1. Dik : S = 200 m T = 25 sDit : a. laju rata-rata (v) b. kecepatan rata-rata (v-)

Jawab : a V= s/t

V= 200 m/25 s = 8 m/s

b karna titik akhir lintasan berimpit dengan titik awal= 0

v= s/t v= 0 m/25 s = 0 m/s

13°2. R=√a2+b2+2.a .b cos 13

= √√22+42+2.2 .4cos13 = √4+16+16.0,17 = √20+16.1 = √36 = 6

40° 127°

3. μk =FfrFn

= 14060¿

¿

= 2.3 N