51
DTFT continue (c.f. Shenoi, 2006) We have introduced DTFT and showed some of its properties. We will investigate them in more detail by showing the associated derivations later. We have also given a motivation of DFT which is both discrete in time and frequency domains. We will also introduce DFT in more detail below.

DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

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Page 1: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

DTFT continue (c.f. Shenoi, 2006)

We have introduced DTFT and showed some of its properties. We will investigate them in more detail by showing the associated derivations later.

We have also given a motivation of DFT which is both discrete in time and frequency domains. We will also introduce DFT in more detail below.

Page 2: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

DC responseWhen w=0, the complex exponential e−jw becomes a constant

signal, and the frequency response X(ejw) is often called the DC response when w=0.

–The term DC stands for direct current, which is a constant current.

Page 3: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

We will represent the spectrum of DTFT either by H(ejwT) or more often by H(ejw) for convenience.

When represented as H(ejw), it has the frequency range [-π,π]. In this case, the frequency variable is to be understood as the normalized frequency. The range [0, π] corresponds to [0, ws/2] (where wsT=2π), and the normalized frequency πcorresponds to the Nyquist frequency (and 2π corresponds to the sampling frequency).

Page 4: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

DC responseWhen w=0, the complex exponential e−jw becomes a constant

signal, and the frequency response X(ejw) is often called the DC response when w=0.

–The term DC stands for direct current, which is a constant current.

DTFT Properties Revisited

Time shifting

Page 5: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

Frequency shifting

Time reversal

Page 6: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

DTFT of δ(n)

DTFT of δ(n+k)+ δ(n-k)According to the time-shifting property,

Hence

( ) jwnn

nen −

−∞=∑δ

( ) ( ) jwkjwk eknekn −−+ is of DTFT , is of DTFT δδ

( ) ( ) ( )wkeeknkn jwkjwk cos2 is of DTFT =+−++ −δδ

10 == jwe

Page 7: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

DTFT of x(n) = 1 (for all n)x(n) can be represented as

We prove that its DTFT is

Page 8: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

Hence

( ) dwekw jwn

k∫ ∑−

−∞=⎥⎦

⎤⎢⎣

⎡−

π

ππδ 2

( ) ( ) ( ) ( )dwwdwwdwwdww ∫∫∫∫∞

∞−−++==

π

π

π

ππ

πδδδδ

( ) dwkwk

∫ ∑−

−∞=⎥⎦

⎤⎢⎣

⎡−=

π

ππδ 2

( ) ndww allfor 1== ∫∞

∞−δ

Page 9: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

From another point of viewAccording to the sampling property: the DTFT of a continuous

signal xa(t) sampled with period T is obtained by a periodic duplication of the continuous Fourier transform Xa(jw) with a period 2π/T = ws and scaled by T.Since the continuous F.T. of x(t)=1 (for all t) is δ(t), the DTFT of x(n)=1 shall be a impulse train (or impulse comb), and it turns out to be

DTFT of anu(n) (|a|<1)let

then

This infinite sequence converges to when |a|<1.

Page 10: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

DTFT of Unit Step Sequence

Page 11: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

Adding these two results, we have the final result

Page 12: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

Differentiation Property

Page 13: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

DTFT of a rectangular pulse

Page 14: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

and get

Page 15: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

ConvolutionConvolution of two discrete-time signalsLet x[n] and h[n] be two signals, the convolution of x and h is

can be written in short by y[n] = x[n] ∗ h[n].

Convolution of two continuous-time signals

can be written in short by y(t) = x(t) ∗ h(t)

[ ] [ ] [ ]∑∞

−∞=

−=k

knhkxny

( ) ( ) ( )∫∞

∞−

−= τττ dthxty

Page 16: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

Continuous convolution: optics example

From Kuhn 2005

Page 17: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

Continuous convolution: electronics example

From Kuhn 2005

Page 18: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

Properties of convolutionCommunitive

x[n] ∗ h[n] = h[n] ∗ x[n]this means that y[n] can also be represented as

Associativex[n] ∗ (h1[n] ∗ h2[n]) = (x[n] ∗ h1[n]) ∗ h2[n].

Linearx[n] ∗ (ah1[n] + bh2[n]) = ax[n] ∗ h1[n] + bx[n] ∗ h2[n].

Sequence shifting is equivalent to convolute with a shifted impulse

x[n-d]= x[n] ∗ δ[n-d]

[ ] [ ] [ ]∑∞

−∞=

−=k

khknxny

Page 19: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

An illustrative example

x[n]∗δ[n] x[n]∗h[n]

Page 20: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let
Page 21: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let
Page 22: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

Convolution can be realized by–Reflecting h[k] about the origin to obtain h[-k].–Shifting the origin of the reflected sequences to k=n.–Computing the weighted moving average of x[k] by using the weights given by h[n-k].

