________________ ___________________________________ ___________________________________ ___________________________________
___________________________________ ___________________________________
q)
2
aa 22a
a 4
−
−
r) 2
x + yxy
x + xyy
___________________________________ ___________________________________ ___________________________________ ___________________________________
___________________________________ ___________________________________ ___________________________________ ___________________________________
___________________________________ ___________________________________
Prof. Cícero José – Anhanguera Uniban 2012
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79) Determine as seguintes potências:
a) 2
2ax
� �� �� �
b) 23x
y� �� �� �
c) 3
xy2a
� �� �� �
_______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________
d) 32
3
m nx
� �� �� �
e) 4
2
1a c� �� �� �
f) 3
1x + 2
� �� �� �
_______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________
g) 2
a + b2c
� �� �� �
h) 2
3
x ya−� �
� �� �
i) 2
x + ax y
� �� �−� �
_______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________
j) 1
ab
−� �� �� �
k) 13x
2a
−� �� �� �
l) 12a
m
−� �� �� �
_______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________
m) 2
2
xy
−� �� �� �
n) 3
2
abm
−� �� �� �
o) 2
ab + c
−� �� �� �
_______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________ _______________________
Prof. Cícero José – Anhanguera Uniban 2012
57
80) Simplifique as seguintes expressões algébricas:
a) 2 2
2 2
(x y) yx 4y− −
− b)
2(x + a)(x a) + aax + bx
−
___________________________________ ___________________________________ ___________________________________ ___________________________________
___________________________________ ___________________________________ ___________________________________ ___________________________________
___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________
c) x y x
: + 1y x y
� � � �−� � � �
� � � � d)
a b a b + 1
a + b b a−� � � �−� � � �
� � � ��
___________________________________ ___________________________________ ___________________________________ ___________________________________
___________________________________ ___________________________________ ___________________________________ ___________________________________
___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________
e) 1 1 a b
+ : + 2 + a b b a� � � �� � � �� � � �
f) x a x a
1 + : 1x + a x + a
− −� � � �−� � � �� � � �
___________________________________ ___________________________________ ___________________________________ ___________________________________
___________________________________ ___________________________________ ___________________________________ ___________________________________
___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________
Prof. Cícero José – Anhanguera Uniban 2012
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g) 2 2
2 2 2
(x y) y(x + y) x y
− −− −
h) x y x y
1 : + 1x + y x + y
� � � �− −−� � � �� � � �
___________________________________ ___________________________________ ___________________________________ ___________________________________
___________________________________ ___________________________________ ___________________________________ ___________________________________
___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________ ___________________________________
81) Sabendo que x ventiladores iguais custam R$ 500,00, pergunta-se: a) Que fração algébrica representa o preço de um deles?
__________________________________________________________________________________ __________________________________________________________________________________ __________________________________________________________________________________
b) Ana deu y reais na compra de um deles. Que fração algébrica representa o troco dessa compra?
__________________________________________________________________________________ __________________________________________________________________________________ __________________________________________________________________________________
Testes de Revisão 82) Em qual expressão abaixo o número 5 pode ser cancelado sem mudar o valor da fração?
a) x + 5y 5−
b) 5 + x5 + y
c) 5x + 5y
5y d)
5x y5−
__________________________________________________________________________________ __________________________________________________________________________________ __________________________________________________________________________________
83) O valor da fração 4 5
4
6 + 66
é:
a) 6 b) 7 c) 36 d) 37
__________________________________________________________________________________ __________________________________________________________________________________ __________________________________________________________________________________ __________________________________________________________________________________
Prof. Cícero José – Anhanguera Uniban 2012
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84) Simplificando a expressão 2 2 2
2 2 2
a + b + ca b c− − −
, obtemos:
a) 0 b) 1 c) –2 d) –1
__________________________________________________________________________________ __________________________________________________________________________________ __________________________________________________________________________________ __________________________________________________________________________________
85) O valor de 4
2
x 1(x 1)(x + 1)
−−
, para x = 1999 é:
a) 2 000 b) 3 000 c) 4 000 d) 5 000
__________________________________________________________________________________ __________________________________________________________________________________ __________________________________________________________________________________ __________________________________________________________________________________
86) (Olimpíada Brasileira de Matemática) Se xy = 2 e x2 + y2 = 5, então 2 2
2 2
x y + + 2
y x vale:
a) 254
b) 52
c) 54
d) 12
__________________________________________________________________________________ __________________________________________________________________________________ __________________________________________________________________________________ __________________________________________________________________________________ __________________________________________________________________________________ __________________________________________________________________________________
87) Em uma prova em que deviam ser dados os resultados do 1º membro um aluno desatento apresenta
estes cálculos:
Quantos enganos esse aluno desatento cometeu?
