Nhieu Trong Thong Tin Di Dong

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    MC LCMC LC.................................................................................................... 1LI MU.............................................................................................. 21.Nhiu trng................................................................................................ 3

    1.1. Khi nim v nhiu trng................................................................... 31.2. Cc php biu din ton hc ca nhiu trng..................................... 41.3. Ph cng sut ca nhiu trng c bng tn gii hn: ......................... 4

    2. Nhiu lin k t ISI (Inter symbol interference) ...................................... 62.2. Cc bin php khc phc nhiu ISI.................................................... 7

    2.2.1. B lc cos nng: .......................................................................... 72.2.2. B lc ngang p khng: ............................................................... 9

    3. Nhiu lin knh ICI (Interchannel Interference)..................................... 11

    3.1. Nhiu lin knh ICI.......................................................................... 113.2.Nhiu xuyn knh trong OFDM knh thng tin di ng................ 123.2.1. Gii thiu.................................................................................. 123.2.2. OFDM knh thay i theo thi gian....................................... 133.2.3. Phn tch nhiu xuyn knh (ICI) .............................................. 153.2.4 Kt lun. ..................................................................................... 19

    3.3.ISI v ICI trong h thng FDM......................................................... 194. Nhiu ng knh (Co-Channel Interference) ......................................... 23

    4.1. Khi nim chung.............................................................................. 234.2.Ti s dng tn s ............................................................................. 24

    4.2.1.Khi nim ti s dng tn s ...................................................... 244.3.Cc mu ti s dng tn s ............................................................... 29

    4.3.1. Mu 3/9...................................................................................... 294.3.2.Mu 4/12..................................................................................... 304.3.3.Mu 7/21..................................................................................... 31

    4.3. Nhn xt........................................................................................... 314.3.1. So snh gia cc mu s dng tn s: ....................................... 314.3.2. Dung lng v t s C/I. ............................................................ 31

    5. Nhiu a truy nhp (Multiple Access Interference)................................ 32

    KT LUN................................................................................................ 37

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    LI MUNhiu l mt vn rt quan trng trong thng tin di ng, nh

    hng n cht lng ca tn hiu, khi x l tn hiu v khi truyn tn hiu

    tn hiu lm gy mo tn hiu hoc xut hin cc tp m trong cc thit b

    ti to li tn hiu

    V vy ta phi gim st c chng v tm bin php khc phc tn

    hiu nhiu n mc ti a tng cht lng ca ca tn hiu.

    Bi tiu lun di y s trnh by mt cch ngn gn l thuyt v 05

    loi nhiu trong thng tin di ng. Nm vng l thuyt v nhiu v tm

    hiu, nghin cu cc bin php khc phc chng s gip mng thng tin di

    ng nng cao cht lng, hiu qu.

    B cc ca bi tiu lun gm c 05 phn, tng ng vi 05 loi

    nhiu, l:

    1.Nhiu trng ( White Gaussian Noise)

    2.Nhiu xuyn m ( Intersymbol Interference)3.Nhiu xuyn knh ( Interchannel Interference)

    4.Nhiu ng knh ( Cochannel Interference)

    5.Nhiu a truy nhp ( Multiple access Interference).

    Nhm chng ti xin chn thnh cm n thy Nguyn Vn c

    hng dn, gip chng ti hon thnh bi tiu lun ny.

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    1.Nhiu trng

    1.1. Khi nim v nhiu trngNhiu trng l qu trnh xc xut c mt ph cng sut phng(

    khng i ) trn ton b di tn

    Nhiu trng l mt loi nhiu c hm mt xc sut tun theo phn

    b Gauss.

    Nhiu trng c th do nhiu ngun khc nhau gy ra nh thi tit,do

    b khuch i my thu,do nhit ,hay do con ngi.Tn hiu thu do vy

    c vit li nh sau:

    y(t)=x(t)*h()+n(t)

    h( )H(j )

    +

    n(t)

    y(t)x(t)

    Tn hiu pht

    M hnh knh

    Tn hiu thu

    Hinh 1. Mi trung truyn dn vi sc mt ca nhiu trng

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    1.2. Cc php biu din ton hc ca nhiu trngV mt ton hc,ngun nhiu trng n(t) c th m hnh bng mt

    bin xc sut Gauss vi gi tr k vng =0 v lch chun l 2

    =E[x]=0

    2 =E[(x- )2]

    Hnh 2. Hm phn bGauss

    Do k vng bng khng nn lch chun cng bng phng sai ca

    bin ngu nhin x. C th hn nhiu trng c cng sut khng i 2

    1.3. Ph cng sut ca nhiu trng c bng tn gii hn:V mt l thuyt ,nhiu trng c bng tn v hn v cng sut nhiu

    l u n mi tn s .V mt thc t khng c h no c bng tn v

    hn m b gii hn mt bng tn no . Do vy mt ph cng sut

    ca nhiu cng b gii hn nhhnh 3

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    Hnh 3. Mt phcng sut nhiu

    hnh trn ta gi s l h thng c bng tn gii hn B = 2g vi

    chu k ly mu l ta.. Mt ph cng sut ca nhiu nh hnh1 c vit

    li nh sau:

    Tt c cc bin ngu nhin u khng tn ti php bin i Fourier

    m ch tn ti hm t tng quan v hm mt cng sut,trong hm

    mt cng sut l php bin i Furie ca hm t tng quan. phng

    trnh trn nn(j) l hm mt cng sut nhiu cn nn() l hm t tng

    quan ca nhiu vi nh ngha :

    nn() = E[n(t)n(t+ )] = 2

    si g

    Theo phng trnh hm t tng quan l bin i Furie ngc ca

    hm mt ph cng sut.Do hm mt ph cng sut c dng hnh ch

    nht nhhnh 1, kt qu bin i Furie ngc ca hm hnh ch nht

    cho ta hm s Si().

