Upload
buiminh
View
216
Download
1
Embed Size (px)
Citation preview
www.le.ac.uk
21 – Fracture and Fatigue Revision
EG2101 / EG2401 March 2015 Dr Rob Thornton Lecturer in Mechanics of Materials
2
Fracture concepts
• Fracture:
– Initiation and propagation of cracks within a material
– Structure no longer sustains any applied loading
– Often occurs at nominal stresses/strains below those material is expected to sustain (why?)
• Design against fracture:
– Crack-free materials are difficult to produce
– Therefore, we design for non-propagation or controlled propagation of cracks
3
Fracture mechanisms (1)
• Brittle (fast) fracture:
– Failure occurs without plastic deformation
– Crystalline materials split along defined planes
• Ductile fracture:
– Failure occurs following necking or shearing
– Substantial plastic deformation
Transgranular (Cleavage)
Intergranular
Rupture
4
Fracture mechanisms (2)
• Type of fracture dependent on:
– Material bonding and structure
– Type of stress applied (e.g. tensile, shear, torsion)
– Rate of stress application
– Temperature (creep)
– Operating environment (corrosion)
– Component geometry (stress concentrators)
– Internal flaws (e.g. vacancies, precipitates, cracks etc.)
– External flaws (e.g. cracks, oxides etc.)
5
Brittle fracture by cleavage
• Occurs in materials where the yield strength is high relative to the bonding strength: – e.g. ceramics, glasses
• As p.d. does not occur, stress at sharp crack tips becomes extremely high: – Sufficient to break
interatomic bonds
• Brittle or fast fracture can propagate at the speed of sound
Crack propagation by cleavage Jones and Ashby, (2011), Engineering Materials 1
So what do brittle fractures look like?
c
6
Brittle fracture – Zn at -120°C
• Very ductile at room temperature Not so much at -120°C when Zn has gone through its ductile-brittle transition phase
• Smooth surfaces are characteristic of brittle fractures
7
Brittle fracture – Al-Li 8090
• Aluminium alloys are usually ductile – but not when inclusions form along grain boundaries… this is an example of an intergranular fracture
8
Ductile fracture by tearing
• In ductile materials, yield strength is low relative to bonding strength, hence p.d. occurs near crack tip: – e.g. metals, polymers
• Within the plastic zone, voids nucleate and grow near defects
• Voids grow, coalesce (merge); allowing crack to propagate
Nucleation
Growth
Coalescence
Crack propagation by ductile tearing Jones and Ashby, (2011), Engineering Materials 1
9
Ductile fracture – (Almost) pure Cu
• Cu is a very ductile material – and can display stable necking if processed correctly
• Ductile tearing can occur as voids nucleate and grow around precipitates or inclusions and then coalesce
• Rough surfaces are characteristic of ductile fracture
10
Fracture mechanics approaches
• Energy balance criterion (Griffith, brittle materials):
– An existing crack will propagate if crack growth releases more stored energy than is absorbed by the creation of the new crack surface
– 𝑈 = 𝑈𝑒 + 𝑈𝑠 ⇒d𝑈
d𝑎> 0 for crack stability
• Stress intensity factors (Irwin, ductile materials):
– The elastic stress distribution in a loaded material is distorted near crack tips and can be characterised if we assume standard crack geometries
– 𝜎𝑖𝑗 𝑟, 𝜃 ≈𝐾
2𝜋𝑟𝑓𝑖𝑗 𝜃 where 𝐾 = 𝑌𝜎 𝜋𝑎
Objective: To determine the critical size of defect necessary for fast fracture to occur
11
Energy balance criterion (1)
• Assume a plate contains an edge-crack (grossly enlarged!)
– Under an applied stress, crack grows by δa
• For crack growth, work must be done (energy must be input):
– δW represents work required to enlarge crack by δa
• Crack growth releases elastic energy but requires energy for crack surface:
– ⇒ δ𝑊 = δ𝑈𝑒 + δ𝑈𝑠
σ
σ
a δa
12
Energy balance criterion (2)
• ⇒ δ𝑊 = δ𝑈𝑒 + δ𝑈𝑠
• Energy absorbed by new crack tip:
– δ𝑈𝑠 = 𝐺𝑐𝑡δ𝑎
• Gc is a material property:
– Toughness or critical strain energy release rate
• ‘Tough’ materials have high Gc:
– Copper, Gc ≈ 106 Jm-2
– Glass, Gc ≈ 10 Jm-2
• In tough materials it is difficult for cracks to propagate
σ
σ
a δa
13
U
a
Energy balance criterion (6)
• 𝜎 𝜋𝑎𝑐 = 𝐸𝐺𝑐 or
𝜎𝑐 𝜋𝑎 = 𝐸𝐺𝑐
• Total energy, 𝑈 = 𝑈𝑒 + 𝑈𝑠
• Critical crack length ac:
– Unstable equilibrium
• If a < ac:
– Growth requires additional energy (stress)
• If a > ac:
– Growth reduces energy
– Spontaneous and catastrophic
ac
d𝑈
d𝑎= 0
𝑈𝑠 = 𝐺𝑐𝑡𝑎
𝑈𝑒 = −𝜎2
2𝐸
𝜋𝑎2𝑡
2
14
Stress intensity factor (1)
• From our fast fracture condition, 𝜎 𝜋𝑎 = 𝐸𝐺𝑐, we can also see that: – A critical combination of stress and crack length exist
when fast fracture will commence
• Defining LHS as the stress intensity factor:
– 𝐾 = 𝜎 𝜋𝑎 (MN m-3/2)
• Defining RHS (only material properties) as the fracture toughness:
– 𝐾𝑐 = 𝐸𝐺𝑐 (MN m-3/2)
• Fast fracture occurs when:
– 𝐾 = 𝐾𝑐
15
Stress intensity factor (2)
• Strictly the result 𝐾 = 𝜎 𝜋𝑎 is only valid for wide plates (thin, semi-finite materials)
• A correction factor must be applied:
– For an edge-crack in a semi-finite plate (W >> a) 𝐾 = 1.12𝜎 𝜋𝑎
– In general, for other geometries:
𝐾 = 𝑌𝜎 𝜋𝑎
• Values for Y can be found in data books
σ
σ
a
W
16
Stress intensity factor (3)
σ
a
σy
Failure by yielding
Failure by fast fracture
σc
𝜎𝑐 =𝐾𝑐
𝜋𝑎
ay
𝜎𝑦 =𝐾𝑐𝜋𝑎𝑦
17
What is fatigue?
