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    Six-Sigma Quality, Process Capability,

    and Statistical Process ControlSelected Slides from Jacobs et al, 9thEdition

    Operations and Supply Management

    Chapter 9 and 9AEdited, Annotated and Supplemented by

    Peter Jurkat

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    Total Quality Management (TQM)

    Total qualitymanagementis definedas managing the entireorganization so that it

    excels on all dimensionsof products and servicesthat are important to thecustomer

    Design quality: Inherentvalue of the product inthe marketplace

    Dimensions include:Performance, Features,Reliability/Durability,Serviceability, Aesthetics,and Perceived Quality.

    Conformance quality:Degree to which theproduct or service designspecifications are met

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    Six Sigma Quality

    A philosophy and set of methods

    companies use to eliminate defects

    in their products and processes Seeks to reduce variation in the

    processes that lead to product

    defects

    9-3

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    McGraw-Hill/Irwin Copyright 2009 by The McGraw-Hill Companies, Inc. All rights reserved.

    Gurus and their wisdom

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    Consensus

    Gurus had considerable differences

    After 30 years get some consensus

    Senior level leadership

    Customer focus

    Work force involvement

    Process analysis

    Continuous improvement

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    Costs of Quality

    External Failure

    Costs

    Appraisal Costs

    Prevention Costs

    Internal Failure

    Costs

    Costs of

    Quality

    9-6

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    9-7

    Cost of Quality Example

    At 20% of sales, represents about $2M sales, at 2.5% about $73M sales

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    Six Sigma Quality Measurement

    Six Sigma allows managers to readily describe process

    performance using a common metric: Defects Per MillionOpportunities (DPMO)

    Defect associated with a critical-to-quality characteristic: a

    measurable quantity used to identify failure

    Statistical six sigma goal is 3.4 failures per 1,000,000 opportunities 1

    failure in about 300,000 DPMO (actually 1 in 294,118)

    1,000,000x

    unitsofNo.x

    unitpererrorfor

    iesopportunitofNumber

    defectsofNumber

    DPMO

    9-8

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    9A-9Process Capability

    Shows to what extent (probability) parts are produced that meet and fall

    outside of specifications

    Achieved when process variation (s.d.) is so small that an acceptable

    proportion are defectsSix-Sigma goal is 3.4 out of one million

    Bearing Diameter

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    Why 3.4 DPMO?

    Six sigma between mean and, say, upper

    specification limit results 1 defect in100,000,000 (see SixSigmaOrigin.xls)

    Experience has shown that in long term

    processes have a wider variation than in shortterm studies, which results in defects with

    probability beyond 4.5 sigma, i.e.3.4 DPMO

    (1.5 sigma less than 6 sigma) See origin of this at http://en.wikipedia.org/wiki/Six_Sigma ( which bases

    above on Tennant, Geoff (2001). SIX SIGMA: SPC and TQM in

    Manufacturing and Services. Gower Publishing, Ltd., p. 25. ISBN

    0566083744.)

    http://en.wikipedia.org/wiki/Six_Sigmahttp://books.google.com/books?id=O6276jidG3IC&printsec=frontcoverhttp://books.google.com/books?id=O6276jidG3IC&printsec=frontcoverhttp://en.wikipedia.org/wiki/Special:BookSources/0566083744http://en.wikipedia.org/wiki/Special:BookSources/0566083744http://en.wikipedia.org/wiki/Special:BookSources/0566083744http://en.wikipedia.org/wiki/Special:BookSources/0566083744http://books.google.com/books?id=O6276jidG3IC&printsec=frontcoverhttp://books.google.com/books?id=O6276jidG3IC&printsec=frontcoverhttp://en.wikipedia.org/wiki/Six_Sigma
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    9A-11

    Mean shift during process improvement

    Still an improvement but capability is now measured against closest of LTL and UTL

    LTL = lower tolerance limit UTL = upper tolerance limit

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    Measure Example

    Example of Defects Per MillionOpportunities (DPMO) calculation.Suppose we observe 200 letters deliveredincorrectly to the wrong addresses in asmall city during a single day when atotal of 200,000 letters were delivered.

    What is the DPMO in this situation?

    000,1 1,000,000x

    200,000x1

    200DPMO

    So, for every onemillion letters

    delivered thiscitys postalmanagers canexpect to have1,000 lettersincorrectly sent to

    the wrongaddress.

    Cost of Quality: What might that DPMO mean in terms ofover-time employment to correct the errors?