Page 23: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let
Page 24: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let
Page 25: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

Convolution can be explained as “arithmetic product.”•Eg.,

–x[n] = 0, 0, 5, 2, 3, 0, 0…–h[n] = 0, 0, 1, 4, 3, 0, 0…–x[n] ∗ h[n]:

0 9, 22,26,18, 5, 0, 0,

0 9, 6, 15, 0, 0, 0, 0, 0 0, 12, 8, 20, 0, 0, 0, 0 0, 0, 3, 2, 5 0, 0,

... 0, 0, 3, 4, 1, 0, 0, *)... 0, 0, 3, 2, 5 0, 0

,

,,

Page 26: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

Convolution vs. Fourier TransformMultiplication Property: For continuous F.T. and DTFT, if we perform multiplication in time domain, then it is equivalent to performing convolution in the frequency domain, and vice versa.

DTFT convolution theorem:Let x[n] ↔ X(ejw) and h[n] ↔ H(ejw).If y[n] = x[n] ∗ h[n], then

Y(ejw) = X(ejw)H(ejw)modulation/windowing theorem (or multiplication property)

Let x[n] ↔ X(ejw) and w[n] ↔ W(ejw).If y[n] = x[n]w[n], then

( ) ( ) ( )( )∫−

−=π

π

θθ θπ

deWeXeY wjjjw

21 a periodic

convolution

Page 27: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

For continuous F. T.

In summary,

Page 28: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

Sampling theorem revisited (oppenheim et al. 1999)

An ideal continuous-to-discrete-time (C/D) converter

Let s(t) be a continuous signal, which is a periodic impulse train:

We modulate s(t) with xc(t), obtaining

( ) ( )∑∞

∞−

−= nTtts δ

( ) ( ) ( ) ( ) ( )∑∞

∞−

−== nTttxtstxtx ccs δ

Page 29: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

Examples of xs(t) for two sampling rates

Page 30: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

Through the ‘sifting property’ of the impulse function, xs(t) can be expressed as

Let us now consider the continuous Fourier transform of xs(t). Since xs(t) is a product of xc(t) and s(t), its continuous Fourier transform is the convolution of Xc(jΩ) and S(jΩ).

( ) ( ) ( )∑∞

∞−

−= nTtnTxtx cs δ

Sampling with a periodic impulse followed by conversion to a discrete-time sequence

Page 31: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

Note that the continuous Fourier transform of a periodic impulse train is a periodic impulse train.

where Ωs =2π/T is the sampling frequency in radians/s.

Since

If follows that

Again, we see that the copies of Xc(jΩ) are shifted by integer multiples of the sampling frequency, and then superimposed to product the periodic Fourier transform of the impulse train of samples.

( ) ( ) ( )Ω∗Ω=Ω jSjXjX cs

( ) ( )( )∑∞

−∞=

Ω−Ω=Ωk

scs kjXT

jX 1

( ) ( )∑∞

−∞=

Ω−Ω=Ωk

skT

jS δ1

Page 32: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let
Page 33: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let
Page 34: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let
Page 35: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

Sampling of Bandpass Signals (c.f. Shenoi, 2006)

Page 36: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

Correlation

Given a pair of sequences x[n] and y[n], their cross correlation sequence is rxy[l] is defined as

for all integer l. The cross correlation sequence can sometimes help to measure similarities between two signals.

It’s very similar to convolution, unless the indices changes from l − n to n − l.

Autocorrelation:

[ ] [ ] [ ] [ ] [ ]lynxlnynxlrn

xy −∗=−= ∑∞

−∞=

[ ] [ ] [ ]∑∞

−∞=

−=n

xx lnxnxlr

Page 37: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

Consider the following non-negative expression:

That is,

Thus, the matrix is positive semidefinite.

Its determinate is nonnegative.

Properties

[ ] [ ]( ) [ ] [ ] [ ] [ ]

[ ] [ ] [ ] 0020

2

2

2222

≥++=

−+−+=−+ ∑∑∑∑∞

−∞=

−∞=

−∞=

−∞=

yyxyxx

nnnn

rlarra

lnylnynxanxalnynax

[ ] [ ] [ ][ ] [ ] a

arlr

lrra

yyxy

xyxx allfor 010

01 ≥⎥

⎤⎢⎣

⎡⎥⎦

⎤⎢⎣

[ ] [ ][ ] [ ]⎥⎦

⎤⎢⎣

⎡0

0

yyxy

xyxx

rlrlrr

Page 38: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

The determinant is rxx[0]ryy[0] − rxy2[l] ≥ 0.

