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MOLE PROBLEMS

Round all masses to the 10ths place Step One: two atoms of iron and three of oxygen Step Two: Fe = 55.8 amu and O = 16.0 amu Step Three: (2 x 55.8)

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Page 1: Round all masses to the 10ths place  Step One: two atoms of iron and three of oxygen  Step Two: Fe = 55.8 amu and O = 16.0 amu  Step Three: (2 x 55.8)

MOLE PROBLEMS

Page 2: Round all masses to the 10ths place  Step One: two atoms of iron and three of oxygen  Step Two: Fe = 55.8 amu and O = 16.0 amu  Step Three: (2 x 55.8)

CALCULATING MOLAR MASS

Round all masses to the 10ths place

Page 3: Round all masses to the 10ths place  Step One: two atoms of iron and three of oxygen  Step Two: Fe = 55.8 amu and O = 16.0 amu  Step Three: (2 x 55.8)

CALCULATE THE MOLECULAR WEIGHT OF Fe2O3

Step One: two atoms of iron and three of oxygen

Step Two: Fe = 55.8 amu and O = 16.0 amu

Step Three: (2 x 55.8) + (3 x 16.0)

Step Four: 111.6 + 48.0 = 159.6 amu (grams) for one mole

Page 4: Round all masses to the 10ths place  Step One: two atoms of iron and three of oxygen  Step Two: Fe = 55.8 amu and O = 16.0 amu  Step Three: (2 x 55.8)

CALCULATE THE MOLECULAR WEIGHT OF KClO4

Step One: one atom of potassium, one of chlorine, and four of oxygen.

Step Two: K = 39.1 amu, Cl = 35.5 amu, O = 16.0 amu

Step Three: (1 x 39.1) + (1 x 35.5) + (4 x 16.0)

Step Four: 39.1 + 35.5 + 64.0 = 138.6 amu (grams) for one mole

Page 5: Round all masses to the 10ths place  Step One: two atoms of iron and three of oxygen  Step Two: Fe = 55.8 amu and O = 16.0 amu  Step Three: (2 x 55.8)

CALCULATE THE MOLECULAR WEIGHT OF (NH4)2S

Step One: two atoms of nitrogen, eight of hydrogen and one of sulfur

Step Two: N = 14.0 amu, H = 1.0 amu, S = 32.1 amu

Step Three: (2 x 14.0) + (8 x 1.0) + (1 x 32.1)

Step Four: 28 + 8.0 + 32.1 = 68.1 amu (grams) for one mole

Page 6: Round all masses to the 10ths place  Step One: two atoms of iron and three of oxygen  Step Two: Fe = 55.8 amu and O = 16.0 amu  Step Three: (2 x 55.8)

CALCULATE THE MOLAR MASS OF Al(NO3)3

Calculate the molar mass of Al(NO3)3

Al(1 x 27.0) + N(3 x 14.0) + O(9 x 16.0) =

213.0 amu (grams) is the mass of one mole of aluminum nitrate.

Page 7: Round all masses to the 10ths place  Step One: two atoms of iron and three of oxygen  Step Two: Fe = 55.8 amu and O = 16.0 amu  Step Three: (2 x 55.8)

YOU TRY THESE… 1. AlCl3 2. Ba(SCN)2 3. LiH 4. Ba(BrO3)2 5. AlBr3 6. HCl

Page 8: Round all masses to the 10ths place  Step One: two atoms of iron and three of oxygen  Step Two: Fe = 55.8 amu and O = 16.0 amu  Step Three: (2 x 55.8)

ANSWERS 1. 133.5 g/mol 2. 253.5 g/mol 3. 7.9 g/mol 4. 393.1 g/mol 5. 266.7 g/mol 6. 36.5 g/mol

Page 9: Round all masses to the 10ths place  Step One: two atoms of iron and three of oxygen  Step Two: Fe = 55.8 amu and O = 16.0 amu  Step Three: (2 x 55.8)

GRAMS TO MOLES

Round all final answers to 3 sig figs

Page 10: Round all masses to the 10ths place  Step One: two atoms of iron and three of oxygen  Step Two: Fe = 55.8 amu and O = 16.0 amu  Step Three: (2 x 55.8)

CONVERT 25.0 GRAMS OF KMnO4 TO MOLES.

