Ch03 Crystalline Solids

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    AL- FATIHAH

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    2MME 2503Materials Science & Engineering

    CHAPTER 3:

    THE STRUCTURE OF CRYSTALLINE SOLIDS

    ISSUES TO ADDRESS...

    How do atoms assemble into solid structures?

    (for now, focus on metals)

    How does the density of a material depend on

    its structure?

    When do material properties vary with the

    sample (i.e., part) orientation?

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    MME 2503Materials Science & Engineering 3

    MATERIALS AND PACKING

    atoms pack in periodic, 3D arraysCrystallinematerials...

    -metals

    -many ceramics

    -some polymers

    atoms have no periodic packing

    Noncrystallinematerials...

    -complex structures-rapid cooling

    crystalline SiO2

    noncrystalline SiO2"Amorphous" = Noncrystalline

    Si Oxygen

    typical of:

    occurs for:

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    Chapter 3 -MME 2503Materials Science & Engineering

    4

    CRYSTAL SYSTEMS

    7 crystal systems

    14 crystal lattices

    Unit cell: smallest repetitive volume whichcontains the complete lattice pattern of a crystal.

    a, b, and care the lattice constants

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    Chapter 3 -MME 2503Materials Science & Engineering 5

    CRYST L SYSTEMS

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    MME 2503Materials Science & Engineering 6

    METALLIC CRYSTAL STRUCTURES

    Tend to be densely packed. Reasons for dense packing:

    - Typically, only one element is present, so all atomic

    radii are the same.

    - Metallic bonding is not directional.

    - Nearest neighbor distances tend to be small in

    order to lower bond energy.

    - Electron cloud shields cores from each other.

    Have the simplest crystal structures.

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    7

    SIMPLE CUBIC STRUCTURE (SC)

    Rare due to low packing density(only Po has this structure)

    Close-packed directionsare cube edges.

    Coordination #= 6

    (# nearest neighbors)

    MME 2503Materials Science & Engineering

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    8

    ATOMIC PACKING FACTOR (APF)

    APF for a simple cubic structure = 0.52

    APF =a3

    4

    3p (0.5a) 31

    atoms

    unit cellatom

    volume

    unit cell

    volume

    APF =Volume of atoms in unit cell*

    Volume of unit cell

    *assume hard spheres

    close-packed directions

    a

    R=0.5a

    contains 8 x 1/8 =1 atom/unit cell

    MME 2503Materials Science & Engineering

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    9

    BODY CENTERED CUBIC STRUCTURE (BCC)

    Coordination # = 8

    Atoms touch each other along cube diagonals.--Note: All atoms are identical; the center atom is shaded

    ex: Cr, W, Fe (), Tantalum, Molybdenum

    2 atoms/unit cell: 1 center + 8 corners x 1/8

    MME 2503Materials Science & Engineering

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    10

    ATOMIC PACKING FACTOR: BCC

    a

    APF =

    4

    3p( 3a/4 )32

    atoms

    unit cell atom

    volume

    a3

    unit cell

    volume

    length = 4R=

    Close-packed directions:

    3 a

    APF for a body-centered cubic structure = 0.68

    aR

    a2

    a3

    MME 2503Materials Science & Engineering

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    11

    FACE CENTERED CUBIC STRUCTURE (FCC)

    Coordination # = 12

    Atoms touch each other along face diagonals.--Note: All atoms are identical; the face-centered atoms are shaded

    ex: Al, Cu, Au, Pb, Ni, Pt, Ag

    4 atoms/unit cell: 6 face x 1/2 + 8 corners x 1/8

    MME 2501 - Engineering Materials

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    MME 2501 - Engineering Materials 12

    ATOMIC PACKING FACTOR: FCC APF for a face-centered cubic structure = 0.74

    maximum achievable APF

    APF =

    43p ( 2a/4 )34

    atoms

    unit cell atomvolume

    a3

    unit cell

    volume

    Close-packed directions:

    length = 4R= 2 a

    Unit cell contains:6 x1/2 + 8 x1/8

    = 4 atoms/unit cella

    2 a

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    Chapter 3 -MME 2501 - Engineering Materials

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    A sites

    B B

    B

    BB

    B B

    Csites

    C C

    CA

    B

    Bsites

    ABCABC... Stacking Sequence

    2D Projection

    FCC Unit Cell

    FCC Stacking Sequence

    B B

    B

    BB

    B B

    Bsites

    C C

    CA

    C C

    CA

    A

    BC

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    MME 2501 - Engineering Materials 14

    HEXAGONAL CLOSE-PACKED STRUCTURE

    (HCP)

    Coordination # = 12

    ABAB... Stacking Sequence

    APF = 0.74

    3D Projection 2D Projection

    6 atoms/unit cell

    ex: Cd, Mg, Ti, Zn

    c/a= 1.633

    c

    a

    A sites

    Bsites

    A sites Bottom layer

    Middle layer

    Top layer

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    Chapter 3 -MME 2501 - Engineering Materials