    Cng sut ca nhiu c th tnh c bng c t hm mt cng

    sut nhiu hoc hm t tng quan ca nhiu nh sau:

    Pn=E[n2(t)] = nn(0) =1/2 +

    nn(j)d = 2 t

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    Khi t s tn hiu trn tp m c tnh theo cng thc sau:

    SNR=Ps/Pn

    Vi Ps l cng sut tn hiu c ch.T s ny quyt nh cht lng

    tn hiu v dung lng knh

    2. Nhiu lin k t ISI (Inter symbol interference)

    Trong mi trng truyn dn a ng, nhiu xuyn k t (ISI) gy

    bi tn hiu phn x c thi gian tr khc nhau t cc hng khc nhau t

    pht n thu l iu khng th trnhkhi. nh hng ny s lm bin dng

    hon ton mu tn hiu khin bn thu khng th khi phc li c tn hiugc ban u. Cc k thut s dng tri ph trc tip DS-CDMA nh trong

    chun 802.11b rt d bnh hng bi nhiu a ng v thi gian tr c

    th vt qu khong thi gian ca mt k t. OFDM s dng k thut

    truyn song song nhiu bng tn con nn ko di thi gian truyn mt k t

    ln nhiu ln. Ngoi ra, OFDM cn chn thm mt khong bo v (guard

    interval - GI), thng ln hn thi gian tr ti a ca knh truyn, gia hai

    Hnh 4. M hnh gy nhiu

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    k t nn nhiu ISI c th b loi b hon ton.2.1. c im:Di thng

    tuyt i ca cc xung nhiu mc nh phng l v hn. Nu cc xung ny

    c lc khng ng khi chng truyn qua mt h thng thng tin th

    chng s tri ra trn min thi gian v xung cho mi k hiu s chn vo cc

    khe thi gian bn cnh gy ra nhiu gia cc k hiu (ISI).ISI l hin tng

    nhiu lin k hiu. ISI xy ra do hiu ng a ng, trong mt tn hiu

    ti sau s gy nh hng ln k hiu trc .

    Chng hn nh hnh 4 pha trn, ta thy r tn hiu phn x

    (reflection) n my thu theo ng truyn di hn so vi cc tn hiu cn

    li.

    2.2. Cc bin php khc phc nhiu ISITrong cc h thng n sng mang, ISI l mt vn kh nan gii.

    L do l rng bng tn t l nghch vi khong thi gian k hiu, do vy,

    nu mun tng tc truyn d liu trong cc h thng ny, tc l gim

    khong k hiu, v hnh chung lm tng mc tri tr tng i. Lc ny

    h thng rt nhy vi tri tr. V vic thm khong bo v kh trit tiu ht

    ISI.

    gim nhiu xuyn m ngi ta phi lm th no hn ch di thng

    m vn khng gy ra ISI. Khi di thng b gii hn, xung s c nh trn

    thay v nh phng.

    Mt trong nhng phng php loi b nhiu ISI l dng b lc

    cos nng v b lc ngang p khng (phng php Nyquist I).

    2.2.1. B lc cos nng:

    Hnh 5. S b lc cos nng

    Ngun s To xung Lc pht Lc thu Nhn tinQuytnh

    mk (t-kT) T( ) n(t) R( ) kak

    s(t) s(t)

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    Tn hiu t ngun gm c M phn t, song chng ta hn ch ch

    kho st trng hp khi cc phn t si(t) ca tp tn hiu ch khc nhau v

    bin , tc l ta s hn ch ch xt h thng iu ch bin xung PAM.

    Thc t h thng ny c th xem nh gn cho mi mt tin mk mt hng s

    akm bin ca xung u ra ca b to xung sc nhn vi n.

    Ta hy gi s rng b to xung cho ra cc xung Dirc ti cc thi

    im t=kTs. Cc xung dng dirac ny, c bin thay i tu theo s thay

    i cc gi tr mk, qua b lc T() s ti knh truyn. Phn my thu trn

    hnh 2.2 l my thu ti u, thu lc phi hp, mch quyt nh thc hin ly

    mu v so ngng. Hm truyn tng cng ca h thng (c tnh tn s

    tng cng ca h thng) l tch ca hai c tnh ca hai b lc pht v thu

    C()=T().R(). By gichng ta s tm kim lp cc c tnh lc C()

    sao cho vic truyn chui tn hiu qua h thng s khng c ISI. Vic

    truyn c coi l khng c ISI nu vo thi im quyt nh tn hiu ly

    mu th k, ch c phn ng xung ca tn hiu th k l khc khng cn phn

    ng ca cc tn hiu khc u bng khng.

    Theo nh l Nyquist, rng bng tn truyn dn nh nht c th

    truyn c khng mo tn hiu bng gc l B=1/2.T. rng bng y

    c ngha l di tn m ngoi n gi tr hm truyn ng nht bng khng.

    Tn s 1/2T c gi l tn s Nyquist. Do vy chng ta s xt cc c tnh

    lc c rng thng tn ti thiu l 1/2T (hay /T tnh theo tn s gc).

