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Chapter 9. Conformal Mapping
Weiqi Luo (骆伟祺 )School of Software
Sun Yat-Sen UniversityEmail : [email protected] Office : # A313
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Preservation of Angles Scale Factors Local Inverses Harmonic Conjugates
2
Chapter 9: Conformal Mapping
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Preservation of Angles Let C be a smooth arc, represented by the equation
and let f(z) be a function defined at all points z on C. The equation
is a parametric representation of the image Г of C under the transformation w=f(z).
101. Preservation of Angles
3
( ), ( )z z t a t b
[ ( )], ( )w f z t a t b
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Suppose that C passes through a point z0=z(t0) (a<t0<b) at which f is analytic and f’(z0)≠0. According to the chain rule, if w(t)=f[z(t)], then
101. Preservation of Angles
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0 0 0'( ) '[ ( )] '( )w t f z t z t 0 0 0arg '( ) arg '[ ( )] arg '( )w t f z t z t
0 0 0
0 0arg '( )f z
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Consider two intersectant arcs C1 and C2
101. Preservation of Angles
5
1 0 1 2 0 2
0 1 1 2 2 1 2 1 2
from C1 to C2 from Г1 to Г 2
Note that both magnitude and sense are the same.
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Conformal A transformation w=f(z) is said to be conformal at a
point z0 if f is analytic there and f’(z0)≠0.
Note that such a transformation is actually conformal at each point in some neighborhood of z0. For it must be analytic in a neighborhood of z0; and since its derivative f ’ is continuous in that neighborhood, Theorem 2 in Sec. 18 tells us that there is also a neighborhood of z0 throughout which f (z) ≠ 0.
101. Preservation of Angles
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Conformal Mapping A transformation w = f (z), defined on a domain D, is
referred to as a conformal transformation, or conformal mapping, when it is conformal at each point in D. That is, the mapping is conformal in D if f is analytic in D and its derivative f has no zeros there.
101. Preservation of Angles
7
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Example 1 The mapping w = ez is conformal throughout the entire z
plane since (ez)’ = ez ≠ 0 for each z.
Consider any two lines x = c1 and y = c2 in the z plane, the first directed upward and the second directed to the right.
101. Preservation of Angles
8
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Isogonal mapping A mapping that preserves the magnitude of the angle
between two smooth arcs but not necessarily the sense is called an isogonal mapping.
Example 3 The transformation , which is a reflection in the real
axis, is isogonal but not conformal. If it is followed by a conformal transformation, the resulting transformation
is also isogonal but not conformal.
101. Preservation of Angles
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w z
( )w f z
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Critical Point Suppose that f is not a constant function and is analytic at a
point z0 . If, in addition, f ’(z0) = 0, then z0 is called a critical point of the transformation w = f (z).
Example 4. The point z0 = 0 is a critical point of the transformation
w = 1 + z2, which is a composition of the mappings
Z = z2 and w = 1 + Z. A ray θ = α from the point z0 = 0 is evidently mapped onto the ray from the point w0 = 1 whose angle of inclination is 2α, and the angle between any two rays drawn from z0 = 0 is doubled by the transformation.
101. Preservation of Angles
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Scale factor From the definition of derivative, we know that
102. Scale Factors
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0
00
0
( ) ( )| '( ) | | lim |
z z
f z f zf z
z z
0
0
0
| ( ) ( ) |lim
| |z z
f z f z
z z
Now |z-z0| is the length of a line segment joining z0 and z, and|f(z)-f(z0)| is the length of the line segment joining the point f(z0) and f(z) in the w plane.
Exercise 7, Sec. 18
0| '( ) | 1f z Expansion: 0| '( ) | 1f z Contraction:
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Example When f(z)=z2, the transformation
is conformal at the point z=1+i, where the half lines
intersect.