    15

    THEORETICAL DENSITY, R

    where n= number of atoms/unit cell

    A=atomic weight

    VC= Volume of unit cell = a3for cubic

    NA= Avogadros number

    = 6.023 x 1023atoms/mol

    Density = =

    VCNA

    nA =

    CellUnitofVolumeTotal

    CellUnitinAtomsofMass

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    Chapter 3 -

    Ex: Cr (BCC)

    A=52.00 g/mol

    R= 0.125 nm

    n= 2

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    THEORETICAL DENSITY, R

    theoretical

    a= 4R/ 3 = 0.2887 nm

    actual

    aR

    =a3

    52.002

    atoms

    unit cell mol

    g

    unit cell

    volume atomsmol

    6.023x1023

    = 7.18 g/cm3

    = 7.19 g/cm3

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    Chapter 3 -MME 2501 - Engineering Materials

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    DENSITIES OF MATERIAL CLASSES

    metals>

    ceramics>

    polymers

    Why?

    (

    g/cm

    )3

    Graphite/Ceramics/

    Semiconductor

    Metals/Alloys

    Composites/fibers

    Polymers

    1

    2

    2 0

    30

    *GFRE, CFRE, & AFRE are Glass,Carbon, & Aramid Fiber-ReinforcedEpoxy composites (values based on60% volume fraction of aligned fibers

    in an epoxy matrix).10

    3

    4

    5

    0.3

    0.4

    0.5

    Magnesium

    Aluminum

    Steels

    Titanium

    Cu,Ni

    Tin, Zinc

    Silver, Mo

    TantalumGold, WPlatinum

    Graphite

    Silicon

    Glass-sodaConcrete

    Si nitrideDiamond

    Al oxide

    Zirconia

    HDPE, PSPP, LDPE

    PC

    PTFE

    PET

    PVCSilicone

    Wood

    AFRE*

    CFRE*

    GFRE*

    Glass fibers

    Carbon fibers

    Aramid fibers

    Metalshave... close-packing

    (metallic bonding)

    often large atomic massesCeramicshave...

    less dense packing

    often lighter elements

    Polymershave...

    low packing density(often amorphous)

    lighter elements (C,H,O)

    Compositeshave... intermediate values

    In general

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    MME 2501 - Engineering Materials 18

    CRYSTALS AS BUILDING BLOCKS

    Someengineering applications require single crystals:

    Properties of crystalline materials

    often related to crystal structure.

    --Ex: Quartz fractures more easily

    along some crystal planes thanothers.

    --diamond single

    crystals for abrasives

    --turbine blades

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    MME 2501 - Engineering Materials 19

    POLYCRYSTALS

    Mostengineering materials are polycrystals.

    Nb-Hf-W plate with an electron beam weld.

    Each "grain" is a single crystal. If grains are randomly oriented,

    overall component properties are not directional.

    Grain sizes typically range from 1 nm to 2 cm

    (i.e., from a few to millions of atomic layers).

    1 mm

    Isotropic

    Anisotropic

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    MME 2501 - Engineering Materials 20

    SINGLE VS POLYCRYSTALS

    Single Crystals

    -Properties vary withdirection: anisotropic.

    -Example: the modulus

    of elasticity (E) in BCC iron:

    Polycrystals

    -Properties may/may not

    vary with direction.

    -If grains are randomly

    oriented: isotropic.(Epoly iron= 210 GPa)

    -If grains are textured,

    anisotropic.

    200 mm

    E (diagonal) = 273 GPa

    E (edge) = 125 GPa

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    Chapter 3 -

    Two or more distinct crystal structures for thesame material (allotropy/polymorphism)

    titanium

    , -Ti

    carbon

    diamond, graphite

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    POLYMORPHISM

    BCC

    FCC

    BCC

    1538C

    1394C

    912C

    -Fe

    -Fe

    -Fe

    liquid

    iron system

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    Chapter 3 -

    Point coordinates for unit

    cell center are

    a/2, b/2, c/2

    Point coordinates for unitcell corner are 111

    Translation: integer multipleof lattice constants identical position inanother unit cell

    MME 2501 - Engineering Materials

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    POINT COORDINATESz

    x

    y

    a b

    c

    000

    111

    y

    z

    2c

    b

    b

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    Chapter 3 -MME 2501 - Engineering Materials

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    CRYSTALLOGRAPHIC DIRECTIONS

    1. Vector repositioned (if necessary) to passthrough origin.

    2. Read off projections in terms of

    unit cell dimensions a, b, and c

    3. Adjust to smallest integer values

    4. Enclose in square brackets, no commas

    [uvw]

    ex:1, 0, => 2, 0, 1 => [201]

    -1, 1, 1

    z

    x

    Algorithm

    where overbar represents a

    negative index

    [111]=>

    y

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    CRYSTALLOGRAPHIC PLANES

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    Chapter 3 -

    Miller Indices: Reciprocals of the (three)axial intercepts for a plane, cleared of

    fractions & common multiples. All parallel

    planes have same Miller indices.

