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Physics 101: Lecture 16, Pg 1 Physics 101: Physics 101: Lecture Lecture 16 16 Angular Momentum Angular Momentum Today’s lecture will cover Textbook Chapter 8.7-8.9 Exam II

Physics 101: Lecture 16, Pg 1 Physics 101: Lecture 16 Angular Momentum Today’s lecture will cover Textbook Chapter 8.7-8.9 Exam II

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Physics 101: Lecture 16, Pg 1

Physics 101: Physics 101: Lecture 16Lecture 16 Angular Momentum Angular Momentum

Today’s lecture will cover Textbook Chapter 8.7-8.9

Exam II

Physics 101: Lecture 16, Pg 2

OverviewOverview

ReviewKrotation = ½ I 2

Torque = Force that causes rotationEquilibrium

F = 0 = 0

TodayAngular Momentum L = IL = 0 if = 0

06

Physics 101: Lecture 16, Pg 3

Linear and AngularLinear and Angular

Linear Angular

Displacement x Velocity v Acceleration a Inertia m I

KE ½ m v2 ½ I 2

N2L F=ma = IMomentum p = mv L = I

Today

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Physics 101: Lecture 16, Pg 4

Define Angular MomentumDefine Angular Momentum

MomentumMomentum Angular MomentumAngular Momentum

p = mV L = I

conserved if Fext = 0 conserved if ext =0

Vector Vector!

units: kg-m/s units: kg-m2/s

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Physics 101: Lecture 16, Pg 5

Right Hand RuleRight Hand Rule Wrap fingers of right hand around direction of

rotation, thumb gives direction of angular momentum.

What is direction of angular momentum for wheel

A) Up B) Down C) Left D) Right

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Physics 101: Lecture 16, Pg 6

Act: Two DisksAct: Two Disks A disk of mass M and radius R rotates around the z

axis with angular velocity i. A second identical disk, initially not rotating, is dropped on top of the first. There is friction between the disks, and eventually they rotate together with angular velocity f.

A) f = i B) f = ½ i C) f = ¼ i

i

z

f

z

Wheel rim

drop

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Physics 101: Lecture 16, Pg 7

Act: Two DisksAct: Two Disks First realize that there are no external torques

acting on the two-disk system.Angular momentum will be conserved!

ii MRL 211 2

10I

0

z2

1

f

z

ff MRL 22211 II

fi MRMR 22

21

fi 21

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Physics 101: Lecture 16, Pg 8

Lecture 16,Lecture 16, Pre-flightsPre-flightsYou are sitting on a freely rotating bar-stool with your arms stretched out and a heavy glass mug in each hand. Your friend gives you a twist and you start rotating around a vertical axis though the center of the stool. You can assume that the bearing the stool turns on is frictionless, and that there is no net external torque present once you have started spinning.

You now pull your arms and hands (and mugs) close to your body.

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Physics 101: Lecture 16, Pg 9

Bonus Question!Bonus Question! There are No External forces acting on the

“student+stool” system.

A) True B) False C) What!?

Key is no external torques about vertical axis! FBD has gravity

and normal force.

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Physics 101: Lecture 16, Pg 10

Lecture 16,Lecture 16, Preflight 1 Preflight 1 What happens to the angular momentum as you pull in your arms?

1. it increases 2. it decreases 3. it stays the same

46%

13%

41%

0% 10% 20% 30% 40% 50%

L1 L2CORRECT

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“Since there are no external torques present, the angular momentum is

conserved”

Physics 101: Lecture 16, Pg 11

Lecture 16,Lecture 16, Preflight 2Preflight 2

6%

8%

86%

0% 20% 40% 60% 80% 100%

1 2

I2 I1

L L

What happens to your angular velocity as you pull in your arms?

1. it increases 2. it decreases 3. it stays the same

CORRECT

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“Angular velocity increases because the moment of inertia decreases and since angular momentum must stay the same, angular

velocity must decrease. ”

“From past experiences where many of my friends decided to start spinning me while I was holding a heavy glass mug, you go faster. ! ”

Physics 101: Lecture 16, Pg 12

Lecture 16,Lecture 16, Preflight 3Preflight 3

30%

7%

63%

0% 20% 40% 60% 80%

What happens to your kinetic energy as you pull in your arms?

