Khoa So Dung Msp430

8/2/2019 Khoa So Dung Msp430

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KHA S IN T

I MC TIU

- Thit k kha s in t bng mt khu (6 s) s dng chip vi x l h msp430.

- Dng bn phm hex (16 phm) thc hin chc nng giao tip.- Dng ng c mt chiu ng m kha bng cch iu khin o chiu ng

c.

- Mt khu c th thay i c.

- Bo ng ra loa v treo h thng khi mt khu nhp sai 3 ln.

II PHNG PHP GII QUYT

- Lp s khi.

- Thit k m hnh phn cng.- Lp s gii thut.

- Tm hiu nguyn tc hot ng ca bn phm hex.

- Thit k khi iu khin o chiu ng c ng mca.

- Thit k khi bo ng.

- Tm hiu chip x l v cc linh kin c s dng.

- Vit chng trnh theo s gii thut.

- Lin kt cc khi.- Rp mch kim tra v chy th.

III NI DUNG

1. S KHI

Hnh 1: S khi h thng

KHI X LKHI

BN PHM

KHIIU KHIN

NG C

KHIBO NG

KHIHIN TH


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Hnh 3: S gii thut cho chng trnh con Change


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3. TM HIU CHIP MSP430G2x52

Hnh 4: S chn ca MSP430G2x52

Hnh 5: S khi chc nng ca MSP430G2x52


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4. BN PHM HEX

4.1. CU TO

Bn phm Hex cu to gm16 phm xp thnh ma trn 4 hng v 4 ct (Nh

hnh 6).

P0

P1

P2

P3

P4

P5

P6

P7

Hnh 6: Cu to bn phm Hex

4.2. NGUYN TC HOT NG CA BN PHM HEX

Khi mt phm no c nhn th tng ng hng v ct ca bn phm Hex

s kt ni vi nhau.

thc hin kim tra mt phm th ta phi cho trc hng (hoc ct) cha

phm tng ng mc logic 0, sau kim tra ct (hoc hng) ca phm, nu ct

(hoc hng) = 0 th c nhn phm ngc li th khng nhn phm.

Nh vy nhn bit phm no c nhn ta phi ln lc qut cc ct, c

nh hng hoc qut cc hng, c nh ct.


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4.3. S BN PHM HON CHNH

P1.0

P1.1

P1.2

P1.3

P1.4

P1.5

P1.6

P1.7

1 2 3

4 5 6

7 8 9

EXIT 0 CLEAR

OPEN

CLOSE

CHANGE

OK

R133k

R233k

R333k

R433k

Hnh 7: Bn phm Hex Hon Chnh

Cc hng v ct ca bn phm kt ni vi Port 1. Bit 0,1,2,3 ca Port 1 s lm

ng ra v kt ni vi cc hng ca bn phm. Cn cc bit 4,5,6,7 lm ng ng vo

kt ni vi cc ct ca bn phm.

4.4. CHNG DI CHO BN PHM

Do thi gian di ca phm vo khong 20ms nn chng di ta s chng

di bng phn mm phn cng c n gin.

on chng trnh chng di:

n=0;while ( n==0 )

{if ((P1IN&COTX) == 0) //Nt ang nhn gi.

n=0;else //Nt nh ra.

n=1;

}Ngoi ra gia cc ln chn hng (hoc ct) qut phm ta thm on delay:

__delay_cycles(5000);


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5. KHI IU KHIN NG C

5.1. S MCH IU KHIN O CHIU NG C NG M

CA

RL1 RL2

Q1C828

Q2C828

R1

330R

R2

330R

D110BQ040 D2

10BQ040

3V

3V 3V

Px Py

Hnh 8: S mch iu khin ng c.

Hai ng vo Px, Py dng iu khin o chiu ng c.

5.2. IU KHIN TC NG C

iu khin tc ng c theo ch PWM (Pluse Width ModulationBin

iu rng xung).

on chng trnh iu khin:

n=0;while ( n


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6. S MCH BO NG

Q2C828

Q1C828

C1

1u

C2

1u

RC1180R

RB21k5

RB11k5

RC2180R

3V

R5

330R

Q4C828

Q5C828

C1

10u

C2

10u

Q6C828

RC1820R

RB28k2

RB18k2

RC2820RR10

330R

C5

10u LS1

SPEAKER

Pz

Q3A1015 Ngo ra

Hnh 9: Mch bo ng.

