Upload
others
View
0
Download
0
Embed Size (px)
Citation preview
Chemical Kinetics
박준원 교수(포항공과대학교 화학과)
General Chemistry
• Rate laws
• Reaction mechanisms
• Reaction mechanisms and rate
• Effect of temperature on reaction rates
• Catalysis
이번 시간에는!
Chemical Kinetics (I-1)
박준원 교수(포항공과대학교 화학과)
General Chemistry
• Why do some chemical reactions proceed with lightning
speed when others require days, months, or even years?
• How do catalysts increase the rates of chemical reactions?
• Why do small changes in temperature often have large
effects on the reaction rate?
• How does a study of the rate of a chemical reaction inform
us about the way in which molecules combine to form
products?
All of these questions is the subject of chemical kinetics.
Rate of chemical reactions
𝑎A + 𝑏B → 𝑐C + 𝑑D
Average reaction rate = change in concentration
chage in time
Average rate = ∆[P]∆𝑡
, [P] = concentration of a product
rate = −1
𝑎
𝑑[A]
𝑑𝑡 = −
1
𝑏
𝑑 B𝑑𝑡
= 1
𝑐
𝑑 C𝑑𝑡
=1
𝑑
𝑑 D𝑑𝑡
[18.1]
1
<Measuring reaction rates>
Rate laws
The relation between the rate of a reaction and concentration is
called a rate law.
Rate law (or empirical rate expression)
zeroth order in A for n = 0; first order in A for n = 1; second
order in A for n = 2; the order of a reaction does not have to be
an integer. Overall reaction order is n + m.
rate = 𝑘[A]𝑛[B]𝑚
2
<Integrated rate laws>
Integrated rate law expresses the concentration
of a species directly as a function of time.
First-order reactions
[ F I G U R E 1 8 . 6 ]
N2O5 g → 2 NO2 g + 1
2 O2(g)
rate = −𝑑 N2O5
𝑑𝑡= 𝑘[N2O5]
𝑐 = 𝑐0𝑒−𝑘𝑡 (𝑐0: initial concentration) [18.2]
𝑡1/2 = ln 2𝑘
= 0.6931
𝑘 [18.3]
Oxtoby, D. W.; Gillis, H. P.; Campion, A., Principles of modern chemistry, 7th ed.; Cengage Learning: Boston, 2012; p 844.
second-order reactions
2 N02 g → 2 NO g + O2(g)
rate = −1
2
𝑑 NO2
𝑑𝑡= 𝑘[NO2]
2
1
𝑐=
1
𝑐0+ 2𝑘𝑡 [18.4]
𝑡1/2 =1
2𝑘[NO2]0
[ F I G U R E 1 8 . 7 ]
Oxtoby, D. W.; Gillis, H. P.; Campion, A., Principles of modern chemistry, 7th ed.; Cengage Learning: Boston, 2012; p 845.
Reaction mechanisms
Many reactions do not occur in a single step, but rather proceed
through a sequence of steps to arrive at the products. Each step
is called an elementary reaction and occurs through the collisions.
<Elementary reactions>
A unimolecular elementary reaction involves only a single
reactant molecule.
3
N2O5∗ g → NO2 g + NO3 g
rate = 𝑘[N2O5∗]
The most common type of elementary reaction involves the collision of two atoms, ions, or molecules, and is called bimolecular.
A termolecular reaction step involves the simultaneous collision of three molecules.
Elementary reactions involving collisions of four or more molecules are not observed, and even termolecular collisions are rare if other pathways are possible.
NO g + O3 g → NO2 g + O2(g)
rate = 𝑘 NO [O3]
I g + I g + Ar(g) → I2(g) + Ar(g)
rate = 𝑘[I]2[Ar]
Solvent molecules are present in liquid phase and may affect the reaction,
even though they do not appear in the rate expression because the
solvent concentration cannot be varied appreciably.
<Reaction mechanism>
A reaction mechanism is a detailed sequence of elementary reactions.
eq 1 + eq 2 ->
A reaction intermediate (here, NO3) is a chemical species that is formed
and consumed in the reaction.
