7/23/2019 CD D 09
1/3
TRNG CKT CAO THNGKHOA IN T - TIN HC
THI MN TCSLP C 09(A+B)
THI GIAN: 90 pht(khng c s dng ti liu)
B i 1: (4 im)
Cho mch chnh lu khng iu khin cu 1 Pha ti R+L. Bit V 2=12 V,
R=10,L=.
1. V s mch in.
2. V th dng sng in p t ln ti vd, dng in qua diode D 1v D3(iD13),
dngin qua diode D2v D4(iD24) v dng in qua cun dy th cp mba i2.
3. Tnh in p trung bnh t ln ti Vdv dng in trung bnh qua ti Id
B i 2: (4 im)
Cho mch in nh hnh 1.
Bit tva sin2220= (V)
)3
2sin(2220
= tvb
(V)
)3
2sin(2220
+= tvc (V)
E=155V, R=10, L=.1. Gi s T5 v T6ang dn cho dng chy
qua, khi12
3
6
+=t th cho xung iu
khin m T1. Gii thch hot ng camch ti thi im trn.
2. V th dng sng in th ti im F (vF), in th ti im G (vG), dng in
quaT1( iT1), dng in qua T4(iT 4) v dng in chy trong cun th cp mba
pha a (ia).
3. Tnh in p trung bnh t ln ti Vd.B i 3: (2 im)
Cho mch in nh hnh 2. Bit V=110 V, gc kch
=30o
, R=100.V th dng sng in p t ln ti vc, dng in quati ic, dng in
qua tiristor T1 iT1 v in p t lntiristor T1vT1.
Ngy thng nm 2011 Ngy 02 thng 01 nm 2011Khoa in T - Tin Hc GV
ra
Thng Vn B
T2
R L110V
V
T1
Hnh 2
T1
+
-
T5T 3va
vb
vc
E
L
R
id
vd
T 4 T2T 6
F
GHnh 1