Khi hai khi hot ng ring l ta c:

- Tn hiu ng ra khi 1 s nh hnh 11 vi chu k T:5

1 B2 2 B1T = (C R + C R )Ln2 = 2.8200.10 Ln2 = 0.1148S

Hnh 11: Tn hiu ng ra khi 1.

- Tn hiu ng ra khi 2 s nh hnh 12 vi chu k T:

61 B2 2 B1T = (C R + C R )Ln2 = 2.1500.10 Ln2 = 0.0021S

Hnh 12: Tn hiu ng ra khi 2.

Khi 1 Khi 2


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Khi kt hp hai khi li cung hot ng th tn hiu ng ra cp cho loa s

nh hnh 13:

Hnh 13: Tn hiu ng ra cp cho loa.

7. S MCH HON CHNH

R74k7

C610u

P2.5/CA53

RST/NMI7

TEST1

P2.4/TA2/CA112

P2.3/TA1/CA011 P2.2/CAOUT/TA0/CA4

10P2.1/INCLK/CA3

9P2.0/ACLK/CA2

8

P1.2/TA1

15P1.1/TA0

14P1.0/TACLK

13

P1.3/TA216

P1.4/SMCLK/TCK17

P1.7/TA2/TDO/TDI20

P1.6/TA1/TDI/TCLK19

P1.5/TA0/TMS18

XIN/P2.6/CA66

XOUT/P2.7/CA75

U1

MSP430G2452

3V

1 2 4 5 6

7 8 9

EXIT 0 CLOSE

OPEN

CLOSE

CHANGE

OK

R133k

R233k

R333k

R433k

3V

RL1RL2

Q13C828

Q12C828

R5330R

R6330R

D110

D210

3V 3V

Px Py

Q2C828

Q1C828

C3

1u

C4

1u

RC3180R

RB41k5

RB31k5

RC4180R

3V

R15

330R

Q4C828

Q5C828

C1

10u

C2

10u

Q6C828

RC1820R

RB28k2

RB18k2

RC2820R

R10330R

C5

10u LS1

SPEAKER

Pz

Q3A1015

Ngo ra

Q7C828

Q8C828

Q9C828

R8330R

R9330R

R11330R

R12100R

R13100R

R14100R

D3LED-RED

D4LED-RED

D5LED-RED

3V

1 32

3V

Hnh 14: S mch hon chnh.


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8. MT S ON CHNG TRNH

8.1. NH NGHA BIT

#define COT0 BIT0#define COT1 BIT1

#define COT2 BIT2#define COT3 BIT3#define COT4 BIT4#define COT5 BIT5#define COT6 BIT6#define COT7 BIT7

8.2. ON QUT PHM

i=0;While(i


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8.3. ON SO SNH PASSWORD

if (*i==0){ if(nhappass[*i] == a)

{

*i = *i+1;if(nhappass[*i] == b){*i = *i+1;if(nhappass[*i] == c)

{*i = *i+1;if(nhappass[*i] == d)

{*i = *i+1;if(nhappass[*i] == e)

{ *i = *i+1;if(nhappass[*i] == h)

*i = *i+1; } } } } } }else

*i = 7;

8.4. ON TREO H THNG

int j;P2OUT |= COT3;

j=0;while (j


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9. PHNG HNG PHT TRIN

- C th m bo gi password thay i khi b mt in hay khi reset h thng.

- Hin th chng trnh ln LCD ngi dng d s dng.

- Thit k phn cng gn hn.10. ON CHNG TRNH CHNH

/**/

/*_ _ _ _ _ _ _ _ _ _Nguyn tc hot ng ca chng trnh_ _ _ _ _ _ _ _ _ _*/

- Khi mi bt u, chng trnh thc hin qut phm s v phm close (phm close

ch c tc dng nu ta cha nhn mt phm s no). y, chng trnh yu cu

nhp password (6 s). Ngoi ra, ta c th dng phm clear xa s va nhp sai.Khi nhn mt phm chng trnh s bo hiu (n sng) mt ln.

