cs1.TXT.HP.txt
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f'c= 280 kg/cm2 apoyo izquierdo sec. Central apoyo derechofy=
4200 kg/cm2 Mm(t.m) 230 109 230b(ancho)= 80 cm Mv(tn.m) 107 52
107h= 130 cm As+ (cm2) 129 64 129L(luz)= 20 m As- (cm2) 40 56 40CM=
6.8 t/mCV= 3.2 t/md'= 5d= =B4-B8Es= 2000000Ec=
=15000*(B1^0.5)solucion:Ig= =(1/12)*(B3*(B4^3)) cm4=(B13/(100^4))
m4fr= =2*(B1^0.5) kg/cm2=B16*10 tn/m2v= =B4/2 cm=B18*(1/100) mtMcr=
=(B17*B14)/(B19) tn*mn= =B10/B11n= 8Icr:sec. Centralc=
=((-(2*B23*G5-G5+(B23*G4))+((2*B23*G5-G5+(B23*G4))^2-(2*B3*(-2*B23*G5*B8+G5*B8-(B23*G4*B9))))^0.5)/(B3))
=((-(2*B23*G5-G5+(B23*G4))-((2*B23*G5-G5+(B23*G4))^2-(2*B3*(-2*B23*G5*B8+G5*B8-(B23*G4*B9))))^0.5)/(B3))c=
27.72Icr=
=(B3*(C28^3)/3)+(B23*G4)*(B9-C28)^2+(2*B23-1)*G5*(C28-B8)^2cm4=C29/(100^4)
m4En el apoyo izquierdoc=
=((-(2*B23*F5-F5+(B23*F4))+((2*B23*F5-F5+(B23*F4))^2-(2*B3*(-2*B23*F5*B8+F5*B8-(B23*F4*B9))))^0.5)/(B3))
=((-(2*B23*F5-F5+(B23*F4))-((2*B23*F5-F5+(B23*F4))^2-(2*B3*(-2*B23*F5*B8+F5*B8-(B23*F4*B9))))^0.5)/(B3))c=
40.56Icr=
=(B3*(C34^3)/3)+(B23*F4)*(B9-C34)^2+(2*B23-1)*F5*(C34-B8)^2cm4=C35/(100^4)
m4En el apoyo derechoc=
=((-(2*B23*H5-H5+(B23*H4))+((2*B23*H5-H5+(B23*H4))^2-(2*B3*(-2*B23*H5*B8+H5*B8-(B23*H4*B9))))^0.5)/(B3))
=((-(2*B23*H5-H5+(B23*H4))-((2*B23*H5-H5+(B23*H4))^2-(2*B3*(-2*B23*H5*B8+H5*B8-(B23*H4*B9))))^0.5)/(B3))c=
40.56Icr=
=(B3*(C40^3)/3)+(B23*H4)*(B9-C40)^2+(2*B23-1)*H5*(C40-B8)^2cm4=C41/(100^4)
m4Icr promedio para el tramo:Icr= =(C36+C42+(2*C30))/4 m4Icr=
=C45*(100^4) cm4
