Do an Tot Nghiep - Truong Duc Tien - 2

8/13/2019 Do an Tot Nghiep - Truong Duc Tien - 2

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TRNG I HC BCH KHOA H NI

VIN IN

B MN T NG HO XNCN

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N TT NGHIP

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THIT K B NGUN HIU CH!NH H CNG U"T

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Trng b mn : TS. Trn Trng Minh

Gio vin hng dn : TS. Ngu!n "#ng $u%ng

Sinh vin &h'( hi)n : Tr*ng +,( Ti-n

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MSS5 : 006434

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%****-------Tinh so soi day chap, so vong day-------****%

J=(2*Eng*10^4)/(Bm*Ap*ku) %mat do dong dienIrms=Ipk/sqrt(2); %dong dien hieu dungAw=Irms/J; %tiet dien day tran yeu cauSn1=Aw/Awd; %so soi day chap

Sn=floor(Sn1); %lay gia tri nguyen lon honNx=(Wa*ku)/(Sn*Awd); %so vong day chua ke den tu thong tanN=round(Nx); %lay gia tri xap xi nguyen cua so vong daylg=((0.4*pi*N*N*Ac*(10^(-8)))/L) - (MPL/tutham); %Khe ho khong khi can thietF=1+(lg/sqrt(Ac))*log((2*G)/lg); %tinh he so tu thong tan cua khe hoN1x=sqrt((lg*L)/(0.4*pi*Ac*F*10^(-8)));%so vong day tinh den ton hao tren khe

hoN1=round(N1x); %lay xap xi nguyen cua so vong day

%****-------kiem nghiem-------****%

Bpk=F*((0.4*pi*N1*Ipk1*(10^(-4)))/lg);%tu cam dinhr1=r/Sn; %Gia tri moi mat do dien tro dai cua dayR=MLT*N1*r1*10^(-6);%Dien tro day quan

PCu=(Irms^2)*R; %Ton hao tren cuon day donganphal=PCu/Po %He so ton hao thuc teBac=(0.4*pi*N1*(deltaI/2)*(10^(-4)))/lg; %Tu cam xoay chieufprintf('\n Tra bang ton hao cua loi ferrit ung voi tan so va vat lieu da

chon:');kfe=input('\n He so ton hao loi kfe=');m=input('\n So mu cua tan so m=');n=input('\n So mu cua dien cam xoay chieu n=');tisocongsuat=kfe*(f^m)*((Bac)^n); %Ti so cong suatPfe=Wrfe*(10^(-3))*tisocongsuat; %Ton hao loiPt=PCu+Pfe; %Tong ton haophi=Pt/At; %Mat do cong suat tren dien tich be matTr=450*(phi)^(0.826); %Do tang nhiet dokut=(N1*Sn*Awd)/Wa; %He so lap day cua so tinh toan

fprintf('\n So vong day can quan n = %d', N1)fprintf('\n So day chap Sn = %d', Sn)fprintf('\n Do tang nhiet do Tr = %d', Tr)fprintf('\n He so lap day cua so tinh toan kutt = %d', kut)fprintf('\n Khe ho khong khi can thiet lg = %f', lg)if(Bm( Q>Q ?=(: Qkl ;) m*qD ?*|( ;(:


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DhJ \J(

kp1=((phi)*wc1*l)/(Vo*ki*sqrt(phi*phi+1))ki1=kp1/ti1Ri=tf([kp1 kp1/ti1],[1 0])fc2=15wc2=2*pi*fc2gc=km/(0.81*ki*kin*Vo)

phi=sqrt(3);ti2=phi/wc2kp2=((phi)*wc2*c)/(gc*ko*sqrt(phi*phi+1))ki2=kp2/ti2Rv=tf([kp2 kp2/ti2],[1 0])

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Do an Tot Nghiep - Truong Duc Tien - 2