UNIVERSIDAD LATINA DE COSTA RICA CAMPUS HEREDIA

Tarea Corta #1 - Diseo de Acero II Cuatrimestre 2013 20-05-2013. Jason Alberto Camacho Murillo.

A. 1 = 3 = 20 0.9 = 18

2 2 = 60 1.2 = 72

2 = 1 + 2 + 3 = 18

2 + 722 + 182 = 1082

Momentos de inercia

= (1

1211

3 + 112) 2 +

1

1222

3

= (1

12 20 (0.9)3 + 182 (30.45)2 ) 2 +

1

12 1.2 (60)3

= 54981.724

= (1

1211

3) 2 +1

1222

3

= (1

12 0.90 (20)3) 2 +

1

12 60 (1.2)3

= 1208.644

Radio de giro

=

= 54981.724

1082= 22.56

=

= 1208.644

1082= 3.35

Mdulo de seccin elstico

=60

2+ 0.9 = 30.90

=

=54981.724

30.90= 1779.343

UNIVERSIDAD LATINA DE COSTA RICA CAMPUS HEREDIA

Tarea Corta #1 - Diseo de Acero II Cuatrimestre 2013 20-05-2013. Jason Alberto Camacho Murillo.

B. 1 = 40 0.90 = 36

2 2 = 60 1.2 = 72

2 3 = 20 0.90 = 18

2 = 1 + 2 + 3 = 36

2 + 722 + 182 = 1262

=( )

()=362 0.45 + 722 30.9 + 182 61.35

1262

= 26.55

Momentos de inercia

= (1

1211

3 + 112) + (

1

1222

3 + 222) + (

1

1233

3 + 332)

= (1

12 40 (0.9)3 + 362 (26.55)2 )

+(1

12 1.2 (60)3 + 722 (4.35)2 )

+(1

12 20 (0.9)3 + 182 (34.8)2 )

= 70141.27

4

= (1

1211

3) +1

1222

3 + (1

1233

3)

= (1

12 0.90 (40)3) +

1

12 60 (1.2)3 + (

1

12 0.90 (20)3)

= 5408.644

Radio de giro

=

=

70141.274

1262= 23.59

=

= 5408.644

1262= 6.55

Modulo de seccin elstico = 34.8 + 0.45 = 35.25

=

=70141.274

35.25= 1989.82

UNIVERSIDAD LATINA DE COSTA RICA CAMPUS HEREDIA

Tarea Corta #1 - Diseo de Acero II Cuatrimestre 2013 20-05-2013. Jason Alberto Camacho Murillo.

C. = 20 40 = 800

2 = 18.2 38.2 = 695.24

2 = 1 2 = 800

2 695.242 = 104.762 Momentos de inercia

= (1

1211

3) 1

1222

3

= (1

12 20 (40)3)

1

12 18.2 (38.2)3

= 22123.164

= (1

1211

3) 1

1222

3

= (1

12 40 (20)3) +

1

12 38.2 (18.2)3

= 7475.724

Radio de giro

=

= 22123.164

104.762= 14.53

=

= 7475.724

104.762= 8.45

Modulo de seccin elstico = 20

=

=22123.164

20= 1106.163

UNIVERSIDAD LATINA DE COSTA RICA CAMPUS HEREDIA

Tarea Corta #1 - Diseo de Acero II Cuatrimestre 2013 20-05-2013. Jason Alberto Camacho Murillo.

D.

1 = 3 = 15 0.9 = 13.52

2 = 40 1.2 = 482

= 1 + 2 + 3 = 13.52 + 482 + 13.52 = 752

=( )

()=13.52 7.5 + 482 0.6 + 13.52 7.5

752

= 3.08

Momentos de inercia

= (1

1211

3 + 112) 2 +

1

1222

3

= (1

12 15 (0.9)3 + 13.52 (20.45)2 ) 2 +

1

12 1.2 (40)3

= 17693.294

= (1

1211

3 + 112) + (

1

1222

3 + 222)

= (1

12 0.90 (15)3 + 13.52 (4.42)2 ) 2

+(1

12 40 (1.2)3 + 482 (2.48)2 )

= 1334.714

Radio de giro

=

= 17693.294

752= 15.36

=

= 1334.714

752= 4.22

Mdulo de seccin elstico = 20 + 0.9 = 20.90

=

=17693.294

20.90= 846.573

UNIVERSIDAD LATINA DE COSTA RICA CAMPUS HEREDIA

Tarea Corta #1 - Diseo de Acero II Cuatrimestre 2013 20-05-2013. Jason Alberto Camacho Murillo.

10

010

010)20(

0

Ay

Ay

Ay

Fx

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Cortante Momento

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UNIVERSIDAD LATINA DE COSTA RICA CAMPUS HEREDIA

Tarea Corta #1 - Diseo de Acero II Cuatrimestre 2013 20-05-2013. Jason Alberto Camacho Murillo.

375.4

375.4

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08)5)(7(

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0

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Mc

5.2

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