    9-12

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    8-13Service Blueprint, Failure Anticipation, and Poka-Yokes

    Complete blueprint (p262-3)identifies 16 failure opportunities

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    Toyota Dealer Service Example

    Blueprint identified 16 failure opportunitiesper customer

    Assume 20 customers /day => 80,000

    customers/year for 250 working days per year At 3.4 failures per 1,000,000 opportunities this

    would allow .272 failures/year, or 3 2/3 years

    between failures What is the critical-to-quality characteristic of

    the first identified failure? Second failure?

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    DMAIC Cycle

    GE developedmethodology

    Overall focus is tounderstand andachieve what the

    customer wants (Juran) Identifies defects and

    variation in processesas underlying cause ofdefects (Deming)

    A 6-sigma programseeks to reduce thevariation in theprocesses that lead tothese defects

    Define customers andtheir priorities

    Measure process and itsperformance

    Analyze causes ofdefects

    Improve by removingcauses

    Control to maintainquality

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    DMAIC in Action

    We are the maker of acereal. Consumer Reportshas just published an articlethat shows that wefrequently have less than 16

    ounces of cereal in a box. What should we do?

    1. Define

    a. What is the critical-to-quality characteristic?

    b. The CTQ (critical-to-quality) characteristic inthis case is the weight ofthe cereal in the box.

    2. Measurea. How would we measure to

    evaluate the extent of theproblem?

    b. What are acceptable limitson this measure?

    c. Lets assume that thegovernment says that wemust be within 5 percentof the weight advertised onthe box.

    d. Upper Tolerance Limit = 16 +.05(16) = 16.8 ouncese. Lower Tolerance Limit = 16

    .05(16) = 15.2 ouncesf. Survey: 1000 boxes have

    mean weight = 15.875 ozwith s.d. = .529

    9 17

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    Upper Tolerance

    = 16.8Lower Tolerance

    = 15.2

    Process

    Mean = 15.875

    Std. Dev. = .529

    What percentage of boxes are defective (i.e. less than 15.2 oz)?

    Z = (xMean)/Std. Dev. = (15.215.875)/.529 = -1.276

    NORMSDIST(Z) = NORMSDIST(-1.276) = .100978

    Approximately, 10 percent of the boxes have less than 15.2

    Ounces of cereal in themway out of six-sigma specs

    9-17

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    DMAIC in Action

    3. Analyze - how can we

    improve the

    capability of our cereal

    box filling process?a. Decrease Variation

    b. Center Process

    c. Tighten Specifications

    4. ImproveHow good is

    good enough?

    a. Set center spec at goal

    (16 oz in this case)b. Set controls so that a

    deviation of 6 s.d.

    occurs only 3.4 times

    out of a million

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    DMAIC in Action

    5. Statistical ProcessControl

    a. Use data from actualprocess

    b. Estimate distributions

    c. Calculate capabilitydobetter if not adequate(actually do better all thetime)

    d. Statistically monitor the

    process over time

    e. Tools1) Process flow charts (e.g.,

    Toyota service blueprint)

    2) Run charts

    3) Pareto charts

    4) Check sheets5) Cause-and-effect

    diagrams

    6) Opportunity flowdiagrams

    7) Failure mode and effect

    analysis (FMEA)8) Statistical Process Control(SPC) and Control charts

    9) Design of Experiments(DOE)

    9-20

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    9-20

    9-21

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    9 21

    9-22

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    9 22

    9-23

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    9 23

    Severity: cost of damage, rating number

    Occurrence: observed relative frequency,

    predicted probability

    Detection: probability of detection

    RPN = Occurrence X Severity X Detection

    Failure Mode and Effect Analysis

    9-24

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    9 24

    Part of Statistical Process Control

    Uses statistical theory and practice to follow processes in order to determine if they are

    within specification/control

    Also used to predict if a process might be going out of control while still within specs

    General approach is to sample a process at intervals, plot the results and compare

    these to control limits

    Upper

    Control

    Limit

    Lower

    ControlLimit

    9A-25

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    Statistical Process Control

    Assignable variationis causedby factors that can be clearlyidentified and possiblymanaged

    Common variationis inherentin the production process

    Example: A poorly trained

    employee that creates

    variation in finished product

    output.

    Example: A molding process

    that always leaves burrs or

    flaws on a molded item.