a) 1 b) 2 c) 3 d) 4
__________________________________________________________________________________ __________________________________________________________________________________ __________________________________________________________________________________ __________________________________________________________________________________ __________________________________________________________________________________
Prof. Cícero José – Anhanguera Uniban 2012
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Respostas dos exercícios
CAPÍTULO I – Matemática Básica
1a) 10 b) 122 c) 1 d) –3 e) –9
f) 3 g) –10 h) 7 i) –14 j) 1
2a) 10 b) 2 c) 11 d) –15 e) –11 f) –2
3a) (3 000 000 – 1 800 000) : 3
b) 26 + 3 � 26
c) (385 : 5) – 32 � 5 ou 385
32 55
− �
d) (960 – 336) : 8 ou 960 336
8−
e) 2 � 27 + 2 � 26
f) 250 + 4 � 140
g) 4 + 2 � 12
h) (814 – 94) : 5 ou 814 94
5−
CAPÍTULO II – Cálculo Algébrico
Parte I – Monômios
4a) –2a b) 2xy c) –6ac d) –3am e) a2 f) 6xy2 g) 9
bc5
h) 21x
10 ou
2x10
i) 5
mn4
− j) 4x k) –4y2 l) ab m) 0 n) 4xy
o) 3n3 p) –5am q) 41a
6 ou
4a6
r) 2
bc5
−
5a) 3y3 – 3y b) a – 2ab + 4b c) 9x2 + 2x – 1 d) 3mn + 2m + n
e) a2 – ab + 9b2 f) 3x – 2y + 4 g) 3 4
a b2 3
− h) 4x2 + 5
x8
ou 28x + 5x
8
6) P = 3x
7a) x2 + 5y b) x2 + y2 c) (x + y)2 d) (a + b)(a – b) e) 2a + 2h
f) a3 + b3 g) (a + b)3 h) x2 – y2 i) 2x
3 j) x – 5
8) A = 100x2 9a) 0,40x + 3y b) 0,30x + 2y c) 0,10x + y 10) 5,87 � 157
11a) –13 b) 15 c) 13
d) 1 e) 144 f) 16
Prof. Cícero José – Anhanguera Uniban 2012
61
Parte II – Polinômios 12a) 3x – 2y b) 4a2 – a – 4 c) 11x3 – 4x2 – 7x + 6 d) a – 11b + 5c e) –y2
f) 2ab + bc g) 2a – 1 h) 3a – d i) 3x – 10y + 16 j) 3x – y
13a) –27y2 b) 10x2y c) 24bc d) –x3y5 e) 10x4y3
f) –12m3nx3 g) 5 23x y
10− h) 3 25
p q4
i) 10x6 j) –18a3x2
k) –60a2b4 l) –m2x5y3 m) –x4y4 n) 4 26h x y
5− o) –30k2x4 p) 215
abn px2
−
14a) 4y3 b) 5x2 c) –3 d) x e) –1
f) 2y g) –a3b h) 4m i) 1
ab2
− j) 5
x3
k) 21n
2− l)
1a
8 m) –6a2b4c n) ab2c
15a) 16x6y2 b) –m3x6 c) 32a5c15 d) 81b8c4 e) h12m6 f) 121y
8−
g) 2 24m n
25 h) x10y25 i) 1024a30 j) 1 k) 181
a64
l) 0,25x8y14
16a) –2m2 + 7m + 2 b) 2m2 – 7m – 2 c) 5m2 + 6m
d) 7m2 – m – 2 e) –5m2 – 6m f) –7m2 + m + 2
17a) 5 3
a c4 2
− b) 1
