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1
III B. Tech I semester (JNTUH-R15)
Prepared
By
Mr. S. Srikanth, Assistant Professor
ELECTRICAL AND ELECTRONICS ENGINEERING
INSTITUTE OF AERONAUTICAL ENGINEERING (AUTONOMOUS)
DUNDIGAL, HYDERABAD – 500 043
2
Power
Electronics (A50220)
3
Unit-I Power Semiconductor Devices &
Commutation Circuits
• Diodes
• Transistors
– Power BJTs
– Power MOSFETs
– Insulated-Gate BJT
• IGBT
– Static Induction
Transistors
• SITs
• Thyristors
– Force-Commutated
– Line-Commutated
– Gate Turn Off--GTO
– Reverse-Conducting
• RCT
– Gate-Assisted Turn-
off
• GATI
4
Thyristor/Triac
SCR1
2N3668
MT1
2N6346
5
Power Electronic Circuits
• Diode Rectifiers (AC to Fixed DC)
• AC-DC Converters (Controlled Rectifiers)
• AC-AC Converters (AC Voltage Controllers)
• DC-DC Converters (DC Choppers)
• DC-AC Converters (Inverters)
• Static Switches
SCR / Thyristor
• Circuit Symbol and Terminal Identification
SCR
2N3668
ANODE
CATHODE
GATE
6
SCR / Thyristor
• Anode and Cathode
terminals as
conventional pn
junction diode
• Gate terminal for a
controlling input signal
SCR
2N3668
ANODE
CATHODE
GATE
7
SCR/ Thyristor
• An SCR (Thyristor) is a “controlled”
rectifier (diode)
• Control the conduction under forward bias
by applying a current into the Gate terminal
• Under reverse bias, looks like conventional
pn junction diode
8
SCR / Thyristor
• 4-layer (pnpn) device
• Anode, Cathode as for a
conventional pn
junction diode
• Cathode Gate brought
out for controlling input
P
N
P
N
Anod
e
Cathod
e
Gate
9
Equivalent Circuit
Q2
BJT_NPN_VIRTUAL
Q1
BJT_PNP_VIRTUAL
ANODE
CATHODE
GATE
P
N
P
N
P
N
CATHOD
E
ANODE
GAT
E
10
Apply Biasing
With the Gate terminal OPEN,
both transistors are OFF. As
the applied voltage increases,
there will be a “breakdown”
that causes both transistors to
conduct (saturate) making IF >
0 and VAK = 0.
VBreakdown = VBR(F)
I
F
IC2=I
B1
I
F
IC1 =
IB2
Q2
BJT_NPN_VIRTUAL
Q1
BJT_PNP_VIRTUAL
ANODE (A)
CATHODE (K)
GATE (G)
Variable
50V
11
Volt-Ampere Characteristic
IF
VAK VBR(
F)
IH Holding
Current
Breakdown Voltage 12
Apply a Gate Current
Q2
BJT_NPN_VIRTUAL
Q1
BJT_PNP_VIRTUAL
ANODE (A)
CATHODE (K)
GATE (G)
Variable
50V
I
F
I
F
IB2
VG
For 0 < VAK < VBR(F),
Turn Q2 ON by applying a
current into the Gate
This causes Q1 to turn ON, and
eventually both transistors
SATURATE
VAK = VCEsat + VBEsat
If the Gate pulse is removed,
Q1 and Q2 still stay ON!
IC2 =
IB1
13
How do you turn it OFF?
• Cause the forward current to fall below the
value if the “holding” current, IH
• Reverse bias the device
14
When the anode is at a positive potential VAK with respect to the cathode with no voltage applied at the gate, junctions J1 and J3 are forward biased, while junction J2 is reverse biased. As J2 is reverse biased, no conduction takes place.
Now if VAK is increased beyond the breakdown voltage VBO of the thyristor, avalanche breakdown of J2 takes place and the thyristor starts conducting.
If a positive potential VG is applied at the gate terminal with respect to the cathode, the breakdown of the junction J2 occurs at a lower value of VAK. By selecting an appropriate value of VG, the thyristor can be switched into the on state suddenly.
Characteristics of thyristors
15
Reverse breakdown voltage
Holding current
Reverse leakage current
Latching current
Forward volt-drop (conducting)
Forward break-over voltage
Forward leakage current
Gate triggered
IH
IL
VBO VAK
IT
Switching Characteristic (IV) Forward breakdown voltage VBO
◦ The voltage of avalanche breakdown
Latching current IL
◦ The minimum anode current required to maintain the thyristor in the on-state immediately after it is turned on and the gate signal has been removed
Holding current IH
◦ The minimum anode current to maintain the thyristor in the on-state
IL > IH
16
Symbol and construction The thyristor is a four-layer, three terminal semiconducting device, with each layer consisting of alternately N-type or P-type material, for example P-N-P-N. The main terminals, labeled anode and cathode, are across the full four layers, and the control terminal, called the gate, is attached to p-type material near to the cathode.
17
• Silicon Controlled Rectifier (SCR).
• TRIAC.
• DIAC.
• Silicon Unilateral Switch (SUS) – has built
in low voltage avalanche diode
Different types of Thyristors
Construction of SUS
18
Application
• Mainly used where high currents and voltages are
involved, and are often used to control alternating currents,
where the change of polarity of the current causes the
device to switch off automatically; referred to as Zero
Cross operation.
• Thyristors can be used as the control elements for phase
angle triggered controllers, also known as phase fired
controllers.
19
Cntd…
• In power supplies for digital circuits, thyristor can be used
as a sort of "circuit breaker" or "crowbar" to prevent a
failure in the power supply from damaging downstream
components, by shorting the power supply output to
ground
Load voltage regulated by thyristor phase control. Red trace: load voltage Blue trace: trigger signal. 20
SCR Ratings
(a) SCR Current Ratings 1- Maximum Repetitive RMS current Rating
• Average on-state current is the maximum average current value that can be carried by the
SCR in its on state.
• RMS value of nonsinusoidal waveform is simplified by approximating it by rectangular
waveform.
• This approximation give higher RMS value, but leaves slight safety factor.
21
22
• Average value of pulse is
• Form factor is
• Knowing the form factor for given waveform, RMS current can be
obtained from
IRMS=fo(IAVE) • Maximum repetitive RMS current is given by
IT(RMS)=fo(IT(AVE)) • Conduction angle verses form factor
23
Conduction angle (θ) Form factor (fo)
20° 5.0
40° 3.5
60° 2.7
80° 2.3
100° 2.0
120° 1.8
140° 1.6
160° 1.4
180° 1.3
Conduction Angle
24
• Duration for which SCR is on. It is measured as
shown
2- Surge Current Rating
Peak anode current that SCR can handle for brief duration.
3- Latching current
Minimum anode current that must flow through the SCR in order for it to
stay on initially after gate signal is removed.
4- Holding Current
Minimum value of anode current, required to maintain SCR in conducting
state.
25
(b) SCR Voltage Ratings
1- Peak repetitive forward blocking voltage
Maximum instantaneous voltage that SCR can block in forward direction.
2- Peak Repetitive Reverse Voltage
Maximum instantaneous voltage that SCR can withstand, without
breakdown, in reverse direction.
3- Non-repetitive peak reverse voltage
Maximum transient reverse voltage that SCR can withstand.
26
(c) SCR Rate-of-Change Ratings
1- (di/dt rating)
Critical rate of rise of on-state current. It is the rate at which anode current increases and must be
less than rate at which conduction area increases.
To prevent damage to SCR by high di/dt value, small inductance is added in series with device.
Vaue of required inductance is
L>= Vp
(di/dt)max
2- dv/dt rating Maximum rise time of a voltage pulse that can be applied to the SCR in the off state without
causing it to fire. Unscheduled firing due to high value of dv/dt can be prevented by using RC
snubber circuit.
27
(d) Gate Parameters
1- Maximum Gate Peak Inverse Voltage Maximum value of negative DC voltage that can be applied without damaging the gate-cathode junction.
2-Maximum Gate Trigger Current Maximum DC gate current allowed to turn on the device.
3- Maximum gate trigger voltage DC voltage necessary to produce maximum gate trigger current.
4- Maximum Gate Power Dissipation
Maximum instantaneous product of gate current and gate voltage that can exist during forward-bias.
5- Minimum gate trigger voltage Minimum DC gate-to-cathode voltage required to trigger the SCR.
6-Minimum gate trigger current Minimum DC gate current necessary to turn SCR on.
28
29
Series and Parallel SCR
Connections
SCRs are connected in series and parallel to
extend voltage and current ratings.
For high-voltage, high-current applications,
series-parallel combinations of SCRs are
used.
30
SCRs in Series
• Unequal distribution of voltage across two series SCRs.
• Two SCRs do not share the same supply voltage. Maximum voltage
that SCRs can block is V1+V2, not 2VBO.
31
• Resistance equalization
• Voltage equalization
32
• RC equalization for SCRs connected in series.
33
SCRs In Parallel • Unequal current sharing between two SCRs is shown:
• Total rated current of parallel connection is I1+I2, not 2I2.
34
• With unmatched SCRs, equal current sharing is achieved by adding low
value resistor or inductor in series with each SCR, as shown below.
• Value of resistance R is obtained from:
R=V1-V2
I2-I1
35
Current sharing in SCRs with parallel reactors
Equalization using resistors is inefficient due to
Extra power loss
Noncompansation for unequal SCR turn-on and turn-off times.
Damage due to overloading
SCRs with center-tapped reactors is shown below.
36
37
SCR Gate-Triggering Circuits
Triggering circuits provide firing signal to
turn on the SCR at precisely the correct time.
Firing circuits must have following
properties 1. Produce gate signal of suitable magnitude and sufficiently short rise time.
2. Produce gate signal of adequate duration.
3. Provide accurate firing control over the required range.
4. Ensure that triggering does not occur from false signals or noise
5. In AC applications, ensure that the gate signal is applied when the SCR is
forward-biased
6. In three-phase circuits, provide gate pulses that are 120° apart with
respect to the reference point
7. Ensure simultaneous triggering of SCRs connected in series or
in parallel.
38
Types Of Gate Firing Signals
1. DC signals
2. Pulse signals
3. AC signals
39
(a) DC Gating Signal From
Separate Source
40
DC Gating signals from Same
Source
41
Disadvantage of DC gating
Signals
1. Constant DC gate signal causes gate
power dissipation
2. DC gate signals are not used for firing
SCRs in AC applications, because
presence of positive gate signal during
negative half cycle would increase the
reverse anode current and possibly
destroy the device. 42
(2) Pulse Signals
1. Instead of continuous DC signal, single
pulse or train of pulses is generated.
