MathByVemuri_ CSAT 2013 Solved Paper (Paper-II)

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  • 09/04/2015 MathByVemuri:CSAT2013SolvedPaper(paperII)

    http://mathbyvemuri.blogspot.in/2013/05/csat2013solvedpaperpaperii.html 1/21

    MathByVemuri

    Home CONCEPTS PUZZLES MathinEveryDayLife GMAT/GRE CAT/Other CSAT/GATE

    MONDAY,27MAY2013

    CSAT2013SolvedPaper(paperII)1.Inararecoincollection,thereisonegoldcoinforeverythreenongoldcoins.10moregoldcoinsareaddedtothecollectionandtheratioofgoldcoinstonongoldcoinswouldbe1:2.Basedontheinformation,thetotalnumberofcoinsinthecollectionnowbecomes

    (a)90(b)80(c)60(d)50Solution:Initialratio=G:N=1:3(1)Afteradding10goldcoins,theratiobecomes(10+G):N=1:2(2)Onsolving(1)&(2),weget,G=20andN=60.Presently,thetotalnumberofcoinsinthecollection=(10+G)+N=10+20+60=90Ans:(a)

    2.A gardenerhas 1000plants.Hewants toplant them in such away that thenumberofrowsandthenumberofcolumnsremainsthesame.Whatistheminimumnumberofplantsthatheneedsmoreforthispurpose?

    (a)90(b)24(c)32(d)34Solution:Ifthenumberofrowsandnumberofcolumnsaretobeequal,thenthetotalnumberoftrees

    will be in the form of x2, which is nothing but a perfect square. As 1000 is not a perfectsquare,weneedtocheckforaperfectsquareaboveandnearestto1000.Its1024,whichissquareof32.Soheneedstoadd24moretreestoget1024.Ans:(b)

    3.ASumofRs700hastobeusedtogive7cashprizestothestudentofaschoolfortheiroverallacademicperformance.Ifeachprize isRs20lessthanitspreceding price,what istheleastvalueoftheprice?

    (a)Rs30(b)Rs40(c)Rs60(d)Rs80Solution:LettheleastvaluepricebeX.ThenthenextvalueisX+20,andthenextvalueisX+40andonandonupto7values.ItsnothingbutanarithmeticProgressionwithsum700.X+X+20+X+40+X+120=700=>7X+(20+40++120)=700=>7X+20(1+2+3++6)=700=>7X+20(21)=700=>7X=280=>X=40Ans:(b)

    4.Outof120applicationsforapost70aremaleand80haveadriverslicense.Whatistheratiobetweentheminimumtomaximumnumberofmaleshavingdriverslicense?

    (a)1to2(b)2to3(c)3to7(d)5to7Solution:70male=>12070=50femaleForamaximum,all70maleshallhavedriverslicenseFor aminimum: If all 50 females posses drivers license, then the remaining 30 licensesshallbepossessedbymales.Sominimummaledriverslicenses=30Mintomax=30to70=3to7Ans:(c)

    5. Inagarrison, therewas food for1000soldiers foronemonth.After10days, 1000moresoldiers joined the garrison. How long would the soldiers be able to carry on with theremainingfood?

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    CSAT2013SolvedPaper(paperII)1.Inararecoincollection,thereisonegoldcoinforeverythreenongoldcoins.10moregoldcoinsareadded...

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  • 09/04/2015 MathByVemuri:CSAT2013SolvedPaper(paperII)

    http://mathbyvemuri.blogspot.in/2013/05/csat2013solvedpaperpaperii.html 2/21

    (a)25days(b)20days(c)15days(d)10daysSolution:After10days,theremainingfoodwouldbesufficientforthe1000soldiersfor20moredays=> If 1000more soldiers are added, it shall be sufficient for only 10 days (as the no. ofsoldiersisdoubled,thedaysarehalved)Ans:(d)

    6.AtankfullpetrolinArunsmotorcyclelastfor10days.Ifhestartsusing25%moreeveryday,howmanydayswillthetankfullpetrollast?

    (a)5(b)6(c)7(d)8Solution:Theanalogyislikethis:Arunhas10ltofpetrolandheuses1ltpereachdayandconsumesitin10days.Ifheuses1.25lteveryday,inhowmanydaysitwillbeconsumed?Weconsidered1.25ltherebecauseits25%morethan1lt.Theanswerwouldbe10/1.25=8Ans:(d)

    7.Apersoncanwalkacertaindistanceanddrivebackin6hrs.Hecanalsowalkbothwaysin10hrs.Howmuchtimewillhetaketodrivebothways?

