Chapa 9 VSEPR b.ppt

  • Upload
    jv-gamo

  • View
    235

  • Download
    0

Embed Size (px)

Citation preview

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    1/44

    molecular geometry the orientation of atoms inspace (how the atoms are

    arranged in a molecule)

    VSEPR TheoryValence Shell Electron PairRepulsion theory

    VSEPR is a simple, yet powerful technique to

    predict the molecular geometry of molecules

    e- pairs (bonding or nonbonding) repel each

    other. Thus, they attempt to get as far apart from

    each other as possible to maximize separation

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    2/44

    # e- pairs around

    central element shapegeometry

    name angles

    2 pairs linear 180

    3 pairstrigonalplanar

    120

    4 pairs tetrahedral 109.5

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    3/44

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    4/44

    electron pair geometry must be known before

    molecular geometry can be predicted

    To determine molecular geometry (MG)

    1. draw the correct Lewis structure

    2. determine # of electron pairs around thecentral element

    3. determine how those electron pairs orient

    4. attach terminal atoms5. the orientation of the atoms in space

    determine the molecular geometry

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    5/44

    determine the molecular geometry of BCl3

    MG = trigonal planar

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    6/44

    determine the molecular geometryof BCl2

    - (anion)

    MG = bent

    bent = 3 atoms that are NOT linear

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    7/44

    determine the molecular geometry of H2O

    MG = bent

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    8/44

    determine the molecular geometry of NH3

    MG = pyramidal

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    9/44

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    10/44

    determine the molecular geometry of CH4

    MG = tetrahedral

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    11/44

    tetrahedral pyramidal bent

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    12/44

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    13/44

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    14/44

    multiple bonds in VSEPR theory

    * treat a double or triple bond as if it were asingle bond from a VSEPR standpoint

    determine the molecular geometry of CO2

    MG = linear

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    15/44

    determine the molecular geometry of NO2- (anion)

    MG = bent

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    16/44

    Cl2

    nonpolar bondelectrons are shared equally in

    the bond

    polar bondelectrons are NOT shared equally

    HCl

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    17/44

    + -

    dipole moment quantitative extent to whichpolarity is measured

    Br-Cl has a polar bond

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    18/44

    Is Br-Cl a polar molecule ?

    Consider the covalent bond as a rope with

    each atom pulling electrons to itself based

    on electronegativities of each atom

    If the entire molecule moves during the

    tugOwar.. the molecule is POLAR

    If the entire molecule does NOT move during the

    tugOwar.. the molecule is NONPOLAR

    Br-Cl is a polarmolecule

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    19/44

    Is CO2 a polar or nonpolar molecule ?

    the individual dipoles cancel such

    that the overall dipole moment = 0

    CO2 is a nonpolarmolecule

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    20/44

    Is H2O a polar or nonpolar molecule ?

    MG = bent

    H2O is a polarmolecule

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    21/44

    Is NF3 a polar or nonpolar molecule ?

    MG = pyramidal

    NF3 is a polarmolecule

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    22/44

    Is BF3 a polar or nonpolar molecule ?

    MG = trigonal planarthe individual dipoles cancel

    such that the overall dipole

    moment = 0

    BF3 is a nonpolarmolecule

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    23/44

    Is CCl4 a polar or nonpolar molecule ?

    the individual dipoles cancel such thatthe overall dipole moment = 0

    CCl4 is a nonpolarmolecule

    MG = tetrahedral

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    24/44

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    25/44

    valence bond theory describes how atomic

    (VB theory) orbitals form bonds

    valence bond theory describes how atomic

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    26/44

    open valency unpaired electron in a valenceorbital available for bonding

    valence bond theory describes how atomic(VB theory) orbitals form bonds

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    27/44

    F F

    2p 2p

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    28/44

    electron promotion electron is removed fromone orbital and placed in

    an orbital of higher energy

    hybridization simple atomic orbitals on thecentral atom mix to form newhybrid orbitals

    hybrid something of a mixed origin

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    29/44

    the two new sp hybrid

    orbitals are 50% s-character

    and 50% p-character

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    30/44

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    31/44

    Remember, this process is occurring only on

    the central element of boron, B

    Determine the hybridization of boron, B in BF3

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    32/44

    the 3 new sp2 hybrid orbitals

    are 33.3% s-character and

    66.6% p-character

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    33/44

    Remember, this process is occurring only on

    the central element of carbon, C

    Determine the hybridization of carbon, C in CH4

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    34/44

    the 4 new sp3 hybrid orbitals

    are 25% s-character and

    75% p-character

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    35/44

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    36/44

    octet expansion requires the central atom to

    have empty d-orbitals

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    37/44

    sigma bond electron overlap that forms all

    single bonds

    pi bond electron overlap that forms alldouble and triple bonds

    H H

    one bondone bond andone bond

    one bond andtwo bonds

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    38/44

    three bonds andtwo bondsfive bonds and

    one

    bond

    seven bonds andone

    bond

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    39/44

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    40/44

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    41/44

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    42/44

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    43/44

  • 7/27/2019 Chapa 9 VSEPR b.ppt

    44/44