1. Ci t phn mm Gx-developerB1. Cho a CD c phn mm Gx-developer vo a

B2. Vo Explore => CD m phn mm Gx-developer.

B3. Chn vo mc

M v chy

B4. Sau khi ci xong bc 3 quay v Gx-developer chy file

2. Ci t cp lp trnh v kt ni my tnh vi PLC

Cp kt ni c in ca dng FX c 1 u ni vi PLC v 1 u ni vi cng COM ca my tnh. Hin nay hu ht cc my tnh th h mi u khng c cng COM ni ra ngoi m ch c cng USB. Do vy hin nay ngi ta c thm loi cp lp trnh cho PLC h FX ni c vi cng USB ca my tnh. kt ni c my tnh vi PLC qua cp ny cn phi ci drive cho cp.

B1. Cho a CD drive ca cp vo CD

B2. Vo Explore => CD

B3. Sau khi ci xong bc 2 kim tra xem my tnh nhn cng cha:

Cm cp vo cng USB ca my tnh v cng lp trnh ca PLC, cp ngun cho PLC.

B4. Ci t kt ni cho phn mmM phn mm Gx-develop

Vo Online chn Transfer setup

Nu kt ni thnh cng:

3. Cu to phn cng ca m hnh

4. Cc bi ton cng ngh m phng trn panel thc hnh

u ni vo/ ra ca PLC

+ u ni ra chn cm

+ u ni ra cng 25 chn

Cc bi cng ngh m phng

Bi 1 iu khin n LED 7 on

1- S cng ngh

2- Yu cu cng ngh.+ LED 7 on loi Anot chung.+ Hin th cc s ln lt t 1 n 9, khi bn u lm vic s 0 sng. Sau 1 giy, s 0 tt; sau 0,1 giy s 1 sng trong khong 0,9 giy, tt 0,1 giy. C th ln lt cc s sng tt quay vng trn t 0 n 9. Tng thi gian l 10,1 giy.3- Kt ni v phn cng vo ra+ Cc u ra ca PLC

Y000 = a

Y001 = b

Y002 = c

Y003 = d

Y004 = e

Y005 = f

Y006 = g

+ Cng kt ni CON1+ Cc s ng vi cc thanh LED0 = a,b,c,d,e,f,g

1= b, c

2 = a, b, d, e, g

3 = a, b, c, d, g

4 = b, c, f, g

5= a, c, d, f, g

6= a, c, d, e, f, g

7= a, b, c

8= a, b, c, d, e, f, g

9 = a, b, c, d, f, g

Bi 2- iu khin ng c

1- S cng ngh

2- Yu cu cng ngh.Khi nhn nt start KM0 v KMS ng ng c khi ng kiu sao. Sau thi gian 5,5s KMS tt v sau 0,5s KMD ng li, ng c ni kiu tam gic kt thc qu trnh khi ng. Khi nhn nt stop tt c dng li.3- Kt ni v phn cng vo ra

+ Cc u vo ca PLC

X000 = StartX001 = Stop+ Cc u ra ca PLCY000 = KM0Y001 = KMSY002 = KMD+ S chn kt ni

Bi 3- iu khin h thng bng ti

1- S cng ngh

2- Yu cu cng ngh.

Khi nhn nt Start nu v tr S2 c hp cha sn phm th PLC ra lnh chy SM1 bng ti BT1 chuyn sn phm ti hp. Khi S1 m c 10 sn phm th PLC ra lnh dng SM1, ng thi ra lnh chy SM2 chuyn hp khi bng ti BT2. Khi S3 pht hin hp ri khi BT2 th PLC ra lnh dng SM2. Qu trnh li lp li nu S2 c hp v nhn nt Start.3- Kt ni v phn cng vo ra

+ Phn cng u vo:

Start = X000

Stop = X001

S1 = X002

S2 = X003

S3 = X004

+ Phn cng u ra:SM1 = Y000

SM2 = Y001+ S chn kt ni

Bi 4 iu khin h thng bm nc

1- S cng ngh

2- Yu cu cng ngh.

Nhn nt Start h thng c t vo ch lm vic, nu b di y S1 tc ng, b trn cn S2, S3 khng tc ng th PLC ra lnh chy P bm nc t b di ln b trn. Khi b trn y, c S3, S2 u tc ng th PLC ra lnh dng bm P. Khng c php bm khi b di cn tc l S1 khng tc ng.Khi nhn nt Stop th ton b h thng dng lm vic.

3- Kt ni v phn cng vo ra

+ Phn cng u vo:

Start = X000

Stop = X001

S1 = X002

S2 = X003

S3 = X004

+ Phn cng u ra:

P = Y000

+ S chn kt ni

Bi 5 iu khin ng t n giao thng

1- S cng ngh

2- Yu cu cng ngh.

3- Kt ni v phn cng vo ra.+ Phn cng u vo:

Start = X000

Stop = X001

+ Phn cng u ra:

R1,R2 = Y000Y1,Y2 = Y001

G1,G2 = Y002

R3,R4 = Y003

Y3,Y4 = Y004

G3,G4 = Y005

+ Kt ni vi PLC

Bi 6 iu khin thang my

1- S cng ngh

2- Yu cu cng ngh.

y l thang my dng nng hng trong cc nh hng, nh my, hm m hoc trong xy dng.Ti t iu khin c 4 nt bm iu khin thang n cc tng.

mi tng c gn cm bin pht hin tng.

Thang chuyn ng ln xung nh ng c khng ng b 3 pha quay thun nghch.

Ngi vn hnh bm vo bt k nt n tng no th thang s chy n tng .

3- Kt ni v phn cng vo ra.

