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Percent Error

Percent Error. The percent error can be determined when the experimental value is compared to the accepted value according to the equation below:

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Page 1: Percent Error. The percent error can be determined when the experimental value is compared to the accepted value according to the equation below:

Percent Error

Page 2: Percent Error. The percent error can be determined when the experimental value is compared to the accepted value according to the equation below:

Percent ErrorThe percent error can be determined when the experimental value is compared to the accepted value according to the equation below:

Page 3: Percent Error. The percent error can be determined when the experimental value is compared to the accepted value according to the equation below:

What you got.

Page 4: Percent Error. The percent error can be determined when the experimental value is compared to the accepted value according to the equation below:

A percent error can be either positive or negative.

If the measured value is greater than the accepted value, the difference (measured value – accepted value) will be positive, and the percent error will be positive.

If the measured value is less than the accepted value, the difference will be negative and the percent error will be negative.

Page 5: Percent Error. The percent error can be determined when the experimental value is compared to the accepted value according to the equation below:
Page 6: Percent Error. The percent error can be determined when the experimental value is compared to the accepted value according to the equation below:

Example:The accepted value for the density of copper is 8.93 g/cm3. In a laboratory setting, three students are asked to experimentally determine the density of copper. Their results are

Student 1: 8.91 g/cm3

Student 2: 8.23 g/cm3

Student 3: 8.99 g/cm3

Calculate the percent error associated with each student’s reported density.

Page 7: Percent Error. The percent error can be determined when the experimental value is compared to the accepted value according to the equation below:

Experimental value: Student 1: 8.91 g/cm3

Accepted value: 8.93 g/cm3

8.91 g/cm3 - 8.93 g/cm3( )

8.93 g/cm3

X 100 = -0.2% error

Always put a box around your answer.

Note that there are no units associated with percent error; g/cm3, present in both numerator and denominator, cancel.

Page 8: Percent Error. The percent error can be determined when the experimental value is compared to the accepted value according to the equation below:

Experimental value: Student 2: 8.23 g/cm3

Accepted value: 8.93 g/cm3

8.23 g/cm3 - 8.93 g/cm3( )

8.93 g/cm3

X 100 = -7.8%error

Always put a box around your answer.

Page 9: Percent Error. The percent error can be determined when the experimental value is compared to the accepted value according to the equation below:

Experimental value: Student 3: 8.99 g/cm3

Accepted value: 8.93 g/cm3

8.99 g/cm3 - 8.93 g/cm3( )

8.93 g/cm3

X 100 = 0.7% error

Always put a box around your answer.

Page 10: Percent Error. The percent error can be determined when the experimental value is compared to the accepted value according to the equation below:

1. A student calculated the volume of a test tube to be 10.3 mL. The true volume is 10.0mL.

10.3 mL - 10.0 mL( )

10.0 mL

X 100 = 3% error

Problems

Page 11: Percent Error. The percent error can be determined when the experimental value is compared to the accepted value according to the equation below:

2. A student determines the density of gold to be 18.98 g/L. The true density of gold is 19.30 g/L.

18.98 g/L - 19.30 g/L( )

19.30 g/L

X 100 = -1.66% error

Page 12: Percent Error. The percent error can be determined when the experimental value is compared to the accepted value according to the equation below:

3. An equation was solved using 299,000,000 m/s as the speed of light. Actually the speed of light in a vacuum is exactly 299,792,458 m/s.

299,000,000 m/s - 299,792,458 m/s( )

299,792,458 m/sX 100 = -0.26434 % error

Page 13: Percent Error. The percent error can be determined when the experimental value is compared to the accepted value according to the equation below:

4. A group of students using a triple beam balance found the mass of a copper sample to be 2.40 g. The actual mass of the copper sample is 2.41 g.

2.40 g - 2.41 g( )

2.41 g

X 100 = -0.415% error

Page 14: Percent Error. The percent error can be determined when the experimental value is compared to the accepted value according to the equation below:

5. Working in the laboratory, a student find the density of a piece of pure aluminum to be 2.85 g. The accepted value for the density of aluminum is 2.69 g.

2.85 g - 2.69 g( )

2.69 gX 100 = 5.95% error

Page 15: Percent Error. The percent error can be determined when the experimental value is compared to the accepted value according to the equation below:

6. A group of students using a triple beam balance found the mass of an aluminum sample to be 1.90 g. The actual mass of the aluminum sample is 2.01 g.

1.90 g - 2.01 g( )

2.01 gX 100 = -5.47% error

Page 16: Percent Error. The percent error can be determined when the experimental value is compared to the accepted value according to the equation below:

7. A student experimentally determines the specific heat of water to be 4.29 J/g Co. He then looks up the specific heat of water on a reference table and finds that is 4.18 J/g Co.

4.29 J/g - 4.18 J/g( )

4.18 J/gX 100 = 2.63% error

Page 17: Percent Error. The percent error can be determined when the experimental value is compared to the accepted value according to the equation below:

8. A student takes an object with an accepted mass of 200.00 grams and masses it on his own balance. He records the mass of the object as 196.5 g.

196.5 g - 200.00 g( )

200.00 gX 100 = -1.75% error

Page 18: Percent Error. The percent error can be determined when the experimental value is compared to the accepted value according to the equation below:

9. A student measured the length of a line to be 23 cm long. The actual length of the line is 23.101 cm long.

23 cm - 23.101 cm( )

23.101 cmX 100 = -0.437% error

Page 19: Percent Error. The percent error can be determined when the experimental value is compared to the accepted value according to the equation below:

10. A person was traveling 65 mph in a 55 mph zone. After being stopped by an officer, the person claimed his speedometer said 55 mph not 65 mph.

65 mph - 55 mph( )

55 mphX 100 = 18% error