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8/4/2019 DA Kamdhenu 2.0
http://slidepdf.com/reader/full/da-kamdhenu-20 1/4
Construction of Problem
Objective Function:-
Our Objective Function is to Maximize net profit. From Exhibit 3, we can derive the net profit as follows:
S.No AlternativesTotalRevenue
Cost of Milk +Processing &Packing Cost Net Profit
1 FA Milk+Butter 7956 7453 503
2 FA Milk+Ghee 7952 7504 448
3 SMP+Butter 8782 8238 544
4 SMP+Ghee 8609 8254 355
5 WMP+Butter 9863 8953 910
6 WMP+Ghee 9698 8953 745
7 BabyFood+Butter 12296 11431 865
8 BabyFood+Ghee 12080 11447 633
9 Cheese+Butter 12650 10817 1833
10 Cheese+Ghee 12546 10936 1610
11 StdzdMilk+Butter 8764 8005 759
12 StdzdMilk+Ghee 8645 8013 632
Thus Objective function can be given as:
Max z=(503x1 + 448x2 + 544x3 + 355x4 + 910x5 + 745x6 + 865x7+ 633x8 + 1833x9 + 1610x10 + 759x11 + 632x12 )
Constraints:-
From the above two tables we can see that total product produced should be less than the production
capacity. Thus,
.062x1 + .992 x3 + .606x5 + .560x7 + .681x9<= 3650
.048x2 + .756x4 + .448x6 + .529x8 + .426x10 +.519x12<= 912.5
S.No Alternatives Qty. of main product Qty of by-product ProductProductioncapacity per year
1 FA Milk+Butter 9874(L) = 1 unit 62= .062 units Butter 3650
2 FA Milk+Ghee 9874(L) = 1 unit 48 = .048 units Ghee 912.5
3 SMP+Butter 813(K) 992 = .992 units Milk Powder(SMP+WMP) 2190000
4 SMP+Ghee 813(K) 756 = .756 units Baby Food 1956.4
5 WMP+Butter 1179(K) 606 = .606 units Cheese 667.95
6 WMP+Ghee 1179(K) 448 = .448 units
FA Milk(min. to be
supplied) 2772.4
7 BabyFood+Butter 1307(K) = 1 unit 696 = .696 units Raw Milk 6043
8 BabyFood+Ghee 1307(K) = 1 unit 529 = .529 units
9 Cheese+Butter 1094(K) = 1 unit 560 = .560 units
10 Cheese+Ghee 1094(K) = 1 unit 426 = .426 units
11 StdzdMilk+Butter 8675(L) = 1 unit 681 = .681 units
12 StdzdMilk+Ghee 8675(L) = 1 unit 519 =.519 units
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813x3+ 813x4 + 1179x5 + 1179x6<= 2190000
x7 + x8<= 1956.4
x9 + x10<= 667.95
x1 + x2>= 2772.40
x1 + x2 + x3 + x4 + x5 + x6 + x7 + x8 + x9 + x10 + x11 + x12<= 6043
Solutions using linear programming software:
a) Annual
The formulation is shown in the next page. The solutions we get are:
ConstraintValueused inequality
max/Minvalue
Valueleft
Butter 1816.158 <= 3650 1833.84
ghee 284.5467 <= 912.5 627.953
milk powder 2190000 <= 2190000 0
baby food 745.1436 <= 1956.4 1211.26
cheese 667.95 <= 667.95 0
FA milk 2772.4 >= 2772.4 0
standardized
milk 0 <= 0
RM 6043 <= 6,043.00 0
So cheese should be produced as it utilizes whole of the constraint.
The final values for objective function are
Profit 4804797
Labor cost 950866.1
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cost 870000
Depriciation 810000
net margin 2173931
b) May-Aug
The only difference lies in the procurement ofraw milk units per day, which is now 11.9 units/day
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Contraint
Value
used inequality
max/Min
value
Value
left
Butter 184.4356 <= 1230 1045.56
ghee 140.7329 <= 307.5 166.767
milk powder 358827.7 <= 738000 379172
baby food 0 <= 659.28 659.28
cheese 225.09 <= 225.09 0
FA milk 934.2608 >= 934.2608 0
standardized
milk 0 <= 0
RM 1463.7 <= 1,463.70 0
Again we see in spite of raw material constrain (equation 8 concerning RM) being changed, cheese
production is a f avoured function.
The final values for objective function are
Gross Profit 1057902
Labor cost 230313.2
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cost 290000
Depriciation 270000
net margin 267588.3
c) Sep-April
Using similar logic as for May-Aug, the only changes are in milk supplied (19 units per day)
Contraint
Value
used inequality
max/Min
value
Value
left
Butter 1507.999 <= 2430 922.001
ghee 278.0332 <= 607.5 329.467
milk powder 1458000 <= 1458000 0
baby food 1089.934 <= 1302.48 212.546
cheese 444.69 <= 444.69 0
FA milk 1845.735 >= 1845.735 0
standardized
milk 0 <= 0
RM 4617 <= 4,617.00 0
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The final values for objective function are
Gross Profit 3610976
Labor cost 726485
Advertisementcost 580000
Depriciation 540000
net margin 1764492
Howmuchmoney can the corporation invest in butter churning and powder drying?
Capacity of milk powder we can expand by 1884211 kg per year(5162 kg/day). Weshouldnt invest more
than 1884211*INR(0.13)= INR 244947 for expansion.
Conclusion: Clearly, what made the production of cheese sound economically expensiveis high overhead
costs. The costs of processing and packaging are high for a perishable like cheese. As a result, the
calculations (without considering overhead costs) show cheese as a feasible product.
In the constraints table, constraints which are non-binding (non zero slack) can be considered as a
expensive weight function in the profit maximization equation. The sensitivity analysis can help us
realize how much constraints can be increased/decreased for the current optimal set. This can help us to
find out how much FA milk we can commit to supply to the state.