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Chem 253, UC, Berkeley
What we will see in XRD of simple cubic, BCC, FCC?
)(75.0);(5.0sin
sin2
2
FCCBCCB
A
222 lkh
adhkl
Chem 253, UC, Berkeley
Reciprocal Lattice
n
'nd
R
cnbnanR 321Path Difference:
mnnRnRnR
)( ''
mnnR
2)(2 '
2
Chem 253, UC, Berkeley
Reciprocal Lattice
d
R
cnbnanR 321
mnnR
2)(2 '
mkkR 2)( '
Correspond to plane wave:12)( '
mikkRi ee
nk2
'k
Chem 253, UC, Berkeley
Reciprocal Lattice
n
'nd
R
cnbnanR 321
1)( '
kkRie Laue Condition
Reciprocal lattice vector
For all R in the Bravais Lattice
'k
k
kkK'
1 RiKe
3
Chem 253, UC, Berkeley
Reciprocal Lattice
d
R
1)( '
kkRie Laue Condition
Reciprocal lattice vector
For all R in the Bravais Lattice
'k
k
kkK'
1 RiKe
K
Chem 253, UC, Berkeley
Reciprocal Lattice
For all R in the Bravais Lattice
A reciprocal lattice is defined with reference to a particular Bravias Lattice.
a
b
c Primitive vectors
)(2
cba
cba
)(2
cba
acb
)(2
cba
bac
1 RiKe
4
Chem 253, UC, Berkeley
Reciprocal Lattice
For all R in the Bravais Lattice
)(2
cba
cba
)(2
cba
acb
)(2
cba
bac
Verify:
0
0
2
ca
ba
aa
For any
cnbnanR
ckbkakK
321
321
)(2 332211 nknknkRK
1 RiKe
Chem 253, UC, Berkeley
Reciprocal Lattice
Simple cubic
Reciprocal lattice is always one of 14 Bravais Lattice.
xaa
yab
zac
)(2
cba
cba
)(2
cba
acb
)(2
cba
bac
ya
2
za
2
xa
2
Simple cubic
5
Chem 253, UC, Berkeley
Primitive Cell of FCC
•Angle between a1, a2, a3: 60o
)(2
11
yxaa
)(2
12
yzaa
)(2
13
xzaa
Chem 253, UC, Berkeley
Primitive Cell of BCC
)(2
12
zyxaa
•Primitive Translation Vectors:
•Rhombohedron primitive cell
0.53a
109o28’)(2
11
zyxaa
)(2
13
zyxaa
6
Chem 253, UC, Berkeley
Reciprocal Lattice
FCC
)(2
cba
cba
)(2
cba
acb
)(2
cba
bac
Reciprocal lattice is always one of 14 Bravais Lattice.
BCC
)(2
zya
a
)(2
zxa
b
)(2
yxa
c
)(2
14
xzya
)(2
14
yzxa
)(2
14
zyxa
Chem 253, UC, Berkeley
Reciprocal Lattice
BCC FCC
Simple hexagonal Simple hexagonal
11
Chem 253, UC, Berkeley
Theorem:
For any family of lattice planes separated by distance d, there are
reciprocal lattice vectors perpendicular to the planes, the shortest
being 2/d.
Chem 253, UC, Berkeley
Orientation of plane is determined by a normal vector
The miller indices of a lattice plane are the coordination at the reciprocal lattice vector normal to the plane.
12
Chem 253, UC, Berkeley
Plane (hkl)
lckbhaK
A
B
C ax1
bx2
cx3
)1
,1
,1
()(321 xxx
hkl
cx
bx
ax 321
222
)()( 3121 cxaxbxaxACABK
cx
bx
ax 321
111
lckbhaK
)(2
cba
cba
)(2
cba
acb
)(2
cba
bac
Chem 253, UC, Berkeley
13
Chem 253, UC, Berkeley
What we will see in XRD of simple cubic, BCC, FCC?