2. It provides precise control of point at
which SCR is fired.
3. It provides electrical isolation between
SCR and gate-trigger circuit.
43
SCR trigger circuits using UJT
oscillator Circuit A
44
Circuit B
45
SCR trigger circuit using DIAC
46
SCR trigger circuit using
Optocoupler
47
(c) AC Signals
48
Resistive phase control RC
phase control
Triggering SCRs in Series and in
Parallel
49
50
SCR Turnoff (Commutation)
Circuits
What is Commutation?
The process of turning off an SCR is
called commutation.
It is achieved by 1. Reducing anode current below holding current
2. Make anode negative with respect to cathode
Types of commutation are: 1. Natural or line commutation
2. Forced commutation 51
SCR Turnoff Methods
1. Diverting the anode current to an alternate path
2. Shorting the SCR from anode to cathode
3. Applying a reverse voltage (by making the cathode positive with
respect to the anode) across the SCR
4. Forcing the anode current to zero for a brief period
5. Opening the external path from its anode supply voltage
6. Momentarily reducing supply voltage to zero
52
(1) Capacitor Commutation
• SCR turnoff circuit using a transistor
switch
53
• SCR turnoff circuit using commutation
capacitor
• Value of capacitance is determined by:
C>= tOFF
0.693RL
54
(2) Commutation By External
Source
55
(3) Commutation by Resonance . Series resonant turnoff circuit
56
57
Parallel resonant turnoff circuit
(4) AC line commutation
58
59
Other members of Thyristor
Family
Power Semiconductor Switches
Power Diodes Power Transistors Thyristors
2 layer device 3 layer Device 4 layer Device
• Thyristor devices can convert and control large amounts of power in AC or DC systems while using very low power for control.
• Thyristor family includes
1- Silicon controlled switch (SCR)
2- Gate-turnoff thyristor (GTO)
3- Triac
4- Diac
5- Silicon controlled switch (SCS)
6- Mos-controlled switch (MCT)
60
Other Types of Thyristors
61
1. Silicon Controlled Switch (SCS)
2. Gate Turnoff Thyristor (GTO)
3. DIAC
4. TRIAC
5. MOS-Controlled Thyristor (MCT)
1. SCS
62
Structure
Symbol
Equivalent circuit
for SCS
(2) GTO
63
Structure
Symbol
GTO Ideal VI
characteristiccs
(3) DIAC
64
Structure
Symbol
VI characteristics
of diac
(4) Triac
65
Structure Symbol SCR
equivalent circuit
Triac VI characteristics
66
(5) MCT
67
Symbol equivalent
circuit
MCT VI
characteristics
UNIT-II AC-DC CONVERTERS (1-PHASE &
3-PHASE CONTROLLED RECTIFIERS)
Introduction to Line commutated Inverter
70
• Type of input: Fixed voltage, fixed frequency
ac power supply.
• Type of output: Variable dc output voltage
• Type of commutation: Natural / AC line
commutation
Line
CommutatedConverter
+
-
DC Output
V0(dc)
AC
Input
Voltage
71
Different types of
Line Commutated Converters
• AC to DC Converters (Phase controlled
rectifiers)
• AC to AC converters (AC voltage controllers)
• AC to AC converters (Cyclo-converters) at low
output frequency.
72
Differences Between
Diode Rectifiers
&
Phase Controlled Rectifiers
Cntd…
73
• The diode rectifiers are referred to as uncontrolled rectifiers .
• The diode rectifiers give a fixed dc output voltage .
• Each diode conducts for one half cycle.
• Diode conduction angle = 1800 or radians.
• We can not control the dc output voltage or the average dc load current in a diode rectifier circuit.
74
Single phase half wave diode rectifier gives an
Average dc output voltage
Single phase full wave diode rectifier gives an
2Average dc output voltage
m
O dc
m
O dc
VV
VV
Cntd…
75
Applications of
Phase Controlled Rectifiers
• DC motor control in steel mills, paper and
textile mills employing dc motor drives.
• AC fed traction system using dc traction motor.
• Electro-chemical and electro-metallurgical
processes.
• Magnet power supplies.
• Portable hand tool drives.
76
Classification of
Phase Controlled Rectifiers
• Single Phase Controlled Rectifiers.
• Three Phase Controlled Rectifiers.
77
Different types of Single
Phase Controlled Rectifiers.
• Half wave controlled rectifiers.
• Full wave controlled rectifiers.
Using a center tapped transformer.
Full wave bridge circuit.
Semi converter.
Full converter.
78
Different Types of
Three Phase Controlled Rectifiers
• Half wave controlled rectifiers.
• Full wave controlled rectifiers.
• Semi converter (half controlled
bridge converter).
• Full converter (fully controlled
bridge converter).
Principle of Phase Controlled Rectifier
Operation
80
Principle of Phase Controlled
Rectifier Operation
81
Single Phase Half-Wave Thyristor
Converter with a Resistive Load
82
Supply Voltage
Output Voltage
Output (load)
Current
83
Supply Voltage
Thyristor Voltage
84
Equations
sin i/p ac supply voltage
max. value of i/p ac supply voltage
RMS value of i/p ac supply voltage2
output voltage across the load
s m
m
mS
O L
v V t
V
VV
v v
85
When the thyristor is triggered at
sin ; to
Load current; to
sinsin ; to
Where max. value of load current
O L m
OO L
mO L m
mm
t
v v V t t
vi i t
R
V ti i I t t
R
VI
R
86
To Derive an Expression for the
Average (DC)
Output Voltage Across The Load
87
2
0
1. ;
2
sin
1sin .
2
1sin .
2
dc OO dc
O m
dc mO dc
mO dc
V V v d t
v V t for t to
V V V t d t
V V t d t
88
sin .2
cos2
cos cos ; cos 12
1 cos ; 22
m
O dc
m
O dc
m
O dc
mm SO dc
VV t d t
VV t
VV
VV V V
89
max
max
Maximum average (dc) o/p
voltage is obtained when 0
and the maximum dc output voltage
1 cos0 ; cos 0 12
mdmdc
mdmdc
VV V
VV V
90
0
1 cos ; 22
The average dc output voltage can be varied
by varying the trigger angle from 0 to a
maximum of 180 radians
We can plot the control characteristic
v by using the eq
mm SO dc
O dc
VV V V
V s
uation for
O dcV
Cntd…
91
Control Characteristic
of
Single Phase Half Wave Phase
Controlled Rectifier
with
Resistive Load
92
The average dc output voltage is given by the
expression
1 cos2
We can obtain the control characteristic by
plotting the expression for the dc output
voltage as a function of trigger angle
m
O dc
VV
Cntd…
93
94
Control Characteristic VO(dc)
Trigger angle in degrees
0 60 120 180
Vdm
0.2 Vdm
0.6Vdm
95
Normalizing the dc output
voltage with respect to , the
Normalized output voltage
1 cos2
11 cos
2
dm
m
dcn
mdm
dcn dcn
dm
V
V
VV
VV
VV V
V
96
To Derive An Expression for the RMS Value of
Output Voltage of a Single Phase Half Wave
Controlled Rectifier With Resistive Load
97
2
2
0
1
22 2
The RMS output voltage is given by
1.
2
Output voltage sin ; for to
1sin .
2
OO RMS
O m
mO RMS
V v d t
v V t t
V V t d t
Cntd…
98
2
1
22
1
2 2
1
2 2
1 cos 2By substituting sin , we get
2
1 cos 21.
2 2
1 cos 2 .4
cos 2 .4
mO RMS
m
O RMS
m
O RMS
tt
tV V d t
VV t d t
VV d t t d t
Cntd…
99
1
2
1
2
1
2
1
2
1 sin 2
22
sin 2 sin 21;sin2 0
2 2
1 sin 2
2 2
sin 2
22
m
O RMS
m
O RMS
m
O RMS
m
O RMS
V tV t
VV
VV
VV
Cntd…
100
Performance Parameters
Of
Phase Controlled Rectifiers
101
Output dc power (avg. or dc o/p
power delivered to the load)
; . .,
Where
avg./ dc value of o/p voltage.
avg./dc value of o/p current
dc dc dcO dc O dc O dc
dcO dc
dcO dc
P V I i e P V I
V V
I I
Cntd…
102
Output ac power
Efficiency of Rectification (Rectification Ratio)
Efficiency ; % Efficiency 100
The o/p voltage consists of two components
The dc component
The ac
O ac O RMS O RMS
O dc O dc
O ac O ac
O dc
P V I
P P
P P
V
/ripple component ac r rms
V V
Cntd…
103
2 2
2 2
The total RMS value of output voltage is given by
Form Factor (FF) which is a measure of the
shape of the output voltage is given by
RMS output l
O RMS O dc r rms
ac r rms O RMS O dc
O RMS
O dc
V V V
V V V V
VFF
V
oad voltage
DC load output load voltage
Cntd…
104
22 2
2
The Ripple Factor (RF) w.r.t. o/p voltage w/f
1
1
r rms acv
dcO dc
O RMS O dc O RMS
v
O dc O dc
v
V Vr RF
V V
V V Vr
V V
r FF
Cntd…
105
2 2
max min
max min
Current Ripple Factor
Where
peak to peak ac ripple output voltage
peak to peak ac ripple load current
r rms aci
dcO dc
acr rms O RMS O dc
r pp
r pp O O
r pp
r pp O O
I Ir
I I
I I I I
V
V V V
I
I I I
Cntd…
106
Transformer Utilization Factor (TUF)
Where
RMS supply (secondary) voltage
RMS supply (secondary) current
O dc
S S
S
S
PTUF
V I
V
I
Cntd…
107
Cntd…
108
1
Where
Supply voltage at the transformer secondary side
i/p supply current
(transformer secondary winding current)
Fundamental component of the i/p supply current
Peak value of the input s
S
S
S
P
v
i
i
I
upply current
Phase angle difference between (sine wave
components) the fundamental components of i/p
supply current & the input supply voltage.
Cntd…
109
1
Displacement angle (phase angle)
For an RL load
Displacement angle = Load impedance angle
tan for an RL load
Displacement Factor (DF) or
Fundamental Power Factor
L
R
DF Cos
Cntd…
110
11
2 22 2 21
2
1 1
1
Harmonic Factor (HF) or
Total Harmonic Distortion Factor ; THD
1
Where
RMS value of input supply current.
RMS value of fundamental component of
the i
S S S
S S
S
S
I I IHF
I I
I
I
/p supply current.