NO2 g + NO2 g → NO3 g + NO g (slow) eq 1
NO3(g) + CO(g) → NO2(g) + CO2(g) (fast) eq 2
2 NO2(g) + NO3(g) + CO(g) → NO3(g) + NO(g) + NO2(g) + CO2(g)
NO2(g) + CO(g) → NO(g) + CO2(g)
<Kinetics and chemical equilibrium>
2 NO g + 2 H2 g ⇄ N2 g + 2 H2O(g)
NO g + NO g ⇄ N2O2 g
N2O2 g + H2 g ⇄ N2O g + H2O g
N2O g + H2 g ⇄ N2 g + H2O(g)
𝑘1
𝑘−1 𝑘2
𝑘−2 𝑘3
𝑘−3
𝐾 = 𝐾1𝐾2𝐾3 =[H2O]𝑒𝑞
2 [N2]𝑒𝑞
[NO]𝑒𝑞2 [H2]𝑒𝑞
2
=𝑘1𝑘2𝑘3
𝑘−1𝑘−2𝑘−3=
[N2O2]𝑒𝑞[N2O]𝑒𝑞[H2O]𝑒𝑞[N2]𝑒𝑞[H2O]𝑒𝑞
[NO]𝑒𝑞2 [N2O2]𝑒𝑞[H2]𝑒𝑞[N2O]𝑒𝑞[H2]𝑒𝑞
Chemical Kinetics (I-2)
박준원 교수(포항공과대학교 화학과)
General Chemistry
Reaction mechanisms and rate
In many reactions mechanisms, one step is significantly slower than all the others; this step is called the rate-determining step.
If the rate-determining step is the first one, the analysis is particularly simple.
A possible mechanism is
The first step is slow and determines the rate (𝒌𝐨𝐛𝐬 = 𝒌𝟏), and the subsequent fast step does not affect the reaction rate.
4
2 NO2 g + F2 g → 2 NO2F(g)
rate = 𝒌𝐨𝐛𝐬 NO𝟐 [F𝟐]
NO2(g) + F2(g)𝑘1→NO2F(g) + F g (slow)
NO2(g) + F(g)𝑘2→NO2F(g) (fast)
Mechanisms in which the rate-determining step occurs after one or more
fast steps are often signaled by a reaction order greater than 2, by a
non-integral reaction order, or by an inverse concentration dependence
on one of the species.
An example is
One possible mechanism would be a single-step termolecular reaction,
but termolecular collisions are rare, and if there is an alternative pathway
it is usually followed.
2 NO g + O2 g → 2 NO2(g)
rate = 𝒌𝐨𝐛𝐬[NO]𝟐[𝐎𝟐]
One such alternative is the two-step mechanism
NO g + NO g ⇄ N2O2 g fast equilibrium
N2O2 g + O2 g ⇄ 2 NO2(g) slow
rate = 𝑘2 N2O2 [O2]
[N2O2]
[NO]2=
𝑘1
𝑘−1= 𝐾1
[N2O2] = 𝐾1[NO]2
rate = 𝑘2𝐾1[NO]2[O2]
𝑘1
𝑘2 𝑘−1
𝑘−2
<The steady state approximation>
In some reaction mechanisms, there is no single step that is much slower
than the others. In such cases we use the steady-state approximation.
𝑘−1
𝑘1
N2O5 g + M g ⇄ N2O5∗(g) + M(g)
N2O5∗ g
𝑘2→ NO3(g) + NO2(g)
NO3 g + NO2 g 𝑘3→ NO g + NO2 g + O2 g (fast)
NO3 g + NO g 𝑘4→ 2 NO2 g (fast)
N2O5(g) → 2 NO2(g) +1
2 O2(g)
The N2O5* is a reactive intermediate. The net rate of change of [N2O5
*] is
then
The approximation consists of the assumption that after the short time
the rate of production and loss of N2O5* becomes equal, and
setting the rate of change of the N2O5* concentration to 0 gives
solving for [N2O5*] gives
𝑑[N2O5
∗]
𝑑𝑡= 𝑘1 N2O5 [M] − 𝑘−1[N2O5
∗][M] − 𝑘2[N2O5∗]
𝑑[N2O5∗]
𝑑𝑡= 0 = 𝑘1 N2O5 [M] − 𝑘−1[N2O5
∗][M] − 𝑘2[N2O5∗]
N2O5∗ 𝑘2 + 𝑘−1 M = 𝑘1 N2O5 [M]
N2O5∗ =
𝑘1 N2O5 [M]
𝑘2 + 𝑘−1[M]
The rate of the overall reaction N2O5 → 2 NO2 +1
2 O2 is
The expression has two limiting cases:
1. Low pressure When [M] is small enough, 𝒌𝟐 ≫ 𝒌−𝟏 M and we can use
the approximation.
