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CPT-14 JEE Mains Medical Chemistry Held on 2-Nov-14
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UG 1 & 2, Above OBC Bank, Concord Complex, R.C. Dutt Road, Alkapuri, Baroda. Ph. 6625979, 6534152 Page # 1
1. (d)2. (a)3. (a)4. (a)5. (a)6. (b)7. (b)8. (c)9. (b)10. (d)11. (d)12. (b)13. (d)14. (c)15. (d)16. (b)17. (a)18. (c)19. (c)20. (c)21. (c) E = E1 + E2
21
hchchc 21
111 2
1680
1355
1 2 = 742.76 nm.22. (b) x P = 4h
x [mv] = 4hv = 100005.0600 = 0.03So x [9.1 1031 0.03] =
14.34106.6 34
x = 3134 1003.01.914.34 106.6 = 1.92 103M.
IIT ASHRAMA VENTURE OF JEE MAINS/ JEE ADVANCED/ AIPMT/ AIIMS/ KVPY/ OLYMIPIAD EXPERTS
COMMON PRACTI CE TEST-14ANANDALAYA
11th (Medical) Chemistry Solution Dt. 02-11-2014
UG 1 & 2, Above OBC Bank, Concord Complex, R.C. Dutt Road, Alkapuri, Baroda. Ph. 6625979, 6534152 Page # 2
23. (c) The electron have n + l higher value have hegher energy.n + l = 3 + 0 = 3n + l = 3 + 1 = 4n + l = 3 + 2 = 5(highest energy)n + l = 4 + 0 = 4
24. (a) 28Ni [Ar]3d8 4s2 4p3d 4sNumber of unpaired electrons (n) = 2 = 84.28)22(2)2n(n
25. (d) Angular momentum of the electron, mvr = 2nh where n = 5 (given) Angular momentum = h5.22h5
26. (c)27. (d)
28. (b) Molarity = ltV
soluteofMoles = 1000/100
1002.6/1102.6 2320 = 0.01 M
29. (b) MnO4 ; x + 4(2) = 1 or x = + 7 ;CrO2Cl2 ; x + 2(2) + 2(1) = 0 or x = +6.
30. (a) 2(+1) + 1(x) + 5(1) + 1 (+1) = 0. x = + 2.31. (b) Eq. mass = Mnof.NooxidationinChange
weightMolecular = 24
wt.Mol. = 2
wt.Mol.
(O.N. of Mn in MnSO4 = +2; O.N. of Mn in MnO2 = +4).
32. (b) PV = P1001P V2V2 =
P100101PV V2 = 101100 V
% decrease % deh = VV
101100
= 101100
%
33. (c) V T (at constant n and P).34. (d) PV = nRT
P dM
= nRT dMVd = RT
PM
35. (a) Equal masses of CO and N2 contain equal moles alsoOn applying charles law :
V P (At const T and n) 2NP = PCO
UG 1 & 2, Above OBC Bank, Concord Complex, R.C. Dutt Road, Alkapuri, Baroda. Ph. 6625979, 6534152 Page # 3
36. (a) P.PCH4 = 1616
4444
2856
1616
720 (where P.P = Partial pressure)= 4
1 720 = 180 mm.
37. (b) 2
2
H
O)dt/dn()dt/dn(
=
2
2
OH
MM
Here, ;gk x = wt. of H2 (H2 dk Hkkj gS
dt2/x
dt32/4
= 322
x32
8 = 4
1
x = 1 g.
38. (a) 2
1
dtdndtdn
= 32Mx
(Here dn is same)
45dn18dn
= 32Mx
2
1845 = 32Mx
Mx = 2
1845 32.
39. (a) 2
2
OSOr
r =
2
2
SOO
MM
2
2
OSOr
r = 64
32 2
2
OSOr
r = 2
1 = 1 : 2
40. (b) 2
1
gasgas
r
r =
1
2
gasgas
dd
2
1
gasgas
r
r = 16
2
1
gasgas
r
r = 4