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KHOA GIÁO DỤC ĐẠI CƯƠNG THI HỌC KÌ I (LẦN 2) - HỆ CAO ĐẲNG BỘ MÔN: VH - NN MÔN: HÓA HỌC ĐẠI CƯƠNG Ngày thi:………………............... THỜI GIAN LÀM BÀI: 60 phút Họ tên sinh viên:…………………………………… MSSV: ……………………………………………… Lớp: ……………………………………………........ Giáo viên coi thi 1 Giáo viên coi thi 2 Giáo viên chấm thi 1 Giáo viên chấm thi 2 Điểm SV chỉ được dùng bảng tuần hoàn để tra cứu. PHN 1 : TRC NGHIM T LUN (5 đim) SV trình bày ngắn gọn cách làm ghi kt qu vo cui câu. Câu 1: Tính biến thiên entanpi chuẩn của phản ứng: C(than chì) + 1/2O 2 (k) CO(k) H 0 = ? Biết: C(than chì) + O 2 (k) CO 2 (k) H 0 = -94,1 kcal CO(k) + 1/2O 2 (k) → CO 2 (k) H 0 = -67,7 kcal ...................................................................... ...................................................................... ...................................................................... ...................................................................... ...................................................................... ...................................................................... ...................................................................... ...................................................................... ...................................................................... .................................................. ................... ...................................................................... Trang 1/7 - Mã đề thi 284

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KHOA GIO DC I CNG

THI HC K I (LN 2) - H CAO NG

B MN: VH - NN

MN: HA HC I CNG

Ngy thi:...............

THI GIAN LM BI: 60 pht

H tn sinh vin:

MSSV:

Lp: ........Gio vin coi thi 1

Gio vin coi thi 2

Gio vin chm thi 1

Gio vin chm thi 2im

SV ch c dng bng tun hon tra cu. PHN 1: TRC NGHIM T LUN (5 im)SV trnh by ngn gn cch lm v ghi kt qua vao cui cu.

Cu 1: Tnh bin thin entanpi chun ca phn ng: C(than ch) + 1/2O2(k) CO(k) H0 = ?

Bit:

C(than ch) + O2 (k) CO2 (k) H0 = -94,1 kcal

CO(k) + 1/2O2(k) CO2(k) H0 = -67,7 kcal........................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................ ..........................................................................................................................................................................

H0 = -26,4 kcalCu 2: Trn ln 50ml dung dch HCl 0,12M vi 50ml dung dch NaOH 0,1M. Tnh pH ca dung dch thu c. ( Xem th tch thay i khng ng k)......................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................... ..................................................................................................................................................................................................................................................................................................................................................

pH = 2Cu 3: Bit h s nhit ca tc phn ng l 2,04. Khi tng nhit phn ng thm 450, th tc phn ng thay i nh th no?........................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................ ..................................................................................................................................................................................................................................................................................................................................................

Tc phn ng tng 24,74 lnCu 4: Cho phn ng thun nghich: 2NO2(k) 2NO(k) + O2(k)

Bng thc nghim quang ph xc nh c nng NO2 lc cn bng l 0,06M. Xc nh hng s cn bng KC ca phn ng trn, bit rng nng ban u ca NO2 l 0,3M.

........................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................ ..................................................................................................................................................................................................................................................................................................................................................

KC = 1,92Cu 5: Cho phn ng n gin : 2A (k)+ B (k) ( C (k), c hng s vn tc k = 0,5 .

Nng ban u ca A l 6M, ca B l 5M. Tinh tc ban u va tc cua phan ng khi c 55% cht B tham gia phn ng......................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................... ..................................................................................................................................................................................................................................................................................................................................................

vo = 90 ; vt = 0,28PHN 2: TRC NGHIM KHACH QUANA. BANG TRA LI

Hng dn lm bi :

Chn : b : chn li : Cu1234567891011121314151617181920

A

B

C

D

B. CU HOI Cu 1: Nguyn t c Z = 26 thuc loi nguyn t no ?

A. Nguyn t s.B. Nguyn t p.C. Nguyn t d.D. Nguyn t f.Cu 2: 1000oC hng s cn bng ca phn ng: FeO(r) + CO(k) (Fe(r) + CO2(k) bng 0,5; nng ban u ca cc cht nh sau: [CO] = 0,05M; [CO2] = 0,01M.

Nng cc cht lc cn bng l :

A. [CO] = 0,02M; [CO2] = 0,04MB. [CO] = 0,04M; [CO2] = 0,02MC. [CO] = 0,02M; [CO2] = 0,01MD. [CO] = 0,01M; [CO2] = 0,02MCu 3: Entropi (S) ca cht no di y ln nht 25oC v 1atm?

