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Ejemplo de uso de listings
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Pruebas del paquete listings
1 \begin{displaymath}2 \oint_{S}\vec{E}\cdot d\vec{S}=\frac{q}{\
epsilon_{0}}3 \end{displaymath}
∮S
~E · d~S =q
ε0
1 \begin{trivlist}2 \item\input{\jobname.exa}3 \end{trivlist}
Let H be a Hilbert space, C be a closedbounded convex subset of H , T a nonex-pansive self map of C. Suppose that asn → ∞, an,k → 0 for each k, and γn =∑∞
k=0 (an,k+1 − an,k)+ → 0. Then foreach x in C, Anx =
∑∞k=0 an,kT
kx con-verges weakly to a fixed point of T .
The numbered equation
utt−∆u+u5+u |u|p−2 = 0 in R3×[0,∞[(1)
is automatically numbered as equation 2.
Let $H$ be a Hilbert space, $C$ be a closed bounded convex subset of $H$, $T$a nonexpansive self map of $C$. Suppose that as $n\rightarrow\infty$,$a_{n,k}\rightarrow0$ for each $k$, and $\gamma_{n}=\sum_{k=0}ˆ{\infty}\left(a_{n,k+1}-a_{n,k}\right) ˆ{+}\rightarrow0$. Then for each $x$ in $C$,$A_{n}x=\sum_{k=0}ˆ{\infty}a_{n,k}Tˆ{k}x$ converges weakly to a fixed point of$T$ .
The numbered equation\begin{equation}u_{tt}-\Delta u+uˆ{5}+u\left| u\right| ˆ{p-2}=0\text{ in }\mathbf{R}%ˆ{3}\times\left[ 0,\infty\right[ \label{eqn1}%\end{equation}is automatically numbered as equation \ref{eqn1}.
1 Let $H$ be a Hilbert space, $C$ be aclosed bounded convex subset of $H$,$T$
2 a nonexpansive self map of $C$. Supposethat as $n\rightarrow\infty$,
3 $a_{n,k}\rightarrow0$ for each $k$, and$\gamma_{n}=\sum_{k=0}ˆ{\infty}\left(
4 a_{n,k+1}-a_{n,k}\right) ˆ{+}\rightarrow0$. Then for each $x$ in $C$,
5 $A_{n}x=\sum_{k=0}ˆ{\infty}a_{n,k}Tˆ{k}x$converges weakly to a fixed point
of6 $T$ .7
8 The numbered equation9 \begin{equation}
10 u_{tt}-\Delta u+uˆ{5}+u\left| u\right|ˆ{p-2}=0\text{ in }\mathbf{R} %
11 ˆ{3}\times\left[ 0,\infty\right[ \label{eqn1} %
12 \end{equation}13 is automatically numbered as equation \
ref{eqn1}.
Let H be a Hilbert space, C be a closedbounded convex subset of H , T a nonex-pansive self map of C. Suppose that asn → ∞, an,k → 0 for each k, and γn =∑∞
k=0 (an,k+1 − an,k)+ → 0. Then foreach x in C, Anx =
∑∞k=0 an,kT
kx con-verges weakly to a fixed point of T .
The numbered equation
utt−∆u+u5+u |u|p−2 = 0 in R3×[0,∞[(2)
is automatically numbered as equation 2.
