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8/14/2019 F9C98EFA-0495-4A52-AC9F-D36A65140630_001
1/246.002 Fall 2000 Lecture 1
te as: Anant Agarwal and Jeffrey Lang, course material
6.002 CIRCUITS ANDELECTRONICS
Introduction and Lumped Circuit Abstraction
http:/electrical.globalautomation.info
8/14/2019 F9C98EFA-0495-4A52-AC9F-D36A65140630_001
2/246.002 Fall 2000 Lecture 1
e as: Anant Agarwal and Jeffrey Lang, course materials for 6.002 Circuits and Electronics, Spring 2007. MITpenCourseWare (http://ocw.mit.edu/), Massachusetts Institute of Technology. Downloaded on [DD Month YYYY
Lecturer: Prof. Anant Agarwal Textbook: Agarwal and Lang (A&L)
Readings are important!
Handout no. 3 Web site
http://electrical.globalautomation.info
Assignments
Homework exercisesLabsQuizzesFinal exam
ADMINISTRIVIA
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Two homework assignments canbe missed (except HW11).
Collaboration policyHomework
You may collaborate withothers, but do your ownwrite-up.
LabYou may work in a team oftwo, but do you own write-up.
Info handout
Reading for today Chapter 1 of the book
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What is engineering?
What is 6.002 about?
Purposeful use of science
Gainful employment ofMaxwells equations
From electrons to digital gatesand op-amps
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Simple amplifier abstraction
Instruction set abstractionPentium, MIPS 6.004
Software systems 6.033Operating systems, Browsers
Filters
Operationalamplifier abstractionabstraction
-
+
Digital abstraction
Programming languages
Java, C++, Matlab 6.001
Combinational logicf
Lumped circuit abstraction
R V C L M +
6.
00
2
Nature as observed in experiments
0.40.30.20.1I
12963V
Physics laws or abstractions Maxwells
OhmsV = R I
abstraction for
tables of data
Clocked digital abstraction
Analog systemcomponents:Modulators,
oscillators,RF amps,power supplies 6.061
Mice, toasters, sonar, stereos, doom, space shuttle6.1706.455
8/14/2019 F9C98EFA-0495-4A52-AC9F-D36A65140630_001
6/246.002 Fall 2000 Lecture 1
Consider
Suppose we wish to answer this question:
What is the current through the bulb?
V
I
?
The Big Jumpfrom physics
to EECS
Lumped Circuit Abstraction
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We could do it the Hard Way
Apply Maxwells
Differential form Integral form
Faradays
Continuity
Others
t
BE
=
tJ
=
0
E
=
tdlE B
=
t
qdSJ
=
0
qdSE =
8/14/2019 F9C98EFA-0495-4A52-AC9F-D36A65140630_001
8/246.002 Fall 2000 Lecture 1
e as: Anant Agarwal and Jeffrey Lang, course materials for 6.002 Circuits and Electronics, Spring 2007. MITenCourseWare (http://ocw.mit.edu/), Massachusetts Institute of Technology. Downloaded on [DD Month YYYY
Instead, there is an Easy Way
First, let us build some insight:
Analogy
I ask you: What is the acceleration?
You quickly ask me: What is the mass?
I tell you: m
You respond:m
Fa =
Done!!!
F
a ?
8/14/2019 F9C98EFA-0495-4A52-AC9F-D36A65140630_001
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Instead, there is an Easy Way
In doing so, you ignored the objects shape its temperature
its color point of force application
Point-mass discretization
F
a ?
First, let us build some insight:
Analogy
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The Easy Way
Consider the filament of the light bulb.
A
B
We do not care about how current flows inside the filament its temperature, shape, orientation, etc.
Then, we can replace the bulb with a
discrete resistorfor the purpose of calculating the current.
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The Easy Way
A
B
Replace the bulb with a
discrete resistorfor the purpose of calculating the current.
R represents the only property of interestLike with point-mass: replace objects
with their mass m to findm
Fa =
andR
VI =
A
B
R
I+
V
In EE, we do thingsthe easy way
8/14/2019 F9C98EFA-0495-4A52-AC9F-D36A65140630_001
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The Easy Way
R represents the only property of interest
andR
VI =
A
B
R
I+
V
In EE, we do thingsthe easy way
R
VI =
relates element v and iR
called element v-i relationship
8/14/2019 F9C98EFA-0495-4A52-AC9F-D36A65140630_001
13/246.002 Fall 2000 Lecture 1
e as: Anant Agarwal and Jeffrey Lang, course materials for 6.002 Circuits and Electronics, Spring 2007. MITenCourseWare (http://ocw.mit.edu/), Massachusetts Institute of Technology. Downloaded on [DD Month YYYY
R is a lumped element abstraction
for the bulb.
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R is a lumped element abstractionfor the bulb.
Not so fast, though
are definedfor the element
V I
A
B
black box
AS
BS
I
+
V
Although we will take the easy wayusing lumped abstractions for the restof this course, we must make sure (atleast the first time) that ourabstraction is reasonable. In this case,ensuring that
8/14/2019 F9C98EFA-0495-4A52-AC9F-D36A65140630_001
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must be definedfor the element
V I
A
B
black box
AS
BS
I
+
V
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I
I into = I out of
in the filament!True only when 0=
t
qAS BS
BA II = only if 0=
t
q
t
qdSJdSJ
A BS S
=
AI BI
AS
dSJ
BS
dSJ
fromMax
well
must be defined. True when
So lets assume this
8/14/2019 F9C98EFA-0495-4A52-AC9F-D36A65140630_001
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V
defined whenABV 0=
t
B
outside elementsdlEVABAB
=
see
A&L
Must also be defined.
So lets assume this too
So
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Lumped circuit abstraction applies when
elements adhere to the lumped matterdiscipline.
Lumped Matter Discipline (LMD)
0=
tB
outside
0=
t
qinside elementsbulb, wire, battery
Or self imposed constraints:
More inChapter 1of A & L
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Lumped element exampleswhose behavior is completelycaptured by their VIrelationship.
Demoonly for thesorts ofquestions we
as EEs wouldlike to ask!
Exploding resistor democant predict that!
Pickle demo
cant predict light, smell
Demo
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Replace the differential equationswith simple algebra using lumped
circuit abstraction (LCA).
For example
What can we say about voltages in a loopunder the lumped matter discipline?
+
1R
2R
4R
5R
3R
a
b d
c
V
So, what does this buy us?
8/14/2019 F9C98EFA-0495-4A52-AC9F-D36A65140630_001
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What can we say about voltages in a loopunder LMD?
+
1R
2R
4R
5R
3R
a
b d
c
V
tdlE B
= under DMD
0
Kirchhoffs Voltage Law (KVL):
The sum of the voltages in a loop is 0.
=++bcabca
dlEdlEdlE 0
=+++bcabca
VVV 0
8/14/2019 F9C98EFA-0495-4A52-AC9F-D36A65140630_001
22/246.002 Fall 2000 Lecture 1
e as: Anant Agarwal and Jeffrey Lang, course materials for 6.002 Circuits and Electronics, Spring 2007. MITenCourseWare (http://ocw.mit.edu/), Massachusetts Institute of Technology. Downloaded on [DD Month YYYY
What can we say about currents?
Consider
ScaI daI
baI
a
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What can we say about currents?
ScaI daI
baI
t
qdSJ
S
= under LMD
0
0=++badaca III
Kirchhoffs Current Law (KCL):
The sum of the currents into a node is 0.
simply conservation of charge
a
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24/24
KVL:0
loop
KCL:
node
=j j
0=j ji
KVL and KCL Summary