Propertiesrxx[0]ryy[0] ≥ rxy

2[l]rxx

2[0] ≥ rxy2[l]

Normalized cross correlation and autocorrelation:

The properties imply that |ρxx[0]|≤1 and |ρyy[0]|≤1.The DTFT of the autocorrelation signal rxx[l] is the squared magnitude of the DTFT of x[n], i.e., |X(ejw)|2.

Correlation is useful in random signal processing

[ ] [ ][ ] [ ] [ ]

[ ] [ ]00

0 yyxx

xyxy

xx

xxxx

rr

lrl

rlr

l == ρρ

Page 39: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

DFT and DTFT – A closer lookWe discuss the DTFT-IDTFT pair (‘I’ means “inverse) for a discrete-time function given by

and

The pair and their properties and applications are elegant, but from practical point of view, we see some limitations; eg. the input signal is usually aperiodic and may be finite in length.

Page 40: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

Example of a finite-length x(n) and its DTFT X(ejw).

A finite-length signal

Its magnitude spectrum

Its phase spectrum

Page 41: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

The function X(ejw) is continuous in w, and the integration is not suitable for computation by a digital computer.

We can discretize the frequency variable and find discrete values for X(ejwk), where wk are equally sampled whthin [-π, π].

Discrete-time Fourier Series (DFS)Let x(n) (n∈Z) be a finite-length sequence, with the length being N; i.e., x(n) = 0 for n < 0 and n > N.Consider a periodic expansion of x(n):

xp(n) is periodic, so it can be represented as a Fourier series:( ) ( ) integerany is ,1,...,1,0 , KnnnxKNnxp −==+

Page 42: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

To find the coefficients Xp(k) (with respect to a discrete periodic signal), we use the following summation, instead of integration:

First, multiply both sides by e-jmw0k, and sum over n from n=0 to n=N-1:

By interchanging the order of summation, we get

Page 43: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

Noting that

pf. When n=m, the summation reduces to

N

When n≠m, by applying the geometric-sequence formula,

we have

( ) ( ) ( )( ) ( )

( )

( ) ( ) ( )

( ) 01

1

/2

)(/2)(/22

/2

)(/2)(/21

'

'/21

0

/2

=−−

=

−−

==

−−+

−−−−

−=

=

− ∑∑

kNj

mkNjmkNjkj

kNj

mkNjmNkNjmN

mn

knNjN

n

mnkNj

eee

eeeee

π

πππ

π

ππππ

1 ,1

1

≠−−

=−+

−=∑ r

rrrr

MNN

Mn

n

Page 44: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

Since there is only one nonzero term,

= Xp(k)N

The final result is

The following pairs then form the DFS

Page 45: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

Relation between DTFT and DFS for finite-length sequences

We note that

In other words, when the DTFT of the finite length sequence x(n) is evaluated at the discrete frequency wk = (2π/N)k, (which is the kth sample when the frequency range [0, 2π] is divided into N equally spaced points) and dividing by N, we get the Fourier series coefficients Xp(k).

DTFT spectrumDFS coeficient

Page 46: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

A finite-length signal

Its magnitude spectrum (sampled)

Its phase spectrum (sampled)

Page 47: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

To simplify the notation, let us denote

The DFS-IDFS (‘I’ means “inverse”) can be rewritten as (W=WN)

Discrete Fourier Transform (DFT)Consider both the signal and the spectrum only within one

period (N-point signals both in time and frequency domains)

( )NjN eW /2π−=

DFT

IDFT(inverseDFT)

Page 48: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

Relation between DFT and DTFT: The frequency coefficients of DFT is the N-point uniform samples of DTFT with [0, 2π].

The two equations DFT and IDFT give us a numerical algorithm to obtain the frequency response at least at the N discrete frequencies. By choosing a large value N, we get a fairly good idea of the frequency response for x(n), which is a function of the continuous variable w.

Question: Can we reconstruct the DTFT spectrum (continuous in w) from the DFT?

→ Since the N-length signal can be exactly recovered from both the DFT coefficients and the DTFT spectrum, we expect that the DTFT spectrum (that is within [0, 2π]) can be exactly reconstructed by the DCT coefficients.

Page 49: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

Reconstruct DTFT from DFT(when the sequence is finite-length)

By substituting the inverse DFT into the x(n), we have

a geometric sequence

Page 50: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

By applying the geometric-sequence formula

Page 51: DTFT continue (c.f. Shenoi, 2006) - 國立臺灣大學cmlab.csie.ntu.edu.tw/DSPCourse/slide/Lecture3.pdf · 2006-11-06 · Convolution Convolution of two discrete-time signals Let

So

The reconstruction formula