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7/29/2019 Pmr Trial 2013 Math Qa SBP
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SULIT 2
[Lihat sebelah
50/1 2013 Hak Cipta BPSBPSK SULIT
Answerall questions
1 Which of the numbers, when rounded off to the nearest thousand becomes 56 000?Nombor manakah apabila dibundarkan kepada ribu yang terdekat menjadi 56 000?
A 55 009B 55 401C 55 499D 55 599
2 A number is a multiple of 9 ifSesuatu nombor adalah gandaan 9 jika
A its last digit is 9digit terakhirnya ialah 9
B the last two digits of the number are divisible by 9dua digit terakhir nombor tersebut boleh dibahagi dengan 9
C the sum of the last two digits of the number is divisible by 9hasil tambah dua digit terakhir nombor tersebut boleh dibahagi dengan 9
D the sum of all the digits of the number is divisible by 9hasil tambah semua digit nombor tersebut boleh dibahagi dengan 9
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SULIT 10
[Lihat sebelah
50/1 2013 Hak Cipta BPSBPSK SULIT
15 Find the area of the shaded part.Cari luas kawasan berlorek.
Diagram 7
Rajah 7
A 1088 cmB 1188 cmC 1288 cmD
1408 cm
16 The Mathematics room is rectangular in measurement of 90m in length and 35m in width. Ifthe room is divided into plots of square. Find the longest side in metre, for each of squares
plot.
Bilik Matematik berbentuk segiempat tepat berukuran 90m panjang dan 35m lebar
dibahagikan kepada plot-plot segiempat sama. Cari panjang sisi dalam meter, yang paling
besar bagi setiap plot segiempat sama itu.
A 9 C 5B 7 D 3
44 cm10 cm
10 cm
32 cm
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SULIT 11
[Lihat sebelah
50/1 2013 Hak Cipta BPSBPSK SULIT
17 Which of the following are possibly the nets of a cone?Antara yang berikut, yang manakah bentangan yang mungkin bagi sebuah kon?
I III
II IV
A I dan II C II dan III
I andII II andIII
B I dan III D III dan IV
I andIII III andIV
18 Diagram 8 shows the net of a cuboid.Rajah 8 menunjukkan bentangan bagi sebuah kuboid.
Diagram 8
Ra ah 8
5 cm
8 cm
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SULIT 14
[Lihat sebelah
50/1 2013 Hak Cipta BPSBPSK SULIT
23 Norfarhan was driving at a constant speed of 90km 1h and he accelerated to 105km 1h in20 minutes. Find the acceleration of the car in km
2h .
Norfarhan memandu pada kelajuan tetap 90 km1
h dan dia telah memecut dengan kelajuan
105 km1
h selama 20 minit. Kirakan kadar pecutannya dalam km2
h .
A 45
B 50
C 54
D 60
24 In Diagram 10, STU is a straight line. Given that 2:3:4:: RTSSRTRST Dalam Rajah 10, STU ialah garis lurus. Diberi 2:3:4:: RTSSRTRST
Find the value ofy.
Cari nilai y.
A 100
B 120
C 140
D 160
Diagram 10
Rajah 10
R
ST U
y
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SULIT 24
[Lihat sebelah
50/1 2013 Hak Cipta BPSBPSK SULIT
37 Which of the following is the table of values of the function ?Antara jadual berikut, yang manakah nilai-nilai bagi fungsi ?
x -1 0 1
y 3 2 1
x -1 0 1
y 1 2 1
x -1 0 1
y 1 0 1
x -1 0 1
y 3 0 1
A
B
C
D
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SULIT 9 50/2
50/2 Hak Cipta BPSBPSK Lihat sebelah
SULIT
9. Diagram 2 shows a quadrilateral EFGH. EG is the bisector ofFEH.Rajah 2 menunjukkan sebuah sisi empat EFGH. EG ialah pembahagi dua sama FEH.
(a)Using only a ruler and pair of compasses, construct Diagram 2 beginning from thestraight lines EF and EH provided in the Diagram 3.
Menggunakan pembaris dan jangka lukis sahaja, bina Rajah 2 bermula dengan garislurus, EF dan EH, yang disediakan di Rajah 3.
(b)Based on the diagram constructed in Diagram 3, measure the length, in cm, of GH.Berdasarkan rajah yang dibina di Rajah 3, ukur panjang, dalam cm, bagi GH.