Cntd…
111
1 1
Input Power Factor (PF)
cos cos
The Crest Factor (CF)
Peak input supply c
For an Ide
urrent
RMS input supply current
1; 100% ;
al Controlled Rectifier
0 ; 1;
S S S
S S S
S peak
S
ac r rms
V I IPF
V I I
ICF
I
FF V V TUF
R
0 ; 0; 1vF r HF THD PF DPF
Cntd…
112
Single Phase Half Wave Controlled Rectifier
With An RL Load
113
Cntd…
114
Input Supply Voltage (Vs)
&
Thyristor (Output) Current
Waveforms
115
Cntd…
116
Output (Load)
Voltage Waveform
117
1
To Derive An Expression For
The Output
(Load) Current, During to
When Thyristor Conducts
t
T
Cntd…
118
1
1
Assuming is triggered ,
we can write the equation,
sin ;
General expression for the output current,
sin
OO m
t
mO
T t
diL Ri V t t
dt
Vi t A e
Z
Cntd…
119
22
1
1
2 maximum supply voltage.
=Load impedance.
tan Load impedance angle.
Load circuit time constant.
general expression for the output load current
sin
m S
Rt
m LO
V V
Z R L
L
R
L
R
Vi t A e
Z
Cntd…
120
1
1
1
1
1
Constant is calculated from
initial condition 0 at ; t=
0 sin
sin
We get the value of constant as
sin
O
Rt
m LO
Rt
mL
R
mL
A
i t
Vi A e
Z
VA e
Z
A
VA e
Z
Cntd…
121
1Substituting the value of constant in the
general expression for
sin sin
we obtain the final expression for the
inductive load current
sin sin
O
Rt
m mLO
Rt
m LO
A
i
V Vi t e
Z Z
Vi t e
Z
;
Where t
Cntd…
122
Extinction angle can be calculated by using
the condition that 0
sin sin 0
sin sin
can be calculated by solving the above eqn.
O
Rt
m LO
R
L
i at t
Vi t e
Z
e
Cntd…
123
To Derive An Expression
For
Average (DC) Load Voltage of a
Single Half Wave Controlled
Rectifier with
RL Load
124
2
0
2
0
1.
2
1. . .
2
0 for 0 to & for to 2
1. ;
2
sin for to
L OO dc
L O O OO dc
O
L OO dc
O m
V V v d t
V V v d t v d t v d t
v t t
V V v d t
v V t t
125
1sin .
2
cos2
cos cos2
cos cos2
L mO dc
mLO dc
mLO dc
mLO dc
V V V t d t
VV V t
VV V
VV V
126
During the period to the
instantaneous o/p voltage is negative
reduces the average or the dc output
vo
and
this
when compared to a purely
resist
ltage
ive load.
t
Effect of Load
Inductance on the Output
127
Average DC Load Current
cos cos
2
O dc m
O dc L Avg
L L
V VI I
R R
Single Phase Half Wave Controlled Rectifier
With RL Load & Free Wheeling Diode
129
V0
i0
T
R
L
Vs ~+
+
FWD
130
0
0
0
0
vS
iG
vO
t
t
t
t
Supply voltage
Load current
Load voltage
t=
2
Gate pulses
iO
131
The followi
The average
ng points a
output voltage
1 cos which is the same as that 2
of a purely resistive load.
For low value of inductance, the load current
tends to become dis
re to be noted
cont
mdc
VV
inuous.
132
During the period to
the load current is carried by the SCR.
During the period to load current is
carried by the free wheeling diode.
The value of depends on the value of
R and L and the forwa
rd resistance
of the FWD.
133
For Large Load Inductance
the load current does not reach zero, &
we obtain continuous load current
0 t
2
t1
i0
SCR SCRFWD FWD
t3t2 t4
134
Single Phase Half Wave
Controlled Rectifier With
A
General Load
135
R
vS~+
L
E+
vO
iO
136
1sin
For trigger angle ,
the Thyristor conducts from to
For trigger angle ,
the Thyristor conducts from to
m
E
V
t
t
137
0
0
iO
t
t
Load current
E
vO
Load voltage
Vm
Im
138
Equations
sin Input supply voltage.
sin o/p load voltage
for to .
for 0 to &
for to 2 .
S m
O m
O
v V t
v V t
t
v E t
t
139
Expression for the Load Current
When the thyristor is triggered at a delay angle of
, the eqn. for the circuit can b
sin +E
e written as
The general expression for the output load
current can be writte
;
n
Om O
diV t i R L t
dt
s
as
int
mO
V Ei t Ae
Z R
140
22
1
Where
= Load Impedance.
tan Load impedance angle.
Load circuit time constant.
The general expression for the o/p current can
be written as sinR
tm L
O
V Ei t Ae
Z
Z R
L
R
L
R
R
L
141
To find the value of the constant
'A' apply the initial conditions at ,
load current 0, Equating the general
expression for the load current to zero at
, we get
0 sinR
mO
O
L
t
i
t
V Ei Ae
Z R
142
We obtain the value of constant 'A' as
Substituting the value of the constant 'A' in the
expression for the load current; we get the
complete expression for the output load c
si
ur
nR
m LVE
A eR Z
sin
rent
in
s
as
Rt
m m LO
V VE Ei t e
Z R R Z
143
To Derive
An
Expression For The Average
Or
DC Load Voltage
144
2
0
2
0
2
0
sin Output load voltage
1.
2
1.
for 0 to & for to 2
for
. .
to
2
1. sin .
2
O
OO dc
O O OO d
m
m
c
O dc
O
V v d t
V v d t v d t v d t
V E d t V t E d t
v V t
v E t t
t
145
2
0
1cos
2
10 cos cos 2
2
cos cos 22 2
2cos cos
2 2
mO dc
mO dc
m
O dc
m
O dc
V E t V t E t
V E V E
V EV
VV E
146
2
2
0
Conduction angle of thyristor
RMS Output Voltage can be calculated
by using the expres
1.
sion
2OO RMS
V v d t
Single Phase Full Wave Controlled Rectifier
Using A Center Tapped Transformer
148
ACSupply
O
A
B
T1
T2
R L
vO
+
149
Discontinuous
Load Current Operation
without FWD
for
150
vOVm
0
( ) ( )
iO
t
t0
151
1
To Derive An Expression For
The Output
(Load) Current, During to
When Thyristor Conducts
t
T
152
1
1
Assuming is triggered ,
we can write the equation,
sin ;
General expression for the output current,
sin
OO m
t
mO
T t
diL Ri V t t
dt
Vi t A e
Z
153
22
1
1
2 maximum supply voltage.
=Load impedance.
tan Load impedance angle.
Load circuit time constant.
general expression for the output load current
sin
m S
Rt
m LO
V V
Z R L
L
R
L
R
Vi t A e
Z
154
1
1
1
1
1
Constant is calculated from
initial condition 0 at ; t=
0 sin
sin
We get the value of constant as
sin
O
Rt
m LO
Rt
mL
R
mL
A
i t
Vi A e
Z
VA e
Z
A
VA e
Z
155
1Substituting the value of constant in the
general expression for
sin sin
we obtain the final expression for the
inductive load current
sin sin
O
Rt
m mLO
Rt
m LO
A
i
V Vi t e
Z Z
Vi t e
Z
;
Where t
156
Extinction angle can be calculated by using
the condition that 0
sin sin 0
sin sin
can be calculated by solving the above eqn.
O
Rt
m LO
R
L
i at t
Vi t e
Z
e
157
To Derive An Expression For The
DC Output Voltage Of
A Single Phase Full Wave
Controlled Rectifier With RL Load
(Without FWD)
158
vOVm
0
( ) ( )
iO
t
t0
159
1.
1sin .
cos
cos cos
dc OO dc
t
dc mO dc
mdcO dc
mdcO dc
V V v d t
V V V t d t
VV V t
VV V
160
When the load inductance is negligible i.e., 0
Extinction angle radians
Hence the average or dc output voltage for R load
cos cos
cos 1
1 cos ; for R load, when
m
O dc
m
O dc
m
O dc
L
VV
VV
VV
161
2 2
To calculate the RMS output voltage we use
the expression
1sin .mO RMS
V V t d t
162
Discontinuous Load Current
Operation with FWD
163
vOVm
0
( ) ( )
iO
t
t0
164
2
2
1
1
Thyristor is trigger
Thyristor is triggered at ;
conducts from to
FWD conducts from to &
0 during discontinuous loa
ed at ;
conducts from t
d current.
o 2
O
T t
T
T t
t
T t
t
v
165
To Derive an Expression
For The
DC Output Voltage For
A
Single Phase Full Wave Controlled
Rectifier
With RL Load & FWD
166
0
1.
1sin .
cos
cos cos ; cos 1
1 cos
dc OO dc
t
dc mO dc
mdcO dc
mdcO dc
mdcO dc
V V v d t
V V V t d t
VV V t
VV V
VV V
167
• The load current is discontinuous for low values
of load inductance and for large values of
trigger angles.
• For large values of load inductance the load
current flows continuously without falling to
zero.
• Generally the load current is continuous for
large load inductance and for low trigger angles.
168
Continuous Load Current
Operation
(Without FWD)
169
vOVm
0
( )
iO
t
t0
( )
170
To Derive
An Expression For
Average / DC Output Voltage
Of
Single Phase Full Wave Controlled
Rectifier For Continuous Current
Operation without FWD
171
vOVm
0
( )
iO
t
t0
( )
172
1.
1sin .
cos
dc OO dc
t
dc mO dc
mdcO dc
V V v d t
V V V t d t
VV V t
173
cos cos ;
cos cos
cos cos
2cos
dcO dc
m
mdcO dc
mdcO dc
V V
V
VV V
VV V
174
• By plotting VO(dc) versus ,
we obtain the control characteristic of a
single phase full wave controlled rectifier
with RL load for continuous load current
operation without FWD
175
cosdc dmV V
176
VO(dc)
Trigger angle in degrees
030 60 90
Vdm
0.2 Vdm
0.6Vdm
-0.6 Vdm
-0.2Vdm
-Vdm
120 150 180
cosdc dmV V
177
00
By varying the trigger angle we can vary the
output dc voltage across the load. Hence we can
control the dc output power flow to the load.
For trigger a . ., ngle , 0 to 90
cos is positive
0 90 ;
i e
and hence is positive
Converter
& are positive ; is positive
Controlled Rectif operates as a
Power flow is from the
ie
ac source to the d.
r.
loa
dc dc dc dc d
d
c
cV
V I P V I
178
0
0
0
0. ., 90 180 ,
is negative; is positive
For trigger angle , 90
;
is negative.
