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Math Exercices Differential equations 1 First order Solve the following differential equations. Find an explicit form y(x) when possible, otherwise an implicit equation F (x, y) = 0. Answers are given between brackets, C is the undetermined constant. (4y +3x 2 )y +2xy =0 y 4 +3x 2 y 2 = C x 2 y + y 2 = xyy y x - ln y = C y = x 1+ y 2 y 1+ x 2 1+ x 2 - 1 - y 2 = C 3xy 3 - 2y +(x 2 y 2 + x)y =0 y = Cx 2 (xy 2 - 1) (3x 2 y +2xy + y 3 )dx +(x 2 + y 2 )dy =0 e 3x (x 2 y + y 3 3 )= C y = a 2 (x + y) 2 y - a arctan ( x+y a ) + C =0 y + y cos x = 1 2 sin(2x) y = sin x - 1+ Ce sin(x) y =(x + y + 1) 2 [y = -x - 1 - tan(C - x)] y = - 1 2xy ( y 2 + 2 x ) xy 2 = C - 2 ln x y = 2x5y+3 2x+4y6 (4y - x - 3)(y +2x - 3) 2 = C (x 3 + x 2 + x + 1)y 2 - (3x 2 +2x + 1)yy +2xy 2 =0 (y - C (x + 1))(y - C (x 2 + 1)) = 0 dx - (xy + x 2 y 3 )dy =0 2 - y 2 + Ce y 2 /2 = 1 x (1 - x 2 )y - xy = xy 2 1 y = -1+ C x 2 - 1 2x 3 y =1+ 1+4x 2 y arctanh 1+4x 2 y + 1 2 ln y = C x 2 y 2 - 2(xy - 4)y + y 2 =0 y = 2 x ;(y - Cx) 2 +8C =0 (1 - x)y 2 dx - x 3 dy =0 2x 2 1 - 2x +2Cx 2 1

Math Exercices

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Page 1: Math Exercices

Math Exercices

Differential equations

1 First order

Solve the following differential equations. Find an explicit form y(x) when possible, otherwise an implicit equationF (x, y) = 0. Answers are given between brackets, C is the undetermined constant.

(4y + 3x2)y′ + 2xy = 0[y4 + 3x2y2 = C

]

x2y′ + y2 = xyy′[yx − ln y = C

]

y′ =x√1 + y2

y√1 + x2

[√1 + x2 −

√1− y2 = C

]

3xy3 − 2y + (x2y2 + x)y′ = 0[y = Cx2(xy2 − 1)

]

(3x2y + 2xy + y3)dx+ (x2 + y2)dy = 0[e3x(x2y + y3

3 ) = C]

y′ =a2

(x+ y)2[y − a arctan

(x+ya

)+ C = 0

]

y′ + y cosx = 12 sin(2x)

[y = sinx− 1 + Ce− sin(x)

]

y′ = (x+ y + 1)2 [y = −x− 1− tan(C − x)]

y′ = − 12xy

(y2 + 2

x

) [xy2 = C − 2 lnx

]

y′ = 2x−5y+32x+4y−6

[(4y − x− 3)(y + 2x− 3)2 = C

]

(x3 + x2 + x+ 1)y′2 − (3x2 + 2x+ 1)yy′ + 2xy2 = 0[(y − C(x+ 1))(y − C(x2 + 1)) = 0

]

dx− (xy + x2y3)dy = 0[2− y2 + Ce−y2/2 = 1

x

]

(1− x2)y′ − xy = xy2[1y = −1 + C

√x2 − 1

]

2x3y′ = 1 +√

1 + 4x2y[arctanh

(√1 + 4x2y

)+ 1

2 ln y = C]

x2y′2 − 2(xy − 4)y′ + y2 = 0[y = 2

x ; (y − Cx)2 + 8C = 0]

(1− x)y2dx− x3dy = 0

[2x2

1− 2x+ 2Cx2

]

1

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Math Exercices

Differential equations

2 Higher order

2x2y′′ − 3xy′ − 15y = 0[y = C1x

5/2 + C2

x3

]

x2y′′ − 2y = x[y = −x

2 + C1x2 + C2

x

]

x2y′′ − 7xy′ + 16y = 0[y = C1x

4 + C2x4 lnx

]

Without solving the equation, find a particular integral y0 ofy′′ − 4y′ − 12y = sin(2x)

[y0 = 1

40 cos(2x)− 120 sin(2x)

]

y′′ − 4y′ − 12y = xe4x[y0 = −1

36 (3x+ 1)e4x]

x3y(3) − 6x2y′′ + 19xy′ − 27y = 0[y = C1x

3 + C2x3 ln(x) + C3x

3 ln(x)2]

y(4) + 2y′′ + y = e−x[y = (C2 + C4x) cosx+ (C1 + C3x) sinx+ 1

4e−x

]