    Based on statistical theory of variation (dispersion)

    Defines process capability

    Establishes process control limits

    Controls process bases on periodic sampling (small samples

    as opposed to inspecting/measuring everything)

    Variation

    9A-26

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    Taguchis View of Variation

    Incremental

    Cost of

    Variability

    High

    Zero

    Lower

    Spec

    Target

    Spec

    Upper

    Spec

    Traditional View

    Incremental

    Cost of

    Variability

    High

    Zero

    Lower

    Spec

    Target

    Spec

    Upper

    Spec

    Taguchis View

    Traditional view is that quality within the LS and US is good and that

    the cost of quality outside this range is constant, Taguchi views costs as

    increasing as variability increases, so seek to achieve zero defects and

    that will truly minimize quality costs.

    Upper and lower specs are also called upper and lower tolerance limits (UTL and LTL)

    9A-27

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    Process Capability Index, Cpk

    3X-UTLor

    3LTLXmin=Cpk

    Shifts in Process Mean

    Capability Index shows

    how well parts being

    produced fit into design

    limit specifications.

    As a production process

    produces items small

    shifts in equipment or

    systems can cause

    differences inproduction

    performance from

    differing samples.

    LTL/UTL = lower/upper tolerance limit

    9A-28

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    The Cereal Box Example

    We are the maker of this cereal. Consumer reports hasjust published an article that shows that we frequentlyhave less than 16 ounces of cereal in a box.

    Lets assume that the government says that we must

    be within 5 percent of the weight advertised on thebox.

    Upper Tolerance Limit = 16 + .05(16) = 16.8 ounces

    Lower Tolerance Limit = 16.05(16) = 15.2 ounces

    We go out and buy 1,000 boxes of cereal and find thatthey weight an average of 15.875 ounces with astandard deviation of .529 ounces.

    9A-29

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    Cereal Box Process Capability

    Specification or Tolerance

    Limits Upper Spec = 16.8 oz

    Lower Spec = 15.2 oz

    Observed Weight

    Mean = 15.875 oz

    Std Dev = .529 oz

    3

    ;3

    XUTLLTLXMinCpk

    )529(.3

    875.158.16;

    )529(.3

    2.15875.15MinCpk

    5829.;4253.MinCpk

    4253.pkC

    9A-30

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    What does a Cpkof .4253 mean?

    An index that shows how well theunits being produced fit within the

    specification limits. This is a process that will produce a

    relatively high number of defects.

    Many companies look for a Cpkof 1.3or better 6-Sigma company wants2.0!

    9A-31

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    Types of Statistical Sampling in SPC

    Attribute (overall acceptable or not)

    Defectives refers to the acceptability of product across arange of characteristics.

    Defects refers to the number of defects per unit whichmay be higher than the number of defectives.

    p-chart application (p for proportion)

    Variable (Continuous)

    Usually actual dimensions (length, weight, hardness, )

    Usually measured by the mean and the standarddeviation.

    X-bar and R chart applications (x-bar for mean and R forrangemuch easier to measure than s.d.)

    9A-32

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    Control Charts

    9A-33

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    Statistical Process Control Formulas:

    Attribute Measurements (p-Chart)

    p =T o t al N u m b e r o f D e fe c tiv e s

    T o ta l N u m b e r o f O b s e rv a tio n s

    n

    s

    )p-(1p=p

    p

    p

    z-p=LCL

    z+p=UCL

    s

    s

    Given:

    Compute control limits:

    9A-34

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    1. Calculate the sample

    proportions, p (these

    are what can be plotted

    on thep-chart) for each

    sample

    Sample n Defectives p

    1 100 4 0.04

    2 100 2 0.02

    3 100 5 0.05

    4 100 3 0.03

    5 100 6 0.06

    6 100 4 0.04

    7 100 3 0.03

    8 100 7 0.07

    9 100 1 0.01

    10 100 2 0.02

    11 100 3 0.03

    12 100 2 0.02

    13 100 2 0.02

    14 100 8 0.0815 100 3 0.03

    Example of Constructing ap-chart

    2. Calculate theaverage and s.d. of the

    sample proportions

    0.036=1500

    55=p

    .0188=

    100

    .036)-.036(1=

    )p-(1p=p

    n

    s

    E l f C t ti Ch t9A-35

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    Example of Constructing ap-Chart

    0

    0.02

    0.04

    0.06

    0.08

    0.1

    0.12

    0.14

    0.16

    1 2 3 4 5 6 7 8 9 10 11 12 13 14 15

    Observation

    p

    UCL

    LCL

    Calculate control limits and plot the individual sample proportions, the

    average of the proportions, and the control limits 3(.0188).036

    UCL = 0.0924

    LCL = -0.0204 (or 0)