Line
to 180
cos is negative and hence
In this case the conve
Co
rte
mmutated In
r operates
s vea a
dc dc
dc dc dc
i e
V I
P V I
Power flows from the load ckt. to the i/p ac source.
The inductive load energy is fed back to the
i/p sou
rter.
rce.
179
Drawbacks Of Full Wave
Controlled Rectifier
With Centre Tapped Transformer • We require a centre tapped transformer which
is quite heavier and bulky.
• Cost of the transformer is higher for the
required dc output voltage & output power.
• Hence full wave bridge converters are
preferred.
Single Phase
Full Wave Bridge Controlled Rectifier
181
Single Phase
Full Wave Bridge Controlled
Rectifier 2 types of FW Bridge Controlled Rectifiers are
Half Controlled Bridge Converter
(Semi-Converter)
Fully Controlled Bridge Converter
(Full Converter)
The bridge full wave controlled rectifier does not
require a centre tapped transformer
182
Single Phase
Full Wave Half Controlled Bridge
Converter
(Single Phase Semi Converter)
183
184
Trigger Pattern of Thyristors
1
2
0
1 2
, 2 ,...
, 3 ,...
& 180
Thyristor T is triggered at
t at t
Thyristor T is triggered at
t at t
The time delay between the gating
signals of T T radians or
185
Waveforms of
single phase semi-converter
with general load & FWD
for > 900
186
Single Quadrant
Operation
187
188
189
1 1
2 2
Thyristor & conduct
from
Thyristor & conduct
from 2
FWD conducts during
0 to , ,...
T D
t to
T D
t to
t to
190
Load Voltage & Load Current
Waveform of Single Phase Semi
Converter for
< 900
& Continuous load current operation
191
vOVm
0
iO
t
( )
t0
( )
192
To Derive an Expression
For The
DC Output Voltage of
A
Single Phase Semi-Converter With
R,L, & E Load & FWD
For Continuous, Ripple Free Load
Current Operation
193
0
1.
1sin .
cos
cos cos ; cos 1
1 cos
dc OO dc
t
dc mO dc
mdcO dc
mdcO dc
mdcO dc
V V v d t
V V V t d t
VV V t
VV V
VV V
194
max
can be varied from a max.
2value of 0 by varying from 0 to .
For 0, The max. dc o/p voltage obtained is
Normalized dc o/p voltage is
2
11 cos
2
dc
m
m
dc
mdn
mdmdc
dcn n
V
Vto
V
V
V V
VVV
V
V
1 cos2
195
RMS O/P Voltage VO(RMS)
1
22 2
1
2 2
1
2
2sin .
2
1 cos 2 .2
1 sin 2
22
mO RMS
m
O RMS
m
O RMS
V V t d t
VV t d t
VV
196
Single Phase Full Wave
Controlled Rectifier
197
Single Phase Full Wave Controlled Rectifier
Using A Center Tapped Transformer
198 198
ACSupply
O
A
B
T1
T2
R L
vO
+
Single Phase Midpoint type
Fully controlled Rectifier
199
199
Discontinuous
Load Current Operation
without FWD
for
200
200
vOVm
0
( ) ( )
iO
t
t0
201
201
1
To Derive An Expression For
The Output
(Load) Current, During to
When Thyristor Conducts
t
T
202
202
1
1
Assuming is triggered ,
we can write the equation,
sin ;
General expression for the output current,
sin
OO m
t
mO
T t
diL Ri V t t
dt
Vi t A e
Z
203
203
22
1
1
2 maximum supply voltage.
=Load impedance.
tan Load impedance angle.
Load circuit time constant.
general expression for the output load current
sin
m S
Rt
m LO
V V
Z R L
L
R
L
R
Vi t A e
Z
204
204
1
1
1
1
1
Constant is calculated from
initial condition 0 at ; t=
0 sin
sin
We get the value of constant as
sin
O
Rt
m LO
Rt
mL
R
mL
A
i t
Vi A e
Z
VA e
Z
A
VA e
Z
205
205
1Substituting the value of constant in the
general expression for
sin sin
we obtain the final expression for the
inductive load current
sin sin
O
Rt
m mLO
Rt
m LO
A
i
V Vi t e
Z Z
Vi t e
Z
;
Where t
206
206
Extinction angle can be calculated by using
the condition that 0
sin sin 0
sin sin
can be calculated by solving the above eqn.
O
Rt
m LO
R
L
i at t
Vi t e
Z
e
207 207
To Derive An Expression For The DC Output
Voltage Of
A Single Phase Full Wave Controlled
Rectifier With RL Load
(Without FWD)
208
208
vOVm
0
( ) ( )
iO
t
t0
209
209
1.
1sin .
cos
cos cos
dc OO dc
t
dc mO dc
mdcO dc
mdcO dc
V V v d t
V V V t d t
VV V t
VV V
210
210
When the load inductance is negligible i.e., 0
Extinction angle radians
Hence the average or dc output voltage for R load
cos cos
cos 1
1 cos ; for R load, when
m
O dc
m
O dc
m
O dc
L
VV
VV
VV
211
211
2 2
To calculate the RMS output voltage we use
the expression
1sin .mO RMS
V V t d t
212
212
Discontinuous Load Current
Operation with FWD
213
213
vOVm
0
( ) ( )
iO
t
t0
214
214
2
2
1
1
Thyristor is trigger
Thyristor is triggered at ;
conducts from to
FWD conducts from to &
0 during discontinuous loa
ed at ;
conducts from t
d current.
o 2
O
T t
T
T t
t
T t
t
v
215
215
To Derive an Expression For The DC Output
Voltage For A Single Phase Full Wave
Controlled Rectifier With
RL Load & FWD
216
216
0
1.
1sin .
cos
cos cos ; cos 1
1 cos
dc OO dc
t
dc mO dc
mdcO dc
mdcO dc
mdcO dc
V V v d t
V V V t d t
VV V t
VV V
VV V
217
217
• The load current is discontinuous for low values
of load inductance and for large values of
trigger angles.
• For large values of load inductance the load
current flows continuously without falling to
zero.
• Generally the load current is continuous for
large load inductance and for low trigger angles.
218
218
Continuous Load Current
Operation
(Without FWD)
219
219
vOVm
0
( )
iO
t
t0
( )
220
220
To Derive
An Expression For
Average / DC Output Voltage
Of
Single Phase Full Wave Controlled
Rectifier For Continuous Current
Operation without FWD
221
221
vOVm
0
( )
iO
t
t0
( )
222
222
1.
1sin .
cos
dc OO dc
t
dc mO dc
mdcO dc
V V v d t
V V V t d t
VV V t
223
223
cos cos ;
cos cos
cos cos
2cos
dcO dc
m
mdcO dc
mdcO dc
V V
V
VV V
VV V
224
224
• By plotting VO(dc) versus ,
we obtain the control characteristic of a
single phase full wave controlled rectifier
with RL load for continuous load current
operation without FWD
225
225
cosdc dmV V
226
226
VO(dc)
Trigger angle in degrees
030 60 90
Vdm
0.2 Vdm
0.6Vdm
-0.6 Vdm
-0.2Vdm
-Vdm
120 150 180
cosdc dmV V
227
227
00
By varying the trigger angle we can vary the
output dc voltage across the load. Hence we can
control the dc output power flow to the load.
For trigger a . ., ngle , 0 to 90
cos is positive
0 90 ;
i e
and hence is positive
Converter
& are positive ; is positive
Controlled Rectif operates as a
Power flow is from the
ie
ac source to the d.
r.
loa
dc dc dc dc d
d
c
cV
V I P V I
228
228
0
0
0
0. ., 90 180 ,
is negative; is positive
For trigger angle , 90
;
is negative.
Line
to 180
cos is negative and hence
In this case the conve
Co
rte
mmutated In
r operates
s vea a
dc dc
dc dc dc
i e
V I
P V I
Power flows from the load ckt. to the i/p ac source.
The inductive load energy is fed back to the
i/p sou
rter.
rce.
229
Single Phase
Full Wave Bridge Controlled Rectifier
230
230
Drawbacks Of Full Wave
Controlled Rectifier
With Centre Tapped Transformer • We require a centre tapped transformer which
is quite heavier and bulky.
• Cost of the transformer is higher for the
required dc output voltage & output power.
• Hence full wave bridge converters are
preferred.
231
231
Single Phase Full Wave Bridge
Controlled Rectifier
2 types of FW Bridge Controlled Rectifiers are
Half Controlled Bridge Converter
(Semi-Converter)
Fully Controlled Bridge Converter
(Full Converter)
The bridge full wave controlled rectifier does not
require a centre tapped transformer
232
232
Single Phase
Full Wave Half Controlled Bridge
Converter
(Single Phase Semi Converter)
233
233
Single Phase Full Wave Half Controlled
Bridge Converter
234
234
Trigger Pattern of Thyristors
1
2
0
1 2
, 2 ,...
, 3 ,...
& 180
Thyristor T is triggered at
t at t
Thyristor T is triggered at
t at t
The time delay between the gating
signals of T T radians or
235
235
Waveforms of
single phase semi-converter
with general load & FWD
for > 900
236
236
Single Quadrant
Operation
237
237
238
238
239
239
1 1
2 2
Thyristor & conduct
from
Thyristor & conduct
from 2
FWD conducts during
0 to , ,...
T D
t to
T D
t to
t to
240
240
Load Voltage & Load Current Waveform of
Single Phase Semi Converter for
< 900 & Continuous load current
operation
241
241
vOVm
0
iO
t
( )
t0
( )
242
242
To Derive an Expression
For The
DC Output Voltage of
A
Single Phase Semi-Converter With
R,L, & E Load & FWD
For Continuous, Ripple Free Load
Current Operation
243
243
0
1.
1sin .
cos
cos cos ; cos 1
1 cos
dc OO dc
t
dc mO dc
mdcO dc
mdcO dc
mdcO dc
V V v d t
V V V t d t
VV V t
VV V
VV V
244
244
max
can be varied from a max.
2value of 0 by varying from 0 to .
For 0, The max. dc o/p voltage obtained is
Normalized dc o/p voltage is
2
11 cos
2
dc
m
m
dc
mdn
mdmdc
dcn n
V
Vto
V
V
V V
VVV
V
V
1 cos2
245
245
RMS O/P Voltage VO(RMS)
1
22 2
1
2 2
1
2
2sin .