10 c) 211 1
m 8m + 2 4
− d) 2 5x 2x +
2−
18a) 3 + 4x b) –3x – 14 c) 1
+ 5x2
19a) 5ax3 + 5bx2 + 5cx
b) –15x2y2 – 18xy3 + 21x2y3
c) m3n – m2n2 + nm3
d) 6ax – 8bx + 10cx
e) 7a2x – 21abx + 35acx
f) 6x3 – 4x2 + 2x
g) 12x3 + 9x2 – 15
x2
Prof. Cícero José – Anhanguera Uniban 2012
62
20a) x3 – 12x2 + 47x – 60 b) x3 – 5x2 – 6x + 30 c) x4 – 7x3 + 6x2 + 42x – 72
d) x4 – 6x3 + x2 + 36x – 42 e) x4 – 8x3 + 18x2 – 5x – 12 f) 2x4 – 20x3 + 67x2 – 79x + 12
21) 2 ab2a +
2
22a) 4x + 3 b) –3x + 2 c) x3 + 5x2 + x – 4
d) 4a3 – 3a2 + 5 e) 2m3 – 7m2 + 3m f) –4x + 2 + 3a10
23a) x + 2 b) 2x – 3; resto 2 c) 3x – 5
d) 2x2 – 3x + 3; resto 1 e) –5x2 + 3x – 7 f) x – 5
g) x2 + 2x – 1 h) –2x + 1 i) 3x + 9; resto –6x – 7
j) x2 + x + 3; resto x + 4 k) 4x2 + 6x+2; resto –3x – 6 l) x2 + 4x + 16
24) 9x2 + 21x 25) 0,70x + 0,12y
26) A(1) = A(3) = A(3) = 2x
2 A(2) = A(4) =
2x4
A(6) = A(7) = x2
27a) 18 28) 27
CAPÍTULO III – Produtos Notáveis
36a) x4 + 2x2y3 + y6 b) 24a2x4 + 60a4x2 + 36a6 c) 16a6x2 + 16a3bxy + 4b2y2
d) a4 + 10a3m + 25a2m2 e) x12 + 6x8 + 9x4 f) 2 225x 20 4y
+ xy + 9 2 9
g) 8 4 19x + 2x +
9 h)
43 29a 3
+ a + a16 2
i) 6 7 8x x x
+ + 9 6 16
j) 2 4 4 2
3 3a b 2 a b + a b +
9 9 9 k) a6 – 8a4 + 16a2 l) 9x4 – 30x3y + 25x2y2
m) 24a4 – 40a2b2 + 16b4 n) x6 – 2x3y3 + y6 o) 4a2x2 – 16a3x4 + 16a4x4
p) 6 38 16x x +
3 9− q) 4 2 5 6 24 2 1
a b a bx + a x9 3 4
− r) 4 2 2 2
4m x m xy 9 + y
16 5 25−
s) 6 2 3 2 24 2 25a x a bxy + b y
9 3 4− t)
126x 5 25
+ x + 4 4 16
Prof. Cícero José – Anhanguera Uniban 2012
63
37a) a4 – 1 b) a6b4 – c2 c) x6 – y6 d) 25a6b2 – 4x2 y4
e) x4y8 – 25x2 f) 4x 9
25 16− g)
49m 14 9
− h) 2
6 ba
25−
i) 425x
369
− j) 8x
369
−
38a) a6 + 3a4b2 + 3a2b4 + b6 b) 8a3x3 + 36a4x2 + 54a5x + 27a6
c) x9 + 3x7 + 3x6 + x3 d) 3
227x 9 1 1+ x + x+
8 4 2 27
e) 6 4 2 2 3a a b a b b
+ + +64 16 12 27
f) 3 6 4 5 2 4 3 3a x a bx ab x b x
+ + +8 4 6 27
g) x6 – 3x4y + 3x2y6 – y9 h) 27a6 – 27a4b3x + 9a2b6x2 – b9x3
i) m6 – 9m4xy2 + 27m2x2y4 – 27x6y6 j) 6 4 2x x 9x 27
+ 27 4 16 64
− −
k) 9
3 61 3 3 aa + a
8 16 32 64− − l)
6 4 2 2 3x x y x y y +
8 8 6 64− −
39a) x2 + y2 + 9 + 2xy + 6y + 6x b) x4 + y2 + 1 + 2x2 y + 2x2 + 2y
c) 4x2 + y2 + 1 – 4xy – 4x + 2y d) x2 + 16y2 + 9 – 8xy + 6x – 4y