102. Scale Factors
12
2 2( ) 2w f z x y i xy
, ( 0) & 1,( 1)y x x x y
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Illustrations
102. Scale Factors
13
C1: y=x, x ≥ 0
C2: x=1,y ≥ 0
C3: y=0,x ≥ 0
Г1: u=0, v=2x2 ,x≥0
Г2: u=1-y2, v=2y
Г3: u=x2, v=0
2 2( ) 2
( , ) ( , )
w f z x y i xy
u x y iv x y
'( ) 2 2( )f z z x iy
'(1) 2 1& | '(1 ) | 2 2 1f f i
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Local Inverse
A transformation w = f (z) that is conformal at a point z0 has a local inverse there.
That is, if w0 = f (z0), then there exists a unique transformation z = g(w), which is defined and analytic in a neighborhood N of w0, such that g(w0) = z0 and f [g(w)] = w for all points w in N. The derivative of g(w) is, moreover,
Note that the transformation z=g(w) is itself conformal at w0.
103. Local Inverses
14
1'( )
'( )g w
f z
Refer to pp. 360-361 for the proof!
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Example If f(z)=ez, the transformation w=f(z) is conformal
everywhere in the z plane and, in particular at the point z0=2πi. The image of this choice of z0 is the point w0=1.
When points in the w plane are expressed in the form w = ρ exp(iφ), the local inverse at z0 can be obtained by writing g(w) = logw, where logw denotes the branch
103. Local Inverses
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( ) log ln , ( 0, 3 )g w w i Why?
(1) 2 & '( ) 1/g i g w w
Not contain the origin
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Example (Cont’) If the point z0=0 is chosen, one can use the principal
branch
103. Local Inverses
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( ) og ln , ( 0, )g w L w i
(1) ln1 0 0g i
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pp. 362-363
Ex. 1, Ex. 6
103. Homework
17
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Suppose
is analytic in a domain D, then the real-valued functions u and v are harmonic in that domain. That is
According to the Cauchy-Riemann equations
And v is called a harmonic conjugate of u.
104. Harmonic Conjugates
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( ) ( , ) ( , )f z u x y iv x y
0 & 0xx yy xx yyu u v v
&x y y xu u u v
pp. 79 Theorem 1
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Properties If u(x,y) is any given harmonic function defined on a simply
connected domain D, then u(x,y) always has a harmonic conjugate v(x,y) in D.
Proof: Suppose that P(x, y) and Q(x, y) have continuous first-order partial derivatives in a simply connected domain D of the xy plane, and let (x0, y0) and (x, y) be any two points in D. If Py = Qx everywhere in D, then the line integral
from (x0, y0) to (x, y) is independent of the contour C that is taken as long as the contour lies entirely in D.
104. Harmonic Conjugates
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( , ) ( , )C
P s t ds Q s t dt
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104. Harmonic Conjugates
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0 0
( , )
( , )
( , ) ( , ) ( , )x y
x y
F x y P s t ds Q s t dt
( , ) ( , ) & ( , ) ( , )x yF x y P x y F x y Q x y
0 0
( , )
( , )
( , ) ( , ) ( , )x y
t s
x y
v x y u s t ds u s t dt
The integral is a single-valued function with the parameters x and y
Furthermore, we have
Since u(x,y) is harmonic 0 ( ) ( )xx yy y y x xu u u u
( , ) ( , )&v ( , ) ( , )x y y xv x y u x y x y u x y
+C,C R
Therefore v is the harmonic conjugate of u.
P Q
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Example Consider the function u(x, y) = xy, which is harmonic
throughout the entire xy plane. Find a harmonic conjugate of u(x,y).
Way #1: (pp.81)
104. Harmonic Conjugates
21
x yu y v 2
( )2
yv x
y xu v '( )x x2
( ) ,2
xx C C R
2 2
,2
x yv C C R
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Example (Cont’) Way #2:
104. Harmonic Conjugates
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( , ) ( , )
(0,0) (0,0)
( , )x y x y
t sv x y u ds u dt sds tdt
( , )u s t st &s tu t u s
2 21 1( , )
2 2v x y x y
O
(x,y)
s
t
(x,0)
+C
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pp. 81
Ex. 1 (using method #2)
104. Homework
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