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Electromagnetismo Lorenzo Mijangos Lester Kevin Santiago Torres Jorge De Los Santos Zaldivar Lopez Roman Azel Ejercicio de resistencias.

Electromagnetismo 1

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Page 1: Electromagnetismo 1

Electromagnetismo

Lorenzo Mijangos Lester Kevin

Santiago Torres Jorge De Los Santos

Zaldivar Lopez Roman Azel

Ejercicio de resistencias.

Page 2: Electromagnetismo 1

En el siguiente circuito electrico

encontrar la resistencia

equivalente, y el voltaje en cada

resistencia, ademas de su

intensidad.

Page 3: Electromagnetismo 1

R1=25 Ω

R2=35Ω

R3=10Ω R4=15Ω

R5=12.5Ω

R6=20Ω

R7=5Ω

R8=13Ω

V=110v

Page 4: Electromagnetismo 1

Rq1= r4+r5

Rq1=12.5Ω+15Ω=27.5 Ω

R1=25 Ω

R2=35Ω

R3=10Ω Rq1=27.5C

R6=20Ω

R7=5Ω

R8=13Ω

V=110v

Page 5: Electromagnetismo 1

Rq2=r3+rq1

Rq2=(10)(27.5) Ω = 7.3333Ω

10+27.5

R1=25 Ω

R2=35Ω

Rq2=7.3333Ω

R6=20Ω

R7=5Ω

V=110v

R8=13Ω

Page 6: Electromagnetismo 1

Rq3=r6+rq2

Rq3=(20+7.3333) Ω=27.3333 Ω

R1=25 Ω

R2=35Ω

Rq3=27.3333Ω

R7=5Ω

V=110v

R8=13Ω

Page 7: Electromagnetismo 1

Rq4=r7+r8

Rq4=(5)(13) Ω =3.6111Ω

5+13

Rq5=rq3+r2

Rq4=(35)(27.3333) Ω =15.3475Ω

35+27.3333

R1=25 Ω

Rq5=15.3475Ω

Rq4=3.6111Ω

V=110v

Page 8: Electromagnetismo 1

Rt= r1+ rq5 + rq4

Rt= (25+ 15.3475 + 3.611) Ω= 43.9586 Ω

Rt=43.9586 Ω

V=110v

Page 9: Electromagnetismo 1

Analisis inverso

It=110V = 2.5023 A

43.9586 Ω

Rt= r1+ rq5 + rq4

Rt= (25+ 15.3475 + 3.611) Ω= 43.9586 Ω

R1= 25 Ω I= 2.5023 A

V= 62.5575 V

Rq5= 15.3475 Ω I= 2.5023 A

V= 38.4040 V

Rq4= 3.611 Ω I= 2.5023 A

V= 9.0358 V

It= Vt

Rq

Page 10: Electromagnetismo 1

Rq4=r7+r8

Rq4=(5)(13) Ω =3.6111Ω

5+13

Rq5=rq3+r2

Rq4=(35)(27.3333) Ω =15.3475Ω

35+27.3333

R7=5 Ω I= 1.8071 A

V= 9.0358 V

R8= 13Ω I= 0.6950 A

V= 9.0358 V

Rq4= 3.611 Ω I= 2.5023 A

V= 9.0358 V

Rq5= 15.3475 Ω I= 2.5023 A

V= 38.4040 V

Rq3=27.3333Ω I=1.4050 A

V= 38.4040 V

R2= 35Ω I= 1.0972 A

V= 38.4040 V

Page 11: Electromagnetismo 1

Rq3=r6+rq2

Rq3=(20+7.3333) Ω=27.3333 Ω

R6=20Ω I= 1.4050 A

V= 28.1 V

Rq2= 7.3333Ω I= 1.4050 A

V= 10.3032 V

Rq3=27.3333Ω I=1.4050 A

V= 38.4040 V

Rq2=r3+rq1

Rq2=(10)(27.5) Ω = 7.3333Ω

10+27.5

Rq2= 7.3333Ω I= 1.4050 A

V= 10.3032 V

R3=10 Ω I= 1.0303 A

V= 10.3032 V

Rq1= 27.5Ω I= 0.3745 A

V= 10.3032 V

Page 12: Electromagnetismo 1

Rq1= r4+r5

Rq1=12.5Ω+15Ω=27.5 Ω

Rq1= 27.5Ω I= 0.3745 A

V= 10.3032 V

R4=15 Ω I= 0.3745 A

V= 5.6175 V

R5= 12.5Ω I= 0.3745 A

V= 4.68125 V

Page 13: Electromagnetismo 1

R5= 12.5Ω I= 0.3745 A

V= 4.68125 V

R4=15 Ω I= 0.3745 A

V= 5.6175 V

R6=20Ω

I= 1.4050 A

V= 28.1 V

R3=10 Ω I= 1.0303 A

V= 10.3032 V

R7=5 Ω I= 1.8071 A

V= 9.0358 V

R8= 13Ω I= 0.6950 A

V= 9.0358 V

R2= 35Ω I= 1.0972 A

V= 38.4040 V

R1= 25 Ω I= 2.5023 A

V= 62.5575 V

Page 14: Electromagnetismo 1

R5=12.5Ω

R6=20Ω

R7=5Ω

R8=13Ω

V=110v

R1= 25 Ω I= 2.5023 A

V= 62.5575 V

R2= 35Ω I= 1.0972 A

V= 38.4040 V

R3=10 Ω I= 1.0303 A

V= 10.3032 V

R4=15 Ω I= 0.3745 A

V= 5.6175 V

R5= 12.5Ω I= 0.3745 A

V= 4.68125 V

R6=20Ω

I= 1.4050 A

V= 28.1 V

R7=5 Ω I= 1.8071 A

V= 9.0358 V

R8= 13Ω I= 0.6950 A

V= 9.0358 V