    Trc tin ta hy xem xt trng h p C() l c tnh ca b lc thng

    thp l tng, tc l p tuyn pha ca b lc th tuyn tnh cn p tuyn

    bin |C()| c dng:

    ( )

    >

    =

    0

    0

    ;0

    0;1

    C

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    B lc ny c phn ng xung l:

    t

    t

    tc0

    0sin

    )( =

    C gi tr cc i bng 1 ti t=0 v c gi tr bng 0 to t=k/0.

    Gi s rng u vo b lc l tng ny c tn hiu c to bi b

    to xung nh trn hnh 2.2, tc l tn hiu li vo b lc T()c cho bi:

    ( )kTtak =

    =

    -k

    s(t)

    Trong trng hp ny, phn ng xung u ra s khng gy nn ISI

    nu tn s ct ca b lc l f0=0/2=1/2T.

    Do n gin trong tnh ton, hm s cong dng cosine thng a

    c s dng phn tch cc b lc ny. Hm truyn tng cng khi c

    dng:

    V phn ng xung c dng:

    222 /41/cos

    //sin)(

    TtTt

    TtTttc

    =

    Hm truyn lin tc th c bin gn sng suy gim theo lu tha 3

    ca bin t. Do vy ngay c khi ng b khng l tng th gi tr ca phn

    ng xung u ra ca cc b lc ny s b chn. Do , ISI s nh ngay c

    khi ng b khng l tng.

    2.2.2. B lc ngang p khng:

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    Theo hnh 6 ta c p ng tn s ca ton h thng t pht n thu l

    H0(f)= HT(f). Hc(f)HE(f)

    Vi p ng xung tng hp

    h0(t)= f-1

    [H0(f) ]

    tho mn iu kin khng c nhiu lin k hiu ISI th

    constT

    kfH =

    +0

    Tn s ly mu tn hiu bn thu l 1/T. Theo th mt cn bng

    l tng zero- ISI n gin l mt b lc nghch o p ng tn s ca bn

    pht v knh truyn. B lc o ny thng c xp x bi mt b lc FIRnh hnh v di

    C-N CN

    D

    C0

    D

    C-N+1

    D D

    tm

    Pcq(t)

    Hnh 7. B lc cn bng knh

    Ngun sliu

    B lcpht

    B lc cnbng knh

    Knh

    truyn

    tm=mT+t

    V(tm)

    V(t)

    Hnh 6. V tr b lc cn bng knh.

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    p ng xung ca b lc cn bng knh l:

    ( )nTtCN

    N

    nE = =

    -n

    (t)h

    p ng tn s tng ng l:

    nTfjN

    N

    nE eC2

    -n

    (f)H

    ==

    Vn ca b lc o chnh l la chn cc h s ca b lc sao cho

    xp xc iu kin zero- ISI.Trong mi trng truyn dn a ng, nhiu xuyn k t (ISI) gy

    bi tn hiu phn x c thi gian tr khc nhau t cc hng khc nhau t

    pht n thu l iu khng th trnh khi. nh hng ny s lm bin dng

    hon ton mu tn hiu khin bn thu khng th khi phc li c tn hiu

    gc ban u. Cc k thut s dng tri ph trc tip DS-CDMA nh

    trong chun 802.11b rt d bnh hng bi nhiu a ng v thi gian tr

    c th vt qu khong thi gian ca mt k t. OFDM s dng k thut

    truyn song song nhiu bng tn con nn ko di thi gian truyn mt k t

    ln nhiu ln. Ngoi ra, OFDM cn chn thm mt khong bo v (guard

    interval - GI), thng ln hn thi gian tr ti a ca knh truyn, gia hai

    k t nn nhiu ISI c th b loi b hon ton.

    3. Nhiu lin knh ICI (Interchannel Interference)3.1. Nhiu lin knh ICI

    Nhiu xuyn knh gy ra do cc thit b pht trn cc knh lin nhau

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    Hnh 8

    Nhiu lin knh thng xy ra do tn hiu truyn trn knh v tuyn

    b dch tn gy can nhiu sang cc knh k n.

    loi b nhiu xuyn knh ngi ta phi c khong bo v (guard

    band) gia cc di tn.

    3.2.Nhiu xuyn knh trong OFDMknh thng tin ding

    3.2.1. Gii thiu

    Trong phng php a truy nh p phn chia theo tn s trc giao

    (OFDM), bng thng truyn c chia thnh nhiu knh nh, v c

    truyn song song vi nhau. Do , gii hn ca k t tng ln v nhiu lin

    k t (ISI) gy ra mi trng fading theo thi gian b loi b. Tuy nhin,

    vi nhng gii hn k t di hn, nhiu xuyn knh (ICI) gy ra bi

    Dopplerknh thng tin di ng li tng ln. Hiu ng Doppler c nh

    hng n h thng OFDM. y, chng ta nhn c gii hn ca ICI,

    tnh ton d dng hn v hu ch hn. Gii hn bao gm c gii hn chung

    v ring. Gii hn chung ch ph thuc vo tn s Doppler ln nht ( df ) v

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    thi gian k t ( sT). Gii hn ring cng ph thuc vo bin ca ph

    Doppler.

    3.2.2. OFDM knh thay i theo thi gianGi s tn hiu OFDM min thi gian l

    ( ) [ ] 2 kj f t k

    x t s k e = vi 0 st T (3.1)

    Vi 0kf f k f = + l tn s ca k knh con (subchannel) v1

    s

    fT

    = .