1. it increases 2. it decreases 3. it stays the same

CORRECT

“KE increases since it is inversely related to I according to the equation KE=L^2/2I.”

1 2

I2 I1

L L

K 12

2I 12

2 2

II 1

22

IL (using L = I )

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“Conservation of energy.”

Physics 101: Lecture 16, Pg 13

What about Energy Conservation?What about Energy Conservation?

A) Energy isn’t conserved here

B) Energy comes from weights

C) Gravitational energy is being converted to rotational kinetic energy

D) Energy comes from cookies.

E ) I have no clue….

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Physics 101: Lecture 16, Pg 14

Turning the bike wheelTurning the bike wheelA student sits on a barstool holding a bike wheel. The wheel is initially spinning CCW in the horizontal plane (as viewed from above) L= 25 kg m2/s She now turns the bike wheel over. What happens?

A. She starts to spin CCW.B. She starts to spin CW.C. Nothing

CORRECT

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Start w/ angular momentum L pointing up from wheel. When wheel is flipped, no more angular momentum from it pointing up, so need to spin person/stool to conserve L!

Physics 101: Lecture 16, Pg 15

Turning the bike wheel (more)Turning the bike wheel (more)She is holding the bike wheel and spinning counter clockwise. What happens if she turns it the other ½ rotation (so it is basically upside down from how it started).

A) Spins Faster B) Stays same C) Stops

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Physics 101: Lecture 16, Pg 16

Turning the bike wheel...Turning the bike wheel... Since there is no net external torque acting on the student-

stool system, angular momentum is conserved.Remenber, L has a direction as well as a magnitude!

Initially: LLINI = LLW,I = + 25 kg m2/s

Finally: LLFIN = LLW,F + LLS

= -25 kg m2/s + Ls

Ls = 50 kg m2/s

LLW,F

LLS

LLW,I

LLW,I = LLW,F + LLS

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Physics 101: Lecture 16, Pg 17

Act 2 Act 2 RotationsRotations

A puck slides in a circular path on a horizontal frictionless table. It is held at a constant radius by a string threaded through a frictionless hole at the center of the table. If you pull on the string such that the radius decreases by a factor of 2, by what factor does the angular velocity of the puck increase?

(a) 2 (b) 4 (c) 8

Puck on ice

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Physics 101: Lecture 16, Pg 18

Act 2 Act 2 SolutionSolution Since the string is pulled through a hole at the center

of rotation, there is no torque: Angular momentum is conserved.

L1 = I11 = mR21

mR m

R/2

L2 = I22 = m 2=2

2R

mR21 = m R2241

41

1 = 2 2 = 41

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Physics 101: Lecture 16, Pg 19

Gyroscopic Motion:Gyroscopic Motion: Suppose you have a spinning gyroscope

in the configuration shown below: If the left support is removed, what will

happen??

pivotsupport

g

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Physics 101: Lecture 16, Pg 20

Gyroscopic Motion...Gyroscopic Motion...

Suppose you have a spinning gyroscope in the configuration shown below:

If the left support is removed, what will happen?The gyroscope does not fall down!

pivot

g

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Physics 101: Lecture 16, Pg 21

Gyroscopic Motion...Gyroscopic Motion... ... instead it precessesprecesses around its pivot

axis !

pivot

Bicycle wheel

Physics 101: Lecture 16, Pg 22

SummarySummary

= I

L = I Right Hand Rule gives directionIf = 0, L is conserved

Physics 101: Lecture 16, Pg 23

Practice Problems for Chapt 8Practice Problems for Chapt 8

Probs. 13, 17, 25, 29, 31, 33, 35, 37, 43, 49, 53, 55, 57, 61, 65, 67, 69 (hard!), 73, 75, 77, 79, 81, 85, 89, 105, 113