KMnO4 = 158.0 g / mole of KMnO4

Now let’s solve it

25.0 g x 1 mole = 0.158191804 moles 158.0 g

0.158 moles

Page 11: Round all masses to the 10ths place  Step One: two atoms of iron and three of oxygen  Step Two: Fe = 55.8 amu and O = 16.0 amu  Step Three: (2 x 55.8)

CALCULATE HOW MANY MOLES ARE IN 17.0 GRAMS OF H2O2.

H2O2 = 34.0 g / mole

Now, let’s solve it

17.0 g x 1 mol H2O2 = 0.5 moles

34.0 g

0.500 moles

Page 12: Round all masses to the 10ths place  Step One: two atoms of iron and three of oxygen  Step Two: Fe = 55.8 amu and O = 16.0 amu  Step Three: (2 x 55.8)

YOU TRY THESE… Calculate the moles present in: 1) 2.00 grams of H2O 2) 75.57 grams of KBr 3) 100. grams of KClO4

4) 8.76 grams of NaOH 5) 0.750 grams of Na2CO3

Remember to round answers to 3 sig figs

Page 13: Round all masses to the 10ths place  Step One: two atoms of iron and three of oxygen  Step Two: Fe = 55.8 amu and O = 16.0 amu  Step Three: (2 x 55.8)

ANSWERS 1) 0.111 moles 2) 0.635 moles 3) 0.722 moles 4) 0.219 moles 5) 0.00708 moles

Page 14: Round all masses to the 10ths place  Step One: two atoms of iron and three of oxygen  Step Two: Fe = 55.8 amu and O = 16.0 amu  Step Three: (2 x 55.8)

MOLES TO GRAMS

Round all answers to 3 sig figs

Page 15: Round all masses to the 10ths place  Step One: two atoms of iron and three of oxygen  Step Two: Fe = 55.8 amu and O = 16.0 amu  Step Three: (2 x 55.8)

CALCULATE HOW MANY GRAMS ARE IN 0.700 MOLES OF H2O2

H2O2 molar mass = 34.0 grams/mole

0.700 moles x 34.0 grams = 23.8 g 1 mole

23.8 grams

Page 16: Round all masses to the 10ths place  Step One: two atoms of iron and three of oxygen  Step Two: Fe = 55.8 amu and O = 16.0 amu  Step Three: (2 x 55.8)

CONVERT 2.50 MOLES OF KClO3 TO GRAMS. KClO3 molecular mass = 122.6 g/mole

2.50 moles x 122.6 g = 306.5 grams 1 mole

307 grams

Page 17: Round all masses to the 10ths place  Step One: two atoms of iron and three of oxygen  Step Two: Fe = 55.8 amu and O = 16.0 amu  Step Three: (2 x 55.8)

YOU TRY THESE… Calculate the grams present in: 1) 0.200 moles of H2S 2) 0.100 moles of KI 3) 1.500 moles of KClO 4) 0.750 moles of NaOH 5) 3.40 x 10-5 moles of Na2CO3

Remember to round answer to 3 sig figs

Page 18: Round all masses to the 10ths place  Step One: two atoms of iron and three of oxygen  Step Two: Fe = 55.8 amu and O = 16.0 amu  Step Three: (2 x 55.8)

ANSWERS 1) 6.82 grams 2) 16.6 grams 3) 136 grams 4) 30.0 grams 5) 0.00360 grams

Page 19: Round all masses to the 10ths place  Step One: two atoms of iron and three of oxygen  Step Two: Fe = 55.8 amu and O = 16.0 amu  Step Three: (2 x 55.8)

AVOGADRO'S NUMBER

6.02 x 1023 particles = 1 mole

Particles can mean atoms or molecules

Page 20: Round all masses to the 10ths place  Step One: two atoms of iron and three of oxygen  Step Two: Fe = 55.8 amu and O = 16.0 amu  Step Three: (2 x 55.8)

ONE MOLE OF ANY SPECIFIED ENTITY CONTAINS 6.02 X 1023

OF THAT ENTITY

Page 21: Round all masses to the 10ths place  Step One: two atoms of iron and three of oxygen  Step Two: Fe = 55.8 amu and O = 16.0 amu  Step Three: (2 x 55.8)