+ Phn cng u vo:

T1 = X000

T2 = X001T3 = X002

T4 = X003

S1 = X004

S2 = X005

S3 = X006

S4 = X007+ Phn cng u ra:

KM1 = Y000KM2 = Y001

+ Kt ni vi PLC

Bi 7 iu khin cn nh lng

1- S cng ngh

2- Yu cu cng ngh.

Khi c xe vo v tr cn, S3 cha tc ng(Trn xe cha c liu), nhn nt Start PLC lnh m van V2, khi ng SM1, SM2. Khi liu xung xe , cm bin S3 bo. PLC ra lnh dng SM1, ng V2, sau 1 giy th dng SM2. Khi liu trong xi l cha ht S1, S2 khng tc ng, PLC ra lnh m van V1. Khi liu y xilo S1, S2 tc ng PLC ra lnh kha V1. H thng li lp li nu c xe, S3 cha tc ng v c lnh Start. H thng dng khi nhn nt Stop.3- Kt ni v phn cng vo ra.

+ Phn cng u vo:

Start = X000

Stop = X001

S1 = X002

S2 = X003

S3 = X004

+ Phn cng u ra:

SM1 = Y000

SM2 = Y001

V1 = Y002

V2 = Y003

+ Kt ni vi PLC

Bi 8- iu khin Robot

1- S cng ngh

2- Yu cu cng ngh.

+ Robot kh nn c 3 khu s dng 3 xilanh kh: xilanh XL1 thc hin chuyn ng Phi(P), Tri(T); xilanh XL2 thc hin chuyn ng Ln(L), Xung(X). Xilanh XL3 thc hin Gp(G), Nh(N). Hn v hnh trnh xilanh1 l cc cm bin S1, S2. Hn v hnh trnh xilanh2 l cc cm bin S3, S4. Hn v hnh trnh xilanh3 l cc cm bin S5(nh), S6(gp).+ Khi nhn nt Start pittong ca XL2 i xung X, khi S4 tc ng dng X, ng thi tc ng gp G. Khi S6 tc ng, ra lnh i ln L. Khi S3 tc ng, ra lnh sang phi P. Khi gp S2, ngt L, tc ng X. Khi gp S4 ngt X ng thi ngt G, ng N. Khi gp S5(Nh xong), ngt N ng thi ng L. Khi gp S3, ngt L, ngt P ng thi ng T. Khi gp S1 ngt T, kt thc 1 chu k lm vic. Chu k sau c bt u khi c lnh Start. H thng s dng khi nhn Stop.3- Kt ni v phn cng vo ra.+ Phn cng u vo:

Start = X000

Stop = X001

S1 = X002

S2 = X003

S3 = X004S4 = X005S5 = X006

S6 = X007+ Phn cng u ra:

P = Y000

T = Y001

X = Y002

L = Y003

G = Y004

N = Y005

+ Kt ni vi PLC

Bi 9 iu khin my trn

1- S cng ngh

2- Yu cu cng ngh.

Xil rng, khi nhn nt Start PLC ra lnh chy bm P1 bm liu 1 vo xil, khi liu 1 y n S2, PLC ra lnh dng P1 ng thi chy P2 bm liu 2 vo xil v khi ng ng c SM khuy 2 loi liu vi nhau. Khi liu 2 c bm n S3, PLC ra lnh dng bm P2 v sau 10giy th dng ng c khuy SM ng thi ra lnh m van x V. Khi hn hp c x ht S3, S2, S1 khng tc ng, PLC ra lnh kha V, ng thi ra lnh khi ng P1 bt u m trn th 2. Qu trnh lm vic ca h thng s dng li sau 10 m trn.3- Kt ni v phn cng vo ra.

+ Phn cng u vo:

Start = X000

Stop = X001

S1 = X002

S2 = X003

S3 = X004

+ Phn cng u ra:

P1 = Y000

P2 = Y001

SM = Y002

V = Y003

+ Kt ni vi PLC

Bi 10 iu khin cu trc

1- S cng ngh

2- Yu cu cng ngh.

H thng cu trc lm vic trong 1 nh my c kh c 4 xng: Xng 1 Kho phi v thnh phm; Xng 2- xng gia cng bc 1; Xng 3 xng gia cng bc 2; Xng 4 xng hon thin.Khi nhn nt Start phi s c cu trc ly Xng 1 v chuyn sang Xng 2, ti xng 2 cu trc dng khong 3 giy gia cng, sau n chuyn phi sang xng 3. Ti xng 3 cu trc dng 5 giy, sau chuyn phi sang Xng 4. Ti Xng 4 cu trc dng 2 giy, sau n chuyn thnh phm quay v Xng 1. hn ch hnh trnh ln xung c cc cm bin S1, S2; nhn bit v tr cc xng c cc cm bin S3, S4, S5, S6. truyn ng cho cu trc, dng 2 ng c: 1 thc hin chuyn ng Ln(L) Xung(X); 1 thc hin truyn ng Phi(P) Tri(T). H thng s dng lm vic khi nhn nt Stop.3- Kt ni v phn cng vo ra.+ Phn cng u vo:

Start = X000

Stop = X001

S1 = X002

S2 = X003

S3 = X004S4 = X005

S5 = X006

S6 = X007

+ Phn cng u ra:

P1 = Y000

P2 = Y001

SM = Y002

V = Y003

Chy SETUP.EXE ci drive

Bm phi chut vo My Computer chn Properties

Chn Hardware

Chn Device Manager

Chn Ports(Com & LPT)

Ta s nhn thy cng lp trnh l USB 2.0-SERIAL(COM5)

Vo New Project chn PLC series: FXCPU

Chn PLC type: FX1S

Chn OK.

Bm vo Serial chn COM5, sau chn Connection test kim tra

PAGE 24