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Metodo newton , en exel, iteraciones
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F(X) = 2X2
- X – 5
F’(X) = 4X - 1
Iteracion Xi f(Xi) f'(Xi) f(Xi)/f'(Xi)
0 0 -5 -1 5
1 -5 50 -21 -2,38095238
2 -2,61904762 11,3378685 -11,4761905 -0,98794705
3 -1,63110057 1,95207873 -7,52440229 -0,25943306
4 -1,37166751 0,13461103 -6,48667004 -0,02075195
5 -1,35091556 0,00086129 -6,40366226 -0,0001345
6 -1,35078107 3,618E-08 -6,40312426 -5,6504E-09
7 -1,35078106 0 -6,40312424 0
Primera Raiz -1,35091556
Iteracion Xi f(Xi) f'(Xi) f(Xi)/f'(Xi)
0 5 40 19 2,10526316
1 2,89473684 8,86426593 10,5789474 0,83791568
2 2,05682116 1,40420539 7,22728463 0,19429225
3 1,86252891 0,07549896 6,45011563 0,01170505
4 1,85082385 0,00027402 6,40329541 4,2793E-05
5 1,85078106 3,6625E-09 6,40312424 5,7199E-10
6 1,85078106 0 6,40312424 0
7 1,85078106 0 6,40312424 0
Segunda raiz 1,85082385
SOLUCION DE ECUACIONES NO LINEALES
METODO DE NEWTON RAPHSON
𝑋𝑖+1 = 𝑋𝑖 −𝐹(𝑋𝑖)
𝐹′(𝑋𝑖)
𝑻𝒐𝒍𝒆𝒓𝒂𝒏𝒄𝒊𝒂 = 𝟎.𝟓
𝑿𝒊 = 𝟎
𝑻𝒐𝒍𝒆𝒓𝒂𝒏𝒄𝒊𝒂 = 𝟎.𝟓
Xi - f(Xi)/f'(Xi) abs(f(Xi)) abs(f(Xi))<=Tol
-5 5 Continuar
-2,619047619 50 Continuar
-1,631100573 11,33786848 Continuar
-1,37166751 1,952078732 Continuar
-1,350915564 0,134611028 Fin
-1,350781065 0,000861287 Fin
-1,350781059 3,618E-08 Fin
-1,350781059 0 Fin
Xi - f(Xi)/f'(Xi) abs(f(Xi)) abs(f(Xi))<=Tol
2,894736842 40 Continuar
2,056821157 8,864265928 Continuar
1,862528908 1,404205389 Continuar
1,850823853 0,075498957 Fin
1,85078106 0,000274017 Fin
1,850781059 3,66249E-09 Fin
1,850781059 0 Fin
1,850781059 0 Fin
SOLUCION DE ECUACIONES NO LINEALES
Evaluacion del
procesoValor absoluto
Valor absoluto
Evaluacion del
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