    Tn hiu truyn qua k (knh con), s[k], c coi l c lp vi cc knh con

    khc. Tn hiu nhn c, sau khi truyn qua knh thay i theo thi gianvi p ng xung ( , )h t , l:

    ( ) ( ) ( )~

    ,x t h t x t d = Vi nhiu knh (channel noise) v nhiu ng knh (co-channel

    interference) khng tnh ti.

    Trong iu kin fading phng, p ng xung knh c tht l:

    ( ) ( ) ( ),h t t =

    Tn hiu nhn c s l:

    ( )t l qu trnh wide-sense stationary stochastic vi dy s 0 v bin n

    v. Vi ph Doppler nguyn thy, mt ph ca ( )t l:

    ( )2

    1 1if

    11

    0

    d

    d

    J

    d

    f ffP f

    f

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    ( )

    1if

    2

    0

    d

    du

    f ffP f

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    3.2.3. Phn tch nhiu xuyn knh (ICI)

    Tn hiu c iu ch li c th bao gm c tn hiu nhn c ( )~

    t l:

    [ ] ( )~ ~

    2

    0

    1ss

    m

    T

    j f t

    s

    m x t e dt T

    = (3.4)

    n gin, s hi nhp (intergration) s dng thay th hm chuyn i

    Fourier ri rc (DFT). Bi vy, kt qu s bao gm c phn a vo trng

    hp s song mang khng xc nh. Tuy nhin, so snh vi trng hp s

    sng mang xc nh th s sai khc l khng ng k.

    a.Tnh ton chnh xc

    n gin, u tin chng ta nhn c bin ICI cho knh fading

    phng, v sau mrng kt qu cho mi trng c tn s bt k khc. T

    (3.1), (3.2) v (3.4), tn hiu c iu ch li trthnh:

    [ ] ( ) [ ]~

    2 2

    0

    1s

    s

    k m

    T

    j f t j f t

    ks

    m t s k e e dt T

    =

    ( ) [ ]2 ( )

    0

    1 s m kT

    j f f t

    k s

    t e dt s k T

    =

    [ ] [ ]0 m km k

    ICI

    a s m a s k

    = + 14243

    (3.5)

    Vi la c nh ngha l:

    ( ) 2

    0

    1 sT j t ft l

    s

    a t e dt T

    = (3.6)

    0a biu din s suy gim v pha ca tn hiu mong mun, cn vi biu

    din h s khuch i knh ca tn hiu nhiu. Vi thi gian bt k trn

    knh, 0la , v ra kt qu ca ICI.

    Nng lng ca ICI c nh ngha l:

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    [ ]2

    0

    ICI l

    l

    P E a s m l

    =

    Vi OFDM c s sng mang con khng xc nh, ICIP c th biu

    din thng qua hm tng quan ( )r l:

    ( ) ( )( )1

    1

    1 1ICI sP x r T x dx

    = (3.7)

    Hoc thng qua mt ph Doppler:

    ( ) ( )

    21 sind

    d

    f

    ICI sf

    P P f c fT df

    =

    (3.8)

    C (7) v (8) u cho OFDM vi s sng mang con xc nh, ta c

    th thy ch c sai s rt nh, ta c th dng cho OFDM vi s sng mang

    xc nh. Do , cng thc (7) v (8) c th dung tnh gn chnh xc nng

    lng ICI cho OFDM vi s sng mang xc nh.

    Bit mi hm tng quan trong min thi gian ca knh thay i theo

    thi gian, ta c th tnh nng lng ca ICI dng cng thc (3.7). Biu dintheo kiu thng thng:

    ( ) ( )1

    0

    1

    1 1 2ICI d sP x J f T x dx

    = (3.9)

    Biu din theo kiu ng dng v kiu 2 ng:

    ( )

    2

    1 os(2 ) 2 (2 )1

    2

    d s d s d sICI

    d s

    c f T f T Si f T P

    f T

    = (3.10)

    V ( )21 sinICI d sP c f T = (3.11)

    b. Gii hn

    S dng cc cng thc pha trn, nng lng ICI c th tnh chnh

    xc. Tuy nhin, cc cng thc tnh chnh xc kh phc t p v khng d

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    dng. Hn na, trong nhiu trng h p, hm tng quan theo min thi

    gian chnh xc hay ph cng sut l khng th tnh. y, chng ta nhn

    c gii hn trn v di v gii hn chung ca cng sut ICI. Nhng gii

    hn ny t phc tp hn v d tnh ton hn.

    u tin, a 1 ( )sr T x (3.7) vo ph cng sut, P(f), ta c:

    ( )( )21 ( ) 1d

    s

    d

    f

    j fT x

    s

    f

    r T x P f e df

    = ( ) ( )( )0

    2 1 os 2df

    sP f c fT x df =

    D thy

    2 4 21 1 11 os2 24 2

    c

    Hn na,

    ( )2 211 ( ) 2

    2s d sr T x f T x

    Vi i=1, 2 ..c nh ngha l

    2 2

    2 2

    0

    1 2( ) ( )

    d d

    d

    f f

    k k

    k k k

    d df

    f P f df f P f df

    f f

    = =

    Hng s1 v 2 d dng tnh ton v a ra kt qu nh bng 1.

    Thay vo bt ng thc (7), chng ta tnh c gii hn ca cng sut ICI.