2
1 cos 2 .2
1 sin 2
22
mO RMS
m
O RMS
m
O RMS
V V t d t
VV t d t
VV
246
Single Phase Full Converter
247
Single Phase Full Converter
247
248
248
Waveforms of
Single Phase Full Converter
Assuming Continuous (Constant
Load Current)
&
Ripple Free Load Current
249
249
250
250
251
251
iOConstant Load Current i =IO a
i
iT1
T2&
Ia
t
t
t
Iai
iT3
T4&
Ia
Ia
252
252
To Derive An Expression For The Average DC
Output Voltage of a Single Phase Full Converter
assuming Continuous & Constant Load Current
253
253
2
0
The average dc output voltage
can be determined by using the expression
1. ;
2
The o/p voltage waveform consists of two o/p
pulses during the input supply time period of
0 to 2 r
dc OO dcV V v d t
adians. Hence the Average or dc
o/p voltage can be calculated as
254
254
2sin .
2
2cos
2
2cos
dc mO dc
mdcO dc
mdcO dc
V V V t d t
VV V t
VV V
255
255
0
max
max
Maximum average dc output voltage is
calculated for a trigger angle 0
and is obtained as
2 2cos 0
2
m mdmdc
mdmdc
V VV V
VV V
256
256
max
The normalized average output voltage is given by
2cos
cos2
O dc dcdcn n
dmdc
m
dcn nm
V VV V
V V
V
V VV
257
257
By plotting VO(dc) versus ,
we obtain the control characteristic of a
single phase full wave fully controlled
bridge converter
(single phase full converter)
for constant & continuous
load current operation.
258
258
To plot the control characteristic of a
Single Phase Full Converter for constant
& continuous load current operation.
We use the equation for the average/ dc
output voltage
2cosm
dcO dc
VV V
259
259
260
260
VO(dc)
Trigger angle in degrees
030 60 90
Vdm
0.2 Vdm
0.6Vdm
-0.6 Vdm
-0.2Vdm
-Vdm
120 150 180
cosdc dmV V
261
261
• During the period from t = to the input
voltage vS and the input current iS are both
positive and the power flows from the supply
to the load.
• The converter is said to be operated in the
rectification mode
Controlled Rectifier Operation
for 0 < < 900
262
262
• During the period from t = to (+), the input voltage vS is negative and the input current iS is positive and the output power becomes negative and there will be reverse power flow from the load circuit to the supply.
• The converter is said to be operated in the inversion mode.
Line Commutated Inverter Operation
for 900 < < 1800
263
Two Quadrant Operation
of a Single Phase Full Converter
264
264
Two Quadrant Operation
of a Single Phase Full Converter
0< < 900
Controlled Rectifier
Operation
900< <1800
Line Commutated
Inverter Operation
265
265
To Derive An
Expression For The
RMS Value Of The Output Voltage
2
2
0
The rms value of the output voltage
is calculated as
1.
2OO RMS
V v d t
266
266
The single phase full converter gives two
output voltage pulses during the input supply
time period and hence the single phase full
converter is referred to as a two pulse converter.
The rms output vo
2
ltage can be calculated as
2.
2OO RMS
V v d t
267
267
2 2
22
2
2
1sin .
sin .
1 cos 2.
2
cos 2 .2
mO RMS
m
O RMS
m
O RMS
m
O RMS
V V t d t
VV t d t
tVV d t
VV d t t d t
268
268
2
2
2
sin 2
22
sin 2 sin 2
2 2
sin 2 2 sin 2;
2 2
sin 2 2 sin 2
m
O RMS
m
O RMS
m
O RMS
V tV t
VV
VV
269
269
2
2 2
sin 2 sin 2
2 2
02 2 2
2
Hence the rms output voltage is same as the
rms input supply voltage
m
O RMS
m m m
O RMS
mSO RMS
VV
V V VV
VV V
270
270
Thyristor Current Waveforms
271
271
iOConstant Load Current i =IO a
i
iT1
T2&
Ia
t
t
t
Iai
iT3
T4&
Ia
Ia
272
272
The rms thyristor current can be
calculated as
2
The average thyristor current can be
calculated as
2
O RMS
T RMS
O dc
T Avg
II
II
273
THREE PHASE LINE
COMMUTATED CONVERTERS
274
Introduction to
Three phase converters
275
3 Phase Controlled Rectifiers
• Three phase converters are 3-
phase controlled rectifiers which
are used to convert ac input power
supply into dc output power across
the load
276
276
Features of 3-phase controlled
rectifiers
• Operate from 3 phase ac supply voltage.
• They provide higher dc output voltage.
• Higher dc output power.
• Higher output voltage ripple frequency.
• Filtering requirements are simplified for
smoothing out load voltage and load
current.
277
277
• Extensively used in high power variable
speed industrial dc drives.
• Three single phase half-wave converters can
be connected together to form a three phase
half-wave converter.
278
Classification of 3-phase converters
• 3-phase half wave converter
• 3-phase semi converter
• 3-phase full converter
• 3- phase dual converter
279
Classification according to
no of pulses in the output wave
• 3- pulse converter
• 6-pulse converter
• 12- pulse converter
280
280
3-Phase
Half Wave Converter
(3-Pulse Converter)
with
R-L Load
Continuous & Constant
Load Current Operation
281
281
Circuit Diagram of 3- pulse converter
282
282
Vector Diagram of
3 Phase Supply Voltages
VAN
VCN
VBN
1200
1200
1200 RN AN
YN BN
BN CN
v v
v v
v v
283
283
3 Phase Supply Voltage Equations
We deifine three line to neutral voltages
(3 phase voltages) as follows
284
284
0
0
0
sin ;
Max. Phase Voltage
2sin
3
sin 120
2sin
3
sin 120
sin 240
RN an m
m
YN bn m
m
BN cn m
m
m
v v V t
V
v v V t
V t
v v V t
V t
V t
285
285
van vbn vcn van
286
286
io=Ia
Constant Load
Current
Ia
Ia
Each thyristor conducts for 2/3 (1200)
287
287
To Derive an
Expression for the
Average Output Voltage of a
3-Phase Half Wave Converter
with RL Load
for Continuous Load Current
288
288
0
1
0
2
0
3
0
306
5 150
6
7 270
6
2Each thytistor conducts for 120 or radians
3
T is triggered at t
T is triggered at t
T is triggered at t
289
289
5
6
6
If the reference phase voltage is
sin , the average or dc output
voltage for continuous load current is calculated
using the equation
3sin .
2
RN an m
dc m
v v V t
V V t d t
290
290
5
6
6
5
6
6
3sin .
2
3cos
2
3 5cos cos
2 6 6
mdc
mdc
mdc
VV t d t
VV t
VV
291
291
0 0
0
Note from the trigonometric relationship
cos cos .cos sin .sin
5 5cos cos sin sin
6 63
2co
cos 150 cos sin 150 sin3
2 cos 30
s .cos sin sin6 6
.cos
mdc
mdc
A
VV
B A B A B
VV
0sin 30 sin
292
292
0 0
0 0 0 0
0 0
0 0
0
0
0
0
0 0
Note: cos 1
cos 180 30 cos sin 180 30 sin3
2 cos 30 .cos sin 30 sin
cos 30 cos sin 30 sin3
2 cos 30 .cos sin 30 s
80 30 cos 30
sin 180 30 sin 30
in
mdc
mdc
VV
VV
293
293
032cos 30 cos
2
3 32 cos
2 2
3 3 33 cos cos
2 2
3cos
2
Where 3 Max. line to line supply voltage
mdc
mdc
m mdc
Lmdc
Lm m
VV
VV
V VV
VV
V V
294
294
max
The maximum average or dc output voltage is
obtained at a delay angle 0 and is given by
3 3
2
Where is the peak phase voltage.
And the normalized average output voltage is
mdmdc
m
ddcn n
VV V
V
VV V
cosc
dmV
295
295
15 26
2 2
6
1
2
The rms value of output voltage is found by
using the equation
3sin .
2
and we obtain
1 33 cos 2
6 8
mO RMS
mO RMS
V V t d t
V V
296
296
3 Phase Half Wave
Controlled Rectifier Output
Voltage Waveforms For RL Load
at
Different Trigger Angles
297
297
0
0
300
300
600
600
900
900
1200
1200
1500
1500
1800
1800
2100
2100
2400
2400
2700
2700
3000
3000
3300
3300
3600
3600
3900
3900
4200
4200
Van
V0
V0
Van
=300
=600
Vbn
Vbn
Vcn
Vcn
t
t
=300
=600
298
298
030
060
090
0120
0150
0180
0210
0240
0270
0300
0330
0360
0390
0420
0
V0
Van
=900
Vbn Vcn
t
=900
299
299
3 Phase Half Wave
Controlled Rectifier With
R Load
and
RL Load with FWD
300
300
a a
b b
c c
R
V0
L
R V0
+
T1
T2
T3
n n
T1
T2
T3
301
301
3 Phase Half Wave
Controlled Rectifier Output
Voltage Waveforms For R Load
or RL Load with FWD
at
Different Trigger Angles
302
302
0
0
300
300
600
600
900
900
1200
1200
1500
1500
1800
1800
2100
2100
2400
2400
2700
2700
3000
3000
3300
3300
3600
3600
3900
3900
4200
4200
Vs
V0
Van
=0
=150
Vbn Vcn
t
VanVbn Vcn
t
=00
=150
303
303
0
0
300
300
600
600
900
900
1200
1200
1500
1500
1800
1800
2100
2100
2400
2400
2700
2700
3000
3000
3300
3300
3600
3600
3900
3900
4200
4200
V0
=300
VanVbn Vcn
t
V0
=600
VanVbn Vcn
t
=300
=600
304
304
To Derive An Expression For The Average
Or Dc Output Voltage Of A
3 Phase Half Wave Converter With
Resistive Load Or RL Load With FWD
305
305
0
1
0 0
1
0
2
0 0
2
0
306
30 180 ;
sin
5 150
6
150 300 ;
sin 120
O an m
O bn m
T is triggered at t
T conducts from to
v v V t
T is triggered at t
T conducts from to
v v V t
306
306
0
3
0 0
3
0
0
7 270
6
270 420 ;
sin 240
sin 120
O cn m
m
T is triggered at t
T conducts from to
v v V t
V t
307
307
0
0
0
0
0
0
180
30
0 0
180
30
180
30
3.
2
sin ; for 30 to 180
3sin .
2
3sin .
2
dc O
O an m
dc m
mdc
V v d t
v v V t t
V V t d t
VV t d t
308
308
0
0
180
30
0 0
0
0
3cos
2
3cos180 cos 30
2
cos180 1, we get
31 cos 30
2
mdc
mdc
mdc
VV t
VV
VV
309
Three Phase Semi-converters
310
310
Three Phase Semi-converters
• 3 Phase semi-converters are used in Industrial
dc drive applications upto 120kW power
output.