e) m10 – 2m5 + 1 f) 64x2y2 – 4xy + 1
16 g) x3 + 15x2 + 75x + 125
h) x3 – 3x2c + 3xc2 – c3 i) 25x10 + 20x6 + 4x2 j) 4 125m
4−
k) 25m6x2 – 49n6z4 l) 9a2 + 12ay + 4y2 m) 4 2 3 69m 15m n + 25n
4−
n) 4 216 4a b
25 81− o) 3 3 3 2 3 31
x y x y + 9x y 27x27
− − p) 4x2 + 2x2y + 41y
4
40a) x2 + 10x + 24 b) a2 – 8a + 15 c) y2 – 4y – 21 d) m2 – 4m – 96
e) x2 – 4x – 45 f) x2 + 18x + 45 g) b2 + 16b – 80 h) k2 – 21k + 104
i) x2 + 5x – 66 j) u2 + 11u – 60 k) 2 5 3x + x +
4 8 l) 2 16
x + x 115
−
m) 2 25x x 6
3− − n) 2 19 3
x x + 10 5
− o) 2 1 14x + x
3 3− p) 2 3 21
x x4 16
− −
41) 29 42) 83 43) 425 44a) 2499 b) 39 996 c) 4851 d) 399
Prof. Cícero José – Anhanguera Uniban 2012
64
45) 404 46) 8 47) 3x2 + 2x – 4 48) 7
50) 16; 22
44x + 8 +
x 51) x2 – 7x + 70 52) 198
125− 53) alternativa c
CAPÍTULO IV – Fatoração 54a) a(a2 – x) b) 5ax(1 – a2x) c) p(7p + 1)
d) 15a2(1 – 15a2) e) 5(3 + 5x2) f) 2x3(3 + x + 2x2)
g) 2xy2(xy – 3x + y) h) 3a2(a2 – 2a2 – 3a3) i) 5x3(x2 – 2a2 – 3a3)
j) 3x(2x2 – 3xy + 4y2) k) 2 3 21 1 1
a b a bc + a b + 12 6 3
� �−� �� �
l) 3 5 5 21 1 1 1m n a m mn + n
4 5 5 2� �−� �� �
m) 2 3 33 2 3 3h k x y + k
5 3 4 2� �−� �� �
n) 3 4 4 3 21 2 1a b a b + 2a
3 5 4� �−� �� �
o) 2 4 6 4 56 1 2 3y z z + y z
5 7 9 5� �−� �� �
55a) (a + b)(a + c) b) (2 + c)(x + c) c) (5 + b)(a + b) d) (x – y)(m – n)
e) (a – c)(a + x) f) (3a – b)(x – y) g) (2x + y)(3x – a) h) (ax – 3by)(x – y)
i) (x – 3)(x – y) j) (x + 1)(x3 + 2) k) 1 1
a + 3 5� �� �� �
(a2 + 1) l) (x + my) 1
x y4
� �−� �� �
m) 2 1 m 2m
3 2 3� �� �− −� �� �� �� �
n) (3a + 2)(2m + 5n) o) (a3 – b)(a2 + 1) p) (4m + 5n)(9a + 1)
56a) (r – x)(r + x) b) (a – 2)(a + 2)
c) (m – 3)(m + 3) d) (b + 4)(b – 4)
e) (5 + y)(5 – y) f) (2 + x)(2 – x)(4 + x2)
g) (a2 – 10)(a2 + 10) h) (np – 1)(np + 1)
i) (x – y)(x + y)(x2 + y2) j) (4x + 5y)(4x – 5y)
k) (x3 – 12a2)(x3 + 12a2) l) (x2 + ab)(x2 – ab)
m) (3a2 + 4n)(3a2 – 4n) n)
1 1y + y
2 2� �� �−� �� �� �� �
o) a b a b
+ 3 4 3 4� �� �−� �� �� �� �
p) x y x y
+ a b a b
� �� �−� �� �� �� �
q) mr xp mr xp
+ 4 5 4 5
� �� �−� �� �� �� �
r) –4ab
s) 4a t) –5(2a + 1)
Prof. Cícero José – Anhanguera Uniban 2012
65
57a) (2x + 1)2 b) (x + 5)2 c) (2x2 + y3)2
d) (4 – x)2 e) (6mn2 – 2x3)2 f) (5x2y – 2p3)2
g) (2x5 + 3y2m)2 h) (2x – 1)2 i) (x – a)2