    ( ) ( )2 41 22 2

    12 360ICI d s d sP f T f T

    (3.12)

    V ( )21 2

    12ICI d sP f T

    (3.13)

    Nu khng bit ph Doppler, 1 v 2 cng c th tnh uowcj thng

    qua cch tnh gn ng khc. V d, c th chng minh nh sau:

    ( ) ( ){ } ( ) ( )2 2 22

    d

    d

    fkk k

    f

    E t f P f df

    =

    Vi ( ) ( )( )kkk

    d tt

    dt

    = . Suy ra:

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    ( ) ( ){ }( )

    2

    22

    k

    k k

    d

    E t

    f

    =

    Cch tnh c phn n gin hn khi lin quan n ph Doppler.

    Bng 1Tnh ngha 1 , r rng 1 1 . Thc t, cng vi (3.13), ta c th tnh gii

    hn trn ca cng sut ICI, ch ph thuc vo d sf T ,

    ( )21 2

    12ICI d sP f T

    (3.14)

    Gii hn trn c th dung cho h thng OFDM vi ph Doppler, bao

    gm h thng OFDM vi tn s off-set. Bi v 1 thng nh hn 1 nn

    gii hn trn rng hn gii hn (3.13). Tuy nhin, (3.14) d tnh ton hn

    v ch ph thuc d sf T . Vi dng hai dng, 1 1 = v gii hn chung cng l

    gii hn hp.

    Nh ni trn, chng ta c gii hn chung v ring cho knh

    fading phng. h thng OFDM knh fading thi gian phn tn, thng th

    ta s gi s rng phn m rng theo chu k c thm vo gia k t

    OFDM trnh nhiu xuyn khi. Vi gi thuyt , ta s c

    ( )2

    2

    0

    siTj l f

    j l ft

    l i

    i s

    ea t e dt

    T

    =

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    Bi v ( )i t c lp vi I v c cng thng k, { }2lE a ging vi c knh

    phng v knh fading phn tn. Hn na, cng thc chnh xc tnh ICIP v

    gii hn khc cng c th tnh knh phn tn.

    3.2.4 Kt lun.

    i su vo tnh chnh xc cc gii hn, chng ta so snh gii hn

    trn v gii hn di v gii hn chung vi gi tr chnh xc ca cng sut

    ICI ( ICIP ). Ch rng vi kiu hai ng, gii hn trn v di l xc nh.

    Gii hn ring rt gn tnh chnh xc ICIP . Khi thit k h thng OFDM,

    nu chu k ca k t, Ts, phi c chn d sf T rt nh, do nh hng

    ca ph Doppler s khng ng k.

    3.3.ISI v ICI trong h thng FDMTrong h thng a sng mang (FDM), vn va ng v fading

    la tn c gi quyt. Tn hiu c chia thnh N dng song song v truyn

    trn N sng mang con vi tc nh hn. tit kim bng thng, ngi

    ta a vo h thng OFDM, trong cc sng mang con l trc giao ln

    nhau, tc l cho php cc sng mang con ny chng ph, nh vy tng c

    hiu qu s dng ph.

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    Hnh 9

    Cc sng mang con c di tn hp, khong k hiu di hn nn tra

    ng tng i l nh. Do vy, kh hon ton nhiu do a ng,

    ngi ta thm vo k hiuOFDM mt khong bo v. Khong ny c th l

    khong trng. Tuy nhin, mt vn mi li ny sinh. l hin tngnhiu lin knh (ICI) gia cc sng mang con ca OFDM. Nguyn nhn

    vn hiu ng a ng, cng thm v khong bo v trng.

    ICI sinh ra do s chng ph gia cc sng mang, gy ra xuyn m.

    Trong cc h thng n sng mang, ICI thng xut hin cc h thng

    lm vic ti cc di tn k nhau. Trong cc h thng ny, ngi ta thng

    a vo gia c di tn lm vic mt khong ph nhm trnh xuyn m.

    Trong h thng OFDM ni trn, ph cc sng mang con vn

    chng ln nhau, tuy nhin vn khng gy xuyn m, l do cc sng

    mang con l trc giao nhau theo ngha ton hc. S trc giao ny s mt i

    nu trong khong k hiu ( chnh xc hn l trong khong tch phn FFT) c

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    mt (hay nhiu) sng mang con khng tn ti chnh xc mt s nguyn ln

    chu k.

    Hnh 10

    Khi , ngi ta thay khong bo v trng bng khong bo v lp,

    tc l mrng chu k mu tn hiu

    Hnh 11

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    H thng OFDM do vy rt c k vng cho cc ng dng a hnh

    phc t p, nh cc thnh ph (vi nhiu nh cao tng) hay vng nng

    thn(nhiu i ni). Theo mnh bit th kthut ny hin c trong cc chun

    pht thanh s (DAB), truyn hnh s (DVB), IEEE802.11a,g v

    IEEE802.16 vi tc truyn d liu rt hp dn, c th ln ti 54Mbps

    thay v 11Mbps nh trong CDMA. Tuy nhin, vn trin khai h thng

    ny cn gp kh nhiu kh khn, ch yu l do vn chi ph lp t, v

    hin ti cng khng c nhiu ng dng i hi tc truyn d liu qu

    cao, cn vi cc ng dng thp hn, cc h thng hin nay qu

    cung cp dch v.

    Nhiu la chn tn s cng l mt vn gy nh hng ln n

    cht lng truyn thng tn hiu. Tuy nhin, OFDM cng mm do hn

    CDMA khi gii quyt vn ny. OFDM c th khi phc li knh truyn

    thng qua tn hiu dn ng (Pilot) c truyn i cng vi dng tn hiu

    thng tin. Ngoi ra, i vi cc knh con suy gim nghim trng v tn s

    th OFDM cn c mt la chn na gim t l li bit l gim bt s btm ho cho mt tn hiu iu ch ti tn s.