FOR EXAMPLE One mole of donuts contains 6.02 x 1023

donuts

One mole of H2O contains 6.02 x 1023 molecules

One mole of nails contains 6.02 x 1023 nails

One mole of Fe contains 6.02 x 1023 atoms

Page 22: Round all masses to the 10ths place  Step One: two atoms of iron and three of oxygen  Step Two: Fe = 55.8 amu and O = 16.0 amu  Step Three: (2 x 55.8)

CONTINUED One mole of dogs contains 6.02 x 1023

dogs

One mole of electrons contains 6.02 x 1023 electrons

One mole of Chemistry students contains 6.02 x 1023 poor, suffering (I mean happy, joyful) high school students

Page 23: Round all masses to the 10ths place  Step One: two atoms of iron and three of oxygen  Step Two: Fe = 55.8 amu and O = 16.0 amu  Step Three: (2 x 55.8)

0.450 MOLE OF Fe CONTAINS HOW MANY ATOMS? 0.450 mole Fe x 6.02 x 1023 atoms

1 mole

= 2.709x1023 atoms

Final, rounded answer: 2.71x1023 atoms

Page 24: Round all masses to the 10ths place  Step One: two atoms of iron and three of oxygen  Step Two: Fe = 55.8 amu and O = 16.0 amu  Step Three: (2 x 55.8)

0.200 MOLE OF H2O CONTAINS HOW MANY MOLECULES? 0.200 mole x 6.02 x 1023 atoms

1 mole

= 1.204x1023 atoms

Final, rounded answer: 1.20x1023 atoms

Page 25: Round all masses to the 10ths place  Step One: two atoms of iron and three of oxygen  Step Two: Fe = 55.8 amu and O = 16.0 amu  Step Three: (2 x 55.8)

YOU TRY THESE… 1) Calculate the number of molecules in

1.058 mole of H2O

2) Calculate the number of atoms in 0.750 mole of Fe

Remember to round to 3 sig figs

Page 26: Round all masses to the 10ths place  Step One: two atoms of iron and three of oxygen  Step Two: Fe = 55.8 amu and O = 16.0 amu  Step Three: (2 x 55.8)

ANSWERS 1) 6.37x1023 molecules

2) 4.52x1023 atoms

Page 27: Round all masses to the 10ths place  Step One: two atoms of iron and three of oxygen  Step Two: Fe = 55.8 amu and O = 16.0 amu  Step Three: (2 x 55.8)

TWO STEP PROBLEMS

Grams to particles OR particles to grams

Grams to atoms OR atoms to grams

If MOLE is not stated, it’s a two step problem

ROUND ALL ANSWERS TO 3 SIG FIGS

Page 28: Round all masses to the 10ths place  Step One: two atoms of iron and three of oxygen  Step Two: Fe = 55.8 amu and O = 16.0 amu  Step Three: (2 x 55.8)

0.450 GRAM OF Fe CONTAINS HOW MANY ATOMS? 0.450 g x 1 mole Fe x 6.02x1023 atoms

= 55.8 g 1 mole

4.8548387x1021 atoms

Final answer = 4.85x1021 atoms

Page 29: Round all masses to the 10ths place  Step One: two atoms of iron and three of oxygen  Step Two: Fe = 55.8 amu and O = 16.0 amu  Step Three: (2 x 55.8)

0.200 GRAM OF H2O CONTAINS HOW MANY MOLECULES? H2O molecular mass = 18.0 g

0.200 g x 1 mole H2O x 6.02x1023 molecules

18.0 g 1 mole

6.6888888889x1021 molecules

Final answer = 6.69x1021 molecules

Page 30: Round all masses to the 10ths place  Step One: two atoms of iron and three of oxygen  Step Two: Fe = 55.8 amu and O = 16.0 amu  Step Three: (2 x 55.8)

YOU TRY THESE… 1) Calculate the number of molecules in

1.058 gram of H2O

2) Calculate the number of atoms in 0.750 gram of Fe

Remember to round answer to 3 sig figs

Page 31: Round all masses to the 10ths place  Step One: two atoms of iron and three of oxygen  Step Two: Fe = 55.8 amu and O = 16.0 amu  Step Three: (2 x 55.8)

ANSWERS 1) 3.54x1022 molecules

2) 8.10x1021 atoms

Page 32: Round all masses to the 10ths place  Step One: two atoms of iron and three of oxygen  Step Two: Fe = 55.8 amu and O = 16.0 amu  Step Three: (2 x 55.8)

THE END