[5 marks]
[5 markah]
Answer/Jawapan:
9
5
1200
Diagram 2
Rajah 2
E H
GF
F
E
Diagram 3
Rajah 3
H
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SULIT 10 50/2
50/2 Hak Cipta BPSBPSK Lihat sebelah
SULIT
10.Diagram 4 in the answer space shows a square PQRS with sides of 8 units drwn ona grid of equal squares with sides of 1 unit. X, Y and Z are three moving points
inside the square.
Rajah 4 di ruang jawapan menunjukkan sebuah segiempat sama PQRS dengan sisi8 unit yang dilukis pada grid segiempat sama bersisi 1 unit. X, Y dan Z adalah tiga
titik yang bergerak di dalam segiempat sama itu.
(a)X is the point which moves such that it is constantly 4 unit from the point K.Describe fully the locus of X.
X ialah titik yang bergerak dengan keadaan titik itu sentiasa berjarak 4 unitdari titik K. Huraikan selengkapnya lokus bagi X.
(b)On Diagram 4, drawPada Rajah 4, lukis
(i) The locus of the point Y which moves that its distance is constantly 3 unitfrom line KM
Lokus bagi titik Y yang bergerak dengan keadaan titik itu sentiasa berjarak
3 unit dari garis lurus KM.(ii) The locus of the point Z which moves such that it is always equidistant from
the point P and the point R.
Lokus bagi titik Z yang bergerak dengan keadaan jaraknya adalah sentiasa
sama dari titik P dan titik R.
(c)Hence, mark with the symbol the intersection of the locus of Y and thelocus of Z.
Seterusnya, tandakan dengan simbol kedudukan bagi semua persilanganlokus Y dan lokus Z itu.
[5 marks]
[5 markah]
Answer/Jawapan:
10
5
P K Q
S M R
Diagram 4
Rajah 4
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SULIT 13 50/2
50/2 Hak Cipta BPSBPSK Lihat sebelah
SULIT
13. Diagram 7 is a data which shows the grade obtained by 30 students in the PMRexamination.
Rajah 7 ialah data yang menunjukkan gred yang diperolehi oleh 30 pelajar dalam
peperiksaan PMR
Diagram/Rajah 7
(a) By using the above data , complete the frequency table in the answer space.Dengan menggunakan data di atas, lengkapkan jadual kekerapan pada ruang jawapan.
(b) State the mode of the data.Nyatakan mod bagi data tersebut.
[3 marks]
[3 markah]
Answer/Jawapan:
(a)
Grade
GredA B C D E
Frequency
Kekerapan
(b) Mode = ____________
A C A D E C E D E C E C C C D
C B B D B D B A B B A C D C A
13
3
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SULIT 15 50/2
50/2 Hak Cipta BPSBPSK Lihat sebelah
SULIT
15. (a) Simplify/Permudahkan25 yy
(b) Find the value of/Cari nilai bagi
3
222
3
93
[3 marks]
[3 markah]
Answer/Jawapan:
(a)
(b)
16. Evaluate/Nilaikan:
3
2
2
1
2
1
64
273
[2 marks][2 markah]
Answer/Jawapan:
3
15
2
16
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SULIT 18 50/2
50/2 Hak Cipta BPSBPSK Lihat sebelah
SULIT
Graph for Question 19
Graf untuk Soalan 19
-3 0-1-2 1 2 3 x
y
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PEPERIKSAAN PERCUBAAN PMR SBP TAHUN 2013
QUESTION MARKING SCHEME SUB MARKS FULL MARKS
1 )416(210
= )4(210
= 810 =18
P1N1 2
2
2
14.024.2
=
2
16.5
= 5.06.5 = 6.1
P1
N1 2
3(a)
(b)
)2(5 m
= 105 m P1
3
ppp 4)]1)(1[(2
= ppp 4)12(22
= ppp 42422
= 222 p
P1
N1
4(a)
(b)
rtr10
= )10( tr P1
3
2273 x
= )91(32
x
= )31)(31(3 xx P1
N1
5
bc
c
b
342
3
2
=
bc
c
b 3
46
3
2
= bc
cc
3
642
= bc
c
3
66
= bcc 22
P1
K1
N1 3
6 Betul semua sisi
Betul 4 @ 5 @ 6 sisi
Betul 1 @ 2 @ 3 sisi
P3
P2
P1 3
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