1
1 \begin{equation}2 \forall x \in \mathbf{R}:3 \qquad xˆ{2} \geq 04 \end{equation}
∀x ∈ R : x2 ≥ 0 (3)
1 \begin{displaymath}2 xˆ{2} \geq 0\qquad3 \textrm{para todo }x\in\mathbb{R}4 \end{displaymath}
x2 ≥ 0 para todo x ∈ R
Codigo de este archivo
\documentclass{article}
\usepackage{amsmath}\usepackage{amsthm}\usepackage[latin1]{inputenc}\usepackage[normalbf,normalem]{ulem}\usepackage{titlesec}\usepackage{titletoc}\usepackage{amsbsy}\usepackage{multicol}\usepackage{fancyhdr}\usepackage{extramarks}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{times}\usepackage[activeacute,spanish]{babel}
\usepackage{color}
\usepackage{verbatim}\usepackage{listings}\definecolor{gray97}{gray}{.97}\definecolor{gray85}{gray}{.95}\definecolor{gray75}{gray}{.75}\definecolor{gray45}{gray}{.45}\definecolor{yellow57}{rgb}{1.00,1.00,0.84}\lstset{ frame=Ltb,
framerule=0pt,aboveskip=0.5cm,framextopmargin=3pt,framexbottommargin=3pt,framexleftmargin=0.4cm,framesep=0pt,
2
rulesep=.4pt,backgroundcolor=\color{gray97},rulesepcolor=\color{black},%stringstyle=\ttfamily,showstringspaces = false,basicstyle=\small\ttfamily,commentstyle=\color{gray45},keywordstyle=\bfseries,%numbers=left,numbersep=15pt,numberstyle=\tiny,numberfirstline = false,breaklines=true,
}%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% minimizar fragmentado de listados\lstnewenvironment{listing}[1][]
{\lstset{#1}\pagebreak[0]}{\pagebreak[0]}
\lstdefinestyle{consola}{basicstyle=\scriptsize\bf\ttfamily,backgroundcolor=\color{blue57},
}
\lstdefinestyle{L}{language=TeX,}
% y en la derecha la composici’on.%% \begin{example}% \Large Esto es grande% \end{example}%% Esta parte procede de verbaim.sty de FMi%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%\makeatletter\newwrite\solution@stream\openout\solution@stream=\jobname.solutions\newcounter{problem}\newcommand*{\problemname}{Problem}\newcommand{\problem}[1]{%
\refstepcounter{problem}%\problemname˜\theproblem:\enskip#1\par
3
}
\newcommand{\solution}[1]{%\protected@write\solution@stream{}{%
\protect\print@solution{\theproblem}{#1}%}%
}
\newcommand*{\printsolutions}{%\closeout\solution@stream\makeatletter\InputIfFileExists{\jobname.solutions}{}{}%\makeatother
}
\newcommand*{\solutionname}{Solution}\newcommand{\print@solution}[2]{%
\solutionname˜#1:\enskip#2\par
}
%\makeatother
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%\makeatletter%\def\ThisFile{\yorname}%\let\OldInput\input%\renewcommand{\input}[1]{%% \renewcommand{\ThisFile}{#1}%% \OldInput{#1}%%}\newwrite\ejercicio@out\newenvironment{ejercicio}%{\begingroup% Lets Keep the Changes Local\@bsphack\immediate\openout \ejercicio@out \jobname.exa\let\do\@makeother\dospecials\catcode‘\ˆˆM\active\def\verbatim@processline{%
\immediate\write\ejercicio@out{\the\verbatim@line}}%\verbatim@start}%
{\immediate\closeout\ejercicio@out\@esphack\endgroup%%% Y aqu’i lo que se ha a˜nadido%
4
\par\small\addvspace{3ex plus 1ex}\vskip -\parskip\noindent\makebox[0.45\linewidth][l]{%\begin{minipage}[t]{0.45\linewidth}
\vspace*{-2ex}\setlength{\parindent}{0pt}\setlength{\parskip}{1ex plus 0.4ex minus 0.2ex}\begin{trivlist}