    Do vy, OFDM khng phi khng c nhc im, l n i hi

    kht khe v vn ng b v s sai lch v tn s, nh hng ca hiu ng

    Doppler khi di chuyn v lch pha s gy ra nhiu giao thoa tn s

    (Intercarrier interference - ICI) m kt qu l ph b s trc giao gia cc

    tn s sng mang v lm tng t s bt li (BER). Tuy nhin OFDM cng

    c th gim bt s phc tp ca vn ng b thng qua khong bo v

    (GI). S dng chui bo v (GI) cho php OFDM c thiu chnh tn s

    thch hp mc d vic thm GI cng ng ngha vi vic gim hiu qu s

    dng ph tn s. Ngoi ra OFDM chu nh hng ca nhiu xung, c ngha

    l mt xung tn hiu nhiu c th tc ng xu n mt chm tn hiu thay

    v mt s k t nh trong CDMA v iu ny lm tng t l li bit ca

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    OFDM so vi CDMA.

    4. Nhiu ng knh (Co-Channel Interference)

    4.1. Khi nim chungNhiu ng knh xy ra khi c hai my pht trn cng mt tn s

    hoc trn cng mt knh. My thu iu chnh knh ny s thu c c hai

    tn hiu vi cng ph thuc vo v tr ca my thu so vi hai my pht.

    Hnh 12: Nhiu ng knh

    Nhiu ng knh thng g p trong h thng thng tin s cellular,

    trong tng hiu sut s dng ph bng cch s dng li tn s. Nh

    vy c th coi nhiu ng knh trong h thng cellular l nhiu gy nn do

    cc cell s dng cng 1 knh tn s.

    Nhiu ng knh lin quan ti vic s dng tn s. C th v d trong

    mng GSM:Trong mng GSM, mi trm BTS c cp pht mt nhm tn

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    s v tuyn. Cc trm thu pht gc BTS ln cn c cp pht cc nhm

    knh v tuyn khng trng vi cc knh ca BTS lin k.

    c trng cho loi nhiu ny l t s sng mang trn nhiu (C/I). T

    s ny c nh ngha l cng tn hiu mong mun trn cng tn

    hiu nhiu sau lc cao tn v n th hin mi quan h gia cng tn

    hiu mong mun so vi nhiu ng knh t cc BTS khc.

    C/I = 10log (Pc/Pi)

    Yu cu l C/I khong cch cc cell cng tn s phi

    ln.

    4.2.Ti sdng tn s

    4.2.1.Khi nim ti s dng tn s

    Mng t bo hot ng trn nguyn tc phn chia vng ph sng dch v

    thnh cc phn vng hoc t bo, c ring mt tp hp ti nguyn hoc

    knh ngi s dng mng truy nhp.

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    Thng thng, cc vng ph sng t bo c xy dng theo cu trc

    t bo lc gic. Mng t bo b gii hn v bng thng hot ng trn

    nguyn l ti s dng tn s. iu ny cho thy, cng mt nhm tn s

    c s dng li trong cc t bo m c gi khong cch vi nhau

    mt khong c ly ln sao cho khng gy tc hi ln nhau m th hiu

    s giao thoa ng knh. i vi mt cu trc t bo lc gic, ta c th co

    gn cc t bo thnh cm m bo khng c hai t bo ln cn no dng

    chung mt tn s.

    Hnh 13: M hnh ti sdng tn s

    S dng li tn s l vic cp pht cng mt nhm tn s v tuyn ti

    cc v tr a l khc nhau trong mng m khng lm nh hng n cht

    lng kt ni ti giao din v tuyn do nhiu ng knh v nhiu knh ln

    cn gy nn.

    a. Nguyn l ti sdng tn s

    Mt h thng t ong lm vic da trn vic s dng li tn s. Nguyn

    l cbn khi thit k h thng t ong l cc mu s dng li tn s. Tng

    bng thng c trn mng c phn chia gia cc t bo trong mt cm.

    Cm ny sau c thc s dng xc nh s cuc gi c thc

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    h trtrong mi t bo. Bng vic gim s lng cc t bo trong mt cm,

    dung lng ca h thng c th tng ln, v c th c thm nhiu knh hn

    trong mi t bo. Tuy nhin mi ln gim kch thc cm s gy nn mt

    ln gim khong cch s dng lp tn, do vy, h thng rt c nguy ctr

    thnh giao thoa ng knh.

    Theo nh ngha s dng li tn s l vic s dng cc knh v tuyn

    cng mt tn s mang ph sng cho cc vng a l khc nhau. Cc

    vng ny phi cch nhau mt c ly ln mi nhiu giao thoa ng

    knh (c th xy ra) chp nhn c. T s sng mang trn nhiu C/I ph

    thuc vo v tr tc thi ca thu bao di ng do a hnh khng ng nht,

    s lng v kiu tn x. Phn b t s C/I cn thit h thng xc nh s

    nhm tn s F m ta c th s dng. Nu ton b s knh quy nh N c

    chia thanh F nhm th mi nhm s cha N/F knh. V tng s knh N l c

    nh nn s nhm tn s F nh hn s dn n nhiu knh hn mt nhm

    v mt i trm. V vy, vic gim s lng cc nhm tn s s cho php

    mi i trm tng lu lng nh s gim s lng cc i trm cn thitcho ti lu lng nh trc. Ta bit rng s dng li tn scc cell khc

    nhau th b gii hn bi nhiu ng knh C/I gia cc cell nn C/I s l

    mt vn chnh cn c quan tm.