- Khi nhp password xong ta nhn ok:

+ Nu password sai th bo ng v cho nhp li, khi nhp sai 3 ln, h thng

treo trong 1 pht sau tr v chng trinh ban u v cho nhp tip.

+ Nupassword ng s bo hiu (n chp), sau chng trnh thc hin n

on qut phm chc nng.

- on chng trnh qut phm chc nng:+ Nu nhn open th ra lnh iu khin m ri tr v on qut phm chc nng.

+ Nu nhn close th ra lnh ng v tr v chng trinh ban u.

+ Nu nhn change thay i password sau tr vchng trinh ban u.

- Sau khi nhn phm change, ta cn thc hin nhp password hai ln (cch nhp

pass tng t nh u chng trnh, tc l sau khi nhp 6 s ta cn nhn

phm ok), chng trnh s ra bo hiu gia hai ln nhp.

+ Nu password gia hai ln nhp khng ging nhau th ra bo ng sau cho

nhp tip. Nu sai 3 ln h thng b treo trong 1 pht ri tr v chng trnh ban

u.

+ Nu password gia hai ln nhp ging nhau, chng trnh s lu v thay ipassword sau tr v chng trnh ban u.


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Ngoai ra, ta c th nhn Exit tr v chng trnh ban u khi khng mun thay

i password na.

/**/

#include "io430.h"#include "intrinsics.h"#define COT0 BIT0#define COT1 BIT1#define COT2 BIT2#define COT3 BIT3#define COT4 BIT4#define COT5 BIT5#define COT6 BIT6

#define COT7 BIT7__intrinsic void __delay_cycles(unsigned long __cycles);/*........................Doan quet phim so va nhap pass......................*/void quetphim (int *nhappass,int *p){

int i=0,n=0;while(i < 6){

P1OUT = 0x0E; /*.................Chon hang thu 1................*/__delay_cycles(5000);

if ((P1IN&COT4) == 0) //Nhap so 1{P2OUT |= COT3;nhappass[i] = 1;i++;n=0;while ( n==0 )

{if ((P1IN&COT4) == 0)

n=0;else

n=1;}

}else if ((P1IN&COT5) == 0) //Nhap so 2{P2OUT |= COT3;nhappass[i] = 2;


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i++;n=0;while ( n==0 )

{if ((P1IN&COT5) == 0)

n=0;else

n=1;}

}else if ((P1IN&COT6) == 0) //Nhap so 3

{P2OUT |= COT3;nhappass[i] = 3;i++;

n=0;while ( n==0 ){if ((P1IN&COT6) == 0)

n=0;else

n=1;}

}else //Khong nhap

P2OUT &= ~COT3;P1OUT = 0x0D; /*.................Chon hang thu 2................*/__delay_cycles(5000);if ((P1IN&COT4) == 0) //Nhap so 4{P2OUT |= COT3;nhappass[i] = 4;i++;n=0;while ( n==0 )

{if ((P1IN&COT4) == 0)

n=0;else

n=1;}



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{P2OUT |= COT3;nhappass[i] = 5;i++;n=0;

while ( n==0 ){if ((P1IN&COT5) == 0)

n=0;else

n=1;}


{

P2OUT |= COT3;nhappass[i] = 6;i++;n=0;while ( n==0 ){if ((P1IN&COT6) == 0)

n=0;else

n=1;

}}else if ((P1IN&COT7) == 0) //Nhan close.

{if (*p==1)

{if (i==0)

{P2OUT |= COT3;n=0;while ( n==0 )

{if ((P1IN&COT7) == 0)

n=0;else

{P2OUT &= ~COT3;n=0;


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while ( n


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elsen=1;

}}

else if ((P1IN&COT6) == 0) //Nhap so 9

{P2OUT |= COT3;nhappass[i] = 9;i++;n=0;while ( n==0 ){if ((P1IN&COT6) == 0)

n=0;else

n=1;}}

else //Khong nhapP2OUT &= ~COT3;

P1OUT = 0x07; /*.................Chon hang thu 4................*/__delay_cycles(5000);if (*p==0)