Note that y = x is a solution of the following equation ifthe right side where 0. Use this fact to obtain the solutionof the equation as given(1− x)y′′ + xy′ − y = (1− x)2

[y = C1x+ C2e

x + x2 + 1]

Given the particular integral y1 = x1−x , solve

x2(1− x)y′′ − x(1 + x)y′ + y = 0 []

y′′(x)2 = 1 + y′(x)[y = −x+ C1 ; y = x3

12 + C1x2

4 + (C2

1

4 − 1)x+ C2

]

yy′′ − y′2 − 6xy2 = 0[y = C1 exp(x

3 + C2x)]

hint : try v = y′/y

1

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Math Exercices

Differential equations

3 Power series

Use power series (expansion at x = 0) to solve the following equations. Solutions are given between brackets.

y′ = x2y

[y = c0

∞∑

n=0

x3n

3n n!

]

y′′ − xy′ − y = 0 , y(0) = 1 , y′(0) = 0

[y =

∞∑

n=0

x2n

2n n!

]

y′′ + x2y′ + xy = 0 , y(0) = 0 , y′(0) = 1

[y = x+

∞∑

n=1

(−)n[2.5...(3n− 1)]2

(3n+ 1)!x3n+1

]

Show that the following Euler equation has a regular singular point at x = 0, and search a series solution by the Frobeniusmethod. Compare to the direct solution.

x2y′′ + 2xy′ − 2y = 0[y = C1x+Bx−2

]

Using the Frobenius method, find a power series solution about the point x = 0 of

2x2y′′ − xy′ + (1 + x)y = 0

[y = c1

√x

(1− x+

x2

6− x3

90...

)+ c2

(x− x2

3+

x3

30...

)]

Consider the two equations below. The first one has two equal indicial roots, the seond one has two integer roots. For bothequations find a series expansion at the origin for the two basis solution y1(x) and y2(x). For y2 give only the recurrencerelation between the coefficients of the series, and the first 3 terms.

xy′′ + y′ + 2y = 0

[y1 =

∞∑

n=0

(−2)n

(n!)2xn ; y2 = y1 ln(x) + c1 + (4− 2c1)x+ (c1 − 3)x2 + . . .

]

y′′x = y

[y1 =

∞∑

n=0

xn+1

n!(n+ 1)!; y2 = y1 ln(x) + 1 + c1x+

(c12

− 3

4

)x2 + . . .

]

Calculate the indicial roots r1 and r2 of the following equation, and show that they are complex. Show that the Frobeniusmethod gives two power series y1 and y2 involving complex coefficients and powers. Considering only the first term ofy1 and y2, combine them to find the first term of the two real-valued solutions y1 and y2 (hint : assume that the firstcoefficient of y1 and y2 is real).

x2y′′ + (x2 + x)y′ + y = 0 [y1 = cos(ln(x)) + . . . ; y2 = sin(ln(x)) + . . .]

1

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Math Exercices

Legendre polynomials and spherical harmonics

1 Variations about Legendre polynomials

1. Show that ∫ 1

−1

Pn(t) (1 + h2 − 2ht)−1/2 dt =2hn

2n+ 1

where h < 1.

2. Using Rodrigues Formula, establish the recurrence relation

P ′n+1(x) = P ′

n−1(x) + (2n+ 1)Pn(x)

3. Expand the function f(x) = ln(

1+x1−x

)as a series in Legendre polynomials for −1 < x < 1. Hint : use the identity

∫ 1

−1

f(x)dn

dxn(x2 − 1)n dx = (−)n

∫ 1

−1

(x2 − 1)ndn

dxnf(x)

2 Multipole expansion

1. A point charge q is located at the position (0, 0, z0). Write down the electric potential V (r, θ) at a point of polarcoordinates (r, θ) using Coulomb’s law. Expand V as a series of Legendre polynomials for r > |z0|, and give thethree first terms of the developpement.

2. Same question if we add a second charge −q at the position −z0. Show that the asymptotic potential is ∝ 1/r2

(dipolar potential).

3. How would be modified the multipole expansion of r < |z0| ? Express the potential of the two charges of question 2near the origin and give the leading term of the series.

4. Write down the multipole expansion as a series in spherical harmonics in the case of 4 charges qi located at positions~ri with : q1 = q3 = q, q2 = q4 = −q, ~r1 = (a, 0, 0) = −~r2, ~r3 = (0, a, 0) = −~r4 (a > 0). Give the first term of theseries.

3 Conducting sphere with hemispheres at different potentials

We consider a conducting sphere of radius a made up of two hemispheres separated by a small insulating ring. Thenorthern hemisphere is kept at fixed potential +V0 (−V0 for the southern hemisphere).

1. Determine the electric potential in the region r > a as a series in Legendre polynomials Pl. Write down the termsup to l = 4.

2. Same question inside the sphere (r < a). Verify that the two series give the same result at r = a.

1

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