    D dng thy rng, vi mt kch thc cell nht nh, khong cch s

    dng li tn s ph thuc vo s nhm tn s N. Nu N cng ln, khong

    cch s dng li tn s cng ln v ngc li.

    b. Cc thng s ti sdng tn s

    Vic s dng lp tn s c thc xc nh theo phng trnh sau cho

    mi kch thc cm t bo:

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    Trong :

    D l khong cch trung bnh s dng lp tn.

    R l bn knh t bo. N l kch ccm.

    Hnh 14: Khong cch ti sdng tn s

    Cc mu ti s dng tn sc k hiu tng qut : mu M/N

    Trong :

    M= tng s site / cluster

    N = tng s cell / cluster

    l H s s dng li tn s: 1/N

    => Mi cell c cp pht 1/N tng s knh tn s v tuyn trong 1 cluster

    .

    Trong mt mi trng tn x di ng mt t, cng cng sut my thu

    c ti mt khong R t thit bj pht lin quan n biu thc sau:

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    Trong l mt hng s lin quan ti mi trng mt t,

    thng ly bng 4.

    i vi mt cu hnh gm 7 t bo s dng lp tn, t s sng mang giao thoa xy ra do mt my mobile trong vng 6 t bo nm trong

    khong cch D so vi my mobile s dng lp tn ti thiu, ngha l, bn

    ngoi vnh ai th nht ca mu cm t bo s dng lp tn, c cho bi

    phng trnh:

    = =

    q: l tham s suy gim giao thao ng knh, c cho bi phng trnh:

    Biu thc trn gi thit rng cng sut pht ra bi tt c cc t bo l

    tng ng v s giao thao ng knh tn hiu nhn c t cc t bo

    hot ng da trn cng loi tn s ti vnh ai th hai ca cm t bo c

    thc lc b. Do vy, i vi , mt mu cm 7 t bo c th cho

    mt t s C/I l 18dB. gim thiu hiu ng ca vic giao thoa ng

    knh, s dng cc k thut iu khin cng sut ti im u cui mobile

    v trm csm bo cht lng dch v Ngoi ra ta cn c cng thc

    tnh C/I ti my di ng MS nh sau:

    Trong x l h s truyn sng.

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    4.3.Cc mu ti sdng tn s

    4.3.1. Mu 3/9

    Mu ti s dng tn s 3/9 c ngha cc tn s s dng c chia

    thnh 9 nhm n nh trong 3 v tr trm gc. Mu ny c khong cch gia

    cc i ng knh l D = 5.2R.

    Hnh 15

    Cc tn smu 3/9

    n nh tn s

    A1 B1 C1 A2 B2 C2 A3 B3 C3

    1 2 3 4 5 6 7 8 9

    10 11 12 13 14 15 16 17 18

    19 20 21 22 23 24 25 26 27

    28 29 30 31 32 33 34 35 36

    37 38 39 40

    Thng thng cm 9 cell c t s C/I khong 9dB. Vi t s ny, cc

    my di ng c th hot ng c nhvic GSM cung cp cc phng

    php o lng c bit c th lm gim nh hng ca nhiu. Cc

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    phng php o lng ny gm nhy tn, iu khin cng sut v truyn

    dn gin on.

    4.3.2.Mu 4/12Mu s dng li tn s 4/12 c ngha l cc tn s s dng c chia

    thnh 12 nhm tn sn nh trong 4 v tr trm gc. Khong cch gia cc

    trm ng knh khi D = 6R.

    Cc tn smu 4/12.

    n nh tn s

    A1 B1 C1 A2 B2 C2 A3 B3 C3 A4 B4 C4

    1 2 3 4 5 6 7 8 9 10 11 12

    13 14 15 16 17 18 19 20 21 22 23 24

    25 26 27 28 29 30 31 32 33 34 35 36

    37 38 39 40

    Ta thy mi cell c th phn b cc i l 4 sng mang.

    Trong mu 4/12 s lng cc cell D sp xp theo cc cch khc nhau

    nhm phc v cho cc cell A, B, C. Hiu qu ca vic iu chnh ny l

    m bo hai cell cnh nhau khng s dng hai sng mang lin nhau

    (khc vi mu 3/9). Hn na, s dng mu ny cng m bo cc cell s

    dng cc sng mang ging nhau c phn cch bi khong cch ti s

    dng.Trong phn trc, chng ta bit rng cm 12 cell c t s C/I khong 12dB.

    y l t s thch hp i vi h thng GSM v nh vy vic s dng k

    vng tn s, iu khin cng sut ng, truyn dn gin on thc cht

    khng cn thit.

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    4.3.3.Mu 7/21

    Mu 7/21 c ngha l cc tn s s dng c chia thnh 21 nhm n

    nh trong 7 trm gc. Khong cch gia cc trm ng knh D = 7.9R.