    (a)Twohours(b)Twoandahalfhours(c)Fiveandahalfhours(d)FourhrsSolution:2waywalk=10hrs=>1waywalk=5hrs1waywalk+1wayDrive=6hrs=>1waydrive=65=1hrHence,2waydrive=2hrsAns:(a)

    8.Considerthefollowingmatrix:

    3 370 72 224 61 730 X

    WhatisthenumberatXintheabovematrix?(a)5(b)8(c)9(d)11

    Solution:

    Consider2ndelementineachrow.Sumupthedigitsofeachnumber.3+7+0=102+2+4=87+3+0=10Nowredrawthetablelikethis:

    3 10 72 8 61 10 X

    Noweachrowfollowsthis:sumof1stand3rdelementsisequalto2ndelement.1+X=10=>X=9Ans:(c)

    9.Examinethefollowingthreefiguresinwhichthenumbersfollowaspecificpattern:84 81 8814 12 18 9 ? 11

    Themissingnumber(?)inthethirdfigureaboveis(a)7(b)16(c)21(d)28

    Solution:Observethefirsttwofigurescarefully:2*(84/12)=142*(81/9)=18Henceforthethirdfigure,2*(88/11)=X=>X=2*8=>X=16Ans:(b)

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  • 09/04/2015 MathByVemuri:CSAT2013SolvedPaper(paperII)

    http://mathbyvemuri.blogspot.in/2013/05/csat2013solvedpaperpaperii.html 3/21

    thatAgetsone lessthanB,Cgets5morethanDandDgets3morethanB.Whogetsthesmallestamount?

    (a)A(b)B(c)C(d)DSolution:A=B1=>B=A+1C=D+5D=B+3Ifwe see these equations,we can find that every one exceptAhas got some thingmorethansomeother(+indicatesmorethan).SoanswermustnotbeB,CorD.SoAisthechoiceAns:(a)

    11.Therearefivehobbyclubsinacollegeviz.,photography,yachting,chess,electronicsandgardening.Thegardeninggroupmeetsevery secondday,theelectronicsgroupmeetseverythirdday,thechessgroupmeetseveryfourthday,theyachtinggroupmeetseveryfifthdayand thephotographygroupmeetseverysixthday.Howmany timesdoall the fivegroupsmeetonthesamedaywithin180days?

    (a)3(b)5(c)10(d)18Solution:It'sasimpleLCMproblem.FindoutLCMof2,3,4,5and6.

    It's 60. SO every 60th day all the five groupsmeet. So in a period of 180 days theymeet

    thriceie.,on60thday,120thdayand180thday.Ans:(a)

    12. In a class of 45 students, a boy is ranked 20th .When two boys joined, his rankwasdroppedbyone.Whatishisnewrankfromend?

    (a)25th(b)26th(c)27th(d)28th

    Solution:Aftertwoboysareaddedtheclassstrengthbecome47.

    Theboy'srankisdroppedbyone=>hisrankbecomes21st

    =>Thereare4721=26belowhisrank

    =>Heisranked27thfromendAns:(c)

    13.Athiefrunningat8km/hrischasedbyapolicemanwhosespeedis10km/hr.Ifthethiefis100maheadofpoliceman,thenthetimerequiredforthepolicemantocatchthethiefwillbe?

    (a)2(b)3(c)4(d)6Solution:Ifweconsiderthedifferenceofspeeds,policemanisat2km/hrleadingspeedandhencehecancatchthethiefat100maheadby100m/2kmph=100/2000hr=3minAns:(b)

    14. A train travels at a certain average speed for a distance of 63 km and then travels adistanceof72kmatanaveragespeedof6km/hrmorethanitsoriginalspeed.Ifittakes3hourstocompletethetotaljourney,whatistheoriginalspeedofthetraininkm/hr?

    (a)24(b)33(c)42(d)66Solution:LettheoriginalspeedbeS.Totaltimetaken=3hr=>63/S+72/S+6=3Letustrywithansweroptions.Aswehave63inthenumerator,wecanassumethatSmaybeamultipleof7.Theonlyoptionavailableis4.So,letustrywiththat.63/42+72/48=3/2+3/2=3=>thissuitsAns:(c)

    15.FourcarsarehiredattherateofRs6perkmplusthecostofdieselatRs40alitre.Inthiscontext,considerthedetailsgiveninthefollowingtable:

    Car Mileage(km/l)

    Hours TotalPayment(Rs)

    A 8 20 2120B 10 25 1950C 9 24 2064

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