7/28/2019 CONTOH SOAL STATIKA 1
2/4
DA = RA = 4.059 ton
Titik C
DCkiri = RA = 4.059 ton
DCkanan = RA P1 x Sin 45= 4.059 3.6 x 2= 4.059 2.545 = 1.514
ton
Titik D
DDkiri = RA P1 x Sin 45= 1.514 ton
DDkanan = RA P1 x Sin 45 P2= 1.514 2.6 = -1.086 ton
Titik E
DEkiri = RA P1 x Sin 45 P2= -1.086 ton
DEkanan = RA P1 x Sin 45 P2 (q x 0 m)= -1.086 ton
Titik B
o DBkiri = RA P1 x Sin 45 P2 (q x 0 m)= -1.086 ton
o DBkanan = RA P1 x Sin 45 P2 (q x 3 m) + RB= -1.086 ton (1.6 x
3m) + 7.086
= -1.086 ton 4.8 ton + 7.086 ton = 1.2 ton
Titik F
o DFkanan = [RA P1 x Sin 45 P2 (q x 3 m) + RB] (q x 1 m)= 1.2
ton 1.6 ton
= -0.4 0
Bidang D
Titik A
MA = 0
Titik C
7/28/2019 CONTOH SOAL STATIKA 1
3/4
MC = RA x 1m= 4.059 ton x 1m = 6.088 tm
Titik D
MD = RA x 3m P1 x Cos 45 x 2m= 4.059 ton x 3m 3.6 x 2 x 2m=
14.206 5.090 = 9.116 tm
Titik E
ME = RA x 6m P1 x Cos 45 x 5m P2 x 3m= 4.059 ton x 6m 3.6 x 2 x
5m 2.6 x 3m= 26.383 12.726 7.8 = 5.857 tm
Titik G
MG = RA x (6+ X) P1 x Cos 45 x (5 + X) P2 x (3 + X) qX2
= 6RA + XRA 3.6 x 2 x (5 + X) 2.6 x (3 + X) x 1.6 x X2
= 6 x 4.059+ X x 4.059 12.726 + 2.545X 7.8 + 2.6X 0.8X 2
= 26.383+ 4.059X 12.726 + 2.545X 7.8 + 2.6X 0.8X2
= 5.857+ 9.204X 0.8X2
a = -0.8 ; b = 9.204 ; c = 5.857
X1 = -0.604X2 = 12.109 karena > 4 m maka X2 tidak
dipakai.
= 5.857 + (9.204 x (-0.604)) 0.8 (-0.6042)= 5.857 5.559 0.292
0
Titik B
MB = RA x 9m P1 x Cos 45 x 8m P2 x 6m (q x 3m x 1)= 4.059 x 9m
3.6 x 2 x 8m 2.6 x 6m (1.6 x 3m x 1)= 38.560 20.361 15.6 7.2
= -4.601
Gambar kira-kira sebagaimana dibawah ini:
http://id.wikipedia.org/wiki/Persamaan_kuadrat