2. High pressure When [M] is large enough, 𝒌−𝟏 M ≫ 𝒌𝟐 and we can use
the approximation.
𝑟𝑎𝑡𝑒 =1
2
𝑑[NO2]
𝑑𝑡= 𝑘2 N2O5
∗ =𝑘1𝑘2 N2O5 [M]
𝑘2 + 𝑘−1[M]
rate = 𝑘1 N2O5 M (second order)
rate =𝑘1
𝑘−1 𝑘2 N2O5 = 𝐾1𝑘1[N2O5] (first order)
Chemical Kinetics (II-1)
박준원 교수(포항공과대학교 화학과)
General Chemistry
Effect of temperature on reaction rates
<Gas-phase reaction rate constants>
Some reactions do proceed at each collision event; rate constant of 𝟏 ×𝟏𝟎𝟏𝟎 𝐋𝐦𝐨𝐥−𝟏𝐬−𝟏.
However, reaction rates that are much lower – by factors of 1012 or more – are common.
The rate of many chemical reactions increase extremely rapidly at temperature increases, typically a 10℃ rise in temperature may double the rate. In 1889 Svante Arrhenius suggested
Where 𝐸a is a constant with dimensions of energy and A is a constant with the same dimensions as k. Taking the natural logarithm of this equation gives
5
𝑘 = 𝐴𝑒−𝐸a/𝑅𝑇 [18.5]
ln 𝑘 = ln𝐴 −Ea
RT [18.6]
𝑬𝒂 is known as the activation energy. The fraction of molecules having
more than the critical energy 𝐸a increases exponentially as exp (-𝐸a/RT).
𝑇1
𝑇2
𝑇2 > 𝑇1
Frac
tio
n o
f m
ole
cule
s
𝑢 = 2𝜀/𝑚
Speed [ F I G U R E 1 8 . 1 0 ]
Oxtoby, D. W.; Gillis, H. P.; Campion, A., Principles of modern chemistry, 7th ed.; Cengage Learning: Boston, 2012; p 858.
<The reaction coordinate and the activated complex>
Activated complex or transition state
The activation energy for an elementary reaction is always positive, but some overall reactions manifest “negative activation energies”.
Oxtoby, D. W.; Gillis, H. P.; Campion, A., Principles of modern chemistry, 7th ed.; Cengage Learning: Boston, 2012; p 858.
[ F I G U R E 1 8 . 1 1 ]
Reaction in solution
Reactions in solution are much more complicated to describe than their gas-
phase counterparts because the transport mechanism in solutions is much
different. Collisions between reactants in solution occur much less frequently
than for those in the gas phase, but the reactants may be bound together by
a “cage” of solvent molecules for sufficiently long periods that they can
acquire enough energy through collisions
k1 << k2, if k1 is limited by the rate at which the reactants encounter
one another by diffusion we call the reaction diffusion-controlled.
k2 << k1 and k2, reactions are often called activation-energy-controlled.
𝑘1
𝑘−1
6
with the solvent to react.
AB𝑘2→products
A + B ⇄ AB
Chemical Kinetics (II-2)
박준원 교수(포항공과대학교 화학과)
General Chemistry
Catalysis
A catalyst is a substrate that takes part in a chemical reaction and
speeds up the rate but undergoes no permanent chemical
change itself. Catalysts therefore
do not appear in the overall
balanced chemical equation.
7
Oxtoby, D. W.; Gillis, H. P.; Campion, A., Principles of modern chemistry, 7th ed.; Cengage Learning: Boston, 2012; p 870.
[ F I G U R E 1 8 . 1 9 ]
In homogeneous catalysis the catalyst is present in the same
phase as the reactants.
In heterogeneous catalysis the catalyst is present as a phase
distinct from the reaction mixture.
C𝟐H𝟒(g) + H𝟐(g) → C𝟐H𝟔(g) solid oxide of vanadium (V2O5) as a
catalyst.
TI+ 𝑎𝑞 + 2 Ce4+ 𝑎𝑞Ag+(𝑎𝑞)
TI3+ 𝑎𝑞 + 2 Ce3+(𝑎𝑞)
<Enzyme catalysis>
The vast majority of chemical reactions in living organisms are
catalyzed by enzymes, proteins that have evolved to enhance
reaction rates by many orders of magnitude with exquisite
selectivity.