• Fatigue: – Slow crack growth at loads less than that described by
the fast fracture criterion, 𝐾 = 𝐾𝑐 – Occurs due to cyclic loading
• Why is understanding fatigue important? – Estimated that 75% of all failures in engineering
components due to fatigue – e.g. De Havilland Comet failures
• Design against fatigue: – Minimise both initial size and rate of growth of cracks – Use of S-N curves to ensure stress cycling does not
exceed the fatigue limit of the material
18
σy
σa
σa
εa
εa
Fatigue loading (2)
Linear-elastic Linear-elastic / yielding
Δεpl
Δεel
Δσ
Δεtot
Δσ
19
101 102 103 104 105 106
∆𝜀𝑡𝑜𝑡
2 (
log
scal
e)
2𝑁𝑓 (log scale)
Fatigue loading (4)
• Fatigue curve results from elastic and plastic strain amplitudes: ∆𝜀𝑡𝑜𝑡
2≈
𝜎𝑓′ 2𝑁𝑓𝑏
𝐸+ 𝜀𝑓′ 2𝑁𝑓
𝑐
• Constants b and c determined from fitting test data; typically:
– -0.12 < b < -0.05
– -0.7 < c < -0.5
𝜎𝑓′
𝐸
𝜀𝑓′
𝜎𝑚, 𝜀𝑚 = 0
True fracture strain
True fracture stress
20
Fatigue failure surfaces
• Characteristics:
– No necking prior to failure elastic strain
– Flat fracture surface
– ‘Beach’ marks visible
– Brittle or ductile fracture follows fatigue surface
21
Fatigue failure – rotating steel shaft
• Initiation at stress concentrating feature
• Beach marks formed during each loading cycle
• Fracture occurs once component can no longer sustain applied stress
22
Fatigue of cracked components (3)
Δσ
Δσ
a δ
Initial crack
Tension Crack widens by δ
Unloading Crack grows by ≈ δ
Tension Crack grows by da/dN
≈ δ
Fatigue crack growth Jones and Ashby, (2011), Engineering Materials 1
23
104 105 106 107 108 109
500
400
300
200
100
Stress-cycle (S-N) curves
σa / MPa
Nf
Fatigue limit
0.4%C steel
2000 series Al-Cu
Wöhler curve: Stress amplitude (S) against logarithmic cycles to failure (Nf)
N
Endurance limit for N cycles
24
Fatigue of cracked components (5)
• Crack growth per cycle (da/dN):
– Steady-state crack growth rate, d𝑎
d𝑁= 𝐴 ∆𝐾 𝑚
• If initial (a0) and failure lengths (af) are known:
𝑁𝑓 = d𝑁𝑁𝑓
0
⇒ 𝑁𝑓 = d𝑎
𝐴 ∆𝐾 𝑚
𝑎𝑓𝑎0
log
d𝑎
d𝑁
log ∆𝐾 K0 Kmax = Kc
Fast fracture
Thre
sho
ld
Paris’ Law
d𝑎
d𝑁= 𝐴 ∆𝐾 𝑚
25
Variable loading
• Typically, Δσ changes during life of components (e.g. due to wind loading, haulage loads, fuel load):
– How do we calculate total cycles to failure?
• Miner’s Rule:
– The sum of the fractions of the cycles to fracture under each loading regime equals 1
𝑁𝑖
𝑁𝑓𝑖𝑖 = 1 =
𝑁1
𝑁𝑓1+
𝑁2
𝑁𝑓2+
𝑁3
𝑁𝑓3…
– Procedure: 1) For each stress range, divide number of cycles by calculated cycles to failure 2) Add fractions until the sum exceeds 1 – at which point fracture should have occurred
26
Exam reminder
• Two and a half hours:
– 6 questions in two sections; answer 4 in total
– Part A – Answer one question out of two
– Part B – Answer three questions out of four
• Questions in Part A do not follow style of previous years’ examples:
– New lecturer, new content – new example slides!
www.le.ac.uk
Good luck!