{if ((P1IN&COT4) == 0) //Nhan nut Exit


{if ((P1IN&COT4) == 0)

n=0;else

{n=1;i=7;*p = *p+1;P2OUT &= ~COT3;}

}}

}if ((P1IN&COT5) == 0) //Nhap so 0


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{P2OUT |= COT3;nhappass[i] = 0;i++;n=0;

while ( n==0 ){if ((P1IN&COT5) == 0)

n=0;else

{n=1;P2OUT &= ~COT3;}

}

}else if ((P1IN&COT6) == 0) //Xoa so vua nhap{if ( i >0 ) //Neu bang i = 1 khong xoa

{i--;P2OUT |= COT3;}

n=0;while ( n==0 )

{if ((P1IN&COT6) == 0)n=0;

elsen=1;

}}

else //Khong nhapP2OUT &= ~COT3;

/*......................Chon nhan ok hay exit hoac clear......................*/while (i==6) //Xoa so vua nhap khi i = 5.

{P1OUT = 0x07; //chon hang thu 4if ((P1IN&COT7) == 0) //Nhan ok

{P2OUT |= COT3;i++;n=0;


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while ( n==0 ){if ((P1IN&COT7) == 0)

n=0;else

{n=1;P2OUT &= ~COT3;}

}}

else if ((P1IN&COT6) == 0) //Xoa so vua nhap{if ( i > 0 ) //Neu bang i = 0 khong xoa

{

i--;P2OUT |= COT3;}

n=0;while ( n==0 )

{if ((P1IN&COT6) == 0)

n=0;else

n=1;

}}else if (*p==0)

{if ((P1IN&COT4) == 0) //Nhan nut Exit


{if ((P1IN&COT4) == 0)

n=0;else

{n=1;i=7;*p = *p+1;P2OUT &= ~COT3;


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}}

}}

else //Khong nhap

P2OUT &= ~COT3;}

/*................Ket thuc doan cho nhan ok hay exit hoac clear...............*/}

}/*.....................Ket thuc doan quet phim so va nhap pass................*//*...........................Doan so sanh pass................................*/void sosanh (int nhappass[6],int *i,int a,int b,int c,int d,int e,int h){

if (*i==0)

{if(nhappass[*i] == a){*i = *i+1;if(nhappass[*i] == b){*i = *i+1;if(nhappass[*i] == c)

{*i = *i+1;

if(nhappass[*i] == d){*i = *i+1;if(nhappass[*i] == e)

{*i = *i+1;if(nhappass[*i] == h)

*i = *i+1;}

}}

}}

}else

*i = 7;}

/*.........................Ket thuc doan so sanh pass.........................*/


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/*............................Doan treo he thong..............................*/void treohethong (void){

int j;P2OUT |= COT3;

j=0;while (j


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BCSCTL1 = CALBC1_1MHZ;DCOCTL = CALDCO_1MHZ;P2DIR = 0xFF;P2OUT = 0x00;P1DIR = 0x0F; //port 1.0,1.1,1.2,1.3 ngo ra,port 1.4,1.5,1.6,1.7 ngo vao.

while(1){P2OUT = 0x00;p=1;quetphim(nhappass,&p);i=0;sosanh(nhappass,&i,a,b,c,d,e,h);

/*...............Doan kiem tra ket qua so sanh pass..............*/k=0;while (k==0)

{ if ( i == 6 )//Nhap pass dung.{denchop ();m=0; //Cho phep vong lap quet phim chuc nang hoat dong.

j=0; //Gan j=0 de dem so lan nhap pass sai trong lan nhap moi.k=1; //Gan k=1 de thoat khoi vong lap so sanh pass.}

else //Nhap sai pass mot lan.{

j++;if (j==3)//So sanh da sai du 3 lan chua.{loakeu();treohethong ();

j=0; //Gan j=0 dem so lan nhap pass sai trong lan nhap moi.k=1; //Gan k=1 de thoat khoi vong lap so sanh pass.m=1;}

else //Nhap sai chua qua 3 lan.{loakeu();k=1; //Gan k=1 thoat khoi doan sanh pass de nhap tiep khi j


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P2OUT &= ~COT3;n=0;while ( n


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}else

m=1;if (p==0)

{

k=0;while (k


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}}

}/*.......................Ket thuc doan quet phim chuc nang....................*/

}

/*..................Ket thuc doan kiem tra ket qua so sanh pass...............*/}

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Khoa So Dung Msp430