\item\input{\jobname.exa}
\end{trivlist}\end{minipage}}%\hfill%\makebox[0.5\linewidth][l]{%\begin{minipage}[t]{0.50\linewidth}
\vspace*{-1ex}\verbatiminput{\jobname.exa}
\end{minipage}}\par\addvspace{3ex plus 1ex}\vskip -\parskip
}%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\newwrite\example@out\newenvironment{example}%{\begingroup% Lets Keep the Changes Local\@bsphack\immediate\openout \example@out \jobname.exa\let\do\@makeother\dospecials\catcode‘\ˆˆM\active\def\verbatim@processline{%
\immediate\write\example@out{\the\verbatim@line}}%\verbatim@start}%
{\immediate\closeout\example@out\@esphack\endgroup%\makeatother%% Y aqu’i lo que se ha a˜nadido%
\par\small\addvspace{3ex plus 1ex}\vskip -\parskip\noindent\makebox[0.5\linewidth][l]{%\hspace*{+2ex}\setlength{\parindent}{0pt}
\setlength{\parskip}{1ex plus 0.4ex minus 0.7ex}\begin{minipage}[t]{0.50\linewidth}% \vspace*{-1ex}\vspace*{-2ex}
5
\lstinputlisting[style=L, basicstyle=\scriptsize\bf\ttfamily,backgroundcolor=\color{yellow57},]{\jobname.exa}%\verbatiminput{\jobname.exa}\end{minipage}}
\hfill\hspace{10pt}%\makebox[0.45\linewidth][l]{%\begin{minipage}[t]{0.45\linewidth}
\vspace*{-2ex}\setlength{\parindent}{0pt}\setlength{\parskip}{1ex plus 0.4ex minus 0.7ex}\begin{trivlist}
\item\input{\jobname.exa}\end{trivlist}
\end{minipage}}%\par\addvspace{3ex plus 1ex}\vskip -\parskip
}
\begin{document}Pruebas del paquete listings\begin{example}$$\oint_{S}\vec{E}\cdot d\vec{S}=\frac{q}{\epsilon_{0}} $$\end{example}
\begin{lstlisting}[style=L]\begin{trivlist}
\item\input{\jobname.exa}\end{trivlist}
\end{lstlisting}\begin{ejercicio}Let $H$ be a Hilbert space, $C$ be a closed bounded convex subset of $H$, $T$a nonexpansive self map of $C$. Suppose that as $n\rightarrow\infty$,$a_{n,k}\rightarrow0$ for each $k$, and $\gamma_{n}=\sum_{k=0}ˆ{\infty}\left(a_{n,k+1}-a_{n,k}\right) ˆ{+}\rightarrow0$. Then for each $x$ in $C$,$A_{n}x=\sum_{k=0}ˆ{\infty}a_{n,k}Tˆ{k}x$ converges weakly to a fixed point of$T$ .
The numbered equation\begin{equation}u_{tt}-\Delta u+uˆ{5}+u\left| u\right| ˆ{p-2}=0\text{ in }\mathbf{R}%ˆ{3}\times\left[ 0,\infty\right[ \label{eqn1}%\end{equation}is automatically numbered as equation \ref{eqn1}.
6
\end{ejercicio}\begin{example}Let $H$ be a Hilbert space, $C$ be a closed bounded convex subset of $H$, $T$a nonexpansive self map of $C$. Suppose that as $n\rightarrow\infty$,$a_{n,k}\rightarrow0$ for each $k$, and $\gamma_{n}=\sum_{k=0}ˆ{\infty}\left(a_{n,k+1}-a_{n,k}\right) ˆ{+}\rightarrow0$. Then for each $x$ in $C$,$A_{n}x=\sum_{k=0}ˆ{\infty}a_{n,k}Tˆ{k}x$ converges weakly to a fixed point of$T$ .
The numbered equation\begin{equation}u_{tt}-\Delta u+uˆ{5}+u\left| u\right| ˆ{p-2}=0\text{ in }\mathbf{R}%ˆ{3}\times\left[ 0,\infty\right[ \label{eqn1}%\end{equation}is automatically numbered as equation \ref{eqn1}.\end{example}\begin{example}\begin{equation}\forall x \in \mathbf{R}:\qquad xˆ{2} \geq 0\end{equation}\end{example}\begin{example}\begin{displaymath}xˆ{2} \geq 0\qquad\textrm{para todo }x\in\mathbb{R}\end{displaymath}\end{example}
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