j) 2
33 bx y
5 4� �−� �� �
k) 2
41 3m
4 2� �−� �� �
l) 2
3 4 21 1a + b c
4 2� �� �� �
m) 2
3 12x + y
3� �� �� �
n) 2
2 3 216m y + xy
2� �� �� �
o) (x – y4)2
p) não é fatorável q) (2x – 1)2 r) não é fatorável
s) não é fatorável t) não é fatorável u) 2
1x + 1
3� �� �� �
58a) (x + 3)(x + 4) b) (x + 2)(x + 5) c) (x – 1)(x – 6) d) (x – 2)(x – 4)
e) (x – 2)(x – 7) f) (x – 3)(x + 4) g) (x – 3)(x – 6) h) (x – 1)(x – 8)
i) (x – 4)(x + 3) j) (x – 2)(x + 6) k) (x – 1)(x + 8) l) (x + 3)(x – 5)
m) (x – 2)(x + 3) n) (x – 1)(x – 4) o) (y + 1)(y – 12) p) (m – 1)(m – 12)
q) (t + 2)(t + 6) r) (a – 4)(a + 2) s) (k + 5)(k + 8) t) (z + 1)(z – 8)
59a) x(x + 5) b) (2x – 3)2 c) (x – 2)(x2 + 4) d) (2x + 3)(2x – 3)
e) a3(a3 – 5a2 + 6) f) (x – 1)(a + b) g) (8y + 5)2 h) a2b2(a + b)
i) (m3 + 1)(m3 – 1) j) (2ax – b)2 k) 6a(2ab + 3) l) (x – y)(x2 + y)
m) (x + 4)(x – 2) n) abc(a + b + c) o) (5x + 7)2 p) (1 + a + b)(1 – a – b)
q) (x2 + 1)(x4 + 1) r) 5a2m(3a – 4) s) 1 1
m + 5n m 5n2 2
� �� �−� �� �� �� �
t) (9y + 1)2
u) (x +1)(x + 2) v) (m – 1)(m + 4) w) (m – 3)(m + 1)
x) (x – 2)(x + 5) y) (m – 2)(m + 1) z) (x – 5)(x – 6)
60a) 10(a + 1)(a – 1) b) x(x – 5)2 c) 2(m + 2)(m – 2) d) a(y + 2)2
e) (h2 + m2)(h + m)(h – m) f) y(x + 6)(x – 6) g) (a + c)(b + 1)(b – 1) h) x2 (x + 1)2
i) (9 + k2)(3 + k)(3 – k) j) xy(x – 4y)2 k) y(x – 4)2 l) 4(z – 15)2
m) 5(x + 2)(x – 2) n) z(2x + 5)(2x – 5) o) 12a(x2 – a)2 p) 4x(x – 1)2
q) (a + 1)(a + 2)(a – 2) r) (x – y)(x2 + xy + y2)(x + y)(x – xy + y2)
s) 12a(b – c) t) –x(x2 + x – 3)(x2 – x + 3)
61) 2006 62a) 99 b) 3999 c) 196 d) 4001 e) 1
Prof. Cícero José – Anhanguera Uniban 2012
66
64) Não, não pode ser um número par. 65) 500 66) 540
67a) (x3 + y2)(x6 – x3y2 + y4) b) (m2 + 2n4)(m4 – 2m2n4 + 4n8)
c) (y4 – 3)(y8 + 3y4 + 9) d) (2a – 3b)(4a2 + 6ab + 9b2)
e) (4 + a2)(16 – 4a2 + a4) f) (5x2 – 1)(25x4 + 5x2 + 1)
g) (x2y – a3b4)(x4y2 + x2ya3b4 + a6b8) h) 3 6 3x 4 x 2x 16
+ + 2 2 4 3 9
� �� �−� �� �
� �� �
i) 5 2 10 5am a m am
1 + + 15 25 5
� �� �−� �� �
� �� � j) 4 8 3 4 62 6 4 4 36
x + a x a x + a3 5 9 5 25
� �� �−� �� �� �� �
k) 2
2 4 21 3a b 13a b 9a + + b
2 2 4� �� �− � �� �
� �� �
68) alternativa B 69a) 899 b) 399 c) 396 d) 8099 e) 9996