    9A-36

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    Example of x-bar and R charts: Steps: Calculate x-bar Chart and Plot Values

    10.601

    10.856

    =).58(0.2204-10.728RA-x=LCL

    =).58(0.2204-10.728RA+x=UCL

    2

    2

    10.550

    10.600

    10.650

    10.700

    10.750

    10.800

    10.850

    10.900

    1 2 3 4 5 6 7 8 9 10 11 12 13 14 15

    S a m p l e

    Means

    UCL

    LCL

    9A-37

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    Example of x-bar and R charts: Calculate R-chart and Plot Values

    0

    0.46504

    )2204.0)(0(RD=LCL

    )2204.0)(11.2(RD=UCL

    3

    4

    0 . 0 0 0

    0 . 1 0 0

    0 . 2 0 0

    0 . 3 0 0

    0 . 4 0 0

    0 . 5 0 0

    0 . 6 0 0

    0 . 7 0 0

    0 . 8 0 0

    1 2 3 4 5 6 7 8 9 1 0 1 1 1 2 1 3 1 4 1 5

    S a m p l e

    RUCL

    LCL

    9A-38

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    Common criteria for concluding

    process is out of control or in

    danger of being so

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    Advantages Economy Less handling damage Fewer inspectors Upgrading of the

    inspection job Applicability to destructive

    testing Entire lot rejection

    (motivation forimprovement)

    Disadvantages

    Risks of accepting badlots and rejecting goodlots

    Added planning anddocumentation

    Sample provides less

    information than 100-percent inspection

    Acceptance Sampling

    PurposesDetermine quality level of acquired goods or services(after the fact) when no sampling of productionprocess is availableEnsure quality is within predetermined level

    9A-40

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    Risk

    Acceptable Quality Level (AQL)

    Max. acceptable percentage of defectives defined

    by producer

    The (Producers risk)

    The probability of rejecting a good lot

    Probability of Type I error based on consumersnull hypothesis that lot is good

    Lot Tolerance Percent Defective (LTPD)

    Percentage of defectives that defines consumers

    rejection point

    The (Consumers risk)

    The probability of accepting a bad lot

    Probability of Type II error based on consumers

    null hypothesis that lot is good

    9A-41

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    Operating Characteristic Curve

    n = 99

    c = 4

    AQL LTPD

    00.1

    0.2

    0.3

    0.4

    0.50.6

    0.7

    0.8

    0.9

    1

    1 2 3 4 5 6 7 8 9 10 11 12

    Percent defective

    Probabilityofacceptinglots

    withgive%o

    fdefectives

    =.10(consumers risk = accept bad lot)

    = .05 (producers risk

    = reject good lot)

    The OCC brings the concepts of producers risk, consumers

    risk, sample size, and maximum defects allowed together

    The shape

    or slope of

    the curve is

    dependent

    on a

    particular

    combination

    of the four

    parameters

    n = sample size

    c = acceptance number (max

    defectives allowed before lotis rejected)

    H0: Lot is good

    Ha: Lot is bad

    9A-42

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    Example: Acceptance Sampling Problem

    Zypercom, a manufacturer of video interfaces,

    purchases printed wiring boards from an outside

    vender, Procard. Procard has set an acceptable

    quality level of 1% and accepts a 5% risk of rejecting

    lots at or below this level. Zypercom considers lots

    with 3% defectives to be unacceptable and will assume

    a 10% risk of accepting a defective lot.

    Develop a sampling plan for Zypercom and determine

    a rule to be followed by the receiving inspection

    personnel.

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    9A-44

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    Example: Step 2. Determine c

    First divide LTPD by AQL

    LTPDAQL

    = .03.01

    = 3

    Then find the value for c by selecting the value in the QA-12 (on disk)

    n(AQL)column that is equal to or just greater than the ratio above.

    Exhibit QA-12

    c LTPD/AQL n AQL c LTPD/AQL n AQL

    0 44.890 0.052 5 3.549 2.6131 10.946 0.355 6 3.206 3.286

    2 6.509 0.818 7 2.957 3.981

    3 4.890 1.366 8 2.768 4.695

    4 4.057 1.970 9 2.618 5.426

    So, c = 6.

    LTPD = Lot tolerant percent defective (buyers)

    AQL = Acceptable quality level (seller)