    Algorithm1. Read off intercepts of plane with axes in

    terms of a, b, c

    2. Take reciprocals of intercepts3. Reduce to smallest integer values

    4. Enclose in parentheses, no

    commas i.e., (hkl)

    MME 2501 - Engineering Materials

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    CRYSTALLOGRAPHIC PLANES

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    CRYSTALLOGRAPHIC PLANESz

    x

    ya b

    c

    4. Miller Indices (110)

    example a b cz

    x

    ya b

    c

    4. Miller Indices (200)

    1. Intercepts 1 1

    2. Reciprocals 1/1 1/1 1/1 1 0

    3. Reduction 1 1 0

    1. Intercepts 1/2 2. Reciprocals 1/ 1/ 1/

    2 0 03. Reduction 2 0 0

    example a b c

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    Chapter 3 -MME 2501 - Engineering Materials

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    CRYSTALLOGRAPHIC PLANES

    z

    x

    ya b

    c

    4. Miller Indices (634)

    example1. Intercepts 1/2 1 3/4

    a b c

    2. Reciprocals 1/ 1/1 1/

    2 1 4/3

    3. Reduction 6 3 4

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    Chapter 3 -

    Linear Density of Atoms LD =

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    LINEAR DENSITY

    ex: linear density of Al in [110]

    direction

    a= 0.405 nm

    a

    [110]

    Unit length of direction vector

    Number of atoms

    # atoms

    length

    13.5 nma2

    2LD -==

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    Chapter 3 -

    We want to examine the atomic packingof crystallographic planes

    Iron foil can be used as a catalyst. The

    atomic packing of the exposed planes is

    important.

    a) Draw (100) and (111) crystallographic planes

    for Fe.

    b) Calculate the planar density for each of these

    planes.

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    CRYSTALLOGRAPHIC PLANES

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    Chapter 3 -

    Solution: At T < 912C iron has the BCCstructure.

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    PLANAR DENSITY OF (100) IRON

    (100)

    Radius of iron R= 0.1241 nm

    R3

    34a =

    Adapted from Fig. 3.2(c), Callister 7e.

    2D repeat unit

    =Planar Density =a2

    1

    atoms

    2D repeat unit

    =nm2

    atoms12.1

    m2

    atoms= 1.2 x 1019

    1

    2

    R3

    34area

    2D repeat unit

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    Chapter 3 -

    Solution (cont): (111) plane

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    PLANAR DENSITY OF (111) IRON

    1 atom in plane/ unit surface cell

    333

    2

    2

    R3

    16R

    3

    42a3ah2area =

    ===

    atoms in plane

    atoms above plane

    atoms below plane

    ah23=

    a2

    1

    = =nm2

    atoms7.0

    m2

    atoms0.70 x 1019

    3 2R3

    16Planar Density =

    atoms

    2D repeat unit

    area

    2D repeat unit

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    Chapter 3 -

    Diffraction gratings must have spacingscomparable to the wavelength of diffractedradiation.

    Cant resolve spacings Spacing is the distance between parallel planes of

    atoms. MME 2501 - Engineering Materials

    35

    X-RAY DIFFRACTION

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    Chapter 3 -MME 2501 - Engineering Materials

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    X-RAYS TO DETERMINE CRYSTAL

    STRUCTURE

    X-rayintensity(fromdetector)

    q

    qc

    d=n

    2sinqc

    Measurement ofcritical angle, qc,allows computation of

    planar spacing, d.

    Incoming X-rays diffractfrom crystal planes.

    Adapted from Fig. 3.19,

    Callister 7e.

    reflections mustbe in phase fora detectable signal

    spacingbetweenplanes

    d

    q

    qextra

    distancetravelledby wave 2

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    X-RAY DIFFRACTION PATTERN

    (110)

    (200)

    (211)

    z

    x

    ya b

    c

    Diffraction angle 2q

    Diffraction pattern for polycrystalline -iron (BCC)

    Intensity(relative)

    z

    x

    ya b

    c

    z

    x

    ya b

    c

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    MME 2501 - Engineering Materials 38

    SUMMARY

    Atoms may assemble into crystallineoramorphousstructures.

    We can predict the densityof a material, provided we

    know the atomic weight, atomic radius, and crystal

    geometry(e.g., FCC, BCC, HCP).

    Common metallic crystal structures are FCC, BCC, and

    HCP. Coordination numberand atomic packing factor

    are the same for both FCC and HCP crystal structures.

    Crystallographic points, directionsand planesare

    specified in terms of indexing schemes.

    Crystallographic directions and planes are related

    to atomic linear densitiesand planar densities.

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    MME 2501 Engineering Materials 39

    SUMMARY

    Some materials can have more than one crystal

    structure. This is referred to as polymorphism(or

    allotropy).

    Materials can be single crystalsor polycrystalline.Material properties generally vary with single crystal

    orientation (i.e., they are anisotropic), but are generally

    non-directional (i.e., they are isotropic) in polycrystals

    with randomly oriented grains.

    X-ray diffractionis used for crystal structure andinterplanar spacingdeterminations.