• Single quadrant operation is possible.
• Power factor decreases as the delay angle
increases.
• Power factor is better than that of 3 phase half
wave converter.
311
311
3 Phase
Half Controlled Bridge Converter
(Semi Converter)
with Highly Inductive Load &
Continuous Ripple free Load Current
312
312
313
313
Wave forms of 3 Phase Semiconverter
for
> 600
314
314
315
315
316
316
0 0
1
3 phase semiconverter output ripple frequency of
output voltage is 3
The delay angle can be varied from 0 to
During the period
30 210
7, thyristor T is forward biased
6 6
Sf
t
t
317
317
1
1 1
If thyristor is triggered at ,6
& conduct together and the line to line voltage
appears across the load.
7At , becomes negative & FWD conducts.
6
The load current contin
ac
ac m
T t
T D
v
t v D
1 1
ues to flow through FWD ;
and are turned off.
mD
T D
318
318
1
2
1 2
If FWD is not used the would continue to
conduct until the thyristor is triggered at
5, and Free wheeling action would
6
be accomplished through & .
If the delay angle , e3
mD T
T
t
T D
ach thyristor conducts
2for and the FWD does not conduct.
3mD
319
319
0
0
0
We deifine three line neutral voltages
(3 phase voltages) as follows
sin ; Max. Phase Voltage
2sin sin 120
3
2sin sin 120
3
sin 240
RN an m m
YN bn m m
BN cn m m
m
v v V t V
v v V t V t
v v V t V t
V t
V
is the peak phase voltage of a wye-connected source.m
320
320
3 sin6
53 sin
6
3 sin2
3 sin6
RB ac an cn m
YR ba bn an m
BY cb cn bn m
RY ab an bn m
v v v v V t
v v v v V t
v v v v V t
v v v v V t
321 321
Wave forms of 3 Phase Semiconverter
for
600
322
322
323
323
324
324
325 325
To derive an Expression for the
Average Output Voltage of 3 Phase
Semi-converter for > / 3
and Discontinuous Output Voltage
326
326
76
6
76
6
For and discontinuous output voltage:3
the Average output voltage is found from
3.
2
33 sin
2 6
dc ac
dc m
V v d t
V V t d t
327
327
max
3 31 cos
2
31 cos
2
3 Max. value of line-to-line supply voltage
The maximum average output voltage that occurs at
a delay angle of 0 is
3 3
mdc
mLdc
mL m
mdmdc
VV
VV
V V
VV V
328
328
17 2
62
6
The normalized average output voltage is
0.5 1 cos
The rms output voltage is found from
3.
2
dcn
dm
acO rms
VV
V
V v d t
329
329
17 2
62 2
6
1
2
33 sin
2 6
3 sin 23
4 2
mO rms
mO rms
V V t d t
V V
330
330
Average or DC Output Voltage
of a
3-Phase Semi-converter
for / 3,
and Continuous Output Voltage
331
331
562
6 2
For , and continuous output voltage3
3. .
2
3 31 cos
2
dc ab ac
mdc
V v d t v d t
VV
332
332
15 2
622 2
6 2
1
22
0.5 1 cos
RMS value of o/p voltage is calculated by using
the equation
3. .
2
3 23 3 cos
4 3
dcn
dm
ab acO rms
mO rms
VV
V
V v d t v d t
V V
333
Three Phase Full Converter
334
334
Three Phase Full Converter
• 3 Phase Fully Controlled Full Wave Bridge
Converter.
• Known as a 6-pulse converter.
• Used in industrial applications up to 120kW
output power.
• Two quadrant operation is possible.
335
335
336
336
337
337
338
338
• The thyristors are triggered at an interval of
/ 3.
• The frequency of output ripple voltage is 6fS.
• T1 is triggered at t = (/6 + ), T6 is already
conducting when T1 is turned ON.
• During the interval (/6 + ) to (/2 + ),
T1 and T6 conduct together & the output load
voltage is equal to vab = (van – vbn)
339
339
• T2 is triggered at t = (/2 + ), T6 turns off
naturally as it is reverse biased as soon as T2 is
triggered.
• During the interval (/2 + ) to (5/6 + ), T1
and T2 conduct together & the output load
voltage vO = vac = (van – vcn)
• Thyristors are numbered in the order in which
they are triggered.
• The thyristor triggering sequence is 12, 23,
34, 45, 56, 61, 12, 23, 34, ………
340
340
0
0
0
We deifine three line neutral voltages
(3 phase voltages) as follows
sin ; Max. Phase Voltage
2sin sin 120
3
2sin sin 120
3
sin 240
RN an m m
YN bn m m
BN cn m m
m
v v V t V
v v V t V t
v v V t V t
V t
V
is the peak phase voltage of a wye-connected source.m
341
341
The corresponding line-to-line
supply voltages are
3 sin6
3 sin2
3 sin2
RY ab an bn m
YB bc bn cn m
BR ca cn an m
v v v v V t
v v v v V t
v v v v V t
342
342
To Derive An Expression For
The Average Output Voltage Of
3-phase Full Converter
With Highly Inductive Load
Assuming Continuous And
Constant Load Current
343
343
2
6
6. ;
2
3 sin6
dc OO dc
O ab m
V V v d t
v v V t
The output load voltage consists of 6 voltage
pulses over a period of 2 radians, Hence the
average output voltage is calculated as
344
344
2
6
mL
max
33 sin .
6
3 3 3cos cos
Where V 3 Max. line-to-line supply vo
The maximum average dc output voltage is
obtained for a delay angle
ltage
3 3
0,
3
dc m
m mLdc
m
m mdmdc
V V t d t
V VV
V
V VV V
L
345
345
1
22
2
6
The normalized average dc output voltage is
cos
The rms value of the output voltage is found from
6.
2
dcdcn n
dm
OO rms
VV V
V
V v d t
346
346
1
22
2
6
1
22
2 2
6
1
2
6.
2
33 sin .
2 6
1 3 33 cos 2
2 4
abO rms
mO rms
mO rms
V v d t
V V t d t
V V
347
Single Phase Dual Converter
348
348
Single Phase Dual Converter
349
349
350
350
351
351
352
352
1 1
2 2
The average dc output voltage of converter 1 is
2cos
The average dc output voltage of converter 2 is
2cos
mdc
mdc
VV
VV
353
353
0
0
1
In the dual converter operation one
converter is operated as a controlled rectifier
with 90 & the second converter is
operated as a line commutated inverter
in the inversion mode with 90
dcV V
2dc
354
354
1 2 2
1 2
2 1 1
2 1
1 2
2 1
2 2 2cos cos cos
cos cos
or
cos cos cos
or
radians
Which gives
m m mV V V
355
355
To Obtain an Expression
for the
Instantaneous Circulating Current
356
356
• vO1 = Instantaneous o/p voltage of converter 1.
• vO2 = Instantaneous o/p voltage of converter 2.
• The circulating current ir can be determined by
integrating the instantaneous voltage difference
(which is the voltage drop across the circulating
current reactor Lr), starting from t = (2 - 1).
• As the two average output voltages during the
interval t = (+1) to (2 - 1) are equal and
opposite their contribution to the instantaneous
circulating current ir is zero.
357
357
1
1
1 2
2
2
1 2
1 2
2
1 1
1. ;
As the o/p voltage is negative
1. ;
sin for 2 to
t
r r r O O
r
O
r O O
t
r O O
r
O m
i v d t v v vL
v
v v v
i v v d tL
v V t t
358
358
1 12 2
1
sin . sin .
2cos cos
The instantaneous value of the circulating current
depends on the delay angle.
t t
mr
r
mr
r
Vi t d t t d t
L
Vi t
L
359
359
1For trigger angle (delay angle) 0,
the magnitude of circulating current becomes min.
when , 0, 2,4,.... & magnitude becomes
max. when , 1,3,5,....
If the peak load current is , one of p
t n n
t n n
I
the
converters that controls the power flow
may carry a peak current of
4,m
p
r
VI
L
360
360
max
max
where
,
&
4 max. circulating current
mp L
L
m
r
r
VI I
R
Vi
L
361
361
Different Modes Of Operation of
Dual converter
• Non-circulating current (circulating current
free) mode of operation.
• Circulating current mode of operation.
362
362
Non-Circulating
Current Mode of Operation
• In this mode only one converter is operated
at a time.
• When converter 1 is ON, 0 < 1 < 900
• Vdc is positive and Idc is positive.
• When converter 2 is ON, 0 < 2 < 900
• Vdc is negative and Idc is negative.
363
363
Circulating
Current Mode Of Operation
• In this mode, both the converters are switched
ON and operated at the same time.
• The trigger angles 1 and 2 are adjusted such
that (1 + 2) = 1800 ; 2 = (1800 - 1).
364
364
• When 0 <1 <900, converter 1 operates as a
controlled rectifier and converter 2 operates as
an inverter with 900 <2<1800.
• In this case Vdc and Idc, both are positive.
• When 900 <1 <1800, converter 1 operates as
an Inverter and converter 2 operated as a
controlled rectifier by adjusting its trigger
angle 2 such that 0 <2<900.
• In this case Vdc and Idc, both are negative.
365
365
Four Quadrant Operation
Conv. 2
Inverting
2 > 900
Conv. 2
Rectifying
2 < 900
Conv. 1
Rectifying
1 < 900
Conv. 1
Inverting
1 > 900
366
366
Advantages of Circulating
Current Mode Of Operation
• The circulating current maintains
continuous conduction of both the
converters over the complete control range,
independent of the load.
• One converter always operates as a rectifier
and the other converter operates as an
inverter, the power flow in either direction
at any time is possible.
367
367
• As both the converters are in continuous
conduction we obtain faster dynamic response.
i.e., the time response for changing from one
quadrant operation to another is faster.
368
368
Disadvantages of Circulating
Current Mode Of Operation • There is always a circulating current flowing
between the converters.
• When the load current falls to zero, there will be a
circulating current flowing between the converters
so we need to connect circulating current reactors in
order to limit the peak circulating current to safe
level.
• The converter thyristors should be rated to carry a
peak current much greater than the peak load
current.
369
Three Phase Dual Converters
370
370
Three Phase Dual Converters
• For four quadrant operation in many industrial variable speed dc drives , 3 phase dual converters are used.
• Used for applications up to 2 mega watt output power level.
• Dual converter consists of two 3 phase full converters which are connected in parallel & in opposite directions across a common load.