f) 9991 g) 9936 h) 1596 i) 896 j) 2475 k) 2499
70) 16 71) alternativa A 72) alternativa A
CAPÍTULO V – Frações Algébricas
73a) mdc = 3x2 / mmc = 36x3 b) mdc = 4mn / mmc = 40m2n3
c) mdc = 2x / mmc = 80x3 d) mdc = 3 / mmc = 18x2y3
e) mdc = 4ax / mmc = 240a2x3 f) mdc = 3ab / mmc = 90a3b4c2
g) mdc = x3 / mmc = 20x5 h) mdc = 12ay / mmc = 120a3y4
74a) mdc = 2 / mmc = 4x(x – 1)
b) mdc = b/ mmc = ab(a + c)
c) mdc = x/ mmc = 15xy(x + y)
d) mdc = a/ mmc = 2ax(a – 1)(a + 1)
e) mdc = (x + 1) / mmc = (x + 1)(x – 1)
f) mdc = (a + b) / mmc = x(a + b)2
g) mdc = (x + y) / mmc = xy(x + y)(x – y)
h) mdc = (x + 2) / mmc = 30(x + 2)
i) mdc = (x – 5) / mmc = 5(x – 5)2(x + 5)
j) mdc = x / mmc = 5x(x – 2)(x + 2)
k) mdc = (x + a) / mmc = 2x(x + a)(x – a)
l) mdc = (x + 3) / mmc = 2(x + 3)(x – 3)
m) mdc = (2 – a) / mmc = a2(2 – a)(2 + a)
n) mdc = 2(x – 1) / mmc = 2(x – 1)2(x + 1)
o) mdc = (a + 1) / mmc = 2(a + 1)(a – 1)
p) mdc = 1 / mmc = 2x(x + 1)(x – 1)
67
75a) ab
b) x2y
c) abc
d) x2y
e) a3
f) 2ac3b
g) 1
m + 1
h) a + b
c
i) b
a + 1
j) 2a
k) 1
a + x
l) xy
m) 1
2a 1−
n) c2
o) h
a b−
p) x + 3x 3−
q) 2
2x 1−
r) 3
1x + 1
s) b + c
a
t) x
x y−
u) x y
5−
v) 2x + 1
x 1−
w) 2x
x) 1
x y−
76a) x2a
b) 5x4y
c) 2
2
x + 2x + 1x
d) 2 23a + 2bab
e) 2
2
4a + 10 a2a
−
f) y + x + 1
xy
g) 2a + 3a 2
2a−
h) 2 2a + yax
i) 2 2x + y2xy
j) 2x 2
(x + 2)(x 2)−
−
k) 2x 2
x 1−−
l) 2 23a + b
(a + b)(a b)−
m) x
x + y
n) 4a
1 a−
o) ab
(a + b)(a b)−
77a) 4a
3xy b) 3
xy2a
c) mya
d) 2a
2x e)
2
2
ab x5cy
f) 2xy g) 2
2
x + x 22x
− h) 2 2
xyx y−
i) a + b
3 j)
3a 2−
k) 3x
x + y l) 2
5xx + 1
m) a + xm + n
n) b + 1x 1−
78a) 23x
ab b)
a2b
c) 3b4
d) 23a
5 e)
2
2
y2x
f) 2mab
g) x 1
a−
h) 1
x y− i)
aa m−
j) x 52y−
k) 2a
l) x 1x + 2
− m)
2 + a(1 b)(a 2)− −
n) a 1
a−
o) a
68
p) ayx
q) a + 2
2 r) 2
1x
79a) 2
2
4ax
b) 6
2
xy
c) 3 3
3
x y8a
d) 6 3
9
m nx
e) 8 4
1a c
f) 2
1x + 4x + 4
g) 2 2
2
a + 2ab + c4c
h) 2 2
6
x 2xy + yx
− i)
2 2
2 2
x + 2ax + ax 2xy + y−
j) ba
k) 3
2ax
l) 2
ma
m) 4
2
yx
n) 6
3 3
ma b
o) 2 2
2
b + 2bc + ca
80a) a
x + 2y b)
xa + b
c) x y
x−
d) 2(a b)
b−
e) 1
a + b f)
xa
g) x 2y
2y−
h) yx
−
81a) 500
x b)
xy 500x−
82) alternativa C 83) alternativa B 84) alternativa D 85) alternativa A 86) alternativa A 87) alternativa D