    Cc tn smu 7/21: mi cell chc phn b ti a 2 sng mang.

    n nh tn s

    A

    1

    B

    1

    C

    1

    D

    1

    E

    1

    F

    1

    G

    1

    A

    2

    B

    2

    C

    2

    D

    2

    E

    2

    F

    2

    G

    2

    A

    3

    B

    3

    C

    3

    D

    3

    E

    3

    F

    3

    1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

    22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40

    4.3. Nhn xt

    4.3.1. So snh gia cc mu s dng tn s:

    Khi s nhm tn s tng N/21, N/12, N/9, ngha l s tn s c th

    dng cho mt i trm tng th khong cch gia cc i ng knh D s

    gim 7.9R, 6R, 5.2R. iu ny ng ngha vi nhiu trong h thng cng s

    tng ln. Vi s nhm tn s tng th s thu bao c phc v cng s tngln. Nh vy, vic la chn mu s dng li tn s phi da trn cc c

    im a l vng ph sng, mt thu bao ca vng ph sng v tng s

    knh N ca mng.

    Mu 3/9: s knh trong mt cell l ln, tuy nhin kh nng nhiu cao.

    M hnh ny c p dng cho vng c mt my di ng cao.

    Mu 4/12: s dng cho nhng vng c mt lu lng trung bnh. Mu 7/21: s dng cho nhng khu vc mt lu lng thp.

    4.3.2. Dung lng v t s C/I.

    Vi tng s knh m ti nguyn h thng cho php l M knh, nu

    chia u cho N nhm knh th s c s knh trong mt nhm knh hay mt

    cell l M/N. Ty ta s tnh ton c dung lng phc vng vi cp

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    phc v GOS nht nh qua bng Erlang. Nh nhn xt trn, s nhm tn

    s cng nh th s lng knh trn mt nhm cng ln v s thu bao c th

    c phc v cng cao, ngha l phn nh hiu qu trung k tt hn. Nhng

    N nh li cho t s C/I nh, nhiu ng knh tng.

    Vi N cho trc, th dung lng trn mt cell s l cnh. Nh

    bit, khu vc cell t l thun vi bnh phng bn knh cell. Do vy, mt

    dung lng trong mt n v din tch l t l nghch vi khu vc cell. Vy

    nu ta chia cell nh c bn knh bng cell c th vi N cho trc dung

    lng s tng ln 4 ln. Tuy nhin, trnh nhiu ng knh th khng th

    lun s dng cng mt nhm tn s cho cc cell nh v iu nny s l

    gim i u im ca vic gim kch ccell s lm gim cht lng.

    5. Nhiu a truy nhp (Multiple Access Interference).Nhiu a truy nhp l nhiu do cc tn hiu ca cc user giao thoa vi

    nhau,l yu tnh hng trc tip n dung lng ca h thng

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    Trong cc h thng a truy nhp:

    TTDDMMAA::aa ttrruuyy nnhhpp pphhnn cchhiiaa tthheeoo tthhii ggiiaann

    Trong TDMA l s giao thoa ca cc tn hiu khe thi gian ny vi khe

    thi gian khc do s khng hon ton ng b gy ra

    Ngi ta phi c khong bo v (guard time) gim xc sut ngi dng

    b giao thoa nhng cng ng thi lm gim hiu sut s dng ph

    FDMA: a truy nhp phn chia theo tn s

    Cc hiu ng Doppler lm dch ph tn s dn n c s giao thoa gia cc

    di tn con

    Guard band gim xc xut giao thoa gia cc knh k nhau =>gim hiu

    sut s dng ph

    CDMA: a truy nhp phn chia theo m

    Trong CDMA ngi ta s dng tnh trc giao ca m nn hu nh khng

    c nhiu gia cc user.

    DS CDMA: a truy nhp phn chia theo m chui trc tip.

    Theo nhng nghin cu gn y, phng thc a truy nhp phn chia theom chui trc ti p DS-CDMA (Direct Sequence Code Division

    Multiplexing Access) da vo vic tri ph dng d liu bng cch s dng

    mt m tri ph c n nh cho mi ngi s dng trong min thi

    gian.Kh nng gim thiu nhiu a truy nh p MAI (Multiple Access

    Interference) da vo tnh tng quan cho ca m tri ph. Trong trng

    hp truyn a ng i hi rt kht khe ca vin thng di ng, kh nng

    phn bit mt tn hiu thnh phn t nhiu thnh phn khc trong tn hiu

    thu tng hp c cung cp bi tnh t tng quan ca m tri ph. My

    thu RAKE c cha nhiu b tng quan, mi b tng quan c ni vi

    mt dng dn c kh nng phn gi khc nhau. V vy hot ng ca h

    thng DS-CDMA s ph thuc nhiu vo s lng ngi s dng thc t,

    c trng ca knh v s lng cc nhnh c dng trong my thu RAKE.

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    kh MAI ngi ta thng dng cc phng php trc giao nhng

    trn thc t khng th c s trc giao hon ton. Do MAI vn tn ti

    trong cc h thng a truy nhp.

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    KT LUNTrn y nhm trnh by mt cch cbn 05 loi nhiu trong thng

    tin di ng, l

    Nhiu trng ( White Gaussian Noise)

    Nhiu xuyn m ( Intersymbol Interference)

    Nhiu xuyn knh ( Interchannel Interference)Nhiu ng knh ( Cochannel Interference)

    Nhiu a truy nhp (Multiple access Interference)

    Trc nhu cu ngy cng ln v thng tin lin lc ni chung v thng tin

    di ng ni ring, vic nghin cu p dng cc cng ngh tin tin cng

    nh tm kim cc gii php mi nhm nng cao v cht lng- dung lng

    cng nh cc loi hnh dch v thng tin lin lc c ngha ht sc quan

    trng v thit thc.