PositionIntensity
Chem 253, UC, Berkeley
Structure Factor:adds up all scattered X-ray from each lattice points in crystal
czbyaxd
lckbhaK
j
2
)( khkl SI
n
j
diKk
jeS1
14
Chem 253, UC, Berkeley
X-ray scattered from each primitivecell interfere constructively when:
nd sin2
For n-atom basis:
sum up the X-ray scattered from the whole basis
1 RiKe
Chem 253, UC, Berkeley
d
Rid jd
k
'k
)( ji ddK Phase difference:
The amplitude of the two rays differ: )( ji ddiKe
kkK'
15
Chem 253, UC, Berkeley
The amplitude of the rays scattered at d1, d2, d3…. are in
the ratios :
The net ray scattered by the entire cell:
2
)( khkl SI
jdiKe
n
j
diKk
jeS1
Chem 253, UC, Berkeley
For simple cubic: (0,0,0)
10 iKk eS
16
Chem 253, UC, Berkeley
For BCC: (0,0,0), (1/2, ½, ½)…. Two point basis
lkh )1(1
S=2, when h+k+l evenS=0, when h+k+l odd, systematical absence
)(
)(2
10
2
1
1 lkhi
zyxiKiK
j
diKk
e
eeeS j
Chem 253, UC, Berkeley
For BCC: (0,0,0), (1/2, ½, ½)…. Two point basis
S=2, when h+k+l evenS=0, when h+k+l odd, systematical absence
(100): destructive
(200): constructive
17
Chem 253, UC, Berkeley
Observable diffraction peaks
222 lkh Ratio
Simple cubic
SC: 1,2,3,4,5,6,8,9,10,11,12..
BCC: 2,4,6,8,10, 12….
FCC: 3,4,8,11,12,16,24….
222 lkh
adhkl
nd sin2
Chem 253, UC, Berkeley
S=4 when h+k, k+l, h+lall even (h,k, l all even/odd)
S=0, otherwise
)()()(1 klilhikhik eeeS
FCC
18
Chem 253, UC, Berkeley
Observable diffraction peaks
222 lkh Ratio
Simple cubic
SC: 1,2,3,4,5,6,8,9,10,11,12..
BCC: 2,4,6,8,10, 12, 14….(1,2,3,4,5,6,7…)
FCC: 3,4,8,11,12,16,24….
222 lkh
adhkl
nd sin2
Chem 253, UC, Berkeley
Observable diffraction peaks
222 lkh Ratio
SC: 1,2,3,4,5,6,8,9,10,11,12..
BCC: 2,4,6,8,10, 12, 14….(1,2,3,4,5,6,7…)
FCC: 3,4,8,11,12,16,24….
222 lkh
adhkl
nd sin2
)(4
sin 2222
22 lkh
a
19
Chem 253, UC, Berkeley
What we will see in XRD of simple cubic, BCC, FCC?
)(75.0);(5.0sin
sin2
2
FCCBCCB
A
222 lkh
adhkl
Chem 253, UC, Berkeley
Ex: An element, BCC or FCC, shows diffraction peaks at 2: 40, 58, 73, 86.8,100.4 and 114.7. Determine:(a) Crystal structure?(b) Lattice constant?(c) What is the element?
2theta theta (hkl)
40 20 0.117 1 (110)
58 29 0.235 2 (200)
73 36.5 0.3538 3 (211)
86.8 43.4 0.4721 4 (220)
100.4 50.2 0.5903 5 (310)
114.7 57.35 0.7090 6 (222)
2sin 222 lkh
a =3.18 Å, BCC, W
20
Chem 253, UC, Berkeley
n
j
dKijk
jekfS1
)(
Polyatomic Structures
fj: atomic scattering factor No. of electrons
czbyaxd
lckbhaK
j
Reading : West Chapter 5
n
j
lzkyhxij
n
j
diKjk efefS j
1
)(2
1
Chem 253, UC, Berkeley
Simple Cubic Lattice
Caesium Chloride (CsCl) is primitive cubic
Cs (0,0,0)
Cl (1/2,1/2,1/2)
What about CsI?
)( lkhiClCsk effS
21
Chem 253, UC, Berkeley
(hkl) CsCl CsI
(100) (110) (111) (200) (210) (211) (220) (221) (300) (310) (311)
Chem 253, UC, Berkeley
FCC Lattices
Sodium Chloride (NaCl)
Na: (0,0,0)(0,1/2,1/2)(1/2,0,1/2)(1/2,1/2,0)
Cl: (1/2,1/2,1/2) (1/2,0,0)(0,1/2,0)(0,0,1/2)
Add (1/2,1/2,1/2)