The major classes and the reactions they catalyze include (1)
oxidoreductase – redox reactions; (2) transferase – functional
group transfer reactions; (3) hydrolase – hydrolysis reactions; (4)
lyase – addition to carbon-carbon double bonds; (5) isomerase –
isomerization reactions; (6) ligase – bond-forming reactions.
<Enzyme kinetics>
The kinetics of enzyme-catalyzed reactions is generally treated using the
steady-state approximation in a form that has become known as
Michaelis-Menten kinetics.
In which E represents the free enzyme, S is the substrate, ES represents
the complex formed, and P is the final product.
The concentration of
𝑘1
𝑘−1
[ES] reaches a steady state.
E + S ⇄ ES
ES 𝑘2→ E + P
𝑑[ES]
𝑑𝑡= 0 = 𝑘1 E S − 𝑘−1 ES − 𝑘2[ES]
The concentration of the free enzyme ([E]) is [ET] – [ES], where [ET] is the
total concentration of enzyme present (i.e., the concentration of enzyme
initially added [Eo].).
𝑑[ES]
𝑑𝑡= 0 = 𝑘1 ET S − 𝑘1[ES][S] − 𝑘−1 ES − 𝑘2[ES]
ES =𝑘1 ET [S]
𝑘−1 + 𝑘2 + 𝑘1[S]
We define the Michaelis constant Km
(in units of molarity) as
𝐾m =𝑘−1 + 𝑘2
𝑘1
Oxtoby, D. W.; Gillis, H. P.; Campion, A., Principles of modern chemistry, 7th ed.; Cengage Learning: Boston, 2012; p 872.
[ F I G U R E 1 8 . 2 2 ]
Substrate molecule
which allows us to express the steady state concentration of [ES] as
ES =ET S
𝐾m + [S]
𝑑[P]𝑑𝑡
= 𝑘2 ES =𝑘2 ET [S]𝐾m+[S]
[18.15] Michaelis-Menten equation
The rate is linear (first-order) with respect to [S] at low substrate
concentrations but rolls over to become independent of [S] at higher
concentrations, saturating at a maximum rate 𝑉max .
At [S] >> 𝐾m, rate = 𝑉max = 𝑘2[ET] from eq [18.15]
Oxtoby, D. W.; Gillis, H. P.; Campion, A., Principles of modern chemistry, 7th ed.; Cengage Learning: Boston, 2012; p 874.
[ F I G U R E 1 8 . 2 3 ]
Rate ≅ 𝑘2
𝐾mET S
at [S] << 𝐾m
An alternative form of Michaelis-Menten equation is
When 𝑑[𝑃]/𝑑𝑡 = 𝑉𝑚𝑎𝑥 /2, 𝐾𝑚 =[S], so we simply use [S] to find 𝐾m
experimentally.
A small value of 𝐾m indicates that the formation of ES complex is faster
than the dissociation of ES complex to the starting materials and the
product.
𝑑[P]
𝑑𝑡= 𝑘2 ES =
Vmax [S]𝐾m+[S]
𝐾m = [S]Vmax
𝑑[𝑃]/𝑑𝑡− 1
Turnover number is defined as the number of substrate molecules
converted into product per enzyme molecule per second, and is easily
calculated from 𝒌𝐜𝐚𝐭.
at saturation,
The turnover numbers for different enzymes vary over an enormously
wide range; each catalase molecule can decompose 40 million molecules
of hydrogen peroxide per second, whereas the turnover number of
chymotrypsin is about 100 and that of lysozymes is about 0.5.
[S] >> 𝐾m, [ES] = [ET], rate = 𝑉max = k2[ET], 𝑘cat ≡ 𝑘2 = 𝑉max /[ET]
A linear version of
Plot the inverse of the rate versus 1/[S], the slope is 𝐾m / 𝑉max, and the
intercept is 1/ 𝑉max .
From the plot, the key parameters (𝑘cat , 𝐾m)
Michaelis-Menten equation is
can be obtained from the rates at a few
concentrations of the substrate.
1
𝑑 P /𝑑𝑡= (
𝐾m
𝑉max)(
1
S) +
1
𝑉max
Oxtoby, D. W.; Gillis, H. P.; Campion, A., Principles of modern chemistry, 7th ed.; Cengage Learning: Boston, 2012; p 875.
[ F I G U R E 1 8 . 2 4 ] 𝐾m =𝑘−1 + 𝑘2
𝑘1
𝐾cat = 𝑉max /[ET]