A. C2H6 (k)

B. CH4 (k)

C. C3H6 (k)

D. C4H10 (k)Cu 4: Cho phn ng sau: C2H5I + OH C2H5OH + I C hng s tc 2890K l k1 = 5,03 . 102 l. mol -1.s -1

3330K l k2 = 6,71 l. mol -1.s -1. Tnh Ea ca phn ng trn.A. 89 kJ/mol

B. 98 kJ/mol

C. 80 kJ/mol

D. 90 kJ/mol

Cu 5: Tnh (H0298 ca phn ng: 2Mg(r) + CO2(k) 2MgO(r) + C(gr)Bit rng (H0298,s (CO2) = 393,5 kJ

(H0298,s (MgO) = 601,8 kJ

A. +208,3 kJB. 208,3 kJC. +810,1 kJD. 810,1 kJCu 6: Cho phn ng: Mg + HNO3 ( Mg(NO3)2 + N2O + H2O

Tng cc h s nguyn, ti gin ca phn ng l:

A. 20.B. 24.C. 22.D. 26.Cu 7: Nguyn t ca nguyn t A c tng s electron trong cc phn lp s l 5. in tch ht nhn nguyn t A l

A. 13+.B. 9+.C. 11+.D. 7+.Cu 8: Trong phn t BF3, ln ca gc lin kt F-B-F l

A. 900.B. 1800.C. 1200.D. 109,50.Cu 9: Electron cui cng ca nguyn t nguyn t X ng vi: n = 3, = 2, m = +2, ms =+1/2 . Vy trong bng tun hon, X thuc s

A. 25.B. 27.C. 28.D. 26 .Cu 10: Cho phn ng v gi tr entropy ca cc cht trong phn ng : 2SO3(k) ( 2SO2(k) + O2(k)

S0298 (cal/mol.) 256,2 248,1 205

Bin thin entropy ca phn ng trn 250C c gi tr bng

A. +188,8.B. +196,9.C. 188,8.D. - 196,9.

Cu 11: B cc s lng t ph hp l :

A. n = 1, l = 0, ml = 1.B. n = 3, l = 0, ml = 2.

C. n = 3, l = 3, ml = 0.D. n = 4, l = 3, ml = 1.Cu 12: Trong cc phn t CO2, SO2, BeCl2, CH4 ; phn t phn cc l

A. BeCl2.B. CO2.C. CH4.D. SO2.Cu 13: Phn t c momen lng cc bng khng ( = 0) l

A. lu hunh ioxit.B. amoniac.C. nc.D. cacbon tetra clorua.Cu 14: Bit rng: khi nhit tng ln 100C, tc ca mt phn ng tng 2 ln. Nu phn ng ang xy ra 20oC, tng tc phn ng ln 32 ln th phi thc hin phn ng

A. 120oC.B. 70oC.C. 60oC.D. 80oC.Cu 15: Cc tiu phn : X, Y+, Z- u c cu hnh electron l 1s2 2s2 2p6 3s2 3p6. X, Y+, Z- ln lt l :

A. Ar, K+, Cl-.B. Ar, Ca2+, Cl-.C. Ar, Mg2+, F-.D. Ne, Mg2+, F-.

Cu 16: C dung H3PO4 14,6% (d = 1,08 g/ml). Vy, dung dch c nng mol l:

A. 1.61M

B. 1,51M

C. 1,41M

D. 1,31MCu 17: Cho phng trnh nhit ha hc sau :

2H2(k) + O2(k) 2H2O(l) ; Ho298 = -571,68 kJ

Nhit to thnh ca H2O(l) l

A. 571,68 kJ/mol.

B. +571,68 kJ/mol.

C. 285,84kJ/mol.

D. + 285,84kJ/molCu 18: Theo thuyt lin kt ha tr VB (Valence Bond), lin kt trong phn t HF c hnh thnh do s xen ph gia cc orbital

A. 2p (ca F) v 1s (ca H).B. 2s (ca F) v 1s (ca H).C. 1s (ca F) v 1s (ca H).D. 2p (ca F) v 2s (ca H).Cu 19: Phng trnh c bn ca nhit ng ha hc l

A. G = H + TS.B. G = H TS.C. G = H + TS.D. G = H TS.Cu 20: Cho s pin : () Zn | Zn2+ || 2I | I2(k) | Pt(r) (+). Bit th kh tiu chun ca Zn2+/Zn l -0,763V v ca I2 /I- l 0,540V th sc in ng chun ca pin bng:

A. +1,303V.B. 0,223V.C. +0,223V.D. 1,303V.

Ngay 4 thang 3 nm 2015Khoa/b mn Ging vin ra

Th Ngc Mai

Trang 3/4 - M thi 284

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