F ( X )=(X+1)3+X−349

(X ¿¿3+3 X2+3 X+1)¿

+X – 349

3 X3+3 X2+4 X−4

(5 X+1)3+5 X−349

[(5 X )3+3 x 5 X2 x 1+3x 5 X x(1)2+(1)3 ]+ 5X – 349