371
371
372
372
373
373
374
374
Outputs of Converters 1 & 2
• During the interval (/6 + 1) to (/2 +
1), the line to line voltage vab appears
across the output of converter 1 and vbc
appears across the output of converter 2
375
375
0
0
0
We deifine three line neutral voltages
(3 phase voltages) as follows
sin ;
Max. Phase Voltage
2sin sin 120
3
2sin sin 120
3
sin 240
RN an m
m
YN bn m m
BN cn m m
m
v v V t
V
v v V t V t
v v V t V t
V t
376
376
The corresponding line-to-line
supply voltages are
3 sin6
3 sin2
3 sin2
RY ab an bn m
YB bc bn cn m
BR ca cn an m
v v v v V t
v v v v V t
v v v v V t
377
377
• If vO1 and vO2 are the output voltages of
converters 1 and 2 respectively, the
instantaneous voltage across the current
limiting inductor during the interval
(/6 + 1) t (/2 + 1) is given by
To obtain an Expression for the
Circulating Current
378
378
1 2
3 sin sin6 2
3 cos6
The circulating current can be calculated by
using the equation
r O O ab bc
r m
r m
v v v v v
v V t t
v V t
379
379
1
1
6
6
1
max
1.
13 cos .
6
3sin sin
6
3
t
r r
r
t
r m
r
mr
r
m
r
r
i t v d tL
i t V t d tL
Vi t t
L
Vi
L
380
380
Four Quadrant Operation
Conv. 2
Inverting
2 > 900
Conv. 2
Rectifying
2 < 900
Conv. 1
Rectifying
1 < 900
Conv. 1
Inverting
1 > 900
381
381
Contd…
• There are two different modes of operation.
Circulating current free
(non circulating) mode of operation
Circulating current mode of operation
382
382
Non Circulating
Current Mode Of Operation
• In this mode of operation only one converter is switched on at a time
• When the converter 1 is switched on,
For 1 < 900 the converter 1 operates in the Rectification mode
Vdc is positive, Idc is positive and hence the average load power Pdc is positive.
• Power flows from ac source to the load
383
383
• When the converter 1 is on,
For 1 > 900 the converter 1 operates in the
Inversion mode
Vdc is negative, Idc is positive and the average
load power Pdc is negative.
• Power flows from load circuit to ac source.
384
384
• When the converter 2 is switched on,
For 2 < 900 the converter 2 operates in the Rectification mode
Vdc is negative, Idc is negative and the average load power Pdc is positive.
• The output load voltage & load current reverse when converter 2 is on.
• Power flows from ac source to the load
385
385
• When the converter 2 is switched on,
For 2 > 900 the converter 2 operates in the Inversion mode
Vdc is positive, Idc is negative and the average load power Pdc is negative.
• Power flows from load to the ac source.
• Energy is supplied from the load circuit to the ac supply.
386
386
Circulating Current
Mode Of Operation
• Both the converters are switched on at the same time.
• One converter operates in the rectification mode while the other operates in the inversion mode.
• Trigger angles 1 & 2 are adjusted such that (1 + 2) = 1800
387
387
• When 1 < 900, converter 1 operates as a
controlled rectifier. 2 is made greater than
900 and converter 2 operates as an Inverter.
• Vdc is positive & Idc is positive and Pdc is
positive.
UNIT-III
DC-DC CONVERTERS (CHOPPERS)
388
389
DC-DC Converters
• Convert a fixed DC Source into a Variable
DC Source
• DC equivalent to an AC transformer with
variable turns ratio
• Step-up and Step-down versions
• Applications
– Motor Control
– Voltage Regulators
390
Step-down Operation
• Switch SW is known as a “Chopper”
• Use BJT, MOSFET, or IGBT
• Close for time t1
– VS appears across R
• Open for time t2
– Voltage across R = 0
• Repeat
• Period T = t1 + t2
391
Waveforms for the Step-Down Converter
392
Average Value of the Output Voltage
1
1
0
0
11
1
1
t
a O
t
a S
a S S
a S
V v dtT
V V dtT
tV V ft V
T
V kV
393
Average Value of the Load Current
1
a Sa
V kVI
R R
T period
tk dutycycle
T
f frequency
394
rms Value of the output voltage
1
22
0
1
22
0
1
1
kT
O O
kT
O S
O S
V v dtT
V V dtT
V kV
395
If the converter is “lossless”, Pin = Pout
0
2
0
2
2
1
1
1
kT
in O
kT
Oin
Sin
Sin
P v idtT
vP dt
T R
VP kT
T R
VP k
R
396
Effective Input Resistance seen by VS
S Si
Sa
i
V VR
VIk
R
RR
k
397
Modes of Operation
• Constant – frequency operation
– Period T held constant, t1 varied
– Width of the pulse changes
– “Pulse-width modulation”, PWM
• Variable -- frequency operation
– Change the chopping frequency (period T)
– Either t1 or t2 is kept constant
– “Frequency modulation”
398
Generation of Duty Cycle
• Compare a dc reference signal with a saw-
tooth carrier signal
DC Reference Signal Carrier Signal
399
rr
Vv k
T
@r cr
rcr
cr
r
v V t kT
VV kT
T
Vk M
V
k
T
400
To generate the gating signal
• Generate the triangular waveform of period T, vr, and
the dc carrier signal, vcr
• Compare to generate the difference vc - vcr
• Apply to a “hard limiter” to “square off”
401
Step-Down Converter with RL Load
402
Mode 1: Switch Closed
1
1S
diV Ri L E
dt
1 1( ) 1
R Rt t
L LSV E
i t I e eR
1( )t t kT
1 ( 0 ) 1( )
ti t I
1
1 2( )
t t kT
i kT I
403
Mode 2: Switch Open
2
2
2 2
2 2
0
( 0)
( ) 1R R
t tL L
diR i L E
dt
i t I
Ei t I e e
R
2
2
2 2 3 1
0 (1 )
@ (1 )
( )
t t k T
t t K T
i t I I
404
Current for “Continuous” Mode
405
1
2
( 1 )
max
1
1
1
1
1
1
4
kz
S
z
kz
S
z
kz z k z
S
z
S
V e EI
R e R
V e EI
R e R
T Rz
L
V e e eI
R e
VI
fL
406
10
10
1
kz
z
S
I
e E
e V
For Continuous Current
407
Define the load emf ratio
1
1
S
kz
z
S
Ex
V
E ex
V e
408
UNIT-IV
AC-AC CONVERTERS (AC
VOLTAGE CONTROLLERS) &
FREQUENCY CHANGERS
(CYCLO-CONVERTERS)
409
Ac Voltage controller circuits
(RMS voltage controllers)
An ac voltage controller is a type of thyristor
power converter which is used to convert a
fixed voltage, fixed frequency ac input supply
to obtain a variable voltage ac output
410
Applications Of Ac Voltage
Controllers
•Lighting / Illumination control in ac power
circuits.
•Induction heating.
•Industrial heating & Domestic heating.
•Transformer tap changing (on load
transformer tap changing).
•Speed control of induction motors C
magnet controls.
411
Type Of Ac Voltage Controllers
• Single phase half wave ac voltage controller (Uni-directional controller).
• Single phase full wave ac voltage controller (Bi-directional controller).
• Three phase half wave ac voltage controller (Uni-directional controller).
• Three phase full wave ac voltage controller (Bi-directional Controller)
412
A.C voltage control technique
413
Principle of ON-OFF Control
Technique
414
Vs
Vo
io
ig1
ig2
wt
wt
wt
wt
Gate pulse of T1
Gate pulse of T2
n m
415
416
417
418
Expression For The RMS Value Of
Output Voltage, For ON-OFF
Control Method
419
420
421
422
423
424
RMS Out put voltage
425
Duty cycle
426
427
Input Power factor
428
429
The Average Current Of Thyristor
430
Waveform of Thyristor current
431
432
RMS Thyristor Current
433
Principle Of AC Phase Control
And
Operation of single Phase half-Wave
A.C Phase controller
Power Electronics Unit-6 434
Principle Of AC Phase Control
435
436
Equations
437
Output Load Voltage
438
Out Put Load Current
439
Expression For RMS Out put Load
Voltage
440
441
442
443
444
Control Characteristics
445
Average Value of Out put Voltage
446
447
448
Disadvantages
449
Single Phase Full Wave Ac Voltage
Controller (Bidirectional Controller)
With R-Load
450
Single Phase Full Wave Ac Voltage
Controller With R-Load
Fig.: Single phase full wave ac voltage controller
(Bi-directional Controller) using SCR
451
Waveforms of single phase full
wave ac voltage controller
452
Expression for RMS output voltage
2 2 2
0
1sin .mL RMS
V V t d t
2
2 2
0
1.
2LL RMS
V v d t
2
2 22 1sin sin
2m mL RMS
V V t d t V t d t
453
Contd…
2
2 2 2 21sin . sin .
2m mV t d t V t d t
2
2 2 2 21sin . sin .
2m mV t d t V t d t
22
1 cos 2 1 cos 2
2 2 2
mV t td t d t
2 22
cos 2 . cos 2 .2 2
mVd t t d t d t t d t
454
2 22
sin 2 sin 2
4 2 2
mV t tt t
2
1 1sin 2 sin 2 sin 4 sin 2
4 2 2
mV
2
1 12 0 sin 2 0 sin 2
4 2 2
mV
2 sin 2sin 2
24 2 2
mV
455
2 sin 2 2sin 2
24 2 2
mV
2
sin 2 12 sin 2 .cos 2 cos 2 .sin 2
4 2 2
mV
sin 2 0 & cos2 1
Therefore,
2
2 sin 2 sin 22
4 2 2
m
L RMS
VV
2
2 2 2 sin 24
m
L RMS
VV
456
• Taking the square root, we get
2 2 sin 22
m
L RMS
VV
2 2 sin 22 2
m
L RMS
VV
1
2 2 sin 222
m
L RMS
VV
1 sin 2
22 22
m
L RMS
VV
457
1 sin 2
22
m
L RMS
VV
1 sin 2
2L RMS i RMS
V V
1 sin 2
2SL RMS
V V
458
Single Phase Full Wave Ac Voltage
Controller (Bidirectional Controller)
With R-L Load
459
Single Phase Full Wave Ac Voltage
Controller (Bidirectional Controller)
With R-L Load
Power Electronics Unit-6 460
Input supply voltage & Thyristor
current waveforms
461
Gating Signals
Power Electronics Unit-6 462
Waveforms For RL load for and
for Discontinuous Conduction
463
sin sinR
tm L
O
Vi t e
Z
Expression for the inductive load
current of a single phase full wave
ac voltage controller with RL load
22Z R L
1tanL
R
Where
= Load impedance angle (power factor
angle of load).
