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Compendium formulas for "machine design II" subject
Force method - Compendium of solutions for beam displacements Load case ii displ. at midspan (f) displ. at end () ij
11 3
lEJ
216Mlf EJ 21 6 lEJ
21,0 16
FlEJ
348Flf EJ
31,0 24
p lEJ
45384
p lf EJ
1,0 24
M lEJ
11 2
lEJ
28Mlf EJ
1,0
l Th
2,0 l Th
33FlEJ
22FlEJ
22M lEJ U M lM EJ
48
p lEJ
Ex: 1 11 1 12 2 10M M
F
p
p
Bolt connections Bolt geometry data (according to the standard UNI 4535-64)
Allowable stresses for the assessment of bolts:
Allowable stresses for the assessment of plates:
Shear joint assessment Bolt Shear (if only tangential stress)
If combined stress on bolt 2 2
, ,1
b adm b adm
Hole plastic deformation Tearing
Friction joint assessment , f 0,8 ,
Beam profiles
Axis yy Axis xx Linear mass Profile identification
Axis-symmetric elastic problems (disks) General stress solution
Solid disk with external pressure pe
Hollow disk with external and internal pressure pe and pi
222
2222
22222
2222
22
1)(1)(
rrrrrpp
rrrprp
rrrrrpp
rrrprp
ieeiie
ieeeii
ieeiie
ieeeiir
Rotating solid disk at constant speed = cost No pressure
2222
222
831
83
)(83
rrrr
e
er
Rotating hollow disk at constant speed = cost No pressure
)331(8
3)(8
322
22222
2222222
rrrrrr
rrrrrrieei
ieeir
TBN The maximum value of is reached for
r F 'r C1 C2r 2 38 2r 3 dF 'dr Frr C1 C2r 2 1 38 2r 2
2
Stress solution for infinite plate with hole Plate with hole subject to biaxial stresses
Plate with hole subject to internal pressure
Plate with hole subjected to uniaxial load
Theoretical solutions for Kt
Coefficients for fatigue assessment Solution for coefficient to calculate the Notch sensitivity index.
Dimensional coefficient md
Surface finish coefficient ms
Finite Elements