Dao Ham Cua Ham So Luong Giac

5/23/2018 Dao Ham Cua Ham So Luong Giac

1/20

Trng PT cp 2-3 Dng Vn An

T ton

Gi o v in thc h in: Nguyn Xun Long


2/20

K im tra bi c?

Nu qui tc tnh o hm ca hm s f ti

imBng nh ngha?

0x


3/20

(raian) 180

360

720

1800

5400

x

xsin999949321,0 999987307,0 999996826,0 999999492,0 999999943,0

x

Bi3: o hm cc hm s lng gic

1,Gii hn

Bng gi tr ca biu thc khi x nhn ccgi tr dng v rt gn im 0 nh sau :

Nhn xt gi tr ca biu thc khi x

x

x

x

sinlim0

x

xsin

H?x

xsin


4/20


Ni dung1, Gii hn

2, o hm cahn s y=sinx

3, o hm ca

hm s y=cosx4, Bi tp

nh l 1:

Ch :x

x

x

sinlim

0

1sin

lim0

x

x

x

1)(

)(sinlim

0)(lim

,0)(

0

0

0

xu

xu

xu

xxxu

xx

xx


5/20


V d: Tm gii hn a

b,

Ni dung:

nh l 1:

1sin

lim0 x

x

x

x

x

x

2sinlim

0

20

cos1lim

x

x

x

21.2

2

2sinlim2

2

2sin.2lim

00

x

x

x

x

xx

2

11.1.

2

1

2

2sin

lim

2

2sin

lim2

1

2

2sin

2

1lim2

sin2

lim

00

2

02

2

0

x

x

x

x

x

x

x

x

xx

xx


6/20


Ni dung

nh l

1:

H12, o hm ca hm s y=s inx nh l 2:a, Hm s c o hm

trn R, v (sinx)= cosx.b, Hm s u=u(x) c o hm trn

J th trn J ta c(sinu(x))=(cosu(x)).u(x)

Vit gn :(sinu)=(cosu).u

= u.cosu

1sin

lim0 xx

x

xy sin


7/20


Ni dung nh l 1:

nh l 2:

V d 2: Tnh o hm cahm s

Bg

H2 3, o hm ca hm s y=cosx. nh l 3:

1

sin

lim0 x

x

x

(sinx)= cosx

(sinu)= (cosu).u= ucosu

)2sin( 3 xxy

)2cos(.13

2.)2cos('32

'33

xxx

xxxxy


8/20

Bi 3: o hm cc hm s lng gic

Ni dung

nh l 1:

nh l 2:

nh l 3:

a, Hm s y=cosx c o hm trnR, v (cosx)= - sinx.

b, Nu hm s u=u(x) c o hmtrn J th trn J ta c :

(cosu(x))= (-sinu(x)).u(x) ,

vit gn :(cosu)= (-sinu).u

H3

1

sin

lim0 xx

x

(sinx)= cosx

(sinu)= (cosu).u =

ucosu


9/20

H1 H2 H3


10/20


H1: Cho . Hy tm kt qung trong cc kt qu sau:

A, B, C, D,

A : D v

xxmx

3cot.lim0

0m 1m3m

3

1m

3

1

3

3sin.3

1.3coslim3sin1.3coslim

3sin

3cos.lim3cot.lim

x

xx

x

xx

x

xxxxm

oxox

oxox


11/20

:Bi3: o hm cc hm s lng gic

H2: Cho hm s . Hy chn ktqu ng trong cc kt qu sau :

A, B, C, D,

xy sin

x

xy

2

cos'

x

xy

cos' xy cos'

x

y

2

1cos'

x

x

x

x

xxy

2

cos

cos.

2

1cos'

'

A : A v


12/20


H3 : Cho hm s . Hy chnkt qu ng trong cc kt qu sau:

A, B, C, D,

A : D v

xy 2sin' xy 2sin' xy 2sin' xy 2sin'

x

xxxx

xxxxy

2sin2

cos.sin2)sin.(cos2cos.cos2coscos'

''2'2

xy

2

cos


13/20

Bi1 Bi2 Bi3


14/20

Bi3 : o hm cc hm s lng gic

nh l 1:

nh l 2:

nh l 3:

Bi1: Hy ghp mi dng ct trivi mt ct v phi c ktqu ng:

1sin

lim0

x

x

x

(sinx)=cosx(sinu)=(cosu).

=ucosu

(cosx)= - sinx

(cosu)= (-sinu).u

x

x

x

5sinlim

01,

2,x

x

x 5sin

2tanlim

0

3,xx

x

x 2sin.

cos1lim

2

0

A,

B,

C,

D,

51

5

2

2

1

5


15/20


nh l 1:

nh l 2:

nh l 3:

Bi2: Hy ghp mi dng cttri vi mt ct v phi ckt qu ng:

1sin

lim0

x

x

x

(sinx)=cosx(sinu)=(cosu).u

=ucosu

(cosx)=- sinx

(cosu)= (-sinu).u

1,

2,

3,

A,

B,

C,

D,

xxy cos3sin5

)23sin( 2 xxy

xy 2cos

12

12sin'

x

xy

)23cos(32' 2 xxxy

xxy sin3cos5'

x

xy

2cos

2sin'


16/20

Bi3: o hm cc hm s lnggic

nh l 1:

nh l 2:

nh l 3:

Bi3: Cc bi gii sau ng ch-a ? Nu cha hy sa li chong1sinlim

0

x

x

x

(sinx)=cosx

(sinu)= (cosu).u

= ucosu

(cosx)= - sinx

(cosu)= (-sinu). u

1,

2,

3,

33

3sin.3lim

3sinlim

x

x

x

x

xx

1

2

2sinlim

2

coslim

22

x

x

x

x

xx

xx

xxy

xy

cos2).cos(cos

)).(coscos(cos'

)sin(cos

2

'22

2


17/20

Bi3: o hm cc hm s lnggic

nh l 1:

nh l 2:

nh l 3:

Bi3: Bi ton c sa li nh sau:

1sin

lim0

x

x

x

(sinx)=cosx

(sinu)= (cosu).u

= ucosu

(cosx)= - sinx

(cosu)= (-sinu). u

1,

2,

3,

33

3sin.3lim

3sinlim

00

x

x

x

x

xx

1

2

2sinlim

2

coslim

22

x

x

x

x

xx

)cos(cos.2sin

sin.cos2).cos(cos

)).(coscos(cos'

)sin(cos

2

2

'22

2

xx

xxx

xxy

xy


18/20

Cng c

0

sin

lim 1x

x

x

(sinx) = cosx,

(sinu)= u.cosu

(cosx) = - sinx,

(cosu)= - u.sinu

Rx

Rx


19/20

Bi tp v nh:

V nh lmli cc bi

tp giiv lm tipbi tp 30,33a,b,34,

35a,bSGK/trang211, 212.


20/20

Documents

Dao Ham Cua Ham So Luong Giac