464
Output voltage and output current waveforms
for a single phase full wave
ac voltage controller with RL load for
vO
2
3
t
Vm
0
Im
t
v =vO S
iO
465
TRIAC and Its Modes of Operation
466
TRIAC
MT2
MT1G
P2
P2 N1
N4
N3
G N2
N1P1
MT1
MT2
P1
Fig.1 : Triac Structure Fig. 2 : Triac
Symbol
467
TRIGGERING MODES OF TRIAC
• MODE 1 : MT1 positive, Positive gate current
( I+ mode of operation)
P1
N1
N2
P2Ig
Ig
MT2 (+)
MT1 ( )G
V(+)
468
• When and gate current are positive with respect
to MT1, the gate current flows through P2-N2 junction
• The junction P1-N1 and P2-N2 are forward
biased but junction N1-P2 is reverse biased.
• When sufficient number of charge carriers are injected in P2 layer by the gate current the junction N1-P2 breakdown and triac starts conducting through P1N1P2N2 layers.
• Once triac starts conducting the current increases and its V-I characteristics is similar to that of thyristor. Triac in this mode operates in the first-quadrant.
469
MODE 2
• MT2 positive, Negative gate current
(I- mode of operation)
P1
N1
N2N3
P2
Ig
MT2 (+)
MT1 ( )G
V
Finalconduction
Initialconduction
470
• When MT2 is positive and gate G is negative with
respect to MT1 the gate current flows through P2-N3
junction
• The junction P1-N1 and P2-N3 are forward biased
but junction N1-P2 is reverse biased. Hence, the triac
initially starts conducting through P1N1P2N3 layers.
• As a result the potential of layer between P2-N3 rises
towards the potential of MT2.
• Thus, a potential gradient exists across the layer P2
with left hand region at a higher potential than the
right hand region.
471
• This results in a current flow in P2 layer from left to right, forward biasing the P2N2 junction. Now the right hand portion P1-N1 - P2-N2 starts conducting.
• The device operates in first quadrant. When compared to Mode 1, triac with MT2 positive and negative gate current is less sensitive and therefore requires higher gate current for triggering.
472
MODE 3
• MT2 negative, Positive gate current
(III+ mode of operation)
P1
N1
N4
N2
P2
Ig
MT2 ( )
MT1 (+)G(+)
473
• When MT2 is negative and gate is positive with respect to MT1 junction P2N2 is forward biased and junction P1-N1 is reverse biased.
• N2 layer injects electrons into P2 layer as shown by arrows in figure below.
• This causes an increase in current flow through junction P2-N1. Resulting in breakdown of reverse biased junction N1-P1.
• Now the device conducts through layers P2N1P1N4 and the current starts increasing, which is limited by an external load.
• The device operates in third quadrant in this mode. Triac in this mode is less sensitive and requires higher gate current for triggering.
474
MODE 4
• MT2 negative, Negative gate current
(III+ mode of operation)
P1
N1
N4
P2
Ig
MT2 ( )
MT1 (+)
N3
G(+)
475
• In this mode both MT2 and gate G are negative with
respect to MT1, the gate current flows through P2N3
junction as shown.
• Layer N3 injects electrons as shown by arrows into
P2 layer. This results in increase in current flow
across P1N1 and the device will turn ON due to
increased current in layer N1.
• The current flows through layers P2N1P1N4. Triac is
more sensitive in this mode compared to turn ON
with positive gate current. (Mode 3).
476
• Triac sensitivity is greatest in the first quadrant when
turned ON with positive gate current and also in third
quadrant when turned ON with negative gate current.
when is positive with respect to it is recommended
to turn on the triac by a positive gate current.
• When is negative with respect to it is recommended
to turn on the triac by negative gate current.
Therefore Mode 1 and Mode 4 are the preferred
modes of operation of a triac (mode and mode of
operation are normally used).
477
Triac characteristics RL
MT1
MT2
Rg
Vs
Vgg
I
A
A
VG
+
+
++
+
-
-
-
-
-
478
V-I Characteristics of a triac
VB02
MT2( )
G( )
MT2(+)
G(+)
VB01
VB01, V
- Breakover voltages B01
Ig1
Ig2I
VV
I > Ig2 g21
479
Single phase full wave ac
voltage controller
(Bi-directional Controller) using
TRIAC
480
Single phase full wave ac voltage
controller (Bi-directional Controller)
using TRIAC
481
Waveforms of single phase full
wave ac voltage controller
482
Single phase full wave ac controller with
common cathode
(Bidirectional controller in common
cathode configuration)
483
Single Phase Full Wave Ac Voltage
Controller Using A Single Thyristor
RL
T1
ACSupply
-
D1
D4
D3
D2
+
484
CYCLOCONVERTER
485
CYCLOCONVERTER
• A device which converts input power at one
frequency to the out put power at different
frequency with one stage conversion is called
a cycloconverter.
• A cycloconverter requires one stage frequency
conversion.
• Cycloconverter of two types
(i) Step-Up Cycloconverter ( fo > s)
(ii) step-Down Cycloconverter ( fo < fs)
Power Electronics Unit-6 486
Single phase to single phase Mid point type
step-up Cycloconverter
with R load
487
Power Electronics Unit-6 488
Single phase to single phase Bridge
type step-up
Cycloconverter with R load
489
Power Electronics Unit-6 490
1-φ to 1-φ Mid point type step-Down
Cycloconverter with R load
491
Output voltage (Vo) and current (Io) waveform
492
1-φ to 1-φ Bridge type Cyclo-
converter with R and R-L load
Power Electronics Unit-6 493
1-φ to 1-φ Bridge type step-Down
Cycloconverter with R load
Power Electronics Unit-6 494
Output voltage (Vo) and current (Io) waveform
Power Electronics Unit-6 495
1-φ to 1-φ Midpoint type step-Down
Cycloconverter with R-L load
Power Electronics Unit-6 496
Output voltage (Vo) and current (Io)
waveform for Discontinuous
Conduction mode
Power Electronics Unit-6 497
Output voltage (Vo) and current (Io)
waveform for Continuous Conduction mode
Power Electronics Unit-6 498
1-φ to 1-φ Bridge-type step-Down
Cycloconverter with R-L load
Power Electronics Unit-6 499
Output voltage (Vo) and current (Io)
waveform for Discontinuous
Conduction mode
Power Electronics Unit-6 500
Output voltage (Vo) and current (Io)
waveform for Continuous Conduction
mode
UNIT-V
DC-AC CONVERTERS
(INVERTERS)
501
502
Single-phase half-bridge inverter
503
Operational Details
• Consists of 2 choppers, 3-wire DC source
• Transistors switched on and off alternately
• Need to isolate the gate signal for Q1 (upper device)
• Each provides opposite polarity of Vs/2 across the load
3-wire DC
source
504
Q1 on, Q2 off, vo = Vs/2
Peak Reverse Voltage of Q2 = Vs
505
Q1 off, Q2 on, vo = -Vs/2
506
Waveforms with resistive load
507
Look at the output voltage
1
222
0
2
4 2
oT
s so
o
V VV dt
T
rms value of the output voltage, Vo
508
Fourier Series of the instantaneous output
voltage
1
0
0
1,3,5,..
cos( ) sin( )2
, 0
1sin( ) ( ) sin( ) ( )
2 2
21,3,5,...
2sin( )
oo n n
n
o n
s sn
sn
so
n
av a n t b n t
a a
V Vb n t d t n t d t
Vb n
n
Vv n t
n
509
rms value of the fundamental component
1,3,5,..
1
1
2sin
21
2
0.45
so
n
so
o s
Vv n t
n
VV
V V
510
When the load is highly inductive
511
Turn off Q1 at t = To/2
Current falls to 0 via D2, L, Vs/2 lower
+
Vs/
2
- +
Vs/2
-
512
Turn off Q2 at t = To
Current falls to 0 via D1, L, Vs/2 upper
+
Vs/
2
- +
Vs/2
-
513
Load Current for a highly inductive load
Transistors are only switched on for a quarter-cycle, or 90
514
Fourier Series of the output current for an RL
load
2 21,3,5,...
1
2sin( )
( )
tan ( )
o o so n
n
n
v v Vi n t
Z R jn L n R n L
n L
R
515
Fundamental Output Power
In most cases, the useful power
2
1 1 1 1 1
2
12 2
cos
2
2 ( )
o o o o
so
P V I I R
VP R
R L
516
DC Supply Current
• If the inverter is lossless, average power absorbed by the load equals the average power supplied by the dc source.
• For an inductive load, the current is approximately sinusoidal and the fundamental component of the output voltage supplies the power to the load. Also, the dc supply voltage remains essentially at Vs.
0 0
( ) ( ) ( ) ( )
T T
s s o ov t i t dt v t i t dt
517
1 1
0 0
11
1( ) 2 sin( ) 2 sin( )
cos( )
T T
s o o s
s
os o
s
i t dt V t I t dt IV
VI I
V
DC Supply Current (continued)
518
Performance Parameters
• Harmonic factor of the nth harmonic (HFn)
1
onn
o
VHF
V for n>1
Von = rms value of the nth harmonic component
V01 = rms value of the fundamental component
519
Performance Parameters (continued)
• Total Harmonic Distortion (THD)
• Measures the “closeness” in shape between a
waveform and its fundamental component
1
2 2
2,3,...1
1( )on
no
THD VV
520
Performance Parameters (continued)
• Distortion Factor (DF)
• Indicates the amount of HD that remains in a
particular waveform after the harmonics have been
subjected to second-order attenuation.
12 2
22,3,...1
2
1
1 on
no
onn
o
VDF
V n
VDF
V n
for n>1
521
Performance Parameters (continued)
• Lowest order harmonic (LOH)
• The harmonic component whose frequency
is closest to the fundamental, and its
amplitude is greater than or equal to 3% of
the amplitude of the fundamental
component.
522
Single-phase full-bridge inverter
523
Operational Details
• Consists of 4 choppers and a 3-wire DC source
• Q1-Q2 and Q3-Q4 switched on and off alternately
• Need to isolate the gate signal for Q1 and Q3 (upper)
• Each pair provide opposite polarity of Vsacross the load
524
Q1-Q2 on, Q3-Q4 off, vo = Vs
+ Vs -
525
Q3-Q4 on, Q1-Q2 off, vo = -Vs
- Vs +
526
When the load is highly inductive
Turn Q1-Q2 off – Q3-Q4 off
527
Turn Q3-Q4 off – Q1-Q2 off
528
Load current for a highly inductive load